Answer:
At the moment, the truck's momentum (in kg · m/s) is 2200 times as large as the truck's speed (in m/s).
This means that as the truck travels, the truck's momentum (in kg · m/s) is always 2200 times as large as the truck's speed (in m/s).
If the truck is travelling at 16 m/s, the truck's momentum is 35200 kg · m/s.
Explanation:
From the question,
The truck's momentum (in kg · m/s) is proportional to the truck's speed (in m/s).
Let the truck's momentum be P and the truck's speed be v,
Then we can write that
P∝v
Then,
P = kv
Where k is the proportionality constant
From the question,
At some moment the truck's momentum is 50600 kg · m/s and the truck's speed is 23 m/s,
To determine how many times the truck's speed is as large as the truck's momentum at this moment, we will divide the truck's momentum by the speed, that is
50600 ÷ 23 = 2200
Hence, at the moment, the truck's momentum (in kg · m/s) is 2200 times as large as the truck's speed (in m/s).
Since, dividing the truck's momentum by the truck's speed gives the proportionality constant k (that is, P/v = k), then
This means that as the truck travels, the truck's momentum (in kg · m/s) is always 2200 times as large as the truck's speed (in m/s).
From
P = kv
Then, k = P/v
At a moment, P = 50600 kg · m/s and v = 23 m/s
∴ k = 50600 kg · m/s ÷ 23 m/s = 2200 kg
k = 2200 kg
To determine the truck's momentum if the truck is traveling at 16 m/s
From
P = kv
k = 2200 kg
v = 16 m/s
∴ P = 2200 kg × 16 m/s
P = 35200 kg · m/s
Hence, if the truck is travelling at 16 m/s, the truck's momentum is 35200 kg · m/s.
1. Imagine that you take a 200.0 km trip. You travel the first half of the trip at 100.0 km/hr. Your speed for the second half is 50.0 km/hr. How much time does the entire trip take?
2. In the above problem, what is your average speed in km/hr and m/s
Answer:
Explanation:
Speed = Distance/Time
Given
Distance = 200km
Total speed = 100+50 = 150km/hr
Time = Distance/Speed
Time = 200/150
Time = 1.33hr
b) Average speed in km/hr is 150km/hr
Convert to m/s
150km/hr = 150 * 1000 m/1 * 3600s
150km/hr = 150,000/360
150km/hr = 416.67m/s
What is the period of revolution of a satellite with mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth)?
When a mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth), the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.
The period of revolution of a satellite with mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth) can be determined by using Kepler's third law which relates the period of revolution of a satellite to the average radius of its orbit.
Kepler's third law states that the square of the period of revolution of a satellite is proportional to the cube of the average radius of its orbit.
Mathematically, the law can be expressed as: T² = (4π² / GM) × R³Where T is the period of revolution, G is the gravitational constant, M is the mass of the earth, and R is the average radius of the orbit of the satellite.
To find the period of revolution of the given satellite, we can substitute the given values in the equation: R = 7480 km + 6370 km = 13850 kmM = 5.97 × 10²⁴ kgG = 6.67 × 10⁻¹¹ Nm²/kg²T² = (4π² / GM) × R³T² = (4π² / (6.67 × 10⁻¹¹ × 5.97 × 10²⁴)) × (13850 × 10³)³T² = 6.7182 × 10¹⁴ seconds²
Taking the square root of both sides, we get:T = 8.2079 × 10³ seconds
Therefore, the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.
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A 3.00 kg mass is traveling at an initial speed of 25.0 m/s. What is the magnitude of the force required to bring the mass to rest in a distance of 62.5 m?
Answer:
Answer is 7.50 N
Explanation:
What is the angular acceleration of a clock's second hand? What is the angular acceleration of a clock's minute hand?
The average angular acceleration of the second hand is zero because the angular speed is constant. The angular speed is 360 degrees/hour.
The angular acceleration of a clock's minute hand on a clock is π1800rad/s
What is an angular acceleration?Angular acceleration means the time rate of change of angular velocity. The second hand of a clock involves an angular displacement of 2π per minute. Its angular speed is w = 2p/60s = 0.105/s. The direction of w is perpendicular to the face of the clock, directing to the face of the clock. The average angular acceleration of the second hand is zero.
Therefore, the correct answer is as given above
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1. A car moves 20 m/s east for 5 sec, 10m/s north for 10 sec and then 30m/s west for 5 sec. Calculate a) displacement
b) average velocity
2. A cyclist ride his half journey at 10 m/s and the rest at 8 m/s. calculate his average speed.
please help me. i will help back
Try the solutions described in the attached picture, note the answers are marked with green colour.
Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a spring 30 centimeters. How much work is done in stretching the spring from 50 centimeters to 80 centimeters
The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.
Hooke's LawHooke's law states that the force applied to an elastic material is directly proportional to its extension, provided its elastic limit is not exceeded.
To calculate the amount of work done by Hooke's law, first, we need to find the force constant of the spring.
Formula:
F = ke................. Equation 1Where:
F = Force appliedk = Spring constante = extensionmake k the subject of the equation
k = F/e................ Equation 2From the question,
Given:
F = 450 Ne = 30 cm = 0.3 mSubstitute these values into equation 2
k = 450/0.3k = 1500 N/m.Finally, To find the work done in stretching the spring from 50 cm to 80 cm, we use the formula below.
W = ke²/2........... Equation 3Where:
W = Work donek = spring constante = extensionAlso, From the question,
Given:
e = (80-50) = 30 cm = 0.3 mk = 1500 N/mSubstitute these values into equation 3
W = 1500(0.3²)/2W = 67.5 J.Hence, The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.
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If a space probe moves 20 m in 4 s, how fast is it moving?
Answer:
Speed =distance/time.
=20/4
=5m/s.
Formula: s = d/t
s = speed
d = distance
t = time
Solve using the values we are given.
s = 20/4
s = 5m/s
best of Luck!
Annalise observes a streak of light in the sky and says she is seeing a shooting star. What is she most likely
observing?
a falling star
an asteroid
O a meteor
O a dwarf planet
Answer:
A meteor
Explanation:
It travels so fast, that when it enters earth's atmosphere it burns up leaving that trail of fire which makes it look like a shooting star.
Answer:
meteor
Explanation:
Its right on edge 2021!
A string that passes over a pulley has a 0.341 kg mass attached to one end and a 0.625 kg mass attached to the other end. The pulley, which is a disk of radius 9.00 cm , has friction in its axle.What is the magnitude of the frictional torque that must be exerted by the axle if the system is to be in static equilibrium? (Answer should be in N m)
Answer:
The frictional torque is \(\tau = 0.2505 \ N \cdot m\)
Explanation:
From the question we are told that
The mass attached to one end the string is \(m_1 = 0.341 \ kg\)
The mass attached to the other end of the string is \(m_2 = 0.625 \ kg\)
The radius of the disk is \(r = 9.00 \ cm = 0.09 \ m\)
At equilibrium the tension on the string due to the first mass is mathematically represented as
\(T_1 = m_1 * g\)
substituting values
\(T_1 = 0.341 * 9.8\)
\(T_1 = 3.342 \ N\)
At equilibrium the tension on the string due to the mass is mathematically represented as
\(T_2 = m_2 * g\)
\(T_2 = 0.625 * 9.8\)
\(T_2 = 6.125 \ N\)
The frictional torque that must be exerted is mathematically represented as
\(\tau = (T_2 * r ) - (T_1 * r )\)
substituting values
\(\tau = ( 6.125 * 0.09 ) - (3.342 * 0.09 )\)
\(\tau = 0.2505 \ N \cdot m\)
Answer:here to earn points
Explanation:
have a difinite shape and do not easily take the shape of their containers
A plank AB 3m long weighing 20kg and with center of gravity 2m from the end A carries a load of mass 10kg at the end A it rests on two supports CandD.
1, compute the values of the reaction forces R1 and R2 at C and D.
2, how far from D and on which side of it must a mass of 24kg be placed on the plank so as to make the reactions equal? What are their values.
3,without this 24kg what vertical force applied at B will just lift the plank clear of D? What is then the reaction at C.
The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.
1) R1 and R2 at C and D respectively are given by the equation R2 = (m1 + m2)g - R1, where m1 and m2 are the masses of the plank and load, respectively, and g is the acceleration due to gravity. Hence, substituting values R2 = (20 + 10) × 9.81 - R1 = 294.3 - R1. Now, taking moments about D, the following equation can be obtained: (20 × 1 + 10 × 3)g = R1 × 2 + R2 × 3 = 2R1 + 3 × (294.3 - R1) = 882.9 - R1, from which R1 = 343.7 N and R2 = 294.3 - 343.7 = -49.4 N. Since the support at D can only push the plank upwards and cannot pull it downwards, a negative value for R2 implies that the plank is actually being pulled downwards by an external force. Therefore, the value of R2 is not relevant. 2) The total weight of the plank and the load acting at the end A is 20 + 10 = 30 kg. For the reactions at C and D to be equal, the 24 kg mass must be placed at a distance x from D such that x × 30 = 24 × 6, from which x = 12/5 = 2.4 m. Since the 24 kg mass is being placed to the left of the plank, it will cause the reaction at C to decrease and that at D to increase. Thus, if R is the vertical force applied at B, then taking moments about D gives 20g × 1 - 10g × 3 + R × 6 = 0, from which R = 90 N. Taking moments about C gives R × 3 - 10g × 2 = 0, from which R = 66.3 N. 3) The vertical force applied at B that will just lift the plank clear of D is the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D. The weight of the plank and the load acting at the end A is 20 + 10 = 30 kg, and the weight of the part of the plank that is to the right of D is 24 × 1.6 = 38.4 kg. Therefore, the vertical force applied at B that will just lift the plank clear of D is (20 + 10 + 38.4)g = 686.4 N. The reaction at C is zero because the plank is not being supported there anymore. The reaction at D is the same as the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D, which is 20 + 10 + 24 × 1.6 = 61.4 kg.For more questions on acceleration
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for a moving object distance covered by it is always greater than or equal to the displacement of the object in a given time. explain.
☯ Distance is a scalar quantity and has only magnitude but no direction.
☯ Displacement is a vector quantity and has both magnitude and direction.
☯ Distance can only have +ve values whereas displacement can be +ve, -ve or even be zero.
Unit 2 Test Study Guide (Electricity and Magnetism)
1. How does distance affect gravitational force between 2 objects?
2. How does mass affect gravitational force between 2 objects?
3. Draw a bar magnet with the magnetic field lines and be able to identify a diagram of this.
4. What are the parts of an electromagnet?
5. What is a solenoid?
6. What are 2 ways to strengthen an electromagnet?
7. What happens to the magnetic force in an electromagnet if the electricity is turned off?
8. How could you test the strength of an electromagnet?
9. Besides the amount of mass an electromagnet produces, what else could you use to measure the strength? (Think about the 2 factors affecting magnetic force between objects).
10. What is electromagnetic induction?
11. Moving a permanent magnet through a coil of wire attached to a circuit produces what?
12. What do ammeters and galvanometers do?
13. What mechanism do they use for this?
14. What is the role/purpose of the generator in a hydroelectric power plant (or any power plant)?
15. What are the energy conversions in an electric generator?
16. What happens when electric current
flows into a simple electric motor?
17. What are the energy conversions in an electric motor?
18. Would an electromagnet or an electric motor include a spinning magnet?
19. What energy source produces light in a flashlight you have to crank?
20. What device uses a rotating coil of wire in a magnetic field to produce motion?
21. What device increases or decreases electrical energy?
1. The gravitational force between two objects decreases as the distance between them increases.
What is gravitational?Gravitational force is the attraction between two objects that is produced by their masses.
2. The gravitational force between two objects increases as the mass of one of the objects increases.
3. A bar magnet with magnetic field lines looks like a line of arrows pointing from the North Pole to the South Pole.
4. The parts of an electromagnet are the core, the coil, and the electricity.
5. A solenoid is a coil of wire wrapped around a core, usually made of iron, that produces a magnetic field when electricity is passed through it.
6. Two ways to strengthen an electromagnet are to increase the number of coils in the solenoid and to increase the strength of the electric current.
7. When the electricity is turned off, the magnetic force in an electromagnet decreases.
8. To test the strength of an electromagnet, you can measure the amount of mass it produces when it is turned on.
9. Besides the amount of mass an electromagnet produces, you can also measure the strength by measuring the current and number of turns in the coil.
10. Electromagnetic induction is the production of an electric current when a magnetic field is changed.
11. When a permanent magnet is moved through a coil of wire attached to a circuit, it produces an electric current.
12. Ammeters and galvanometers measure electric current in a circuit.
13. They use the principle of electromagnetic induction to measure the electric current in a circuit.
14. The generator in a hydroelectric power plant (or any power plant) is used to convert mechanical energy from the turbine into electrical energy.
15. In an electric generator, mechanical energy is converted into electrical energy through electromagnetic induction.
16. When electric current flows into a simple electric motor, it causes a spinning magnet to move and generate motion.
17. In an electric motor, electrical energy is converted into mechanical energy through electromagnetic induction.
18. An electromagnet does not include a spinning magnet, while an electric motor does.
19. The energy source that produces light in a flashlight you have to crank is mechanical energy.
20. The device that uses a rotating coil of wire in a magnetic field to produce motion is an electric motor.
21. A transformer is a device that increases or decreases electrical energy.
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A baseball (m = 140 g) traveling at 30. m/s moves a fielder's glove backward 35 cm when the ball is caught.
What was the average force exerted by the ball on the glove?
Answer:
180
Explanation:
1) E=F*L, where E - energy of the baseball, F - the required force, L - backward moving (0.35m);
2) E=mV²/2, where E - energy of the baseball, m - the mass of the baseball (0.14kg), V - the velocity of the baseball (30m/s).
3) if E=F*L and E=mV²/2, then F*L=mV²/2, from which
\(F=\frac{mV^2}{2L};\)
4) according to the last formula
\(F=\frac{0.14*900}{2*0.35}=\frac{126}{0.7}=180(N).\)
The force exerted by the ball on the glove is 180 Newtons.
In mechanics, a force is any action that has the potential to change, maintain, or deform a body's motion. The three principles of motion outlined by Isaac Newton in his Principia Mathematica are frequently used to illustrate the concept of force (1687).
Newton's first law states that a body at rest or moving uniformly in a straight line will stay in that state until a force is applied to it. According to the second law, a body will accelerate (change in velocity) in the direction of any external force acting on it.
Given:
A baseball (m = 140 g) traveling at 30 m/s moves a fielder's glove backward 35 cm when the ball is caught,
Calculate the value of force as shown below,
Force = m × V² / 2L
Force = 0.140 × 30² / 2 × 0.35
Force = 0.140 × 900 / 0.70
Force = 126 / 0.7
Force = 180 N
Thus, the force exerted by the ball is 180 Newtons.
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Where can you find most of earths freshwater
Answer:
HEY PLS LISTEN THERE IS A GUY GOING AROUND TELLING GIRLS TO JOIN HIS ZOOM ON BRAINLY AND MAKING ACCS AND STUFF TO MAKE PEOPLE JOIN HIS ZOOM.THE CODE IS 387 187 6280 HES A PEDXO AND TELLING GIRLS TO SHOW THERE BODIES TO HIM. SO PLEASE BE AWARE! COPY AND PASTE THIS TO SPREAD THE WORD!
Explanation:
HEY PLS LISTEN THERE IS A GUY GOING AROUND TELLING GIRLS TO JOIN HIS ZOOM ON BRAINLY AND MAKING ACCS AND STUFF TO MAKE PEOPLE JOIN HIS ZOOM.THE CODE IS 387 187 6280 HES A PEDXO AND TELLING GIRLS TO SHOW THERE BODIES TO HIM. SO PLEASE BE AWARE! COPY AND PASTE THIS TO SPREAD THE WORD!
Icecaps and Glaciers
Explanation:
Icecaps and Glaciers hold 68 percent of fresh water on earth :)
A storm system moves 5000km due east, then shifts course at 40 degrees north of east for 1500km. Calculate the storm’s resultant displacement
In hiking, what fitness component is required of you
The melting ice of a glacier represents what type of change
a. transitional
b. physical
c. chemical
d. transformative
Answer:
PHYSICAL CHANGE
Explanation:
PLEASE DON'T JUST IGNORE IT
I HOPE I WILL GET A GOOD RESPONSE
Calculate the average (mean) of these numbers: 6, 5, 7, 9.8*
1. 35
2. 8.75
3. 5
4. 7
Answer:
13.94 to 2 d.p
Explanation:
just add them all up and i am confused the ones you said or the ones listed ?
the one i did was the listed ones
PLEASE ANSWER THIS WILL MARK AS BRAINLIEST PLEASE USE TRUTHFUL ANSWERS PLEASE
Which best explains why species living in Australia are found nowhere else on Earth? This is an example of Geologic Evolution.
A.
Australia has an ecosystem different from any other area on Earth.
B.
Humans have genetically altered many Australian species in laboratories.
C.
Australian species were genetically altered after a comet hit the landmass.
D.
Australia separated from other continents and species there evolved independently.
Please help! Will mark brainliest.
Answer:
736.2
Explanation:
Work = mass * gravity * height
W = m * g * h
W = 6.26 * 9.8 * 12
W= 736.176 Joules
Rounding to 736.2.
Fossils are remains of organisms found in sedimentary rock. These remains are found in thousands of rock layers around the world and provide evidence for Earth's long history of changing lifeforms.
Rock layers that formed more recently
Answer:
metamorphic rocks
Explanation:
I hope this helps you, I'm sorry if it's wrong!
If it's right please don't forget to mark me as brainliest!
Answer:
the top layers
Explanation:
sedimentary layers are deposited on top of each other over time
4
Select the correct answer from each DROP-DOWN MENU.
A graph plots time in seconds versus position (m). A line rises from a point A (0, 0) to a point B (4, unit 6) extends linearly through a point C (11, unit 6), and rises to a point D (12, unit 7 point 5).
The graph describes the motion of an object.
The object moves with
from A to B. It
from B to C. It moves with
from C to D.
Reset Next
(a) The object moves with uniform velocity from A to B.
(b) The object moves with constant velocity from B to C.
(c) The object moves with increasing velocity from C to D.
Velocity of the object from point A to B
V(A to B) = (6 - 0)/(4 - 0) = 1.5 m/s
Velocity of the object from point B to CV(B to C) = (6 - 6)/(11 - 4) = 0 m/s
Velocity of the object from point C to DV(C to D) = (7 - 6)/(12 - 11) = 1 m/s
final velocity = 1 + 1.5 m/s = 2.5 m/s
Thus, we can conclude the following;
The object moves with uniform velocity from A to B.
The object moves with constant velocity from B to C.
The object moves with increasing velocity from C to D.
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Answer:The object moves with
positive accelaration
from A to B. It
speeds up
from B to C. It moves with
constant velocity
from C to D.
Explanation:I took the test
answer and solution to this question
Frequency= 30 Hz, Period= 0.0333 s, Wave Number=15.708 rad/m, Wave Function= y(x, t) = 0.05 sin(15.708x - 94.248t), Transverse displacement= -0.013 m, Time= 0.297 s.
How to calculate the frequency?(a) To find the frequency (f), we can use the equation: wave speed = frequency x wavelength. Rearranging this equation, we get:
frequency = wave speed / wavelength
Substituting the given values, we get:
frequency = 12 m/s / 0.4 m = 30 Hz
Therefore, the frequency of the wave is 30 Hz.
To find the period (T), we can use the equation:
period = 1 / frequency
Substituting the frequency value we just calculated, we get:
period = 1 / 30 Hz = 0.0333... s (rounded to four decimal places)
Therefore, the period of the wave is approximately 0.0333 s.
To find the wave number (k), we can use the equation:
wave number = 2π / wavelength
Substituting the given values, we get:
wave number = 2π / 0.4 m = 15.708 rad/m (rounded to three decimal places)
Therefore, the wave number of the wave is approximately 15.708 rad/m.
(b) The wave function for a transverse wave on a string is given by:
y(x, t) = A sin(kx - ωt + φ)
where A is the amplitude, k is the wave number, x is the position of the point on the string, t is the time, ω is the angular frequency, and φ is the phase constant.
We already know the values of A, k, and ω from the previous calculations. To find φ, we can use the given initial condition: "at t = 0 end of the string has zero displacement and is moving upward". This means that y(0,0) = 0 and ∂y/∂t(0,0) > 0. Substituting these conditions into the wave function, we get:
0 = A sin(0 + φ)
∂y/∂t = -Aω cos(0 + φ)
Since sin(0 + φ) = sin(φ) = 0 (because sin(0) = 0), we get:
φ = nπ, where n is an integer
Since cos(0 + φ) = cos(φ) = 1 (because cos(0) = 1) and ∂y/∂t(0,0) > 0, we get:
n = 0 or 2
Therefore, the possible values of φ are 0 or 2π.
Substituting the values of A, k, ω, and φ, we get:
y(x, t) = 0.05 sin(15.708x - 94.248t)
Therefore, the wave function describing the wave is:
y(x, t) = 0.05 sin(15.708x - 94.248t)
(c) To find the transverse displacement of a wave at x = 0.25 m and t = 0.15 s, we can use the wave function we just found:
y(0.25, 0.15) = 0.05 sin(15.708(0.25) - 94.248(0.15))
y(0.25, 0.15) ≈ -0.013 m (rounded to three decimal places)
Therefore, the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m.
(d) To find how much time must elapse from the instant in part (c) until the point at x = 0.25 m has zero displacement,
From part (c), we know that the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m. We need to find the time it takes for this point to return to zero displacement.
We can use the wave function we found in part (b) and set y(0.25, t) = 0:
0 = 0.05 sin(15.708(0.25) - 94.248t)
Since sin(θ) = 0 when θ = nπ (where n is an integer), we get:
15.708(0.25) - 94.248t = nπ
Solving for t, we get:
t = (15.708(0.25) - nπ) / 94.248
To find the smallest positive value of t that satisfies this equation, we need to use the smallest positive value of n that makes the right-hand side of the equation positive (because we want to find the time it takes for the point at x = 0.25 m to return to zero displacement, which happens after the point has completed a full cycle). We can see from the equation that n must be an even integer to make the right-hand side positive. The smallest even integer greater than zero is 2. Substituting n = 2, we get:
t = (15.708(0.25) - 2π) / 94.248
t ≈ 0.297 s (rounded to three decimal places)
Therefore, the time it takes for the point at x = 0.25 m to return to zero displacement is approximately 0.297 s.
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Part C Now, grab Tracker’s protractor tool (the green angle in the video frame) and measure the angle of incidence and the angle of refraction for the frame numbers specified in the table below. Hints: To advance the video a frame at a time, use the step buttons on the right. Position the vertex of the protractor exactly at the origin of the coordinate axis. Move the arms of the protractor so that one arm is on the vertical axis (above or below, as appropriate) and the other on the light ray.
In order to measure the angle of incidence and the angle of refraction using Tracker's protractor tool (the green angle in the video frame), the following steps should be followed:
Step 1: Open the video in Tracker software.
Step 2: Click on the "Measure" button on the toolbar at the top of the software.
Step 3: From the dropdown menu, select "Angle".
Step 4: Click on the "protractor tool" icon (the green angle in the video frame).
Step 5: Position the vertex of the protractor exactly at the origin of the coordinate axis and move the arms of the protractor so that one arm is on the vertical axis (above or below, as appropriate) and the other on the light ray.
Step 6: Measure the angle of incidence and the angle of refraction for the frame numbers specified in the table below by using the step buttons on the right to advance the video a frame at a time.
Step 7: Record the measured angles in the table below. Note that the angle of incidence should be measured on the incident ray (the ray that is coming from the left), and the angle of refraction should be measured on the refracted ray (the ray that is coming from the right).In conclusion, by following these steps, one can measure the angle of incidence and the angle of refraction using Tracker's protractor tool.
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Một vật nhỏ khối lượng m = 200g được treo vào một lò xo khối lượng không đáng kể, độ cứng k = 80N/m. Kích thích để con lắc dao động điều hoà(bỏ qua các lực ma sát) với cơ năng bằng 6,4.10-2J. Gia tốc cực đại và vận tốc cực đại của vật lần lượt là
Explanation:
what is this language? ..............
What is the displacement (in miles, with direction) from the
Aquarium to the Cemetery?
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Why does heating water affect surface tension
As temperature increases, molecules of liquid become more active and they move more rapidly.
A thermionic tube with only a cathode and an anode is called?
a 22-kg chimpanzee hangs from the end of a horizontal broken branch the branch sags downward through a vertical distance of 13 cm treating the branch as a spring satisfying hooke's law what is its spring constant
The spring constant of the branch satisfying Hooke's law is 1,658.46 N/m.
The given parameters;
mass of the chimpanzee, m = 22 kgextension of the branch, x = 13 cm = 0.13 mThe spring constant of the branch satisfying Hooke's law is calculated as follows;
F = kx
mg = kx
\(k = \frac{mg}{x} \\\\k = \frac{22 \times 9.8}{0.13} \\\\k = 1658.46 \ N/m\)
Thus, the spring constant of the branch is 1,658.46 N/m.
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