a stone thrown horizontally from the top of a 24-m tower hits the ground at a point 18 m from the base of the tower. (ignore any effects due to air resistance.) (a) find the speed with which the stone was thrown. (b) find the speed of the stone just before it hits the ground.

Answers

Answer 1

The speed of the stone just before it hits the ground is 23.05 m/s.

The given information is:

Height of the tower, h = 24 m

Horizontal distance traveled by the stone, x = 18 m


(a) To find the speed with which the stone was thrown, we need to find the time it takes for the stone to hit the ground. We can use the equation for vertical displacement:

y = y0 + v0y*t - (1/2)g*t^2

Since the stone is thrown horizontally, v0y = 0. Substituting the given values:

0 = 24 - (1/2)(9.8)t^2

Solving for t, we get:

t = sqrt(24/(1/2)(9.8)) = 2.21 s

Now, we can find the horizontal speed of the stone using the equation for horizontal displacement:

x = x0 + v0x*t

Substituting the given values:

18 = 0 + v0x*(2.21)

Solving for v0x, we get:

v0x = 18/2.21 = 8.14 m/s

Therefore, the speed with which the stone was thrown is 8.14 m/s.


(b) To find the speed of the stone just before it hits the ground, we need to find the vertical and horizontal components of the velocity.

The horizontal component is the same as the initial horizontal speed, which we found in part (a) to be 8.14 m/s. The vertical component can be found using the equation for vertical velocity:

vy = v0y - g*t

Substituting the given values:

vy = 0 - (9.8)(2.21) = -21.66 m/s

Now, we can find the magnitude of the velocity using the Pythagorean theorem:

v = sqrt(vx^2 + vy^2) = sqrt((8.14)^2 + (-21.66)^2) = 23.05 m/s

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Related Questions

A car initially traveling at 15.0 m/s accelerates at a constant rate of 4.50 m/s2 over a distance of 45.0 m. how long does it take the car to cover this distance? (4 points)

Answers

A car initially traveling at 15.0 m/s accelerates at a constant rate of 4.50 m/s2 over a distance of 45.0 m, the time taken to cover this distance  is mathematically given as

t = 2.24 s

What is the time taken to cover this distance?

Generally, the equation for Kinematic relation is mathematically given as

S = ut + (1/2)at^2

Therefore

45 = 15t + 2.25 t^2

2.25 t^2 + 15 t -45 = 0

t = 2.24 s

In conclusion, the time is taken to cover this distance

t = 2.24 s

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a dc series motor is supplied by 200 vdc. the motor current is 5 a when it runs at 600 rpm. the armature resistance is 1.1 ω, and the field winding resistance is 0.8 ω. calculate the motor constant.

Answers

The motor constant (K) for the given values is approximately 0.0633.

The motor constant of a DC series motor can be calculated using the formula:

K = (Ea - Ia * Ra) / (Ia * N)

where K is the motor constant, Ea is the applied voltage, Ia is the armature current, Ra is the armature resistance, and N is the motor speed in revolutions per minute (RPM).

Given:

Applied voltage (Ea) = 200 V

Armature current (Ia) = 5 A

Motor speed (N) = 600 RPM

Armature resistance (Ra) = 1.1 Ω

Substituting the given values into the formula, we get:

K = (200 - 5 * 1.1) / (5 * 600)

Simplifying the equation:

K = 190 / 3000

K = 0.0633

Therefore, the motor constant is 0.0633.

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Which observations most likely led to Jenna’s conclusion?

a change of odor
a decrease in temperature
a change in moisture content
a decrease in mass

Answers

The findings that most likely contributed to Jenna's conclusion were a change in smell. Option A is correct.

What is odor?

A fragrance, usually an unpleasant one: The smell of sweaty feet was palpable throughout the space. Our body odor has a big impact on the kinds of scents we enjoy.

The complete question is;

"Jenna pulled out an open bowl of leftover mashed potatoes from the fridge and smelled something different. She discovered that since the potatoes were initially placed there, chemical changes had taken place. Which facts most likely supported Jenna's judgment?

a change of odor

a decrease in temperature

a change in moisture content

a decrease in mass"

The observation that most likely inspired Jenna to draw her conclusion was a change in odor.

Hence, option A is correct.

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Answer:

A change in odor

Explanation:

The Oort Cloud is about 70 000 times as far as from Earth as Earth is from the Sun. How far away is the Oort Cloud?

Answers

Answer:The Oort Cloud is about 70 000 times as far

Using the side lengths of △pqr and △stu, which angle has a sine ratio of four-fifths? ∠p ∠q ∠t ∠u

Answers

∠p has a sine ratio of four-fifths.

The answer is option A.

Trigonometric Ratios are defined because the values of all the trigonometric features are based totally on the fee of the ratio of sides in a right-angled triangle. The ratios of sides of a right-angled triangle with recognition of any of its acute angles are referred to as the trigonometric ratios of that particular perspective.

The six trigonometric ratios are sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (sec).

In geometry, trigonometry is a department of mathematics that offers the sides and angles of a right-angled triangle. Therefore, trig ratios are evaluated with admire to aspects and angles.

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Answer: A

Explanation: Angle P

Planets A and B have the same size, mass, and direction of travel, but planet
A is traveling through space at half the speed of planet B. Which statement
correctly explains the weight you would experience on each planet?
A. You would weigh the same on both planets because their masses
and the distance to their centers of gravity are the same.
B. You would weigh less on planet B because it is traveling twice as
fast as planet A.
C. You would weigh the same on both planets because your mass
would adjust depending on the planet's speed.
D. You would weigh more on planet B because it is traveling twice as
fast as planet A.

Answers

Answer: A

Explanation:

Answer:

A. You would weigh the same on both planets because their masses and the distance to their centers of gravity are the same.

Explanation:

A pe x :)

You place a basketball in the back of a pickup truck and then accelerate the pickup quickly.
Describe the motion of the ball relative to:
(a) the ground and
(b) the pickup.

Answers

a)When the pickup truck accelerates forward then the ball will shift to the back of the of the truck because of inertia relative to ground.

b)You place a basketball in the back of a pickup truck and then accelerate the pickup quickly then ball would be traveling at the same speed with respect to the truck.

What do you mean by relative motion?

Relative Motion refers to the motion of any object with respect to a particular point.

For example, a ball thrown upward in a moving object such as bus, would be traveling in the same speed with respect to the bus and would fall in relation to that speed.

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The formula shown below is used to calculate the energy released when a specific quantity of fuel is burned so that it heats up some water. What is the missing factor?

Answers

Answer:

8400 J

Explanation:

That is the picture of the explanation

The formula shown below is used to calculate the energy released when a specific quantity of fuel is

How does head to tail rule helps us to find the resultant of forces ?? Explain with the help of a diagram.

Answers

Head to tail rule helps us to find the resultant of forces because in this rule we join many vectors with each other forming resultant vector.

What is head to tail rule?

The joining of tail of the first vector with the head of the second vector represents the resultant vector whereas the direction of the resultant vector is from the tail of the first vector towards the head of the second.

So we can conclude that Head to tail rule helps us to find the resultant of forces because in this rule we join many vectors with each other forming resultant vector.

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Which of the following statements is true about roasting in convection ovens.

Answers:
- Convection ovens are very effective for browning roasts.
- A convection oven should be set about 50°F (25°C) higher than a conventional oven.
- Conventional ovens are more efficient than convection ovens for high-temperature roasting.
- Most chefs believe that roasts cooked in convection ovens shrink less than those cooked in conventional ovens.

Answers

The following statements is true about roasting in convection ovens is a. Convection ovens are very effective for browning roasts.

The convection oven's fan and exhaust system circulate hot air around the food, creating a consistent and even heat distribution. This allows for a quicker and more even cooking process, resulting in a beautiful browned crust on the outside of the roast. However, it is important to note that a convection oven should be set about 50°F (25°C) lower than a conventional oven, this is because the circulating hot air in the convection oven cooks the food faster than in a conventional oven.

Additionally, most chefs believe that roasts cooked in convection ovens shrink less than those cooked in conventional ovens because the even heat distribution allows for more moisture retention in the meat. Overall, roasting in a convection oven can be a great option for achieving a beautifully browned and evenly cooked roast. So therefore the correct answer is a. Convection ovens are very effective for browning roasts.

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The drawings show the mass and weight of four objects on different planets:

(see the picture)

(a)
On which of the four planets is the object with the largest mass?​

Answers

The object with the highest mass is the one on planet D. This is because mass is a measure of the amount of matter an object contains, and is not affected by gravity. Therefore, although the weight of the object on planet D is lower than that of the other planets, its mass remains the same.

Weight, on the other hand, is a measure of the gravitational force acting on an object. Therefore, the weight of an object will vary on different planets due to different gravitational forces. As shown in the drawings, the object on planet A has the greatest weight, but nevertheless the greatest mass.

In summary, the object with the greatest mass is on planet D, while the object with the greatest weight is on planet A.

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A golf ball is initially travelling at 25m/sec hits a sand traps and slow down with an acceleration of -25m/sec. find its displacement after 2.0 sec.

Answers

The displacement of the ball is zero.

What is displacement?

The smallest distance between the initial and final position of an object.

What are the equations of motion?

There are three equations of motion that completely describes the motion of an object.

The first equation of motion gives the relationship between the initial velocity, final velocity, acceleration, and time.

The second equation of motion gives the relationship between the initial velocity, displacement, acceleration, and time.

The third equation of motion gives the relationship between the initial velocity, final velocity, acceleration, and displacement.

Given time, initial velocity, and acceleration, the displacement can be calculated using the second equation of motion. The second equation of motion is,

s=u*t+(1/2)*a*t^2

Here, u=25 m/sec, a=-25 m/sec and t=2.0 sec.

Put the values in the formula and calculate the displacement.

s= (25)*(2.0)+(1/2)*(-25)*(2.0)^2

s=50-50

s=0 m.

Hence the displacement of the ball is zero.

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A machines mechanical advantage is the number of times the machine multiplies the input force. True or False?

Answers

Answer:

The answer is True

Explanation:

~FuntimeFazbear87

Gravitational force between two masses m, and m, is represented as F Gm₂ m₂ 7 where = xi+yj + zk and Irl=√√x² + y² + z² G,m,, m₂ are nonzero constants and let's assume that I 0 a) Calculate curl of and divergence of F (4 points) b) Show the integral ffdf is path independent and calculate following (4 points) (11) 우리가 일반물리 시간에 중력장을 이용한 포텐셜은 위치의 함수라는 걸 배운게 기억이 날겁니다. 이 문제는 사실 vector function 에 대한 문제인데 (9.10.11 단원), 우리가 배운 수학적 도구를 가지고 한번쯤 생각해볼 필요가 있어서 넣었습니다.

Answers

Gravitational force between two masses m, and m, is represented as F = Gm₂ m₂ / r^2 where r = xi+yj + zkG, m, m₂ are nonzero constants and let's assume that I = 0

a) Calculation:For F = Gm₂ m₂ / r^2.

Using r = xi+yj + zk and let r^2 = x^2 + y^2 + z^2∴ F = Gm₂ m₂ / (x^2 + y^2 + z^2), Where G, m, m₂ are nonzero constants. Divergence of F = ∇ · F= 1/r^2(d/dx(r^2Fx) + d/dy(r^2Fy) + d/dz(r^2Fz))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)^(3/2)) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)^(3/2)) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)^(3/2)))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2))= 1/r^2(Gm₂ m₂ [2x(x^2+y^2+z^2)-3x^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2y(x^2+y^2+z^2)-3y^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2z(x^2+y^2+z^2)-3z^2]/(x^2+y^2+z^2)^(5/2))= 1/r^2(Gm₂ m₂ [(2x^2+2y^2+2z^2-3x^2)/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3y^2]/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3z^2]/(x^2+y^2+z^2)^(3/2)])= 1/r^2(Gm₂ m₂ [x^2+y^2+z^2]/(x^2+y^2+z^2)^(3/2))= 0.

Curl of F = ∇ × F= i(d/dy(Fz) - d/dz(Fy)) - j(d/dx(Fz) - d/dz(Fx)) + k(d/dx(Fy) - d/dy(Fx))= i(d/dy(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ y/(x^2+y^2+z^2))) - j(d/dx(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ x/(x^2+y^2+z^2))) + k(d/dx(Gm₂ m₂ y/(x^2+y^2+z^2)) - d/dy(Gm₂ m₂ x/(x^2+y^2+z^2)))= i(Gm₂ m₂ [-2xz]/(x^2+y^2+z^2)^(5/2)) - j(Gm₂ m₂ [-2yz]/(x^2+y^2+z^2)^(5/2)) + k(Gm₂ m₂ [(x^2+y^2-2z^2)]/(x^2+y^2+z^2)^(5/2))

b) Calculation:The line integral of F along a curve C can be evaluated by the following formula∫C F.dr = ∫∫ ( ∇ x F) ds, Where r is the position vector of the curve, s is the scalar parameter representing the curve, and the integral is evaluated from the initial point to the final point.

Using the curl of F obtained in part a) and for the surface with ∂S as C∫C F.dr = ∫∫ ( ∇ x F) ds= ∫∫ curl(F) ds= ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds...[1]

Let's consider the surface S as a plane perpendicular to the z-axis of the form ax+by+c=0 and the curve C as the intersection of the plane and the cylinder x^2 + y^2 = a^2.

Let's choose the unit normal to the surface S as k (along the z-axis).

The curl of F is a vector field perpendicular to the plane and along the direction of k.

Thus the integral can be written as∫C F.dr = ∫∫ ( ∇ x F) . k ds= ∫∫ (x^2+y^2-2z^2) ds...[2]

Now let's evaluate the integral over the given plane ax+by+c=0. We can write x = t, y = (c-at)/b and z = 0, where t is the scalar parameter along the line of intersection of the plane and the cylinder (x^2 + y^2 = a^2).

Since the curve C is on the cylinder of radius a, we have x^2+y^2 = a^2 ⇒ t^2+(c-at)^2/b^2 = a^2On solving for t, we have t = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2].

Substituting t in x and y, we get the curve C in the x-y plane as a function of the scalar parameter s asx = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2]y = (c-at)/b= (c-(bc±ab √(a^2-b^2-c^2))/[a^2+b^2])/b.

Now we can evaluate the integral over the curve C, which is along the intersection of the plane and the cylinder.

Integral over C (x^2+y^2-2z^2) ds= ∫t₁^t₂ [(t^2 + [(c-at)^2]/b^2 - 2(0)^2)^(1/2)] dt= ∫t₁^t₂ [(a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2]^(1/2) dt.

Now we can choose the value of t₁ and t₂ such that the square root in the integrand is minimized (so that the integral is path-independent).

This can be done by choosing the value of t that gives the minimum value of (a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2 over the range of t from t₁ to t₂.

On differentiation with respect to t and equating to 0, we get the value of t = bc/(a^2+b^2).

Substituting this value of t in the integrand, we get the minimum value of the square root in the integrand to be |c| √(a^2+b^2)/|b|.

Thus the integral over C is given by∫C F.dr = ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds= ∫∫ (x^2+y^2-2z^2) ds= ∫t₁^t₂ |c| √(a^2+b^2)/|b| dt= |c| √(a^2+b^2)/|b| (t₂-t₁).

Now we can see that the integral is path-independent as it depends only on the end points t₁ and t₂ and not on the path taken to reach them.

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A crane moves a 250 kg scoreboard from the ground to the height of 100 m. What is the work done on the scoreboard?

Answers

If you’re doing potential and kinetic energy then the answer is potential.

Answer:

You will have to do the last PE - the initial PE

Explanation:

6. What is the mass of an object that requires a force of 30 N to accelerate at 5 m/s??

Answers

According to the Newton's second law,

\(F=ma\)

where F is the force on the object, m is the mass of the obect and a is the acceleration of the object.

Substituting the known values,

\(30=m\times5\)

Thus, the mass of the object is,

\(\begin{gathered} m=\frac{30}{5} \\ m=6\text{ kg} \end{gathered}\)

Hence, the mass of the object is 6 kg.

How long does it take for jupiter to rotate on its axis.

Answers

Answer:

10 hours.

Every 10 hours, Jupiter will rotate at least once. It takes 12 years for Jupiter to make a revolution. This is because Jupiter is a gas, non-solid planet and also has a very large mass.

Answer: 10 Hours

Explanation:

Jupiter is the fastest spinning planet in the solar system

a person jogs eight complete laps around a 400-m track in a total time of 15.1 min .calculate the average speed, in m/s .

Answers

The average speed in m/s of a person that jogs eight complete laps around a 400m track in a total time of 15.1 min is 0.44m/s.

How to calculate average speed?

Average speed of a moving body can be calculated by dividing the distance moved by the time taken.

Average speed = Distance ÷ time

According to this question, a person jogs eight complete laps around a 400m track in a total time of 15.1 min. The average speed is calculated as follows:

15.1 minutes in seconds is as follows = 906 seconds

Average speed = 400m ÷ 906s

Average speed = 0.44m/s

Therefore, the average speed in m/s of a person that jogs eight complete laps around a 400m track in a total time of 15.1 min is 0.44m/s.

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A stone is thrown upwards from the edge of a cliff with a speed of 5.0 ms. It hits the
ground 2.0 s later. What is the height of the cliff?

If you can provide some explanation I will greatly appreciate it.

Answers

Answer:

3.0 would be it

Explanation:

Because if you think bout it the 5.0 negative 2.0 is 3.0

What is the ground-state energy of a proton if each is trapped in a one-dimensional infinite potential well that is 200 pm wide?

Answers

The ground-state energy of a proton trapped in a one-dimensional infinite potential well that is 200 pm wide is approximately \(6.84 x 10^-14 J.\)

"How to calculate proton's ground-state energy?"

The energy levels of a particle trapped in a one-dimensional infinite potential well are given by the formula:

\(E_n = (n^2 * h^2)/(8mL^2)\)

where E_n is the energy of the nth energy level, n is a positive integer, h is Planck's constant, m is the mass of the particle, and L is the width of the well.

For a proton, the mass is approximately \(1.67 x 10^-27 kg.\) The width of the well is given as 200 pm, which is \(2 x 10^-10 meters\). Plugging these values into the equation, we get:

\(E_1 = (1^2 * h^2)/(8mL^2)\)

= \((1^2 * 6.626 x 10^-34 J s)^2 / (8 * 1.67 x 10^-27 kg * (2 x 10^-10 m)^2)= 6.84 x 10^-14 J\)

Therefore, the ground-state energy of a proton trapped in a one-dimensional infinite potential well that is 200 pm wide is approximately \(6.84 x 10^-14 J.\)

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What type of device is a refrigerator?
A. A heat pump that uses work to move heat
B. A heat pump that uses heat to do work
C. A heat engine that uses work to move heat
D. A heat engine that uses heat to do work

Answers

A heat pump that uses work to move heat

Why do you measure the disappearance of reactant and not the appearance of product in this experiment?.

Answers

The disappearance of the reactant and not the appearance of the product in this experiment is flipping the sign-on rates for reactants.

The reaction rate is a measure of the change in concentration of the disappearance of a reactant or the change in concentration of the appearance of a product per unit of time. The vanishing rate value is always negative because the reactant concentration is consumed in the reaction. The product is formed in a reaction, so the rate of occurrence value is always positive.

The rate of reaction is defined as the rate of disappearance of reactants and the rate of appearance of products, and the rate constant is the constant of proportionality between reaction rate and concentration conditions. The rate of a chemical reaction can be measured as the rate of appearance of one of the products or the rate of disappearance of one of the reactants. If the reactant concentration decreases, use the negative sign to represent the rate of reaction for the reactant.

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What is a wiggle in time called? What do you call a wiggle in space and time?

Answers

Answer: a periodic wiggle in time is called a vibration, while a wiggle in space and time is a wave. ... The source of all waves, whether mechanical or electromagnetic, is something that is vibrating.

Explanation:

(4.81•10^3)+(7.913•10^5)
in scientific notation

Answers

Answer:

796110

Explanation:

(4.81)(1000)+7.913(105)

=4810+7.913(105)

=4810+(7.913)(100000)

=4810+791300

=796110

Anwser:hehehrbdjwjhsbs

Explantion:

Find the displacement the body in the following graph​

Find the displacement the body in the following graph

Answers

Answer:

150

Explanation:

15m/s×10s= 15m/a

and that is the correct answer

a flatbed truck is carrying a heavy crate. the coefficient of static friction between the crate and the bed of the truck is 0.75. what is the maximum rate at which the driver can accelerate and still avoid having the crate slide across the bed of the truck?

Answers

A flatbed truck is carrying a heavy crate. the coefficient of static friction between the crate and the bed of the truck is 0.75. The maximum rate at which the driver can accelerate and still avoid having the crate slide across the bed of the truck will be 7.35 \(m/s^{2}\)

Static friction force = mu * N

mu = coefficient of static friction

N = normal

m = mass

g = acceleration due to gravity  

Static friction force = 0.75 * m * g = 7.35 * m  N

7.35 * m  Newton  is the maximum force , above which the crate will start to move

Force = mass * acceleration

7.35 * m = m * a

a = 7.35 \(m/s^{2}\)

The maximum rate at which the driver can accelerate and still avoid having the crate slide across the bed of the truck will be 7.35 \(m/s^{2}\)

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fill in the blank. once we leave for mars we won’t be able to come back for over ___________ amount of time because of the alignment of the planets.

Answers

once we leave for mars we won’t be able to come back for over 6 to 18 months amount of time because of the alignment of the planets.This is because the planets Earth and Mars are not always in the same position relative to each other. When the planets are aligned, it takes less time for a spacecraft to travel between them. However, when the planets are not aligned, it takes much longer for a spacecraft to travel between them.

The alignment of the planets is important for space travel because it affects the amount of fuel that is needed to travel between planets. When the planets are aligned, the spacecraft can take advantage of the gravitational pull of the planets to help it travel. However, when the planets are not aligned, the spacecraft must use more fuel to travel between planets.

The alignment of the planets also affects the amount of time it takes for a spacecraft to travel between planets. When the planets are aligned, it takes less time for a spacecraft to travel between them. However, when the planets are not aligned, it takes much longer for a spacecraft to travel between them.

The alignment of the planets is an important factor to consider when planning a space mission. By taking into account the alignment of the planets, space agencies can save money and time on their missions.

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a car is moving 18m/s to the east. if it takes the car 5 seconds to reach a velocity of 19 m/s to the east, what is its acceleration?

Answers

Kinematics

First Velocity (Vf) = 18 m/s

Last Velocity (Vl) = 19 m/s

time (t) = 5 seconds

acceleration = ______?

Answer :

Vl = Vf + a × t

19 = 18 + a × 5

19 - 18 = 5a

1 = 5a

1 / 5 = a

0,2 m/ = a

Answer: 0.2 m/s^2 east

Explanation:

A PE X

The energy transferred to the water in 100 seconds was 155 000 J. specific heat capacity of water = 4200 J/kg °C
Determine the mass of water in the kettle.
Use Figure 10.
Give your answer to 2 significant figures.
Any help would be appreciated

The energy transferred to the water in 100 seconds was 155 000 J. specific heat capacity of water = 4200

Answers

Answer:

0.37 kg

Explanation:

I'm not a professor myself, but this is how I worked it out:

using the graph, after 100 seconds, the temperature is 100 degrees Celsius.

If we now substitute everything into the specific heat capacity equation, making the mass "m", we would come up with:

4200 = 155000/(m x 100)

If we rearrange and solve for m, we get 0.37 kg.

I'm not sure if I have done this correctly, feel free to correct me.

Hope this helps!

By using the specific heat capacity formula, the  mass of water in the kettle is 0.47 kg

Give that the energy transferred to the water in 100 seconds was 155 000 J and the specific heat capacity of water = 4200 J/kg °C

From the graph;

The initial temperature of the water at time zero is 22 degree Celsius

The final temperature of the water at time 100s is 100 degree Celsius

Change in temperature (T) = 100 - 22 = 78 degree Celsius

To determine the mass of water in the kettle, use the heat energy formula below

E = mcT

Substitute all the parameters into the equation

155000 = 4200 x 78 M

Make M the subject of the formula

M = 155000/327600

M = 0.47 kg

Therefore, the  mass of water in the kettle is 0.47 kg

Learn more here: https://brainly.com/question/15475909

What happens to the density of an object if the mass increases, but the volume remains the same?

Answers

A measure of mass per unit of volume. It is how much material a certain volume contains. ... If the volume of the object stays the same but the mass of the object increases then its density becomes greater.

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