If the ball is dropped with no initial velocity, then its velocity v at time t before it hits the ground is
v = -g t
where g = 9.80 m/s² is the magnitude of acceleration due to gravity.
Its height y is
y = 40 m - 1/2 g t²
The ball is dropped from a 40 m height, so that it takes
0 = 40 m - 1/2 g t²
==> t = √(80/g) s ≈ 2.86 s
for it to reach the ground, after which time it attains a velocity of
v = -g (√(80/g) s)
==> v = -√(80g) m/s ≈ -28.0 m/s
During the next bounce, the ball's speed is halved, so its height is given by
y = (14 m/s) t - 1/2 g t²
Solve y = 0 for t to see how long it's airborne during this bounce:
0 = (14 m/s) t - 1/2 g t²
0 = t (14 m/s - 1/2 g t)
==> t = 28/g s ≈ 2.86 s
So the ball completes 2 bounces within approximately 5.72 s, which means that after 5 s the ball has a height of
y = (14 m/s) (5 s - 2.86 s) - 1/2 g (5 s - 2.86 s)²
==> (i) y ≈ 7.5 m
(ii) The ball will technically keep bouncing forever, since the speed of the ball is only getting halved each time it bounces. But y will converge to 0 as t gets arbitrarily larger. We can't realistically answer this question without being given some threshold for deciding when the ball is perfectly still.
During the first bounce, the ball starts with velocity 14 m/s, so the second bounce begins with 7 m/s, and the third with 3.5 m/s. The ball's height during this bounce is
y = (3.5 m/s) t - 1/2 g t²
Solve y = 0 for t :
0 = (3.5 m/s) t - 1/2 g t²
0 = t (3.5 m/s - 1/2 g t)
==> (iii) t = 7/g m/s ≈ 0.714 s
As we showed earlier, the ball is in the air for 2.86 s before hitting the ground for the first time, then in the air for another 2.86 s (total 5.72 s) before bouncing a second time. At the point, the ball starts with an initial velocity of 7 m/s, so its velocity at time t after 5.72 s (but before reaching the ground again) would be
v = 7 m/s - g t
At 6 s, the ball has velocity
(iv) v = 7 m/s - g (6 s - 5.72 s) ≈ 4.26 m/s
7. A 5.0 m ladder is placed so that it leans against a wall so that the end of the ladder is 4.0 m up
the wall. If the ladder has a mass of 12.0 kg and a 45.0 kg person climbs the ladder so that they
are standing at the 3.75 m point on the ladder, what is the force that the ground exerts on the
ladder so that it remains in equilibrium?
Because the horizontal fraction of ground-generated pressure (F_ground) corresponds to F_wall, it is reasonable to assume that the duration of ground influence on the ladder is roughly 481.55 N in magnitude.
How to solveThe ladder's grounding point on the wall is 3.0 m away with the application of the Pythagorean theorem. By analyzing the torque at the ladder's foundation and surveying its diversified forces, we can derive estimates:
• The person's strength (F_person), determined by 45.0 kg * 9.81 m/s^2 calculations, is approximately 441.45 N when applied to a length of 3.75 m.
• The ladder's mass-based force (F_ladder), calculated as 12.0 kg * 9.81 m/s^2, is about 117.72 N exerted upon a distance of 2.5 m.
• Atop the ladder falls the wall's upward-directed push action- referred to as F_wall- which operates at an elevation of 4.0m from the earth's plane.
To ensure compliance: Equilibrium occurs if the equation (3.75 m * 441.45 N) + (2.5 m * 117.72 N) - (4.0 m * F_wall) equals zero.
Thus, F_wall ≈ 481.55 N after resolving the problem mathematically.
Additionally, because the horizontal fraction of ground-generated pressure (F_ground) corresponds to F_wall, it is reasonable to assume that the duration of ground influence on the ladder is roughly 481.55 N in magnitude.
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A hammer strikes a nail with a 10 N force for 0.01 seconds. Calculate the impulse of the hammer.
Answer:
0.1Ns
Explanation:
Impulse is the product of Force and time
Impulse = Force * Time
Given
Force = 10N
Time = 0.01s
Substitute into the formula
Impulse = 10 * 0.01
Impulse = 10 * 1/100
Impulse = 10/100
Impulse = 0.1Ns
hence the impulse of the hammer is 0.1Ns
the temperature rise a motor when operating for 25 minutes on full load is 25 degrees Celsius and becomes 40degree when the motor operates for another 25 minutes on same load determine heating time constant and steady state temperature.
The heating time constant is 13 seconds and the steady state temperature is 38°C.
How to determine time and temperatures?To find the heating time constant and steady state temperature, use the formula:
ΔT = P × R × (1 - e^(-t/τ))
where ΔT = temperature rise, P = power, R = thermal resistance, t = time, τ = heating time constant, and e = natural logarithmic constant.
Let's use the given information to solve for τ:
ΔT1 = 25°C (for the first 25 minutes)
ΔT2 = 40°C (for the second 25 minutes)
t = 25 + 25 = 50 minutes
The temperature rise over the entire 50 minutes is:
ΔT = ΔT1 + ΔT2 = 25°C + 40°C = 65°C
The average power can be calculated as:
P = ΔT / (t × R)
Assume that the power output is the rated power of the motor. Let's assume that the rated power is 100 W.
Then, solve for R:
R = ΔT / (t × P) = 65°C / (50 min × 100 W) = 0.13 °C/W
Now, solve for the heating time constant:
τ = R × C
where C = thermal capacitance. Value of C is unknown, but make an assumption that the thermal time constant is on the order of minutes to hours. Let's assume that C = 100 J/°C.
Then, τ = 0.13 °C/W × 100 J/°C = 13 seconds
Finally, solve for the steady state temperature:
ΔT = P × R
T_ss = T_amb + ΔT = 25°C + 100 W × 0.13°C/W = 38°C
Therefore, the heating time constant is 13 seconds and the steady state temperature is 38°C.
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How do our attitudes help us organize our reality?
Answer:
If we are upset, often our mind cannot think straight. we need to take deep breaths, and focus on reality. When we are upset we do things out of anger.
Explanation:
Hope this helps!
A steel ball moves from a position of +125 meters to a position of -75 meters. This motion takes 90.0 seconds. What is the velocity of the steel ball?
Answer:
2.22m/s to the left
Explanation:
Given parameters:
Initial position = +125m
Final position = -75m
Motion time = 90s
Unknown:
Velocity of the steel ball = ?
Solution:
The velocity of the steel ball is given as the displacement divided by the time;
Velocity = \(\frac{displacement}{time}\)
The net displacement of the ball = 125- (-75) = 200m to the left
Input the parameters and solve for the velocity;
Velocity = \(\frac{200}{90}\) = 2.22m/s to the left
which system works with the respiratory system for the exchange of gases to take place?
Answer:
Circulatory System
Explanation:
The respiratory system works with the circulatory system to provide tis oxygen and to remove the waste products of metabolism. It also helps to regulate PH of the blood. Respiration is the sequence of events that result in the exchange of oxygen and carbon dioxide between the atmosphere and the body cells.
What best describes the speed of light waves in solids, liquids, and gases?
The speed is fastest in solids.
The speed is fastest in liquids.
The speed is fastest in gases.
The speed is the same in all matter.
Answer: It’s fastest in gases. Letter C !
Explanation:
Answer:
its c
Explanation:
A 15.0 Ohms resistor is connected in series to a 120V generator and two 10.0 Ohms resistors that are connected in parallel to each other.
-What is the total resistance of the load?
-What is the magnitude of the circuit current?
-What is the current in one of the 10.0 Ohms resistors?
-what is the potential difference across 15.0 Ohms resistor?
draw the diagram please
Hi there! :)
Reference the diagram below for clarification.
1.
We must begin by knowing the following rules for resistors in series and parallel.
In series:
\(R_T = R_1 + R_2 + ... + R_n\)
In parallel:
\(\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}\)
We can begin solving for the equivalent resistance of the two resistors in parallel using the parallel rules.
\(\frac{1}{R_{T, parallel}} = \frac{1}{10} + \frac{1}{10}\\\\\frac{1}{R_{T, parallel}} = \frac{2}{10} = \frac{1}{5}\\\\R_{T, parallel} = 5\Omega\)
Now that we have reduced the parallel resistors to a 'single' resistor, we can add their equivalent resistance with the other resistor in parallel (15 Ohm) using series rules:
\(R_T = 15 + 5\\\\\boxed{R_T = 20 \Omega}\)
2.
We can use Ohm's law to solve for the current in the circuit.
\(i = \frac{V}{R_T}\\\\i = \frac{120}{20} = \boxed{6 A}\)
3.
For resistors in series, both resistors receive the SAME current.
Therefore, the 15Ω resistor receives 6A, and the parallel COMBO (not each individual resistor, but the 5Ω equivalent when combined) receives 6A.
In this instance, since both of the resistors in parallel are equal, the current is SPLIT EQUALLY between the two. (Current in parallel ADDS UP). Therefore, an even split between 2 resistors of 6 A is 3A for each 10Ω resistor.
4.
Since the 15.0 Ω resistor receives 6A, we can use Ohm's Law to solve for voltage.
\(V = iR\\\\V = (6)(15) = \boxed{90 V}\)
Water drips from rest from a leaf that is 12.0 meters above the ground. Neglecting air
resistance, how long does it take the water drop to hit the ground? What is the speed of
each water drop when it hits the ground?
Speed of the drop will be 15.4919m/s
Given :- g =10m/s²
u=0
s=12
v²-u²=2as is the formula to be used.
v²=u²+2as
v²=2 x 10 x 12
=240
v=√240 m/s
=15.4919m/s
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Calculate the net force on the particle q1.
Answer:
-12.1
Explanation:
i’m almost sure this is it, i’m checking my old answers
if not let me know and i’ll give you some more answers
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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What is Concave lenses ?
Explanation:
A concave lens is also known as a diverging lens because it is shaped round inwards at the centre and bulges outwards through the edges, making the light diverge. They are used to treat myopia as they make faraway objects look smaller than they are.
A wire moving at right angles to a magnetic field has NO induced voltage if the wire is covered with insulation if it is moving very fast. if it is moving slowly. if it is made of copper. None of the above choices are correct.
D) None of the options above is the proper response. Option (D)
describes the movement of a wire perpendicular to a magnetic field with no induced voltage.
If the wire has insulation surrounding it, then there will also be some induced voltage present in the wire.
It will also have some induced voltage if it is moving very quickly or vibrating back and forth.
The wire induced voltage will also be low if the wire is moving slowly.
It also induces voltage if it is composed of copper.
There is just one situation where the wire is stationary and does not produce induced voltage.
hence the appropriate choice is Alternative (d) None of the above
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1) Andrea and Chuck are riding on a merry-go-round. Andrea rides on a horse at the outer rim of the circular platform, twice as far from the center of the circular platform as Chuck, who rides on an inner horse. When the merry-go-round is rotating at a constant angular speed, Andrea's tangential speed is which of the following?a) twice Chuck's.b) the same as Chuck's.c) half of Chuck's.d) impossible to determine.2) When the merry go round is rotating at a constant angular speed, Andrea's tangential speed is:______.a) twice Chuck's.b) the same as Chuck's.c) half of Chuck's.d) impossible to determine.
Explanation:
The tangential speed of Andrea is given by :
\(v=r\omega\)
Where
r is radius of the circular path
ω is angular speed
The merry-go-round is rotating at a constant angular speed. Let the new distance from the center of the circular platform is r'
r' = 2r
New angular speed,
\(v'=r'\omega'\\\\v'=(2r)\omega\\\\v'=2r\omega\\\\v'=2v\)
New angular speed is twice that of the Chuck's speed.
Each of the following figures shows a person (not to scale) located on Earth at either 40°N or 40°S latitude. Rank the figures based on how much time the person spends in daylight during each 24-hour period, from most to least. To rank items as equivalent, overlap them.
The ranking is based on the tilt of the Earth's axis and its orbit around the Sun. The figure at 40°N in June receives the most daylight because it is located at a high latitude during the summer solstice in the Northern Hemisphere. The Earth's axis tilts towards the Sun, resulting in longer days and shorter nights. The figure at 40°S in December receives a moderate amount of daylight as it is located at a lower latitude during the summer solstice in the Southern Hemisphere.
The figure at 40°N in December experiences less daylight because it is located at a high latitude during the winter solstice in the Northern Hemisphere, with shorter days and longer nights. Lastly, the figure at 40°S in June receives the least amount of daylight as it is located at a lower latitude during the winter solstice in the Southern Hemisphere, where the days are shortest and the nights are longest. Based on the information given, the ranking of figures based on the amount of daylight they experience in a 24-hour period, from most to least.
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13. List the general strengths and weaknesses of epidemiology for providing an answer to Mary Beth’s question.
14. List the specific strengths and weaknesses of this study.
15. List the general strengths and weaknesses of toxicology for providing an answer to Mary Beth’s question.
The general strengths of epidemiology for providing an answer to Mary Beth’s question.
epidemiology can study a large populationepidemiology can identify patterns and trends in health and diseaseepidemiology can be used to study different diseases and health conditionsThe general weaknesses of epidemiology for providing an answer to Mary Beth’s question:
epidemiology may not provide a definitive answer or explanationepidemiology results may be affected by biases and confounding variablesThe Specific strengths of a study:
Big sample sizeLengthy follow-up periodThe specific weaknesses of a study are :
Use of self-recorded data, which may be inaccurate or biasedBiased selection due to non-random samplingWhat is epidemiology?Epidemiology is described as the study and analysis of the distribution, patterns and determinants of health and disease conditions in a defined population.
The main objective of epidemiology has been said is to find out what causes different health outcomes in different groups of people.
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a cat is being chased by a dog both are running in a straight line at constant speed. The cat has a headstart
PLEASE HELP!!!!
Do you think we will ever be able to get rid of our dependency on fossil fuels? Why or why not?
Answer:Probably because we've been so dependent on them,and we took to long to find new reusable resources.
Explanation:
Bumper car A (296 kg) moving +3.74 m/s makes an
elastic collision with bumper car B (222 kg) moving
+1.85 m/s. What is the velocity of car A after the
collision?
Use the formula to find the final velocity of car A.
Bumper Car A
m₁ = 296 kg
V₁i = 3.74 m/s
m₁ - m²)√₁i+
m1
m2
V₁f = (m
Bumper Car B
m₂ = 222 kg
V2i = 1.85 m/s
(m²
2m²)V₂i = [?] m/s
m₁ + m2
m₁ + m2
Remember: right is +, left is -.
The speed of car A after the collision is 0.52 m/s.
What is speed?In everyday use and kinematics, the speed of object is the amount of change in position over time, or the amount of change in position per unit time. So it's a scalar quantity.
For a bumper car A
Mass (m₁) = 296 kg
Velocity (V₁) = 3.74 m/s,
For a bumper car B
Mass (m₂) = 222 kg
Velocity (V₂) = 1.85 m/s,
To calculate velocity of car A after the collision mathematically:
Vₙ =(m₁-m₂/m₁+m₂)V₁
Vₙ = Final velocity of car A
Vₙ = (296 - 222/296 + 222) × 3.74
Vₙ = 0.52 m/s
Hence, the velocity of car A after the collision
Vₙ = 0.52 m/s
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What is a push or pull that one object excerpts on another object?
Answer:
Force
Explanation:
Drag the tiles to the correct boxes to complete the pairs.
Identify the type of potential energy described.
Tiles
gravitational
chemical
magnetic
elastic
electric
Answer:
those are all correct. The arrows are matched correctly
2. The weight of a basketball player is 6 ft and 1 12 inches. Change his height to:
a. Feet
b. Inches
C. Centimeters
d. Meters
Answer:
a feat
Explanation:
cause the mf already 7ft on the dot there is no such thing as 6 ft 12
If Earth were a perfect sphere, would you weigh more or less at the equator than at the poles? Explain
Answer:
You would weigh the same.
Explanation:
At the moment, since Earth is not a perfect sphere, the Earth "bulges out" at the equator, so you're further from the centre of the Earth. Since gravity acts through a body's center of mass, the further you are from the centre the weaker the gravitational acceleration you will feel, because gravity weakens over distance.
So, you're actually lighter at the equator than you'd be at the poles.
However, if the Earth was a perfect sphere, this "bulge" at the equator would not happen, and so you would weigh the same at the poles and at the equator.
Hope this makes sense.
Why won’t anyone help me please anybody help me I really need help .
Answer:
1➡️ this is the method of decomposition
2➡️ H2 and O2
3➡️ b
sorry if I am wrong
TIME REMAINING
58:50
Shelly tells a friend that her computer needs to be fixed because it has been producing a lot of heat and is smoking. Where
is the error in her statement?
• Heat cannot be described as having been produced.
Thermal energy cannot be produced by electronics.
Her computer should be producing a lot of heat and does not need to be fixed.
Her computer is producing thermal energy, not heat.
Mark this and return
Save and Exit
Next
Submit
Answer:
Her computer is producing thermal energy, not heat.
Explanation:
Answer:
Her computer is producing thermal energy,not heat
Explanation:
hummingbird beat its wings up and down with a frequency of 65 hz. what is the period of the hummingbirds flaps?
Answer:
15.4
Explanation:
True Or False weather conditions in the atmosphere can be recognized through direct observation.
Answer:
yes, we can tell if there will be rain by the swelling in rain clouds, we can also see if a tornado is forming based on the look of the wall cloud. we can use satellites to predict the amount of precipitation or wind.
Explanation:
thank you for ur generosity
A block with mass 0.50 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.20 m . When released, the block moves on a horizontal tabletop for 1.00 m before coming to rest. The spring constant k is 100 N/m. What is the coefficient of kinetic friction between the block and the tabletop
Answer:
μ = 0.41
Explanation:
\(\frac{1}{2} kx^2 = \mu mgd\)
\(\mu = (\frac{1}{2} kx^2)/mgd\)
\(\mu = (\frac{1}{2} (100)(0.2)^2)/(0.5)(9.81)(1)\)
\(\mu = 0.41\)
The coefficient of kinetic friction between the block and the tabletop is 0.41.
The given parameters;
mass of the block, m = 0.5 kgextension of the spring, x = 0.2 mspring constant, K = 100 N/mThe coefficient of kinetic friction between the block and the tabletop by applying the principle of conservation of energy as shown below.
Fd = Uₓ
μmgd = ¹/₂kx²
where;
μ is the coefficient of kinetic frictionThe coefficient of kinetic friction between the block and the tabletop;
\(\mu_k = \frac{kx^2}{mgd} \\\\\mu_k = \frac{100\times 0.2^2}{2\times 0.5\times9.8 \times 1 } \\\\\mu_k = 0.41\)
Thus, the coefficient of kinetic friction between the block and the tabletop is 0.41.
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Shannon and Chris push on blocks with identical force. SHannon's block is twice as massive as Chris'. After pushing for 5 seconds, who did more work?