A student was designing a model of the solar system and used a golf ball to represent the earth. which two objects could the student use to represent jupiter and the moon?

Answer: 37.485 psi

Explanation: using the gas law and assuming that volume is constant due to nor being stated we use the formula

P1/T1=P2/T2

Note that the tempreture should be changed from °C to K by adding 273

The chemical equations, IUPAC name, and Structural formulas are given below.

i. Chemical equations:

a) Conversion of unsaturated compound B to compound C:

B + HBr → C (Addition of hydrogen bromide to unsaturated B to form bromohexane C)

b) Conversion of compound C to compound D:

C + Na + Ether → D (Reaction of bromohexane C with sodium metal in the presence of ether to form compound D)

ii. IUPAC names:

Compound C: Bromohexane

Compound D: Hexane

iii. Structural formulae of positional isomers of compound C:

Positional isomers of bromohexane can have different bromine atoms attached at different positions along the hexane chain. Here is an example of one positional isomer of bromohexane:

1-Bromohexane:

CH3CH2CH2CH2CH2CH2Br

2-Bromohexane:

CH3CH2CH2CH2CH2CHBr

3-Bromohexane:

CH3CH2CH2CH2CHBrCH3

Therefore, the chemical equations, IUPAC name, and Structural formulas are provided above.

Learn more about IUPAC name here:

https://brainly.com/question/11516594

#SPJ1

Answer:

2,400 seconds

Explanation:

I multiplied the time value by 60 to get my answer

Hope this helped!

1.  the final concentration of NaOH after adding 125 mL of water to 45.3 mL of 0.71 M NaOH solution is approximately 0.189 M.

2.  the final concentration of KOH after adding 550 mL of water to 125 mL of 3.01 M KOH solution is approximately 0.557 M.

1.) If 125 mL of water is added to 45.3 mL of a 0.71 M NaOH solution, the resulting solution will be a diluted NaOH solution. The addition of water will increase the total volume while reducing the concentration of NaOH. To determine the final concentration of NaOH, we need to consider the conservation of moles.

First, let's calculate the moles of NaOH in the initial solution:

moles of NaOH = volume (in L) × concentration (in M)

moles of NaOH = 0.0453 L × 0.71 M = 0.0321433 moles

After adding 125 mL (0.125 L) of water, the total volume of the solution becomes 0.0453 L + 0.125 L = 0.1703 L.

To find the final concentration, we divide the moles of NaOH by the total volume:

final concentration of NaOH = moles of NaOH / total volume

final concentration of NaOH = 0.0321433 moles / 0.1703 L ≈ 0.189 M

Therefore, the final concentration of NaOH after adding 125 mL of water to 45.3 mL of 0.71 M NaOH solution is approximately 0.189 M.

2.) If 550 mL of water is added to 125 mL of a 3.01 M KOH solution, the resulting solution will also be a diluted solution. Again, we will apply the conservation of moles to determine the final concentration of KOH.

First, calculate the moles of KOH in the initial solution:

moles of KOH = volume (in L) × concentration (in M)

moles of KOH = 0.125 L × 3.01 M = 0.37625 moles

After adding 550 mL (0.55 L) of water, the total volume of the solution becomes 0.125 L + 0.55 L = 0.675 L.

To find the final concentration, divide the moles of KOH by the total volume:

final concentration of KOH = moles of KOH / total volume

final concentration of KOH = 0.37625 moles / 0.675 L ≈ 0.557 M

For more such questions on concentration visit:

https://brainly.com/question/28564792

#SPJ8

The freezing point of the solution is approximately 1.06306 °C

The freezing point of a solution of 0.300 mol of lithium bromide in 525 mL of water would be lower than the freezing point of pure water. The exact freezing point depression can be calculated using the formula ΔTf = Kf·m, where ΔTf is the freezing point depression, Kf is the freezing point depression constant of water (1.86 °C/m), and m is the molality of the solution. To find the molality of the solution, we need to convert the volume of water to mass using its density (1 g/mL), which gives us 525 g of water. Then, we can calculate the molality as:

molality = moles of solute/mass of solvent in kg
             = 0.300 mol / 0.525 kg
             = 0.571 mol/kg

Substituting this value into the freezing point depression formula, we get:

ΔTf = 1.86 °C/m x 0.571 mol/kg
      = 1.06306 °C

Therefore, the freezing point of the solution would be lowered by 1.06 °C compared to pure water.

Learn more about freezing point at https://brainly.com/question/40140

#SPJ11

From the balanced equation below the mole ratio of PCl3 to PCl5 is 1:1

\(PCl_{5} + PCl_{5}\) -------------------> \(PCl_{5}\)

Number of moles of \(PCl_{3}\) can be expressed as  1 mole

Number of moles of  \(Cl_{2}\) can be expressed as 1 mole

Number of moles of  \(PCl_{5}\) can be expressed as 1 mole

Mole ratio of \(PCl_{5}\) can be expressed as 1:1

The ratio of the mole quantities of any two compounds present in a balanced chemical reaction is known as the mole ratio. A comparison of the ratios of the molecules required to accomplish the reaction is given by the balancing chemical equation.

Learn more about mole ratio at;

https://brainly.com/question/30632038

#SPJ1

Answer:

A

Explanation:

Answer:

A. antibodies

Explanation:

Answer:

44

Explanation:

(16 × 2) + (12 × 1)

so basically 32 plus 12 which equals 44

Answer:

60 dollars!

Explanation:

So, 12 oranges cost $36 dollars.

Now, we can solve this by finding the value for only one orange, then multiplying that by 20 to get our answer!

So, the value of one orange is $36 / 12 = $3. One orange is worth $3 dollars.

So, 20 oranges will be worth 20 * 3 = $60 dollars!

The percent ionization of a 0.14 M benzoic acid solution in pure water is approximately 2.6%.

Benzoic acid is a weak acid, and when it is dissolved in water, it undergoes a reversible dissociation reaction:

The equilibrium constant for this reaction is known as the acid dissociation constant, Kₐ. The value of Kₐ for benzoic acid is given as 6.5 x 10⁻⁵.

To calculate the percent ionization, we need to determine the concentration of the ionized form of the acid (C₇H₅O₂⁻) at equilibrium.

At equilibrium, the initial concentration of benzoic acid (HC₇H₅O₂) will decrease by an amount x, and the concentration of the ionized form (C₇H₅O₂⁻) will increase by the same amount.

Using the equilibrium expression for Ka, we can write:

Assuming that x is small compared to the initial concentration of benzoic acid, we can make the approximation that [HC₇H₅O₂] ≈ 0.14 M - x, and [C₇H₅O₂⁻] ≈ x. We can also assume that [H₃O⁺] ≈ x, since benzoic acid is a weak acid and the concentration of H₃O⁺ will be very small compared to the initial concentration of benzoic acid.

Substituting these approximations into the equilibrium expression, we get:

Solving for x using the quadratic formula, we get:

The percent ionization is then:

Therefore, the percent ionization of a 0.14 M benzoic acid solution in pure water is approximately 2.6%.

To learn more about percent ionization, here

https://brainly.com/question/31358773

#SPJ4

We need to take 5ul of stock solution and add it to 5ul of diluent to achieve a final concentration of 100ug/L.

To solve this problem, you will need to create a stock solution of the chemical substance and then dilute it to the desired concentrations. Here's one way you could approach it:

Create a stock solution by dissolving the 5mg of powder in a solvent with a 2g/L solubility. We know that the solubility of the substance is 2g/L, so we can use the formula:

Stock solution concentration = (mass of substance) / (volume of solvent)

In this case, the mass of the substance is 5mg and the volume of solvent is 1L. So, the stock solution concentration is:

5mg / (1L) = 5mg/L

Dilute the stock solution to the desired concentration for the first dose of 10ug/L. To do this, we can use the formula:

Desired concentration = (volume of stock solution) / (volume of diluent)

In this case, we want a final concentration of 10ug/L, so we'll let the volume of stock solution be x and the volume of diluent be (5ul-x). Then we can set up the equation:

10ug/L = (x) / (5ul-x)

Solving this equation:

x = 0.5ul

Therefore, we need to take 0.5ul of stock solution and add it to 5ul of diluent to achieve a final concentration of 10ug/L

Dilute the stock solution to the desired concentration for the second dose of 100ug/L. Using the same formula as before:

Desired concentration = (volume of stock solution) / (volume of diluent)

In this case, we want a final concentration of 100ug/L, so we'll let the volume of stock solution be y and the volume of diluent be (10ul-y). Then we can set up the equation:

100ug/L = (y) / (10ul-y)

Solving this equation:

y = 5ul

Therefore, we need to take 5ul of stock solution and add it to 5ul of diluent to achieve a final concentration of 100ug/L

So, you can create a stock solution by dissolving 5mg of powder in a solvent with 2g/L solubility and obtain a stock solution of 5mg/L. With this stock solution, you can create two dilutions, the first one is 10ug/L by adding 0.5ul of stock solution to 5ul of diluent, and the second one is 100ug/L by adding 5ul of stock solution to 5ul of diluent.

Learn more about stock solution in brainly.com/question/25256765

#SPJ1

The molecule contains two chiral carbon atoms.

To determine the number of chiral carbon atoms in a molecule, we need to identify the carbon atoms that are bonded to four different substituents.

The structure of 2-chloro-4,5-dimethyl-3-hexone is:

    Cl

     |

CH3-C-CH2-C(CH3)2-CH(CH3)-CO

     |

    CH3

There are two carbon atoms that have four different substituents: the second carbon (C2) and the fifth carbon (C5). These two carbon atoms are chiral centers.

Therefore, the molecule contains two chiral carbon atoms.

To know more about substituents refer here

brainly.com/question/30779133#

#SPJ11

Answer:

Por formación de burbujas.

Explicación:

La presencia de burbujas en la superficie de la bebida ayuda a determinar si la bebida tiene gas carbonatado o dióxido de carbono. El gas de dióxido de carbono no se puede mezclar con agua ni disolver en agua normalmente. Se puede agregar mediante alta presión al agua para que cuando se coloquen en condiciones normales, el dióxido de carbono se libere en forma de burbujas. No, el gas hidrógeno y el gas hidrógeno no podrían formar agua carbonatada porque ambos son átomos diferentes. El agua carbonatada tiene gas dióxido de carbono, no gas hidrógeno.

Answer:

The energy needed to change the temp of a substance

Explanation:

Answer:

when we drink the milk the digestive system produce protease enzyme to break down the protein of milk.

Answer: only for the equation.

2KNO3->2KNO2+O2

Explanation:

Answer:

883g

Explanation:

The mass of 0.327 liters of Aluminum is 0.8829g.

Mass is an intrinsic property of a body which is related to the amount of matter in a physical body until the discovery of atomic and particle physics.

It is described as the amount of matter present in an object or body. Everything we see around us has mass like table, chair, your bed, football, glass and even air has mass.

Mass can be expressed as

Density= Mass/ Volume

so,

mass= Density * volume

where, mass is in grams

density is in \(g/cm^3\)

volume is in \(cm^3\) or Litres

For above given information, Density is 2.72 \(g/cm^3\) for Aluminum

Volume is 0.327 Lt.

so, mass= 2.72 * 0.327

mass = 0.8829g

Thus, the mass of 0.327 liters of Aluminum is 0.8829g.

Learn more about Mass, here:

https://brainly.com/question/952755

#SPJ2

Answer:

Yes Because the calculated volume is more accurate because you are able to measure the smaller dimensions.

~Apex lab

There are 4.52 × 10²³ molecules in 0.75 moles of oxygen gas.

The molecules in a substance can be calculated by multiplying the number of moles in the substance by Avogadro's number as follows;

no of molecules = no of moles × 6.02 × 10²³

According to this question, there are 0.75 moles of oxygen gas. The number of molecules can be calculated as follows;

no of molecules = 0.75 × 6.02 × 10²³

no of molecules = 4.52 × 10²³ molecules

Learn more about no of molecules at; https://brainly.com/question/11815186

#SPJ1

Answer:

a. atoms are made up of mostly empty space.(this is because most of the atoms were able to pass through the gold foil undeflected)

Explanation:

Answer:

a. atoms are made up of mostly empty space

There are 6.4 × 10⁻¹⁵ Coulombs in 4 × 10⁴ electrons.

To convert the number of electrons to coulombs, we need to first multiply the number of electrons by the charge of a single electron

No. of electrons × Charge of single electron

Charge of single electron = 1.6 × 10⁻¹⁹ coulombs

Calculating using the above formula

we get: 4 × 10^4 electrons × 1.6 × 10⁻¹⁹ C/electron = 6.4 × 10⁻¹⁵ Coulombs

To know more about Electrons refer to this link

https://brainly.in/question/374445

Answer:

if hyper its probaly because the have ADHD which is a type of drug that helps people with behavior disorders . the might have ticks wich is something that people can not control.

Explanation:

B

The sodium hydroxide (NaOH) solution is a basic solution, so the pH of that solution should be close to 14

then when adding hydrochloric acid (HCl) we start to neutralice the solution, meaning the pH must sift slowly to lower pH.

Assuming both solutions have similar concentration the pH shall shift form basic (above 7) to acid pH (below 7). Until now both B and D images agreed with the explanation given. To chose between them we need to remember that HCl is a very strong acid, which means that in solution will get to very acid solutions (very low pH values) which leaves only B as possible answer

"Hypotonic solution," refers to a solution with the highest water concentration due to its lower solute concentration compared to the other options, leading to water influx into cells.

A hypotonic solution would be most likely to have the highest water concentration. In a hypotonic solution, the solute concentration is lower than that inside the cell or compared to another solution. As a result, water tends to move into the cell or the solution to equalize the concentration.

When a cell is placed in a hypotonic solution, water molecules will move into the cell through the process of osmosis. This influx of water increases the water concentration inside the cell, leading to cell swelling or even bursting in extreme cases.

Compared to hypertonic and isotonic solutions, a hypotonic solution has a lower solute concentration, allowing for a higher concentration of water molecules. This results in a higher water concentration in the solution. It's important to note that the concept of tonicity is related to the relative solute concentrations between two solutions and their effect on cell osmosis. In this case, a hypotonic solution is characterized by a higher water concentration compared to the other options.

learn more about Hypotonic solution here:

https://brainly.com/question/28020628

#SPJ11

Answer:

I can confirm that 100 degrees Celsius is 373 degreed Kelvin

Explanation:

To be exact, 100°C = 373.15°K, but rounding down would then give us 373.

Explanation:

b. salt water is the correct answer

Which of the following is a solution?

A) milk

B) salt water

C) chlorine

D) muddy water

What is a solvent ?

A liquid that can dissolved in a solution.

What is a solute ?

A substance that is dissolved in a solution.

What is a solution ?

A solution is a homogeneous mixture of one or more solutes dissolved in a solvent.

Opition a)

Milk is not a solution. Milk is a mixture because milk has more than one phase suspended in it. Milk is a mixture of water, lipids, fats, proteins, and carbohydrates, as well as other substances.

Opition a is not the correct answer

Opition b)

Salt water is a solution. It is a solution because salt particles completely dissolve in water.

Opition b is the correct answer

Opition c)

Chlorine gas is an element. An element is a pure substance that consists of only one type of particle.

Opition d)

Muddy water is not a solution.It is a mixture. Solid dust and liquid have been mixed but the two but the two are not mixed on a molecular scale to form one state.

Opition d is not the correct answer

Answer:

\(\boxed {\boxed {\sf About \ 1.040 \ moles \ of \ nitrogen }}\)

Explanation:

To convert from grams to moles, we must use the molar mass. This can be found on the Periodic Table. We have a sample of nitrogen, so look for N on the table.

Now, use this molar mass as a ratio.

\(\frac {14.007 \ g \ N }{1 \ mol \ N }\)

Multiply by the number of grams in the sample (14.57)

\(14.57 \ g \ N *\frac {14.007 \ g \ N }{1 \ mol \ N }\)

Flip the fraction so the grams of nitrogen will cancel.

\(14.57 \ g \ N *\frac {1 \ mol \ N }{14.007 \ g \ N}\)

\(14.57 *\frac {1 \ mol \ N }{14.007 }\)

\(\frac {14.57 \ mol \ N }{14.007 }\)

\(1.04019419 \ mol \ N \\\)

The original measurement of grams had 4 significant figures, so we need to round our answer to the same number of sig figs.

For the number we calculated, that is the thousandth place. The 1 in the ten thousandth place tells us to keep the 0 in the thousandth place.

\(1.040 \ mol \ N\)

There are about 1.040 moles of nitrogen in 14.57 grams.