A titration is performed as follows: 12.984 mL of Fe2 solution of unknown concentration is charged into a 100 mL beaker 45 mL of deionized water is added the solution is titrated with 0.649 M Ce4 solution the equivalence point is reached after 21.707 mL of Ce4 solution is added What is the concentration of the Fe2 solution

Answers

Answer 1

The concentration of the Fe2+ solution is approximately 1084.897 M.

To determine the concentration of the Fe2+ solution, we can use the concept of stoichiometry and the volume of the titrant solution added at the equivalence point.

Here's how we can calculate it:

First, let's find the moles of Ce4+ solution used at the equivalence point.

The volume of Ce4+ solution added is 21.707 mL, and its concentration is 0.649 M.

Thus, the moles of Ce4+ used can be calculated as:

moles of Ce4+ = volume × concentration

                         = 21.707 mL × 0.649 M

                         = 14.086743 moles

Next, since the balanced chemical equation between Fe2+ and Ce4+ is 1:1, the moles of Ce4+ used are equal to the moles of Fe2+ present in the initial solution.

Now, let's find the concentration of the Fe2+ solution.

The initial volume of the Fe2+ solution is 12.984 mL, which is equivalent to 0.012984 L.

Therefore, the concentration of the Fe2+ solution can be calculated as:

concentration of Fe2+ = moles of Fe2+ / volume of Fe2+ solution

                                      = 14.086743 moles / 0.012984 L

                                      = 1084.897 M

Hence, the concentration of the Fe2+ solution is approximately 1084.897 M.

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Related Questions

Glycoproteins are proteins to which carbohydrates have been covalently attached. the amino acid r groups that serve as sites for linkages in glycoproteins include:________.

Answers

Glycoproteins are proteins to which carbohydrates have been covalently attached. The amino acid R groups that serve as sites for linkages in glycoproteins include serine, threonine and asparagine.

Additionally, tyrosine, which contains a phenolic hydroxyl group, can also serve as a site for the attachment of carbohydrate moieties to proteins. Glycoproteins are a type of protein that has one or more carbohydrates covalently attached to it.

They play a vital role in many cellular functions, such as cell signaling and recognition. The amino acid R groups that serve as sites for linkages in glycoproteins are important in determining the function of the protein.

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Which of the following is an oxidation-reduction reaction?

Which of the following is an oxidation-reduction reaction?

Answers

Answer:

last choice

Explanation:

oxidation and reduction can be defined in terms of adding or removing oxygen to a compound

oxidation is gaining oxygen

reduction is to loss oxygen

Based off of your solubility chart, which of the following compounds would form a precipitate in water?
a. KCI
c. (NH4)₂S
d. BaSO4
b.NaOH

Answers

The compound that would form a precipitate in water is  BaSO4.

option d.

BaSO4 (barium sulfate) would form a precipitate in water because it is classified as an insoluble compound according to most solubility charts. When a compound is considered insoluble, it means that it has a very low solubility in water, resulting in the formation of solid particles or precipitate when dissolved in water.

In the case of BaSO4, it does not readily dissociate into ions in water and remains as solid particles, causing it to precipitate.

On the other hand, a. KCI (potassium chloride), b. NaOH (sodium hydroxide), and c. (NH4)2S (ammonium sulfide) are soluble compounds in water. They dissociate into ions and form homogenous solutions when dissolved in water, without forming a precipitate.

It's worth noting that solubility can vary depending on factors such as temperature and concentration, so it's always important to consult a solubility chart or reference for accurate and up-to-date information on specific compounds.option d.

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Calculate the work for the expansion of CO2 from 1.0 to 6.5 litres against pressure of 1.0 atm at constant temperature

Answers

Answer:

557.3J is the work of expansion of the CO2 gas

Explanation:

The work of expansion of a gas under constant temperature and pressure (Isobaric pressure) is:

W = P*ΔV

Where W is work

P is pressure = 1.0atm

ΔV = Final volume - Initial Volume = 6.5L - 1.0L = 5.5L

Replacing:

W = 1.0atm*5.5L

W = 5.5atmL

In Joules (1atmL = 101.325J):

5.5atmL * (101.325J / 1atmL) =

557.3J is the work of expansion of the CO2 gas

The electron configuration of the sodium atom (z=11)


K2 L8 N2

K2 L8 M1

K2 L7 M2

Answers

Explanation:

K2 L8 M1

first, we fill k shell where only 2 electrons can be found

then l electron which tends 8 electron

at last m

the approximate structures, which can be depicted using curved arrows to show the movement of delocalized electrons, are called resonance contributors. draw curved arrows to indicate how each resonance contributor leads to the next for the molecule shown.

Answers

This given statement that show the delocalization of electron pairs that transforms the structure into the indicated resonance structure is false.

What is resonance structure?

Resonance structure are a group of two or more Lewis structure that represents a single polyatomic species. Resonance is the ability of system to moves it's pi electron to the system. Resonance structure are more significant because they provide a much more realistic views of the shape of a molecule.

Therefore, each individual resonance structure is averaged into a resonance that is both the molecule's true shape.

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If 4.0 mol of NO and 4.0 mol of O2 are combined, how many moles
of NO2 can be produced?
2NO+O2 —> 2NO2

Answers

4.0


i think it has something to do with molar ratios and finding the limiting reactant

4.0 mol NO * 2 mol NO2/2 mol NO = 4.0 moles of NO2

4.0 mol O2 * 2 mol NO2/1 mol O2 = 8.0 moles of NO2

so the limiting reactant (the reactant that runs out the quickest leaving an excess) is NO

once the limiting reactant is found, we can use that data for that substance to calculate the amount of product

4.0 mol NO * 2 mol NO2/2 mole NO = 4.0 moles of NO2

Use Charles's law to solve for the missing value:
V1 = 125 L, V2 = 85.0 L, T2 = 127°C, T1 = ?

Answers

Answer:

441.7K

Explanation:

From Charles law , we know that ,

→ V1/T1 = V2/T2

Substitute,

→ 125L / T1 = 85L/127°C

Convert Celsius to kelvin scale,

→ 125L / T1 = 85L/(127+273)K

→ 125/T1 = 85L/300K

Cross multiply,

→ T1 = 441.7 K

I need help with this question

I need help with this question

Answers

It would be 4-ethyldecane. It has 12 carbons.

DETAILED Description on the applications of Nanochemistry.... about 100 words for each( note: has to be detailed)

Answers

Answer:

Explanation:

Nanochemistry is a branch of nanoscience, deals with the chemical applications of nanomaterials in nanotechnology.

Nanochemistry involves the study of the synthesis and characterisation of materials of nanoscale size.

4. Manik saw his father watering his garden plants in hot weather. He noticed that
water doesn’t stick to the plant leaves and leaves become dry but looked fresh. He asked

following questions to his teacher

a. Which tissue forms the outer covering of a plant and does it have a protective role

to play?How ?

b. Why does water not stick to the leaves?

Answers

Water does  not stick to the leaves of the plant  owing to the fact that the leaves has a waterproof cuticle.

What tissues protects the leaves?

We know that the leaves are the parts of the plant that are involved in photosynthesis. Photosynthesis is the process by which green plants produce their own food in the presence of sunlight and chlorophyll. We know that the leave has an outer protective covering.

The tissue that plays this outer covering of a plant for is the  epidermis and its waxy cuticle. It prevents damage to the plant.

Water does  not stick to the leaves of the plant  owing to the fact that the leaves has a waterproof cuticle.

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what is the rate constnat for the uncatalyzed hydrolysis of this bond if the reaction is first order

Answers

The rate constant for the uncatalyzed hydrolysis of the glycosidic bond in trehalose is 1.45 × 10⁻¹³ s⁻¹, and the rate enhancement for the glycosidic bond hydrolysis catalyzed by trehalase is 1.79 × 10¹⁶.

The rate constant for the uncatalyzed hydrolysis of the glycosidic bond in trehalose can be calculated using the half-life,  \(t_{1/2}\), which is given as 6.6 × 10⁶ years:

\(t_{1/2}\) = ln(2) / k

Rearranging this equation gives:

k = ln(2) / \(t_{1/2}\)

Substituting the given values, we get:

k = ln(2) / 6.6 × 10⁶ years

Using the conversion factor 1 year = 31,536,000 s, we can convert the time unit from years to seconds:

k = ln(2) / (6.6 × 10⁶ years × 31,536,000 s/year)

k = 1.45 × 10⁻¹³ s⁻¹

The rate enhancement for the catalyzed reaction can be calculated using the following equation:

Rate enhancement = (kcat / kuncat)

where kcat is rate constant for catalyzed reaction, and kuncat is  rate constant for uncatalyzed reaction.

Substituting the given values, we get:

Rate enhancement = (2.6 × 10³ s⁻¹) / (1.45 × 10⁻¹³ s⁻¹)

Rate enhancement = 1.79 × 10¹⁶

Therefore, the rate enhancement for the glycosidic bond hydrolysis catalyzed by trehalase is 1.79 × 10¹⁶, which indicates that the catalyzed reaction is much faster than the uncatalyzed reaction.

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--The given question is incomplete, the complete question is

"The half-life for the hydrolysis of the glycosidic bond in the sugar trehalose is 6.6 × 10⁶ years. a. What is the rate constant for the uncatalyzed hydrolysis of this bond? [Hint: For a first-order reaction, the rate constant, k, is equal to 0.693/\(t_{1/2}\).] b. What is the rate enhancement for glycosidic bond hydrolysis catalyzed by trehalase if the rate constant for the catalyzed reaction is 2.6 × 10³ s⁻¹?"--

a_Zn(s) + _b_AgNOs(ag) -> c Zn(NO3)(20) + d Ag(s)

Answers

I i,itcoycUgoycog itcoyidioyxkctiitditdu

Required information The Foundational 15 (Algo) [LO8-2, LO8-3, LO8-4, LO8-5, LO8-7, LO8-9, LO8-10] (The following information applies to the questions displeyed below] Morganton Company makes one product and it provided the following information to help prepare the master budget:
a. The budgeted selling price per unit is $65. Budgeted unit sales for June, July, August, and September are 8,200, 12,000,14,000, and 15,000 units, respectively. All sales are on credit.
b. Forty percent of credit sales are collected in the month of the sale and 60% in the following month.
c. The ending finished goods inventory equals 20%, of the following month's unit sales.
d. The ending raw materlals inventory equals 10% of the following month's raw materials production needs. Each unit of finished goods requires 5 pounds of raw materiais. The raw materials cost $2.00 per pound.
e. Twenty percent of raw materials purchases are pald for in the month of purchase and 80% in the following month.
f. The direct labor woge rate is $13 per hour. Each unit of finished goods requires two direct labor-hours.
g. The variable selling and administrative expense per unit soid is $1.30. The fliced selling and administrative expense per month is $62.000. pundational 8-5 (Algo)

5. If 71.000 pounds of raw materials are needed to meet production in August, how many pounds of raw materials should be irchased in July?
6. If 7.000 pounds of raw materlats are needed to meet production in August, what is the estimated cost of raw materials purchases for July?
7. In July whot are the total estimated cach disbursements for raw materials purchases? Assume the cost of raw material purchases in June is $93.040, and 371.000 pounds of raw materials are needed to meet production in August.
8. If 7.000 pounds of raw materials are needed to meet production in August, what is the estimated accounts payable balance at the end of July?
9. If 7.000 pounds of raw materials are needed to meet production in August what is the estimated raw materiais inventory balance at the end of July?
10. What is the total estimated direct labor cost for July?

Answers

5. To meet production in August, 71,000 pounds of raw materials are needed.

Since each unit of finished goods requires 5 pounds of raw materials, we can calculate the number of units needed in August as 71,000 pounds / 5 pounds per unit = 14,200 units.

The ending To determine the answers to the questions, we need to calculate the required information based on the provided data. inventory in July is 10% of the following month's raw materials production needs, which is 10% of 14,200 units = 1,420 units. Since each unit requires 5 pounds of raw materials, the total pounds of raw materials to be purchased in July is 1,420 units * 5 pounds per unit = 7,100 pounds. 6. To calculate the estimated cost of raw materials purchases for July, we need to determine the cost per pound of raw materials. Given that the raw materials cost $2.00 per pound, the estimated cost of raw materials purchases for July is 7,100 pounds * $2.00 per pound = $14,200. 7. The total estimated cash disbursements for raw materials purchases in July can be calculated by considering the payment terms. Twenty percent of raw materials purchases are paid for in the month of purchase, and 80% are paid in the following month. Given that the cost of raw material purchases in June is $93,040, the payment made in July is 20% * $93,040 = $18,608. The payment made in August would be 80% * $93,040 = $74,432. Therefore, the total estimated cash disbursements for raw materials purchases in July would be $18,608. 8. To calculate the estimated accounts payable balance at the end of July, we need to consider the payment terms. Since 80% of raw materials purchases are paid in the following month, 80% * $14,200 = $11,360 will be paid in August. Therefore, the estimated accounts payable balance at the end of July would be $14,200 - $11,360 = $2,840. 9. The estimated raw materials inventory balance at the end of July can be calculated by considering the ending raw materials inventory in July. Given that the ending raw materials inventory equals 10% of the following month's raw materials production needs, which is 10% of 14,200 units = 1,420 units. Since each unit requires 5 pounds of raw materials, the estimated raw materials inventory balance at the end of July would be 1,420 units * 5 pounds per unit = 7,100 pounds. 10. To calculate the total estimated direct labor cost for July, we need to consider the number of units produced and the direct labor wage rate. The budgeted unit sales for July are 12,000 units. Each unit of finished goods requires 2 direct labor-hours, so the total direct labor-hours for July would be 12,000 units * 2 direct labor-hours per unit = 24,000 direct labor-hours. Given that the direct labor wage rate is $13 per hour, the total estimated direct labor cost for July would be 24,000 direct labor-hours * $13 per hour = $312,000.

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5) 14,200 units of finished goods will be produced in August.

6) The estimated cost of raw materials purchases for July is  $2,800.

7) The total estimated cash disbursements for raw materials purchases in July is $18,608 + $74,432 = $93,040.

8) The estimated accounts payable balance at the end of July is  $59,546.40.

9)  Raw materials inventory balance is 700 pounds.

10) Total estimated direct labor cost for July is $312,000.

Let's solve  in detail:

5. To meet production in August, 71,000 pounds of raw materials are needed. Since each unit of finished goods requires 5 pounds of raw materials, the total number of units to be produced is 71,000 pounds / 5 pounds per unit = 14,200 units. Therefore, 14,200 units of finished goods will be produced in August.

6. If 7,000 pounds of raw materials are needed to meet production in August, and each unit of finished goods requires 5 pounds of raw materials, the total number of units to be produced is 7,000 pounds / 5 pounds per unit = 1,400 units.

The estimated cost of raw materials purchases for July is 1,400 units * $2.00 per pound = $2,800.

7. To calculate the total estimated cash disbursements for raw materials purchases in July, we need to consider the payment terms.

In July, 20% of raw materials purchases are paid for in the month of purchase, and 80% is paid in the following month.

The raw materials purchased in June amount to $93,040. Assuming 20% is paid in June, the cash disbursement for June is $93,040 * 20% = $18,608.

For the remaining 80% of the June purchases, which will be paid in July, we need to calculate the amount. This is given by 80% of the June purchases - 20% of the July purchases.

Amount to be paid in July = ($93,040 * 80%) - (Total purchases for July * 20%)

Solving for the Total purchases for July:

($93,040 * 80%) - (Total purchases for July * 20%) = Total purchases for July * 80%

Rearranging the equation:

($93,040 * 80%) = (Total purchases for July * 80% + Total purchases for July * 20%)

($93,040 * 80%) = Total purchases for July * 100%

Total purchases for July = ($93,040 * 80%) / 100%

Substituting the value of June purchases, we get:

Total purchases for July = ($93,040 * 80%) / 100% = $74,432

Therefore, the total estimated cash disbursements for raw materials purchases in July is $18,608 + $74,432 = $93,040.

8. If 7,000 pounds of raw materials are needed to meet production in August, and 80% of raw materials purchases are paid in the following month, the estimated accounts payable balance at the end of July would be 80% of the purchases for July.

Accounts payable balance = Total purchases for July * 80% = $74,432 * 80% = $59,546.40.

9. If 7,000 pounds of raw materials are needed to meet production in August, and the ending raw materials inventory equals 10% of the following month's raw materials production needs, the estimated raw materials inventory balance at the end of July would be 10% of the raw materials needed for August.

Raw materials inventory balance = 10% of the raw materials needed for August = 10% of 7,000 pounds = 700 pounds.

10. The total estimated direct labor cost for July can be calculated by multiplying the direct labor wage rate per hour by the total direct labor hours required for production in July.

Total direct labor hours for July = Number of units to be produced in July * Direct labor hours per unit = 12,000 units * 2 hours per unit = 24,000 hours.

Total estimated direct labor cost for July = Total direct labor hours for July * Direct labor wage rate = 24,000 hours * $13 per hour = $312,000.

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A chemist adds a chemical to pure water and there is a 100-fold increase in the concentration of hydrogen ions. What is the best approximation of the new ph value?.

Answers

If a chemist adds a chemical to pure water and there is a 100-fold increase in the concentration of hydrogen ions then the best approximate value of new pH is 5.

When only pure water is there.

H₂O ⇌ H⁺ + OH⁻

pKw = pH + pOH

14 = pH + pH ( This is because the value of pH and pOH is same in water and we need to consider pH here.)

14 = 2pH

pH= 14/2 = 7

So, pH of pure water is 7.

Concentration of hydrogen ions in pure water can be calculated using the equation

pH = -log[H⁺]

7 = -log[H⁺]

[H+] = 10⁻⁷ M

So, the concentration of hydrogen ions in pure water is 10⁻⁷ M.

Now, the chemist added a chemical to this pure water such that there is   100- fold increase in concentration of hydrogen ions.

So, the new concentration of hydrogen ions is calculated as shown below.

[H⁺] = 100 ×10⁻⁷ M

      = 10⁻⁵ M

The new concentration of hydrogen ions is 10⁻⁵ M.

Now, the new pH can be calculated using the formula

pH  = -log[H⁺]

      = -log[10⁻⁵]

      = -×-5log[10]        

       = 5×1

       = 5

So, the new pH value = 5.

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electricity generated from burning switchgrass is called a biomass energy. b biofuel. c ethanol energy. d biopower.

Answers

Answer: The correct answer is:

d) biopower.

Explanation:

Electricity generated from burning switchgrass is commonly referred to as biopower. Biopower is a form of renewable energy derived from organic materials, such as biomass, that can be burned or converted into usable energy. Switchgrass, a type of biomass, can be burned to produce heat, which is then used to generate electricity through steam turbines or other power generation methods. Biopower is a sustainable and environmentally friendly energy source that helps reduce reliance on fossil fuels.

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The correct answer is:

d) biopower.

Electricity generated from burning switchgrass is commonly referred to as biopower. Biopower is a form of renewable energy derived from organic materials, such as biomass, that can be burned or converted into usable energy. Switchgrass, a type of biomass, can be burned to produce heat, which is then used to generate electricity through steam turbines or other power generation methods. Biopower is a sustainable and environmentally friendly energy source that helps reduce reliance on fossil fuels.

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Testing precision and accuracy of scale, weigh block exactly 1.000g. these are measurements captured:
0.843 g
0.842 g
0.843 g
Is the scale precise, accurate, both, or neither?

Answers

we can conclude that the scale is precise but not accurate. The correct option is d.This means that the scale consistently gives the same measurements, but they are not accurate or close to the true value.

To understand whether the scale is precise, accurate, both, or neither, we need to define these terms. Precision refers to the consistency or reproducibility of measurements, while accuracy refers to how close the measured value is to the true or accepted value. In this case, the true value is 1.000g, and the measurements captured are 0.843 g, 0.842 g, and 0.843 g.Looking at these measurements, we can see that they are not accurate since none of them are close to 1.000g. However, we can also see that they are precise since they are all very similar to each other, with a difference of only 0.001g between the highest and lowest measurement.
Therefore, To improve accuracy, the scale may need to be recalibrated or replaced.

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complete question: Testing precision and accuracy of scale, weigh block exactly 1.000g. these are measurements captured:

a. 0.843 g

b. 0.842 g

c. 0.843 g

d. Is the scale precise, accurate, both, or neither?

A peptide has the following sequence: Glu-His-Trp-Ser-Gly-Leu-Arg-Pro-Gly.

What is the net charge of the molecule at pH 3, 8, and 11?

Answers

By analyzing the charges of all ionizable groups in this peptide (shown in the attached table), we can conclude that the net charge of the molecule at pH 3 will be +3, at pH 8 it will be +1, and at pH 11 it will be 0.

To answer this question, we must look at the pKa values of all the groups that can be ionized in this peptide.

Glu is glutamic acid, and because it is located on the N-terminus of this peptide, we need to consider its amino group (pKa = 9.67) and its side-chain carboxylic group (pKa = 4.25). For histidine (His) the only relevant group is the one in its side-chain (pKa = 6.00). Tryptophan (Trp), serine (Ser), one of the glycines (Gly), leucine (Leu), and proline (Pro) do not have side chains that can be ionized and their amino and carboxylic groups are engaged in the peptide bonds, so we do not have to consider them for this. However, we have to consider arginine's (Arg) side chain (pKa = 12.48) and C-terminus glycine's carboxylic group (pKa = 2.34).

Based on this, we can construct a table (attached below) that shows what charge (if any) the listed groups will bear at the given pH values, and sum them up to calculate the net charge.

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A peptide has the following sequence: Glu-His-Trp-Ser-Gly-Leu-Arg-Pro-Gly.What is the net charge of the

What is the molarity when 25.0 g of the compound NaClO3 is placed in 85.0 mL of solution?

Answers

Answer: Molarity when 25.0 g of the compound \(NaClO_{3}\)is placed in 85.0 mL of solution is 294.12 M.

Explanation:

Given: Mass = 25.0 g

Volume  = 85.0 mL (1 mL = 0.001 L) = 0.085 L

Molarity is the number of moles of a substance divided by volume in liter.

Hence, molarity of given solution is calculated as follows.

\(Molarity = \frac{mass}{Volume (in L)}\)

Substitute the values into above formula as follows.

\(Molarity = \frac{mass}{volume (in L)}\\= \frac{25.0 g}{0.085 L}\\= 294.12 M\)

Thus, we can conclude that molarity when 25.0 g of the compound \(NaClO_{3}\)is placed in 85.0 mL of solution is 294.12 M.

ftir spectra of a sample shows a strong shap signal 1715 cm-1, what functional group does the sample possibly have?

Answers

A strong sharp signal at 1715 cm-1 on an FTIR spectrum indicates the presence of a carbonyl functional group.

An FTIR spectrum provides information about the types of functional groups present in a molecule. A strong, sharp signal at 1715 cm-1 is indicative of the presence of a carbonyl functional group, which is characterized by the C=O bond stretching vibration. A carbonyl functional group is present in compounds such as aldehydes, ketones, carboxylic acids, and esters. The position of the carbonyl group in a molecule can also be determined by analyzing the FTIR spectrum.

For example, in an aldehyde, the carbonyl group will be located at the end of the carbon chain, while in a ketone, the carbonyl group will be located within the carbon chain. Therefore, by analyzing the FTIR spectrum of a sample, the type and location of the carbonyl functional group can be identified, which provides valuable information about the sample's chemical structure and properties.

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How many eggs is 4 moles of eggs?

Answers

each egg has 6.022x1023 moles in it so it would just be 4 moles

Thomson's model suggested that electrons were mixed into thhe sphere of an atom, much like raisins in-

Answers

Thomson's model suggested that electrons were mixed into the sphere of an atom, much like raisins in a plum pudding.

What is Thomson's model?

Thomson's atomic model was proposed by William Thomson in the year 1900. This model explained the description of the inner structure of the atom and was strongly supported by Joseph Thomson, who had discovered the electron earlier.

A negatively charged particle was discovered by J.J. Thomson during the cathode ray tube experiment that was called an electron. Thomson assumed that an electron was lighter than a proton and that an atom is composed of thousands of electrons.

In this atomic model, he considered an atom is a cloud having positive as well as negative charges. The demonstration of the ionization by X-ray was done by him together with Rutherford. Thomson’s model of an atom was quite similar to a plum pudding.

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Part C
Why do you use the same amount of baking soda and same amount of liquid for each combination?

Answers

Answer:

because you might have a too much bigger than explosion if you add more baking soda or vinegar

Explanation:

You use the same amount of baking soda and the same amount of liquid for each combination for the explosion.

We know that,

When you use the same amount of baking soda and the same amount of liquid for each combination then be get the explosion.

Baking soda and liquid are base and acid so they react chemically.

Here, the given liquid is vinegar

If you will increase the amount of baking soda and if you will increase the amount of liquid then no reaction

So, you use the same amount of baking soda and the same amount of liquid for each combination for the explosion.

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The rate of hormone removal is called the __________, and the length of time required to clear 50% of the hormone from the blood is the __________.

Answers

Answer:

1st answer clearance of hormones

the 2nd question im not sure but it take 4 weeks

Explanation:

ashe needs to make a total of 0.750 g of benzopinacolone. assuming a 100% yield, how much benzopinacol should they start with to make a theoretical 0.750 g of final product?

Answers

The mass of benzopinacol required is 0.788 grams to make 0.750 grams of benzopinacolone.

The molecular formula of benzopinacolone is C₂₆H₂₀O. Its molecular mass is 348.4 grams/moles.

The molecular formula of benzopinacol is C₂₆H₂₂O₂. Its molecular mass is 366.45 grams/mol.

In the presences of Iodine as a catalyst.

One molecule of benzopinacol forms one mole of benzopinacolone.

And we know that,

Moles = mass formed/molar mass

As the moles are equal,

So we can write,

Reacted mass of benzopinacol/molar mass of benzopinacol = formed mass of benzopinacolone/molar mass of benzopinacolone

Putting all the values,

Reacted mass of benzopinacol/366.45 = 0.750/348.4

Reacted mass of benzopinacol = 0.788 grams

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which gas would most likely be found in the greatest amount in the bubbles? a) oxygen. b) ozone. c) nitrogen. d) carbon dioxide

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The gas that would most likely be found in the greatest amount in bubbles is nitrogen, option c.

When a liquid undergoes a rapid change in pressure or temperature, bubbles are usually formed due to the presence of dissolved gases. Nitrogen is the most abundant gas available in natural environments such as water, due to its high solubility. Nitrogen is the primary component in Earth's atmosphere, with nearly 78% of it dissolved in water bodies.

Nitrogen is readily drawn out of the solution when you reduce pressure or the water temperature rises, leading to bubbles.

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The gas that would most likely be found in the greatest amount in the bubbles is d) carbon dioxide.

During various natural processes and chemical reactions, gases can be released in the form of bubbles. When considering the options given, the gas that is commonly produced and released in significant amounts is carbon dioxide (CO2). Carbon dioxide is a byproduct of respiration, combustion, and other metabolic activities in living organisms. It is also released during the process of fermentation, photosynthesis, and decomposition of organic matter.

Oxygen (O2) is an essential gas for respiration, but it is typically consumed rather than produced in significant quantities during most natural processes. Ozone (O3) is a less common gas and is typically found in the Earth's ozone layer. Nitrogen (N2) is a major component of the Earth's atmosphere, but it is relatively inert and does not readily form bubbles.

Carbon dioxide, on the other hand, is frequently produced and released in various natural and chemical processes, making it the gas most likely to be found in the greatest amount in bubbles.

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May someone help me plz

May someone help me plz

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Answer:

how many people are going to Kathmandu

a safe procedure to heat a chemical in a test tube is to place the test tube in a hot-water bath. group of answer choices true

Answers

True. Heating a chemical in a test tube by placing it in a hot-water bath is a safe method. This is because the heat is transferred evenly and gradually to the contents of the test tube, reducing the risk of the test tube breaking due to thermal stress.

Here are some additional points to consider when using a hot-water bath:

Ensure the test tube is securely clamped or held in place to prevent it from tipping or breaking.Gradually heat the water bath to the desired temperature to avoid thermal shock to the test tube.Avoid direct heating of the test tube using a flame, as this can result in thermal stress and cause the test tube to break.Stir the water bath occasionally to ensure even heating and minimize temperature gradients.Always use heat-resistant gloves to handle the hot test tube and water bath.After the reaction is complete, allow the test tube and water bath to cool down gradually before handling.

By following these guidelines, you can safely and effectively heat a chemical in a test tube using a hot-water bath.

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CsH16 +12028CO2 +8H₂O
What is the ratio of octene (C8H16) to
oxygen in the reaction?

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The ratio of octene to oxygen is 1:12.

To determine the ratio of octene (C8H16) to oxygen (O2) in the given reaction, we need to examine the balanced chemical equation. However, the equation you provided does not seem to be balanced. The coefficients for each compound must be determined to achieve a balanced equation before we can calculate the desired ratio.

Assuming you meant the combustion reaction of octene, a balanced equation would be:

C8H16 + 12O2 → 8CO2 + 8H2O

From the balanced equation, we can see that for every 1 mole of octene (C8H16), we require 12 moles of oxygen (O2) to completely react.

This means that for every 1 mole of octene, we need 12 moles of oxygen to fully combust the octene and produce the corresponding amounts of carbon dioxide (CO2) and water (H2O) as shown in the balanced equation.

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Jose left a place p and drove toward a place q at an average speed of 40 km/h. Rob left some time later driving in the same direction at an average speed of 48 km/h. After driving for five hours rob caught up with jose. How long did jose drive before rob started?.

Answers

Jose needs six hours to get there. The object's average speed is the total distance it travels in a predetermined amount of time. A scalar value is used to represent the normal speed. It is characterized by the magnitude and lacks direction.

Given

D(distance)=RT

D=40T

T FOR JOSE IS D/40.

D FOR ROB = 48*5.

From the White House to the recycling facility, it is D miles.

240=40T

T=240/40

Jose's travel time is T=6 Hours.

Calculating the ratio of the body's total distance travelled to the time needed to complete that distance yields the average speed formula. The average speed of an item travelling at a variable speed is calculated using equation.

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