A truck accelerates from a speed of 5.6 m/s to 8.1 m/s in 5.0 seconds. The average rate of acceleration during
this 5.0-seconds is approximately-
0.5m/s/s
1.1 m/s/s
1.6 m/s/s
2.7 m/s/s

Answer:

table??

Explanation:

The degree of data stability when the measurement is replicated under identical circumstances is known as reproducibility or reliability.

Reproducibility determines how an entire study an experiment can be replicated, whereas repeatability assesses the variation in data made by a single equipment or human under similar circumstances.

Science needs reproducibility because it enables more in-depth investigation, and replication validates our findings. There are several investigations and experiments, which result in a wide range of variables, unforeseen, and things that are either outside your influence or you cannot guarantee.

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Answer:

D

Explanation:

A and C are balanced, B has a resultant force of 5N right, and D has a resultant force of 20N right.

To determine the magnitude of the lift force ⃗ and the force of air resistance ⃗ acting on the jet, we need to resolve the weight ⃗ and the forward thrust ⃗ into their horizontal and vertical components.

The weight ⃗ can be resolved into two components:

- the vertical component, Wsin(30°), acting downward

- the horizontal component, Wcos(30°), acting to the left

The forward thrust ⃗ can also be resolved into two components:

- the vertical component, Tsin(30°), acting upward

- the horizontal component, Tcos(30°), acting to the right

Since the jet is flying at a constant speed, the lift force ⃗ must be equal in magnitude to the weight component acting downward, Wsin(30°). Therefore, the magnitude of ⃗ is 86,500 Nsin(30°) = 43,250 N.

The force of air resistance ⃗ is equal in magnitude to the horizontal component of the weight, Wcos(30°), minus the horizontal component of the forward thrust, Tcos(30°). Therefore, the magnitude of ⃗ is (86,500 Ncos(30°)) - (103,000 Ncos(30°)) = -8,715 N, where the negative sign indicates that the force of air resistance is acting in the opposite direction to the motion of the jet.

Therefore, the magnitude of the lift force ⃗ is 43,250 N and the magnitude of the force of air resistance ⃗ is 8,715 N.

The energy lost to friction and air resistance is 186 J.

option B.

The energy lost to friction and air resistance is calculated from the change in the mechanical energy of the pendulum.

The initial potential energy of the pendulum at the initial position is calculated as;

PEi = mghi

where;

P.Ei = 12 kg x 9.8 m/s² x 20 m

P.Ei = 2,352 J

The final kinetic energy of the pendulum is calculated as follows;

K.Ef = 0.5 x 12 kg x (19 m/s)²

K.Ef = 2,166 J

ΔE = 2,166 J - 2,352 J

ΔE = -186 J

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The head loss doubles when the average velocity is doubled.

The vector quantity velocity (v), denoted by equation v = s/t, quantifies dislocation (or shift in position, s), over change in time (t).

Velocity is the pace and direction of the an object's movement, whereas speed is the timekeeping at which an object is travelling along a path.In other words, velocity is a vector, whereas speed is indeed a scalar value.

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Answer:

The two answers that are likely to be true are:

She will think of the results as an opportunity to find joy.

She will identify areas for self-development in her results.

By setting her mind on growth, Jackie is likely to approach the personality test with a positive and open mindset. This can lead to the following outcomes:

She will think of the results as an opportunity to find joy: Jackie may view the test results as a chance to discover aspects of her personality that bring her joy and satisfaction. She might focus on finding strengths and positive qualities that can contribute to her personal and professional growth.

She will identify areas for self-development in her results: Rather than viewing the test results as fixed labels or limitations, Jackie is likely to see them as valuable feedback for self-improvement. She may actively seek out areas where she can further develop her skills, knowledge, and personality traits to enhance her personal and career growth.

It's important to note that the other options listed in the question (1. She will score high in the areas she chooses to and 2. She will respond based on what's best in her desired career path) are not directly related to having a growth mindset. They suggest a more biased or strategic approach to the test, which may not align with the concept of growth and self-improvement.

An increase in the spring constant changes will result in a larger frequency for an oscillating spring-mass system.

The mass spring system is a system composed of objects that have mass and are connected to springs. The spring circuit can be composed of several springs mounted in series or parallel as needed. Springs connected in series will decrease the value of the spring constant, while the installation of springs in parallel will increase the value of the spring constant.

Spring system formation is a simple spring system formation arranged in series or parallel. The stages of the research carried out included determining the mathematical equation for mass movement determined from the equilibrium position in the formation of a spring system, including a spring system of a mass connected to two springs arranged in series, a spring system of a mass connected to two springs arranged in parallel and a spring system of two masses. connected by two springs arranged in series, then create a spring system simulation program.

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Answer:

3000m

Explanation:

The second submarine is located 3000 meters away from the first submarine.

Wavelength is a property of waves that describes the distance between two consecutive points on the wave that are in phase with each other. In other words, it is the distance between two points on a wave that are at the same stage of their cycle, such as two consecutive crests or two consecutive troughs.

Wavelength is usually denoted by the Greek letter lambda (λ), and its unit of measurement depends on the type of wave being considered. For example, in the case of electromagnetic waves such as light, wavelength is typically measured in meters (m), while in the case of sound waves, wavelength is typically measured in units of length such as meters (m) or centimeters (cm).

Here in the question,

The speed of sound in water is approximately 1500 meters per second. We can use the speed of sound, the frequency of the signal, and the wavelength of the signal to calculate the distance between the two submarines.

First, we need to calculate the period of the signal, which is the time it takes for one complete cycle. The period can be calculated as the reciprocal of the frequency:

Period = 1 / Frequency = 1 / 512 cycles per second = 0.001953125 s

Next, we can use the time it takes for the signal to travel to the other submarine and back to calculate the round-trip time:

Round-trip time = 4.00 s

Finally, we can use the round-trip time and the speed of sound to calculate the distance between the two submarines:

Distance = (Round-trip time x Speed of sound) / 2

Distance = (4.00 s x 1500 m/s) / 2 = 3000 m

Therefore, the second submarine is located 3000 meters away from the first submarine.

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Answer:

24KHz

Explanation:

See attached file

Given :

To Find :

The falling apple's kinetic energy, gravitational potential energy, and total mechanical energy.

Solution :

We can use the conservation of energy principle to find the apple's kinetic energy, gravitational potential energy, and total mechanical energy at the height of 3.0m above the ground.

First, we need to find the gravitational potential energy (GPE) of the apple when it is at the height of 4.0m above the ground:

GPE = mgh

where m is the mass of the apple, g is the acceleration due to gravity (9.81 m/s^2), and h is the height above the ground.

So, GPE = (0.21 kg) x (9.81 m/s^2) x (4.0 m) = 8.2266 J

Next, we find the apple's kinetic energy (KE) just before it hits the ground. We can use the conservation of energy principle, "which states that a system's total mechanical energy is conserved (i.e., it remains constant) if no external forces are acting on it." In this case, gravity is the only force acting on the apple, an internal force within the system (i.e., the apple and the Earth).

So, at the height of 3.0m above the ground, the total mechanical energy (TME) of the system is:

TME = GPE + KE

Since the apple is falling freely, we can assume that all of its potential energy at the height of 4.0m has been converted into kinetic energy just before it hits the ground. Therefore, at the height of 3.0m above the ground, the GPE is:

GPE = (0.21 kg) x (9.81 m/s^2) x (3.0 m) = 6.1359 J

Using the conservation of energy principle, we can find the kinetic energy just before the apple hits the ground:

TME = GPE + KE

KE = TME - GPE = (0.21 kg) x (9.81 m/s^2) x (4.0 m) - 6.1359 J = 2.0907 J

Therefore, the kinetic energy of the apple just before it hits the ground is 2.0907 J.

To summarize:

Gravitational potential energy (GPE) of the apple at a height of 4.0m above the ground: 8.2266 J

Gravitational potential energy (GPE) of the apple at a height of 3.0m above the ground: 6.1359 J

Kinetic energy (KE) of the apple just before it hits the ground: 2.0907 J

The system's total mechanical energy (TME) is conserved throughout the fall.

The East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).

Isaac's force:

Magnitude: 255 N

Angle: 13 degrees North of East

x-component: 255*cos(13) = 245.1 N (Eastward)

y-component: 255*sin(13) = 58.1 N (Northward)

Newton's force:

Magnitude: 156 N

Angle: 34 degrees South of East

x-component: 156*cos(34) = 129.4 N (Westward)

y-component: 156*sin(34) = 86.5 N (Southward)

Now we can add the x- and y-components of the forces to find the net force:

Net force:

x-component: 245.1 N - 129.4 N = 115.7 N (Eastward)

y-component: 58.1 N - 86.5 N = -28.4 N (Southward)

The net force has an Eastward component of 115.7 N. Therefore, the East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).

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Answer:

C) The book's inertia carried it forward.

When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.

To find the distance between the two points we use the Pythagorean theorem and the distance between the two points is 11 units.

To find the distance between two points on a coordinate plane, you can use the distance formula. The distance formula is derived from the Pythagorean theorem and is given by:

d = √[(x2 - x1)² + (y2 - y1)²]

In your case, the starting point is (-6, 4) and the endpoint is (5, 4). Plugging these values into the distance formula, we have:

d = √[(5 - (-6))² + (4 - 4)²]

= √[(5 + 6)² + (0)²]

= √[11² + 0²]

= √[121 + 0]

= √121

= 11

Therefore, the distance between the two points is 11 units.

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Answer:

108 N

Explanation:

Use Newton's second law.

F = ma

F = (90 kg) (1.2 m/s²)

F = 108 N

Answer:

 h '= [ ( \frac{ M-m}{M +m  } )+ 2 (\frac{M}{M+m})]²  h

Explanation:

Let's analyze this problem, first the two bodies travel together, second the superball bounces, third it collides with the marble and fourth the marble rises to a height h ’

let's start by finding the velocity of the two bodies just before the collision, let's use the concepts of energy

starting point. Starting point

         Em₀ = U = m g h

final point. Just before the crash

         Em_f = K = ½ m v²

as there is no friction the mechanical energy is conserved

         Em₀ = Em_f

         mg h = ½ m v²

         v = √2gh

this speed is the same for the two bodies.

Second point. The superball collides with the ground, this process is very fast, so we will assume that the marble has not collided, let's use the concept of conservation of moment

initial instant. Just when the superball starts contacting the ground

      p₀ = M v

this velocity is negative because it points down

final instant. Just as the superball comes up from the floor

      p_f = M v '

the other body does not move

      p₀ = p_f

     - m v = M v '

       v ’= -v

Therefore, the speed of the asuperbola is the same speed with which it arrived, but in the opposite direction, that is, upwards.

Let's use the subscript 1 for the marble and the subscript 2 for the superball

Third part. The superball and the marble collide

the system is formed by the two bodies, so that the forces during the collision are internal and the moment is conserved

initial instant. Moment of shock

        p₀ = M \(v_{1'}\)+ m v_2

final instant. When the marble shoots out.

        P_f = Mv_{1f'}+ m v_{2f}

        p₀ = p_

        M v_{1'}+ m v_2 = M v_{1f'} + m v_{2f}

        M (v_{1'} - v_{1f'}) = -m (v_2 - v_{2f})

in this expression we look for the exit velocity of the marble (v2f), as they indicate that the collision is elastic the kinetic nerve is also conserved

       K₀ = K_f

       ½ M v_{1'}² + m v₂² = M v_{1f'}²  + ½ m v_{2f}²

        M (v_{1'}² - v_{1f'}²) = - m (v₂² - v_{2f}²)

Let's set the relation  (a + b) (a-b) = a² - b²

      M (v_{1'} + v_{1f'})  (v_{1'} - v_{1f'}) = -m (v₂ + v_{2f}) (v₂ - v_{2f})

let's write our two equations

           M ( v_{1'} - v_{1f'}) = -m (v₂ - v_{2f})                 (1)

           M (v_{1'} + v_{1f'})  (v_{1'} - v_{1f'}) = -m (v₂ + v_{2f}) (v₂ - v_{2f})

if we divide these two expressions

           (v_{1'}+ v_{1f'}) = (v₂ + v_{2f} )

we substitute this result in equation 1 and solve

          v_{1f'}= (v₂ + v_{2f}) - v_{1'}

          M (v_{1'} - [(v₂ + v_{2f}) - v_{1'}] = -m (v₂ - v_{2f})

           -M v₂ - M v_{2f1'} + 2M v_{1'} = m v₂ - m v_{2f}

          -M v_{2f} -m v_{2f} = m v₂ -M v₂ + 2M v_{1'}

          v_{2f} (M + m) = - v₂ (M-m) + 2 M v_{1'}

          v_{2f} = - \(( \frac{ M-m}{M +m } )\)) v₂ + 2 \((\frac{M}{M+m})\) v_{1'}

now we can substitute the velocity values ​​found in the first two parts

          \(v_{2f}\) = - ( \frac{ M-m}{M +m  } ) √2gh + 2(\frac{M}{M+m}) √2gh

we simplify

          v_{2f} = [( \frac{ M-m}{M +m  } ) + 2 (\frac{M}{M+m})] \(\sqrt{2gh}\)

let's call the quantity in brackets that only depends on the masses

          A = ( \frac{ M-m}{M +m  } )+ 2 (\frac{M}{M+m})]

           v_{2f}= A \sqrt{2gh}

in general, the marble is much lighter than the superball, so its speed is much higher than the speed of the superball

finally with the conservation of energy we find the height that the marble reaches

Starting point

          Emo = K = ½ mv_{2f}²

Final point

          Emf = U = m g h'

          Em₀ = Em_f

          ½ m v_{2f}² = m g h ’

          h ’= ½ v_{2f}² / g

         h ’= ½ (A \sqrt{2gh})² / g

         h ’= A² h

         h '= [ ( \frac{ M-m}{M +m  } )+ 2 (\frac{M}{M+m})]²  h

When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.

The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.

Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:

Mass of air = Mass of filled container - Mass of empty container

= 0.428 kg - 0.419 kg

= 0.009 kg

Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:

Volume of air = Volume of perplex box * Number of times air inside

= 1000 cm³ * 7.2

= 7200 cm³

Convert the volume of air to cubic meters (m³) by dividing by 1000000:

Volume of air = 7200 cm³ / 1000000

= 0.0072 m³

Calculate the density of air using the formula:

Density = Mass / Volume

Density = 0.009 kg / 0.0072 m³

≈ 1.25 kg/m³

Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.

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The rate at which the price is increasing is approximately 140.74 dollars per year. The rate of growth given by the coefficient 1.65

The rocking chair's value is given by the equation \(V = 50(1.65t)\)

where V is the rocking chair's dollar worth and t is the number of years since 1975.

To find the rate at which the price is increasing, we need to take the derivative of V with respect to t.

\(dV/dt = 50(1.65)t(ln 1.65)\)

The age since 1975 can be substituted with the value of t. The number of years since 1975 would be t = 2023 - 1975 = 48 if t = 0 represents the year 1975.

In the equation above, t = 48 is substituted, and we obtain:

\(dV/dt = 50(1.65)^48(ln 1.65)\)

Using a calculator:

\(dV/dt = 140.74 dollars/yr\)

Thus, the price is rising at a pace of about 140.74 dollars per year. This indicates that since 1975, the rocking chair's worth has grown by $140.74 year. According to the equation for the rocking chair's value, the value is increasing exponentially with time at a rate provided by the coefficient of 1.65. This implies that the chair's rate of value growth will keep accelerating over time.

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Answer:

Explanation:

How much force is acting on a certain area

According to the law of collision'

m1u1 + m2u2 = (m1+m2)v

Given the following:

m1 = 22,680kg

u1 =170km/h

m2 = 1200kg

u2 = 5km/hr

Get the final velocity "v"

22680(170) + 1200(5) = (22680 + 1200)v

3855600 + 6000 = 12880v

3,861,600 = 12880v

v = 3,861,600/12,880

v = 229.82km/hr

Hence the final velocity of the objects is 229.82km/hr

Since energy was lost after the collision, the type of collision that occurs is an elastic collision.

According to Newton's second law, the formula for calculating the force is expressed as;

F = ma

F = m(v-u)/t

F = 22680+1200(229.82-175)/t

Ft = 23880(54.82)

F = 1,309,101.6/0.0012

F = 1,090,918,000N

Hence the required force is 1,090,918,000N

KE lost = Kinetic energy after collision - Kinetic energy before collision

Kinetic energy after collision = 1/2 * 12880 * 229.82²

Kinetic energy after collision = 340,142,976.656 Jolues

Kinetic energy before collision = 1/2 * 22680(170)²+ 1/2*1200(5)²

Kinetic energy before collision = 327,726,000 + 15000

Kinetic energy before collision = 327,741,000

Kinetic energy lost = 340,142,976.656 - 327,741,000 =  12,401,976.656Joules

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There are 90 phones of volume, 10-7 W/m2 of sound intensity, and 0.0314 watts of source power.

A straightforward frequency analysis compares the values of the fields you provide and generates a report listing each value for those fields along with the frequency at which each value occurs.

The rate at which a sound power wave repeats itself, also known as frequency or pitch, is measured in cycles per second. Bullfrog calls and cricket chirps have lower frequencies than drum beats and whistles, respectively.

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Answer:

correct answer is A

Explanation:

The diagram shows a series circuit with three resistors and two power sources.

In a series circuit the current through the entire circuit is constant and the resistance is the sum of the resistances in the circuit.

When the power sources are placed in opposite position the voltage between them is subtracted.

     V_b - 30 = I (10 + 4 + 6)

     V_b = I (20) - 30

      V_b = 30 - 2 20

       V_b = 10 V

the correct answer is A

D. Kinetic energy is converted to potential energy.

At point C, the pendulum is at its highest point, and the kinetic energy it has accumulated from the initial release at point A has been fully converted to potential energy. As the pendulum swings back toward point A, it will lose potential energy and gain kinetic energy until it reaches point A once again.

At point A, potential energy is converted to kinetic energy. At point C, the pendulum is at its highest point, and the kinetic energy has been fully converted to potential energy. As the pendulum swings back toward point A, it will lose potential energy and gain kinetic energy until it reaches point A once again.

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9514 1404 393

Answer:

  D. Segment D

Explanation:

The origin is represented on the graph by the position (y-value) being 0. The portion of the graph that shows position being non-zero and ending at 0 is the portion marked segment D.

When a butane lighter is lit, chemical energy transforms into heat energy.

Energy cannot be created or destroyed, says the law of conservation of energy. However, it has the ability to change its form. The total energy of an isolated system is constant when all sources of energy are taken into account.

The chemical energy is the bonds of chemical molecules contain energy. Exothermic reactions are those in which chemical energy is released during the reaction, frequently in the form of heat.

In butane energy is stored as a chemical energy as  bonds of chemical molecules and when it is lit, the chemical energy of the butane transforms into heat energy.

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