A tennis ball is dropped from the top of a tall building. a second tennis ball is thrown down from the same building make a statement about the acceleration of each tennis ball.
A) The first ball falls with a greater acceleration
B) The second ball falls with a greater acceleration.
C) they both are with the same acceleration because they started from the same height.
D) they both are the same acceleration because they are in free fall.
E) more information is required
Answers
The two balls have the same acceleration because they are in free fall.
The two balls projected downwards from the top of the build are influenced by gravity. Both ball experience free fall due to gravity.
The equation of motion of the two ball is given as;
v² = u² + 2gh
where;
v is the final velocity of each ballu is the initial velocity of each ballh is the distance traveled by each ballg is acceleration due to gravity = 9.8 m/s²Thus, we can conclude that the two balls have the same acceleration because they are in free fall.
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Related Questions
give an example of free fall
Answers
Answer:
A stone that is dropped down into an empty well
what scale ranks minerals from softest to hardest
Answers
Answer: Mohs Scale
Explanation: Mohs Scale of Hardness
hope this helped!!!!!!!!!!!
Neptune circles the Sun at a distance of 4.50 × 1012 m once every 164 years. Saturn circles the Sun at a distance of 1.43 × 1012 m. What is the orbital period of Saturn?
Answers
The orbital time period of the Saturn is 29.6 years
We are given that,
Distance from Sun to Saturn is = a = 1.43 × 10¹²
The mass of the Sun is = M =1.99 × 10³⁰kg
The Gravitational constant = G = 6.67 × 10⁻¹¹N-m²kg⁻²
To find the orbital period of Saturn we can use the equation ,
\(T^{2} = \frac{4\pi }{GM}a^{3}\)
Where, T is the orbital time period of the of the Saturn , M is the mass of the sun , G is the gravitational constant.
Therefore, after putting the value in above equation we can get,
\(T^{2} = \frac{4(\(3.14)^{2} }{(6.67*10)^{-11} )N-m^{2} kg^{-2}}(1.43*10^{12}) ^{3}m\)
\(T^{2} = \sqrt{8.688*10^{17} } s\)
\(T = 932094415.818s\)
So that , from above to convert the orbital time period of Saturn from second into year i.e. above seconds divided by seconds (1 sec = 3.154 ×10⁷ Earth years)
Thus, the orbital time period can be ,
\(T = 29.6 years\)
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Nowton's third law refers to 'action reaction forces*. These forces are
always:
Answers
equal in magnitude but opposite in direction
A local municipality placed an advert in the local newspaper for a competition of local high schools to participate to build a security system in the community hall to avoid vandalism and break ins
Answers
We will use the design process to meet the requirements of the competition by the given explained in the main answer.
What is the competition?The initiative was taken by two or more parties operating independently to win the business of a third party by competing to hire contractors on the best terms possible.
The complete question is
"A local businessperson placed an advert in the local newspaper for a competition for girls only from different schools to participate in the competition. The competition is about drawing ideas for a shopping complex for the local community. Girls from the different schools are excited about the competition. you are a group of boys in the local schools who saw the advert and feel it is unfair for you to be excluded from the competition.
consider yourself as one of the learners in the local schools.
Explain why the project should be given to boys also who have better skills for this project than the girls do.
1.2 think about the design process skills, investigates, design, make, evaluate and communicate."
Explain how you will use the design process to meet the requirements of the competition.
[ 1.1 ]Boys should also be given the project because some of them have more artistic talent than girls do when it comes to sketching designs for local shopping centers.
Boys can also present a clear picture of how local communities can expand their shopping options.
For instance, they can encourage local merchants to offer seasonal items because doing so will benefit their businesses.
They can also suggest that retailers encourage customers to bring a friend to participate in competitions, which will be highly regarded.
[1.2] In order to fulfill the needs of the competition, I would make sure to explore how a shopping center for the neighborhood functions, for instance, by making sure I am aware of the strategies one may use to enhance his or her firm in the neighborhood.
In order to win the competition, I would make sure that I was confident in what I was saying and that I was audible enough to be heard during the competition.
Finally, I would make sure I met the competition's conditions by staying on-topic and solely addressing the issues raised in the advertisement
Hence will use the design process to meet the requirements of the competition.
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In an experiment, a group of students will determine the dielectric constant of paper. They have the following materials available, as well as other materials traditionally available in a high school physics lab. _____ Aluminum foil _____ Sheets of paper _____ Sheets of plastic _____ Multimeters with the ability to measure capacitance(a) Outline an effective experimental procedure to gather the necessary data that can be used to determine the dielectric constant of paper. Place a check mark next to each item above that the students should use. Draw a labeled diagram to represent the setup used for this procedure.The table below shows data from a different experiment in which students measure the capacitance of different setups as they vary the distance between the two plates of the capacitor, the area of the plates, and the material inserted between the plates.Trial Capacitor Dielectric Distance Between the Plates ( m ) Area of the Plates ( m2 ) Capacitance ( F )1 paper 1.00×10−4 0.04 8.1×10−92 paper 1.00×10−4 0.09 18.3×10−93 paper 1.00×10−4 0.16 32.6×10−94 paper 1.00×10−4 0.25 49.8×10−95 paper 2.00×10−4 0.25 23.1×10−96 paper 3.00×10−4 0.25 18.9×10−97 paper 4.00×10−4 0.25 14.9×10−98 paper 5.00×10−4 0.25 9.2×10−99 plastic 1.10×10−4 0.04 11.3×10−910 plastic 1.10×10−4 0.09 25.3×10−911 plastic 1.10×10−4 0.16 45.1×10−912 plastic 1.10×10−4 0.25 70.4×10−913 plastic 2.20×10−4 0.25 35.2×10−914 plastic 3.30×10−4 0.25 23.5×10−915 plastic 4.40×10−4 0.25 17.6×10−916 plastic 5.50×10−4 0.25 14.1×10−9(b)i. What subset of the experimental trials would be most useful in creating a graph to determine the dielectric constant of paper? Explain why the selected trials are most useful.ii. Indicate below which quantities should be graphed to yield a straight line whose slope could be used to calculate a numerical value for the dielectric constant κ of paper.Vertical axis: Horizontal axis:(c) Plot the data points for the quantities indicated in part (b)(ii) on the graph below. Clearly scale and label all axes including units, if appropriate. Draw a straight line that best represents the data.(d) Use the data to determine a value for κ of paper.(e) On the axes below, sketch the Capacitance C as functions of plate separation d, plate area A, and dielectric constant κ.
Answers
(a) The students should use aluminum foil, sheets of paper, sheets of plastic, and multimeters with the ability to measure capacitance for the experiment.
What is dielectric constant?Dielectric constant, also known as relative permittivity, is a measure of a material's ability to store electrical energy in an electric field. It is defined as the ratio of the electric flux density produced by an applied electric field to the electric flux density that would be produced by the same electric field in a vacuum.
An effective experimental procedure to determine the dielectric constant of paper could involve the following steps:
Cut two pieces of aluminum foil and attach them to opposite sides of a sheet of paper using tape, leaving a small area of the foil exposed.
Measure the area of the exposed foil using a ruler and calculate the capacitance of the capacitor using a multimeter with the ability to measure capacitance.
Repeat step 2 for different distances between the plates of the capacitor by adjusting the distance between the foil pieces and measuring the capacitance at each distance.
Plot the capacitance versus distance data on a graph and determine the slope of the best-fit line.
Calculate the dielectric constant of paper using the slope of the best-fit line and the equation C = κεA/d, where C is the capacitance, A is the area of the plates, d is the distance between the plates, ε is the permittivity of free space, and κ is the dielectric constant of paper.
(b)
i. The trials with paper inserted between the plates and varying distances between the plates would be most useful in creating a graph to determine the dielectric constant of paper. Specifically, trials 1-5 would be most useful, as they all use paper as the dielectric material and vary the distance between the plates.
ii. The capacitance C should be graphed on the vertical axis, and the reciprocal of the distance between the plates (1/d) should be graphed on the horizontal axis to yield a straight line whose slope could be used to calculate the dielectric constant κ of paper.
(d) Using the data from trials 1-5 and the graph in part (c), the slope of the best-fit line is 3.77 x 10^-9 F/m. Using the equation C = κεA/d and the measured values of A and d, and ε (permittivity of free space), we can solve for the dielectric constant κ of paper as:
κ = Cd/εA = (3.77 x 10^-9 F/m) / [(8.85 x 10^-12 F/m) x (0.04 m^2)] = 10.7
Therefore, the dielectric constant of paper is approximately 10.7.
(e) See attached image for sketches of Capacitance C as a function of plate separation d, plate area A, and dielectric constant κ. The capacitance rises as the space between the plates gets closer. With a rise in plate area, the capacitance also grows. Last but not least, the capacitance increases as the dielectric constant increases at a certain plate gap and area.
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A dog weighs 178 N on Earth. What would its weight be on Pluto where gravity is 0.784 m/s??
Answers
Answer:
14.24 N
Explanation:
First, we need to calculate the mass of the dog. It can be calculated as the weight on Earth divided by the gravity on Earth, so
m = 178 N/ 9.8 m/s²
m = 18.16 kg
Then, the weight of the dog on pluto is equal to the mass times the gravity on pluto, so
W = (18.16 kg)(0.784 m/s²)
W = 14.24 N
Therefore, the answer is
14.24 N
In the ballistic pendulum experiment, a bullet of mass 0.06 kg is fired
horizontally into a wooden block of mass 0.2 kg. The wooden block is
suspended from the ceiling by a long string. The collision is perfectly
inelastic and after impact the bullet and the block swing together until
the block is 0.12 m above its initial position. Find the velocity of the
bullet and the block just after impact. Round your answer to the
nearest tenth.
Answers
The velocity of the bullet and the block just after impact is mathematically given as
u=6.647m/s
v=1.534m/s
Velocity of the bullet and the blockQuestion Parameters:
In the ballistic pendulum experiment, a bullet of mass 0.06 kg is fired
horizontally into a wooden block of mass 0.2 kg.
the block is 0.12 m above its initial position.
Generally the equation for the conservation of energy is mathematically given as
0.5(m+n)v^2=(m+n)gh
Therefore
v^2=2gh
\(v=\sqrt{2*9.8*0.12}\)
v=1.534m/s
Hence
mu+m*0=(m+n)v
0.060*u=(0.060+0.2)*1.534
u=6.647m/s
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An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.
Answers
The mass of the object is approximately 0.457 kg.
The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.
Using the momentum equation, the mass of the object can be calculated as follows:
Total momentum before collision = Total momentum after collision
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
Solving for the mass of the object, we get:
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object
0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object
0.32 kg = 0.70 kg * mass of the object
Dividing both sides by 0.70 kg, we find:
mass of the object = 0.32 kg / 0.70 kg = 0.457 kg
The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.
The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.
After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.
In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.
Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.
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Why must humans limit their exposure to X-rays and gamma rays?
A. The rays can change molecules and atoms in the body into ions.
B. Exposure can cause the human body to give off heat.
O C. Even a small amount of radiation can burn the skin.
D. These rays act similarly to microwaves on the human body.
Answers
Answer:
A. The rays can change molecules and atoms in the body into ions.
I need 6 things to save energy or increase energy efficiency in any part of a house
Answers
Here are six things you can do to save energy or increase energy efficiency in any part of a house:
Install energy-efficient lighting and switch to LED lights from incandescent ones. While they live longer and consume up to 80% less energy than incandescent lights, LED bulbs require fewer replacements over time.
Upgrade your windows: Replace old windows with energy-efficient ones. Windows with double or triple panes, low-emissivity coatings, and insulated frames can significantly reduce heat loss in the winter and heat gain in the summer.
Install a programmable thermostat: A programmable thermostat allows you to set different temperatures for different times of the day, so you can automatically reduce heating or cooling when you're not at home or when you're sleeping.
Insulate your home: Adding insulation to walls, floors, and attics can help keep heat inside during the winter and outside during the summer, reducing your need for heating and cooling.
Upgrade to energy-efficient appliances: Energy-efficient appliances, such as refrigerators, dishwashers, and washing machines, use less energy and water than older models, which can help you save on your energy bills.
Seal air leaks: Seal air leaks around windows, doors, and other areas of your home to prevent drafts and heat loss. You can use weatherstripping, caulking, or other materials to seal gaps and cracks. This can help you save on heating and cooling costs and improve your overall energy efficiency.
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People travel from all over the world to see more than 30 glaciers at Glacier National Park in Alaska.
Which factor causes glacial movement downhill?
A. gravity
B. oceans
C. snow
D. wind
Answers
Explanation
During the day when temperatures are higher, the snow melts and water enters the cracks in the rock. When the temperature drops below 0°C the water in the crack freezes and expands by about 9 per cent. This makes the crack larger.
Glaciers move by sliding over bedrock or underlying gravel and rock debris. With the increased pressure in the glacier because of the weight, the individual ice grains slide past one another and the ice moves slowly downhill.
5.5A Two similar dielectric ellipsoids are placed in an electric field as shown in Fig. P5.5. For which orientation is the depolarization factor larger? Give qualitative reasons. Fig. P5.5 (a) (b) E
Answers
In order to determine which orientation results in a larger depolarization factor for the similar dielectric ellipsoids placed in an electric field, we need to consider the shape and alignment of the ellipsoids with respect to the electric field.
The depolarization factor measures the reduction in the electric polarization of a material due to its shape and alignment in an electric field. It is influenced by the geometry of the material and how it interacts with the electric field.
Qualitatively, if the ellipsoids are aligned in such a way that their major axes are parallel to the electric field lines, the depolarization factor would be smaller. This is because the electric field would act along the long axis of the ellipsoid, resulting in less distortion of the polarized charges inside the material. The polarization would be more effectively aligned with the electric field, minimizing the depolarization effect.
On the other hand, if the ellipsoids are oriented such that their major axes are perpendicular or at an angle to the electric field lines, the depolarization factor would be larger. In this case, the electric field would act in a direction that is not aligned with the major axis of the ellipsoid, causing more distortion and misalignment of the polarized charges inside the material. This results in a larger depolarization effect.
Without a specific diagram or more information about the orientations shown in Figure P5.5, it is difficult to determine the exact orientation with the larger depolarization factor. However, based on the general understanding of the relationship between alignment and the depolarization effect, the orientation where the major axes of the ellipsoids are perpendicular or at an angle to the electric field lines is likely to result in a larger depolarization factor.
Draw a free body diagram showing all forces acting on the air cart, including the extra
force that may be causing a discrepancy between your numbers.
Answers
A free body diagram is a visual representation of all the forces acting on an object.
What is a free body diagram?A free body diagram is a visual representation of all the forces acting on an object. It is a tool commonly used in physics to help analyze the motion of an object.
What are the forces acting?In the case of an air cart, the forces acting on the cart might include the force of gravity pulling the cart downward, the normal force of the surface supporting the cart pushing upward, and the force of air resistance acting against the cart as it moves through the air. There may also be other forces at play, depending on the specific situation, such as an applied force from a fan or a motor driving the cart forward.
If there is an extra force causing a discrepancy between your numbers, you would also include this force on the free body diagram, with an arrow representing the magnitude and direction of the force
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Two car (A) and (B) start from the rest at the same instant of time t=0 . From the points M and N respectively in uniformly accelerated rectilinear motion and in opposite directions as shownin the adjacent figure give acceleration of (A) is 4m/s² and that (B) is 2m/s² .MN 30km At the instant t the car (A) covered a distance d¹ and B covers a distance d² 1 determine as a function of t d¹and d² . 2 deduce the time meeting 2 cars . 3 answer the preceding questions but consider that car (B) in uniform rectilinear motion with a speed of 10 m/s
Answers
To solve the problem, let's break it down into three parts:
1. Determining the distance covered by cars A and B as a function of time:
For uniformly accelerated rectilinear motion, we can use the following equation to calculate the distance covered:
distance = initial velocity * time + (1/2) * acceleration * time^2
For car A:
The initial velocity is 0 m/s, and the acceleration is 4 m/s².
So, the distance covered by car A at time t is:
d¹(t) = 0.5 * 4 * t^2 = 2t^2
For car B:
The initial velocity is 0 m/s, and the acceleration is -2 m/s² (opposite direction to car A).
So, the distance covered by car B at time t is:
d²(t) = 0.5 * -2 * t^2 = -t^2
2. Deducing the time of meeting for the two cars:
To find the time of meeting, we need to set the distances covered by both cars equal to each other:
2t^2 = -t^2
Simplifying the equation:
2t^2 + t^2 = 0
3t^2 = 0
Since the equation equals zero, the only solution is t = 0. This means that the two cars meet at the starting point at t = 0.
3. Considering car B in uniform rectilinear motion with a speed of 10 m/s:
If car B is moving at a constant speed of 10 m/s, it means its acceleration is 0 m/s². Therefore, the equation for car B's distance covered becomes:
d²(t) = initial velocity * time = 10 * t = 10t
Now, we can answer the preceding questions using this new equation for car B.
1. The distance covered by car A at time t is still d¹(t) = 2t^2.
The distance covered by car B at time t is now d²(t) = 10t.
2. The time of meeting for the two cars can be found by setting the distances equal to each other:
2t^2 = 10t
Simplifying the equation:
2t^2 - 10t = 0
2t(t - 5) = 0
From this equation, we have two solutions:
t = 0 (the initial meeting point)
t = 5 seconds (when the two cars meet again after 5 seconds)
Therefore, the cars meet again after 5 seconds.
Please note that the distances calculated above are in terms of t, the time elapsed since t = 0.
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chemical name and a common name for NaOH
Answers
the common name of sodium hydroxide is causyic soda
what is prefixe name of 1.5×10⁴
Answers
Answer:
10000
Explanation:
10 to the 5th power
Which of the following sets of quantum numbers is possible?
Select one:
a. 1,1, +1, +1/2
b. 1,0,0,0
c. 2, 1,-1,-1/2
d. 3, 0,-1, +1/2
e. None of these are allowed.
Answers
Answer:
I think c
Explanation:
hope that helps
Vector Addition, pahelp po with solutions ty!
Answers
Answer:
What is Vector Addition?
What is Vector Addition?Two vectors, A and B, can be added together using vector addition, and the resultant vector can be written as:
R = A + B
Vector Addition:Triangle, Parallelogram and Polygon Law of VectorsAs already discussed, vectors cannot be added algebraically. Following are a few points to remember while adding vectors:Vectors are added geometrically and not algebraically.Vectors whose resultant have to be calculated behave independently.Vector Addition is nothing but finding the resultant of a number of vectors acting on a body.Vector Addition is commutative. This means that the resultant vector is independent of the order of vectors.During a car accident on the NJ Turnpike, the airbags deploy. A 79 kg passenger traveling at 32 m/s makes impact with the airbag over a time of 0.25 seconds. What
was the impact force experienced by the passenger?
Answers
Hi there!
Recall that:
Impulse = Δ in momentum = mΔv
Impulse = Force · time
Begin by calculating the change in momentum, or impulse.
I = mΔv = m(vf - vi)
I = (79)(0 - 32) = -2528 Ns
Now, we can use the equation relating force and time to impulse.
I = Ft
Rearrange for time:
I/F = t
-2528/0.25 = -10112 N
**OR, if magnitude ⇒ |-10112| = 10112 N
A coconut falls out of a tree 12.0 m above the ground and hits a bystander 3.00 m tall on the top of the head. It bounces back up 1.50 m before falling to the ground. If the mass of the coconut is
2.00 kg, calculate the potential energy of the coconut relative to the ground at each of the following sites:
(a) while it is still in the tree,
(b) when it hits the bystander on the head,
(c) when it bounces up to its maximum height,
(d) when it lands on the ground,
(e) when it rolls into a groundhog hole, and falls 2.50 m to the bottom of the hole.
Answers
Answer:
A. 240 J
B. 60 J
C. 90 J
D. 0 J
E. 50 J
Explanation:
A. Determination of the potential energy of the coconut while it is still in the tree
Mass (m) = 2 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) = 12 m
Potential energy (PE) =.?
PE = mgh
PE = 2 × 10 × 12
PE = 240 J
B. Determination of the potential energy of the coconut when it hits the bystander on the head,
Mass (m) = 2 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) = 3 m
Potential energy (PE) =.?
PE = mgh
PE = 2 × 10 × 3
PE = 60 J
C. Determination of the potential energy of the coconut when it bounces up to its maximum height,
Mass (m) = 2 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) = 3 + 1.5 = 4.5 m
Potential energy (PE) =.?
PE = mgh
PE = 2 × 10 × 4.5
PE = 90 J
D. Determination of the potential energy of the coconut when it lands on the ground,
Mass (m) = 2 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) = 0 m
Potential energy (PE) =.?
PE = mgh
PE = 2 × 10 × 0
PE = 0 J
E. Determination of the potential energy of the coconut when it rolls into a ground hole, and falls 2.50 m to the bottom of the hole.
Mass (m) = 2 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) = 2.50 m
Potential energy (PE) =.?
PE = mgh
PE = 2 × 10 × 2.50
PE = 50 J
(a) The potential energy of the coconut relative to the ground while it is still in the tree is 235.2 J.
(b) The potential energy of the coconut relative to the ground when it hits the bystander on the head is 58.8 J.
(c) The potential energy of the coconut relative to the ground when it bounces up to its maximum height is 88.2 J.
(d) The potential energy of the coconut relative to the ground when it lands on the ground is 0 J.
(e) The potential energy of the coconut when it rolls into a groundhog hole, and falls 2.50 m to the bottom of the hole is 49 J.
The given parameters;
height of the tree, h = 12 mheight of the bystander, h' = 3 mheight it bounced back = 1.5 mmass of the coconut, m = 2.0 kgThe potential energy of the coconut relative to the ground while it is still in the tree;
\(P.E = mgh\\\\P.E = 2 \times 9.8 \times 12\\\\P.E = 235.2 \ J\)
The potential energy of the coconut relative to the ground when it hits the bystander on the head;
\(P.E = 2 \times 9.8 \times 3 \\\\P.E = 58.8 \ J\)
The potential energy of the coconut relative to the ground when it bounces up to its maximum height;
\(P.E = 2 \times 9.8 (1.5 + 3)\\\\P.E = 88.2 \ J\)
The potential energy of the coconut relative to the ground when it lands on the ground;
\(P.E = 2 \times 9.8 \times 0\\\\P.E = 0 \ J\)
The potential energy of the coconut relative to the ground when it rolls into a groundhog hole, and falls 2.50 m to the bottom of the hole;
\(P.E = 2\times 9.8 \times 2.5 \\\\P.E = 49 \ J\)
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How do bumper cars at an amusement pack demonstrate Newton’s third law?
Answers
Answer:
If two bumper cars collide with a certain force, then they will move away from each other in opposite directions with the same force. This demonstrates Newton's third law, which states that for every action, there is an equal and opposite reaction.
Explanation:
a 40 kg object is sliding on a surface accelerating to the right. force of friction is 20N, the applied force is 100N. draw and label all forces. what is the acceleration?
Answers
When the pressure (100 N) and weight (40 kg) are entered into the appropriate fields, the gravity is 2 m/s².
What is the acceleration force?Force and acceleration are linked by the equation F=ma. The characters "F," "m," and "a" stand for acceleration, mass, and force, respectively. Force is the ability of one object to exert a pull or force on another. Acceleration is the rate at which an object's speed changes.
Describe acceleration in detail.Speed increase is the pace of progress of speed. Acceleration typically indicates a change in speed, but not always. Because its velocity is changing in the opposite direction, even if an object moves in a circle at the same speed, it will still accelerate.
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why did you test the resistance of the wire
Answers
Answer:
What????
Explanation:
is there more to the problem???
One end of a string is attached to the ceiling with the other end attached to a toy. The toy can be set into motion such that it travels in a horizontal circular path at a constant tangential speed, as shown above. Which of the following measuring tools, when used together, could be used to determine the time it takes for the toy to complete one revolution around the circle? Select two answers.
Answers
The correct measuring tool is a Graduated cylinder. The correct option is B
Tangential speed refers to the linear speed or velocity of an object along its circular path, specifically in the direction tangent to the circle. It represents how fast an object is moving along the circumference of the circle at a given point.
The other options are not suitable for measuring the time it takes for the toy to complete one revolution around the circle for the following reasons:
A) Force probe: A force probe is used to measure forces, not time. It would not provide accurate timing information for the toy's revolution.
C) Meterstick: A meterstick is used to measure lengths and distances. It cannot directly measure time, which is required to determine the time for one revolution.
D) Spring scale: A spring scale is used to measure forces. It would not provide accurate timing information for the toy's revolution.
On the other hand, a graduated cylinder is a cylindrical container with markings indicating volume. While it is primarily used for measuring the volume of liquids, it can also be used as a timing tool in this scenario. By filling the graduated cylinder with a known volume of liquid and placing it under the toy's path, the time it takes for the toy to complete one revolution can be measured by observing the displacement of the liquid level in the graduated cylinder over time.
Therefore, the correct answer is option B.
The question is incomplete , I think the question is,
One end of a string is attached to the ceiling - with the other end attached to toy. The toy can be set into motion such that travels in horizontal circular path , constant tangential speed as shown above: Which of the following measuring tools could be used to determine the time it takes for the toy to complete one revolution around the circle? String
A) Force probe
B) Graduated cylinder
C)Meterstick
D) Spring scale Toy
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Can you list the offensive position on a flag football team?
Answers
Answer:
yes u can flag football has everything that pad football has so you can enlist on being offensive position but you have to play like you want that position
Explanation:
A political campaign manager must decide whether to emphasize television advertisements or letters to potential voters in a reelection campaign. Describe the production function for campaign votes.
A. Campaign managers produce campaign votes.
B. Reelection campaigns produce campaign votes.
C. Television advertisements and campaign votes produce letters to potential voters.
D. Television advertisements and letters to potential voters produce reelection campaigns.
E. Television advertisements and letters to potential voters produce campaign votes.
How might information about this function (such as the shape of the isoquants) help the campaign manager plan strategy?
A. If the marginal rate of technical substitution of television advertisements for letters to potential voters is constant, then the campaign manager should use a combination of the two inputs.
B. If television advertisements and letters to potential voters are perfect complements, then the campaign manager should use them in fixed proportions.
C. If television advertisements and letters to potential voters are perfect substitutes, then the campaign manager should use them in fixed proportions.
D. If the isoquant curves for television advertisements and letters to potential voters are convex, then the campaign manager should use only the cheaper input per vote.
E. If the isocost lines for television advertisements and letters to potential voters are convex, then the campaign manager should use a combination of the two inputs.
Answers
Answer:
First answer - (E)
Second answer - (B)
Explanation:
The trade-off here is between TV ADVERTISEMENTS and LETTERS TO POTENTIAL VOTERS. The campaign manager for the candidate who is running for reelection, is trying to decide which of the two factors he should use more of or emphasize. The production function for campaign votes can be simplified as
TVAD + LTPV = CV
This is the production function for campaign votes.
PART A
Describe the production function for campaign votes (in words).
ANSWER: (E)
Television advertisements and (or 'plus') letters to potential voters, produce (or 'equal') campaign votes.
PART B
How might information about this function (such as the shape of the isoquants) help the campaign manager plan strategy?
ANSWER: (B)
If television advertisements and letters to potential voters are perfect complements (complements are goods or actions that 'must' go together or be used together) then the campaign manager should use them in fixed proportions (e.g. in a ratio of 50:50).
The vapor pressure of liquid ethanol, C2H5OH, is 100. mm Hg at 308 K.
A sample of C2H5OH is placed in a closed, evacuated 529 mL container at a temperature of 308 K. It is found that all of the C2H5OH is in the vapor phase and that the pressure is 67.0 mm Hg. If the volume of the container is reduced to 344 mL at constant temperature, which of the following statements are correct?
Choose all that apply.
a. The pressure in the container will be 103 mm Hg.
b. Some of the vapor initially present will condense.
c. Liquid ethanol will be present.
d. Only ethanol vapor will be present.
e. No condensation will occur.
B
Answers
The statements that apply are;
The pressure in the container will be 103 mm Hg. Some of the vapor initially present will condense.Liquid ethanol will be present.What is the new pressure?We know that the pressure can be taken as the force with which the molecules of the substance are able to hit the walls of the container in this case, we need to obtain the pressure of the ethanol vapor when the volume has been reduced.
Using
P1 = initial pressure
P2 = final pressure
V 1 = initial volume
V2 = final volume
By the use of the Boyle's law we have;
P1V1 = P2V2
P2 = P1V1 /V2
P2 = 67.0 * 529/344
P2 = 103 mmHg
Thus, as the volume is reduced there would be an increase in the pressure and some of the ethanol would condense and we would have liquid ethanol in the system.
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A concave mirror in an amusement park has a radius of curvature of 4.0 m. A child stands in front of the mirror so that she appears 3.0 times taller than her actual height. a) If the image is upright, how far is she standing from the mirror? Where will his image be formed? 1.3 m b) Locate image using graphical method.
Answers
The distances of the image and object from the mirror and the focal length are represented by the variables v, u, and f, respectively, in the mirror.
briefly:-
formula 1/v+1/u=1/f.
Positive magnification exists. ⇒M
M=−vu=3⇒v=−3u.
The radius of curvature is 4 m with a 2 m f-value.
1/v+1/u=1/f,
1/3u+1/u=12, and 4u=12u m.
u= 1/3 m
A mirror at a theme park is it convex or concave?Through the use of convex and concave surfaces, a fun-house mirror at a theme park distorts an image. The appearance of the image can be either significantly magnified or diminished.
What is the mathematical formula for the magnification a concave mirror produces?1/f = 1/v+1/u; Here, u and v represent the distances of the object and its image from the mirror's pole. Additionally, the principal focus distance from the pole is the focal length (f).
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find the power of a lift that transfers 450 J of energy in 15 seconds.
Answers
Answer: P=30W
Explanation:
formula is p=w/t
p = power
w = work
t = elapsed time
input variables, solve then simplify.
The power of a lift that transfers 450 J of energy in 15 seconds is 30 watts.
Power is defined as the rate of doing work, i.e. the amount of work done per unit time.
Mathematically, it can be represented as follows:
Power = Work done / time taken
Therefore, the power of a lift that transfers 450 J of energy in 15 seconds can be calculated as follows:
Power = Work done / time taken= 450 J / 15 s= 30 W
Therefore, the power of the lift is 30 watts.
To explain further, we know that power is measured in watts (W), and it is the rate at which work is done or energy is transferred.
Here, we are given that the lift transfers 450 J of energy in 15 seconds.
We can find the power of the lift by dividing the amount of work done by the time taken to do it. By substituting the given values, we get the power of the lift as 30 W.
In simple terms, this means that the lift can transfer energy at a rate of 30 joules per second. This can also be interpreted as the lift can do 30 joules of work in one second.
Hence, we can conclude that the power of the lift is 30 watts.
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