A stream of refrigerant-134a at 1 MPa and 20 C is mixed with another stream at 1 MPa and 80 C. If the mass flow rate of the cold stream is 10 kg/min and the hot stream is 11 kg/min, determine the temperature and the quality of the exit stream. You only need to report the quality here in the quiz, but be sure to identify the temperature in your supporting calculations. Report the quality to two decimal digits, for example 0.32, or 0.86.

Answers

Answer 1

To solve this problem, we can use the energy conservation equation and the properties of the refrigerant-134a to determine the temperature and quality of the exit stream.

Refrigerant-134a, also known as R-134a, is a hydrofluorocarbon (HFC) refrigerant widely used in various cooling and refrigeration systems. It is a colorless gas under normal atmospheric conditions and is commonly used as a replacement for chlorofluorocarbon (CFC) and hydrochlorofluorocarbon (HCFC) refrigerants, which have been phased out due to their harmful effects on the ozone layer.

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Related Questions

The minimum direct-burial depth for rigid metal conduit containing a 480-volt circuit not encased in concrete and not subject to vehicular traffic is ?

Answers

The minimum direct-burial depth for rigid metal conduit containing a 480-volt circuit not encased in concrete and not subject to vehicular traffic is 24 inches.

Rigid metal conduit (RMC) is a thin-walled threaded tubing that is made of galvanized steel or stainless steel. Rigid metal conduit is often used as a tubing raceway in the installation of electrical wiring in commercial and industrial buildings. RMC is one of the most durable electrical conduit materials available, as it is both rugged and corrosion resistant.

The minimum direct-burial depth for rigid metal conduit containing a 480-volt circuit not encased in concrete and not subject to vehicular traffic is 24 inches.

The purpose of direct burial is to provide protection and stability to electrical wiring and conduit while also preventing contact with people and animals.

Direct burial depths are frequently specified by electrical codes.

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(25 pts) Consider the RLC circuit shown below. Derive a differential equation relating


the input x(t) and the output y(t).


(a) (10 pts) If x(t) = Vs(t) and y(t) = Vc(t).


(b) (15 pts) If x(t) = Vs(t) and y(t) = I(t).

Answers

If x(t) = Vs(t) and y(t) = Vc(t), where Vs(t) is the input voltage and Vc(t) is the voltage across the capacitor, we can derive the differential equation relating the two.

In the RLC circuit, we have a resistor (R), an inductor (L), and a capacitor (C) cnnected in series.

Using Kirchhoff's voltage law, we can write the equation:

Vs(t)  VR(t) + VL(t) + VC(t)

Where VR(t) is the voltage across the resistor, VL(t) is the voltage across the inductor, and VC(t) is the voltage across the capacitor.

Since y(t) = Vc(t), we can rewrite the equation as:

Vs(t) = VR(t) + VL(t) + y(t)

ow let's express each component of the circuit in terms of its voltage and current.

\(VR(t) = IR(t) * RVL(t) = L * dI(t)/dtVC(t) = (1/C) ∫[0 to t] I(t') dt'\)

Substituting these expressions back into the equation, we have:

\(Vs(t) = IR(t) * R + L * dI(t)/dt + (1/C) ∫[0 to t] I(t') dt' + y(t)\)

Rearranging the equation and assuming ideal components, we get:

\(L * dI(t)/dt + IR(t) * R + (1/C) ∫[0 to t] I(t') dt' + y(t) = Vs(t)\)

Differentiating both sides of the equation with respect to time, we get:

\(L * d²I(t)/dt² + R * dI(t)/dt + (1/C) * I(t) + dy(t)/dt = dVs(t)/dt\)

This is the derived differential equation relating the input x(t) = Vs(t) and the output y(t) = Vc(t) for the given RLC circuit. If x(t) = Vs(t) and y(t) = I(t), where Vs(t) is the input voltage and I(t) is the current flowing through the circuit, we can derive the differential equation relating the two.

Using Kirchhoff's voltage law, we can write the equation:

\(Vs(t) = VR(t) + VL(t) + VC(t)\)

Since y(t) = I(t), we can rewrite the equation as:

\(Vs(t) = VR(t) + VL(t) + (1/C) ∫[0 to t] y(t') dt'\)

Now let's express each component of the circuit in terms of its voltage andcurrent.

\(VR(t) = IR(t) * RVL(t) = L * dI(t)/dtVC(t) = (1/C) ∫[0 to t] I(t') dt'\)

Substituting these expressions back into the equation, we have:

\(Vs(t) = IR(t) * R + L * dI(t)/dt + (1/C) ∫[0 to t] I(t') dt'\)

Differentiating both sides of the equation with respect to time, we get:

\(L * d²I(t)/dt² + R * dI(t)/dt + (1/C) * I(t) = dVs(t)/dt\)

This is the derived differential equation relating the input x(t) = Vs(t) and the output y(t) = I(t) for the given RLC circuit.

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what were researchers alarmed to discover in the gulf of mexico in 1974?

Answers

In 1974, researchers were alarmed to discover that the Gulf of Mexico had an area of water that was almost devoid of oxygen and was thus unsuitable for marine life. The oxygen-deprived zone is known as the “Dead Zone,” and it is caused by excessive nutrient pollution from human activities.

Dead zones are hypoxic (low-oxygen) areas in the world's oceans and lakes, where aquatic life is unable to survive due to insufficient oxygen levels in the water. These hypoxic regions are caused by large quantities of nutrient pollution (particularly nitrogen and phosphorus) from human activities, such as fertilizer runoff from agricultural fields, sewage discharge from urban areas, and emissions from factories and vehicles.The oxygen-deprived area in the Gulf of Mexico was first discovered in the 1970s, and it has grown larger and more persistent over time.

The zone's size can fluctuate from year to year, but it typically covers a region of the Gulf of Mexico that is roughly the size of Connecticut.

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Technician A says that Detroit ACR injectors will amplify injection
pressure under heavy loads as needed by the engine. Technician B
says that injection amplification in the ACR injector takes place at
engine speeds just above idle. Who is correct?

Answers

With regard to the scenario given on the injector, neither technician A nor Technician B is entirely correct. Here's why:

What is the explanation for the above?

The Detroit ACR (Active Control of the Fuel Injection Rate) injectors are designed to maintain a constant injection pressure, which means they do not amplify the injection pressure under heavy loads. Instead, they vary the timing and duration of the injection events to optimize fuel delivery and reduce emissions.

However, Technician B is partially correct in that the ACR injectors do operate differently at different engine speeds. At engine speeds just above idle, the ACR injectors can provide a more precise fuel delivery and reduce emissions by using multiple injection events during each combustion cycle.

So, in summary, Technician A is incorrect and Technician B is partially correct.

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Sketch (and please upload a screenshot of your paper or digital board) a distance protection system with the following characteristics: -> (2.5) There are three buses in the system (G, H, R) and two transmission lines, one connecting G to H and another one connecting H to R. The relay to be configured is at bus G and it has a CT and a VT properly connected at the bus. Draw a mho-type characteristic zone 1 distance for GH at ~80% reach, and a zone 2 distance at 120% reach on the same R-X diagram. -> (2.5) Mark with a fault that would trip with enough delay the zone 2 but would not trip the zone 1. -> (2.5) Add a directional module and mark with a load value that generally would trip the zone 1 setting, but that after adding the directional module it will be marked as safe operation (will not trip).

Answers

The distance protection system in the power system consists of three buses (G, H, R) and two transmission lines.

What are the characteristics and configurations of the distance protection system in a power system with three buses (G, H, R) and two transmission lines?

In the given distance protection system:

1. Three Buses: The system consists of three buses named G, H, and R.

2. Transmission Lines: There are two transmission lines. One line connects bus G to bus H, and the other line connects bus H to bus R.

3. Relay Configuration: The relay to be configured is located at bus G. It is equipped with a Current Transformer (CT) and a Voltage Transformer (VT) properly connected at the bus.

4. Mho-Type Characteristic Zones:

  - Zone 1 for GH: Draw a mho-type characteristic zone 1 distance on the R-X diagram. This zone should have a reach of approximately 80% and is centered at the origin (0, 0).

  - Zone 2 for GH: Draw a mho-type characteristic zone 2 distance on the same R-X diagram. This zone should have a reach of 120% and is centered at the origin (0, 0).

5. Fault Condition: Mark a fault on the R-X diagram that would cause a delay in tripping the zone 2 but would not trip the zone 1. This fault condition demonstrates a scenario where the fault is located closer to bus H, causing zone 1 to operate before zone 2.

6. Directional Module: Add a directional module to the relay. Mark a load value on the R-X diagram that would generally trip the zone 1 setting. However, after adding the directional module, this load value should be marked as safe operation, indicating that it will not trip the relay.

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In flowing from section (1) to section (2) along an open channel, the water depth decreases by a factor of two and the Froude number changes from a subcritical value of 0.4 to a supercritical value of 2.5. Determine the channel width at (2) if it is 13 ft wide at (1).

Answers

Answer:

channel width = 2.621 ft

Explanation:

Given data :

Decreasing Factor = 2

subcritical value = 0.4

super critical value = 2.5

width = 13 ft

attached below is a detailed solution and

In flowing from section (1) to section (2) along an open channel, the water depth decreases by a factor

I need to solve for d

I need to solve for d

Answers

Answer:

it's not included

Explanation:

plz exact ur explain

Answer:

si amor

Explanation:

Hoiykñjdnlklbutrk

the maximum distance between two pieces of electrical equipment that are considered to be in sight of each other is ? .

Answers

The maximum sight distance is 50 feet (15.24 meters) for equipment operating at more than 600 volts.

What is operating?

Operating is the process of running and controlling the operations of an organization in order to meet desired objectives. It involves coordinating and integrating the activities of personnel, resources, and systems to generate desired results. Operating an organization requires making sure that all the parts of the organization work together in a coordinated manner.

The maximum distance between two pieces of electrical equipment that are considered to be in sight of each other is determined by the National Electrical Code (NEC) and is based on the type of equipment and the voltage rating of the equipment. Generally, the maximum sight distance is 30 feet (9.14 meters) for equipment operating at 600 volts or less, and the maximum sight distance is 50 feet (15.24 meters) for equipment operating at more than 600 volts.

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The fourth main layer is the __________, which is the lower part of the thermosphere, contains less than 1% of the total mass of the atmosphere, and contains mostly oxygen ions that are formed when the ultraviolet radiation from the Sun takes away electrons from the oxygen atoms producing ionospheric plasma.

Answers

To answer the given student question, the fourth main layer is the ionosphere, which is the lower part of the thermosphere, contains less than 1% of the total mass of the atmosphere, and contains mostly oxygen ions that are formed.

When the ultraviolet radiation from the Sun takes away electrons from the oxygen atoms producing ionospheric plasma. The ionosphere is a region of the Earth's atmosphere that is ionized by solar and cosmic radiation. It is located in the upper mesosphere and lower thermosphere, between about 60 and 1,000 kilometers (37 and 620 miles) above the Earth's surface.The ionosphere is responsible for a number of important atmospheric phenomena, including the aurora, the formation of clouds, and the reflection of radio waves. It also plays a crucial role in the transmission of radio and television signals, as well as in the navigation of aircraft and spacecraft. In addition, the ionosphere is a region of intense scientific interest, as it provides important insights into the dynamics of the Earth's atmosphere and the effects of solar activity on our planet.

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Before using a vise to mount work, you should do all of the following except

Answers

Before using a vise to mount work, wipe the vise base and worktable clean, inspect it for burrs and nicks, and bolt it firmly to the table.

What is meant by vise?A vise or vice is a mechanical tool used to hold an object in place so that work can be done on it. The two parallel jaws of a vise are threaded in and out by a screw and a lever, with one jaw being fixed and the other movable. A set of locking pliers with a lever action is what is meant by the term "vise grip." A vise, also spelled vice, is a holding mechanism with two parallel jaws; one jaw is fixed and the other is moveable via a screw, lever, or cam. The vise may be permanently affixed to a bench when used to hold a workpiece during manual processes like filing, hammering, or sawing.

The complete question is,
When a vise is used to mount work, ____.

wipe the vise base and worktable clean, inspect it for burrs and nicks, and bolt it firmly to the table

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what are two types of drag that act on an aircraft in flight

Answers

Answer:

Parasite drag and induced drag.

15. Whether technology is good or bad depends on how it is used.
(1 point)
O True
O False

Answers

Answer:

true

Explanation:

Answer:

True

Explanation:

The internet is a very useful tool, but remember there are billions of people out there who would use it for good purpose or bad ones.

What is the relationship between inductive reactance and frequency?

Answers

Answer:

Inductive reactance is denoted by \(X_L\) where

\(X_L=2\pi fL\)

from looking at the equation, you can see that as frequency increases, so does the inductive reactance.

Simplify the following Boolean functions, using three- variable maps (a) F(x, y, z)=Σ(0, 2, 4, 5, 6) (b) F (x, y, z)=Σ(0, 1, 2, 3, 5) (c) F(x, y, z)=Σ(1,2,3,5,6,7) (d) F(x, y, z)=Σ(2, 3, 4, 5) (e) F (x, y, z)=x'y+yz +y'z'

Answers

(a) F(x, y, z) = x'z' + xz

(b) F(x, y, z) = x' + yz

(c) F(x, y, z) = y + xz

(d) F(x, y, z) = yz + xz'

(e) F(x, y, z) = x'y + yz, already simplified.

What are these?

These are simplified Boolean expressions using Karnaugh Maps or three-variable maps for each function, where Σ represents minterms.

Karnaugh map (KM) is a method of simplifying Boolean algebra expressions. It is a visual way to represent the truth table of a Boolean function. KM can be used to simplify functions with up to four variables.


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The liquid-phase reaction A + B → C follows an elementary rate law and is carried out isothermally in a flow system. The concentrations of A and B feed streams are 2 M before mixing. The volumetric flow rate of each stream is 5 dm3 /min and the entering temperature is 300 K. The streams are mixed immediately before entering. Two reactors are available: One is a gray 200.0 dm3 CSTR that can be heated to 77°C or cooled to 0°C, and the other is a white 800.0 dm3 PFR operated at 300 K that cannot be heated or cooled but can be painted red or black. (Note: k = 0.07 dm3 /mol*min at 300 K and E = 20 kcal/mol.) How long would it take to achieve 90% conversion in a 200 dm3 batch reactor with CA ° = CB ° = 1 ???? after mixing at a temperature of 70°C?

Answers

Answer:

1.887 minutes

Explanation:

We are given k = 0.07 dm3 /mol*min at 300 K and E = 20 kcal/mol = 20000 cal/mol

To solve this, first of all let's calculate the rate constant(k);

For this question, The formula is;

K(t) = k(300K) × exp[(E/R)((1/300) - (1/T2))]

R is gas constant = 1.987 cal/mol.K

For temperature of 70°C which is = 70 + 273K = 343K, we have;

K(343) = 0.07 × exp[(20000/1.987)((1/300) - (1/343))]

K(343) = 4.7 dm³/mol.min

The design equation is;

dX/dt = -(rA/C_Ao) = K•(C_Ao)²•(1 - X)²/(C_Ao) = (KC_Ao)(1 - X)²

Since there is no change in volume by cause of the state at which the reaction is carried out, that is liquid. Thus, integrating and solving for time for a 90% conversion we obtain;

(0.9,0)∫dX/(1 - X)².dX = (KC_Ao)((t, 0)∫dt

So, we'll get;

0.9/(1 - 0.9) = 4.77 × 1 × t

t = 9/4.77

t = 1.887 minutes

Which is the maximum length for any opening on the surface of a 2G SMAW guided bend test specimen?
O 1/3 inch
O 1/4 inch
O 1/8 inch
O 1/2 inch

Answers

Answer:

1/8 is the maximum length for opening any on the surface of 2 gtam guided bend test specimen

Pls help!!! will give brainly!!!
Bridge collapses have hit the news recently with more frequency. Do some research online and state two possible reasons for these collapses. How might those employed in the Health, Safety, & Environmental Management pathway help prevent these collapses and keep us safe?

Answers

Answer:

The main reason for bridges collapses is: earthquakes (natural disasters) and construction incidents. Whenever a natural disaster occur, it makes the bridge collapse. An example is hurricanes. Hurricanes come with a great wind and that might lead to the bridge collapsing. Construction incidents means the bridge falls during construction. Those who are employed in health, safety and environmental management need to make sure that during the construction, they have examined the material and made sure it is strong. Working with economists, they should seek better understanding of the methods for minimizing the costs during the life of the bridge. In case for natural disasters, like flooding, they should make the bridge in a lever where the water won't reach the bridge. And they should have a limit for weight in the bridges because that is another reason it collapses, because the bridge does not support extra weight.

Explanation:

hope this helps

fraternity house with 40 occupants is considered a Group pancy. a. R-1 c. R-3 Reference b. R-2 d.

Answers

A fraternity house with 40 occupants is considered a Group A fraternity house with 40 occupants is considered a Group R-2 occupancy. The correct option is B.

What is a fraternity house?

Fraternity and sorority housing in North America primarily refers to the residences or communities where members of these organizations live and socialize. Fraternity and sorority housing can serve as a place to live as well as a place to host social events, meetings, and community-oriented activities.

When there are 40 residents living in a fraternity house, it is referred to as a Group R-2 occupancy. Therefore, based on the information, the correct option is B.

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a packet of five cards consists of the ace of spades, the ace of hearts, the 2 of spades, the 3 of diamonds, and the 4 of clubs. if the packet is thoroughly shuffled, what is the probability that the two aces end up side by side?

Answers

Answer:

There are 5! = 120 possible ways to order the five cards in the packet. To find the probability that the two aces end up side by side, we can count the number of ways in which the two aces are adjacent and divide by the total number of possible orderings.If we consider the two aces as a single unit, there are 4! = 24 ways to arrange the three-card unit {AA, 2S, 3D, 4C} with the aces together. However, the aces can be arranged within the unit in two ways (Ace of Spades - Ace of Hearts or Ace of Hearts - Ace of Spades). So there are 2 x 24 = 48 ways to arrange the five cards with the two aces together.Therefore, the probability that the two aces end up side by side is 48/120 = 2/5 or 0.4.:

An elevation is.... * 10 points a. A detailed description of requirements, composition and materials for a proposed building. b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building. c. The development of the last remaining lots in an existing developed area, the new development within an area already served by existing infrastructure and services, or the reuse of already developed, but vacant properties. d. The practice of creating structures and using processes that are environmentally responsible and resource-efficient throughout a building's life-cycle from siting to design, construction, operation, maintenance, renovation and deconstruction.

Answers

Answer:

b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building.

Explanation:

An elevation is a three-dimensional, orthographic, architectural projection that reveals just a side of the building. It is represented with diagrams and shadows are used to create the effect of a three-dimensional image.

It reveals the position of the building from ground-depth and only the outer parts of the structure are illustrated. Elevations, building plans, and section drawings are always drawn together by the architects.

Waterbutt filtration system for pond. Water pressure principles, help needed?

I have water butt 1 and 2 working perfectly but as soon as I add another to the system water butt 1 and 2 start rising and overflowing.

Is there something I'm missing or doing wrong here? How does water leveling work?

Thanks all.

Answers

Water pressure principles is known to  state that the amount of Fluid pressure is said to be perpendicular to the surface on which it it exert or works on.

Note that  principle is shown by a vessel that is said to be having flat sides and has water. The pressure exerted by the weight of the water is therefore known to be perpendicular to the walls of the storage.

What is a Waterbutt used for?

A water butt is known to be a container that is made and also used to store a lot of rainwater.

Note that Water pressure principles is known to  state that the amount of Fluid pressure is said to be perpendicular to the surface on which it it exert or works on.

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Suppose that x is an int variable, ch is a char variable, and the input is:
276.
Choose the values after the following statement executes:
cin >> ch >> x;
a. ch='2',x=276
c. ch='',x=276
b. ch='276',x='.'
d. ch='b',x=76

Answers

The values for the datatypes variable after the following statement executes are: ch = '2', x = 76

What is datatype?

Data types describe the kinds of values that a variable can store. They establish the kind of operations that can be carried out on the data, the amount of memory needed to hold the data, and the possible range of values. Integer, float, double, char and boolean are a few examples of common data types. A boolean datatype stores either true or false values, while a float or double data type stores floating point numbers, a char data type stores single characters, a string data type stores a series of characters, and an integer data type stores full integers. The type of data to be saved and the unique program requirements both influence the datatype to be used.

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Technician A says that latent heat is hidden heat and cannot be measured on a thermometer. Technician B says that latent heat is hidden heat that is required for a change of state of matter. Who is correct? a. A only b. B only c. Both A and B d. Neither A nor B

Answers

Answer: C

Both A and B are correct

Explanation:

Latent heat is the hidden heat.

Latent heat is the heat energy required to change one state of matter to another state of matter without change in temperature. For example, solid state to liquid state, or liquid state to gaseous state.

Thermometer can not detect the latent heat. That is why it is called hidden heat.

If Technician A says that latent heat is hidden heat and cannot be measured on a thermometer. And Technician B says that latent heat is hidden heat that is required for a change of state of matter, then we can therefore conclude that both Technician A and Technician B are correct.

A circular secondary clarifier (a.k.a. a final clarifier) is to be designed for an activated sludge treatment plant serving a municipality. The state regulatory agency criteria for final clarifiers used for activated sludge are: Peak SOR = 1,200 gal/day-ft2 Average SOR = 500 gal/day-ft2 Peak solids loading 50 lb/day-ft Peak weir loading-30,000 gal/day.ft - The average flow to the aeration basin prior to junction with the recycle line is 3.5 MGD - The recycled sludge flow is 30 percent of the average influent flow rate and is constant throughout the day. 0.3 The mixed liquor suspended solids (MLSS) 2,500 mg/L. - The ratio of the peak hourly influent flow to the average hourly flow is 2.0 Qpsayo..g = 2.0 Determine a. The clarifier diameterb. The peak weir loading if peripheral effluent weirs are used.

Answers

a. The clarifier diameter is approximately 174 feet.

b. The peak weir loading is approximately 0.009 lb/day-ft.

To determine the clarifier diameter, we can use the formula:

D = sqrt[(Qp / (2.26 * SOR * (1 + R))] where Qp is the peak influent flow rate, SOR is the peak surface overflow rate, and R is the recycle ratio. Plugging in the given values, we get:

D = sqrt[(2.0 * 3.5 MGD / (2.26 * 1200 gal/day-ft2 * (1 + 0.3)))]

D ≈ 174 ft

To determine the peak weir loading, we can use the formula:

W = Qp / (1 + R) where W is the peak weir loading. Plugging in the given values, we get:

W = 2.0 * 3.5 MGD / (1 + 0.3)

W ≈ 105,263 gal/day-ft

To convert the weir loading to solids loading, we can use the formula:

SL = W * MLSS * 8.34 lb/gal where SL is the solids loading and MLSS is the mixed liquor suspended solids concentration. Plugging in the given values, we get:

SL = 105,263 gal/day-ft * 2,500 mg/L * 8.34 lb/gal / (1,000,000 mg/L)

SL ≈ 0.009 lb/day-ft

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Is a 10 foot ladder long enough to safely reach a landing that is 9 feet above the adjacent floor

Answers

Answer:

Definitely not

Explanation:

You should have 1-2 feet of extra ladder on a flat surface so 1 foot on an adjacent floor is a no no

A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes through the center of gravity of the box. The box is 5m wide x 5m tall, and the coefficient of static friction between the box and the surface is u=0.15. Determine the smallest magnitude of the force P that will cause the box to slip or tip first. Specify what will happen first, slipping or tipping.

A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes

Answers

Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

A site is underlain by a soil that has a unit weight of 118 lb/ft3. From laboratory shear strength tests that closely simulated the field conditions, the total stress parameters were measured to be C total = 250 lb/ft2 and φ total = 29°. Estimate the shear strength on a horizontal plane at a depth of 12 ft below the ground surface at this site in lbs/ sq ft

Answers

Answer: the shear strength at a depth of 12 ft is 1034.9015 lb/ft²

Explanation:

Given that;

Weight of soil r = 118 lb/ft³

stress parameter C = 250 lb/ft²

φ total = 29°

depth Z = 12 ft

The shear strength on a horizontal plane at a depth of 12ft

ζ = C + δtanφ

where δ = normal stress

normal stress δ = r × z = 118 × 12 = 1416

so

ζ = C + δtanφ

ζ = 250 + 1416(tan29°)

ζ = 250 + 1416(tan29°)

ζ = 250 + 784.9016

ζ = 1034.9015 lb/ft²

Therefore the shear strength at a depth of 12 ft is 1034.9015 lb/ft²

Describe the steps in the PDCA (Deming or Shewhart) cycle.

Answers

PDCA (Plan-Do-Check-Act) is a four-step iterative management method. Plan: Set objectives and devise a plan. Do: Implement the plan on a small scale.

Check: Evaluate the results against objectives and identify deviations. Act: Adjust and refine the plan based on the evaluation. Repeat the cycle to continuously improve processes.

The PDCA cycle begins with planning, where objectives are set and a plan is developed. Next is the implementation stage, where the plan is executed on a small scale. The check phase involves evaluating the results and comparing them with the objectives to identify any deviations or gaps. In the act phase, necessary adjustments and refinements are made to the plan based on the evaluation. The cycle repeats to foster continuous improvement and maintain a dynamic process of goal-setting, implementation, evaluation, and refinement.

Learn more about refinement here:

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Fig. 1. shows a support system for a wooden balcony, knowing that the tension is 425 lb. in cable AB and 510 lb. in cable AC, determine the magnitude and direction of the resultant of the forces exerted at A by the two cables.

Fig. 1. shows a support system for a wooden balcony, knowing that the tension is 425 lb. in cable AB

Answers

Answer: point A[{-40i + 0j + 45k}], B[{0i + 0j + 60k}], C[{ 60i + 0j + 60k}] from there you can now find the Magnitudes then The unit vectors multiplied by the forces provided 425lb AB and 510lb AC.

Explanation:

What should you do if you encounter a fishing boat while out in your vessel?.

Answers

Answer:

if you encounter fishing or hunting boats while you are paddling, be courteous.

Give them a wide berth.

Never run overfishing lines. Be aware that anglers may have lines out to the sides of their boat or trolling behind them.

Explanation:

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