A student leaving school walks 2.5 km North and then walks 1.0 km South what is the students displacement

Answer:

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2).

The distance that the vehicles will slide after the collision is 15 meters.

To find the distance that the vehicles will slide after the collision, we need to use the equation of motion for uniformly accelerated motion, which is given by:

S = ut + 1/2at²

where S is the distance traveled, u is the initial velocity, a is the acceleration, and t is the time taken. Here, the initial velocity of both vehicles is zero, and the acceleration is given as 5 m/s². The time taken for both vehicles to come to a stop is given as 3 seconds.So, for each vehicle:

S = 0 + 1/2 × 5 × 3²

= 22.5 meters

The total distance traveled by both vehicles before coming to a stop is:

\(S_{total}\)= 22.5 + 22.5= 45 meters

However, the distance between the vehicles before the collision is given as 30 meters. Therefore, the distance that the vehicles will slide after the collision is:

\(S_{slide}\) = 45 - 30= 15 meters.

Therefore, the distance that the vehicles will slide after the collision is 15 meters.

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In order to find the time it takes, first let's convert the distance from miles per hour to feet per second: calculate the acceleration using Torricelli's equation

Then, let's :

Now, we calculate the time with the formula below:

Therefore the time required is 1.7 seconds.

The current is 3.33A, the resistance is 36.03 Ohm, and the peak voltage is 169.68V.

Given information:

The power rating of the resistive element (P) = 400 W

Voltage supplied by the outlet (V) = 120 VAC (RMS)

a) To find the current flowing through the element, the formula:

Power (P) = Voltage (V) × Current (I)

Current (I) = Power (P) / Voltage (V)

Substituting the given values:

Current (I) = 400 W / 120 VAC

= 3.33 A

b) To find the resistance of the element, Ohm's Law can be used :

Resistance (R) = Voltage (V) / Current (I)

Resistance (R) = 120 VAC / 3.33A

= 36.03 Ohm

c) To find the peak voltage, it is required to convert the RMS voltage to peak voltage. For an AC voltage, the relationship between RMS voltage (\(V_{rms\)) and peak voltage (\(V_{peak\)) is given by:

\(V_{peak} = V_{rms} \times \sqrt2\)

Substituting the given RMS voltage:

Peak voltage  = \(120 \times \sqrt2\)

= 169.68 V

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2​​=2×9.8(48.6)2​=121m​The maximum displacement above pad is given by '

ymax=y1+y2=525+121=646  m The velocity just before crashing is given by vA22=vC2+2gymax  ⇒(3) By substitution in (2) get that vA2=2×9.8×646≈113  m/s vA2​​=2×9.8×646 ≈113m/s​ the maximum height this rocket will reach above the launc is ymax=646M.

Whether an object is moving or not, gravity still exerts a pull on it.In real life, an object's gravitational pull does not vary considerably when it ascends above the Earth.

An object is considered to be in terminal decline when gravity is the only force affecting it.9.8 m/s is the acceleration caused by gravity.

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The average velocity for the entire trip is 22.76 km/hr.

To calculate the average velocity for Billie's entire trip, we need to determine the total displacement and the total time taken for the trip. We'll break down the process into steps:

1. Determine the displacement for each segment of the trip:

- Segment 1: 3.2 km due east

- Segment 2: 3.2 km at 15.0 degrees eastward of due north

- Segment 3: 3.2 km due east

2. Calculate the x and y components of the displacement for Segment 2:

- x-component: 3.2 km * cos(15.0) = 3.09 km

- y-component: 3.2 km * sin(15.0) = 0.83 km

3. Calculate the total displacement in the x and y directions:

- Total x-displacement: 3.2 km (Segment 1) + 3.09 km (Segment 2) + 3.2 km (Segment 3) = 9.49 km

- Total y-displacement: 0.83 km (Segment 2)

4. Calculate the total displacement using the Pythagorean theorem:

\(Total displacement = \sqrt{((9.49 km)^2 + (0.83 km)^2)\)

                              = 9.56 km

5. Calculate the total time taken for the trip:

- Total time = 0.1 hr (Segment 1) + 0.21 hr (Segment 2) + 0.1 hr (Segment 3)    

                   = 0.42 hr

6. Calculate the average velocity by dividing the total displacement by the total time:

- Average velocity = Total displacement / Total time

                              = 9.56 km / 0.42 hr

                               = 22.76 km/hr

So, the average velocity for the entire trip is 22.76 km/hr.

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Answer:

Explanation:

Given:

R = 18 Ohm

U = 9.0 V

__________

I - ?

Ohm's law:

I = U / R

I = 9.0 / 18 = 0.5 A

Answer:

Hey there!

Kelvin is correct. Farenheit and Celsius are scales derived from the Kelvin scale. For example, K=C+273.15 is the conversion between Kelvin and Celsius.

Let me know if this helps :)

Gravitational force between two masses m, and m, is represented as F = Gm₂ m₂ / r^2 where r = xi+yj + zkG, m, m₂ are nonzero constants and let's assume that I = 0

a) Calculation:For F = Gm₂ m₂ / r^2.

Using r = xi+yj + zk and let r^2 = x^2 + y^2 + z^2∴ F = Gm₂ m₂ / (x^2 + y^2 + z^2), Where G, m, m₂ are nonzero constants. Divergence of F = ∇ · F= 1/r^2(d/dx(r^2Fx) + d/dy(r^2Fy) + d/dz(r^2Fz))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)^(3/2)) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)^(3/2)) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)^(3/2)))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2))= 1/r^2(Gm₂ m₂ [2x(x^2+y^2+z^2)-3x^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2y(x^2+y^2+z^2)-3y^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2z(x^2+y^2+z^2)-3z^2]/(x^2+y^2+z^2)^(5/2))= 1/r^2(Gm₂ m₂ [(2x^2+2y^2+2z^2-3x^2)/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3y^2]/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3z^2]/(x^2+y^2+z^2)^(3/2)])= 1/r^2(Gm₂ m₂ [x^2+y^2+z^2]/(x^2+y^2+z^2)^(3/2))= 0.

Curl of F = ∇ × F= i(d/dy(Fz) - d/dz(Fy)) - j(d/dx(Fz) - d/dz(Fx)) + k(d/dx(Fy) - d/dy(Fx))= i(d/dy(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ y/(x^2+y^2+z^2))) - j(d/dx(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ x/(x^2+y^2+z^2))) + k(d/dx(Gm₂ m₂ y/(x^2+y^2+z^2)) - d/dy(Gm₂ m₂ x/(x^2+y^2+z^2)))= i(Gm₂ m₂ [-2xz]/(x^2+y^2+z^2)^(5/2)) - j(Gm₂ m₂ [-2yz]/(x^2+y^2+z^2)^(5/2)) + k(Gm₂ m₂ [(x^2+y^2-2z^2)]/(x^2+y^2+z^2)^(5/2))

b) Calculation:The line integral of F along a curve C can be evaluated by the following formula∫C F.dr = ∫∫ ( ∇ x F) ds, Where r is the position vector of the curve, s is the scalar parameter representing the curve, and the integral is evaluated from the initial point to the final point.

Using the curl of F obtained in part a) and for the surface with ∂S as C∫C F.dr = ∫∫ ( ∇ x F) ds= ∫∫ curl(F) ds= ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds...[1]

Let's consider the surface S as a plane perpendicular to the z-axis of the form ax+by+c=0 and the curve C as the intersection of the plane and the cylinder x^2 + y^2 = a^2.

Let's choose the unit normal to the surface S as k (along the z-axis).

The curl of F is a vector field perpendicular to the plane and along the direction of k.

Thus the integral can be written as∫C F.dr = ∫∫ ( ∇ x F) . k ds= ∫∫ (x^2+y^2-2z^2) ds...[2]

Now let's evaluate the integral over the given plane ax+by+c=0. We can write x = t, y = (c-at)/b and z = 0, where t is the scalar parameter along the line of intersection of the plane and the cylinder (x^2 + y^2 = a^2).

Since the curve C is on the cylinder of radius a, we have x^2+y^2 = a^2 ⇒ t^2+(c-at)^2/b^2 = a^2On solving for t, we have t = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2].

Substituting t in x and y, we get the curve C in the x-y plane as a function of the scalar parameter s asx = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2]y = (c-at)/b= (c-(bc±ab √(a^2-b^2-c^2))/[a^2+b^2])/b.

Now we can evaluate the integral over the curve C, which is along the intersection of the plane and the cylinder.

Integral over C (x^2+y^2-2z^2) ds= ∫t₁^t₂ [(t^2 + [(c-at)^2]/b^2 - 2(0)^2)^(1/2)] dt= ∫t₁^t₂ [(a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2]^(1/2) dt.

Now we can choose the value of t₁ and t₂ such that the square root in the integrand is minimized (so that the integral is path-independent).

This can be done by choosing the value of t that gives the minimum value of (a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2 over the range of t from t₁ to t₂.

On differentiation with respect to t and equating to 0, we get the value of t = bc/(a^2+b^2).

Substituting this value of t in the integrand, we get the minimum value of the square root in the integrand to be |c| √(a^2+b^2)/|b|.

Thus the integral over C is given by∫C F.dr = ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds= ∫∫ (x^2+y^2-2z^2) ds= ∫t₁^t₂ |c| √(a^2+b^2)/|b| dt= |c| √(a^2+b^2)/|b| (t₂-t₁).

Now we can see that the integral is path-independent as it depends only on the end points t₁ and t₂ and not on the path taken to reach them.

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Answer:

yes it will

Explanation:

As the net torque on the see-saw  is not equal to zero, the see-saw in the given diagram will move.

The force that can cause an object to rotate along an axis is measured as torque. In linear kinematics, force is what drives an object's acceleration. Similar to this, an angular acceleration is brought on by torque.

As a result, torque can be thought of as the rotational counterpart to force.  Torque is referred to using a variety of terms, including moment and moment of force. The moment arm or lever arm is the measurement of the separation between the point of application of force and the axis of rotation.

The net torque on the see-saw = 3 N × 1.20m - 8 N × 0.50 m

= - 0.4 N-m.

As the net torque on the see-saw  is not equal to zero,  the see-saw move will move.

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Explanation:

F = 40 N

d = 3 m

Work

W = Fd

where: W - work, J

F - force, N

d - distance, m

W = Fd

W = (40 N)(3 m)

W = 120 Nm or 120 J

The ball is on the 50-yard line. The ball travels west 5 yards. The distance ball traveled was 60 yards.

Distance can be defined as the length of any path between any two locations. Displacement is the direct distance between any two points when calculated via the shortest path between them. When computing distance, the direction is disregarded. The displacement computation takes the direction into consideration.

The 5 yard gain would bring the ball to the 45 yard line (ball was tackled  at the 50 yard line, so 50 - 5 = 45), but the 15 yards lost due to the tackle and push back would bring ball to the 60 yard line (45 + 15 = 60).

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The amount of heat needed to change the temperature of the hydrogen gas from 50 K to 100 K is 214.5 J.

To calculate the amount of heat needed to change the temperature of the hydrogen gas, we can use the equation:

Q = m * c * ΔT

where:

Q is the heat transferred,

m is the mass of the gas,

c is the specific heat capacity of the gas, and

ΔT is the change in temperature.

Mass of hydrogen gas (m) = 0.30 g

Change in temperature (ΔT) = 100 K - 50 K = 50 K

The specific heat capacity of hydrogen gas is typically around 14.3 J/g·K.

Substituting the given values into the formula, we can calculate the amount of heat (Q):

Q = (0.30 g) * (14.3 J/g·K) * (50 K)

Q = 214.5 J

Therefore, the amount of heat needed to change the temperature of the hydrogen gas from 50 K to 100 K is 214.5 J (joules).

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Answer:

Kinematics

given,

time (t)=100 s, distance (s)=1 km=1000 m

V

b

=10m/s (relative speed r.p to bus)

Velocity (v)=

time

distance

=

100

1000

V

s

= velocity of scooter

V

b

→ Velocity of bus

V=V

s

−V

b

→As we know

10=V

s

−10

20=V

s

V

s

=20 m/s

Velocity with which scooterist

should chase the bus →20 m/s

Explanation:

I Hope you Guys Understood

please mark as Brainliest....

The given wavelength is between 400 nm to 700 nm, so the maximum frequency of visible light is 7.5 x 10¹⁴ Hz.

The length between corresponding spots of two successive waves is known as the wavelength. Two points or particles that are in the same phase and have finished the same portions of their periodic motion are referred to as "corresponding points."

In transverse waves, the length is frequently measured from peak to peak or from trough to trough, and in longitudinal waves, from compression to compression.

Now, let's find out the frequency,

f = c/v

Where c is the speed of light and f is the frequency of the wave.

f = (3 x 10⁸)/(400 x 10⁻⁹)

f  = 7.5 x 10¹⁴

Therefore, the highest frequency is 7.5 x 10¹⁴ Hz.

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I suggest that the students move forward with option A.

Test funnels of the same size and material with varying sized openings. This will allow them to determine the optimal size for the opening that will help direct the marble to the launch pad. Once they have determined the optimal size, they can move forward with constructing the funnel with that size opening.

Answer:

if f = 20n then force must be impatient and it must solve for nutrulization so to do that formula = 1cm = 20n is really prehalf into the stuff to calculate magnitude we will determine cosplay which will rather not do something instead its like finn balor winning nxt.

Explanation:

The potential energy (Ep) is 490 J and the velocity is 9.9  m/s.

To calculate the potential energy (Ep) of an object with mass M at a height h above a reference point, you can use the formula:

Ep = M * g * h

where,

g =the acceleration due to gravity (approximately 9.8 m/s² on the surface of the Earth).

M = mass

h = height

For this case:

Ep = 10 kg * 9.8 m/s² * 5 m

Ep = 490 J

To calculate the velocity (v) of an object in free fall, you can use the formula:

v = \(\sqrt{2gh}\)

So in this case:

v = \(\sqrt{2 * 9.8 m/s^{2} * 5 m }\)

v = 9.899 m/s

v ≈ 9.9 m/s

Note: These formulas assume that the object is in free fall and that there is no air resistance or other forces acting on the object.

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We can presume that an ambulance with its siren activated is rushing to get somewhere and, depending on the driving circumstances, is likely travelling between 30 and 150 km/h. The vehicle's speed can be determined using the Doppler effect equation. Let va represent the ambulance's maximum speed. The frequency, f'=(vvv a)f=560Hz, is audible as it gets closer.

Because the source is travelling in the direction of the observer, a negative sign appears. The ambulance is described as moving away by the opposite sign with source velocity magnitude. The Doppler shifted frequency as it recedes is f')=(vv+v0)f=480Hz.

The speed of the source can be calculated as va=v(f'f')f'+f'=(343ms)(560Hz480Hz)560Hz+480Hz=26.4ms by solving the second of these equations for f and substituting into the other.

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Answer:

b. between 2 s and 4 s

Explanation:

2-4 was both 3m/s

The correct answer is: object A must have a higher average internal kinetic energy than object B to have a higher absolute temperature.

To understand which of the given options would make object A have a higher absolute temperature than object B, we first need to understand what temperature is and how it is related to the properties of an object.

Temperature is a measure of the average internal kinetic energy of the particles in an object. The greater the average internal kinetic energy, the higher the temperature. So, to have a higher temperature than object B, object A must have a higher average internal kinetic energy.

Now let's consider the given options:

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Answer:

5/8 times that on the surface of the earth or 2.41 × 10^23 kg

Answer:

if the object can sink it will sink but if the object can float it will float

The magnetic field inside the solenoid is 0.055 T (tesla).

The magnetic field inside a solenoid is given by the formula:

B = μ₀ * n * I

Where B is the magnetic field, μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A), n is the number of turns per unit length (in this case, per meter), and I is the current flowing through the solenoid.

Plugging in the values given in the problem, we get:

B = (4π × 10⁻⁷ T·m/A) * (2100 turns/m) * (5.2 A)

B = 0.055 T

A solenoid is a coil of wire that is usually wound in the shape of a cylinder or helix. When an electric current flows through the wire, a magnetic field is created inside the solenoid.

The strength of the magnetic field depends on several factors, including the number of turns of wire in the coil (n), the current flowing through the wire (I), and the physical properties of the materials inside and around the solenoid.

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The force exerted on the car by the raising mechanism is 7,100 N.

The given parameters:

The force exerted on the car by the raising mechanism is calculated as follows;

\(W = Fd\\\\F = \frac{W}{d} \\\\F = \frac{2.13 \times 10^6}{300} \\\\F = 7,100 \ N\)

Thus, the force exerted on the car by the raising mechanism is 7,100 N.

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Answer: The Sun's core generates energy through nuclear fusion, specifically the fusion of hydrogen nuclei (protons) into helium nuclei. This process releases a tremendous amount of energy in the form of light and heat, which is what makes the Sun shine.

The current estimate for the age of the Sun is about 4.6 billion years, and it is currently in the middle of its main sequence phase, where it is burning hydrogen into helium in its core. It is estimated that the Sun has been in this phase for about 4.6 billion years, and it will continue to burn hydrogen in its core for another approximately 5 billion years, based on our current understanding of stellar evolution.

So, at the present rates of energy generation in the Sun's core, it is estimated that the Sun will continue to generate energy for another 5 billion years. However, it is worth noting that as the Sun ages, it will gradually evolve and change, eventually entering a phase of expanding into a red giant, and ultimately shedding its outer layers to become a white dwarf. The exact timeline and details of these changes are still a subject of ongoing scientific research and investigation.

Answer: There is nothing here

Explanation: Could you please add a picture or something

The given nuclear reaction is: 43K(1³=)43Ca(1"=2/2) + e + v  This nuclear reaction is a beta decay reaction. The atomic number of the daughter nucleus increases by one. A neutrino is produced in the process as well.

Beta decay is a radioactive decay process in which the beta particle is emitted from the nucleus. The nucleus emits a beta particle and a neutrino (antielectron) during beta decay.

The atomic number of the daughter nucleus is increased by one in this process, while the mass number remains constant. In this reaction, the parent nucleus, 43K, decays to form the daughter nucleus, 43Ca.The atomic number of the daughter nucleus is increased by one in this process, while the mass number remains constant.

The allowed values of Al are 0 and 1. In beta decay, a neutron in the nucleus is converted into a proton, and the beta particle is emitted from the nucleus.

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However, it is widely accepted that an alternating current (AC) of around 100 milliamperes (mA) flowing through the heart for a duration of a few seconds can lead to ventricular fibrillation, which is a potentially fatal arrhythmia. Direct current (DC) generally requires higher currents to cause similar effects.

The minimum magnitude of current passing through the human body that may cause death as a result of ventricular fibrillation can vary depending on several factors, including the duration of the current flow, the path the current takes through the body, and individual variations in susceptibility to electric shock.

However, it is widely accepted that an alternating current (AC) of around 100 milliamperes (mA) flowing through the heart for a duration of a few seconds can lead to ventricular fibrillation, which is a potentially fatal arrhythmia. Direct current (DC) generally requires higher currents to cause similar effects.

It's important to note that even lower currents can cause other serious physiological effects or indirect injuries. The effects of electric shock on the human body can be influenced by variables such as the frequency of the current, the contact area, the moisture level of the skin, and the path the current takes through the body.

It is crucial to prioritize electrical safety, implement proper insulation and grounding measures, and seek immediate medical attention in the event of an electric shock or suspected injury.

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