Answers
Answer: a. Place the object on one side of a lever at a known distance away from the fulcrum. Place known masses on the other side of the fulcrum so that they are also paced on the lever at known distance from the fulcrum. Move the known masses to a known distance such that the lever is in static equilibrium.
d. Place the object on the end of a vertically hanging spring with a known spring constant. Allow the spring to stretch to a new equilibrium position and measure the distance the spring is stretched from its original equilibrium position.
Explanation:
The options are:
a. Place the object on one side of a lever at a known distance away from the fulcrum. Place known masses on the other side of the fulcrum so that they are also paced on the lever at known distance from the fulcrum. Move the known masses to a known distance such that the lever is in static equilibrium.
b. Place the object on a surface of negligible friction and pull the object horizontally across the surface with a spring scale at a non constant speed such that a motion detector can measure how the objects speed as a function of time changes.
c. Place the object on a surface that provides friction between the object and the surface. Use a surface such that the coefficient of friction between the object and the surface is known. Pull the object horizontally across the surface with a spring scale at a nonconstant speed such that a motion detector can measure how the objects speed as a function of time changes.
d. Place the object on the end of a vertically hanging spring with a known spring constant. Allow the spring to stretch to a new equilibrium position and measure the distance the spring is stretched from its original equilibrium position.
Gravitational mass simply has to do with how the body responds to the force of gravity. From the options given, the correct options are A and D.
For option A, by balancing the torque, the mass can be calculated. Since the known mass and the distance has been given here, the unknown mass can be calculated.
For option D, here the gravitational force can be balanced by the spring force and hence the mass can be calculated.
The experiments which a student can use to determine the gravitational mass of an object are:
A. Place the object on one side of a lever at a known distance away from the fulcrum. Place known masses on the other side of the fulcrum so that they are also paced on the lever at known distance from the fulcrum. Move the known masses to a known distance such that the lever is in static equilibrium. D. Place the object on the end of a vertically hanging spring with a known spring constant. Allow the spring to stretch to a new equilibrium position and measure the distance the spring is stretched from its original equilibrium position.According to the complete question, we can see that a student is trying to find the gravitational mass of an object and he has to perform a series of steps to get the answer he needs and we need to show the two experiments which would be valid.
As a result of this, a gravitational mass of an object is the feature of a system which affects the amount of gravitational force which acts on it.
WIth this in mind, we can see that gravitational mass of an object, we would use a fulcrum and a spring constant.
Therefore, the correct answers are options A and D
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Related Questions
A disk of radius 25 cm spinning at a rate of 30 rpm slows to a stop over 3 seconds. What is the angular acceleration? B. How many radians did the disk turn while stopping ? C. how many revolutions?
Answers
Answer:
A. The angular acceleration of the disk is -1.047 radians per square second.
B. The disk turns 4.715 radians while stopping.
C. The disk did 0.750 revolutions while stopping.
Explanation:
A. In this case, the disk is deceleration at a constant rate. Hence, the angular acceleration experimented by the object (\(\alpha\)), in radians per square second, can be found by means of this kinematic expression:
\(\alpha = \frac{\omega-\omega_{o}}{t}\) (1)
Where:
\(\omega_{o}\) - Initial angular speed, in radians per second.
\(\omega\) - Final angular speed, in radians per second.
\(t\) - Time, in seconds.
If we know that \(\omega_{o} \approx 3.142\,\frac{rad}{s}\), \(\omega = 0\,\frac{rad}{s}\) and \(t = 3\,s\), then the angular acceleration of the disk is:
\(\alpha = \frac{\omega-\omega_{o}}{t}\)
\(\alpha = -1.047\,\frac{rad}{s^{2}}\)
The angular acceleration of the disk is -1.047 radians per square second.
B. The change in position of the disk (\(\Delta \theta\)), in radians, is determined by the following kinematic formula:
\(\Delta \theta = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot \alpha}\) (2)
If we know that \(\omega_{o} \approx 3.142\,\frac{rad}{s}\), \(\omega = 0\,\frac{rad}{s}\) and \(\alpha = -1.047\,\frac{rad}{s^{2}}\), then the change in position is:
\(\Delta \theta = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot \alpha}\)
\(\Delta \theta = 4.715\,rad\)
The disk turns 4.715 radians while stopping.
C. A revolution equals 2π radians, then, then number of revolutions done by the disk while stopping is found by simple rule of three:
\(\Delta \theta = 4.715\,rad \times \frac{1\,rev}{2\pi\, rad}\)
\(\Delta \theta = 0.750\,rev\)
The disk did 0.750 revolutions while stopping.
Write 5.34 x 10^3 in standard form.
Answers
\(\\ \bull\tt\dashrightarrow 5.34\times 10^3\)
\(\\ \bull\tt\dashrightarrow 534\times 10^{-2}\times 10^3\)
\(\\ \bull\tt\dashrightarrow 534\times 10^{-2+3}\)
\(\\ \bull\tt\dashrightarrow 534\times 10^1\)
\(\\ \bull\tt\dashrightarrow 534\times 10\)
\(\\ \bull\tt\dashrightarrow 5340\)
In the Roman soldier model for refraction, what angle do the soldiers now appearing to be walking at (remember they entered at 45 )?
A. 45
B. Less than 45
C. Greater than 45
D. Not enough info
Answers
Snell's law states:
n₁ * sin(θ₁) = n₂ * sin(θ₂),
where n₁ and n₂ are the refractive indices of the first and second medium, respectively, and θ₁ and θ₂ are the angles of incidence and refraction, respectively.
Without knowing the refractive indices of the two media involved, we cannot determine the angle of refraction (θ₂) and cannot answer the question.In the Roman soldier model for refraction, the soldiers appear to be walking at an angle that is different from their actual direction of motion due to the bending of light at the interface between two media with different refractive indices.
Assuming that the soldiers entered the interface at an angle of 45 degrees, the angle at which they appear to be walking will depend on the refractive indices of the two media and the angle of incidence.
Since we are not given any information about the refractive indices of the media, we cannot determine the angle at which the soldiers appear to be walking. Therefore, the answer is D. Not enough info.
Can you help me with all 14 of this?
Answers
Answer: Can't see the graph clearly.
The displacement (in meters) of a particle moving in a straight line is given by the equation of motion:
s = 4/t^2, where t is measured in seconds.
Required:
Find the velocity of the particle at times t = a, t = 1, t = 2, and t = 3.
Answers
Answer:
At \(t = 1\; \rm s\), the particle should have a velocity of \(-8\; \rm m \cdot s^{-1}\).At \(t = 2\; \rm s\), the particle should have a velocity of \(-1\; \rm m \cdot s^{-1}\).At \(t = 3\; \rm s\), the particle should have a velocity of \(\displaystyle -\frac{8}{27}\; \rm m \cdot s^{-1}\).For \(a > 0\), at \(t = a \; \text{second}\), the particle should have a velocity of \(\displaystyle -\frac{8}{a^3}\; \rm m \cdot s^{-1}\).
Explanation:
Differentiate the displacement of an object (with respect to time) to find the object's velocity.
Note that the in this question, the expression for displacement is undefined (and not differentiable) when \(t\) is equal to zero. For \(t > 0\):
\(\begin{aligned}v &= \frac{\rm d}{{\rm d}t}\, [s] = \frac{\rm d}{{\rm d}t}\, \left[\frac{4}{t^2}\right] \\ &= \frac{\rm d}{{\rm d}t}\, \left[4\, t^{-2}\right] = 4\, \left((-2)\, t^{-3}\right) = -8\, t^{-3} =-\frac{8}{t^3}\end{aligned}\).
This expression can then be evaluated at \(t = 1\), \(t = 2\), and \(t = 3\) to obtain the required results.
A metal pot feels hot to the touch after a short time on the shove. what type of material is the metal pot
Answers
A record has an angular speed of
38.9 rev/min.
What is its angular speed?
Answer in units of rad/s.
pt 2
Through what angle does it rotate in 1.9 s?
Answer in units of rad
Answers
The record will rotate through an angle of 1.24°.
Angular speed of the record, ω = 38.9 rev/min = 0.65 rev/s
Time taken for the rotation, t = 1.9 s
Motion in a circular path or around the circumference of a circle is referred to as circular motion. It may rotate at a particular speed and angular rate or it may rotate at a variable rate, making it either uniform or non-uniform circular motion.
The angular speed is the rate of change of angular displacement.
Therefore, angular displacement of the record,
θ = ωt
θ = 0.65 x 1.9
θ = 1.24°
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greta is experiencing difficulty in mr. popanopoulous' class because she has different needs than many of the other students. greta must use a variable-speed tape recorder to record the lessons, she often struggles with spasticity, and she frequently uses finger spelling as a method of communication. which of the following disorders does not appear to describe greta's possible condition?
Answers
The disorder that does not appear to describe Greta's possible condition is epilepsy. The correct answer is B.
While epilepsy is a neurological disorder that can cause seizures and other symptoms, it does not typically result in the physical challenges that Greta is experiencing, such as spasticity and the need for a variable-speed tape recorder.
Additionally, epilepsy does not necessarily affect an individual's ability to communicate using finger spelling or impact their hearing or vision. Therefore, while Greta may have epilepsy in addition to her other challenges, it is not directly related to the issues she is experiencing in Mr. Popanopoulous' class.
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Your question seems incomplete, but I suppose the question was:
"Greta is experiencing difficulty in Mr. Popanopoulous' class because she has different needs than many of the other students. Greta must use a variable-speed tape recorder to record the lessons, she often struggles with spasticity, and she frequently uses finger spelling as a method of communication. Which of the following disorders does NOT appear to describe Greta's possible condition?
A) Cerebral palsy
B) Epilepsy
C) Hearing impairment
D) Visual impairment"
If a waterfall and a dam have the same height,
which one would have the most kinetic energy?
Explain why.
Answers
If a waterfall and a dam have the same height, the waterfall would have more kinetic energy. This is because kinetic energy depends on both height (potential energy) and velocity. A waterfall, being a free-falling stream of water, has a greater velocity than a dam, where the water is held back by a barrier. The greater velocity of the waterfall means that it has a greater kinetic energy.
Kinetic energy (KE) = 0.5 * mass * velocity^2, where mass is the mass of the water and velocity is its speed. As velocity increases, so does kinetic energy.
A boy throws a tell ball straight up . disregarding any effects of air resistance, the forces acting 9n the ball untill it returns to the ground is are
Answers
Which formula describes Boyle's law?
ОА.
OB.
D = m/v
V1T2 = V2T
P1V1 = P2V2
P1T2 = P2T1
Ос.
OD
Answers
Answer: P1V1 = P2V2
Explanation:
a ball is thrown with a speed of 17.7 m/s at an angle of 49.8° above the horizontal. how much time does the ball need to reach a height of 4.7 m above the release point ?
Answers
Answer:
The ball needs approximately \(0.41\; \rm s\) to reach that height for the first time.
Explanation:
The initial speed of the ball \(17.7\; \rm m \cdot s^{-1}\). However, what would be the initial vertical speed of this ball?
The angle of elevation is \(\theta = 49.8^\circ\). Consider the initial speed of this ball as the length of the hypotenuse of a right triangle. If the angle of elevation is one of the two acute angles of this triangle, the initial vertical speed of this ball would be the leg opposite to that angle.
\(\displaystyle \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}}\).
\(\displaystyle \sin \theta = \frac{v(\text{vertical, initial})}{v(\text{initial})}\).
Therefore:
\(\begin{aligned}&v(\text{vertical, initial})\\ &= v(\text{initial}) \cdot \sin\theta \\ &= 17.7\; \rm m \cdot s^{-1} \times \sin \left(49.8^\circ\right) \approx 13.5\; \rm m \cdot s^{-1}\end{aligned}\).
Let \(t\) denote the time (in seconds) required for the ball to reach a height of \(4.7\; \rm m\).
Let \(g\) denote the acceleration because of gravity (typically \(g \approx 9.81\; \rm m \cdot s^{-2}\) near the surface of the earth.) The height of the ball \(t\) seconds after it was thrown would be: \(\displaystyle \frac{1}{2}\, g \cdot t^{2} + v(\text{vertical, initial}) \cdot t\).
Assume that \(g \approx 9.81\; \rm m \cdot s^{-2}\). Set the value of this expression for height to \(4.7\; \rm m\) and solve for \(t\):
\(\displaystyle \frac{1}{2} \times 9.81 \, t^{2} + 13.5 \, t = 4.7\).
Either \(t \approx 0.41\) or \(t \approx 2.3\) will satisfy this equation. Both of these two values are reasonable. The first value for \(t\) (\(0.41\; \rm s\)) is the time required for the ball to reach a height of \(4.7\; \rm m\) for the first time. The second value (\(2.3\; \rm s\)) is the time required for the ball to come under that height on its way back to the ground. The question seems to be asking only for the first (the smaller one) of these two times.
Two boats start together and race across a 50-km-wide lake and back. Boat A goes across at 50 km/h and returns at 50 km/h. Boat B goes across at 25 km/h, and its crew, realizing how far behind it is getting, returns at 75 km/h. Turnaround times are negligible, and the boat that completes the round-trip first wins.
Required:
a. Which boat wins?
b. What is the average velocity of the winning boat?
Answers
Answer:
Boat A wins and 50km/hr
Explanation:
To solve this problem we need to calculate the time required for both boats to make the round trip.
For Boat A.
The time required for the first trip =distance/ speed = 50/50 = 1h
For the return trip the time is same since it's the same distance on the same speed.
Hence the time taken for boat A to make the round trip is 2hrs.
For boat B,
The time required for the first trip =distance/ speed = 50/25 = 2h
The time for the return trip is;
=distance/ speed = 50/75 = 2/3h= 2/3×60= 40mins
By comparing both time.
Boat A requires less time hence Boat A wins.
2.The average velocity of the winning boat is the velocity of boat A.
Which is total distance/ total time for the trip.
100km/2hrs = 50km/hr
boat A would win the race and the average velocity of the winning boat would be 50 km/h
What is Velocity?The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.
As given in the problem Two boats start together and race across a 50-km-wide lake and back. Boat A goes across at 50 km/h and returns at 50 km/h. Boat B goes across at 25 km/h, and its crew, realizing how far behind it is getting, returns at 75 km/h.
Turnaround times are negligible, and the boat that completes the round-trip first wins
Average velocity of the boat A = ( 50 + 50 ) / 2
= 50 km /h
Thus, boat A would win the race and the average velocity of the winning boat would be 50 km/h
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12.
A hiker walks for 5km on a bearing of 053" true (North 53° East). She then turns and
walks for another 3km on a bearing of 107° true (East 17° South).
(a)
Find the distance that the hiker travels North/South and the distance that she travels
East/West on the first part of her hike.
Answers
The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.
This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.
Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.
The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.
Angles will always be expressed in degrees in the solution.
The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.
The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.
Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.
The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.
The angle between the two is (180 - 53 - 17) = 110 degrees.
The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.
Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.
Distance Travelled East/WestThe hiker walked East for the second part of the hike.
To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.
The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.
Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.
To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.
The angle between the second vector and the Eastern direction is 17 degrees.
Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.
The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.
Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
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A bicycle wheel with a diameter of 24 inches is rotating 3 revolutions per second. What is the linear speed in feet/sec? Use 3.14 for pi and round to the nearest tenth
Answers
ANSWER
\(18.8ft\/s\)EXPLANATION
We want to find the linear speed of the bicycle in feet per second.
First, we have to find the circumference of the bicycle wheel (in feet).
The circumference of a circle is:
\(C=\pi\cdot D\)First, convert the diameter to feet:
\(\begin{gathered} 12in=1ft \\ \Rightarrow24in=\frac{24}{12}=2ft \end{gathered}\)Hence, the circumference of the wheel is:
\(\begin{gathered} C=3.14\cdot2 \\ C=6.28ft \end{gathered}\)This implies that each revolution is an equivalent linear distance of 6.28 ft i.e 6.28 feet per revolution.
To find the linear speed, we have to find the product of the circumference and the
rotational speed. That is:
\(\begin{gathered} s=6.28\frac{ft}{rev}\cdot3\frac{rev}{\sec } \\ s=18.84ft\/s \\ s\approx18.8ft\/s \end{gathered}\)That is its linear speed.
Phobos, one of the moons of Mars, orbits at a distance of 9378 km from the center of the red planet.
Part A What is the orbital period of Phobos?
Answers
The orbital period of Phobos is 7.66 hours.
What is orbital period?The orbital period also known as the revolution period is the amount of time it takes an astronomical object to complete one orbit around another. It usually refers to planets or asteroids orbiting the Sun, moons orbiting planets, exoplanets orbiting other stars, or binary stars in astronomy.
It will be calculated thus:
T^2 = (4π)^2( d^3) / ((G)(Mm))
where d is the distance in meters, 9.378 x 10^6 meters
(4π)^2 = 39.5
G = 6.67 x 10^-11 m^3 kg^-2 s^-2
Mm = the mass of Mars in kg which is 6.42 x 10^23 kg.
T^2 = 7.61 x 10^8 sec^2
Find the square root.
T = 2.76 x 10^4 sec
T = 7.66 hours
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No esporte coletivo, um dos principais fatores desenvolvidos é o desenvolvimento social. Qual desses não faz parte das virtudes ensinadas no esporte?
Companheirismo
Humildade
Ser justo (Fair Play)
Vencer independente do que precise ser feito
Answers
Answer:
fair palybtgshsisuehdh
You will need to know that Force (N) is equal to mass (kg) multiplied by acceleration (m/s2) for this problem. A fearless space explorer has discovered a new planet with a frictionless surface! He pushes a large crate with a mass of 220kg a distance of 5.3 km, as he does so, it accelerates at a rate of 2m/s2. How much work has our intrepid hero done?
Answers
Our intrepid hero has done 2332 kJ of work pushing the crate on the frictionless surface of the newly discovered planet.
The work done by the space traveler can be determined utilizing the recipe W = F x d, where W is work, F is power, and d is distance. To find the power, we can utilize the recipe F = m x a, where m is mass and an is speed increase. Connecting the given qualities, we get F = 220 kg x 2 m/s^2 = 440 N.
Presently we can compute the work done by increasing the power by the distance: W = 440 N x 5.3 km = 2332 kJ. Accordingly, our fearless legend has done 2332 kJ of work pushing the container on the frictionless surface of the newfound planet.
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what is the Gravitational strength of the planet Eris
Answers
0.82 m/s²
How?Though its gravity is weak compared to earth, Eris has the strongest gravity out of all the dwarf planets: 0.82 m/s².
How Is Eris Important?
Eris is the largest dwarf planet in the Solar System, and the ninth largest body orbiting our Sun. The discovery of Eris was so important because it was a celestial body larger than Pluto, which forced astronomers to consider, for the first time in history, what the definition of a planet truly is!
Hope this helps you!! :D
what are the three law of reflection?
Answers
Answer:
The three law of reflection are:-The incident ray, the reflected ray, and normal ray all lie in same plane.The angle of reflection is always equal to the angle of incidence.Incident ray and reflected ray are on different sides of the normal.Hope you like it.....To see how two traveling waves of the same frequency create a standing wave. Consider a traveling wave described by the formula:
y1(x,t)=Asin(kx−ωt).
This function might represent the lateral displacement of a string, a local electric field, the position of the surface of a body of water, or any of a number of other physical manifestations of waves.
Required:
Find ye(x) and yt(t). Keep in mind that yt(t) should be a trigonometric function of unit amplitude.
Answers
Answer:
y_e = 2A sin kx
y_t = cos wt
Explanation:
A standing wave is produced by the reflection of a traveling wave in an obstacle, let's write the initial traveling wave
y₁ = A sin (kx -wt)
let's write the reflected wave
y₂ = A sin (kx + wt)
we find the sum of these two waves
y = y₁ + y₂
y = A sin (kx -wt) + A sin (kx + wt)
let's develop the double angles
y = A [sin kx cos wt - cos kx sin wt + sin kx cos wt + cos kx sin wt]
y = A [2 sin kx cox wt]
we can write this resulting wave
y_e = 2A sin kx
y_t = cos wt
Your Friend Wants To Travel Abroad For University Education.Write a Letter Expressing Your Views about his or her intentions and advising him or her on wat to do.
Answers
Answer:
ALT TO FRIEND
HI FIREND
COPY BOB IN ALT ACC
CANT GET BAN
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────█░░█░░░░░█░░█──── this is Taco
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░░░▌░▄▄▄▐▌▀▀▀░░ This is Bob
▄░▐░░░▄▄░█░▀▀ ░░ they have made an alliance
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Explanation:
A geologist notices that a river is eroding its valley at a constant rate. Knowing the height of the valley walls, how could the geologist figure out when the river started carving the valley?
A.
Count growth rings of trees growing on the valley floor.
B.
Divide the height of the valley walls by the rate of erosion.
C.
Fill up the river valley with rocks, and time how long it takes the rocks to wash out.
D.
Sit and observe the river for a few hours until the valley walls double in height.
Answers
Answer:
B.
Divide the height of the valley walls by the rate of erosion.
Explanation:
There is a relationship between the rate of erosion and the hieght at which it is eroded according to Newton's law of motion. In the case of the scenario above, the best way to determine the time the river started carving the valley would be the division of the height of the valley walls by the rate of erosion.
HELP ME ASAPPPPPPPPPPP
A penny sinks to the bottom of a wishing well
What type of frictional force is that?
Answers
The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.
what evidence supports the information consolidation theory?
PLEASE HELP ME ITS DUE NEXT PERIOD
Answers
Explanation:
Memory loss in retrograde amnesia has long been held to be larger for recent periods than for remote periods, a pattern usually referred to as the Ribot gradient. One explanation for this gradient is consolidation of long-term memories. Several computational models of such a process have shown how consolidation can explain characteristics of amnesia, but they have not elucidated how consolidation must be envisaged. Here findings are reviewed that shed light on how consolidation may be implemented in the brain. Moreover, consolidation is contrasted with alternative theories of the Ribot gradient. Consolidation theory, multiple trace theory, and semantization can all handle some findings well but not others.
A 5kg objects is sliding across a floor at 10m/s. How much work is done by friction to bring it to a stop?
Answers
If A 5kg objects is sliding across a floor at 10m/s.then the work done by friction to bring the 5 kg object to a stop is -250 Joules.
To calculate the work done by friction to bring the object to a stop, we need to determine the change in kinetic energy.
Given:
Mass of the object, m = 5 kg
Initial velocity, u = 10 m/s
Final velocity, v = 0 m/s (object comes to a stop)
The work done by friction can be calculated using the equation:
Work = Change in Kinetic Energy
The change in kinetic energy (ΔKE) can be calculated as:
ΔKE = (1/2) * m * (v^2 - u^2)
Plugging in the values:
ΔKE = (1/2) * 5 kg * (0 m/s)^2 - (10 m/s)^2
= (1/2) * 5 kg * (0 - 100 m^2/s^2)
= (1/2) * 5 kg * (-100 m^2/s^2)
= -250 J
The negative sign indicates that the work done by friction is in the opposite direction of the displacement of the object.
Therefore, the work done by friction to bring the 5 kg object to a stop is -250 Joules.
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What causes coastal erosion
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La erosión costera es la pérdida o desplazamiento de tierra, o la remoción a largo plazo de sedimentos y rocas a lo largo de la costa debido a la acción de olas, corrientes, mareas, agua impulsada por el viento, hielo transportado por el agua u otros impactos de marejadas ciclónicas.
HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
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Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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I need to sketch force diagram
This problem is already solved
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The free body diagram of the given system will include a normal force of value 9 Newton perpendicular to the surface with friction force at 30° with 12 newton force and the weight of 15 Newton pointing downwards.
What is free body diagram?Free body diagram refers to the formation of a system showing all the possible forces that are being exerted on the body isolating it from the surrounding.
What is system and surrounding?System refers to the object of inspection i.e. the thing that is being noted down a system can be anything from an object to multiple objects and even surrounding whereas surrounding is everything else that is not a part of the system.
We have been already given all the required inputs that will help us to create a free body diagram including:
Friction force on the body being = 12 Newton
Weight of the body = 15 Newton
Normal acting on the body = 9 Newton
To create the free body diagram we simply isolate or from the surrounding and consider it to be a system then help of the vectors we will create the system consisting of the body and all the possible forces that acting on it.
We now draw the vectors for friction force weight of the body and normal acting on the body to get our required free body diagram.
Therefore, the free body diagram of the given system will include a normal force of value 9 Newton perpendicular to the surface with friction force at 30° with 12 newton force and the weight of 15 Newton pointing downwards.
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Why is people to come together and combine their efforts?
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Answer:
people who had a hard time to help other people because they feel that if they help
that the work of the person is much harder than his own work
Individuals who find it difficult to help others because they believe that if they do, the person's job will be much tougher than their own.
A group of people working together to achieve a shared purpose.
Collaboration, cooperation, and coordination are all words that come to mind when thinking of teaming.
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