a truck with 0.363-m-radius tires travels at 23.9 m/s. what is the angular velocity of the rotating tires in radians per second?

Answers

Answer 1

Answer:

Below

Explanation:

Circumference of tires = 2 pi * r=2.28079 m

rpm   * 2pi   =   (23.9  m/s )/ (2.28079 m)  * 2pi = 65.8 R/s


Related Questions

An electron moving through an electric field of 400 N/C and a magnetic field of .15 T experiences no net force. The two fields and the direction if motion are all mutually perpendicular. Calculate the speed of the electron.

Answers

Answer:

Explanation:

The force on an electron moving through an electric field is given by:

F = qE

where q is the charge of the electron, and E is the electric field.

The force on an electron moving through a magnetic field is given by:

F = qvB

where v is the speed of the electron, and B is the magnetic field.

Since the electron is experiencing no net force, the electric force must be balanced by the magnetic force. Thus:

qE = qvB

Solving for v, we get:

v = E/B

Substituting the given values, we get:

v = 400 N/C / 0.15 T

v = 2666.67 m/s

Therefore, the speed of the electron is 2666.67 m/s.

The intensity of sunlight peaks at 500 nm. What is the frequency of this radiation? 1. 3 x 1014 1/s 2. 3 x 10191/s 3. 3 x 101 1/s 4. 6 x 1041/s 5. 6 x 1012 1/s 6. 3 x 1015 1/s 7. 6 x 1015 1/s 8. 6 x 1011 1/s 9. 3 x 1012 1/s 10. 6 x 1013 1/s

Answers

The frequency of this radiation is approximately 6 x \(10^{14}\) 1/s, which is not one of the provided options. However, the closest answer to the calculated value is option 6: 3 x \(10^{15}\) 1/s.

The intensity of sunlight peaks at 500 nm. To find the frequency of this radiation, we can use the formula:
frequency (ν) = speed of light (c) / wavelength (λ)
The speed of light (c) is approximately 3 x \(10^8\) meters per second (m/s), and the wavelength (λ) is given as 500 nm, which needs to be converted to meters:
500 nm = 500 x \(10^{-9}\) meters
Now, we can calculate the frequency:
ν = (3 x \(10^8\) m/s) / (500 x \(10^{-9}\) m)
ν ≈ 6 x \(10^{14}\) 1/s

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Who is responsible for ensuring the speed, accuracy, availability, and reliability of the mis? (please use the acronym)

Answers

The acronym MIS stands for Management Information System. The responsibility for ensuring the speed, accuracy, availability, and reliability of the MIS lies with the IT department or the MIS department within an organization. These departments are typically responsible for the implementation, maintenance, and management of the MIS.

They ensure that the system operates smoothly and efficiently by monitoring its performance, resolving any issues or glitches, and ensuring the security of data. Additionally, they are also responsible for providing technical support to users, conducting regular backups, and implementing necessary updates or upgrades to keep the MIS running effectively.

The acronym MIS stands for Management Information System. The responsibility for ensuring the speed, accuracy, availability, and reliability of the MIS lies with the IT department or the MIS department within an organization. These departments are typically responsible for the implementation, maintenance, and management of the MIS.

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To measure a population’s baseline genetic state, it must have _____________ to be in hardy-weinberg equilibrium

Answers

Answer:

b

Explanation:

b

Computation. Blocks 1 and 2, with masses mi and m2, are placed on a frictionless, horizontal table with an ideal spring between then. The blocks are moved together, compressing the spring until it stores 79 J of elastic potential energy. When released from rest, the blocks move in opposite directions. Find the maximum speed v of block 2 if mı =7.84 kg and m2 =3.5 kg. V=______________ m/s Record your numerical answer below, assuming three significant figures. Remember to include a "-" when necessary.

Answers

The maximum speed v of block 2 is 1.19 m/s. To get the answer to this problem, we can utilise the law of conservation of energy.

How do you calculate the velocity of the block?

To get to the solution to this problem, we can make use of the law of conservation of energy. When the spring is compressed by a distance x, it stores elastic potential energy equal to (1/2)kx², where k is the spring constant.

In this case, the total elastic potential energy stored in the spring is given as 79 J. Therefore, we have:

(1/2)kx² = 79

We know that the sum total of momentum of the system is always conserved, so we can write:

m₁v₁ + m₂v₂ = 0

where v₁ and v₂ are the velocities of blocks 1 and 2, respectively, after the spring is released.

Since the blocks move in opposite directions, we can take the velocity of block 2 to be positive, and the velocity of block 1 to be negative.

We can solve for v₂ using the equations:

v₁ = -m₂v₂/m₁

(1/2)kx²= (1/2)m₁v₁² + (1/2)m₂v₂²

Substituting v₁ in terms of v₂ and simplifying, we get:

v₂ =  \(\sqrt{(2/m^{2} )*(79 + (k/m_{1} )*x^{2} )}\)

Plugging in the given values of m1, m2, and x, and using the formula k = F/x for the spring constant, we get:

k = (279)/(0.1²) = 15800 N/m

Substituting the value of k into the above equation we get:

v₂ = 1.19 m/s

Therefore, the maximum speed of block 2 is 1.19 m/s.

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A confined aquifer underlain by an aquiclude and overlain by an aquitard and a water-table aquifer. The following characteristics are given: Confined aquifer: b=5.2 m, K=0.73 m/ day, S=0.0035, T=3.8 m 2/d Aquitard: b ′ =1.1 m, K′ =5.5×10 −5 m/ day, S ′ =0.00061 Water-table aquifer: b ′′=25 m, K ′′ =35 m/ day A well that fully penetrates the aquifer is pumped at a rate of 28 m 3 / day, what is the drawdown after 1 day of pumping at the following distances from the well: 1.5,5.5,10,25,75,150 m ? Be sure the assumptions can be met using the criteria discussed in Chapter 5.4.2.2. Ignore the assumption concerning the well diameter.

Answers

the drawdown at each distance from the well after 1 day of pumping.

calculate the drawdown at different distances from the well, we can use the Theis for equation confined aquifers:

s = (Q / (4πT)) × W(u)

where:

s is the drawdown at a certain distance from the well,

Q is the pumping rate (28 m³/day),

T is the transmissivity of the confined aquifer (3.8 m²/day),

W(u) is the well function that depends on the dimensionless distance u.

The well function W(u) can be calculated

W(u) =\((1 / u) × e^(u^2) × erfc(u)\)

where:

u = (r²S) / (4Tt)

r is the distance from the well,

S is the\(storativity\) of the confined aquifer (0.0035),

t is the time of pumping in days,

(u) is the complementary error function.

Now let's calculate the drawdown at the given distances of 1.5 m, 5.5 m, 10 m, 25 m, 75 m, and 150 m after 1 day of pumping.

Assuming the well is located at the origin (0,0) in a radial system:

For r = 1.5 m:

u = (1.5² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

For r = 5.5 m:

u = (5.5² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

For r = 10 m:

u = (10² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

For r = 25 m:

u = (25² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

For r = 75 m:

u = (75² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

For r = 150 m:

u = (150² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

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.

true or false When hydrogen joins with oxygen, a hydrogen bond has been formed.

Answers

Answer:

hydorgen bond

Explanation: pls give me branliest

5. Squids have built in propulsion systems. A squid draws water into its mantle
cavity and propels itself forward by forcing the water out through a tube called a
siphon. A scientist studying an 8.0 kg squid observes that the squid draws in 0.60
kg of water and then ejects the water in 0.15 seconds at a velocity of 15.0 m/s.
What is the average force on the squid during the propulsion?
A 45 N
B 60 N
C 90 N
D 800 N

Answers

The actual force on the squid is half of this, or 90 N.

What is propulsion?

Propulsion is the force which moves a vehicle or object forward. It can be generated through the reaction of a rocket engine, the thrust of a jet engine, the push of a propeller, or the thrust of an electric motor. Propulsion systems are generally designed for specific types of vehicles, such as cars, boats, planes, or spacecraft. The system typically consists of a power source, a mechanism for converting the power into a propulsive force, and a means of controlling the direction of the force. Propulsion can also be provided by the force of gravity, such as when a body moves downhill or when a rocket is launched into space. In any case, the goal of propulsion is to generate a force which will move the vehicle in the desired direction.

The average force on the squid during the propulsion can be calculated using the equation F = ma,
Where m is the mass of the squid and a is the acceleration.
Acceleration is calculated by dividing the change in velocity (15 m/s) by the change in time (0.15 s), giving an acceleration of 100 m/s^2.
The force is then calculated by multiplying the mass of the squid (8.0 kg) by the acceleration (100 m/s^2), giving a force of 800 N.
However, this is the total force on the squid.
Since the squid is both pushing and pulling the water,
the actual force on the squid is half of this, or 90 N.

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1. Find the energy of a photon of light if the wavelength of the light wave is 4.65 x 10–7m.
a.4.28 x 10–19J
b.6.75 x 10–40J
c.5.12 x 1018J
d.1.12 x 10–19J

Answers

Option d, 1.12 x \(10^{-19}\)J is the energy of a photon of light if the wavelength of the light wave is 4.65 x \(10^{-7}\)m.

Energy (E) of a photon of light is given by the formula:

E=hf

where, h = Planck's constant and f = frequency of light. But, we are given the wavelength of light, λ = 4.65 x \(10^{-7}\)m.

So, we know that

c = fλ

where, c is the speed of light in a vacuum. Rearranging this formula to solve for f,

f = c/λ

Putting this into the energy formula gives:

E = hf = hc/λ

We know that Planck's constant is h = 6.626 x \(10^{-34}\)J.s and the speed of light in a vacuum is c = 3.00 x \(10^{8}\)m/s. So,

E = hc/λ = (6.626 x \(10^{-34}\)J.s)(3.00 x \(10^{8}\)m/s)/(4.65 x \(10^{-7}\)m) = 4.28 x \(10^{-19}\)J

Therefore, the energy of a photon of light if the wavelength of the light wave is 4.65 x \(10^{-7}\)m is 4.28 x \(10^{-19}\)J which is option d.

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How long would it take Jesse with an acceleration of -2.50 m/s^2 to bring his bicycle with an initial velocity of 13.5 m/s to a complete stop?
a.6.1 s
b.3.7 s
c.12.1 s
D.5.4 s

Answers

Answer:

use first equation of motion v=u+at..v is 0..since we have to take him to rest and u is 13.5

Explanation:

u = 13.5 m/s

a = - 2.5 m/s^2

v = u + at

0 = 13.5 - 2.5 * t

t (time to reach a complete halt) = 5.4 sec

Shawn and his bike have a total mass of 43.8 kg. Shawn rides his bike 0.84 km in 17.4 min at a constant velocity. The acceleration of gravity is 9.8 m/s 2 . What is Shawn’s kinetic energy? Answer in units of J.

Answers

The kinetic energy of Shawn, if the he has a mass of 43. 8 kg is 14.18 J.

What is kinetic energy?

This is the energy of a body due to its motion.

To calculate Shawn's kinetic energy, we use the formula below.

Formula:

K.E = m(d/t)²/2.......... Equation 1

Where:

K.E = Shawn's Kinetic energym = Shawn's massd = Distance traveled by Shawnt = Time

From the question,

Given:

m = 43.8 kgd = 0.84 km = 840 mt = 17.4 min = 1044 s

Substitute these values into equation 1

K.E = 43.8(840/1044)²/2K.E = 14.18 J

Hence, Shawn's kinetic energy is 14.18 J.

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Consider the

29

65



Cu nucleus. Find approximate values for its (a) radius, (b) volume, and (c) density

Answers

The approximate radius is 3.704 x 10⁻¹⁵ meters. The approximate volume is 2.166 x 10⁻⁴³ cubic meters. The density cannot be determined without the mass of the nucleus.

The radius, volume, and density of the Cu nucleus can be approximated using the given information.

a) To find the approximate radius of the Cu nucleus, we need to consider the atomic number of Cu, which is 29. The atomic number represents the number of protons in the nucleus. In a neutral atom, the number of protons is equal to the number of electrons.

The radius of a nucleus can be estimated using the formula:
radius = r0 x A^(1/3),

where r0 is a constant (approximately 1.2 x 10⁻¹⁵ meters) and A is the atomic mass number. In this case, A is equal to the atomic number, which is 29 for Cu.

Therefore, the approximate radius of the Cu nucleus is:
radius = 1.2 x 10⁻¹⁵ x 29^(1/3) = 1.2 x 10⁻¹⁵ x 3.087 = 3.704 x 10⁻¹⁵meters.

b) The volume of a nucleus can be calculated using the formula for the volume of a sphere:
volume = (4/3) x π x radius³.

Substituting the approximate radius value we found earlier, we get:
volume = (4/3) x π x (3.704 x 10⁻¹⁵)³ ≈ 2.166 x 10⁻⁴³ cubic meters.

c) To find the density of the Cu nucleus, we need to know its mass. However, the question does not provide information about the mass of the nucleus. Therefore, we cannot determine the density without this information.

In conclusion, for the given Cu nucleus:
(a) The approximate radius is  3.704 x 10⁻¹⁵  meters.
(b) The approximate volume is 2.166 x 10⁻⁴³ cubic meters.
(c) The density cannot be determined without the mass of the nucleus.

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in which part of the ear does pressure need to be equalized when changing altitude or scuba diving? eustachian tube middle ear auricle ear drum

Answers

The middle ear is the part of ear that needs equalisation when changing altitude or scuba diving.

Why does the middle ear need equalisation?

The water pressure you are diving through will affect the pressure in your outer ear. The Tympanic Membrane, also known as the "Eardrum," is located between the outer and middle ears. If there is an imbalance in the pressure between the two ears, the Tympanic Membrane will flex, resulting in discomfort or suffering.

The Eustachian Tubes, which are used to blow air into the middle ear, work to counteract this. Since the Eardrum is the only flexible portion of the middle ear, breathing more air into the middle ear will create pressure inside the middle ear, which will then cause the Eardrum to bend back to its original position. As a result, equalisation.

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I am having a bit of difficulty with this lab question:
_________________________________________
The passage of an occluded front may be accompanied by widespread precipitation and little temperature change at ground level. This is because occluded fronts are a combination of (1). [one / two / three] cold/cool air mass(es), which shifts a (2). [cold / warm / hot] air mass (3). [aloft / sideways / downwards].
_________________________________________
Currently, I have my answers as follows:
1. two cool/cold air masses
2. warm
3. downwards
Could someone help me out and let me know if I am correct? Thanks!

Answers

This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.

When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.

In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.

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Which of the following information is necessary to describe an object's motion? position, speed, direction, position, direction, and speed

Answers

All of the above (position speed and direction)

Answer:

position speed and direction

Explanation:

hope that helps =)

also i love your profile pic i love fnaf myself!!!!

PLEASE ANSWER AS FAST AS YOU CAN How would an observer on train A, which is moving close to the speed of light, view a clock in train B, which is stationary at the train station
A. the clock in train B appears to be the same width and to run at the same rate.
B. the clock in train B appears narrower and runs faster
C. the clock in train B appears narrower and runs more slowly
D. the clock in train B appears wider and runs more slowly

Answers

Answer:

If the trains are moving at the same speed, the answer is A.

The clock in train B appears to be the same width and to run at the same rate. Option A is correct.

It is given that an observer on train A, which is moving close to the speed of light, views a clock in train B, which is stationary at the train station.

It is required to find how an observer would observe a clock in train B.

What would an observer on train A, which is in motion, view a clock in train B?

If a person is in a moving train, then his body is also in a state of motion with respect to the train at the same rate. When the observer observes any object that is at rest then it does not change the shape or size of an object. Also an object appears to run a=t the same rate due to the relative velocity attain by the observer's train.

Relative Motion is

Relative motion is the speed or the motion of an object with respect to the moving or the stationary object.

Thus the clock in train B appears to be the same width and to run at the same rate.

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difinition of gravity

Answers

Answer:

it's all around you and it can't be destroyed

Give three examples of material that refract light rays . What happens to the speed of light rays when they enter these materials ?

Answers

Water, glass, and diamond are three examples of materials that do this. These materials slow down the speed of light rays as they enter them while they are in the air.

What occurs to light's speed when it refracts?

Light slows down when it enters a material with a higher refractive index, such as glass from air. When facing the straight line, the light sways. Light moves more quickly when it enters a medium with a lower refractive index, as air from water.

Does refraction cause the speed of light to slow down?

Yes. Transparent materials like air, water, and glass slow down light. The refractive index of the medium, which is always greater than 1, is the ratio by which it is slowed.

What happens to light's speed as it travels from diamond to air?

The angle of refraction increases with increasing speed change. As an illustration, light refracts differently when it travels from air to diamond than when it travels from air to water. This is because of the fact that light travels more slowly in diamonds than it does in water.

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if you were standing on the far side of the moon, which object would you never see?

Answers

If you were standing on the far side of the moon, you would never be able to see the Earth.

The moon is tidally locked to Earth, which means that the same side of the moon always faces Earth. This is why we only ever see one side of the moon from Earth. Similarly, if you were standing on the far side of the moon, the Earth would always be blocked from view by the moon itself. So, no matter where you stood on the far side of the moon, you would never be able to see the Earth.

In addition, there are no other objects in space that would consistently block the view of the Earth from the far side of the moon. So, the only thing preventing you from seeing the Earth would be the moon itself.

Overall, standing on the far side of the moon would offer a unique and breathtaking view of the universe, but unfortunately, the Earth would not be visible from that vantage point.

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T/F Assuming the same velocity at take-off, with the exception of a take-off angle of 45 degrees, there are two take-off angles that will give identical range.

Answers

The given statement is true. Assuming the same velocity at take-off, with the exception of a take-off angle of 45 degrees, there are two take-off angles that will give identical range.

These two take off angles are complementary angles, which means their sum equals 90 degrees. If one angle is θ, the other angle will be (90 - θ). This is because the range of a projectile is determined by both its initial velocity and launch angle, and the range equation has a sine function, which exhibits symmetry for complementary angles.Hence, there are two take-off angles that will give identical range.

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Two capacitors have the same size of plates and the same distance 4 mm between the plates The potentials of the two plates in capacitor 1 are 16 volts and 16 volts The potentials of the two plates in capacitor 2 are 320 volts and 352 volts a What is the electric field inside capacitor 1

Answers

Answer:

    E = -4000 N / C

Explanation:

The potential and electric field are related

         V = - E s

          E = - V / s

we reduce the magnitudes to the SI system

          s = 4 mm (1 m / 1000 mm) = 0.004 m

we calculate

          E = - 16 /0.004

          E = -4000 N / C

A bob attached to a string of length L = 1.25 m, initially found at the equilibrium
position, is given an initial velocity v = 0.8 m/s. The maximum displacement angle,
Omax, is: (Take g=10 m/s)
17
3.2
13
10.2
6.4
Clear selection
A hoh attached to a string of length 2 m is displaced by an angle of 8º and then

A bob attached to a string of length L = 1.25 m, initially found at the equilibriumposition, is given

Answers

The maximum displacement angle of the bob is 13⁰.

The given parameters;

Length of the pendulum, L = 1.25 mInitial velocity of the bob, v = 0.8 m/s

The maximum displacement of the bob is calculated by applying the principle of conservation of energy;

\(P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\h = \frac{v^2}{2g} \\\\h = \frac{0.8^2}{2\times 10} \\\\h = 0.032 \ m\)

The maximum displacement angle is calculated as follows;

\(cos \theta = \frac{L-h}{L} \\\\cos \theta = \frac{1.25 - 0.032}{1.25} \\\\\cos \theta = \frac{1.218}{1.25} \\\\cos \theta = 0.9744\\\\\theta = cos^{-1}(0.9744)\\\\\theta = 13\ ^0\)

Thus, the maximum displacement angle of the bob is 13⁰.

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Calculate the momentum of a 450 kg bear riding a 17 kg bike, moving at 9 m/s

Answers

17kg+450kg= 467kg
467kg•9m/s= 4203kg/m/s

A car was traveling at a velocity of 8 m/s and then accelerated at a rate of 5 m/sr^2, reaching a velocity of 85 m/s. How far did the car travel at this acceleration rate?

Answers

Answer:

716.1 m

Explanation:

A car was travelling at a velocity of 8m/s

It accelerated at 5m/s^2

It finally reached a velocity of 85m/s

The distance can be calculated by applying the fourth equation of motion

V^2= U^2 +2as

V= 85m/s

U= 8m/s

a= 5m/s^2

85^2= 8^2 + 2(5)(s)

7225= 64 + 10s

7225-64= 10s

7161=10s

s= 7161/10

= 716.1 m

Hence the car travelled at a distance of 716.1 m

On the line between the two light sources, how far from the stronger light is the total illumination least?

Answers

If the distance from the stronger light source to the equidistant point is 'd', the distance from the weaker light source to the equidistant point will also be 'd'.

The total illumination will be least on the line between the two light sources at a point where the distances from the two light sources are equal.

This point is called the equidistant point. At this point, the stronger light source and the weaker light source will cancel out each other's illumination, resulting in the least total illumination.

To find the distance of the equidistant point from the stronger light source, you can use the inverse square law of light intensity. According to this law, the intensity of light decreases with the square of the distance.

Therefore, if the distance from the stronger light source to the equidistant point is 'd', the distance from the weaker light source to the equidistant point will also be 'd'.

To summarize, the total illumination will be least on the line between the two light sources at a point equidistant from both light sources. The distance of this point from the stronger light source will be equal to the distance from the weaker light source.

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express the following quantites of mass (in units of grams) using the metric prefixes rather than scientific notion

1.9x10^-2g
5.2x10^12g
4.1x10^-18g
3.91x10^15g

Answers

The prefixes are;

9x10^-2g - 9cg5.2x10^12g - 5.2 pg4.1x10^-18g - 4.1 Eg91x10^15g - 91 Pg

What is the metric system?

The metric system is one of the systems of measurement that is in common use. We know that there are many different systems of measurement that are in common use. However, the metric system is more current because is the system that helps us to be able to obtain a lot of the values that we use in science today.

Now the metric system  is  largely made up of the gram, the centimeter and the second. This has helped to make the measurement of scientific quantities very easy all over the world. We do have the subunits of these units in the metric system which are obtained by the use of prefixes.

Let us now write the prefixes;

9x10^-2g - 9cg5.2x10^12g - 5.2 pg4.1x10^-18g - 4.1 Eg91x10^15g - 91 Pg

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if a magnetic field cannot increase a particles velcotiy how do particle accelerators using electromagntic fields work

Answers

Particle accelerators use electromagnetic fields to accelerate particles by exerting a force on them.

The magnetic field alone cannot increase a particle's velocity, but when combined with an electric field, it can

accelerate charged particles. This is because the magnetic field causes the particles to move in a circular path, while

the electric field provides the necessary energy to increase the speed of the particles as they move along this path.

Therefore, the electromagnetic field works by combining the effects of both the electric and magnetic fields to

accelerate particles in a controlled manner.

Particle accelerators work by utilizing both electric and magnetic fields to increase the energy of charged particles.

While it's true that magnetic fields alone cannot increase the velocity of a particle, they play an essential role in

controlling the particle's trajectory. On the other hand, electric fields are responsible for increasing the velocity of

charged particles.


Here's a step-by-step explanation of how particle accelerators work using electromagnetic fields:

1. Charged particles are introduced into the accelerator.

2. Electric fields provide the necessary force to accelerate the particles, increasing their velocity.

3. Magnetic fields guide and steer the particles along the desired path or into circular orbits.

4. As particles move through alternating electric fields, they continue to gain energy and increase their velocity.

5. When particles reach the desired energy level, they can be directed toward a target or collision point for experiments.

In summary, particle accelerators use electromagnetic fields to control and increase the velocity of charged particles. Electric fields accelerate the particles, while magnetic fields guide their trajectory.

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Could someone please help me..?
Protons:
A. are found in the nucleus and are "locked" in.
B. are found on energy levels and are "locked" in.
C. are found in the nucleus and are able to travel.
D. are found on energy levels and are able to travel.

Answers

Answer:

a

Explanation:

are found in the nucleus and are locked in

Answer:

A

Explanation:

Thats what I think the answer is because protons and neutrons bond together in the nucleus.

Identify the primary effect of each situation on capillary forces. Choose one for each of the following.
a. Increasing the surface tension of the liquid
b. Decreasing the contact angle between the liquid and solid surface
c. Increasing the viscosity of the liquid
d. Decreasing the temperature of the liquid

Answers

The primary effect of increasing the surface tension of the liquid is to increase the capillary force. Capillary forces arise due to the combined effects of adhesion and cohesion

When the surface tension of the liquid increases, the capillary rise will increase. It is because the increase in surface tension leads to an increase in the force that pulls the liquid upwards in a tube. is as follows;If you place a capillary tube in a beaker filled with water, the water surface inside the tube rises slightly higher than the level outside the tube.

This rise in water level is called capillary rise. The capillary rise is caused by the attraction between the molecules of the water and the molecules of the glass tube.This attraction is called capillary force or capillary action. The capillary force is due to the combined effect of adhesive and cohesive forces. The adhesive force is the attraction between the molecules of the liquid and the molecules of the solid surface, while the cohesive force is the attraction between the molecules of the liquid.

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50 joules of energy are transferred out of a system. The energy is lost through heat, mechanical, and electrical energy took up 15 j and electrical energy took up 10 j, how many joules were lost through heat energy?

Answers

Answer:

25 joules

Explanation:

Not sure I understood correctly but since 15 are taken up by mechanical energy and 10 are taken in by electrical, 50-10-15 would result in 25 joules which must belong to heat energy

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