A toy shop owner is designing a display for his store window. He would like a snowman on a sled to travel in a circular path of radius ???? on an icy (frictionless) surface. To make this happen, he attaches a string to the sled, passes the string through the center of a vertical pole, and anchors the other end of the string to a teddy bear, a distance ???? from the pole, on a different level. He will give the sled a little push to get it started traveling at a constant speed ????. Since he might want to sell the bear later, he will not glue it down and has to rely on the friction between the bear and the surface, which has a coefficient of static friction ????. An image illustrates the scenario described in the problem. A toy snowman on a sled travels along a circular path, which has a radius labeled as D. The snowman and sled have a mass of M. A string attached to the sled runs to the center of the circle, then upward through a vertical pole, and then horizontally to a toy bear on a shelf. The horizontal distance from the pole to the bear is labeled L. The mass of the bear is marked as M subscript bear. If the mass of the snowman and sled combined is m, what is the minimum mass of the bear mbear for which this motion is possible? Express your answer in terms of m, ????, ????, ????, ????, and ???? (the acceleration due to gravity).
Answers
To determine the minimum mass of the bear (mbear) for which the motion is possible, we need to consider the forces acting on the sled and the bear.
The only force acting on the sled and the snowman in the circular path is the tension in the string, which provides the centripetal force to keep the sled moving in a circle. The centripetal force is given by: Fc = (m)(v^2) / r. where m is the mass of the sled and snowman combined, v is the speed of the sled, and r is the radius of the circular path. Now, for the bear to stay in place without slipping, the maximum static friction force between the bear and the surface should be able to provide the necessary centripetal force. The maximum static friction force is given by: Fs(max) = μsN. where μs is the coefficient of static friction and N is the normal force on the bear, which is equal to the gravitational force acting on the bear. Since the gravitational force acting on the bear is given by mg, where g is the acceleration due to gravity, we have: Fs(max) = μs(mbear)(g). To ensure that the motion is possible, we need the maximum static friction force to be equal to or greater than the centripetal force: Fs(max) >= Fc. Substituting the expressions for Fs(max) and Fc, we have: μs(mbear)(g) >= (m)(v^2) / r. Simplifying and rearranging the equation, we can solve for the minimum mass of the bear (mbear): mbear >= (m)(v^2) / (μs(g)(r)). Therefore, the minimum mass of the bear for which this motion is possible is (m)(v^2) / (μs(g)(r)).
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Related Questions
A student drops a ball from the top of a 24 m tall building. Ignoring air resistance, how long did it take for the ball to hit the ground?
Answers
Answer:
1.11111 century mother duck
give an example of how the law of inertia is demonstrated (a) for moving objects and (b) for objects at rest
Answers
Answer:
Both
Explanation:
Both of them are part of newtons laws of motion
Ans
2075 Set B Q.No. 90 A water reservoir fank of capacity
is situated at a height of 20 m from the water level. W
be the power of an electric motor to be used to fill the
3 hours? Efficiency of motor is 70%.
Answers
Marking brailiest: Two Speed and velocity questions below
A car travels a distance of 100 km in 2 hours. What is the average speed of the car (km/h)?
An NFL wide receiver prospect runs 40 m in 4.5 seconds. What is the average speed of the wide receiver (m/s)?
Answers
Answer:
1) 50 km/h
2)80/9 m/s
Explanation:
Speed = Distance / time
I NEED THE RIGHT ANSWER ASAP THIS IS A SCIENCE QUESTION
Answers
Answer:
The answer is B.
Explanation:
A Block has a density of 0.97 g/cm 3. That is why 97 percent of the ice will sink in below the water.
A double inclined plane that moves is a(n) .
Answers
Answer:
a wedge.
Explanation:
it moves when you apply force to one end of the wedge.
beansFe(aq) + Al(s) → beansAl(aq) + Fe(s) (7 points) a. What type of reaction is this? Explain what you think happened.b. This is also another type of reaction. What is it? Give another common example of this type of reaction.c. Do you think it is OK to eat the green beans? Explain why, or why not.
Answers
Answer:
tôi đoán lagf pjhAWN ỨNG HÓA HỌC
Explanation:
one mole of an ideal gas is expanded isothermally and reversibly from pressure of 10.0 bar to 2.00 bar at 300k. please calculate (a) the change in entropy of the system;
Answers
One mole of an ideal gas is expanded isothermally and reversibly from a pressure of 10.0 bar to 2.00 bar at 300K, Therefore change in entropy of the system is 0.018 kJ/K.
Explanation:
One mole of an ideal gas is expanded isothermally and reversibly from a pressure of 10.0 bar to 2.00 bar at 300K. We are to calculate the change in entropy of the system. The entropy change of the system can be calculated by using the following formula ΔS=∫Qrev/T where ΔS is the change in entropy of the system, Qrev is the reversible heat transfer of the system, and T is the absolute temperature of the system. We know that the process is isothermal and reversible.
Therefore, ΔU = 0.From the first law of thermodynamics ΔU = Qrev + W... (1)Since the process is isothermal, ΔU = 0... (2)From equations (1) and (2), Qrev = -W... (3)We know that work done in the isothermal and reversible expansion of an ideal gas can be calculated by the following equation W = nRT ln (V2/V1)W = (1 mol) (8.314 J/K mol) (300 K) ln (2.00/10.0)W = -5.5 kJ Therefore, Qrev = 5.5 kJFrom the formula for entropy change:ΔS = Qrev/TΔS = 5.5 kJ / 300 KΔS = 0.018 kJ/KSo, the change in entropy of the system is 0.018 kJ/K. Answer: The change in entropy of the system is 0.018 kJ/K.
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a group of friends are playing football in the park. one of the players is hit in the chest and falls to the ground. he gets up holding his right chest area with his arm. which injury would be most likely?
Answers
Based on the description, the player most likely suffered a rib injury or a chest wall contusion. When the chest is hit with significant force, it can cause bruising or contusions of the muscles and tissues, resulting in pain and discomfort. Rib injuries are also common in such scenarios, as the ribs can fracture or bruise, causing sharp pain and difficulty breathing.
Holding the chest with the arm is a natural response to the pain and discomfort felt in the chest area. It is essential to seek medical attention if such an injury occurs to rule out any serious complications.
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PLS Can someone help me with this I don’t know how to do it. I’ll give brainliest to whoever answers it.
Answers
Answer:
I think this is how you do it
Explanation:
the diagram shows some of the energy levels of an isolated hydrogen atom. The lowest energy
level of the atom is known as its ground
state. Each energy level is assigned an
integer number n, known as the principal
quantum number. The ground state has n
= 1.
15 m
when in
ause neu
tratin
a) Explain what happens to an
b)
electron in the ground state when
it absorbs the energy from a
photon of energy 21.8 x 10-19 J.
Energy/1013
24
-5.4
21.8
"=1 (ground state)
i. Explain why a photon is emitted when an electron makes a transition between
energy levels of n = 3 and n = 2.
ii.
Calculate the wavelength of electromagnetic radiation emitted when an electron
makes a jump between energy levels of n = 3 and n = 2.
iii.
Using the energy level diagram above to show that the energy E of an energy level is
inversely proportional to n².
Answers
1) There is a movement from n = 1 to n = 2
2) The wavelength of the transition from n =3 to n = 2 is 656 nm
What happens when a photon in the ground state of hydrogen absorbed 21.8 x 10^-19 J of energy ?When a photon is absorbed by an atom, it can cause an electron to transition from a lower energy level to a higher energy level. In the case of a hydrogen atom, the absorbed energy can cause the electron to transition from the ground state (n=1) to a higher energy level (n>1). The energy of the absorbed photon must match the difference in energy between the two energy levels involved in the transition.
We know that from the Rydberg equation;
1/λ = RH (1/n1^2 - 1/n2^2)
1/λ = 1.097 * 10^7(1/2^2 - 1/3^2)
1/λ =
λ = 656 nm
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Answer:
In conclusion, I hope I've convinced you that using computers and the internet can greatly enhance your life as an older adult. Whether it's staying in touch with loved ones, learning new things, or simplifying daily tasks, there are many benefits to using technology. So why not give it a try? I encourage you to explore the possibilities and see what the digital world has to offer. Thank you.
Which surfaces tend to have the largest and smallest coefficients of friction? Explain why.
Answers
Ice on steel has low coefficient of friction whereas rubber on pavement has high coefficient of friction. Object such as silicone rubber can have a coefficient of friction much greater than one.
Which surfaces have the largest and smallest coefficients of friction?Polytetrafluoroethylene has the lowest friction coefficient of any solid-state material but the coefficient of friction depends on the materials used.
Ice on steel has a low coefficient of friction as the two materials slide past each other very easily whereas rubber on pavement has a high coefficient of friction that is the materials do not slide past each other easily. We can say that rougher surfaces have a higher coefficient of friction.
Coefficient of friction more than one means that the frictional force is stronger than the normal force. An object such as silicone rubber, for example, can have a coefficient of friction much greater than one.
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what is ap physics equation sheet?
Answers
The AP Physics Equation Sheet is a resource provided by the College Board, which administers the Advanced Placement (AP) program in the United States. The AP Physics exams cover a range of topics in physics, including mechanics, electricity and magnetism, and thermodynamics, among others.
The essential equations and formulae that students could utilise on the test are included on the equation page. It is meant to aid in exam preparation and make sure that students have access to the relevant equations.
The equation sheet contains formulae for many different physical quantities, including, but not limited to, force, energy, power, velocity, acceleration, and electric charge. Formulas for specific subjects are also included, including those for Newton's equations of motion, work and energy, momentum and collisions, and electric circuits.
During the exam, students are permitted to utilise the AP Physics Equation Sheet, but it is assumed that they are already familiar with the equations and know how to use them to answer questions.
The equation sheet is not a replacement for a thorough comprehension of the fundamental ideas and tenets of physics.
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Please help me on this
Answers
Answer:
2nd option is the correct answer
"Please include all relevant working out as detailed as possible
and all relevant diagram to find the answer. Much appreciated! I
will upvote! Thank you so much"
Find total response of the system (transient+steady state). Do not solve for coefficients. Determine the frequency of applied force at which resonance will occur? M = 20 kg F, = 90 N Given: -6 rad/s M
Answers
Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.
The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.
To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:
ωn = √(K / M),
where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.
Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.
ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.
Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.
The correct question is given as,
M= 20kg
Fo = 90 N
ω = 6 rad/s
K = 400 N/m
C = 125 Ns/m
Determine the frequency of applied force at which resonance will occur?
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why do stars in the halo of the galaxy have almost no heavy elements
Answers
Stars in the halo of a galaxy have almost no heavy elements because the halo is composed of older stars that formed early in the history of the galaxy. These stars formed from pristine gas, which had not undergone extensive enrichment with heavy elements.
When a galaxy forms, it starts with a large amount of mostly hydrogen and helium gas. Over time, stars begin to form from this gas through gravitational collapse. As stars evolve, they undergo nuclear fusion in their cores, converting hydrogen into helium and eventually fusing helium into heavier elements. Through stellar evolution, stars can synthesize heavier elements such as carbon, oxygen, nitrogen, and so on. These heavy elements are released into the surrounding interstellar medium when stars go through stellar processes like supernovae or stellar winds In the central regions of a galaxy, where ongoing star formation is more active, the gas is enriched with heavy elements from multiple generations of stars. As a result, the stars in these regions have higher abundances of heavy elements. However, the halo of a galaxy consists of older stars that formed earlier in its history, when the galaxy had not yet accumulated a significant amount of heavy elements. The halo stars formed from gas with relatively low metallicity, meaning it had a low abundance of heavy elements. As a result, these halo stars have very low metallicity compared to stars in the younger regions of the galaxy. So, the lack of heavy element
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Imagine that your standing on a beach but cannot swim. Your friend encourages you to walk into the surf zone created by incoming deep-water waves that have a wavelength of 30 meters. Would it be safe to walk out to where the waves are breaking? Explain how you arrived at your answer.
Answers
Answer:
It would not be safe to walk out to where waves are breaking due to the effect of rip currents
Explanation:
The water depth in the surf zone is between 5 to 10 meters deep and with a wavelength of 30 meters, the speed of the wave is considerably fast such that control for safety may be difficult
Also the speed of the wave is directly related to the depth of the water which means that where the wave described above is fast as well as the rip current, also the water depth is expected to be considerable for a non swimmer
It is best to seek for sign post regarding safe areas and do not go into the water where there are no lifeguards or marked safe zones.
It won't be safe to walk out to where the waves are breaking.
This is because the wavelength is 30 meters which is a characteristic of
areas with significant water depth in the range of 5-11 meters.Under these
conditions the waves are usually very fast and may get swept with the
current from the water waves when trying to run from it.
It is recommended that we stay in areas where the depth is noted as not
being much and should always seek help and clarity from the life guards so
as to prevent drowning and death.
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use the values from practice it to help you work this exercise. what if an additional mass is attached to the ball? how large must this mass be to increase the downward acceleration by 35%?
Answers
If the additional mass is attached to the ball, it must be large enough to increase the downward acceleration by 35%.
What is acceleration?
An object is said to have been accelerated if its velocity changes. An object's velocity can change depending on whether it moves faster or slower or in a different direction. A falling apple, the moon orbiting the earth, or a car stopped at a stop sign are a few instances of acceleration. Through these illustrations, we can see that acceleration happens whenever a moving object changes its direction or speed, or both. Since acceleration has both a magnitude and a direction, it is a vector quantity. Additionally, it is either the first derivative of velocity in relation to time or even the second derivative of position in relation to time.
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A hammer drives a nail into a piece of wood. Identify an action-reaction pair.Group of answer choicesThe hammer exerts a force on the nail; the wood exerts a force on the nail.The hammer exerts a force on the nail; the hammer exerts a force on the wood.The nail exerts a force on the hammer; the hammer exerts a force on the wood.The hammer exerts a force on the nail; the nail exerts a force on the hammer.
Answers
Newton's third law states that if an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.
Let:
A = Hammer
B = Nail
so:
\(F_{AB}=-F_{BA}\)Therefore:
The hammer exerts a force on the nail; the nail exerts a force on the hammer.
Q3. A space probe is traveling in outer space with a momentum that has a magnitude
of . A retrorocket is fired to slow down the probe. It applies a force to
the probe that has a magnitude of and a direction opposite to the probe’s
motion. It fires for a period of 12 s. Determine the momentum of the probe after the
retrorocket ceases to fire
Answers
The momentum of the probe after the retrorocket ceases to fire is 9.9 * 10^7 Kg m/s
What is the momentum?We know that the momentum of an object has to do with the product of the mass and the velocity of an object. The momentum of an object is a vector quantity and the direction of the momentum is the direction of the velocity of the object that is in motion.
According to the Newton second law of motion, we know that the rate of change of the momentum is equal to the impressed force that is acting on the body.
We know that;
\(F_{t}\) = \(p_{f}\) -\(p_{i}\)
F = force
t = time taken
\(p_{f}\)= final velocity
\(p_{i}\) = initial velocity
\(p_{f}\) = \(F_{t}\) + -\(p_{i}\)
\(p_{f}\) = (2.0 * 10^6 * 12 s) + 7.5 * 10^7
\(p_{f}\) = 2.4 * 10^7 + 7.5 * 10^7
\(p_{f}\) = 9.9 * 10^7 Kg m/s
Hence, the momentum of the retrorocket is 9.9 * 10^7 Kg m/s.
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Missing parts;
A space probe is traveling in outer space with a momentum that has a magnitude of 7.5 * 10^7 kgm/s. A retrorocket is fired to slow down the probe. It applies a force to the probe that has a magnitude of 2.0 * 10^6 N and a direction opposite to the probe's motion. It fires for a period of 12 s. Determine the momentum of the probe after the retrorocket ceases fire.
Porque crees que algunas personas sienten seguridad en el dinero?
Answers
Muchas personas sienten seguridad en el dinero porque con el mismo puede tener un mator control de su vida en general.
Hay varias razones por las que algunas personas pueden sentir seguridad en el dinero:
Primero, el dinero es una forma tangible de riqueza y puede ser utilizado para comprar bienes y servicios necesarios para la supervivencia y la comodidad. En segundo lugar, el dinero también puede proporcionar una sensación de seguridad en caso de emergencias o imprevistos, ya que puede ser utilizado para pagar gastos médicos, reparaciones del hogar, etc. En tercer lugar, el dinero puede proporcionar seguridad a largo plazo a través de inversiones y ahorros para el futuro.En resumen, la seguridad que el dinero puede proporcionar está relacionada con la capacidad de satisfacer las necesidades básicas, hacer frente a situaciones de emergencia y planificar el futuro.
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When a car comes to a sudden stop to avoid hitting a cat, it slows from 40 km/hr. to 0.00 km/hr. in 1.50 seconds. find the average acceleration of the car in km/hr2?
Answers
The average acceleration of the car, when it comes to a sudden stop with a velocity from 40 km/hr to 0.00 km/hr in 1.50 seconds, is approximately -17.78 km/hr².
Acceleration is defined as the rate of change of velocity. In this scenario, the initial velocity of the car is 40 km/hr, and it comes to a stop with a final velocity of 0.00 km/hr. The change in velocity is therefore 0.00 km/hr - 40 km/hr = -40 km/hr.
To calculate the average acceleration, we need to divide the change in velocity by the time taken. The change in velocity is -40 km/hr, and the time taken is 1.50 seconds.
To convert the units to km/hr², we divide the change in velocity (-40 km/hr) by the time taken (1.50 seconds) and multiply by a conversion factor (3600 seconds/hr). This is done to ensure that the units are consistent.
Average acceleration = (-40 km/hr / 1.50 seconds) * (3600 seconds/hr) = -17.78 km/hr².
Therefore, the average acceleration of the car is approximately -17.78 km/hr². The negative sign indicates that the car is decelerating or slowing down.
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Ms. Johnson points a laser pointer from a certain angle toward the bottom of an empty aquarium. Her students see the reflection of its rays at the bottom of the aquarium.
A hand holding a laser pointer toward the bottom of an aquarium and the end of the beam is reflected at the bottom of the aquarium.
She then partially fills the aquarium and points the laser pointer from the same height and angle as before.
A laser pointer pointing toward water in an aquarium.
Predict whether or not the reflected spot of light will be in the same place as it was when she pointed the laser pointer into the empty aquarium. Explain your reasoning.
Answers
Answer:
The reflected spot will appear to be closer than when the aquarium was empty.
N1 sin θ1 = N2 sin θ2 N1 is in air and equals 1, N2 is greater than one
θ2 is measured from the vertical and the ray is less than θ1
The distance to spot is less so it appears closer
(Consider a spot directly below the pointer L1 = N2 L2)
If N2 = 4/3 then L2 would be 3/4 L1
a positively charged insulated rod is brought near two neutral conducting spheres, a and b, which are touching each other and held in place and insulated from the rest of the environment. once the rod is close to (but not touching) sphere a, the spheres are separated from each other. sphere a is then suspended from a string, and the rod is brought near it again while sphere b is moved far away. sphere a is attracted to the rod. the investigation is repeated with a negatively charged rod, and the observed results are the same. which of the following best explains why the results are the same for a positively charged rod and a negatively charged rod?
Answers
The best explanation for why the results are the same for a positively charged rod and a negatively charged rod is that the charge on the spheres is redistributed to create opposite charges on the spheres.
The charge on the spheres is redistributed to create opposite charges on the spheres, which is why the results are the same for a positively charged rod and a negatively charged rod. This redistribution happens as a result of induction. As a result of the charge redistribution, the spheres develop an attraction to the rod. When a negatively charged rod is brought close to the spheres, the charge on the spheres is redistributed, causing one of the spheres to have a net positive charge and the other to have a net negative charge.
The sphere with the opposite charge (in this case, the one with a net positive charge) is attracted to the negatively charged rod, while the sphere with the same charge (in this case, the one with a net negative charge) is repelled. This redistribution results in the spheres separating from one other.When a positively charged rod is brought near the spheres, the same charge redistribution occurs, resulting in the same attraction between the oppositely charged sphere and the rod. Sphere B is far away, hence it does not undergo any charge redistribution as a result of the presence of the charged rod.
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helpppppp please!!!!!
Answers
Answer:
6
Explanation:
Answer:
6 m/s
Explanation:
Velocity = Distance/Time
= 84 meters/14 seconds
= 6 m/s
Hope this helps! :)
A bullet is shot horizontally from the edge of a tall cliff. At the instant the bullet is shot, a rock is dropped from the same height. Neglecting air resistance, which one will hit the ground first
Answers
Answer:
The bullet and the rock will hit the ground at exactly the same time
Explanation:
Due to the gravitational forces, defined by Newton's law of gravitation, the acceleration of objects towards the center of the Earth is constant and equal to the acceleration due to gravity, g ≈ 9.8 m/s².
Therefore, given that the initial vertical velocity, u, of the rock and the bullet are both equal to zero, from the following equation of motion, we have;
s = u×t + 1/2·g·t²
t = Time
s = The height from which the bullet is fired and the rock is dropped
s = 0×t + 1/2 × 9.8 × t²
s = 1/2 × 9.8 × t²
t = √(2 × s/9.8)
Therefore, the time to hit the ground is only dependent on the height from which the bullet and the rock were allowed to fall freely.
please help :(
3.) What is the physical quantity which
represents the basis of the functioning of a
loudspeaker?
4.) Why doesn't a direct current operate a
loudspeaker?
Answers
4. A direct current will cause momentary movement in one direction only. For the speaker to produce sound you would need alternating current which makes the cone vibrate back & forth.
A positive charge is placed in the center of an uncharged metal spherical shell with some thickness as shown above.
1. Draw the electric field that exists inside the empty volume enclosed by the shell.
(Empty except for
the positive charge.) Explain your drawing either in words or through use of a
diagram, or both.
2. Draw the electric field that exists inside the metal shell. Explain your drawing
either in words or
through use of a diagram, or both.
3. Draw the electric field that exists outside of the metal shell. Explain your drawing
either in words or
through use of a diagram, or both.
Answers
The drawing of the positive charge showing the electrical fields inside the empty volume enclosed by the shell is attached accordingly. See explanation below.
What is the explanation of the drawing the positive charge inside the center of the uncharged spherical metal?The electrostatic potential at any location outside the shell, assuming the center of the shell is Z, equals Z/4π∈₁r, where r is the distance from O.
It's also worth noting that the spherical shell's outer surface is an equipotential shell, which means that the electric field at any place inside the shell except O is zero.
Because the shell is metallic, charge Z will induce uniformly on the inner surface and +Z will induce uniformly on the outer surface, with O as the charge center.
As a result, an electric field will exist both within and outside the shell, but the total charge will remain the same.
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1. What is the kinetic energy of $150 \mathrm{~kg}$ object that is moving at $7 \mathrm{~m} / \mathrm{s}$ ?
2. What is velocity of $60 \mathrm{~kg}$ object if its kinetic energy is $1080 \mathrm{~J}$ ?
3. If a $10 \mathrm{~kg}$ object is raised to a place of $3.0 \mathrm{~m}$ high, what is gravitational potential energy of the object?
4. How high must you lift a $5.25 \mathrm{~kg}$ object if the gravitational potential energy is increased by $729.56 \mathrm{~J}$ ?
Answers
1)the kinetic energy of 150 kg object that is moving at 7 m/s is 3675 J.
2)velocity of 60 kg object if its kinetic energy is 1080 J will be 6 m/s.
3)the gravitational potential energy of a 10 kg object that is raised to a place of 3.0 m high is 294 J.
4) you must lift the 5.25 kg object to a height of 14.04 m if the gravitational potential energy is increased by 729.56 J
1. An item weighing 150 kg and travelling at 7 m/s has kinetic energy.
The equation for kinetic energy is KE= 1/2mv2, where m stands for mass and v for velocity.
When the supplied values are substituted into the formula, we obtain KE = 1/2mv2 = 1/2(150 kg)(7 m/s)² = 3675 J
Therefore, the 150 kilogram object's kinetic energy at 7 m/s equals 3675 J.
2. The speed of a 60 kilogram object with a 1080 J kinetic energy
Kinetic energy is defined as KE= 1/2mv2.
Inputting the values provided yields:
KE = 1/2mv2
1080J = 1/2(60 kg)v2
v2 = (1080 J x 2)/60 kg = 36 m²/s²
Consequently, v = (36 m²/s²) = 6 m/s.
3. A 10 kilogram item is elevated to a height of 3.0 m, and its gravitational potential energy
PE = mgh, where m denotes mass, g denotes gravitational acceleration, and h denotes height, is the formula for gravitational potential energy.
With the above numbers substituted, we obtain PE = mgh = (10 kg)(9.8 m/s²)(3.0 m) = 294 J.
Therefore, a 10 kilogram object elevated to a height of 3.0 m has a 294 J gravitational potential energy.
4. The height to which a 5.25 kg item must be lifted in the event that the gravitational potential energy is raised by 729.56 J
PE = mgh is the equation for gravitational potential energy.
With the provided numbers substituted, we obtain PE = mgh 729.56 J = (5.25 kg)(9.8 m/s²)
h ⇒ h = 14.04 m
Therefore, if the gravitational potential energy is raised by 729.56 J, you must lift the 5.25 kg item to a height of 14.04 m.
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A marble has a volume of 1 mL. How much water will it displace in a graduated cyclinder
A.
1 mm
B.
more than 1 mL
C.
less than 1 mL
D.
1mL