A teacher Ask for students To write three side lengths that will not make a triangle and describe why.

Answer:

4×6=24

24×15=360

360×2=720

15-12=3

3×6=18

18×18=324

324+720=1044inches

Answer:

  1856 ft²

Step-by-step explanation:

You want the surface area of an isosceles triangular prism 23 ft long with a triangle base of 24 ft and a height of 16 ft.

The area of the two triangles is ...

  A = 2 × 1/2bh = bh

  A = (24 ft)(16 ft) = 384 ft²

The area of the three rectangular sides is ...

  A = LW

  A = (24 ft + 20 ft + 20 ft)(23 ft) = 64·23 ft² = 1472 ft²

The surface area of the prism is the sum of the base area and the lateral area:

  A = 384 ft² +1472 ft² = 1856 ft²

The surface area of the prism is 1856 square feet.

__

Additional comment

We recognize each of the smaller right triangles that make up one base is a 3-4-5 right triangle with a scale factor of 4 ft. That makes the hypotenuse exactly 20 ft, as shown in the diagram.

The lateral area is effectively the product of the prism length (23 ft) and the perimeter of the triangular base.

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Answer:

thomas's age is 38

Step-by-step explanation:

Answer:

The answer to your problem is, F = 15N

Step-by-step explanation:

You have: F = ka

Where F is the force acting on the object, A is the object's acceleration and is the constant of proportionality.

Which will be our letters that we will NEED to use for today.

You can calculate the constant of proportionality by substituting F = 18 and a = 6 into the equation and solving for k: Then we can now figure out the “ formula of expression “

18 = k6

k = \(\frac{18}{6}\)

K = 3

We would need to calculate the force when the acceleration of the object becomes 5 m/s², as following: F = 3 x 5 ( Basic math )

= F = 15

Thus the answer to your problem is, F = 15N

Answer:

4.500

Step-by-step explanation:

Answer:

13 ang sagot po nan paramis

Step-by-step explanation:

pa heart at pa brenlest at pa vote plsssss

Answer:

c

Step-by-step explanation:

Answer:

5.6

Step-by-step explanation:

11*7=77

11.8*7= 82.6

82.6-77=5.6

Answer:yes

Step-by-step explanation:

Let's let h be the height of building B, and let x be the distance between the point on the roof of building A and the base of building B. We can use the tangent function to set up two equations with two unknowns:

tan(24) = h / x

tan(34) = h / (x + 35)

We can solve for h by eliminating x from these equations. We can do this by solving the first equation for x and substituting into the second equation:

x = h / tan(24)

tan(34) = h / (h / tan(24) + 35)

Simplifying this equation, we get:

h = (35 * tan(24) * tan(34)) / (tan(34) - tan(24))

Plugging in the values, we get:

h = 22.7 meters

So building B is 22.7 meters tall. To find the height of building A, we can use the equation:

x = h / tan(24)

Plugging in the values, we get:

x = 55.1 meters

So building A is 55.1 meters tall.

A fter solving system of equations, we can conclude that, you should buy 60 Polo Shirts, 20 T- Shirts, 120 Rugby Shirts.

Let, x be the number of T-shirts, y be the number of polo shirts and z be the number of rugby shirts

A clothing store and budget $6000 to restock 200 shirts.

So, we get an equation,

x + y + z = 200                      ...................(1)

If you want to have twice as many rugby shirts as polo shirts.

So, we get an equation,

z = 2y                                   ......................(2)

You can buy T-shirts for $12 each, polo shirts for $24 each, and rugby shirts for $36 each.

So, we get an equation,

12x + 24y + 36z = 6000

We rewrite above expression as,

x + 2y + 3z = 500                         ..............(3)

Now we substitute z = 2y, into equations (1) and (3)

x + y + 2y = 200

x + 3y = 200                               ..................(4)

and equation (3) becomes,

x + 2y + 3(2y) = 500

x + 8y = 500                               ...............(5)

After solving equations (4) and (5) we get,

y = 60 and x = 20

Now substitute above value of y in equation z = 2y

z = 2(60)

z = 120

Therefore, after solving system of equations, we can conclude that, you should buy 60 Polo Shirts, 20 T- Shirts, 120 Rugby Shirts.

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Light bulbs is normally distributed with a variance of 625 and a mean lifetime of 520 hours, we need to calculate the cumulative probability up to 549 hours. The answer will be rounded to four decimal places.

Given a normally distributed lifetime with a mean of 520 hours and a variance of 625, we can determine the standard deviation (σ) by taking the square root of the variance, which gives us σ = √625 = 25.

To find the probability of a bulb lasting for at most 549 hours, we need to calculate the area under the normal distribution curve up to 549 hours. This can be done by evaluating the cumulative distribution function (CDF) of the normal distribution at the value 549, using the mean (520) and standard deviation (25).

The CDF will give us the probability that a bulb lasts up to a certain point. Rounding the result to four decimal places will provide the desired precision.

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The problem involves using normal distribution to find the probability of a given outcome. Using the Z-score, we can determine that the probability of a light bulb lasting for at most 549 hours is approximately 0.8770 or 87.70%

Given the mean (µ) of the lifetime of a bulb is 520 hours. Also, the variance (σ²) is given as 625. Thus, the standard deviation (σ) is the square root of the variance, which is 25.

To find the probability of a bulb lasting for at most 549 hours, we first calculate the Z score. The Z-score formula is given as follows: Z = (X - µ) / σ, where X is the number of hours, which is 549. So substitute the given values into the formula. Z = (549 - 520) / 25, the Z value is 1.16.

We then look up the Z-table to find the probability associated with this Z-score (1.16), which is approximately 0.8770. Therefore, the probability of a bulb lasting for at most 549 hours is approximately 0.8770 or 87.70%.

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Answer:x=9/4 nine over 4 for improper fraction I hope this is helpful mark me brainlist if this sounds good

Step-by-step explanation:

7(x-1)=3x+2

Distribute through the parentheses

7x-7=3x+2

Move the variable to the left-hand side and change its sign

7x-7-3x=2

or Move the constant to the right-hand side and change its sign

7x-7-3x=2

Collect like terms

4x=2+7

And then Add the numbers

4x=9

Divide both sides of the equation by 4

x=9/4

Mixed number is 2 1/4

Given the demand equation p+ 5x =40, where p represents the price in dollars and x the number of units, the elasticity of demand when the price p is equal to $5 is elastic.

Elasticity of demand is given as:

ED= dp / dx * x / p  where,dp / dx = 5 (-1 / 5) = -1x / p = 5 / (40 - 5) = 1 / 7

Therefore,ED = -1 * (7 / 1) = -7

The elasticity of demand is given as -7, which is elastic.

A small increase in price will result in a decrease in total revenue, and a small decrease in price will result in an increase in total revenue.

A unitary elastic demand would have resulted in an ED of -1, while an inelastic demand would have resulted in an ED of less than -1.

Therefore, demand is elastic when price is equal to $5.

The equation given in the question suggests that there is a direct relationship between price and quantity demanded, as an increase in price results in a decrease in quantity demanded.

When demand is elastic, consumers are highly responsive to price changes, and a small increase in price will result in a large decrease in quantity demanded.

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The surface area of the square pyramid is 115 square meters

From the question, we have the following parameters that can be used in our computation:

The square based pyramid

The formula for the surface area of a square pyramid is:

S = a² + 2al

where a is the length of one side of the square base and l is the slant height.

Area of 4 triangles

This is calculated as

A = 1/2 * 5 * 9 * 4 = 90

Area of the square

This is calculated as

A = 5 * 5 = 25

So, we have

Area = 90 + 25

Area = 115

Hence, the surface area of the square pyramid is 115 square meters.

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Answer:

\(x=43\)

Step-by-step explanation:

Given equation:

\(25=5(3x-4)^{\frac13}\)

Divide both sides by 5:

\(\implies 5=(3x-4)^{\frac13}\)

Cube both sides:

\(\implies 5^3=((3x-4)^{\frac13})^3\)

\(\implies 125=(3x-4)^{\frac33}\)

\(\implies 125=(3x-4)^1\)

\(\implies 125=3x-4\)

Add 4 to both sides:

\(\implies 129=3x\)

Divide both sides by 3:

\(\implies x=43\)

Answer:

x = 43

Step-by-step explanation:

If he makes a deposit of of $830 dollars in a currency 3x the dollar, the amount, $830 will be equivalent to:

In that case, he deposited 276.67 units of the unknown currency in cheque

and 276 units in currency since coins are not an option.

Answer:

65

Step-by-step explanation:

Base by High

then divided by 2

The cost of plain wrapping paper is $13 and the cost of holiday wrapping paper is $18

Chloe:

Number of plain wrapping paper sold = 2

Number of holiday wrapping paper sold = 10

Total income = $206

Eduardo:

Number of plain wrapping paper sold = 3

Number of holiday wrapping paper sold = 5

Total income = $129

Let x represent the cost of plain wrapping paper and y represent the cost of holiday wrapping paper:

Formulating the equations:

2x+10y = 206-----(1)

3x+5y = 129------(2)

Multiplying (2) with 2 and subtracting with (1) we get:

2x+10y = 206

6x+10y = 258

4x = 52

x = 13

So cost of plain wrapping paper is $13

holiday wrapping paper = $18

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Substituting the values ∂c_j / ∂ℓ(θ) = (1/N) ∑_i=1^N E[h∼p(h|v_i)][h_j] - (1/N) ∑_i=1^N E(v,h)∼p(v,h)[h_j].

To show that ∂c_j / ∂ℓ(θ) = (1/N) ∑_i=1^N E[h∼p(h|v_i)][h_j] - (1/N) ∑_i=1^N E(v,h)∼p(v,h)[h_j], we'll first derive the expression for the gradient of the log-likelihood function ℓ(θ) with respect to c_j. Then, we'll use the concept of the expectation under the RBM distribution to further simplify the expression.

Deriving the gradient: We have ℓ(θ) = (1/N) ∑_i=1^N log p_θ(v_i), where p_θ(v) = ∑_h p_θ(v, h). Taking the gradient of ℓ(θ) with respect to c_j:

∂ℓ(θ) / ∂c_j = (1/N) ∑_i=1^N ∂log p_θ(v_i) / ∂c_j. Using the energy-based model, p_θ(v, h) = 1/Z Σ_e^-E(v,h), where E(v,h) = -v^TWh - b^Tv - c^Th. Taking the derivative of log p_θ(v_i) with respect to c_j:

∂log p_θ(v_i) / ∂c_j = ∂log (1/Z ∑_h e^-E(v_i, h)) / ∂c_j

= 1/Z ∑_h ∂(-E(v_i, h)) / ∂c_j

= -1/Z ∑_h [∂(v_i^TWh) / ∂c_j + ∂(b^Tv_i) / ∂c_j + ∂(c^Th) / ∂c_j]

Notice that ∂(c^Th) / ∂c_j = [h_j]. Applying this to the expression above:

∂log p_θ(v_i) / ∂c_j = -1/Z ∑_h [∂(v_i^TWh) / ∂c_j + ∂(b^Tv_i) / ∂c_j + [h_j]]

= -1/Z ∑_h [0 + 0 + [h_j]]

= -1/Z ∑_h [h_j]

= -E[h∼p(h|v_i)][h_j]

Therefore, ∂ℓ(θ) / ∂c_j = (1/N) ∑_i=1^N -E[h∼p(h|v_i)][h_j] = - (1/N) ∑_i=1^N E[h∼p(h|v_i)][h_j]. Using the expectation under the RBM distribution:

Using the expectation under the RBM distribution, we can write E[h∼p(h|v_i)][h_j] = E(h_j) = ∑_h (h_j * p(h_j=1|v_i)). Similarly, E(v,h)∼p(v,h)[h_j] = E(h_j) = ∑_v,h (h_j * p(v,h)). Substituting these values into the previous expression, we get:

∂ℓ(θ) / ∂c_j = - (1/N) ∑_i=1^N E[h∼p(h|v_i)][h_j] + (1/N) ∑_i=1^N E(h_j) = (1/N) ∑_i=1^N E(h_j) - (1/N) ∑_i=1^N E(h_j)

= (1/N) ∑_i=1^N E(h_j) - (1/N) ∑_i=1^N E(h_j)

= 0.

Hence, ∂c_j / ∂ℓ(θ) = (1/N) ∑_i=1^N E[h∼p(h|v_i)][h_j] - (1/N) ∑_i=1^N E(v,h)∼p(v,h)[h_j]. Assuming we already know the optimal parameters W and b, the contrastive divergence algorithm to find the optimal c involves the following steps:

Initialize c with some initial values.

For each training example v_i:

Sample a hidden vector h_i from p(h|v_i).

Compute the positive gradient contribution: ∂c_j / ∂ℓ(θ) = E[h∼p(h|v_i)][h_j].

Sample a reconstructed vector v'_i from p(v|h_i).

Sample a hidden vector h'_i from p(h|v'_i).

Compute the negative gradient contribution: ∂c_j / ∂ℓ(θ) = - E(v'_i, h'_i)∼p(v,h)[h_j].

Update c using a learning rate: c_j = c_j + learning_rate * (∂c_j / ∂ℓ(θ)).

Repeat steps 2 and 3 for multiple iterations until convergence.

This algorithm iteratively adjusts the values of c to maximize the log-likelihood function ℓ(θ) by updating c in the direction that reduces the difference between the positive and negative gradient contributions.

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The set of all sets of exactly three integers are finite set, countably infinite set, and Uncountable.

A set is simply an organized collection of distinct objects forming a group and can be expressed in set-builder form or roaster form.

Let A= [2,3,4] = uncountable

B= [3,4)=uncountable

A ∩ B ={3}= finite

Hence,A ∩ B  is finite set .

Let A= set of positive real numbers that is Uncountable.

B= Set of negative real numbers and positive integers that is  Uncountable

Now, A ∩ B =Set of positive integer numbers  

A ∩ B =countably infinite set.

Let A= set of real numbers that is Uncountable

B= Set of irrational numbers that is Uncountable

Then, A ∩ B = set of irrational numbers is Uncountable.

when A is a set of real numbers and B is a set of irrational numbers.

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The volume of a stack of 9 books is 1368.75 cubic inches.

To find the volume of a stack of 9 books, we first need to find the height of the stack. Since each book is 3/4 inch thick, the height of the stack is 9 times 3/4 inch, which is 6 3/4 inches.

Now we need to find the area of the base of the rectangular prism formed by the stack of books. Since each book has an area of 22 1/2 square inches, the total area of the base of the stack is 9 times 22 1/2 square inches, which is 202 1/2 square inches.

Therefore, the volume of the stack of 9 books is:

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1. Since triangle ABC and DEF are congruent, the value of x is -3

2. length AB = 24

length DE = 24

If the three angles and the three sides of a triangle are equal to the corresponding angles and the corresponding sides of another triangle, then both the triangles are said to be congruent.

Since triangle ABC is congruent to triangle DEF , then we can say that line AB is equal to line DE

therefore;

12- 4x = 15-3x

collect like terms

12 -15 = -3x +4x

x = -3

therefore the value of x is -3 and

AB = 12 - 4x

AB = 12 -4( -3)

AB = 12 +12 = 24

DE = 15-3x

= 15-3(-3)

= 15 + 9

= 24

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Answer:

2.34

Normally it would be 1.95*6 however since everything is 20% off you need to find 20% of 1.95. You find that by:

Step-by-Solution for What is 20 percent of 1.95: 20 percent *1.95 = (20:100)*1.95 = (20*1.95):100 = 39:100 = 0.39. Now we have 20 percent of 1.95 = 0.39. explanation:

After you find that you multiply it by 6 so it would be 0.39*6 which equals 2.34. I hope this helped! :)

Answer:

m = 17h

Step-by-step explanation:

85/5 = 17 (she makes $17 per hour)

Therefore:

m = 17h

Answer:

h = 17m

Step-by-step explanation:

yup

The equation to solve is

We need to isolate x.

That means dividing 13 by 4.

So,

This is the value of x, 3 and 1/4th.

In the number line, it is just past "3".

Answer is

The value of n if the slope of the line that passes through points (n,7) and ( – 1, – 9) is 8, is calculated as: n = 1.

The slope of a line is calculated as, m = change in y / change in x = \(\frac{y_2 - y_1}{x_2 - x_1}\).

Given the following points that lies on a line that has a slope of 8 as (n, 7) and (-1, -9), therefore let:

(n, 7) = \((x_1, y_1)\)

(-1, -9) = \((x_2, y_2)\).

m = 8

Substitute the values into the slope formula:

8 = (-9 - 7) / (-1 - n)

8 = -16 / (-1 - n)

8(-1 - n) = -16

-1 - n = -16/8

-1 - n = -2

-n = -2 + 1

-n = -1

n = 1

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Answer:

CIRCLE : CIRCLE

Ratio of area is the scale factor squared. So find the radii of the two circles, square both values, and simplify the ratio.

SQUARE : SQUARE

Ratio of area is the scale factor squared, So find the side lengths of the two squares, square both values, and simplify the ratio.

SQUARE : CIRCLE

Using the formulas A = s*s and A = pi*r^2, find the areas of the circle and the square. Then simplify the ratio.