If the tension on a stretched string is doubled, the speed of a wave on the string will increase by a factor of the square root of 2 (√2).
The speed of a wave on a stretched string is given by the equation:
v = √(T/μ)
where v is the wave speed, T is the tension in the string, and μ is the linear mass density of the string.
If the tension on the string is doubled (2T), the equation becomes:
v' = √(2T/μ)
To compare the new wave speed (v') with the original wave speed (v), we can take the ratio:
v' / v = √(2T/μ) / √(T/μ)
Simplifying the expression:
v' / v = √(2T/μ) * √(μ/T)
= √(2Tμ / μT)
= √2
Therefore, if the tension on the string is doubled, the speed of the wave on the string will increase by a factor of the square root of 2 (√2).
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5 points
What did Alfred Wegener think happens during Continental Drift?
A. Continents move
B. The mantle warms
C. Convection Stops
D. Continents freeze
Answer:
Continents move
Explanation:
Choose the best equation below to solve this kinematics question:
An aircraft has to have a final velocity of 33 m/s at the end of a runway to be able to liftoff. What acceleration rate would the plane need if it starts from rest and has a runway 240 m long?
A) vf = vi +atvf = vi +at
B) d =12 (vi +vf)t d =12 (vi +vf)t
C) d = vit + 12at2d = vit + 12at2
D) (vf)2 = (vi)2 +2ad
Answer:
(D) Vf² = Vi² + 2ad
a = 2.269 m/s²
Explanation:
Given;
final velocity of the aircraft, Vf = 33 m/s
initial velocity of the aircraft, Vi = 0
distance traveled by the plane, d = 240 m
The acceleration of the plane is given by the following kinematic equation;
Vf² = Vi² + 2ad
where;
a is the acceleration;
Based on the given options, the correct option is "D".
Calculating the acceleration with the chosen equation;
Vf² = Vi² + 2ad
Vf² = 0+ 2ad
Vf² = 2ad
a = Vf² / 2d
a = (33)² / (2 x 240)
a = 2.269 m/s²
A soccer player kicks a ball with initial velocity of 10m/s at an angle of 30 degrees above the horizontal.....what is the magnitude of the vector
Answer: 10m/s^2
Explanation:
Given the following :
Initial Velocity(U) = 10m/s
Angle of inclination = 30°
In other to calculate the magnitude of the vector,
We need to resolve into verti AL and horizontal component.
Vertical component of a vector(Uy) = U × Sinθ
Horizontal component(Ux) = U × Cosθ
Uy = 10 × sin30 = 10 × 0.5 = 5m/s
Ux = 10 × Cos30 = 10 × 0.866 = 8.66m/s
Therefore the magnitude equals :
U = √(Uy)^2 + (Ux)^2
U = √5^2 + 8.66^2
U = √25 + 74.9956
U = √99.9956
U = 9.9997799
U = 10m/s^2
HELPPP TIMED The etiology of somatoform disorders may consist of all of the following except __________ factors.
A.
personality
B.
biological
C.
cognitive
D.
environmental
Answer:
b. biologucal
Explanation:
it is b. biologucal
The etiology of somatoform disorders may consist of all the following except biological. Option B is correct.
What are the somatoform disorders?Somatoform disorder,is a mental health illness in which a person experiences physical symptoms as a result of psychological discomfort.
Family with a negative or anxious personality are more likely to acquire somatoform illnesses.
The etiology of somatoform disorders may consist of all the following except biological.
Hence,option B is correct.
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A P-watt lightbulb emits 5% of its energy as electromagnetic radiation What is the magnitude of the average Poynting vector a distance r from the bulb? Expression:|S_avg| = _____Select from the variables below to write your expression. Note that all variables may not be required β. εo, π, θ, b, c, d, g, h,j, k, P,r, S,z
The expression for |S_avg| is: |S_avg| = (P * β) / (4πε₀r^2c)
The magnitude of the average Poynting vector (|S_avg|) at a distance r from the lightbulb can be calculated using the following expression:
|S_avg| = (P * β) / (4πε₀r^2c)
where:
- |S_avg| is the magnitude of the average Poynting vector
- P is the power emitted by the lightbulb (given as P-watt)
- β is the fraction of energy emitted as electromagnetic radiation (given as 0.05 or 5%)
- π is a mathematical constant (approximately 3.14159)
- ε₀ is the permittivity of free space (a constant)
- r is the distance from the lightbulb
- ^2 denotes "squared"
- c is the speed of light (a constant)
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Consider a 8.96 gram copper block of 24.44JK−1 mol−1 constant molar heat capacity at 85∘C placed in 125 g water constant molar heat capacity 75.29JK−1 mol−1at 25∘C. Consider the heat capacities as constant within the temperature range and calculate for each the change in entropy
Mass of copper block, m = 8.96 g
Constant molar heat capacity of copper, c1 = 24.44 J K⁻¹ mol⁻¹
Initial temperature of copper block, T1 = 85°C
Mass of water, M = 125 g
Constant molar heat capacity of water, c2 = 75.29 J K⁻¹ mol⁻¹
Initial temperature of water, T2 = 25°C
Heat is transferred from the copper block to the water until both reach a common temperature, T. We are to find the change in entropy for each process using the following formula:
Change in entropy, ΔS = Q / T
where Q is the amount of heat transferred and T is the common temperature of the system. Since the process is reversible, we can also write this as:
ΔS = ∫ dQ / T
Change in entropy of copper block:
The amount of heat transferred from the copper block to the water, Q1 = mc1ΔT = (8.96/63.546) × 24.44 × (T - 85) J/K
where ΔT = T - T1 is the change in temperature.
Using the formula for change in entropy:
ΔS1 = Q1 / T = (8.96/63.546) × 24.44 × (T - 85) / T J/K
Change in entropy of water:
The amount of heat transferred from the copper block to the water is the same as the amount of heat gained by the water, Q2. So,
Q2 = -Q1 = -(8.96/63.546) × 24.44 × (T - 85) J
Using the formula for change in entropy:
ΔS2 = Q2 / T = -(8.96/63.546) × 24.44 × (T - 85) / T J/K
Therefore, the change in entropy for the copper block is given by:
ΔS1 = (8.96/63.546) × 24.44 × (T - 85) / T J/K
And the change in entropy for water is given by:
ΔS2 = -(8.96/63.546) × 24.44 × (T - 85) / T J/K
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Help me please help I need it for today please help I don’t want to get zero it my last cance
Answer:
1. D
2. A
v
g the magneto used in the ignition system of old automobile engines consists of a permanent magnet mounted on the fly?wheel of the engine. as the flywheel turns, the magnet passes by a stationary coil, which is connected to the spark plug. explain how this device produces a spark.
The magneto used in the ignition system of old automobile engines produces a spark by utilizing the principle of electromagnetic induction. As the flywheel, with the permanent magnet mounted on it, turns, it generates a changing magnetic field around the stationary coil. This changing magnetic field induces an electric current in the coil, which is then sent to the spark plug. The spark plug, in turn, produces a spark to ignite the fuel mixture in the engine's cylinders. Therefore, the magneto is responsible for providing the necessary spark for the engine to start and run.
I'm happy to help you with your question about the magneto ignition system in old automobile engines. Here's a step-by-step explanation:
1. In a magneto ignition system, a permanent magnet is mounted on the engine's flywheel.
2. As the flywheel rotates with the engine, the magnet also moves along with it.
3. The magnet passes by a stationary coil, which is connected to the spark plug. This coil is also known as the ignition coil.
4. When the magnet moves past the stationary coil, it generates a change in magnetic flux, which in turn induces an electromotive force (EMF) in the coil according to Faraday's law of electromagnetic induction.
5. The induced EMF in the ignition coil causes a current to flow through the coil. This current charges the capacitor, which is part of the ignition circuit.
6. When the current reaches a certain threshold, the contact breaker (or points) in the circuit opens, rapidly interrupting the current flow through the coil.
7. This abrupt interruption of current flow causes the magnetic field in the coil to collapse quickly, which in turn induces a high voltage across the coil terminals, as per Lenz's law.
8. The high voltage generated at the coil terminals is then sent to the spark plug through the distributor.
9. The high voltage across the spark plug creates an electric field strong enough to ionize the air-fuel mixture in the combustion chamber, resulting in a spark.
10. This spark ignites the air-fuel mixture, initiating the combustion process in the engine, and thus, powering the automobile.
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Brandon buys a new Seadoo He goes 12 km north from the beach . He jumps wakes for 6 km to the east . What distance cover ? What was his displacement ?
Answer:
distance- I think it is 6 then the displacement is 13.41
Explanation:
Dave and Alex push on opposite ends of a car that has a mass of 875 kg. Dave pushes the car to the right with a force of 250 N, and Alex pushes to the left with a force of 315 N. Assume there is no friction.
a. Draw a free-body diagram showing all the forces acting on the car.
c. What is the acceleration of the car?
d. What is the normal force acting on the car?
There is a net force of 65 Newton operating on the car in this situation.
What is force, exactly?A body can change its condition of rest or motion through the application of force, which is an external agent. It has both a magnitude and a direction.
F = m * a, where F is force, m is an object's mass, and an is its acceleration
Given this, Dave pushes the car with a force of 250 N, and Alex pushes with a force of 315 N. It is obvious that only horizontal forces will be taken into account, therefore with both objects operating in opposing directions, the net force on the car is = 315-250 = 65N.
Consequently, there is a net force of 65 Newton operating on the car in this situation.
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A more energy-efficient television costs $150
more than a less-efficient model. What are
some reasons you might choose to buy each
television?
PLEASE HELP ME
while undergoing a transition from the n = 1 to the n = 2 energy level, a harmonic oscillator absorbs a photon of wavelength 5.10 μm. What is the wavelength of the absorbed photon when this oscillator undergoes a transition from the n = 2 to the n = 3 energy level?
When the harmonic oscillator undergoes a transition from the n = 1 to the n = 2 energy level and absorbs a photon of wavelength 5.10 μm, we can use the equation E = hc/λ, where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.
First, we need to find the energy of the absorbed photon. We know that the oscillator undergoes a transition from n = 1 to n = 2, so the energy of the photon is equal to the energy difference between these two levels. Using the equation E = -13.6 eV (1/n_final^2 - 1/n_initial^2), where n_final is the final energy level and n_initial is the initial energy level, we can calculate the energy difference to be 10.2 eV.
Now, we can use the equation E = hc/λ to find the wavelength of the absorbed photon. Rearranging the equation, we get λ = hc/E. Plugging in the values we know, we get λ = (6.626 x 10^-34 J s) x (3 x 10^8 m/s) / (1.602 x 10^-19 J/eV x 10.2 eV) = 1.22 μm.
When the oscillator undergoes a transition from the n = 2 to the n = 3 energy level, it emits a photon with a wavelength equal to the energy difference between these two levels. Using the same equation as before, we can calculate this energy difference to be 1.89 eV.
Again, using the equation E = hc/λ, we can find the wavelength of the emitted photon. Rearranging the equation, we get λ = hc/E. Plugging in the values we know, we get λ = (6.626 x 10^-34 J s) x (3 x 10^8 m/s) / (1.602 x 10^-19 J/eV x 1.89 eV) = 3.30 μm.
Therefore, the wavelength of the absorbed photon when the oscillator undergoes a transition from the n = 2 to the n = 3 energy level is 3.30 μm.
To find the wavelength of the absorbed photon when the harmonic oscillator undergoes a transition from the n = 2 to the n = 3 energy level, we can use the energy difference between these levels and the relationship between energy and wavelength.
Here's a step-by-step explanation:
1. Determine the energy difference between n = 1 and n = 2 levels using the given wavelength (5.10 μm):
E1 = (hc) / λ1, where h is Planck's constant (6.626 x 10^(-34) J s), c is the speed of light (3 x 10^8 m/s), and λ1 is the given wavelength (5.10 x 10^(-6) m)
2. Calculate the energy difference between the n = 2 and n = 3 levels:
E2 = E1 * 2 (because the energy levels of a harmonic oscillator are evenly spaced)
3. Determine the wavelength of the absorbed photon during the transition from n = 2 to n = 3:
λ2 = (hc) / E2
4. Solve for λ2 to find the wavelength of the absorbed photon.
By following these steps, you will find the wavelength of the absorbed photon when the harmonic oscillator undergoes a transition from the n = 2 to the n = 3 energy level.
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if your brakes fail, the first thing to do is to... choose one a. apply the parking brake. b. shift to a lower gear, then apply the parking brake. c. pump your brakes. d. shift to neutral.
Answer:
apply the parking break
HELP PLS 100 POINTS TAKING TEST RN
WHEN you look at the speedometer in a moving car, you can see the car's.
A.instantaneous speed.
B.average speed.
C.instantaneous acceleration.
D.average acceleration.
E.average distance traveled.?
Answer:
I think he answer is C but I could be wrong
Explanation:
brainliest plz
Answer:
d mark brainlyest
Explanation:
A car is moving with a constant speed of 15 meters per second. What total
distance does the car travel in 90 seconds?
Answer:
1350 meters
Explanation:
this is easy
15 meters per second
90 seconds
90 * 15 = 1350
Calculate the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 mhz
The wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is 1.978 meter
According to the question
The frequency of a photon of electromagnetic radiation = 151.7 Mhz
By using the Formula of wavelength and frequency
λ = C/f
Where,
λ (Lambda) = Wavelength in meters
C = Speed of Light (c = 3x10⁸ m/s)
f = Frequency
Now, the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is
1 Mhz = 1000000 Hz
151.7 Mhz = 151.7 * 10⁶ Hz
λ = C/f
Substituting the value of C and f
λ = \(\frac{3*10^{8} }{151.7 * 10^{6} }\)
λ = 1.978 meter
Hence, the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is 1.978 meter
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what is the work requird to lift a 215 kg mass a distance of 5.65 m using a machine that is 72.5% efficient?
The maximum work required by the machine is 16420 J.
What is work?Work is energy transferred to or from an object via the application of the force along with the displacement. Work is the standard mechanical quantity. In its simple form, for a constant force aligned with it direction of motions the work equals the product of the forced by the strength and to the distance traveled.
Here mass M is 215 kg
And the height lifted H is 5.65
The energy or workdone needed to lift is W= MgH = 215(9.8)(5.65)= 11904.5 J
The minimum efficiency of to the machine is 72.5 %
So we can write that
The workdone by machine is
11904.5(100/72.5) = 16420 J ( approx)
So the workdone by machine is 16420 J
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1. What happens when like charges come together?*
Answer:
When like charges come together, they repel each other. For instance, when the north and south poles of a magnet come together, they push each other apart. The like poles in the magnet repel each other and unlike poles attract each other much. The same reaction occurs in like and unlike charges. Also, the repulsion acts along the line between the two charges.
Describe an object's velocity when an acceleration-time graph is zero?
A town has 500 real estate agents. The mean value of the properties sold in a year by these agents is $800,000 and the standard deviation is $300,000. A random sample of 100 agents is selected, and the value of the properties they sold in a year is recoreded.
a. What is the standard error of the sample mean?
b. What is the probability that the sample mean exceeds $ 825,000?
c. What is the probability that the sample mean exceeds $ 780,000?
d. What is the probability that the sample mean is between 790,000 and 820,000?
The probability that the sample waves mean is between $790,000$ and $820,000$ is:$$P(-0.33 < z < 0.67) = P(z < 0.67) - P(z < -0.33)$$$$= 0.7486 - 0.3707 = 0.3779$$.
Correct option is, D.
The standard error of the sample mean is:$SE = \frac{300,000}{\sqrt{100}} = 30,000$b. To find the probability that the sample mean exceeds $825,000$, we need to standardize the sample mean using the formula: $$z = \frac{\bar{x} - \mu}{SE}$$Where:z is the standard normal variable$\bar{x} = 825,000$ is the sample mean$\mu = 800,000$ is the population meanSE is the standard error of the sample meanFrom the above data:$z = \frac{825,000 - 800,000}{30,000} = 0.83$Using the standard normal table, we can find that the probability of $z$ being less than $0.83$ is $0.7967$.
The standard error of the sample mean is given by: $ \frac{S}{\sqrt{n}}$ Where:S = the standard deviation of the populationn = sample size$S = 300,000$ and $n = 100$. Therefore, the probability that the sample mean is between $790,000$ and $820,000$ is $0.3779$ or approximately $37.79$%.
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What are the three main guidelines in psychological research?
Answer:
Ethical Guidelines for Research With Human Subjects
Participation Must Be Voluntary.
Researchers Must Obtain Informed Consent.
Researchers Must Maintain Participant Confidentiality
Explanation:
Basta Yun na yan correct me if I'm wrong hehehhe
The primary job of a(n) ____
is to increase the power of a modified radio wave.
The primary job of a(n) ____
is to increase the power of a modified radio wave.
Answer:
amplifierExplanation:
Hope it helps:)
#CarryOnLearning
Answer: Amplifier
Explanation: Edge 2021
Have a great day :D
What is the potential difference between two points when a 65 C charge requires 250 J to move between the points?
Answer:
3.85 V
Explanation:
The potential difference between two points can be calculated using the following equation
\(V=\frac{E}{Q}\)Where E is the energy and Q is the charge. So, replacing E = 250 J and Q = 65 C, we get:
\(V=\frac{250J}{65C}=3.85\text{ V}\)Therefore, the potential difference is 3.85 V
He nurse educator is demonstrating percussing the seventh right intercostal space at the midclavicular line over the liver. which sound should the students expect to hear?
The right upper quadrant of the body contains the liver, which would produce a dull percussion noise.
What is midclavicular line?
The midclavicular line is one of the surface reference lines used in the surface anatomy of the thorax.
Midway through the clavicle's body, a parasagittal vertical plane pierces the bone. While the lateral section of the clavicle is situated near to the highest point of the shoulder joint, the head (medial aspect) lies just lateral to the jugular notch of the sternum, a depression in the superior area of the sternal manubrium (the acromioclavicular joint).
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when a falling merteoiud is at a distance above the earth's surface of 3 times the earth's radius what is it acelartion due to earths gravitation
At a distance above the Earth's surface of 3 times the Earth's radius, the acceleration due to Earth's gravity is approximately 1.23 m/s².
Distance above the Earth's surface of 3 times the Earth's radius, the distance from the center of the Earth is:
d = 4 * R
where R is the radius of the Earth.
The acceleration due to gravity at this distance can be calculated using the formula:
a = G * M / d²
where G is the gravitational constant,
M is the mass of the Earth, and
d is the distance from the center of the Earth.
Substituting the values, we get:
a = G * M / (4*R)²
where G = 6.67 × 10⁻¹¹ Nm²/kg² and M = 5.97 × 10²⁴ kg.
Substituting these values, we get:
a = 1.23 m/s²
Therefore, the acceleration due to Earth's gravity at a distance above the Earth's surface of 3 times the Earth's radius is approximately 1.23 m/s².
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which solutions do you think are:
a. acidic in nature?
b. basic in nature?
[A] Acidic in nature:-
Lime juiceHumans BloodVinegar[B] Basic in nature:-
Lime WaterAntacidButtermilkExplanation:
a) The solutions can be classified as basic or acidic depending on their hydrogen ion concentration relative to pure water. If the value of pH is below seven, then the solution is acidic and if the pH is greater than seven then the solution is said to be basic.
b) Basic in nature means when a substance is soapy and bitter in taste and when a subtance changes red litmus blue. This nature of substance is basic.
HOPE THIS HELPS YOU.....Someone please help me!!! Please explain and I will mark brainliest!!!
R=10+15+30
55 is the answer to the question
A jet flying north increases its velocity at a uniform rate from 138.5 m/s to 432.8 m/s in 47 seconds. Calculate the acceleration of the jet. a 12.16 m/s2 b 294.3 m/s c 6.26 m/s2 d 571.3 m/s
The acceleration of this jet is equal to: C. 6.26 m/s².
How to calculate the acceleration of this jet?In Physics, the acceleration of a physical object (jet) or body can be calculated by using this formula:
a = (V - U)/t
Where:
U represents the initial velocity.a represents the acceleration.V represents the final velocity.t represents the time measured in seconds.Substituting the given parameters into the formula, we have;
Acceleration, a = (432.8 m/s - 138.5 m/s)/47 seconds
Acceleration, a = 294.3/47
Acceleration, a = 6.26 m/s².
In conclusion, we can logically deduce that this jet has an acceleration of 6.26 meters per seconds square (m/s²).
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A tow rope pulls a skier of mass 75 kg up a hill with a force of 20 N. The skier is moving at constant speed. The hill has an incline of 25 degrees. What is the value of the force of friction on the skier? What is the value of the normal force?
The magnitude of the frictional force on the skier is 20 N.
The magnitude of the vertical force of skier is 666.14 N.
What is the frictional force on the skier?The value of the frictional force on the skier is determined by applying Newton's second law of motion as follows;
F - Ff = ma
where;
F is the applied force in horizontal directionFf is the frictional force m is the mass of the skier a is the acceleration of the skierAt a constant speed, the acceleration, a = 0
F - Ff = 0
F = Ff
20 N = Ff
The vertical force due to weight of the skier is calculated as follows;
Fₙ = mg cosθ
where;
θ is the angle of inclination of the hillFₙ = (75 x 9.8) cos(25)
Fₙ = 666.14 N
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Label the following variables below as: Ratio Scale, Equal-Interval, Rank-Order, or Nominal. Then label if: Discrete or Continuous. Each variable should have two labels. A. Letters of the alphabet B. Time of day C. Medals Won in the Olympics D. Percent score from a memory test E. Number of teen pregnancies in San Clemente F. G.P.A. G. Food Grades at Restaurants
Different measurement scales, such as ratio scale, equal-interval, rank-order, and nominal, are used in many disciplines, including statistics and the social sciences.
A. Letters of the alphabet:
Nominal: Without any intrinsic order or numerical value, the letters of the alphabet indicate categories or labels.
Discrete: Each letter is unique and cannot be divided into more compact parts.
B. Time of day:
Equal-Interval: A continuous scale with equal gaps between each unit (such as minutes or seconds) is what the term "time of day" represents.
Continuous: Any fractional value between units is possible when measuring time as a continuous variable (for example, 12:15, 12:30, or 12:45).
C. Medals Won in the Olympics:
Rank-Order: Olympic medals can be rated according to level of accomplishment (for example, gold, silver, and bronze).
Discrete: The total number of medals earned cannot be divided further because it is a whole number.
D. Percent score from a memory test:
Ratio Scale: A score of 50% is half of a score of 100%, for example, and percentage scores from memory tests can be compared using ratios because they have a meaningful zero point.
Continuous: Percent scores allow for fractional values and can range from 0 to 100.
E. Number of teen pregnancies in San Clemente:
Ratio Scale: A scale with a meaningful zero point and the capacity to compare ratios can be used to calculate the number of teen pregnancies.
Discrete: Pregnancies are counted as a whole; they cannot be subdivided into smaller numbers.
F. G.P.A.:
Equal-Interval: A continuous scale with equal distances between each unit is represented by the GPA (for example, 2.0, 2.5, and 3.0).
Continuous: Any value within a range, including fractional values (like 3.75), can be used for G.P.A.
G. Food Grades at Restaurants:
Rank-Order: Restaurants may rate their food using a letter grading system (A, B, C, etc.).
Discrete: There is no more subdividing the grades because they are separate groups.
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