Answer:
The metal is Tin (Sn)
Explanation:
The following data were obtained from the question:
Mass of metal = 32.56 g
Volume of water = 14.78 mL
Volume of water + metal = 20.44 mL
Next, we shall determine the volume of the metal. This is illustrated below:
Volume of water = 14.78 mL
Volume of water + metal = 20.44 mL
Volume of metal =..?
Volume of metal = (Volume of water + metal) – (Volume of water )
Volume of metal = 20.44 – 14.78
Volume of metal = 5.66mL
Next, we shall determine the density of the metal.
Density of a substance is defined as the mass of the substance per unit volume of the substance. Mathematically, the density of a substance is expressed as:
Density = Mass / volume
With the above formula, we can obtain the density of the metal as follow:
Mass of metal = 32.56 g
Volume of metal = 5.66mL
Density =.?
Density = Mass /volume
Density = 32.56g/5.66mL
Density of the metal = 5.75g/mL
Comparing the density of the metal with standard density of elements, the metal is Tin (Sn)
Please help!!
How many O2 molecules occupy a 1.0 L flask at 65°C and
103.7 kPa?
Select one:
O a. 28 molecules
O b. 2.2 x 1022 molecules
O c.
1.1 x 1023 molecules
O d.
1.6 x 1025 molecules
e. 1.7 x 1025 molecules
Answer:
B, 2.22×10^22 molecules
Explanation:
Given PV=nRT, n=PV/RT
n=103.7×1.0/8.314×(65+273.15)
= 0.0368858... moles
Given n= number of particles/avogadros number
number of particles=n×avogadros number
number of particles = 0.03688...×6.02x10^23
= 2.22×10^22 molecules
Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine ΔHrxn for
C(diamond) → C(graphite)
with equations from the following list:
(1) C(diamond) + O2(g) → CO2(g) ΔH = −395.4 kJ
(2) 2 CO2(g) → 2 CO(g) + O2(g) ΔH = 566.0 kJ
(3) C(graphite) + O2(g) → CO2(g) ΔH = −393.5 kJ
(4) 2 CO(g) → C(graphite) + CO2(g) ΔH = −172.5 kJ
The enthalpy change of the reaction C(diamond) → C(graphite) is -2.9 kJ.
The given information is ΔHrxn for the reaction C(diamond) → C(graphite) can be calculated with the given equations:Equations: C(diamond) + O2(g) → CO2(g) ΔH = −395.4 kJ 2 CO2(g) → 2 CO(g) + O2(g) ΔH = 566.0 kJ C(graphite) + O2(g) → CO2(g) ΔH = −393.5 kJ 2 CO(g) → C(graphite) + CO2(g) ΔH = −172.5 kJThe required reaction can be obtained by adding the equations (1) and (4), as follows:C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)Addition of the two equations (1) and (4) results in a reaction whose products are C(graphite) and CO2.
To get the final equation that involves only the required reactants and products, the equation (2) should be added, which consumes CO2 and produces O2, as shown below:C(diamond) + O2(g) → CO2(g) ΔH = −395.4 kJ [eq. (1)] 2 CO(g) → C(graphite) + CO2(g) ΔH = −172.5 kJ [eq. (4)] 2 CO2(g) → 2 CO(g) + O2(g) ΔH = 566.0 kJ [eq. (2)] C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g) ΔHrxn=ΣΔHf(products)−ΣΔHf(reactants) ΔHrxn=[(3 mol CO2)(-393.5 kJ/mol) + (1 mol C(graphite))(0 kJ/mol)] − [(1 mol C(diamond))(0 kJ/mol) + (1 mol O2)(0 kJ/mol) + (2 mol CO(g))(−172.5 kJ/mol)] − [(2 mol CO2)(566.0 kJ/mol)] ΔHrxn=−2.9 kJ.
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A 0.550 M solution of KCl needs to be prepared through dilution. A 2.00 M stock solution will be added to a 0.250 L volumetric flask and then water will be added to the 0.250 L mark.
Determine the volume (in mL) of the 2.00 M stock solution of KCl needed to produce this solution.
We need to add 68.8 mL of the 2.00 M stock solution of KCl to a 0.250 L volumetric flask and then add enough water to reach the 0.250 L mark to prepare a 0.550 M solution of KCl.
We can use the dilution equation to calculate the volume of the 2.00 M stock solution of KCl needed to prepare the 0.550 M solution:
M1V1 = M2V2
where M1 is the initial concentration of the stock solution, V1 is the volume of the stock solution added, M2 is the final concentration of the diluted solution, and V2 is the final volume of the diluted solution.
We know that M1 = 2.00 M, M2 = 0.550 M, and V2 = 0.250 L. Substituting these values into the dilution equation, we can solve for V1:
(2.00 M)(V1) = (0.550 M)(0.250 L)
V1 = (0.550 M)(0.250 L) / (2.00 M)
V1 = 0.0688 L
We need to convert the volume to milliliters (mL):
V1 = 68.8 mL
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45 The mass of an unidentified metal sphere is 133 grams. Students determine the
volume of the metal sphere by placing it in a graduated cylinder filled with 25
milliliters of water. The volume of the water rises to 40 milliliters when the metal
sphere is placed into the graduated cylinder. The students calculate the density
of the metal sphere in order to determine the identity of the metal using the
chart below.
Density of Common Metals
Density (g/mL)
Aluminum
Metal
2.70
Tin
7.26
Iron
7.87
8.86
Cobalt
What is the identity of the metal?
A Aluminum
B
Tin
C Iron
D Cobalt
Answer:
D Cobalt
Explanation:
The volume of the sphere is 40 -25 = 15 cm^3
Density = mass/volume = 133 gm / 15 cm^3 = 8.87 gm/cm^3
which corresponds to Cobalt from the chart
Lap safety rules crossword
Glucose, C6H12O6, is used to prepare intravenous feeding solutions. What volume of 5.0 % W/V glucose solution can be prepared using 125 g of glucose? Show your working.
Please if the answer is correct, ill give brainliest
250 L of 5.0% w/v glucose solution can be prepared using 125 g of glucose.
We use the below formula to solve our problem,w/v = [ mass of solute (g) / volume of solution (mL) ] × 100
Substitute the values from our problem,5.0 % w/v = [ 125 g / volume of solution (mL) ] × 100
Rearranging the formula, we havevolume of solution (mL) = [ 125 g / 5.0 % w/v ] x 100
Substitute further for w/v,volume of solution (mL) = [ 125 g / (5.0 / 100) ] x 100
Simplify the expression,volume of solution (mL) = [ 125 g / 0.05 ] x 100
Hence, the volume of solution (mL) = 250,000 mL or 250 Lassume that a soil has a water content of 40 percent by weight and a bulk density of 1.3g per cubic centimeter. if the soil dries to 20 percent by weight and shrinks by an amount equal to the water loss, calculate the bulk density at 20 percent moisture
The bulk density at 20 percent moisture, given that the soil dries to 20 percent by weight is 1.4 g/cm³
How do i determine the bulk density?First, we shall obtain the initial volume of the soil. Details below:
Total mass = 100 gBulk density = 1.3 g/cm³Initial volume of soil =?Volume = mass / density
Initial volume of soil = 100 / 1.3
Initial volume of soil = 76.93 cm³
Next, we shall obtain the volume after the soil dries to 20 percent by weight. Details below:
We were told that the soil shrinks by an amount equal to the water loss, thus we have
Initial mass of water = 40% = 40 g
Water lost = 20% = 20 g
New mass of water = 40 - 20 = 20 g
Thus,
Volume = Equal value of mass of water lost = 20 cm³
Finally, we shall obtain the bulk density at 20 percent moisture. Details below:
Mass of dry soil = 60 gNew of mass water = 20 gTotal mass = 20 + 60 = 80 gramsInitial volume = 76.93 cm³Volume at 20 percent moisture = 20 cm³New volume = 76.93 - 20 = 56.93 cm³Bulk density at 20 percent moisture =?Bulk density at 20 percent moisture = Total mass / new volume
Bulk density at 20 percent moisture = 80 / 5.93
Bulk density at 20 percent moisture = 1.4 g/cm³
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How many grams of NH3 can be generated from 8.11x10^23 hydrogen atoms
Answer:
Mass = 15.13 g
Explanation:
Given data:
Mass of ammonia formed = ?
Number of hydrogen atoms = 8.11× 10²³ atoms
Solution:
Chemical equation:
N₂ + 3H₂ → 2NH₃
1 mole = 6.022× 10²³ atoms
8.11× 10²³ atoms × 1 mol / 6.022× 10²³ atoms
1.35 moles of hydrogen
Now we will compare the moles of hydrogen and ammonia,
H₂ : NH₃
3 : 2
1.35 : 2/3×1.35 = 0.89
Mass of ammonia:
Mass = number of moles × molar mass
Mass = 0.89 mol × 17 g/mol
Mass = 15.13 g
Which of the following statements is true regarding soundwaves?
a. Soundwaves travel as longitudinal or transverse waves depending on the medium they’re traveling through.
b. Soundwaves travel as transverse waves only.
c. Soundwaves travel as longitudinal or transverse waves depending on the temperature of the medium.
d. Soundwaves travel as longitudinal waves only.
Answer: Soundwaves travel as longitudinal or transverse waves depending on the temperature of the medium.
Explanation: i think its C
What forms of energy are produced when
fossil fuels burn?
When fossil fuels burn, several forms of energy are produced, including:
Heat energy: The primary form of energy released during fossil fuel combustion is heat. Fossil fuels contain chemical energy stored for millions of years, and when they burn, this energy is released in the form of heat. The heat energy can be harnessed for various purposes, such as heating buildings or generating steam to drive turbines.
Light energy: Burning fossil fuels can also produce light energy in the form of flames or glowing embers. This light energy is a byproduct of combustion.
Mechanical energy: Heat generated by burning fossil fuels can be converted into mechanical energy. This is typically achieved by using heat to produce steam, which drives a turbine connected to a generator. The rotating turbine converts the heat energy into mechanical energy, which is further transformed into electrical energy.
Electrical energy: Through the process described above, burning fossil fuels can ultimately generate electrical energy. The mechanical energy produced by the turbine is converted into electrical energy by the generator. Electrical energy can power various devices, appliances, industries, and infrastructure.
It's critical to note that while burning fossil fuels can produce useful forms of energy, it also results in the release of carbon dioxide and other greenhouse gases. This contributes to climate change and environmental concerns. As a result, there is a global shift towards cleaner and renewable energy sources to mitigate these negative impacts.
What is a solute? A. the substance that dissolves another substance.
A 25.0 mL sample of 0.125 molL−1 pyridine (Kb=1.7×10−9) is titrated with 0.100 molL−1HCl Calculate the pH at 40 mL of added acid.
The pH of added acid at 40 mL is 1.87.
Given,
Concentration of pyridine = 0.125 M
Concentration of HCl = 0.1 M
Volume of pyridine = 25 mL
The millimoles of HCl is calculated as follows:
mmol of HCl = Molarity × Volume of HCl
= 0.1 M × 40 mL
= 4 mmol
The millimoles of pyridine is calculated as follows:
mmol of pyridine = Molarity × Volume of HCl
= 0.125 M × 25 mL
= 3.125 mmol
The concentration of excess HCl is calculated as follows:
Concentration of excess HCl = Millimoles / Total volume
= (4.0 - 3.125) mmol / (40 + 25) mL
= 0.0135 M
The pH of added acid is calculated as shown below:
pH = - log [H⁺]
= - log (0.0135)
= 1.87
Hence, the pH of added acid is 1.87.
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Mang Kadyo has just bought a piece of land in province.The place is situated near a mountain with a lagoon on the southern part of the lot.Where shall he place the water lily plant in order to grow? a.in the garden b.in the lagoon c.near the fence d.on the rocks
Answer:
a.In the garden
Explanation:
Because, inside from garden with big tub like a stock tank on your patio. They grow tubers planted in pots beneath the water and send up stems with rounded leaves and star-shaped blossoms that float on the surface.
I hope it helps to us. Always welcome my youngest sister:). keep learning and God bless.
How much heat is evolved in converting 1.00 mol of steam at 160.0 ∘C to ice at -55.0 ∘C? The heat capacity of steam is 2.01 J/(g⋅∘C) and of ice is 2.09 J/(g⋅∘C).
Answer:
the heat capacity of steam is 2.01 J/(g⋅∘C) and of ice is 2.09 J/(g⋅∘C). 1. See answer.
A 29.3-g sample of an alloy at 93.00 °C is placed into 50.0 g of water at 22.00 °C in an insulated coffee-cup calorimeter with a heat capacity of 9.20
K. If the final temperature of the system is 31.10 °C, what is the specific heat capacity of the alloy?
The specific heat capacity of the alloy is 0.120 J/g°C.
What is Specific heat capacity?
Specific heat capacity, also known as specific heat, is the amount of heat required to raise the temperature of a unit mass (usually one gram) of a substance by one degree Celsius or Kelvin. Each substance has its own specific heat capacity, which depends on its chemical composition and physical state. The SI unit of specific heat is joules per gram per degree Celsius (J/g°C).
First, we need to calculate the heat absorbed by the water:
q_water = m_water * C_water * ∆T
where m_water is the mass of water, C_water is the specific heat capacity of water, and ∆T is the change in temperature of the water.
m_water = 50.0 g
C_water = 4.18 J/g°C
∆T = 31.10°C - 22.00°C = 9.10°C
q_water = (50.0 g) * (4.18 J/g°C) * (9.10°C) = 1911.5 J
Next, we need to calculate the heat released by the alloy:
q_alloy = - q_water
Since the calorimeter is insulated, the heat lost by the alloy is equal to the heat gained by the water.
q_alloy = m_alloy * C_alloy * ∆T
where m_alloy is the mass of the alloy, C_alloy is the specific heat capacity of the alloy, and ∆T is the change in temperature of the alloy.
m_alloy = 29.3 g
∆T = 31.10°C - 93.00°C = -61.90°C (note the negative sign)
q_alloy = (29.3 g) * C_alloy * (-61.90°C)
Finally, we can solve for the specific heat capacity of the alloy:
C_alloy = - q_water / (m_alloy * ∆T)
C_alloy = - (1911.5 J) / ((29.3 g) * (-61.90°C))
C_alloy = 0.120 J/g°C
Therefore, the specific heat capacity of the alloy is 0.120 J/g°C.
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Which object would likely have the least amount of wasted energy?
a hairdryer
a solar cell
a car engine
a hydroelectric dam
Answer:
The answer is solar cell.
Explanation:
It’s the smallest of the 4 choices, the smaller it is the less it wastes.
Answer:
Explanation:
solar cell
CuBr2 percent composition
The percent composition of CuBr₂ is approximately 28.46% of Cu and 71.54% of Br.
To determine the percent composition of CuBr₂ (copper(II) bromide), we need to calculate the mass of each element in the compound and then divide it by the molar mass of the entire compound.
The molar mass of CuBr₂ can be calculated by adding up the atomic masses of copper (Cu) and bromine (Br) in the compound. The atomic masses of Cu and Br are approximately 63.55 g/mol and 79.90 g/mol, respectively.
Molar mass of CuBr₂ = (63.55 g/mol) + 2(79.90 g/mol) = 223.35 g/mol
Now, let's calculate the percent composition of each element in CuBr₂:
Percent composition of copper (Cu):
Mass of Cu = (63.55 g/mol) / 223.35 g/mol × 100% ≈ 28.46%
Percent composition of bromine (Br):
Mass of Br = 2(79.90 g/mol) / 223.35 g/mol × 100% ≈ 71.54%
Therefore, the percent composition of CuBr₂ is approximately:
- Copper (Cu): 28.46%
- Bromine (Br): 71.54%
These values represent the relative mass percentages of copper and bromine in the compound CuBr₂.
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Which equation was used by Albert Einstein to explain the photoelectric effect? [E = energy, h = Planck’s constant, and v = frequency.] E = h/v E = hv E = v/h E = h - v\
Answer:
E = hV
Explanation:
Hello,
Photo electric effect theory was borne out the the confusing if light was either a particle or a wave. However Albert Einstein came up with a theory that light was a particle and each particle carry a certain amount of energy referred to as photons.
He used Max Planck's idea and theorized that since light is made up of photon, when each photon comes in contact with the surface of a metal, the energy is transferred to the electron.
E = hv
E = energy of the photons
h = Planck's constant = 6.626×10⁻³⁴Js
v = frequency of the photon in Hz
Answer:
B
Explanation:
an object has a density of 2.9 grams/cm^3 and a mass of 45.6 grams. Calculate the objects volume.
Answer:
15.72 cm³Explanation:
The volume of a substance when given the density and mass can be found by using the formula
\(volume = \frac{mass}{density} \\\)
From the question we have
mass = 45.6 g
density = 2.9 g/cm³
\(volume = \frac{45.6}{2.9} \\ = 15.724137\)
We have the final answer as
15.72 cm³Hope this helps you
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The statement which interpret the object motion is the object moves with a constant positive velocity and then stops moving. The slope represents velocity. Therefore, option B is correct.
What is velocity ?The term velocity is defined as vector expression representing the change in position over time of an object or particle. It is also known as speed.The unit of velocity magnitude is the meter per second (m/s).
A positive velocity merely indicates that an object is moving in the coordinate system's positive direction, whereas a negative velocity denotes that the item is going in the opposite direction.
Thus, option B is correct.
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which type on bond is present in copper wire?
A. Covalent
B. Ionic
C Electrovalent
D. Metallic
Answer:
metallic bonding
Explanation:
Copper wire consists of Cu nuclei (that are positively charged due to the positively charged protons) that are surrounded by a "sea" of delocalized electrons (that are negatively charged that move freely throughout the material which is known as metallic bonding.
Answer:
Metallic bonding.
Explanation:
Pure copper is neither covalent nor ironic. It is a bonding called metallic bonding.
b. How many kJ of heat are needed to completely vaporize 50.0g of water at 100°C? [Ans:113. kJ]
The amount, in kJ, of heat needed to completely vaporize 50.0g of water at 100°C is 118.8 kJ.
Heat of vaporization of waterThe heat needed to completely vaporize 50.0g of water at 100°C can be calculated using the following formula:
q = m x Hv
where:
q is the heat needed in joules (J)m is the mass of water in grams (g)Hv is the heat of vaporization of water which is approximately 40.65 kJ/mol at standard temperature and pressure.First, we need to convert 50.0g to moles by dividing by the molar mass of water which is approximately 18.015 g/mol3:
moles of water = 50.0 g / 18.015 g/mol moles of water = 2.776 mol
Thus:
q = (2.776 mol) x (40.65 kJ/mol) q = 112.8 kJ
In other words, 112.8 kJ of heat is needed to completely vaporize 50.0g of water at 100°C.
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whats the meaning
Speed ?
and the
meaning of
of Motion?
How many grams of carbon are in 243.3 g
of carbon tetrachloride?
Health Science
1. Structural Levels of the body
a. Characteristics of Living Things
b. Cell Specialization
2. Skeletal and Muscular System
a. The Skeletal System
b. The Muscular System
3. Food and Nutrition
a. Food Pyramid
4. Digestive System
a. Enzymes
5. Circulatory System
a. Circulation
b. Heart
c. Blood Vessels
6. Respiratory System
a. Respiration
b. Breathing
c. The movement of Oxygen
7. Excretion
a. Excretory Organs
8. Nervous System
a. Nerve Cells
b. The Brain
Answer:
Explanation:
Structural Levels of the body:
a. Characteristics of Living Things: Living things exhibit certain characteristics such as the ability to grow, reproduce, respond to stimuli, and maintain homeostasis.
b. Cell Specialization: Cells in the body are specialized to perform different functions such as muscle cells for movement, nerve cells for communication, and red blood cells for carrying oxygen.
Skeletal and Muscular System:
a. The Skeletal System: The skeletal system provides support, protection, and movement for the body. It is composed of bones, cartilage, and ligaments.
b. The Muscular System: The muscular system allows movement of the body and helps in maintaining posture. It is composed of muscles, tendons, and ligaments.
Food and Nutrition:
a. Food Pyramid: The food pyramid is a guide for healthy eating that emphasizes the importance of a balanced diet including fruits, vegetables, grains, protein, and dairy.
Digestive System:
a. Enzymes: Enzymes are proteins that help in breaking down food into simpler forms for absorption in the body. They are produced by different organs in the digestive system such as the pancreas, stomach, and small intestine.
Circulatory System:
a. Circulation: The circulatory system is responsible for the transport of blood and nutrients throughout the body. It consists of the heart, blood vessels, and blood.
b. Heart: The heart is a muscular organ that pumps blood to different parts of the body.
c. Blood Vessels: Blood vessels include arteries, veins, and capillaries that transport blood to and from the heart.
Respiratory System:
a. Respiration: Respiration is the process of inhaling oxygen and exhaling carbon dioxide. The respiratory system is responsible for this process and includes the nose, trachea, bronchi, and lungs.
What is the molarity of a solution made from 325.4g of Aluminum chloride with enough water te
make 500.0 mL?*
(1 Point)
AICIAl = 26.9828 C1 = 35.45
mol
8
mol
0.488M
O 4.88M
0 2.44M
0 2.440M
Answer:
awdaef
Explanation:
explain why division by zero is undefined
Answer:
Division by zero is undefined because there is no other number to divide it by.
Explanation:
Unlike 2/2, 2/0 doesn't have anything to divide the 2 by which makes it undefined and impossible to solve.
The division by zero is undefined, because whatever response we may give, we will then have to concur that the answer times 0 = 1, which is illogical because anything multiplied by zero is zero.
Why division by zero is undefined ?Since any attempt at definition results in a contradiction, the outcome of a division by zero cannot be defined. a=r*b. r*0=a. (1) (1) But because r*0=0 for all r, there is no solution to the equation unless a=0 (1).
Again, mathematicians have left zero divided by zero as an open problem because they are both equally valid and, to be honest, neither of them is consistent with the rest of mathematics.
Mathematically, it is impossible to divide a number by zero, just as in this illustration. Or, at the very least, there isn't currently a means to do that. Numerous attempts have been made to figure out how to divide by zero, as mathematicians are constantly looking for solutions to intriguing mathematical issues.
Thus, The division by zero is undefined, because whatever response we may give, we will then have to concur that the answer times 0 = 1.
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9.23 x 10^23 Au atoms= moles Au
Answer:
1.533 moles Au
Explanation:
To find the moles from atoms, you just use Avogadro's number (6.02214076×10^23 mol^-1) and divide by it. Hope this helped!
Answer:
\(\boxed {\boxed {\sf 1.53 \ mol \ Au}}\)
Explanation:
We are asked to find how many moles of gold are in 9.23 *10²³ atoms of gold.
Avogadro's Number or 6.022 *10²³ is used to convert atoms to moles. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of gold.
We convert using dimensional analysis. Set up a conversion factor using Avogadro's Number.
\(\frac {6.022 \times 10^{23} \ atoms \ Au}{ 1 \ mol \ Au}\)
We are converting 9.23 * 10²³ atoms of gold to moles, so we multiply by this value.
\(9.23 \times 10^{23} \ atoms \ Au *\frac {6.022 \times 10^{23} \ atoms \ Au}{ 1 \ mol \ Au}\)
Flip the conversion factor so the units of atoms of gold cancel.
\(9.23 \times 10^{23} \ atoms \ Au *\frac { 1 \ mol \ Au}{6.022 \times 10^{23} \ atoms \ Au}\)
\(9.23 \times 10^{23} *\frac { 1 \ mol \ Au}{6.022 \times 10^{23}}\)
\(\frac {9.23 \times 10^{23} }{6.022 \times 10^{23} } \ mol \ Au\)
\(1.53271338426 \ mol \ Au\)
The original measurement of atoms has 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 2 in the thousandth place tells us to leave the 3.
\(1.53 \ mol \ Au\)
9.23 *10²³ atoms of gold is equal to approximately 1.53 moles of gold.
Calculate the heat change (ΔΗ°rxn) for the slow reaction of zinc with water
Zn(s)+2H2O(l) ---> Zn^2+ (aq) +H2(g)
ΔΗ°rxn = kJ
The heat change or enthalpy change, ΔH°rxn, for the slow reaction of zinc with water is +417.7 kJ/mol.
The heat change or enthalpy change, ΔH°rxn, for the reaction of zinc (Zn) with water (H₂O) can be calculated using the standard enthalpies of formation for each species involved in the reaction.
Balanced chemical equation for the reaction is;
Zn(s) + 2H₂O(l) → Zn²⁺(aq) + H₂(g)
The standard enthalpy change for the reaction, ΔH°rxn, can be calculated as the sum of the standard enthalpies of formation of the products minus the sum of the standard enthalpies of formation of the reactants, each multiplied by their respective stoichiometric coefficients;
ΔH°rxn = Σ(nΔH°f, products) - Σ(mΔH°f, reactants)
where n and m are the stoichiometric coefficients of the products and reactants, respectively, and ΔH°f is the standard enthalpy of formation.
Assuming standard conditions (25°C and 1 atm), the standard enthalpies of formation for Zn²⁺(aq) and H₂(g) are typically tabulated values. Let's assume their values to be ΔH°f(Zn²⁺(aq)) = -153.9 kJ/mol and ΔH°f(H₂(g)) = 0 kJ/mol, respectively.
The standard enthalpy of formation of water (H₂O) is -285.8 kJ/mol.
Put the values into the equation, we get;
ΔH°rxn = [ΔH°f(Zn²⁺(aq)) + ΔH°f(H₂(g)] - [ΔH°f(Zn(s)) + 2ΔH°f(H₂O(l))]
ΔH°rxn = [-153.9 + 0] - [0 + 2(-285.8)]
ΔH°rxn = -153.9 + 571.6
ΔH°rxn = 417.7 kJ/mol
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Explain ocean currents and how density differences between HOT/COLD and SALT/FRESH affect them.
-for science
Density differences caused by temperature and salinity variations are fundamental drivers of ocean currents of seawater . Warm currents transport heat from the equator to higher latitudes, while cold currents transport cold water from higher latitudes to lower latitudes.
When seawater is heated, it expands and becomes less dense, causing it to rise. Conversely, when seawater cools, it contracts and becomes denser, causing it to sink. These density differences due to temperature variations create vertical movements in the ocean known as thermohaline circulation or convection currents. On the other hand, regions with high freshwater input from rivers or heavy precipitation have lower salinity, resulting in lower density. This lighter water tends to float on the denser seawater beneath it, leading to the formation of surface currents that transport water from areas of low salinity to areas of higher salinity. These ocean currents play a vital role in shaping global climate patterns and maintaining the balance of heat and nutrients in the ocean ecosystem.
Learn more about the ocean current here.
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