a student records the mass of objects a, b, c, and d. then the velocity of each object is measured using a track and timer. does object a, b, c, or d have the greatest momentum?

Answer:

B. 2 m/s

Explanation:

With all collisions, momentum is conserved. This is known as the Conservation of Momentum.

To find the momentum of an object, multiply its mass by its velocity.

\(m_yv_y+m_ov_o=(m_y+m_o)v_f\), solving for vf

Plugging in numbers, we get:

\(100\cdot 8 + 200(-1)=(100+200)v_f\)

\(300v_f=600,\\v_f=\boxed{2\text{ m/s}}\)

Answer:

F = M a        describes motion of cart

F = 10 kg * 4 m/s^2 = 40 Newtons           applied force

W = F * S = 40 N * 3 m = 120 Joules         work resulting

 The question asks about the best time to conduct a quick inspection of the work area to identify potential hazards.

The best time to perform a quick inspection of the work area to identify potential hazards is before starting any task or activity. Prior to beginning work, it is crucial to conduct a visual assessment of the surroundings to identify any existing or potential hazards. This proactive approach allows for early detection and mitigation of risks, ensuring a safer work environment.

By conducting a pre-task inspection, workers can identify potential hazards such as spills, loose wires, obstructed pathways, or any other unsafe conditions that may pose a risk to their safety or the safety of others. Addressing these hazards before commencing work minimizes the chances of accidents or injuries and promotes a more secure work environment.

Taking the time to regularly assess the work area for hazards is a fundamental aspect of maintaining a safe workplace. It is essential to remain vigilant throughout the workday, promptly addressing any new hazards that may arise and promptly resolving them. By continuously monitoring and inspecting the work area, potential hazards can be identified and rectified promptly, helping to prevent accidents and maintain a safe and healthy working environment.

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The gravitational force of Earth on the satellite, given that the satellite is launched into orbit 30000 km above sea level is 1.63×10³ N

The gravitaional force between two objects can be obtained by using the following formula:

F = GM₁M₂ / r²

Where

The following data were obtained from he question:

The gravitaional force can be obtained as shown below:

F = GM₁M₂ / r²

F = (6.673×10¯¹¹ × 5.4×10³ × 6.0×10²⁴) / (36400000)²

F = 1.63×10³ N

Thus, the gravitational force is 1.63×10³ N

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Cost estimated is ₹[19/4]y/-.

Given :- Power=3kW  , Time=1hr 35min

Now to convert this time completely into hours following steps can be adopted:- 1 min =1/60 hour,       so 35min =35/60 hour

35min= 35/60 =7/12 hour

So total computed time = 1hr + [7/12]hr

computed time =19/12hr

Now since in the question there is no mention about cost , so let the cost be ₹y/unit.

Mathematically , Energy is the product of power and time , i.e.

E= Power x Computed time = 3 x 19/12 = 19/4 units.

Now the energy estimated is 19/4 units whose cost equivalent will be ₹[19/4]y/- , as cost of one unit energy  is ₹y/- so cost of 19/4 energy units will be ₹[19/4]y/-.

Once the cost of one unit energy is known to us then just its value in the place of y and we will get the exact amount expended on the total energy consumption.

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The general equation of a circle in Cartesian coordinates is given by:

\((x - h)^2 + (y - k)^2 = r^2,\)

where (h, k) represents the coordinates of the center of the circle, and r represents the radius. Without the specific equation, we cannot determine if x and y satisfy it.

A circle is a two-dimensional geometric shape that is perfectly round and symmetrical. It is defined as a set of points that are equidistant from a central point called the center. The distance from the center to any point on the circle is called the radius, and it is the same for all points on the circle.

A circle is often represented by the symbol "⚪" or by writing its name. It is a fundamental concept in geometry and mathematics, and it has numerous properties and applications in various fields.

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The final velocity of the ball, given the data is –13.8 m/s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

The final velocity of the ball can be obtained as follow:

a = (v – u) / t

–2 = (v – 0.2) / 7

Cross multiply

v – 0.2 = –2 × 7

v – 0.2 = –14

Collect like terms

v = –14 + 0.2

v = –13.8 m/s

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Answer:

Yes

Explanation:

sorry if im wrong

The velocity of the child is 3.36 m/s. Then, the distance it covered is 14 meters. The radius from the centre is then, 2.24 m.

Centripetal acceleration is the acceleration of a body moving through a circular paths. It is the rate of change of its angular velocity.

The acceleration of the child = 0.80 ms/²

time  = 4.2 s

velocity = time interval × acceleration

             = 4.2 s ×  0.80 ms/²= 3.36 m/s.

Then the distance covered  = velocity × time

= 3.36 m/s × 4.2 = 14.22 m.

This is the circumference of the circular path which is equal to 2πR.

The distance from the centre = radius of the path.

2πR = 14.22 m

R = 2.24 m

Therefore, the child will be 2.24 m far from the center of the ride.

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Answer:

friction

the rubbing of the surfaces create friction, giving off heat

Answer:

heat is produced by rubbing our hands  together which cause friction and during the process you can feel heat.

The magnitude of the sum of the frictional forces acting on the bike and its rider is 400N.

The friction force is the opposing force which acts on the object which is in relative motion.

The driving force is equal and opposite to the friction force acting between road and bicycle.

Friction force = 400N

The friction force between rider and bike is zero.

So the magnitude of sum of friction force = 400N +0 = 400N

Thus, the magnitude of the sum of the frictional forces acting on the bike and its rider.

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The force of gravity acting on 23.9 kg person is equal to 234.22 Newton.

Force of gravity is also referred to weight and it can be defined as the force acting on a physical object or body, especially due to the effect of gravity.

Mathematically, the force of gravity on a physical body can be calculated by using this formula:

W = mg

Where:

Note: Acceleration due to gravity is equal to 9.8 m/s².

Substituting the given parameters into the formula, we have;

Force of gravity = 23.9 × 9.8

Force of gravity = 234.22 Newton.

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Complete Question:

What is force of gravity acting on 23.9 kg person?

The types of electromagnetic radiation in order of decreasing frequency will be D. ultraviolet > infrared > microwave > radio.

This is the radiation that travels in waves and possesses both an electric and magnetic field. Both natural and artificial sources contribute to it. The energy levels of electromagnetic radiation can range from low to high. It consists of x-rays, gamma rays, infrared light, visible light, ultraviolet light, radio waves, and microwaves.

When a charged particle, like an electron, changes its velocity—that is, when it is accelerated or decelerated—electromagnetic radiation is created. As a result, the charged particle loses the energy of the electromagnetic radiation that is thus created.

It should be noted that radio has highest wavelength and ultraviolet has lowest wavelength.

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Answer:

it gives off 71.0 kJ of heat.

Explanation:

Answer:

the driver need to stop before he drive

Explanation:

if he keep driving he will hit a car

Answer:

Explanation:

Fgrav = 45.9 N; Fnorm = 45.9 N; Ffrict = 5.32 N; Fnet = 3.81 N, right; mu = 0.116

The starting point for any problem such as this is the construction of a free-body diagram in which you show all the individual forces which are acting upon the book. There are two vertical forces - gravity and normal force. There are two horizontal forces - friction and the applied force.

Since there is no vertical acceleration, normal force = gravity force. Each of these forces can be determined using the equation Fgrav = m • g = (4.68 kg) • (9.8 m/s/s) = 45.864 N

The net force can be determined from knowledge of the mass and acceleration of the sled. Fnet = m • a = (4.68 kg) • (0.815 m/s/s) = 3.8142 N, right.

Since the net force is to the right (in the direction of the applied force), then the applied force must be greater than the friction force. The friction force can be determined using an understanding of net force as the vector sum of all the forces. So 3.81 N, right = 9.13 N, right + Ffrict. Therefore, Ffrict = 5.32 N, left.

The coefficient of friction can now be determined as the ratio of friction force to normal force. "mu" = Ffrict / Fnorm = (5.32 N) / (45.864 N) = 0.116.

Thermal equilibrium is the final state of two objects in thermal contact with each other because when two objects are in thermal contact, heat will transfer between them until they reach the same temperature.

Thermal equilibrium can also mean an even distribution of thermal energy throughout a single object or body. Thermal energy in a single system does not immediately have an equal level of heat across its entirety. If an object is heated, the point on the object or system at which thermal energy is applied will initially be the area with the highest temperature whereas other regions on or in the system will have a lower temperature.

So, Thermal equilibrium is the final state of two objects in thermal contact with each other.

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The degree in which the question measures what the analyst intends to measure is called validity.

Validity is a measure of how accurately a test or questionnaire captures the construct it is intended to measure. It ensures that the test is measuring what it is supposed to measure and that the results are meaningful and reliable.
There are different types of validity that can be assessed to determine the accuracy of a measure. For example, content validity examines whether the items in a test adequately represent the content domain being measured. Criterion validity determines how well the test scores correlate with a criterion measure. Construct validity evaluates how well a test measures an underlying construct or concept.
Validity ensures that the measure accurately captures what the analyst intends to measure. It is an important aspect to consider when designing and evaluating tests or questionnaires.

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Airport security uses X-rays to see items inside of luggage without having to open the bags. Hence, the type of electromagnetic waves that would be best for airport security to use is X-rays.

Electromagnetic waves are a type of wave that includes both electric and magnetic energy that propagate through space at the speed of light. They are created by the oscillation of electric and magnetic fields that are perpendicular to one another. They are classified according to their frequency or wavelength.

The different types of electromagnetic waves are:

X-rays are a form of electromagnetic radiation. They have a higher frequency and shorter wavelength than ultraviolet (UV) radiation. X-rays are used to take images of the inside of objects or to treat cancer.What are X-rays used for?X-rays are used for medical imaging, such as chest X-rays, mammograms, and dental X-rays. They are also used in the manufacturing industry to check for defects in products, in research to study the properties of materials, and in security to scan luggage at airports.

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Answer:

If an object is in motion, then the object will stay in motion because they go the same direction unless acted upon by an unbalanced force.

Explanation:

i got it right . :)

To win a  driver negligence claim, the victim (plaintiff) must prove four things: OBLIGATIONS, BREACH OF DUTY, CAUSE OF INJURY AND DAMAGE.

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Approximately 31.6 times more energy is released in a 6.5 moment magnitude earthquake than in one with mw of 5.5.

In terms of seismic energy, the difference between a 6.5 moment magnitude (Mw) earthquake and a 5.5 Mw earthquake is significant. The moment magnitude scale is logarithmic, which means that each whole number increase represents a tenfold increase in the amplitude of seismic waves and roughly 31.6 times more energy release. In other words, a 6.5 Mw earthquake releases approximately 31.6 times more energy than a 5.5 Mw earthquake.

The moment magnitude scale provides a measure of the total energy released by an earthquake, taking into account the area of the fault that slipped and the average amount of slip along the fault. It is a more accurate and reliable measure compared to the Richter scale, which only considers the amplitude of seismic waves at a specific distance from the earthquake.

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To determine the relative size of nuclei, you can use a simple relationship known as the "semi-empirical mass formula" or the "liquid drop model." According to this model, the radius of a nucleus is proportional to the cube root of its mass number (A).

Let's compare the nuclei:

For the nucleus 56^26Fe, the mass number (A) is 56.

For the nucleus 112^48Cd, the mass number (A) is 112.

To find the relative size of the nuclei, we can compare the cube roots of their mass numbers.

For the nucleus 56^26Fe:

Cube root of 56 = ∛56 ≈ 3.78

For the nucleus 112^48Cd:

Cube root of 112 = ∛112 ≈ 4.83

Comparing the cube roots, we find that the cube root of 112^48Cd is approximately 1.28 times larger than the cube root of 56^26Fe. Therefore, the radius of the nucleus 112^48Cd is about 1.28 times larger than the radius of the nucleus 56^26Fe.

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Ultra = X-ray

Explanation:

how are things going to paint the roof for beginners painting and decorating the whole house so I'm going away with a few sports mates for a couple nights for beginners but will have a look painting at a time and see what is going to be Strong enough

The clearest example of a neuronal membrane's selective permeability is an option (b) - K+ ions can diffuse across the membrane more easily than Na+ ions. This is because the membrane is more permeable to K+ ions than to Na+ ions.

This is due to the presence of potassium ion channels, which allow K+ ions to easily cross the membrane. On the other hand, the presence of sodium ion channels is limited, which makes it more difficult for Na+ ions to cross the membrane.

The selective permeability of the neuronal membrane is crucial for maintaining the proper functioning of the nervous system. It allows for the regulation of ion concentrations inside and outside the cell, which is essential for generating and transmitting electrical signals. This selective permeability is achieved through the presence of ion channels and transporters that selectively allow certain ions to pass through the membrane.

In summary, the clearest example of a neuronal membrane's selective permeability is the fact that K+ ions can diffuse across the membrane more easily than Na+ ions, due to the presence of potassium ion channels and the limited presence of sodium ion channels. Hence, b is the correct option.

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The correct response is conduction.

                      Conduction provides an explanation for how heat is transferred from the hot soup to the spoon. The mechanism of heat transfer is known as conduction. It involves materials or objects coming into direct touch with one another.

                      In this instance, the spoon is in direct contact with the hot soup, allowing heat energy to transfer from the soup to the spoon. The particles of the spoon vibrate more vigorously as particles in the soup have a higher temperature, which raises the temperature of the spoon.

                      Whereas convection is the process of transferring heat by the circulation or stirring of a fluid, such as hot soup. In this situation, radiation which is the transfer of heat by electromagnetic waves is not happening. Examples of radiation: are sunrays, microwaves from an oven, X-rays from an X-ray tube, and gamma rays from radioactive elements.

Correct question:

"A spoon becomes warmer as it rests in a cup of hot soup." Choose the phenomenon causing this among the given options:

conduction

convection

radiation

convection

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(a)The pressure at B is 0.1248 atm.

(b)The temperature at C is 727.1 K.

(c)The total work done by the gas in one cycle is -1979J

General calculation:

We can use the First Law of Thermodynamics to analyze the heat engine cycle:

ΔU = Q - W

where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system. For a complete cycle, ΔU = 0, so:

Q = W

We can also use the ideal gas law to relate the pressure, volume, and temperature of the gas:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature.

(a)How to find the pressure at B segment?

To find the pressure at B, we can use the fact that the segment AB is an isothermal expansion. This means that the temperature remains constant, so:

PV = nRT

PB = (nRT)/(2V) = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/(2V) = (0.0821 L·atm/mol)(600 K)/V

Since the pressure at A is 5.00 atm, we can use the fact that the temperature is constant to find the volume at A:

PV = nRT

VA = (nRT)/P = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/5.00 atm = 197.76 L

Since the volume at B is twice the volume at A, we have:

VB = 2VA = 395.52 L

Substituting into the expression for PB, we get:

PB = (0.0821 L·atm/mol)(600 K)/395.52 L = 0.1248 atm

Therefore, the pressure at B is 0.1248 atm.

To find the temperature at C, we can use the fact that the segment BC is an adiabatic expansion. This means that no heat is added or removed from the system, so:

\(PV^\gamma\)= constant

where γ is the ratio of specific heats (for a monoatomic gas, γ = 5/3). We can use the fact that the volume at C is equal to the volume at A to find the pressure at C:

\(PAV^\gamma = PCV^\gamma\)

PC =  \(PA(V/A)^\gamma\) = 5.00 atm\((1/2)^(^5^/^3^)\) = 1.556 atm

Since the segment BC is adiabatic, the temperature changes but no heat is added or removed from the system. Using the ideal gas law, we can relate the pressure, volume, and temperature:

PV = nRT

TC = (PCVC)/(nR) = (1.556 atm)(197.76 L)/(2.00 mol)(0.0821 L·atm/mol·K) = 727.1 K

Therefore, the temperature at C is 727.1 K.

The total work done by the gas in one cycle is the sum of the work done in each segment of the cycle:

W = WAB + WBC + WCD + WDA

For segment AB, the work done is:

WAB = -QAB = -∫PdV = -nRT∫(1/V)dV = -nRT ln(VB/VA) = -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2) = -602 J

For segment BC, the work done is:

WBC = -QBC = -∫PdV = -nγRT∫(1/V)dV = -nγRT

We know that VB = 2VA and VC = 2VD, so we can express the ratio VB/VC in terms of VA/VD:

VB/VC = (2VA)/(2VD) = VA/VD

Substituting into the expression for WBC, we get:

WBC = -nγRT ln(VA/VD)

For segment CD, the work done is:

WCD = -QCD + PCDΔV = -nCpΔT + PCDΔV

where Cp is the specific heat at constant pressure, ΔT is the change in temperature, and ΔV is the change in volume. We know that the segment CD is isobaric, so ΔV = VB - VA = (2VA) - VA = VA. We can also use the ideal gas law to relate the pressure, volume, and temperature:

Substituting into the expression for WCD, we get:

WCD = -nCpΔT + (nRT/VD)VA = -nCp(TC - TD) + (nRT/VD)VA

For segment DA, the work done is:

WDA = -QDA + ΔU = -nCvΔT

where Cv is the specific heat at constant volume. We know that the segment DA is isovolumetric, so ΔV = 0. Using the First Law of Thermodynamics, we know that ΔU = 0 for a complete cycle, so:

QDA = -WDA = nCvΔT

Substituting into the expression for WDA, we get:

WDA = -nCvΔT

Adding up the work done in each segment, we get:

W = WAB + WBC + WCD + WDA

= -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(Cp)(TC - TD) + (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(Cv)(TC - TA)

We know that Cp and Cv for a monoatomic gas are related by Cp = Cv + R, so we can express Cp in terms of Cv:

Cp = Cv + R = (3/2)R + R = (5/2)R

Substituting and simplifying, we get:

W = (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(727.1 K)+ (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(600 K)

W = -966.2 J - 4957 J - 7476 J + 5154 J

    = -1979 J

Therefore, the total work done by the gas in one cycle is -1979 J

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On mercury, the smooth plains and the intercrater plains are different in that the smooth plains formed more recently while the intercrater plains took longer to form.

The planet is terrestrial, which means it has a solid surface and is primarily composed of silicate rocks or metals. Iron dominates the composition of Mercury. Mercury lacks a moon

Mercury, like Earth, Venus, and Mars, is a terrestrial planet, which means that its silicate mantle and crust are made up of silicate minerals, while its iron core is made up of silicate minerals and metals. The plane's iron content, however, is disproportionately high compared to other rocky planets in the solar system.

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When the distance between two point charges is increased by a factor of 2, the force they exert on each other decreases to 1/4 of the original force. The relation is governed by the Coulomb's Law.

According to Coulomb's Law, the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. In this scenario, if the distance between the charges is increased by a factor of 2, it means that the new distance is twice the original distance.

Since the force is inversely proportional to the square of the distance, doubling the distance will result in the force becoming 1/4 of the original force. Mathematically, this can be represented as follows:

\(F' = F / (2^2)\)

\(F' = F / 4\)

Therefore, the force between the two charges will become 1/4 (or 25%) of the original force when the distance between them is increased by a factor of 2.

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Answer:

1: The Ball Has 80,000 J

2: Their Potential Energy Is 934,083 J At That Point

3: They Would Have 203,200 Kinetic Energy

4: The Person Would Have More Potential Energy GoingUp A 1500 M Hill Rather Than Walking 1500 M On A Flat Surface Because When You Walk Up Something You Have More Potential Energy Then When You Walk On Flat Ground

Reason:

1: 100kg x 40 m/s = 80,000

2: 63.5 x 1500 M = 934,083

3: 63.5 x 80 M/s = 203,200