a square has sides of 10x. simplifyan expression for the perimeter of that square14x40x20x100x

Answer: 71.57

Step-by-step explanation:

You are going to use SOH CAH TOA to find the angle

because the opposite and adjacent are the sides from the reference angle use TOA (tanΘ=opp/adj)

TanΘ=\(\frac{9}{3}\)

now use that tan^-1 (9/3) on your calculator (make sure your calc is in degree mode)

71.57

Answer:

\(C_{22} = 389\)

\(Max(A_{31}) =376\)

Step-by-step explanation:

Given

See attachment for complete question

Solving (a): The entry C22

First, matrix C represents the inventory at the end of July.

The entry of C is calculated as:

\(C = Inventory - Sales\)

i.e.

\(C = \left[\begin{array}{ccc}543&356&643\\364&476&419\\376&903&409\end{array}\right] - \left[\begin{array}{ccc}102&78&97\\98&87&59\\54&89&79\end{array}\right]\)

\(C = \left[\begin{array}{ccc}543-102&356-78&643-97\\364-98&476-87&419-59\\376-54&903-89&409-79\end{array}\right]\)

\(C = \left[\begin{array}{ccc}441&278&546\\266&389&360\\322&814&330\end{array}\right]\)

Item C22 means the entry at the second row and the second column.

From the matrix

\(C_{22} = 389\)

Solving (b): The maximum A31 possible.

From the given data, we have:

\(Inventory = \left[\begin{array}{ccc}543&356&643\\364&476&419\\376&903&409\end{array}\right]\)

\(Unit\ Sales = \left[\begin{array}{ccc}102&78&97\\98&87&59\\54&89&79\end{array}\right]\)

From the matrices above.

A31 means entry at the 3rd row and 1st column.

So, the possible values of A31 are:

\(A_{31} = 376\)

and

\(A_{31} = 54\)

By comparison, 376 > 54

So:

\(Max(A_{31}) =376\)  

Answer:

b = 79

Step-by-step explanation:

The y-intercept is the point at which x is 0. Looking at the data table, when x is 0, y is 79.

Raw materials purchases in July - Payment for raw materials purchases in July = Desired ending raw materials inventory for July

X pounds - 0.35 * X pounds = 9,500 pounds

Solving this equation will give us the value of X, which represents the pounds of raw materials that should be purchased in July.

To determine the number of pounds of raw materials that should be purchased in July, we need to calculate the raw materials production needs for August and then consider the inventory policies given in the information provided.

Each unit of finished goods requires 5 pounds of raw materials. The budgeted unit sales for August are 19,000 units. Therefore, the raw materials production needs for August would be 19,000 units multiplied by 5 pounds per unit, which equals 95,000 pounds.

The ending raw materials inventory equals 10% of the following month’s raw materials production needs. Therefore, the desired ending raw materials inventory for July would be 10% of 95,000 pounds, which is 9,500 pounds.

To calculate the raw materials purchases for July, we need to consider the payment terms provided. Thirty-five percent of raw materials purchases are paid for in the month of purchase and 65% in the following month.

Let's assume the raw materials purchases for July are X pounds. Then the payment for 35% of X pounds will be made in July, and the payment for 65% of X pounds will be made in August.

The payment for raw materials purchases in July (35% of X pounds) will be:

0.35 * X pounds

The payment for raw materials purchases in August (65% of X pounds) will be:

0.65 * X pounds

Since the raw materials purchases for July should cover the desired ending raw materials inventory for July (9,500 pounds), we can set up the following equation:

Raw materials purchases in July - Payment for raw materials purchases in July = Desired ending raw materials inventory for July

X pounds - 0.35 * X pounds = 9,500 pounds

Solving this equation will give us the value of X, which represents the pounds of raw materials that should be purchased in July.

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Answer:

a

Step-by-step explanation:

because as absolute value gets smaller the line gets steeper

r

Answer:

C

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Answer:

6 1/2 hours

Step-by-step explanation:

the ratio of (painters*hours)/rooms is constant, so

3*9/4 = 27/4

or, consider that 1 painter can paint those 4 rooms in 27 hours

so it will take him 27/4 hours to do one room

Answer:

\( 6.7 -0.674 *1.1 =5.96\)

\( 6.7 +0.674 *1.1 =7.44\)

Step-by-step explanation:

Let X the random variable that represent the  head breadths of a population, and for this case we know the distribution for X is given by:

\(X \sim N(6.7,1.1)\)  

Where \(\mu=6.7\) and \(\sigma=1.1\)

We want the range of the middle 50% values on the distribution. Since the normal distribution is symmetrical we know that in the tails we need to have the other 50% and on each tail 25% by symmetry.

We can use the z score formula given by:

\(z=\frac{x-\mu}{\sigma}\)

The critical values that accumulates 0.25 of the area on each tail we got:

\( z_{crit}= \pm 0.674\)

And if we solve x from the z score we got:

\( x = \mu \pm z \sigma\)

And replacing we got:

\( 6.7 -0.674 *1.1 =5.96\)

\( 6.7 +0.674 *1.1 =7.44\)

Answer:

decimal form, fraction form i think dont qoute me

Answer:

\(P(\text{Science}|\text{Math})\approx64\%\)

Step-by-step explanation:

\(\displaystyle P(\text{Science}|\text{Math})=\frac{P(\text{Science and Math})}{P(\text{Math})}\\\\P(\text{Science}|\text{Math})=\frac{0.45}{0.70}\\ \\P(\text{Science}|\text{Math})\approx0.643\approx64\%\)

None of the answer choices have this solution apparently, so either you left out some option, mistyped them, or it wasn't there to begin with

Answer:

A linear equation is of the form:

y = a*x + b

Where a and b are real numbers, and we only have one term with x, and no powers of x larger than 1.

Let's rearrange all the given options to see if they take this form. I will isolate x for all of them.

a) 2x + 5y = 13

5y = -2*x + 13

y = (-2/5)*x + 13/5

(this is a linear equation)

b) -x^2 = 3y + 10

 -3*y = x^2 + 10

y = (-1/3)*x^2 + 10/3

(this is not a linear equation)

c) 3(2x + y) = 14

 6x + 3y = 14

 3y = 14 - 6x

y = (-6/3)*x + 14/3

(this is a linear equation)

d) y = 13 - 2*x^2

(this is not a linear equation, we have a x^2 there)

e) 2 = y + x^5

-y = x^5 - 2

(this is not a linear equation, we have a x^5 there)

f) y = x + 7

we can rewrite this as:

y = 1*x + 7

(this is a linear equation)

Answer:

i just wanted to say, that I took the test and A and F are correct, but C (the person above me says C is correct) is not correct

Step-by-step explanation:

Answer:

A. h = 64

B.  t = 4 -> 4 seconds

C. t = 1.5 -> 1.5 seconds

D. maximum height is 100 ft

E. The domain that makes sense for the function in this context is t

is any positive real number since time can not be negative.

Step-by-step explanation:

h = -16t2 + vt + 64

A. What tower platform height was the projectile launched from?

when the projectile was not launched, t = 0

h = -16(0)^2 + v(0) + 64 = 64

B. How long was the projectile in the air?

if the projectile lands, its height = 0 so substitute 0 for h

0 = -16(t)^2 + 48(t) + 64

  = -16(t^2 - 3t -  4)

 = -16(t - 4)(t + 1)

t = 4 or t = -1

Since time can not be negative, t = -1 can not be the answer. Therefore, the projectile lands when t = 4 or 4 seconds.

C. When did it reach its maximum height?

maximum -> t=-b/2a where in -16(t)^2 + 48(t) + 64, b = 48 and a = -16

t = -48/-32 = 1.5

D. What was its maximum height?

plug t = 1.5 into -16(t)^2 + 48(t) + 64

-16(1.5)^2 + 48(1.5) + 64 = -36 + 72 + 64 = 100

E. The domain that makes sense for the function in this context is t

is any positive real number since time can not be negative.

The maximum height is 100 feet at a time of about 1.5 seconds.

An equation is an expression that shows the relationship between two or more variables and numbers.

Given that:

h = -16t² + vt + 64

-16t² + 48t + 64 = h

h is the height, v is the initial velocity and t is the time.

a) The tower height is about 64 feet from the equation

b) The time is at h = 0, hence:

-16t² + 48t + 64 = 0

t = 4 seconds

c) Maximum height is at h' = 0

h' = -32t + 48

-32t + 48 = 0

t = 1.5 seconds

d) h(1.5) = -16(1.5)² + 48(1.5) + 64 = 100 feet

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When listing all the pairs of factors for a particular term, the factorization process is used.

This process is fundamental in number theory and is used to break down composite numbers into their simplest building blocks: prime numbers.

For example, if we want to find all pairs of factors for the number 24, we could follow these steps:

Start with 1 and the number itself (in this case 24), as these are always factors.

Check if 2 divides 24 evenly. If it does, then 2 and 24/2 (which is 12) are a pair of factors.

Continue this process with increasing numbers. Check 3 (yes, it works, with the pair being 3 and 8), 4 (yes, with the pair being 4 and 6), and so on.

When the numbers you're testing exceed the square root of the original number (approximately 4.9 for 24), you can stop, as you'll have found all pairs.

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The parent function of the transformed function is y = f ( x ) = x

Given data ,

Let the parent function be represented as f ( x )

Now , the value of f ( x ) is

The transformed function is represented as y

where y = 2 ( x - 5 )

On simplifying , we get

y = 2( x - 10 )

If the original function is y = f(x), assuming the horizontal axis is the input axis and the vertical is for outputs, then:

The function is shifted horizontally left by 10 units and multiplied by a scale factor of 2 units.

Hence , the parent function is f ( x ) = x

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When one of the parent cell keeps dividing while the other matures, this is known as arithmetic growth. The early stages of geometric growth are characterized by slow expansion, whereas the latter stages are characterized by rapid expansion.

When one of the parent cell keeps dividing while the other matures, this is known as arithmetic growth. An illustration of arithmetic growth is the ongoing elongation of roots. The early stages of geometric growth are characterized by slow expansion, whereas the latter stages are characterized by rapid expansion.

The amounts added grow by a fixed rate of growth, expressed in percentages. Due to the fact that these remain constant while the amounts added rise, growth is then typically measured in doubling times.

Due to the fact that all populations of organisms have the potential to experience exponential growth, the concept of exponential growth is particularly intriguing in the field of population biology.

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Answer: E

Step-by-step explanation:

Answer:

See the image below for answer:)

Step-by-step explanation:

Answer:

B. (1 ± sqrt(33)) / 4

Step-by-step explanation:

the 2 solutions for a quadratic equation

ax² + bx + c = 0

are defined as

x = (-b ± sqrt(b² - 4ac)) / 2a

in our example here we have

a = -2

b = 1

c = 4

=>

x = (-1 ± sqrt(1 + 32)) / -4 = (1 ± sqrt(33)) / 4

as we can easily divide top and bottom by -1 to turn the -1 and -4 into positive numbers, and the second top part, the square root, is a ± factor anyway. just withing the sign dues not change the fact that is is still a ± factor (both signs apply).

and now it is clear, it has to be option B.

the others disqualify because they have either no division by any form of 4, or the "1" and the "4" have different signs. but our equation shows they need to have equal signs (either both negative or both positive).

Answer:

5th grade mean - 4.67

7th grade mean - 3.46

5th-grade median - 5

7th-grade median - 3.5

Based on the fact that the function is f(x)=x²-16 and the domain is f(x)>0?​, the inverse of the function is f⁻¹(x) = √( x + 16).

The inverse of the function will be such that the operations in the function will be the opposite in the inverse function.

This means that f(x) will be taken to the power negative one (-1) to show that the function has been inverted to become 1/f(x).

The fact that x was being squared will then become a square root and the addition sign between x and 16 will become a square root.

This gives:

f⁻¹(x) = √( x + 16)

Full question is:

Which function is the inverse of f(x)=x²-16 if the domain is f(x)>0?​

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Answer:

C. Statistic because the value is a numerical measurement describing a characteristic of a sample

The ordered triple representing \(3u - 2v\) is \((13, -8, 5)\).

To find an ordered triple representing \(3u - 2v\),

where \(u = (5, -2, 3)\) and \(v = (1, 1, 2)\),

we can perform the following operations:

\(3u = 3(5, -2, 3)\)

\(3u = (15, -6, 9)\)

\(2v = 2(1, 1, 2)\)

\(2v = (2, 2, 4)\)

Now, subtracting 2v from 3u gives:

\(3u - 2v = (15, -6, 9) - (2, 2, 4)\)

\(3u - 2v = (15-2, -6-2, 9-4)\)

\(3u - 2v = (13, -8, 5)\)

Therefore, the ordered triple representing 3u - 2v is (13, -8, 5).

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Answer:

The answer is 2√10

Step-by-step explanation:

Hyp²=opp²+adj²

let hyp be x

x²=6²+2²

x²=36+4

x²=40

square root both sides

√x²=√40

x=2√10

Answer:

B

A

C

Step-by-step explanation:

Simply the inequalities

y - 13 > -85

y > -85 + 13

y > -72

Graph B is the solution

13 < -85 + y

y > 13 + 85

y > 98

Graph A is the solution

y + 13 < -85

y < -85 -13

y < -98

Graph C is the solution

Answer:

B A C

Step-by-step explanation:

Answer:

y-1 over 3 (y -5)

Step-by-step explanation:

i think that s correct but the getting the app m a t h w a y for any further problems

The complete solution of the integral ∫ x · √(8 · x - x²) dx is equal to [- √(8 · x - x²)³ / 3] - (- 2 · x + 8) · √(8 · x - x²) + 32 · [ -  sin⁻¹ [(- 2 · x + 8) / 8]].

Some integrals cannot be resolved immediately or at least in few steps, requiring sometimes the resolution of some intermediate integrals. In this case, we have an integral of the form:

∫ x · √(a · x² + b · x + c) dx, where a, b, c are real constants.       (1)

The use of integral tables allows us to save time on resolution of integrals.

The solution of (1) can be found by using part integration several times. In accordance with the table of integrals, we find the following information:

∫ x · √(a · x² + b · x + c) dx = [√(a · x² + b · x + c)³ / (3 · a)] - [[b · (2 · a · x + b)] / (8 · a²)] · √(a · x² + b · x + c) - [[b · (4 · a · c - b²)] / (16 · a²)] ∫ [1 / √(a · x² + b · x + c)] dx

∫ [1 / √(a · x² + b · x + c)] dx = - (1 / √- a) · sin⁻¹ [(2 · a · x + b) / [√(b² - 4 · a · c)]]

Then, the complete solution of the integral is:

∫ x · √(a · x² + b · x + c) dx = [√(a · x² + b · x + c)³ / (3 · a)] - [[b · (2 · a · x + b)] / (8 · a²)] · √(a · x² + b · x + c) - [[b · (4 · a · c - b²)] / (16 · a²)] · [ - (1 / √- a) · sin⁻¹ [(2 · a · x + b) / [√(b² - 4 · a · c)]]]

If we know that a = - 1, b = 8 and c = 0, then the complete solution of the integral is:

∫ x · √(8 · x - x²) dx = [- √(8 · x - x²)³ / 3] - (- 2 · x + 8) · √(8 · x - x²) + 32 · [ -  sin⁻¹ [(- 2 · x + 8) / 8]]

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To calculate the circumference of a circle, you can use the formula:

\(\displaystyle C=2\pi r\)

Where \(\displaystyle C\) represents the circumference and \(\displaystyle r\) represents the radius of the circle.

Given that the radius \(\displaystyle r\) is 8 inches, we can substitute this value into the formula:

\(\displaystyle C=2\pi (8)\)

Simplifying the expression:

\(\displaystyle C=16\pi \)

Thus, the circumference of a circle with a radius of 8 inches is \(\displaystyle 16\pi \) inches.

Note: \(\displaystyle \pi \) represents the mathematical constant pi, which is approximately equal to 3.14159.

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♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

The weight on the inflation gap has increased from 0.5 to 0.75. The real interest rate is 16.86% and Nominal interest rate is 20%

a. In the base scenario, the real interest rate will be 20%, and the nominal interest rate will be 20%.

b. In scenario B, inflation rate will be higher (4%) compared to the base scenario (3.14%).

Output gap is 0% in both the scenarios, however, in the base scenario inflation gap is 0% (3.14 - 3.14) and in scenario B, inflation gap is 0.86% (4 - 3.14).

Now, let's calculate the real interest rate.

Real interest rate in base scenario = 20% - 3.14%

= 16.86%.

Real interest rate in scenario B = 20% - 3.14% + 1.5 + 0.5 (4-3.14) + 0.5 (0-0/0)

= 19.22%.

The real interest rate has moved in the direction to move inflation rate towards its target.

c. In scenario C, the output gap will be 20% compared to 0% in the base scenario.

Inflation gap is 0% in both the scenarios

Inflation rate is 3.14% and in scenario C, inflation rate is 2%.

Let's calculate the real interest rate. Real interest rate in the base scenario = 20% - 3.14%

= 16.86%.

Real interest rate in scenario C = 20% - 2% + 1.5 + 0.5 (3.14 - 3.14) + 0.5 (20-0/20)

= 20.15%.

Real interest rate in scenario C = 20% - 2% + 1.5 + 0.75 (3.14-3.14) + 0.25 (20-0/20) = 18.78%.

The new policy rule has changed the weight of the output gap in the Taylor Rule from 0.5 to 0.25.

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The optimal Bayesian classifier is the one that minimizes the probability of misclassification. This can be achieved by choosing the class that has the highest posterior probability given the observed data. In this case, we need to compare the conditional class probabilities P2(t) and P0(I) for each data point and choose the class with the higher probability.

To find the optimal Bayesian classifier, we need to find the values of a and b that define the decision boundary between the two classes. This can be done by setting P2(t) = P0(I) and solving for x:

P2(t) = P0(I)
Pr(Y; = 1|X, = x) = Pr(Y; = 0[Xi = 1)
1 - P2(I) = P2(I)
2P2(I) = 1
P2(I) = 0.5

Now we can solve for x to find the decision boundary:

0.5 = Pr(Y; = 1|X, = x)
0.5 = P2(I)
x = a + b

Therefore, the optimal Bayesian classifier is of the form:

if Xe [a, b] then yi = 1
if Xe [b, a] then yi = 0

where a and b are the values of x that satisfy P2(I) = 0.5.

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A) the total number of boxes in the bottom 2 layers is 100 + 80 = 180 boxes. B) Number of boxes in each layer = W(n) * D C) the total number of boxes needed to make up the 4 layers is 280 boxes.

A) To determine the number of boxes in the bottom 2 layers:

The bottom layer has a width of 20 boxes and is 5 boxes deep.

The second layer has a width of 16 boxes and is also 5 boxes deep.

Number of boxes in the bottom layer = 20 boxes wide * 5 boxes deep = 100 boxes

Number of boxes in the second layer = 16 boxes wide * 5 boxes deep = 80 boxes

Therefore, the total number of boxes in the bottom 2 layers is 100 + 80 = 180 boxes.

B) To develop a formula to calculate the number of boxes in n layers:

Let's denote the width of each layer as W and the depth of each layer as D.

The width of each layer follows the pattern: 20, 16, 12, 8.

We can observe that the width decreases by 4 units for each consecutive layer.

The formula to calculate the width of the nth layer can be written as:

W(n) = 20 - 4 * (n - 1)

Since each layer has a depth of 5 boxes, the number of boxes in each layer can be calculated as:

Number of boxes in each layer = W(n) * D

C) To use the formula from part B to solve for the total number of boxes needed to make up the 4 layers:

We want to calculate the total number of boxes in 4 layers.

Number of boxes in 4 layers = Number of boxes in the first layer + Number of boxes in the second layer + Number of boxes in the third layer + Number of boxes in the fourth layer

= W(1) * D + W(2) * D + W(3) * D + W(4) * D

= (20 - 4 * 0) * 5 + (20 - 4 * 1) * 5 + (20 - 4 * 2) * 5 + (20 - 4 * 3) * 5

= 20 * 5 + 16 * 5 + 12 * 5 + 8 * 5

Simplifying the expression, we get:

Number of boxes in 4 layers = 100 + 80 + 60 + 40 = 280 boxes

Therefore, the total number of boxes needed to make up the 4 layers is 280 boxes.

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