A student measures the mass of a clean, dry flask and stopper is measured using a laboratory balance. The mass of the empty stoppered flask is 36.724 g. The flask is then filled with deionized water and the mass of the filled stoppered flask is determined to be 65.858 g. The mass of the filled stoppered flask equals the sum of the mass of the empty stoppered flask plus the mass of the water. what is the volume of the flask?

Explanation:

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The empirical formula of polyethylene can be determined by converting the given percentages of carbon (C) and hydrogen (H) into grams. To find the grams of each element, we assume a 100.0 g sample of polyethylene.

For carbon:

Mass of carbon = 86.0% × 100.0 g = 86.0 g

For hydrogen:

Mass of hydrogen = 14.0% × 100.0 g = 14.0 g

Therefore, in a 100.0 g sample of polyethylene, there are 86.0 grams of carbon and 14.0 grams of hydrogen.

The empirical formula of a compound represents the simplest whole-number ratio of atoms present in the compound. To determine the empirical formula, we need to find the ratio of carbon to hydrogen in terms of moles.

First, we convert the masses of carbon and hydrogen into moles using their respective molar masses. The molar mass of carbon is approximately 12.01 g/mol, and the molar mass of hydrogen is approximately 1.008 g/mol.

Number of moles of carbon = 86.0 g / 12.01 g/mol ≈ 7.162 mol

Number of moles of hydrogen = 14.0 g / 1.008 g/mol ≈ 13.89 mol

Next, we divide the number of moles of each element by the smallest number of moles to get a simplified ratio.

Carbon: Hydrogen ≈ 7.162 mol : 13.89 mol ≈ 1 : 1.939

Since we want to express the ratio in whole numbers, we multiply both sides by 2 to get a whole number ratio.

Carbon: Hydrogen ≈ 2 : 3.878

Rounding to the nearest whole number, we find that the empirical formula of polyethylene is CH₂.

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Answer:Cellular respiration is not the same as breathing, but they are closely related

Explanation: When you breathe in, you take in the oxygen your cells need for cellular respiration. When you breathe out, you get rid of carbon dioxide that your cells produce during cellular respiration.

The molality of a solution prepared by dissolving 56.1 grams of NaCl in 60.0 mL of water is 16mol/kg.

Molality is the concentration of a substance in solution, expressed as the number of moles of solute per kilogram of solvent.

This means that the molality can be calculated by dividing the number of moles of solute by mass in kilograms of solvent.

moles of NaCl = 56.1g ÷ 58.5g/mol = 0.96 moles

The mass of the solvent (water) can be calculated as follows:

Density = mass ÷ volume

1g/mL = mass ÷ 60mL

mass = 60g, which is equivalent to 0.06kg

Molality = 0.96mol ÷ 0.06kg = 16mol/kg

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Marks that might link a bullet to a specific weapon include striations, which are unique patterns and imperfections left on the bullet's surface as it passes through the barrel of a firearm. As for the fingerprints found, it depends on the context of the investigation. Fingerprints can be categorized into three main types: latent, patent, and plastic.

Marks that might link a bullet to a specific weapon include striations, which are unique patterns and imperfections left on the bullet's surface as it passes through the barrel of a firearm. These striations are caused by the unique characteristics of the rifling inside the barrel, such as the number of lands and grooves, their width, depth, and the direction of twist. Comparing the striations on a recovered bullet to test-fired bullets from a suspected weapon can help determine if they match, indicating a potential link.

As for the fingerprints found, it depends on the context of the investigation. Fingerprints can be categorized into three main types: latent, patent, and plastic. Latent fingerprints are invisible and require development techniques such as powder or chemical methods to make them visible. Patent fingerprints are visible prints left on a surface, such as blood or dirt. Plastic fingerprints are three-dimensional impressions left on soft surfaces like clay or wax.

Without specific information on the crime scene or the type of fingerprints found, it is not possible to determine which type the investigator has encountered.

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Answer:

Explanation: Liquid Chromatography  

I'm sorry if i'm wrong

Answer:

joib

Explanation:

When fossil fuels burn, several forms of energy are produced, including:

Heat energy: The primary form of energy released during fossil fuel combustion is heat. Fossil fuels contain chemical energy stored for millions of years, and when they burn, this energy is released in the form of heat. The heat energy can be harnessed for various purposes, such as heating buildings or generating steam to drive turbines.

Light energy: Burning fossil fuels can also produce light energy in the form of flames or glowing embers. This light energy is a byproduct of combustion.

Mechanical energy: Heat generated by burning fossil fuels can be converted into mechanical energy. This is typically achieved by using heat to produce steam, which drives a turbine connected to a generator. The rotating turbine converts the heat energy into mechanical energy, which is further transformed into electrical energy.

Electrical energy: Through the process described above, burning fossil fuels can ultimately generate electrical energy. The mechanical energy produced by the turbine is converted into electrical energy by the generator. Electrical energy can power various devices, appliances, industries, and infrastructure.

It's critical to note that while burning fossil fuels can produce useful forms of energy, it also results in the release of carbon dioxide and other greenhouse gases. This contributes to climate change and environmental concerns. As a result, there is a global shift towards cleaner and renewable energy sources to mitigate these negative impacts.

The mass of BrCl that is present in the reaction mixture at equilibrium is 0.519 grams

Generally, To calculate the mass of BrCl present at equilibrium, we need to use the equilibrium constant expression (Kp) for the reaction:

Kp = [BrCl]^2 / [Br2] [Cl2]

where [BrCl], [Br2], and [Cl2] are the concentrations of the respective gases at equilibrium.

Since we know the initial amounts of Br2 and Cl2, and the volume of the flask, we can calculate the initial concentrations of each gas.

[Br2]_initial = 0.902 kg / (201.0 L * 0.08206 Latm/molK * 150 K)

= 0.0014 mol/L [Cl2]_initial

= 1.066 kg / (201.0 L * 0.08206 Latm/molK * 150 K)

= 0.0017 mol/L

We are also given the value of Kp, so we can substitute the initial concentrations into the Kp expression and solve for [BrCl].

Kp = [BrCl]^2 / 0.0014 mol/L * 0.0017 mol/L

= (1.1×10^-4)

[BrCl] = √(Kp * [Br2]_initial * [Cl2]_initial)

=√(1.1×10^-4 * 0.0014 mol/L * 0.0017 mol/L)

= 1.61802349*10^{-5} mol/L

To convert molarity to mass, we need to multiply the molarity by the molar mass of BrCl.

The molar mass of BrCl is

(2 * 79.904 g/mol) = 159.808 g/mol.

mass of BrCl = [BrCl] * V * M

=1.61802349*10^{-5}mol/L * 201.0 L * 159.808 g/mol

= 0.519 grams

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Answer:  The nuclear equation for the beta decay is

⁹²₃₈St-------->⁹²₃₉Y +     ⁰₋₁e

Explanation:

Beta decay(beta-minus and beta-plus.) occurs due to the fact that some atoms are unstable and to become stable must undergo a decay.

The beta decay that occurs in Strontium  is a beta-minus decay,where it changes to another element since its atom gains a proton

A beta decay (beta minus) occurs when an atom emits beta particle (   ⁰₋₁e) Here in Strontium  undergoing a beta(minus) decay, the mass number remains the same but a proton was gained. Hence the new  isotope is  Yttrium ⁹²₃₉Y .

⁹²₃₈St-------->⁹²₃₉Y +     ⁰₋₁e

Answer:

A

Explanation:

it increase the rate of reaction when necessary

The chemical change that is  responsible for producing the heat that maintains the temperature of your body is metabolism.

Chemical changes are defined as changes which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical change.

There are several characteristics of chemical changes like change in color, change in state , change in odor and change in composition . During chemical change there is also formation of precipitate an insoluble mass of substance or even evolution of gases.

There are three types of chemical changes:

1) inorganic changes

2)organic changes

3) biochemical changes

During chemical changes atoms are rearranged and changes are accompanied by an energy change as new substances are formed.

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Step by step solutions:

1 mole of A contains 6.022x10^23 molecules

∴ x moles A contains 5.99x10^23 molecules

Then, moles of A = (5.99x10^23 /6.022x10^23 )molecules

=5.99/6.02

=0.995moles of A Sample

Given that -

Mass = 93.5g

Mol Mass Ammonium carbonate (NH4)2CO3= 96,09 g/mol

∴ moles B = mass /molecular mass

=93.5g /96.09g/mol

=0.973 moles of sample B

Conclusion: Sample A has 0.995 moles, this is bigger that the moles of Sample B that has 0.973 moles.

The Method of Mixtures Electrical Method is a method used to determine the electrical conductivity of a material.

The Electrical Method is a geophysical prospecting technique that uses electrical resistivity to map subsurface features, such as geological structures, fractures, and mineral deposits.

It involves measuring the amount of current that passes through a mixture of two materials under the application of a known voltage. The electrical conductivity of each material can then be determined by calculating the ratio of the current to the applied voltage. The electrical conductivity obtained from the Method of Mixtures Electrical Method can be used to characterize materials such as semiconductors and insulators.

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Answer:

1.30

Explanation:

The neutralization reaction involved in the titration is:

HClO₄(aq) + KOH(aq) → KClO₄(aq) + H₂O(l)

According to the chemical equation,

1 mol of HClO₄ reacts with 1 mol of KOH (1 equivalent of acid with 1 equivalent of base). The moles are calculated from the product of the molar concentration (M) and the volume in liters.

We have the following moles of acid (HClO₄):

40.0 mL x 1 L/1000 mL = 0.04 L 0.200 mol/L x 0.04 L = 8 x 10⁻³ moles HClO₄

Since HClO₄ is a strong acid (completely dissociated into H⁺ and ClO₄⁻ ions), the moles of HClO₄ are equal to the moles of H⁺.

Then, we can calculate the initial pH:[H⁺] = 0.200 M → pH = -log [H⁺] = -log (0.200) = 0.70

Now, we calculate the pH after the addition of KOH. Since KOH is a strong base, the concentration of KOH is equal to the concentration of OH⁻ ions.

a) 0.0 mLNo KOH is added, so the pH is the initial pH:

0.70

b) 80.0 mL KOH80.0 mL x 1 L/1000 mL = 0.08 L0.100 mol/L x 0.08 L = 8 x 10⁻³ moles KOH = 8 x 10⁻³ moles OH⁻

After neutralization we have: 8 x 10⁻³ moles H⁺ - 8 x 10⁻³ moles OH⁻ = 0The neutralization reaction is complete and there is no remaining H⁺ from the acid.

The concentration of H⁺ is equal to the concentration of H⁺ of water:

[H⁺] = 1 x 10⁻⁷ M → pH = -log [H⁺] = -log (1 x 10⁻⁷) = 7.0

c) 10.0 mL KOH10.0 mL x 1 L/1000 mL = 0.01 L0.100 mol/L x 0.01 L = 1 x 10⁻³ moles KOH = 1 x 10⁻³ moles OH⁻

After neutralization we have: 8 x 10⁻³ moles H⁺ - 1 x 10⁻³ moles OH⁻ = 7 x 10⁻³ moles H⁺

The total volume is:

V = 40.0 mL + 10.0 mL = 50 mL = 0.05 L[H⁺] = 7 x 10⁻³ moles/0.05 L = 0.14  → pH = -log [H⁺] = -log (0.14) = 0.85

d) 100.0 mL KOH100.0 mL x 1 L/1000 mL = 0.1 L0.100 mol/L x 0.1 L = 0.01 moles KOH = 1 x 10⁻² moles OH⁻

After neutralization we have:

1 x 10⁻² moles OH⁻ - 8 x 10⁻³ moles H⁺ = 2 x 10⁻³ moles OH⁻

The total volume is:

V = 40.0 mL + 100.0 mL = 140 mL = 0.14 L[OH⁻] = 2 x 10⁻³ moles/0.14 L = 0.014  → pOH = -log [OH⁻] = -log (0.014) = 1.84pH + pOH = 14 → pH = 14 - pOH = 14 - 1.84 = 12.15

e) 40.0 mL KOH40.0 mL x 1 L/1000 mL = 0.04 L0.100 mol/L x 0.04 L = 4 x 10⁻³ moles KOH = 4 x 10⁻³ moles OH⁻

After neutralization we have: 8 x 10⁻³ moles H⁺ - 4 x 10⁻³ moles OH⁻ = 4 x 10⁻³ moles H⁺

The total volume is:

V = 40.0 mL + 40.0 mL = 80.0 mL = 0.08 L[OH⁻] = 4 x 10⁻³ moles/0.08 L = 0.05 M  → pH = -log [H⁺] = -log (0.05)

= 1.30

CuI2 is not a known compound. Copper compounds typically have different oxidation states for copper, resulting in various compound names.

Copper(II) oxide (CuO): It is a black solid compound where copper is in the +2 oxidation state. It is commonly used as a pigment and in catalytic reactions.

Copper(II) sulfate (CuSO4): It is a blue crystalline compound in which copper is in the +2 oxidation state. It is used in various applications such as agriculture, electroplating, and as a laboratory reagent.

Copper(I) oxide (Cu2O): It is a red crystalline compound in which copper is in the +1 oxidation state. It is used as a pigment, in solar cells, and as a catalyst.

Copper(II) chloride (CuCl2): It is a greenish-brown solid compound in which copper is in the +2 oxidation state. It is utilized in various chemical processes, including etching and catalyst synthesis.

Copper(II) nitrate (Cu(NO3)2): It is a blue crystalline compound where copper is in the +2 oxidation state. It is commonly used in the production of catalysts, as a coloring agent, and in electroplating.

These are just a few examples of copper compounds with different oxidation states and properties. It's important to note that the compound CuI2 mentioned in the question, if it exists, would be an exception to the typical nomenclature for copper compounds.

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In order to answer this question we will need the properly balanced reaction, which the question already gave us:

C5H12 + 8 O2 -> 5 CO2 + 6 H2O

Then we need to focus on the compounds that the question is asking, which are C5H12 and 5 CO2, from the reaction we can also identify the molar ratio between both molecules, 1:5, that means that for every mole of C5H12, we will end up with 5 moles of CO2

Now let's find out how many moles of C5H12 are in 25.5 grams of it, we will use its molar mass to find the answer, molar mass is 72.15 g/mol

72.15 g = 1 mol

25.5 g = x moles

x = 0.35 moles of C5H12

Now we have 0.35 moles of C5H12, we know that molar ratio is 1:5, now let's see how many moles of CO2 we will have

1 C5H12 = 5 CO2

0.35 C5H12 = x CO2

x = 1.75 moles of CO2

And now we will do a similar step using CO2 molar mass in order to find the final mass, molar mass for CO2 is 44.01 g/mol

44.01 g = 1 mol

x grams = 1.75 moles

x = 77.02 grams of CO2

Answer:

Part 1)  85.3 grams NaCl

Part 2)  8.79 x 10²³ formula units NaCl

Explanation:

(Part 1)

To find the mass of NaCl, you need to multiply the given value (1.46 moles) by the molar mass of NaCl. This measurement is the atomic masses of the elements times each of their quantities combined. In this case, there is only one mole of each element in the molecule. Moles should be located in the denominator of the conversion to allow for the cancellation of units. The final answer should have 3 sig figs to reflect the given value.

Molar Mass (NaCl): 22.99 g/mol + 35.45 g/mol
Molar Mass (NaCl): 58.44 g/mol

1.46 moles NaCl            58.44 g
---------------------------  x  ----------------  =  85.3 grams NaCl
                                        1 mole

(Part 2)

I do not know which other question the second part is referring to, so I will just use the moles given in the first part. To find the formula units, you need to multiply the given value (1.46 moles NaCl) by Avogadro's Number. This conversion represents the number of formula units found in 1 mole of the sample. The moles should be in the denominator of the conversion to allow for the cancellation of units.

Avogadro's Number:

1 mole = 6.022 x 10²³ formula units

1.46 moles NaCl         6.022 x 10²³ units
------------------------  x  -----------------------------  =  8.79 x 10²³ formula units NaCl
                                          1 mole

The volume of the gold plates in cm₃ is 2.513274 cm₃

Volume is the space occupied by a three-dimensional object“”

Volume = {mass} {density}

Given that the thickness or height of medallion, h = 2 mm = 0.2 cm

Diameter of the medallion, d = 4 cm

Radius of medallion, r = d/2 = 2 cm⁻³

The thickness of the gold plating, x = 1 μm = 10⁻⁴ cm

The density of gold = 19.3 g cm

Now we know that the shape of a medallion is cylindrical.

Hence, the volume of the medallion before platting,

Vbefore = π.r2.h = π.(2)2.0.2 = 2.513274 cm₃

Therefore, the volume of the gold-plated is 2.513274 cm₃.

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At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Hi just wanted to say thank you for answering my question and I wanted to help so I believe the answer is A.

Option (d) is correct. Nitrates used in crop fertilizers does not contribute to ozone depletion.

The Ozone depletion can be defined as the gradual thinning of ozone layer of the earth in the upper atmosphere caused by the release of chemical compounds containing gaseous chlorine or bromine from industry and other human activities. Ozone layer depletion is a major environmental problem because it increases the amount of ultraviolet  radiation that reaches the surface of the earth which increases the rate of skin cancer, eye cataracts and immune system damage. The Ozone depleting substances are chlorofluorocarbons (CFCs), halon, carbon tetrachloride (CCl4), methyl chloroform (CH3CCl3), hydrochlorofluorocarbons (HCFCs), methyl bromide (CH3Br), bromochloromethane (CH2BrCl).

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Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

Explanation:

A pure substance is a form of matter that has a constant composition and properties that are constant throughout the sample. Mixtures are physical combinations of two or more elements and/or compounds

Explanation:

Chemistry

Matter and change

Extensive and Intensive Properties

----

Intensive properties: do not depend on the amount of substance.

Extensive properties: depend on the amount of substance.

----

According to this task, reactivity is intensive and a chemical property.

Answer: intensive

3 MnO\(_4\)⁻ + 2N\(_2\)O\(_3\)  + 2H\(_2\)O → 3Mn²⁺ + 2 NO\(_3\)⁻ + 6 OH⁻ is the balanced redox reaction in the basic condition.

Any chemical process in which a participating chemical species' oxidation number changes is known as an oxidation-reduction reaction, often known as a redox reaction. The phrase refers to a broad range of processes. Numerous oxidation-reduction processes are as frequent and well-known as fire, metal corrosion and disintegration, fruit browning, respiration, and photosynthesis—basic life processes.

3 MnO\(_4\)⁻ + 2  N\(_2\)O\(_3\) + 6 H⁺ + 6 OH⁻ → 3Mn²⁺ + 2 NO\(_3\)⁻  + 4 H\(_2\)O + 6 OH⁻

3 MnO\(_4\)⁻+ 2 N\(_2\)O\(_3\) + 6 H\(_2\)O → 3 Mn²⁺ + 2 NO\(_3\)⁻  + 4 H2O + 6OH⁻

3 MnO\(_4\)⁻ + 2N\(_2\)O\(_3\)  + 2H\(_2\)O → 3Mn²⁺ + 2 NO\(_3\)⁻ + 6 OH⁻

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Answer:

the centromere, the arm and the telomere

Explanation:

Answer:

0.16 atm

Explanation:

Let's look at the formula PV=nRT. First of all, T should be in kelvin, so let's add 273. Now solve for P so we get P = nRT/V.

Now let's plug these in...

P = (0.034 mol)(0.08206 L atm mol^-1 K^-1)(298 K)/5.1 L

After solving and rounding to sig figs we get 0.16 atm