A stockroom worker pushes a box with a mass of 11.2 kg on a horizontal surface with a constant speed of 3.5 m/s. The coefficient of kinetic friction between the box and the surface is 0.20. a) What horizontal force must be applied by the worker to maintain the motion? b) If the force calculated in part (a) is removed, how far does the box slide before coming to rest?

Answer:

The three forms of water are gas, liquid, and ice, I'm not sure if these were mentioned in the passage since you did not attach a picture.

Please mark this the Brainliest.

Answer:

False

Explanation:

Vertical component = 250 sin30

250×1/2=125N

21-centimeter radiation provides information about the velocity, density, temperature, magnetic fields, and cosmic evolution of the gas cloud that emitted it.

21-centimeter radiation, or the 21-cm line, emitted by neutral hydrogen atoms, offers valuable insights about the gas cloud that emitted it.

By analyzing the Doppler shift, astronomers can determine the cloud's velocity and motion. The intensity of the 21-cm line provides information about the cloud's density and distribution, while the line width indicates its temperature.

Additionally, the polarization of the line reveals the presence and strength of magnetic fields within the cloud. Overall, studying the 21-cm radiation helps understand the structure, dynamics, and cosmic evolution of the gas cloud.

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The system's momentum and total kinetic energy are different before and after the collision depending on the location of the impact.This henceforth indicates that a net external force is exerted on the system.

In a closed system where no external forces act, the total momentum and total kinetic energy of the system are conserved. This is known as the conservation of momentum and the conservation of energy, respectively.

If external forces act on the system, then the total momentum and total kinetic energy of the system are not conserved. In this case, the net external force can be calculated by the change in momentum over time using Newton's second law, F = Δp/Δt.

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Answer:

"caffeine"    both products contain this compound

Yes, if the net force and the net torque on a moving object are both zero, the object can be in static equilibrium. Static equilibrium refers to a state where an object is at rest and not experiencing any acceleration.

The net force acting on the object must be zero. This means that the vector sum of all the forces acting on the object, including external forces and internal forces, must add up to zero. If the net force is zero, the object will not accelerate and will remain at rest or move with a constant velocity.

The net torque acting on the object must be zero. Torque is the rotational equivalent of force, and it depends on the force applied and the distance from the pivot point. Therefore, if both the net force and the net torque on a moving object are zero, it can be in static equilibrium, either at rest or moving with a constant velocity.

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Work is equal to energy. Since your braking distance is 10.8 m. you will not stop before you hit the oil spill

Energy is the ability to do work. The work done on an object is tantamount to energy used on the object.

If you are first place in Mario Kart at the moment. Your 5.0 kg Mario Kart is moving at 5.5 m/s when you see an oil spill 10 m ahead. If your maximum braking force is 7.0 N, will you stop before you hit the oil spill? What is your braking distance?

By using the concepts of work and energy, that is,

1/2mv² = F × s

Where

Substitute all the parameters into the formula

1/2 × 5 × 5.5² = 7 × s

75.625 = 7s

s = 75.625/7

s = 10.8 m

Since the calculated distance is greater than the given distance (10 m), you will not stop before you hit the oil spill. And your braking distance will be 10.8 m

Therefore,  you will not stop before you hit the oil spill.

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The eigenfunction property of Linear Time-Invariant (LTI) systems is closely related to the Laplace and Fourier transforms.

The eigenfunction property states that the input-output relationship of an LTI system can be represented by multiplication with a complex exponential function. This means that if the input to an LTI system is a complex exponential function, the output will also be a scaled and delayed complex exponential function.

The Laplace and Fourier transforms are mathematical tools used to analyze LTI systems. The Laplace transform is particularly useful for analyzing continuous-time LTI systems, while the Fourier transform is used for analyzing discrete-time or periodic LTI systems.

The eigenfunction property of LTI systems is directly related to the use of complex exponentials in the Laplace and Fourier transforms. Complex exponentials are eigenfunctions of LTI systems, meaning that they retain their form (up to scaling and delay) after passing through the system.

By expressing the input and output signals of an LTI system in terms of complex exponentials, the Laplace or Fourier transforms can be used to characterize the system's frequency response, impulse response, and stability properties. This connection between eigenfunctions, Laplace transforms, and Fourier transforms allows for efficient analysis and understanding of LTI systems in the frequency domain.

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Answer:

The correct answer would be Saturn's Cassini Division.

Explanation:

Read about it here.

https://caps.gsfc.nasa.gov/simpson/kingswood/rings/

Hope this helps! :)

If the final potential difference across the 69micro -f then capacitor is 40Mf

We cannot expect simple energy conservation to hold because energy is presumably dissipated as heat in the connection wires or as radio waves while the charge oscillates during the system "settling down" to its final state (40V across the parallel pair of capacitors C and 60 F).

We anticipate that charge will be conserved. Thus, if Q is the initial charge stored on C and q 1 and q2 are the charges on the parallel pair after "settling down," then -

Q= q1+ q2

C(100V) = C(40V) + 60mf(40V)

C= 40Mf

An electrical component that stores electrical energy in an electric field is known as a capacitor. It is made up of two conductive plates separated by a nonconductive material known as a dielectric.

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To find the electric potential energy of a 4.0-μC charge at a point with an electric potential of 20 V, you can use the following formula:

Electric Potential Energy (EPE) = Charge (Q) × Electric Potential (V)

In this case, Q = 4.0 μC and V = 20 V.

Remember to convert the charge to coulombs by multiplying by \(10^-6\):

Q = 4.0 ×\(10^-6\)

Now, plug in the values:

EPE = (4.0 × 1\(10^-6\) C) × (20 V)

EPE = 8 ×\(10^-5\) J (joules)

So, the electric potential energy of the 4.0-μC charge at that point is 8 × \(10^-5\) joules.

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Answer:

A planet can have a surface made of either liquid or gas.

Hope it helped brainiest plz and thank you.

Explanation:

Which of the following is an example of a difference between planets in the solar system?

"A planet can have a surface made of either liquid or gas."

that's the answer:A planet can have a surface made of either liquid or gas.

Answer:

A i know its correct please give brainliest  and does anydoby here play sky: children of light

Explanation:

Answer:

b

Explanation:

it is the only one that has to do with animals

Answer:

The answer is B

Explanation:

Answer:

1) Use multiple instruments to measure

2) Take several measurements

3) Control the other variables delicately  

4) Be meticulous when measuring

The mass of an electron is 9.1 x 10⁻³¹ kg. The mas of a proton is 1.7 x 10⁻²⁷ kg. An electron and a proton are about 0.59 x 10⁻¹⁰ m apart in a hydrogen atom. then  gravitational force exists between the proton and the electron of a hydrogen atom is 2.96 × 10⁻⁴⁷ N.

Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,

F ∝ m₁.m₂

F ∝ 1/r²

F = G m₁,m₂÷r²

where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².

Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].

This is analogous with coulomb's law which gives force between two charges.

Given,

m(e) = 9.1 x 10⁻³¹ kg

m(p) = 1.7 x 10⁻²⁷ kg

r =  0.59 x 10⁻¹⁰ m

putting all the values in equation,

F = G m₁,m₂÷r²

F = 6.6743 × 10⁻¹¹ × 9.1 x 10⁻³¹  ×  1.7 x 10⁻²⁷ ÷ (0.59 x 10⁻¹⁰ m)²

F = 2.96 × 10⁻⁴⁷ N

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The length of the SLAC accelerator as measured in the reference frame of the electrons is 3,2 km. Here's an explanation of the SLAC accelerator and its length.

The SLAC accelerator is a linear particle accelerator located in Menlo Park, California. It was created in 1962 by the Stanford Linear Accelerator Center (SLAC), which is now known as the SLAC National Accelerator Laboratory. The SLAC accelerator is a 3.2 km-long linear accelerator that uses microwaves to accelerate electrons to extremely high speeds.

The length of the SLAC accelerator as measured in the reference frame of the electrons is 3,2 km because the electrons are moving very quickly relative to the laboratory reference frame, causing them to contract in length. This phenomenon is known as length contraction and is a consequence of Einstein's theory of special relativity.

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Answer:

The suction pressure decreases and the superheat increases when the liquid line is restricted and the supply of refrigerant to the metering device is reduced.

Explanation:

1. The five components of refrigeration are:

       The compressor limits the vapor released by the refrigerant. This            

       causes a rise in pressure (in refrigerant), which then pushes the  

       vapor into the coils on the outside of the refrigerator.

2. Now when the cooler air meets the warm gas present in the coils, it

   gets converted into liquid form.

3. Thus, when the liquid form is at high pressure, the refrigerant then  

   cools down as it flows through the coils placed in the fridge ( in both

   freezing and normal sections).

4. The refrigerant also absorbs the warm air present in the fridge, which  

   causes it to evaporate and flow back through the compressor and the

   cycle repeats in the same form.

Thus, when the liquid line is restricted and the supply of refrigerant to the metering device is reduced it causes a decrease in suction pressure and an increase in superheat.

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Answer:

vf = 32ms

Explanation:

v  =  u  +  a t ,

v  =  0  +  8.0  x  4.0  

v  =  32 ,

v  =  32 m /s  

Hope it Helps! :D  

The rise segment will start at 0° and end at 100°, the constant segment will continue from 100° to 145°, and the drop segment will span from 145° to 265° for the given Cam design.

1. Rise Segment:

The cam needs to rise 2 cm for the first 100° of rotation. We will assume a linear rise for simplicity. Given that the base radius is 10 cm, the rise can be achieved by offsetting the cam profile by 2 cm at the maximum lift point.

2. Constant Segment:

The cam needs to maintain a constant height for the next 45° of rotation. To achieve this, the cam profile should remain at the same height as the maximum lift point.

3. Drop Segment:

The cam needs to drop 2 cm for the next 120° of rotation. Similar to the rise segment, we will assume a linear drop for simplicity. The cam profile should be offset by 2 cm in the opposite direction from the maximum lift point.

Considering the given radius of the follower (0.5 cm), the actual profile of the cam will be the sum of the base radius (10 cm) and the offset values calculated for each segment.

To illustrate the design, we can plot the cam profile on a graph with the x-axis representing the angle of rotation and the y-axis representing the height of the cam profile. The rise segment will start at 0° and end at 100°, the constant segment will continue from 100° to 145°, and the drop segment will span from 145° to 265°.

Here is a rough representation of the cam profile:

            ___

         __/ \__

      __/       \__

   __/             \__

___/                 \___

         |---|---|---|

    0° 100° 145° 265°

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The kinetic energy of the diver just before he hits the ground is 6860 J.

Kinetic energy can be defined as the energy of a body due to its motion.

Note: Just before the diver hits the ground, the potential energy is converted into kinetic energy.

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The kinetic energy of the diver just before he hits the ground is 6860 J.

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Answer:

Approximately \(1.1 \times 10^{4}\; {\rm Pa}\) and \(8.0 \times 10^{3}\; {\rm Pa}\), respectively (assuming that \(g = 9.81\; {\rm N \cdot kg^{-1}}\).)

The \(55.5\; {\rm kg}\) box exerts more pressure than the \(65.5\; {\rm kg}\) box.

Explanation:

Let \(m\) denote the mass of the \(55.5\; {\rm kg}\) box.

The weight of that box would be: \(W = m\, g\).

The normal force \(N\) that this box exerts on the ground would be the same as its weight: \(N = W = m\, g\).

If the contact area between the box and the ground is \(A\), the pressure \(P\) that this box exerts on the ground would be \(N / A\). That is:

\(\displaystyle P = \frac{N}{A}= \frac{m\, g}{A}\).

The contact area between the ground and this \(55.5\; {\rm kg}\) box is \(A = 0.25\; {\rm m} \times 0.20\; {\rm m}\). Substitute in these values and evaluate to find the pressure:

\(\begin{aligned} P &= \frac{N}{A} \\ &= \frac{m\, g}{A} \\ &= \frac{55.5\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}}}{0.25\; {\rm m} \times 0.20\; {\rm m}} \\ & \approx 1.1 \times 10^{4}\; {\rm Pa}\end{aligned}\).

Similarly, for the \(65.5\; {\rm kg}\) box:

\(\begin{aligned} P &= \frac{N}{A} \\ &= \frac{m\, g}{A} \\ &= \frac{65.5\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}}}{0.20\; {\rm m} \times 0.40\; {\rm m}} \\ & \approx 8.0 \times 10^{3}\; {\rm Pa}\end{aligned}\).

Thus, the \(55.5\; {\rm kg}\) box exerts greater pressure on the ground than the \(65.5\; {\rm kg}\) box.

Answer:

Explanation:

Given the following data;

Mass = 2kg

Energy = 50J

Height = 10m

To find the speed

Kinetic energy can be defined as the energy possessed by a body due to its motion.

K.E = ½mv²

Substituting into the equation, we have;

50 = ½*2*v²

V² = 50

Taking the square root of both sides, we have;

V = 7.07m/s

Answer:

Density= 2.78 g/cm³

Relative density=2.8

Explanation:

To calculate the density of the cube we have to use the formula ρ=mass/volume

ρ stands for density.

So now we don't have the volume of the cube and to find the volume of the cube we have to use the formula a³

3³= 9 cm³

Now plug in the values. ρ= 25 g/9 cm³

ρ= 2.78 g/cm³

To find the relative density, we have to use the formula ρsample/ρH20

The sample means the density of the substance earlier. We do not know the density of water but it is constant at 997 kg/m³.

Now we have to make the units same so you change the unit of the density of cube to kg/m³

So, 25/1000= 0.025 kg

9/100×100×100 (because cm³ which means that there should be 3 meters to change the unit and to conver cm to meter we need to divide by 100 so 9cm/100, 9cm²/100×100, 9cm³/100×100×100)

=0.000009 m³

The new density= 0.025 kg/ 0.000009 m³

= 2777.78 kg/m³

Now plug the values into the formula:

relative density= 2.777.78 kg/m³ / 997 kg/m³

=2.8

There is no unit since kg/m³ and kg/m³ cancels

The object travels a distance of =54m If starts with initial velocity of 12m/s.

Velocity is the high indicator of the position in addition to the rapidity of the object. it is able to be defined as the distance blanketed by means of an object in unit time. velocity can be described because the displacement of the item in unit time. Pace is the time price at which an object is transferring along a path, whilst speed is the rate and direction of an object's motion.

Velocity is a vector expression of the displacement that an object or particle undergoes with appreciate to time. velocity is defined as a vector size of the price and route of motion. put really, velocity is the velocity at which some thing moves in one path. the speed of a car traveling north on a primary parkway and the velocity a rocket launching into space can both be measured the usage of velocity.

Given,

   Acceleration =  4 m/s^2

 Time = 3 second

S = u t +1/2at²

s=12*3+0.5*4*3*3

=36+18

=54m                          answer

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Answer:

the study of earthquake waves

Explanation:

Since acceleration is uniform, if the velocity at point B is v, then

\(v^2 - \left(20\dfrac{\rm m}{\rm s}\right)^2 = 2\left(3\dfrac{\rm m}{\mathrm s^2}\right)(120\,\mathrm m)\)

Solve for v :

\(v^2 = \left(20\dfrac{\rm m}{\rm s}\right)^2 + 2\left(3\dfrac{\rm m}{\mathrm s^2}\right)(120\,\mathrm m) \\\\ v = \sqrt{\left(20\dfrac{\rm m}{\rm s}\right)^2 + 2\left(3\dfrac{\rm m}{\mathrm s^2}\right)(120\,\mathrm m)} \\\\ \boxed{v \approx 34 \dfrac{\rm m}{\rm s}}\)

Analytical maps can be created to depict historical ownership, paved areas for cars, parks, natural amenities, and community street design. Streets, being public spaces, require measurement to determine their intended beneficiaries.

Analytical maps offer a valuable tool for visualizing and understanding various aspects of urban planning. By creating maps that showcase historical ownership patterns, paved areas designated for cars, locations of parks and natural amenities, and community street design, it becomes easier to assess the distribution of resources and infrastructure within a city.

In this context, streets hold a significant role as public spaces. They are not solely meant for vehicular traffic but should also prioritize the needs and activities of pedestrians, cyclists, and the wider community. Analyzing street design through mapping can help evaluate whether streets are primarily designed to cater to cars or if they accommodate a balanced and inclusive approach that considers the needs of all users.

To achieve equitable urban environments, it is crucial to assess the intended beneficiaries of street design and identify any discrepancies or biases in the allocation of public space. By utilizing analytical maps, planners, policymakers, and communities can have a clearer understanding of the current state of street design and work towards creating more people-centric and sustainable cities.

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Answer:(d) mass

Explanation: The kilogram is the standard mass unit that is used almost globally and is the SI unit of mass. The kilogram weighs 9.8 Newtons under normal conditions on the surface of the Earth, and Newton is the corresponding SI unit of force and weight.