a tank at is filled with of sulfur hexafluoride gas and of dinitrogen difluoride gas. you can assume both gases behave as ideal gases under these conditions. calculate the mole fraction and partial pressure of each gas, and the total pressure in the tank. be sure your answers have the correct number of significant digits. sulfur hexafluoride mole fraction: partial pressure: dinitrogen difluoride mole fraction: partial pressure: total pressure in tank:

Yes, sulfate exists as a resonance hybrid.

Sulphate has six equivalent contributing structures. According to the Lewis structure in the sulphate ion, each oxygen is linked with sulphur by a double bond or a  single bond. The bond order of sulfur oxygen bond in any contributor is 2,2,1 and 1.  It has an average bond order of 1.5 in its equivalent hybrid structure.

Sulfuric acid, H2SO4, has two O-H bonds and two S-O bonds, as seen by its Lewis structure. The O-H bond in sulfuric acid has a length of 0.96 nm, whereas the S-O bond has a length of 1.43 nm.

The Lewis structure of sulphate, reveals that it has one double bond between an O atom and an S atom in addition to four O-S bonds. O-S and S-O bonds in sulphate were measured to be 1.48 nm and 1.50 nm, respectively, in length.

Resonance structures are used when a single Lewis structure cannot fully describe the bonding; the combination of possible resonance structures is defined as a resonance hybrid, which represents the overall delocalization of electrons within the molecule. Also, this is shown by the resonance structures of sulphate which is why it is a resonance hybrid.

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The image of the resonance structures of sulphate is given in the attachment.

We have that  the time that will have elapsed when 25.00 grams remains is

T=72hours

From the question we are told

100.0 grams of an isotope with a half-life of 36.0 hours is present at time zero. How much time will have elapsed when 25.00 grams remains?

Generally the equation for the Half life  is mathematically given as

Where

\(X=\frac{25}{100}\\\\X=0.25\\\\Therefore\\\\\frac{1}{2}^n=0.25\\\\n=2 half lives\)

Therefore

T=2*36

T=72 hours

Hence

 the time that will have elapsed when 25.00 grams remains is

T=72hours

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The Brownstead Lowry base of the equation is PO4^-.

We know that there are several definitions for acid and base. We know that in the case of the Brownstead Lowry definition of an acid and a base. A base would accept the proton while the caid is the specie that would put out the proton.

In this case, we can see that in the compound we have the phosphate ion as the ion that accepted the proton hence that is the Brownstead Lowry base. This can be seen as we look at the equations shown here.

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Answer:

D

Explanation:

While scientific laws more accurately forecast natural events, scientific theories are beliefs that explain natural happenings. So, the correct option is D.

Scientific laws are explanations for why certain occurrences occur or explanations of the phenomenon occurring itself. The outcomes or the causes of such phenomena are not explained. By stating a link verbally or mathematically, it only clarifies the situation and makes the underlying "science" simpler to comprehend.

On the other hand, scientific theories are those that make an effort to define or clarify why a phenomenon occurs. Its foundation is observation. Before drawing a conclusion, there is still a process of learning or discovery. It is a conceptual framework for explaining and projecting new information.

Thus, the correct option is D.

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The temperature of the equilibrium mixture should be increased. The given decomposition reaction of \(CaCO_3\) to CaO and \(CO_2\) is endothermic, which means that the reaction requires heat to proceed.

Increasing the temperature of the equilibrium mixture will favor the endothermic reaction, causing more \(CaCO_3\) to decompose into the CaO and the \(CO_2\). As a result, the production of carbon dioxide will increase. This is because the forward reaction (decomposition of \(CaCO_3\)) is favored at higher temperatures due to the heat being absorbed by the reaction. Therefore, to increase the production of carbon dioxide in this reaction, the temperature of the equilibrium mixture should be increased.

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For a  concentration of  is initially 0.150 M before it proceeds to equilibrium, the equilibrium concentration of B  is mathematically given as

x=3.0*10^{-7}m

Generally, the equation for the  change in Gibbs free energy   is mathematically given as

dG=-RTInK

Therefore

31.5*10*^{3}=-(8.314)(298)(ink)

K=3*10^(-6)

Eqution

A--->B

K=x/0.1-x

x=3.0*10^{-7}m

In conclusion, the equilibrium concentration

x=3.0*10^{-7}m

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This is a Charles' Law problem: V1/T1 = V2/T2. As the temperature of a fixed mass of gas decreases at a constant pressure, the volume of the gas should also decrease proportionally.

To use Charles' Law, the temperature must be in Kelvin (x °C = x + 273.15 K). We want to solve Charles' Law for V2, which we can obtain by rearranging the equation into V2 = V1T2/T1. Given V1 = 25 L, T1 = 1200 °C (1473.15 K), and T2 = 25 °C (298.15 K):

V2 = (25 L)(298.15 K)/(1473.15 K) = 5.1 L.  

The volume of this gas will be "5.1 L".

Given:

             \(= 1473 \ K\)

             \(= 298 \ K\)

As we know,

→ \(\frac{V_1}{V_2} = \frac{T_1}{T_2}\)

By substituting the values, we get

→ \(\frac{25 \ L}{V_2} = \frac{1473 \ K}{293 \ K}\)

→    \(V_2 = \frac{25\times 298}{1473} \ L\)

→         \(= 5.1 \ L\)

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The number of ionic bond in copper is zero.

Pure copper or any pure metal for that matter are examples of metallic bonds, which are neither ionic nor covalent. The copper atoms are stacked very tightly in a solid lattice. In fact it has a face centered cubic lattice which is the closed packing of atoms possible. Each atom has twelve nearest neighbors which allows their 4s orbitals (mostly) to have the optimal overlap. All of these orbitals therefore combine in one gigantic band of delocalized orbitals that spans the entire crystal with its myriad atoms. This band is only partly filled and the difference in energy between one state and the next is puny, which explains copper’s outstanding conductive properties.

Therefore, the bonding in copper has a metallic character.

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Answer:

8.14x6.022×10^23 ~ 4.901908x10^24

Explanation:

Answer:

6 g

Explanation:

The balanced equation for the reaction is:

CH4 + 2O2 → CO2 + 2H2O

Using the balanced equation, we can see that 1 mole of CH4 reacts with 2 moles of O2 to produce 1 mole of CO2 and 2 moles of H2O.

We first need to calculate the number of moles of water produced:

20.0 g H2O × (1 mol H2O/18.015 g H2O) = 1.11 mol H2O

Since 1 mole of CH4 produces 1 mole of CO2, we know that the number of moles of CO2 produced is also 1.11 mol.

Now we can use the molar mass of CO2 to convert moles to grams:

1.11 mol CO2 × (44.01 g CO2/1 mol CO2) = 48.85 g CO2

Therefore, the mass of CO2 produced in the reaction is approximately 6 g.

Answer:

One mole of H2O corresponds to 18 g .

Answer:

Nickel (I) Phosphate

Explanation:

PO4 is a -3 ion it will need 3 Ni(I) ion, which is -1 ion. Therefore it is Ni3PO4.

The substance that keeps its shape because its particles cannot flow freely is known as a solid. Solids have a fixed shape and volume because the particles are tightly packed together and cannot move freely.

The particles in solids are arranged in a specific pattern that gives them a definite shape. This pattern of arrangement is referred to as the crystal lattice structure.Solids are distinguished from liquids and gases by their ability to maintain their shape and volume. Liquids, on the other hand, take the shape of their container because their particles can flow freely, but they still have a fixed volume. Gases, on the other hand, can flow freely and can also expand or contract to fill the entire space available to them.In summary, a substance that keeps its shape because its particles cannot flow freely is a solid. This characteristic is due to the tight packing of particles and the arrangement of the crystal lattice structure. Solids are one of the three states of matter and are distinguished from liquids and gases by their fixed shape and volume.

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Answer:

It's (A)

Because: No, heat can only travel through solids by conduction.

Answer:

Heat ALWAYS flows from warmer objects to cooler objects.

Explanation:

Heat always transfers from warmer objects to cooler objects. For example, if you put a piece of ice in your drink, heat from your drink transfers into the ice, thus, cooling your drink and melting the ice.

Chlorine has 17 protons, 17 electrons and 18 neutrons. The atomic number is 17 and the mass number is 35.

The given element is Chlorine with an atomic number of 17 and a mass number of 35. The subscript serves as the atomic number while the superscript is the mass number.

The proton number is equal to the atomic number and electron number of a chlorine atom. Therefore;

Proton number = electron number = 17

For the neutron number

Neutron number is the difference between the mass number and the proton number;

Neutron number = Mass number - Proton number

Neutron number = 35 - 17 =18

Hence there are 18 neutron numbers in a chlorine atom

suppose mol of electrons must be transported from one side of an electrochemical cell to another in minutes. the size of electric current that must flow is   104.54 A.

Suppose 650 mmol of electrons must be transported from one side of an electro chemical cell to another in 10.0 minutes Then, we have to calculate the size of electric current that must flow. Then we know that Current I = Charge(q) / time(t), Charge = mols of e-x charge of electron = (0.650 mol of e-) x (96500 C/mol of e-) = 62725 C. now, time in seconds t = 10 min = 10 min x 60 s/ min = 600 s therefore, I = C/t = (62725)/600

| = 104.54 C/s, Also, 1 C/s = 1 Amp. Hence, I = 104.54 A. A torrent of particles, such as ions or electrons travelling through an electrically conducting or a vacuum is called as an electric current. The net rate of electric charge passing throughout a surface or through a control volume is how it is determined. Electric current is a term that refers to how so much electricity to flow across a circuit and how it flows in an electronic circuit. Amperes are employed to measure it (A). More and more electricity going through the circuit, the greater the ampere value.

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Slime can be made without glue or activator with shampoo by mixing shampoo and cornstartch in a bowl.  If desired, colour the two parts cornflour to one part water mixture using food colouring. Without glue or borax, this mixture might result in a slimy, goopy texture.

Two parts of  cornflour to one part water, then add food colouring if desired. This mixture has the ability to produce a slimy, sticky texture without glue or borax. You can make slime without glue, borax, or cornflour by mixing cornflour and water. Use 2 parts cornflour with 1 part water to produce the mixture, and you may also add food colouring if you like. The resulting slurry feels sticky and slimy and may be shaped and moulded like conventional slime. This type of slime is also entirely safe to use because it has no harmful chemicals. You may adjust the consistency of the slime by adding more or less water or cornflour, as desired.

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Answer:

A.) Longer and Shorter

Explanation:

If the wavelength of a light wave is shorter that means the frequency will be higher.

That means that longer wavelengths have a lower frequency.

Answer:1.30 x 10 to the 4th

Explanation:

Just know

Answer:

A

Explanation:

It is correct please I hope it helps! :)

Answer: genotype: Ee phenotype: two small eyes.

genotype: RR'  phenotype: pink eyes

genotype: GB phenotype: green and blue splotches

genotype: cc phenotype:  straight

genotype: Tt phenotype:  has tail

genotype: Ss phenotype: sharp teeth

genotype: FF' phenotype: three toes

genotype: ww phenotype: white

genotype: YY phenotype: pointy

genotype: nn phenotype: two ears

genotype: Ll phenotype: long

Explanation: hope this helps (the uppercase letters are dominant genes. the lowercase letter are recessive genes. for a recessive gene to show up in a phenotype you need 2 lower case letters such as cc or ss. for a dominant gene to show up in phenotype you need either 1 or 2 uppercase letters such as Cc or SS. Codominant genes present both colors in the phenotypes i.e. a brown and white cow. incomplete dominance is when neither gene is dominant so a mix of the 2 are present in the phenotype i.e. a pink rose. A regulatory gene controls the expression of a gene

Answer: 1s²2s²2p³ or it can also be 3s²2p³

The value of b in the equation \(\( f(t) = 85 \cdot b^t \)\) represents the decay factor of the radioactive substance. To determine the value of \( b \), we can use the information that the half-life of the substance is 21 years.

The half-life of a radioactive substance is the time it takes for half of the substance to decay. In this case, the half-life is 21 years, which means that after 21 years, the amount of the substance remaining will be half of the initial amount.

We can use this information to set up an equation:

\(\(\frac{1}{2} = b^{21}\)\)

To solve for b, we need to take the 21st root of both sides of the equation:

\(\(b = \left(\frac{1}{2}\right)^{\frac{1}{21}}\)\)

Using a calculator, we can evaluate this expression:

\(\(b \approx 0.965\)\)

Therefore, the value of b in the equation \(\( f(t) = 85 \cdot b^t \)\) is approximately 0.965.

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The answer is A. factory worker

Answer:

Explanation:

Explanation

Yes because it released the most amount of heat overall!!! well done xx

The concentration of KOH in the final solution is approximately 0.0153 M.

The stock solution is prepared by dissolving 10.0 g of KOH in enough water to make 150 ml of solution. This gives us the concentration of the stock solution.

Concentration of stock solution = mass of solute / volume of solution

Concentration of stock solution = 10.0 g / 150 ml = 0.067 M

The student then takes 15.0 ml of the stock solution and dilutes it with enough water to make 65.0 ml of the final solution.

To calculate the concentration of the final solution, we can use the dilution equation:

C1V1 = C2V2

Where:

C1 = concentration of stock solution

V1 = volume of stock solution used

C2 = concentration of the final solution

V2 = volume of the final solution

Plugging in the values:

(0.067 M)(15.0 ml) = C2(65.0 ml)

Solving for C2 (concentration of the final solution):

C2 = (0.067 M)(15.0 ml) / 65.0 ml

C2 = 0.0153 M

Therefore, the concentration of KOH in the final solution is approximately 0.0153 M.

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(A) R_r represents the rate of change of resistance with respect to the radius of the artery, r. The units of R_r are mmHg/mm. A negative value for R_r indicates that an increase in the radius of the artery will result in a decrease in resistance, meaning it becomes easier for blood to flow through the wider artery.

(b) The derivative is zero because the resistance with respect to the radius does not depend on the length of the artery.

(a) To calculate R_L (L, r), we differentiate the equation with respect to L while keeping r constant:

\(R_L(L, r) = d/dL (kL/r^4) = k/r^4\)

R_L represents the rate of change of resistance with respect to the length of the artery, L. The units of R_L are mmHg/cm. A positive value for R_L indicates that an increase in the length of the artery will result in an increase in resistance, meaning it becomes harder for blood to flow through the longer artery.

To calculate R_r (L, r), we differentiate the equation with respect to r while keeping L constant:

\(R_r(L, r) = d/dr (kL/r^4) = -4kL/r^5\)

R_r represents the rate of change of resistance with respect to the radius of the artery, r. The units of R_r are mmHg/mm. A negative value for R_r indicates that an increase in the radius of the artery will result in a decrease in resistance, meaning it becomes easier for blood to flow through the wider artery.

(b) To calculate R_rr (L, r), we differentiate R_r (L, r) with respect to r while keeping L constant:

\(R_rr(L, r) = d/dr (-4kL/r^5) = 20kL/r^6\)

R_rr represents the rate of change of R_r with respect to r. The units of R_rr are mmHg/mm^2. A positive value for R_rr indicates that as the radius of the artery increases, the rate of decrease in resistance increases. In other words, the wider the artery becomes, the easier it is for blood to flow through.

To calculate R_rL (L, r), we differentiate R_r (L, r) with respect to L while keeping r constant:

\(R_rL(L, r) = d/dL (-4kL/r^5) = 0\)

R_rL represents the rate of change of R_r with respect to L. The units of R_rL are mmHg/(cm·mm). The derivative is zero because the resistance with respect to the radius does not depend on the length of the artery. This implies that changes in the length of the artery do not affect the rate of change of resistance with respect to the radius.

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The correct matches are:

(i) Acid chlorides and esters experience primarily dipole-dipole interactions between their molecules.

(ii) 1º and 2º amides experience primarily hydrogen bonding between their molecules.

(iii) Acid chlorides, esters, and 3º amides have lower boiling points than other carboxylic acid derivatives of similar size and shape.

(iv) 1º and 2º amides have the highest boiling points among other carboxylic acid derivatives of similar size and shape.

i.

Acid chlorides and esters experience primarily dipole-dipole interactions between their molecules due to the presence of polar bonds within the molecules.

ii.

1º and 2º amides experience primarily hydrogen bonding between their molecules, as they contain the necessary hydrogen and oxygen or nitrogen atoms for hydrogen bonding.

iii.

Acid chlorides, esters, and 3º amides have lower boiling points than other carboxylic acid derivatives of similar size and shape. This is due to the absence of hydrogen bonding in these compounds, resulting in weaker intermolecular forces.

iv.

1º and 2º amides have the highest boiling points among other carboxylic acid derivatives of similar size and shape. This is because they can form extensive hydrogen bonding between their molecules, leading to stronger intermolecular forces and higher boiling points.

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Answer:

all

of them

Explanation: