a steam power plant with a power output of 150 mw consumes coal at a rate of 60 tons/h. if the heating value of the coal is 30,000 kj/k

A graeco-latin square experiment was conducted to compare the effects of five different assembly methods (a, b, c, d, and e) on the throughput, using three blocking variables.

In experimental design, a graeco-latin square is a systematic and efficient method used to reduce confounding factors and obtain reliable results. It involves the arrangement of treatments in a square matrix where each treatment appears once in each row and column. In this case, the five assembly methods (a, b, c, d, and e) are compared in terms of their effects on the throughput, which is the measure of the rate of production or completion.

By incorporating three blocking variables, the experiment ensures that the effects of potential confounding factors are controlled. Blocking variables are factors that may influence the response variable but are not the primary focus of the study. By including them, the experiment can account for their effects and improve the accuracy of the results.

The graeco-latin square design allows for a balanced and structured comparison of the assembly methods, reducing bias and providing a clear understanding of their impact on throughput. This design is particularly useful when multiple factors need to be evaluated simultaneously.

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Yes, 9.81 is the acceleration of gravity on the Earth's surface.

The acceleration of gravity is the rate at which an object falls towards the center of the Earth, or the force that pulls objects towards the center of the Earth.

The acceleration of gravity is denoted by the symbol g and its standard value on Earth is 9.81 meters per second squared (m/s^2).

This value is commonly used in physics calculations involving gravity, such as calculating the weight of an object or the velocity of a falling object.

It's worth noting that the acceleration of gravity is not constant everywhere on the earth, it varies with the latitude and altitude.

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Answer:

The ball takes \($t=1 \cdot 917sec$\) to hit the ground.

Explanation:

• The second equation of motion represents the total distances travelled by an object in a time interval of \($\Delta t$\) with an initial speed of \($u$\) and acceleration \($a$\).

• To find the time, ball takes to hit the ground, use the formula: \($$s = ut + \frac{1}{2}a{t^2}$$\)

Where, \($t$\) is time, \($u$\) is initial velocity, \($a$\) is acceleration and\($s$\) is displacement.

• In this case, \($a = g = 9 \cdot 8m/se{c^2}$\).

• Placing the value of the given initial velocity, \($u=0cm/s$\) and displacement,\($s = 13m$\) in the above formula.

\(& \therefore s = ut + \frac{1}{2}g{t^2} \\& \Rightarrow 13 = 0 \cdot t + \frac{1}{2} \times 9 \cdot 8 \times {t^2} \\\)

\(& \Rightarrow 13 = 4 \cdot 9{t^2} \\& \Rightarrow {t^2} = \frac{{13}}{{4.9}} \\& \Rightarrow t = 1 \cdot 917sec \\\end{align}\]\)

• Hence, ball takes \($t=1 \cdot 917sec$\) to hit the ground.

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Answer:

The projectile's horizontal speed is constant throughout the entire trajectory because gravity only acts downwards in the vertical direction.

Explanation:

I did this in Physics a while ago but I believe my answer is correct.

Hope this helps! (:

ANSWERS:

A. 38.3 m/s
B. Yes. 38.3 m/s is a very high speed and could potentially cause serious injury or death
C. 656.1 m
D. Not very realistic. The resisting force depends on the speed of the skydiver.

EXPLANATIONS:

(A) To solve for the speed of the skydiver when he lands on the ground, we can use conservation of energy. The initial potential energy of the skydiver is equal to the final kinetic energy plus the final potential energy.

Initial potential energy = mgh1 = 80.0 kg x 9.8 m/s^2 x 1000 m = 784000 J

Final potential energy = mgh2 = 80.0 kg x 9.8 m/s^2 x 200.0 m = 156800 J

With the parachute closed, the total resisting force is 50.0 N, so we can use the work-energy principle to find the final kinetic energy:

Work done by resisting force = Fd = 50.0 N x (1000 m - 200 m) = 40000 J

Final kinetic energy = Initial potential energy - Work done by resisting force - Final potential energy

Final kinetic energy = 784000 J - 40000 J - 156800 J = 587200 J

Finally, we can solve for the speed using the equation for kinetic energy:

Final kinetic energy = (1/2)mv^2

587200 J = (1/2)(80.0 kg)v^2

v = sqrt(1468 m^2/s^2) = 38.3 m/s

Therefore, the speed of the skydiver when he lands on the ground is 38.3 m/s.

(B) It's difficult to say whether the skydiver will get hurt based solely on the speed of impact. However, 38.3 m/s is a very high speed and could potentially cause serious injury or death. Other factors, such as the angle of impact and the condition of the ground, would also affect the outcome.

(C) We can use the same conservation of energy equation as in part (A), but solve for the height at which the parachute should be opened to achieve a final speed of 5.00 m/s.

Initial potential energy = mgh1 = 80.0 kg x 9.8 m/s^2 x h1

Final potential energy = mgh2 = 80.0 kg x 9.8 m/s^2 x 0

With the parachute open, the total resisting force is 3600 N, so we can use the work-energy principle to find the work done by the resisting force:

Work done by resisting force = Fd = 3600 N x (h1 - 0) = 3600h1 J

Then we can solve for the height using the equation:

Initial potential energy - Work done by resisting force = Final kinetic energy + Final potential energy

mgh1 - 3600h1 = (1/2)mv^2 + 0

Simplifying and solving for h1:

h1 = (v^2)/(2g) + 3600/g = (5.00 m/s)^2 / (2 x 9.8 m/s^2) + 3600/9.8 = 656.1 m

Therefore, the parachute should be opened at a height of 656.1 m to achieve a final speed of 5.00 m/s.

(D) The assumption that the total resisting force is constant is not very realistic because the resisting force depends on the speed of the skydiver. As the skydiver falls faster, the resisting force will increase due to air resistance. Therefore, the actual speed of the skydiver with the parachute closed and the actual speed with the parachute open would not be constant.

The time of motion of the satellite is 1.65 hours. The speed of the satellite from the centre of the Earth is 26,945.35 km/h.

This is the motion of an object in which the object travels in a straight line and its velocity remains constant along that line as it covers equal distances in equal intervals of time, regardless of time duration.

The time of motion of the satellite in hours is calculated as follows;

t = ( 99 min / 1 ) x ( 1 hour / 60 min )

t = 1.65 hours

The speed of the satellite from the centre of the Earth in km/h is calculated as follows;

v = ( 2πr ) / ( t )

where;

r is the distance of the satellite from the centre of the Earth

The position of the satellite above the surface of the Earth = 705 km

The radius of Earth = 6,371 km

The total distance of the satellite from the centre of the Earth = 705 km + 6,371 km = 7,076 km

v = ( 2π x 7076 ) / ( 1.65 )

v = 26,945.35 km/h

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The complete question is attached with the answer below.

The efficiency of an engine is 0.457  and the work done in each cycle is 827 J and the mechanical power is 5.2×10³ W.

The efficiency of a heat engine is calculated between the heat and cold reservoir.

Efficiency,η = 1 - (T(cold) / T(hot))

T(hot) = 1809 J

T(cold) =  982 J

η = 1 - (982 J /1809 J)

  = (1809 -982) / 1809

  = 0.457

The efficiency of the engine,η = 0.457

The work done, W = (T(hot) - T(cold))

W = 1809 - 982

   = 827 J

The work done on the engine, W = 827 J.

The mechanical power, P = Work / time

P = 827 / 0.159

  = 5.201×10³W

The power of the heat engine, P = 5.201kW.

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Centripetal force on the end of a 66.0 m (radius) wind turbine blade that is rotating is calculated as = 1.23 *10^-4 N.

Centripetal force is the force acting on the object in curvilinear motion directed towards axis of rotation or the center of curvature and the unit of centripetal force is newton. It is directed perpendicular to the direction of the displacement of the object.

Given, radius= 66m mass is 3.4 kg

Given 0.47 rev/s

Angular velocity = 0.47 * 2π / 60

= 0.049 m/s

Centripetal force = mass * velocity²/radius

= 3.4 *  0.049² /66

Centripetal force= 1.23 *10^-4 N

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The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

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Answer:

Electromagnetism causes like-charged objects to repel each other and oppositely charged objects to attract each other. The electromagnetic force binds negative electrons to the positive nuclei in atoms and underlies the interactions between atoms.

The capacitor is the energy storage device in the form of electrical energy and the capacitance is the ratio of charge and potential difference between capacitors.

The capacitance in the parallel plate capacitor is directly proportional to the area of the conductor and inversely proportional to the distance between the capacitors. The unit of capacitance is Farad(F).

1) Capacitance of the parallel plate capacitor is directly proportional to the area of the conductors and hence Area increases, the capacitance also increases.

2) Capacitance is inversely proportional to the distance between the capacitors and hence distance between the capacitors increases, Capacitance decreases.

3)  C = ε₀A/d, where A is the area of the capacitor and d is the distance between the capacitor, and C is the capacitance of the capacitor. The capacitance of the parallel plate capacitor is directly proportional to the area of the parallel plate capacitor and d is the distance of separation of plates.

4) If two identical capacitors are connected in parallel, the potential across the capacitors are same and the charge in the capacitors is different.

5) If the system has two capacitors connected in parallel, the charges remain unchanged and hence the net charge is equal to the individual charges of the capacitors. The net charge of the system is, Q = Q₁+Q₂. Q₁=C₁V and Q₂=C₂V, Q = V(C₁+C₂).

6) The device used to measure the decay of voltage in an RC circuit is the voltmeter. Voltmeter is a device used to measure the potential difference between two points.

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Answer:

Explanation:

The kinetic energy of a body can be found by using the formula

where

m is the mass

v is the velocity

From the question

mass = 5 kg

velocity = 4 m/s

Substitute the values into the above formula and solve

We have

We have the final answer as

Hope this helps you

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The Earth has an atmosphere, while the Moon does not, primarily due to differences in their sizes and the presence of sufficient gravity. Here are the main factors that contribute to this distinction:

Mass and Gravity: The Earth is significantly larger and more massive than the Moon. Its stronger gravitational pull allows it to retain an atmosphere. Gravity holds the gases in the atmosphere close to the Earth's surface, preventing them from escaping into space. The Moon, on the other hand, has much lower gravity, so it is unable to hold onto an atmosphere.

Escape Velocity: Escape velocity is the minimum speed an object needs to reach to escape the gravitational pull of a celestial body. The Earth's escape velocity is about 40,270 km/h (25,020 mph), while the Moon's escape velocity is much lower, around 2,380 km/h (1,480 mph). As a result, the Earth can hold on to lighter gases like nitrogen and oxygen, while the Moon's lower escape velocity allows these gases to escape into space.

Volatile Substances: The Earth has a range of volatile substances, such as water vapor, carbon dioxide, and nitrogen, that can exist as gases at the planet's surface temperature. These substances are released from the Earth's interior through processes like volcanic activity and are sustained in the atmosphere due to its composition and gravity. The Moon lacks significant amounts of such volatile substances, which further limits the formation and retention of an atmosphere.

Magnetic Field: The Earth has a strong magnetic field generated by its molten iron core. This magnetic field helps protect the atmosphere from being stripped away by the solar wind, a stream of charged particles emitted by the Sun. The Moon, however, does not possess a global magnetic field, which makes it more susceptible to the solar wind and further contributes to the lack of a substantial atmosphere.

Overall, the combination of the Earth's size, mass, gravity, presence of volatile substances, and protective magnetic field allows it to maintain an atmosphere, while the Moon's smaller size, lower gravity, absence of volatile substances, and lack of a significant magnetic field result in its lack of a substantial atmosphere.

A source emits monochromatic light of wavelength 549 nm in air. when the light passes through a liquid, its wavelength reduces to 433 nm, the liquid's index of refraction is approximately 1.269.

The index of refraction (n) of a medium can be calculated using the formula

n = λair / λmedium

Where λair is the wavelength of light in air and λmedium is the wavelength of light in the medium.

Given:

λair = 549 nm

λmedium = 433 nm

Substituting these values into the formula, we get

n = 549 nm / 433 nm

Simplifying the calculation

n = 1.269

Therefore, the liquid's index of refraction is approximately 1.269.

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Answer:

D. Mass

hope it helps

Explanation:

Mass is commonly measured with a balance

Answer:

If you mean for exercising  then, The Treadmill. Purists may claim that treadmill running isn't "real" running. ...

The Elliptical Trainer. ...

The Stair-Climber. ...

The Cross-Country Skiing Simulator. are all  machines that help you practice agility

Explanation:

Answer:

12

Explanation:

600/50 is 12 so the answer is twelve

Answer:

You may tip the car over or crash.

Explanation:

Going really fast at high speeds and turn a corner might make the car crash into an object or fall over.

The charge Q inside the box, after applying Gauss's law is ε₀ \(E a^2\).

Since the electric field is uniform and vertically directed, the electric field lines will be parallel to each other, as shown in the figure.

Let's apply Gauss's law to a cube with a length of side x, where x < a. The cube is shown in blue in the figure. The electric flux through the top and bottom faces of the cube are \(E x^2\) and \(2E x^2\), respectively, since the electric field is uniform on each face.

By Gauss's law, the electric flux through any closed surface is equal to the charge enclosed by the surface divided by the permittivity of free space (ε₀). The cube encloses a charge Q, so the electric flux through the cube is Q/ε₀. Therefore, we have:

\(E x^2 + 2E x^2 = Q/ε₀\)

Simplifying, we get:

Q = ε₀\(E a^2\)

Therefore, the charge Q inside the box is ε₀ \(E a^2.\)

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An frictionless hemispherical bowl is being traversed by a particle P. When time t = 0, it moves past point A. The horizontal component of its velocity are v at this precise moment. 

What makes speed and velocity different from one another?

Most people mix the terms velocity and velocity in regular speech. These are different concepts that don't share the same significance in physics. Speed has no direction, which is one significant distinction. Speed is therefore a scalar.

Is the term "velocity" a vector term?

In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate. A moving item can never move at a negative speed. A moving item can have zero velocity. The main determinant of an object's quickness is its speed.

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On a 6°C day, the surveyor needs to add a correction factor to get the true distance between the two stakes.

The steel measuring tape is calibrated for 20°C, so when the temperature is lower, the tape contracts, making it slightly shorter than its calibrated length.

Therefore, the measured distance will be shorter than the true distance, and a correction factor must be added to account for this difference.

Summary: To determine the true distance between two stakes measured as 75.175 m on a 6°C day, the surveyor should add a correction factor to the measured value.
For part b of your question, additional information such as the coefficient of linear expansion for the steel tape would be needed to calculate the correction factor in millimeters.

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If C4 has a frequency of 262 Hz, then C6 will have a frequency twice that of C5 and four times that of C4. Thus, the frequency of C6 can be calculated as follows:

C5 = 2 x C4 = 2 x 262 Hz = 524 Hz

C6 = 2 x C5 = 2 x 524 Hz = 1048 Hz

Therefore, the frequency of C6 is 1048 Hz. The frequency of a string is proportional to the square root of its tension. Thus, if we want to lower the pitch of the string by one octave (i.e., halve its frequency), we need to reduce its tension by a factor of four.

Since A3 is one octave lower than A4, we need to reduce the tension of the string tuned to A4 by a factor of four to tune it to A3. Therefore, the tension of the string, A3, should be one-fourth that of the string tuned to A4. In terms of A4, the tension of the string, A3, can be expressed as:

A3 = (1/4) x A4

Therefore, the tension of the string, A3, should be one-fourth that of the string tuned to A4.

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Answer:

Astronauts who are orbiting the Earth often experience sensations of weightlessness. These sensations experienced by orbiting astronauts are the same sensations experienced by anyone who has been temporarily suspended above the seat on an amusement park ride. Not only are the sensations the same (for astronauts and roller coaster riders), but the causes of those sensations of weightlessness are also the same. Unfortunately however, many people have difficulty understanding the causes of weightlessness.

The final speed of the car at the given conditions is 30.1 m/s.

The given parameters:

The change in the energy applied to the car is calculated as;

\(\Delta E = E_1 - E_2\\\\\Delta E = 22,000 \ J \ - \ 3,666.67 \ J\\\\\Delta E = 18,333.33 \ J\)

The final speed of the car is calculated as follows;

\(\Delta E = \frac{1}{2} m(v_f^2 - v_0^2)\\\\v_f^2 - v_0^2 = \frac{2\Delta E}{m} \\\\v_f^2 = \frac{2\Delta E}{m} + v_0^2\\\\v_f = \sqrt{ \frac{2\Delta E}{m} + v_0^2} \\\\v_f = \sqrt{ \frac{2\times 18,333.4}{1700} + (21)^2} \\\\v_f = 30.1 \ m/s\)

Thus, the final speed of the car at the given conditions is 30.1 m/s.

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The result of two or more vectors is the outcome.  it's the outcome of multiplying two or more vectors.  The resultant result of adding the displacement vectors A, B, and C are vector R. An appropriately drawn, scaled, vector addition diagram is often used to compute vector R, as illustrated within the diagram.

What do three resultant vectors add up to?

Afbeeldingsresultat for these vectors' offspring

The outcome of multiplying vectors A + B + C is the same as that of multiplying vectors B + A + C or even C + B + A.  The resultant result will be the same as long as all three vectors are present with the appropriate magnitude and direction. The resultant of two or more vectors is the outcome.

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Answer:

A. As the blackbody radiator becomes warmer, it emits light of shorter wavelengths.

The temperature, and electromagnetic radiation has a relationship where blackbody radiator becomes warmer, it emits light of shorter wavelengths.

radiation can be regarded as the process of heat dissipation without contact with a body.

Therefore , temperature, and electromagnetic radiation of a black body works in the sense that

blackbody radiator becomes warmer during emissions.

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The person can jump a distance of approximately 0.541 meters in the standing broad jump.

To calculate the distance that a person can jump in the standing broad jump, we can use the equation for the horizontal displacement of an object subject to constant acceleration:

x = v0t + (1/2)at^2

where x is the displacement (in meters), v0 is the initial velocity (in meters per second), t is the time of flight (in seconds), and a is the acceleration (in meters per second squared).

We can use the information provided in the problem to solve for the time of flight:

t = √(20.670 m / (1.26g))

The acceleration due to gravity, g, is approximately 9.8 m/s^2. Substituting this value into the equation for t gives us:

t = √(20.670 m / (1.269.8 m/s^2)) = 0.293 s

Now that we know the time of flight, we can use the equation for horizontal displacement to solve for the distance traveled:

x = v0t + (1/2)at^2

= 0 + (1/2)(1.26g)*(0.293 s)^2

= 0.541 m

Assumptions:

The acceleration achieved from the crouch position is constant during the jump.

The person's arms do not contribute significantly to the horizontal displacement of the jump.

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Answer:

Squatting exercises are closed-chain kinetic exercises, which recruit several joints and muscles in order to perform the lift properly.

Explanation:

An athlete completing a back squat exercise is performing a closed kinetic chain activity. In a closed kinetic chain exercise, the distal end of the body is fixed, and the movement occurs at the proximal end. This means that during a back squat exercise, the athlete's feet are fixed on the ground, and the movement occurs at the hips, knees, and ankles. This type of exercise is important for improving strength, stability, and proprioception.

Closed kinetic chain exercises are beneficial for athletes because they engage multiple muscle groups, and they mimic functional movements used in sports and daily activities. Back squats specifically target the quadriceps, glutes, hamstrings, and lower back muscles, which are all important for explosive movements like jumping, running, and changing direction. Additionally, back squats can help improve core stability and posture, which can reduce the risk of injury and improve overall athletic performance.

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Answer:b

Explanation:

Answer:

B

Explanation:

Answer:

C

Explanation:

During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons. Hydrogen nuclei fuse to form one helium atom.