Answer:
s + b ≤ 2
Explanation:
If athletes train for no more than 2 hours a day, we have that the sum of the hours training swimming s and biking b should be less than or equal to 2. It means that we can write the following inequality:
s + b ≤ 2
So, the inequality that represents Mai's statement is:
s + b ≤ 2
What’s the correct answer for this?
Answer:
x = 19
Step-by-step explanation:
In the attached file
What information is needed to show that △ ABC ≅ △ DEF by SAS congruence?
In order to show that △ ABC ≅ △ DEF by SAS congruence, we need the sides of triangles ABC and DEF with the angle between the respective sides.
What do we understand by congruency of a triangle?Triangle congruence: Two triangles are said to be congruent if all three of their corresponding sides and all three of their corresponding angles have the same measurements. Slide, twist, flip, and turn these triangles to create an identical appearance. They are in alignment with one another when moved. "" is the congruence symbol. When two figures are comparable to one another in terms of their size and shape, this is what mathematicians mean by congruence. In essence, there are four congruence principles that demonstrate if two triangles are congruent. However, locating all six dimensions is essential. As a result, the congruence of triangles can be assessed using just three of the six variables.
Congruency Requirements:
SSS (Side-Side-Side)
SAS (Side-Angle-Side)
ASA (Angle-Side-Angle)
AAS (Angle-Angle-Side)
RHS (Right angle-Hypotenuse-Side)
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Condense each Logarithm
The equation of logarithm are solved and
a) A = 2 + 3 log x + 4 log b
b) B = ( 36 + x + y ) ( log 6 )
c) C = ( 1/2 )x log 5
d) D = ln ( x⁴ / y² )
Given data ,
Let the logarithmic equation be represented as A
Now , the value of A is
a)
A = 2 log 10 + 3 log x + 4 log b
The base of the logarithm is 10 , so
A = 2 + 3 log x + 4 log b
b)
B = log 6³⁶ + log 6ˣ - log 6^ ( y )
From the properties of logarithm , we get
log A + log B = log AB
log A − log B = log A/B
log Aⁿ = n log A
B = 36 log 6 + x log 6 + y log 6
On taking the common term , we get
B = ( 36 + x + y ) ( log 6 )
c)
C = ( 1/2 )log 5ˣ
From the properties of logarithm , we get
C = ( 1/2 )x log 5
d)
D = 4 ln x - 2 ln y
From the properties of logarithm , we get
D = ln x⁴ - ln y²
On further simplification , we get
D = ln ( x⁴ / y² )
Hence , the logarithmic equations are solved
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Can an opposite and an absolute value of an integer be the same?
Yes and opposite and an absolute value of an integer will be the same.
98.8% of 668.49 to 2DP
Answer:
Your answer is 660.47 :)
what is the most effluence first step to isolate the variable term on one side of this equation -9x=-4x+5
Pls help with this question pictured below.
The implicit derivative is given as follows:
dx/dt(x = 4) = 1/12.
How to obtain the implicit derivative?The function in this problem is given as follows:
y = 3x² + 1.
The implicit derivative, relative to the variable t, is given as follows:
dy/dt = 6x dx/dt.
(the derivative of the constant 1 is of zero).
The parameters for this problem are given as follows:
x = 4, dy/dt = 2.
Hence the derivative is obtained as follows:
2 = 6(4) dx/dt
dx/dt = 2/24
dx/dt = 1/12.
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Today, Thurber studies math for 15 minutes and he studies science for 75 minutes. From now on, Thurber plans to study math for 50 minutes per day and to study science for 30 minutes per day. Will Thurber ever have studied the same total amount of time for both math and science? Explain. Use the drop-down menus to complete the sentence. days from today, Thurber will have studied of math and minutes of science.
Answer:
3 days
Step-by-step explanation:
Given that :
Today :
Study time for math = 15 minutes
Study time for science = 75 minutes
Subsequent days :
Study time for math = 50 minutes
Study time for science = 30 minutes
Let the number of days when study time for math and science will be the same = x
15 + 50x = 75 + 30x
50x - 30x = 75 - 15
20x = 60
x = 60 / 20
x = 3
3 days
Morganton Company makes one product and it provided the following information to help prepare the master budget:
The budgeted selling price per unit is $60. Budgeted unit sales for June, July, August, and September are 8,600, 17,000, 19,000, and 20,000 units, respectively. All sales are on credit.
Thirty percent of credit sales are collected in the month of the sale and 70% in the following month.
The ending finished goods inventory equals 25% of the following month’s unit sales.
The ending raw materials inventory equals 10% of the following month’s raw materials production needs. Each unit of finished goods requires 5 pounds of raw materials. The raw materials cost $2.40 per pound.
Thirty five percent of raw materials purchases are paid for in the month of purchase and 65% in the following month.
The direct labor wage rate is $14 per hour. Each unit of finished goods requires two direct labor-hours.
The variable selling and administrative expense per unit sold is $1.80. The fixed selling and administrative expense per month is $67,000.
5. If 96,250 pounds of raw materials are needed to meet production in August, how many pounds of raw materials should be purchased in July?
Raw materials purchases in July - Payment for raw materials purchases in July = Desired ending raw materials inventory for July
X pounds - 0.35 * X pounds = 9,500 pounds
Solving this equation will give us the value of X, which represents the pounds of raw materials that should be purchased in July.
To determine the number of pounds of raw materials that should be purchased in July, we need to calculate the raw materials production needs for August and then consider the inventory policies given in the information provided.
Each unit of finished goods requires 5 pounds of raw materials. The budgeted unit sales for August are 19,000 units. Therefore, the raw materials production needs for August would be 19,000 units multiplied by 5 pounds per unit, which equals 95,000 pounds.
The ending raw materials inventory equals 10% of the following month’s raw materials production needs. Therefore, the desired ending raw materials inventory for July would be 10% of 95,000 pounds, which is 9,500 pounds.
To calculate the raw materials purchases for July, we need to consider the payment terms provided. Thirty-five percent of raw materials purchases are paid for in the month of purchase and 65% in the following month.
Let's assume the raw materials purchases for July are X pounds. Then the payment for 35% of X pounds will be made in July, and the payment for 65% of X pounds will be made in August.
The payment for raw materials purchases in July (35% of X pounds) will be:
0.35 * X pounds
The payment for raw materials purchases in August (65% of X pounds) will be:
0.65 * X pounds
Since the raw materials purchases for July should cover the desired ending raw materials inventory for July (9,500 pounds), we can set up the following equation:
Raw materials purchases in July - Payment for raw materials purchases in July = Desired ending raw materials inventory for July
X pounds - 0.35 * X pounds = 9,500 pounds
Solving this equation will give us the value of X, which represents the pounds of raw materials that should be purchased in July.
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Prove that if triangle ABC and triangle DEF are triangles with equal defects and a pair of congruent sides, their associated Saccheri quadrilaterals are congruent. (HINT: Recall that the angle sum for a triangle is equal to the sum of the measures of the summit angles of its associated Saccheri quadrilateral and that the two summit angles of a Saccheri quadrilateral are congruent.)
Answer:
According to theorem 7.5
Π ABB'A' ≅ Π DEE'D'
therefore by transitivity of equivalence it is proven that triangle ABC and triangle DEF are triangles with equal defects and a pair of congruent sides
Step-by-step explanation:
To prove that triangle ABC and triangle DEF are triangles with equal defects and a pair of congruent sides :
Assume: б(Δ ABC ) = б(Δ DEF ) and also AB ≅ DE
let Π ABB'A' and DEE'D' be taken as the saccheri quadrilaterals that corresponds to Δ ABC and Δ DEF respectively
Following the Lemma above; б(Π ABB'A' ) = б( Π DEE'D' ) given that
AB = summit of ABB'A' and DE = summit of DEE'D' also AB ≅ DE
According to theorem 7.5
Π ABB'A' ≅ Π DEE'D'
therefore by transitivity of equivalence it is proven that triangle ABC and triangle DEF are triangles with equal defects and a pair of congruent sides
16 families went on a trip which cost them Rs 2,16,352. How much did each
family pay?
Given that 16 families went on a trip and the cost of the trip was Rs. 2,16,352.The amount paid by each family is to be determined by unitary method Hence each family paid Rs.13522
Now, let's solve this by using the method of unitary method. To find the cost of 1 family trip, we will divide the total cost of the trip by the number of families.2,16,352 / 16 = 13,522 So, the cost of the trip per family is Rs. 13,522.Hence, each family paid Rs. 13,522 for the trip.
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Answer:
Step-by-step explanation
1. The total cost of the trip for all 16 families is Rs 2,16,352.
2. To find out how much each family paid, we need to divide the total cost by the number of families: Rs 2,16,352 ÷ 16.
3. When we do the division, we get the result: Rs 13,522.
Now let's check if this result is correct:
1. If each family paid Rs 13,522 for the trip, then the total cost for all 16 families would be: 16 × Rs 13,522 = Rs 2,16,352.
2. This is exactly the same as the total cost given in the problem statement.
So we have shown that each family paid **Rs 13,522** for the trip
URGENT!!!!!!! HELP PLEASE!!!!!!
Answer:
\(x^\frac{2}{3}\)
Step-by-step explanation:
Using the power of power rule (multiply the exponents)
\(x^\frac{4}{3}\) × \(^\frac{1}{3}\) \(x^\frac{2}{3}\) × \(^\frac{1}{3}\)
\(x^\frac{4}{9}\) \(x^\frac{2}{9}\)
When exponents are multiplied, add the answers:
x ^ ( 4/9 + 2/9 )
x ^ ( 6/9 )
x ^ ( 2/3 )
What is the greatest common factor of the terms of the polynomial below? 8x^4 - 12x^3 + 20x^2
Answer: I think the greatest common factor is 4x^2
Step-by-step explanation:
Find the numerical common factors. Which are 8, -12, and 20. Find the variable common factors for x^4, x^3, and x^2. Multiply them together. Then break down the factors on both sides and pick the biggest one. Finally multiply them together. (I’m sorry, I’m very bad at explaining things.)
True or False: If the discriminant is less than zero, then the graph will never cross the x-axis.
False
True
Answer:
True
Step-by-step explanation:
If the discriminant \(D=b^2-4ac < 0\), then there are two complex roots
If the discriminant \(D=b^2-4ac > 0\), then there are two real roots
If the discriminant \(D=b^2-4ac=0\), then there is only one real root
This pattern follows the rule add 7, then subtract 3. What are the next two numbers?
19, 23, 27, ________, ________
Group of answer choices
31, 35
31, 38
34, 35
31 and 35.
Sure hope this helps you
Party trays which cost $14.00 to make not including labor are sold for $35.00 if two people work 8 hour shifts making the trays at $7.00 per hour how many trays must be sold to cover all costs including labor?
A cellphone company charges $40 per month plus a $35 activation fee. Evaluate your expression for 10 month of service.
Answer:
Expression: 40x+35
40(10)+35= $435
Step-by-step explanation:
There are 12 months, and we want to use the cellphone company for 10 months.
Let x represent months, and put 40 in front because that's the monthly charge for each month.
Next add 35 as your initial value to the expression.
When you go in the equation, 40 multiplied by 10 is 400.
400 plus 35 is 435.
So, $435 will be charged for 10 months of service.
What is the value of x?
3x
69°
23
32
17
26
Click Save and Submit to save and submit. Click Save All Answers to save all
Answer:
23
Step-by-step explanation:
3x = 69°
This is because they are vertically opposite angles.
You would have to divide 69 by 3.
69 ÷ 3 = 23
23 · 3 = 69
The basic rate pay is K8.20. If the overtime is paid at time-and-a-quarter, what is the overtime rate of pay?
The overtime rate of pay is K10.25.
The overtime rate of pay can be calculated by multiplying the basic rate pay by the time-and-a-quarter factor. In this case, the basic rate pay is K8.20.
To determine the overtime rate of pay, we need to calculate one-quarter (1/4) of the basic rate pay, and then add that amount to the basic rate pay. One-quarter of K8.20 is calculated as (1/4) * K8.20 = K2.05.
By adding the calculated overtime amount to the basic rate pay, we get the overtime rate of pay: K8.20 + K2.05 = K10.25.
Therefore, the overtime rate of pay is K10.25.
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Answer correctly and give the solution.
Answer:
(a) Independent variable: b (number of bags sold)
Dependent variable: p(b) (profit)
(b) 25
(c) 84700
(d) 70
(e) b < 25
Step-by-step explanation:
(a) Independent variable: b (number of bags sold)
Dependent variable: p(b) (profit)
(b) To break even, set p(b) to zero and solve for b:
⇒ 350b - 8750 = 0
⇒ 350b = 8750
⇒ b = 8750 ÷ 350
⇒ b = 25
(c) Substitute b = 267 into equation and solve for p(b):
⇒ 350(267) - 8750 = 84700
(d) Set p(b) to 15750 and solve for b:
⇒ 350b - 8750 = 15750
⇒ 350b = 15750 + 8750
⇒ 350b = 24500
⇒ b = 24500 ÷ 350
⇒ b = 70
(e) If she breaks even when she sells 25 bags, if she sells less than 25 bags she will have a negative profit. So b < 25
5/6 having denominator 35
Answer:( 175/6)
Step-by-step explanation: 5*35/6=175/6 sour our numerator is 175/6. So sour answer is (175/6)/35
Question:
which is a y-intercept of the graphed function?
Answers:
A. (-9,0)
B. (-3,0)
C. (0,-9)
D. (0,-3)
Answer:
(0, -9)
Step-by-step explanation:
The y intercept is the y value when x =0
(0, -9)
last question of the unit test
Answer:
Step-by-step explanation:
Take angle A as reference angle
using sin rule
sin A=opposite/hypotenuse
sin A=10/13
sin A=0.76
\(sin^{-1}\) 0.76=49.46 degree
A=49.5 degree
please help me i really need help please help me please i really need help please help me please
Answer:2.
Step-by-step explanation:
trust me on this one
Conduct the hypothesis test and provide the test statistic and the critical value, and state the conclusion. A person drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 200 times. Here are the observed frequencies for the outcomes of 1, 2, 3, 4, 5, and 6, respectively: 29, 31, 49, 37, 26, 28. Use a 0.025 significance level to test the claim that the outcomes are not equally likely. Does it appear that the loaded die behaves differently than a fair die?
The loaded die appears to behave differently from a fair die.Based on the chi-square test, the loaded die does not exhibit equal probabilities for each outcome.
To test the claim that the outcomes of the loaded die are not equally likely, we can use the chi-square goodness-of-fit test. The null hypothesis (H₀) assumes that the outcomes are equally likely, while the alternative hypothesis (H₁) assumes that they are not equally likely.
Step 1: Set up hypotheses
H₀: The outcomes of the die are equally likely.
H₁: The outcomes of the die are not equally likely.
Step 2: Select the significance level
The significance level is given as 0.025, which means we have a two-tailed test and an alpha level of 0.025 for each tail.
Step 3: Compute the test statistic
We calculate the chi-square test statistic using the observed frequencies and the expected frequencies assuming equal probabilities for each outcome.
Expected frequencies (fair die):
1: 200/6 = 33.33
2: 200/6 = 33.33
3: 200/6 = 33.33
4: 200/6 = 33.33
5: 200/6 = 33.33
6: 200/6 = 33.33
Applying the chi-square formula, we get the test statistic:
χ² = ∑((observed - expected)² / expected)
Calculating this value, we get χ² ≈ 13.97.
Step 4: Determine the critical value
Since the significance level is 0.025 and the test is two-tailed, we divide the significance level by 2 to find the critical value associated with each tail. With 5 degrees of freedom (6 categories - 1), the critical value is approximately 11.07.
Step 5: Make a decision
The test statistic (13.97) is greater than the critical value (11.07), which leads us to reject the null hypothesis. Thus, we have evidence to suggest that the outcomes of the loaded die are not equally likely.
The loaded die appears to behave differently from a fair die.
In conclusion, based on the chi-square test, the loaded die does not exhibit equal probabilities for each outcome.
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how do I write two trillion ninety nine in number form?
Answer:
here
Step-by-step explanation:
2.000.000.099
Anu was checking her emails she casually told her friend siting next to her the ratio of unread emails in my inbox is 4:1 The total number of emails is 120 what is the number of unread emails in her inbox
In a case whereby Anu was checking her emails and she casually told her friend siting next to her the ratio of unread emails in my inbox is ratio 4:1 where the total number of emails is 120 then the number of unread emails in her inbox is 96mails.
How can the unread mails be calculated?The concept that will be used here is ratio. An ordered pair of numbers a and b, represented as a / b, is a ratio if b is not equal to 0. A proportion is an equation that sets two ratios at the same value. For instance, you could express the ratio as follows: 1: 3 if there is 1 boy and 3 girls (for every one boy there are 3 girls)
The total mails in her box is 120
The we can represent the unread mails as 4x and read mails be 1x
This can be expressed as :
(4x+1x)=120mails
5x=120mails
x=120/5
x=24
This implies that the uread mails(4×24)
=96mails
Then the number of the read mail =(1×24)=24mails
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Kripa’s father is 35 years younger than her grandfather, and 40 years older than her. If the sum of the ages of the three is 160 years, let’s find her grandfather’s age?
Answer:
90 years
Step-by-step explanation:
if Kripa's age = x
Father's age = x + 40
Grandfather's age = (x + 40) + 35 = x + 75 (father is 35 years younger than grandfather i.e. grandfather is 35 years older than father)
x + x + 40 + x + 75 = 160
=> 3x = 160 - 115
=> x = 45/3 = 15
grandfather's age = x + 75 = 90 years
Answer:
90 yearsStep-by-step explanation:
x + x + 40 + x + 75 = 160
=> 3x = 160 - 115
=> x = 45/3 = 15
Grandfather's age = x + 75 = 90 years
The sum of 21 and n is equal to 43.23
please help me!!!
I’ll give out 30 points!!!
Answer:
n=22.23
Step-by-step explanation:
21+n=43.23
-21 to both sides
0+n=22.23
n=22.23
X 5.2.19
Find the quadratic function y = ax2 + bx+c whose graph passes through the given points.
(-2,-27), (3, - 42), (1, -12)
y =
Answer:
Step-by-step explanation:
y = ax² + bx + c
Plug the points into the equation to get a system of 3 equations with 3 unknowns a, b, and c.
-27 = 4a - 2b + c
-42 = 9a + 3b + c
-12 = a + b + c
(a,b,c) = (-4,1,-9)
y = -4x² + x - 9