A string that is under 55.0 N of tension has linear density 4.20 g/m . A sinusoidal wave with amplitude 3.10 cm and wavelength 1.70 m travels along the string.
What is the maximum velocity of a particle on the string?

Answer:

short circuit

Explanation:

A disrupted circuit in which the current bypasses its proper path is a short circuit.

A short circuit is an electrical circuit which allows the electric current to travel along an unintended and uninterrupted path with no or very low electrical impedance in the circuit. This results in an excessive current flow through the electric circuit.

A short circuit is a situation in which there is  faulty connection or damaged wire that causes electric current to travel along the wrong route in the circuit with low or no resistance and damage an electrical device. This may cause serious damage, fire, or even small-scale explosions.

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Answer:

Explanation:

Using the equation of motion v² = u²+2aS

v is the final velocity = 120km/hr

120km/hr = 120 * 1000/1 * 3600 = 33.3m/s

u is the initial velocity = 0m/s

a is the acceleration

S is the distance covered = 240m

On substituting the given parameters

33.3² = 0²+2a(240)

33.3² = 480a

1110 = 480a

a = 1110/480

a = 2.3125m/s²

Hence the minimum constant acceleration that the aircraft require to be airborne after a takeoff run of 240 m is 2.3125m/s²

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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Taking into account the definition of wavelength, frecuency and propagation speed, the frequency of the waves in the tsunami is 2.59×10⁻⁴ Hz.

First of all, wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

On the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

Finally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.

The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f×λ

In this case, you know:

Replacing:

0.194 m/s=f× 750 km

Solving:

f= 0.194 m/s ÷ 750 km

λ= 2.59×10⁻⁴ Hz

In summary, the frequency of the waves in the tsunami is 2.59×10⁻⁴ Hz.

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The work done by the lift with a mass of 1050 kg and a gravitational field strength is 10 N/kg and a height of 15m is 157.5kJ

The work done is the amount of work done in lifting the object to a certain distance. The work done is the product of mass, gravitational field, and height.

Work done = m×g×h

mass (m) = 1050 kg

        g     = 10 N/kg

height (h) = 15m

W = m×g×h

   = 1050×10×15

  = 157.5 kJ

Thus, the work done(W) = 157.5 kJ.

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The obvious major issue is that Wind and Solar energies are intermittent. They need to be supplemented with another source.

Batteries are harmful to the environment if installed in large quantities to back up solar and wind power. Right now, we have to. In the United States, we get around this by importing the ingredients used to create batteries. We export pollution so that we can purchase batteries (or the materials to make batteries).

One further subtle issue is that the times they work are strongly connected, at least in many regions. In many places, it is windier throughout the day, therefore we obtain wind power when we don't need it since we also have solar power.

The alternative or solution to wind and solar are to use Hydro Electric and or Nuclear energy sources.

Wind and solar, as carbon-free, renewable energy sources, can help lessen the world's reliance on oil and gas.

These carbon fuels contribute to environmental degradation and climate change by emitting damaging greenhouse gases that degrade air, water, and soil quality.

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Answer:

45,000 J

General Formulas and Concepts:

Energy

Kinetic Energy Formula: \(\displaystyle KE = \frac{1}{2}mv^2\)

Explanation:

Step 1: Define

Identify variables

[Given] m = 900 kg

[Given] v = 10 m/s

Step 2: Solve for KE

Answer:

The horse moves due to kinetic energy and is walking balanced because of the gravitational energy

Explanation:

hope this helps :) please mark me brainliest

The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

The given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:

The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:

Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26

Normalize the vector by dividing each component by the magnitude:

Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k

Multiply the normalized vector by the desired magnitude:

To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:

Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)

Simplifying the expression gives:

Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k

So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

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Answer:

no kinetic energy

hope this helps! :-D

Explanation:

the monk is not moving

Answer:

interest point:

1) Point on the left side

2) Point within the radius r₁ of the first sphere

3) Point between the two spheres

4) point within the radius r₂ of the second sphere

5) Right side point

Explanation:

In this case, the total electric field is the vector sum of the electric fields of each sphere, to simplify the calculation on the line that joins the two spheres

We will call the sphere on the left 1 and it has a positive charge Q with radius r1, the sphere on the right is called 2 with charge -Q with radius r2. The total field is

          E_ {total} = E₁ + E₂

          E_{ total} = \(k \frac{Q}{x_1^2} + k \frac{Q}{x_2^2}\)

the bold indicate vectors, where x₁ and x₂ are the distances from the center of each sphere. If the distance that separates the two spheres is d

          x₂ = x₁ -d

          E total = \(k \frac{Q}{x_1^2} - k \frac{Q}{(x_1 - d)^2}\)

Let's analyze the field for various points of interest.

1) Point on the left side

in this case

            E_ {total} = \(k Q \ ( \frac{1}{x_1^2} - \frac{1}{(x_1 +d)2} )\)

            E_ {total} = \(k \frac{Q}{x_1^2}\)   \(( 1 - \frac{1}{(1 + \frac{d}{x_1} )^2 } )\)

We have several interesting possibilities:

* We can see that as the point is further away the field is more similar to the field created by two point charges

* there is a point where the field is zero

            E_ {total} = 0

             x₁² =  (x₁ + d)²

2) Point within the radius r₁ of the first sphere.

In this case, according to Gauus' law, the charge is on the surface of the sphere at the point, there is no charge inside so this sphere has no electric field on its inner point

              E_ {total} = \(-k \frac{Q}{x_2^2} = -k \frac{Q}{((d-x_1)^2}\)

this expression holds for the points located at

                  -r₁ <x₁ <r₁

3) Point between the two spheres

                E_ {total} = \(k \frac{Q}{x_1^2} + k \frac{Q}{(d+x_1)^2}\)

This champ is always different from zero

4) point within the radius r₂ of the second sphere, as there is no charge inside, only the first sphere contributes

                  E_ {total} = \(+ k \frac{Q}{(d-x_1)^2}\)+ k Q / (d-x1) 2

point range

                  -r₂ <x₂ <r₂

5) Right side point

            E_ {total} = \(k \frac{Q}{(x_2-d)^2} - k \frac{Q}{x_2^2}\)

             E_ {total} = \(- k \frac{Q}{x_2^2} ( 1- \frac{1}{(1- \frac{d}{x_2})^2 } )\)- k Q / x22 (1- 1 / (x1 + d) 2)

we have two possibilities

* as the distance increases the field looks more like the field created by two point charges

* there is a point where the field is zero

The resistance over the bulb in the circuit set up as shown in the diagram is 30 Ω.

Resistance can be defined as the opposition to current flow in a circuit.

To calculate the resistance over the bulb, we use the formula below.

Formula:

Where:

From the diagram,

Note: Since the bulb and the 60 Ω resistor are connected in parallel, therefore,

From the diagram,

Given:

Substitute these values into equation 1

Hence, the resistance over the bulb is 30 Ω.

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Answer:

Police powers are the fundamental ability of a government to enact laws to coerce its citizenry for the public good, although the term eludes an exact definition. The term does not directly relate to the common connotation of police as officers charged with maintaining public order, but rather to broad governmental regulatory power. Berman v. Parker, a 1954 U.S. Supreme Court case, stated that “public safety, public health, morality, peace and quiet, law and order. . . are some of the more conspicuous examples of the traditional application of the police power”; while recognizing that “an attempt to define police powers reach or trace its outer limits is fruitless.”

Explanation:

yes, yes it helps in improving locomotive skills

We have the following obervations:

Where v is obtaineg by dividing the distance by the time. Now, if we plot the time and the velocity on the plane we will get the following graph:

From the graph we notice that:

• As time increases the velocity of the object increases as well.

• It appears that we can model this increase in the velocity with a linear equation on the time, in the graph shown above we notice that if we perform a linear regression we get the equation:

and that the line is a good fit. Now, the equation we got has the form:

where a is the acceleration of the ball and v0 is its initial velocity.

Now, even the line we obtain is a good fit for the data we found we know that something is wrong. This comes from the fact that the initial velocity of the object is 1.12 for the line we found and we know that, in our experiment, the initial velocity is zero. This would mean that we need to perform the experiment a few more times to correctly measure what is happening.

Even from this, we are certain of two things that we mention above:

• As time increases the velocity of the object increases as well.

• The velocity of the object as it is falling in the ramp can be modeled by a linear equation.

Answer:

a) \(W=9810\: N\)

b) \(F_{1}=251.14\: N\)        

c) \(V_{g}=0.012\: m^{3}\)

Explanation:

a)

El peso del cuerpo es:

\(W=mg\)

g es la gravedad (9.81 m/s²)

\(W=1000*9.81\)

\(W=9810\: N\)

b)

Usando el principio de Pascal tenemos:

\(P_{1}=P_{2}\)

y la presion es la fuerza sobre el area.

\(\frac{F_{1}}{A_{1}}=\frac{F_{2}}{A_{2}}\)

Despejando F(1):

\(F_{1}=F_{2}\frac{A_{1}}{A_{2}}\)

el area del plato es: \(A=\pi R^{2}\)

\(F_{1}=F_{2}\frac{\pi R_{1}^{2}}{\pi R_{2}^{2}}\)

\(F_{1}=F_{2}\frac{R_{1}^{2}}{R_{2}^{2}}\)

F(2) es el peso del cuerpo de 1000 kg (W)

\(F_{1}=9810\frac{8^{2}}{50^{2}}\)

Por lo tanto, la fuerza que se debe hacer es:

\(F_{1}=251.14\: N\)          

c)

Como tenemos un sistema cerrado el volumen de agua que desciende por el embolo pequeño debe ser igual al que sube por el grande, por lo tanto:

\(V_{p}=V_{g}\)

Vp es el volumen de agua en el émbolo pequeño

Vg es el volumen de agua en el émbolo grande

Como sabemos que son cilindros (V=πR²h)

\(\pi R^{2}h=V_{g}\)

Entonces el volumen del émbolo mayor será:

\(V_{g}=\pi 0.08^{2}0.6\)

\(V_{g}=0.012\: m^{3}\)

Espero te haya sido de ayuda!

Apply third equation of kinematics

\(\\ \rm\rightarrowtail v^2-u^2=2as\)

\(\\ \rm\rightarrowtail -(10)^2=-8s\)

\(\\ \rm\rightarrowtail -100=-8s\)

\(\\ \rm\rightarrowtail s=12.5m\)

Answer:

A

Explanation:

Answer: a or e

Explanation:

Having said that,

Gravitational Constant: g=GMR2

G=6.621011Nm2kg2 R=Radius Earth's M stands for Earth's mass.

The spacecraft is currently far away. R′=2R

As a result, g will be as follows: g′=GMR′2 R′=2R g′=GM4R2 g′=g4 g′=9.84 g′=2.45ms2

At any point on its surface, a non-rotating perfect sphere with equal mass density or one whose density varies exclusively with distance from the centre (spherical symmetry) will produce a constant gravitational field. The Earth is an oblate spheroid because it rotates and is not spherically symmetric; rather, it is slightly flatter towards the poles and bulges at the Equator. As a result, the magnitude of gravity varies slightly throughout the surface.

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Answer:

Explanation:

Velocity measuring by m/s ,speed measuring by m/s,acceleration measuring by m/s² and velocity is vector physical quantity and speed is scalar physical quantity

The maximum force of static friction that the car's wheels can experience with the flat concrete road is  μ×5000 N.

The force of friction that the wheels experience when the car is moving is less than maximum force of static friction.

The definition of static friction is: The resistance people feel when they attempt to move a stationary object across a surface without actually causing any relative motion between their body and the surface they are moving the object across.

As the normal force = 5000 N.

The maximum force of static friction = μ×5000 N.

The force of friction that the wheels experience when the car is moving is less than maximum force of static friction.

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Answer:

aa!aaaaaaaaaaaaaaaaaaaaaaaaaaaa

We are given that an object leaves the earth at a speed of 5054 m/s. We want to determine how far from the center of the earth the object travels. To do that we will do an energy balance. We will have into account that the total energy at the surface of the earth is the kinetic energy of the object plus the gravitational potential energy, and when the object stops the energy is equal to the gravitational potential energy:

Where:

The kinetic energy is given by:

Where:

The gravitational potential energy is given by:

Where:

Substituting the values we get:

In this case, R1 is the radius of the earth since the object leaves from the surface of the earth and R2 the distance to the center of the earth from the object stops as shown in the diagram above.

Now we can set them equal due to conservation of energy:

Now we may cancel out the "m":

We wish to determine the distance to the center of the earth when the object stops, therefore, we solve for "R2". We do this first by multiplying both sides by R2:

Now we divide both sides by the factor multiplying R2:

Now we substitute the known values:

Solving the operations we get:

Therefore, the distance from the earth is 8.06x10^6 meters.

The correct matches for the given words are:

1. grand unified theory - predicts the strong, weak, and electromagnetic forces

2.electroweak force

3. Inflation

4. Olbers' paradox

5. cosmic microwave background

6. annihilation

Physical interactions between electrically charged particles are known as the electromagnetic force. It is the result of the interaction of all magnetic and electrical forces and operates between charged particles.

Both visible light and radiation in other wavebands that the human eye cannot see are produced by the electromagnetic field.

A faint glow of light known as the Cosmic Microwave Background radiation, or CMB for short, permeates the entire cosmos and falls on Earth with a remarkably consistent intensity from all directions.

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kinetic energy = 1/2* m* v^2

Potential energy = m*g*h

Where:

m= mass

g= acceleration due to gravity

h= height

v= velocity

on the top of the building:

K = max ( max height)

U= 0 (no velocity)

Before striking the ground:

k= gets lower ( less h)

U= higher ( it has velocity)

Answer

D. K is less than U.​

According to Coulomb's law, the force between the two magnets is expressed as

F = μom1m2/4πr^2

where

F is the force

m1 and m2 are the pole strength of the magnets

r is the distance between the magnets

μo is the permeability constant

If every thing remains tha same and the distance is doubled, it means that r = 2r

Thus,

F = μom1m2/4π * 2^2 = μom1m2/4π * 1/4

Thus, the correct option is

D) one-fourth as much

Explanation:

F1 will have to have  65 N vertical up force to balance the net 65 N down on the body  AND it will have to have  70 N horizontal to the right to balance the 70 N force that is acting to the left

Magnitude = sqrt ( 65^2 + 70^2) = 95.5  N

Answer:

26621 km

Explanation:

We are given;

Mass: m = 5.98 x 10^(24) kg

Period; T = 43200 s

Formula for The velocity(v) of the satellite is:

v = 2πR/T

Where R is the radius

Formula for centripetal acceleration is;

a_c = v²/R

Thus; a_c = (2πR/T)²/R = 4π²R/T²

Formula for gravitational acceleration is:

a_g = Gm/R²

Where G is gravitational constant = 6.674 × 10^(-11) m³/kg.s²

Now the centripetal acceleration of the satellite is caused by its gravitational acceleration. Thus;

Centripetal acceleration = gravitational acceleration.

Thus;

4π²R/T² = Gm/R²

Making R the subject gives;

R = ∛(GmT²/4π²)

Plugging in the relevant values;

R = ∛((6.674 × 10^(-11) × 5.98 x 10^(24) × 43200²)/(4 × π²))

R = 26.621 × 10^(6) m

Converting to km, we have;

R = 26621 km

Answer:

2.66 *10^7

Explanation:

Sorry I don't know the process if you were interested in that :/

The pelvis in humans serves a functional purpose by supporting the upper body and attaching it to the lower body. Other vestigial structures in humans include ear muscles, tail bone, and hair raising.

As humans evolved, the pelvis became increasingly important in supporting the weight of the upper body and allowing for efficient movement of the legs. In fact, the shape of the pelvis is one of the key factors that distinguishes humans from other primates, as it evolved to accommodate the unique demands of bipedalism. However, not all structures in the human body are as essential as the pelvis. Some, like the ear muscles and tail bone, have lost their original function over time. The ear muscles, for example, were once used to orient the ears towards sounds, but are no longer functional in most humans. Similarly, the tail bone, or coccyx, is a vestige of the tail that our primate ancestors once had, but which no longer serves any purpose in humans. Other vestigial structures in humans include the appendix, which may have once been used to digest a more plant-based diet, and the ability to raise our hair, which was likely used to intimidate predators but now only causes goosebumps.

Despite their lack of function, these vestigial structures continue to exist in humans due to their evolutionary history. And while they may not be essential to our survival, they serve as a reminder of our evolutionary past and the many adaptations that have made us the unique species we are today.

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Explanation:

time taken fir 50 oscillations is 6 seconds

time taken for 1 oscillation is 6/50

convert it into a decimal