a sprinter starts from rest and accelerates at a rate of 0.16 ms ^-2 over a distance of 50.0 meters . How fast is the athlete traveling at the end of the 50.0 meters?

Answer:

I feel like it's Convection because if its dry , then the water comes over it and it warms it also the sun gives it light it's gonna be more warmer. So I think your answer will be Convection.

Explanation:

Because conduction is Anything being warmed by objects touching.

And radiation is Anything being warmed by heat transferring through space.

And the meaning of Convection is Anything being warmed in WATER.

I hope this is right and I hope this will help you in any way!! <3

We know that,

\(\huge ➸ C = ϵ₀ \frac{A}{d} \)

given ↷

to find ↷

solution ↷

\(\begin{gathered}➸ C = ϵ₀ \frac{A}{d} \\ \end{gathered} \)

\(\begin{gathered}➸ A =  \frac{Cd}{ϵ₀} \\ \end{gathered}  \\ \)

\(\begin{gathered}➸ A =  \frac{5.31 \times  {10}^{ - 9} \times 5 }{8.85 \times  {10}^{ - 12} } \\ \end{gathered}  \\  \)

\(➸ A =3 \times  {10}^{3}  {mm}^{2} \)

\(➸ A =3  {m}^{2} \)

Hence, the area is 3m²

Answer:

Explanation:

The capacitance of two parallel square plates of area A and separated by distance d is given as:

 C = ε(A/d) where ε is the permittivity of the dielectric material

For air, ε = 8.854x10^(-12) F/m

Substituting into the equation:

5.31x10^(-9) = 8.854x10^(-12) * A / 5x10^(-3)

A = 3.00 m^2

Answer:  240 kmph

Explanation:

The fastest roller coaster made by man is currently present in the ferrari world in Abu Dhabi, UAE which can reach upto 240 km/h

The fastest roller coaster ever built is the Formula Rossa located at Ferrari World in Abu Dhabi.

This roller coaster reaches a top speed of 149 miles per hour (240 kilometers per hour) in just 4.9 seconds. Formula Rossa is a steel roller coaster that is 2.2 kilometers long and reaches a height of 52 meters. It has a launch system that propels the coaster from 0 to 149 miles per hour in just a few seconds, making it one of the most thrilling roller coasters in the world. The ride lasts for approximately 1 minute and 32 seconds, and riders experience a maximum g-force of 4.8 during the ride.

The Formula Rossa roller coaster is definitely not for the faint of heart and is a must-ride for thrill-seekers who are looking for an adrenaline-pumping experience.

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Answer:

The correct answer is C.) C

Explanation:

I just did the test on edge and got it right

A car sits on a tall orange box with a shorter orange box in front if it. A short line from the car leads to line, which curves down to the shorter box, and line. Therefore, the correct option is option C.

Many of us do not pause to contemplate the importance of play in the lives of children, whether they are our own or the children of friends and relatives. We just take it for granted that kids spend their free time driving toy trucks about or pretending to be dragons (or both), and although it's amusing (certainly for them and occasionally for us), we don't give it much thought beyond that.

It's a great time to start playing with cars, dump trucks, and other vehicles. Not that they'll need much convincing: boys, in particular, appear to be captivated to anything that includes wheels long before their first birthday. which curves down to the shorter box, and line.

Therefore, the correct option is option C.

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Answer:

The final velocity of the object is 330 m/s.

Explanation:

To solve this problem, we first must find the acceleration of the object.  We can do this using Newton's Second Law, given by the following equation:

F = ma

If we plug in the values that we are given in the problem, we get:

42 = 7 (a)

To solve for a, we simply divide both sides of the equation by 7.

42/7 = 7a/7

a = 6 m/s^2

Next, we should write out all of the information we have and what we are looking for.

a = 6 m/s^2

v1 = 0 m/s

t  = 55 s

v2 = ?

We can use a kinematic equation to solve this problem.  We should use:

v2 = v1 + at

If we plug in the values listed above, we should get:

v2 = 0 + (6)(55)

Next, we should solve the problem by performing the multiplication on the right side of the equation.

v2 = 330 m/s

Therefore, the final velocity reached by the object is 330 m/s.

Hope this helps!

The correct option is a)  7.28 x 10-5 m/s.

de Broglie wavelength, λ = 1 cm

de Broglie wavelength is given asλ = h/mv,

where h is Planck’s constant, m is the mass of the electron and v is the velocity of the electron.

Rearranging this equation, we get: v = h/mλ

Now substituting the values of h, m, and λ,

we get:v = (6.626 × 10⁻³⁴ J.s)/(9.109 × 10⁻³¹ kg)(1 × 10⁻² m)= 7.28 × 10⁻⁵ m/s

Hence, the velocity of an electron that has a de Broglie wavelength of 1 cm is 7.28 × 10⁻⁵ m/s, which is an option (a).

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The velocity of an electron that has a de Broglie wavelength of 1 cm is 7.28 x 10⁻² m/s.

option C is the correct answer.

The velocity of an electron that has a de Broglie wavelength of 1 cm is calculated as follows;

λ = h / mv

Where;

mass of electron =  9.11 x 10⁻³¹ kg.

The velocity of an electron is calculated as;

v = h / (mλ)

v = (6.626 x 10⁻³⁴ J·s) / (9.11 x 10⁻³¹ kg x 0.01 m)

v = 7.28 x 10⁻² m/s

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Answer:

extension = 0.9 m

Explanation:

The formula relating force to extension for a spring is given as follows:

\(\boxed{F = kx}\),

where:

• F = force applied on spring

• k = spring constant

• x = extension of spring

From the above formula:

\(\frac{F}{x} = k = \mathrm{constant}\)

This means that, for a spring, the ratio \(\frac{F}{k}\) is a constant value. Therefore, we can say:

\(\frac{F_1}{x_1} = \frac{F_2}{x_2}\)

Substituting 2.0N and 0.30m for F₁ and x₁ respectively, and 6N for F₂, in the above equation, we can solve for x₂:

\(\frac{2.0}{0.3} = \frac{6.0}{x_2}\)

⇒ \(x_2 \times \frac{2.0}{0.3} = 6.0\)          [Multiplying both sides of the equation by x₂]

⇒ \(x_2 = 6.0 \div \frac{2.0}{0.3}\)

⇒ \(x_2= \bf 0.9 m\)

Therefore, the extension of the spring when 6N force is applied is 0.9 m.

The extension of the spring when the force applied becomes 6 N is 0.9 m.

The force constant or spring constant of the spring is calculated as follows;

F = kx

k = F/x

where;

k = (2 N) / (0.3 m) = 6.67 N/m

The extension of the spring when the force applied on the spring becomes 6 N is calculated as follows;

x = F/k

x = (6 N) / (6.67 N/m)

x = 0.9 m

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The new  time period of the system is 8.77 sec. If she stands up.

calculation

T = 2π√(L/g)

l = g*(8.85/2π)^2

new length = l -0.35= 8.85-0.35

T = 8.77 sec

Term (T) is the amount of time an oscillating body takes to repeat itself, and Frequency (f or ν) is the variety of instances it repeats in one 2d or unit time. in case you degree time in s (seconds) then frequency is measured in Hz (cycles or durations in keeping with second.

center of mass:

The centroid of a mass distribution in space is the unique point where the weighted relative positions of the distribution masses sum to zero. This is the point where force can be applied to produce linear acceleration without angular acceleration.

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The type of stream transportation described as a series of short leaps or bounces off the bottom of the streambed is called saltation.

In saltation, particles such as sand or pebbles are lifted off the streambed by the force of flowing water and then fall back to the bed in a series of jumps. This type of transportation occurs in streams with moderate to high flow velocities and where the bed is composed of a mix of sediment sizes.

Saltation can be an important process in erosion and sediment transport in streams, particularly in the formation of gravel bars and channels.

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The work done during the kick is 200 J

The workdone during the kick can be obtained as follow:

Wd = F × d

Wd = 1000 × 0.2

Workdone = 200 J

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The amount of work done during the kick is 200 Joules.

The formula for work done is Force× Distance

This is represented by fd

The force applied is 1,000 Newton

The displacement exerted by the force during kicking is 0.2meter

From this we can get the work done which is:

W= fd

= 1000N × 0.2m

= 200 Joules.

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The amount of torque exerted by the bar on the gymnast's hands will be 90Nm, Newtons 3rd law of motion.

According to newton's 3rd law of motion :- for every action in nature there is an equal and opposite reaction.

if an object exert a force on other object, then the other object must exert force of equal magnitude and opposite direction back on object.

so here also the same laws applied and the torque exerted by the bar on the hands on gymnast's is of 90 Nm.

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The spring balance provides a mass measurement

Answer:

mass

Explanation:

The mass is hung on the end of a spring, and the deflection of the spring due to the downwards gravitational force on the mass is measured against a scale.

Answer:

ROYGBIV or Roy G. Biv is an acronym for the sequence of hues commonly described as making up a rainbow: red, orange, yellow, green, blue, indigo and violet. The initialism is sometimes referred to in reverse order, as VIBGYOR.

The induced voltage in the second case will be higher but the change in flux will be same in comparison to the first case.

In the experiment of measuring the change of flux and the induced voltage,

In the first case the magnet is dropped from a height 3cm of the coil and in the second case the the magnet is raised so that it drops 20cm before entering the coil.

When compare to the first case the second case will have a higher value of induced voltage but the change in flux will be same.

The induced voltage in a coil is given by,

E = dM/dt

dM is change in magnetic flux,

t is time,

As we can see that the time is inversely proportional to the induced emf and in the second case the magnet is drop from a height which allows it to go with the higher velocity in a less time that is why the induced EMF is more in magnitude but because the magnet is same in both the cases the change in flux is constant.

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Answer:

true

Explanation:

The magnitude of the average vertical force exerted by the horizontal surface on the bar can be found using the impulse-momentum theorem,

which states that the impulse applied to an object is equal to its change in momentum.

Assuming that the bar is rigid and does not deform during the impact, the change in momentum of the bar is equal to the product of its mass and the change in velocity.

Since the bar is released from rest, its initial velocity is zero and its final velocity after rebounding is also zero.

Therefore, the change in momentum is zero, which means that the impulse applied to the bar during the impact is also zero.

However, we know that the duration of the impact is 0.01 s. This means that the average force exerted by the horizontal surface on the bar is given by the equation:

Average force = Impulse / Duration of impact

Since the impulse is zero, the average force is also zero. Therefore, the magnitude of the average vertical force exerted by the horizontal surface on the bar at point P is zero.

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A. We need to compute the entire cross-sectional area of the prime movers for elbow flexion and multiply it by the specific tension of muscle to get the maximum force that the elbow flexors can produce. The elbow flexors have a total cross-sectional area of 3.6 + 6.0 + 1.5 = 11.1 cm2. As a result, the elbow flexors may exert the following amount of force:

Cross-sectional area times a certain tension equals force.

Force = 333 N Force = 11.1 cm2 x 30 N/cm2

B. We must compare the torques generated by the triceps and the elbow flexors in order to determine whether the elbow will flex or extend. A muscle's torque is determined by multiplying the force it exerts by the moment arm. The moment arm is the angle at which the muscle's line of action is perpendicular to the axis of rotation.

The total torque for the elbow flexors is:

Torque equals force times moment arm

Torque equals 333 N/4 cm.

1332 N cm of torque

The total torque for the triceps is:

Torque equals force times moment arm

Torque is equal to 17.8 cm2 x 30 cm2 x 2.5 cm.

1335 N cm of torque

Since the triceps generate slightly more torque than the elbow flexors do, the elbow would extend if all of these muscles were fully engaged.

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A. To determine the maximum force that the elbow flexors can exert, we need to calculate the total cross-sectional area of the prime movers for elbow flexion, and then multiply it by the specific tension of the muscle:

The total cross-sectional area of elbow flexors = Biceps brachii + Brachialis + Brachioradialis

= 3.6 cm2 + 6.0 cm2 + 1.5 cm2

= 11.1 cm2

The maximum force that the elbow flexors can exert = Total cross-sectional area x Specific tension of muscle

= 11.1 cm2 x 30 N/cm2

= 333 N

Therefore, the maximum force that the elbow flexors can exert is 333 N.

B. To determine whether the elbow would flex or extend if all of these muscles were activated fully, we need to calculate the net torque generated by the muscles:

Net torque = (Force x Moment arm)flexors - (Force x Moment arm)triceps

Where force is the maximum force that the elbow flexors can exert (333 N), the moment arm of the elbow flexors is 4 cm, and the moment arm of the triceps is 2.5 cm.

Net torque = (333 N x 4 cm) - (333 N x 2.5 cm)

= 999 Ncm - 832.5 Ncm

= 166.5 Ncm

Since the net torque is positive (166.5 Ncm), the elbow would flex if all of these muscles were activated fully.

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The measure of average kinetic energy of molecules is called tempreture.

What is kinetic energy?

kinetic energy is a form of energy that an particle has by reason of it's motion.

If we want to accelerate an object then we must apply a force .

The average kinetic energy of all the molecule assumed to be directly proportional to the absolute tempreture of the gas.

The Kelvin tempreture of a substance is directly proportional to the average kinetic energy of the particles of the substance.

This is the reason why measure of the average kinetic energy of the molecule of a material called tempreture.

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If the two particles are moving at the same speed in a vacuum, then their kinetic energy will be the same. The kinetic energy of a particle is given by the equation:

KE = (1/2)mv^2

Where KE is the kinetic energy of the particle, m is its mass, and v is its speed.

In this case, the kinetic energy of the particle with mass m will be:

KE = (1/2)m*v^2

And the kinetic energy of the particle with mass 3m will be:

KE = (1/2)3mv^2 = (3/2)mv^2

Since the particles have the same kinetic energy, we can set the two equations equal to each other and solve for v:

(1/2)mv^2 = (3/2)mv^2

(1/2)*v^2 = (3/2)*v^2

1/2 = 3/2

This equation does not have a valid solution, which means that the two particles cannot be moving at the same speed in a vacuum if one has a mass of m and the other has a mass of 3m.

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Answer:

3.3×10⁻⁹ kg/s

Explanation:

There are two forces on the particle: weight force pulling down and drag force pushing up.  At terminal velocity, the speed is constant, so the acceleration is zero.

∑F = ma

bv − mg = 0

b = mg / v

b = (10⁻¹³ kg) (9.8 m/s²) / (3×10⁻⁴ m/s)

b = 3.3×10⁻⁹ kg/s

Answer:

So overall, motion and interference of matter are needed equally for friction, which is held together by the force of gravity. Without gravity, everything would have fly away in the universe, and the friction would not have exist. Hence, friction is dependent on gravity.

Elaborately means in a detailed and carefully arranged manner.

Explanation:

hope this helps!!!!

Answer:

Explanation: O B. Diffraction

We need to use the formula for stress, which is:

stress = force / area

where force is the weight supported by the column, and area is the cross-sectional area of the column.

First, we need to convert the dimensions of the column to meters to match the units of force:

Length = 25.0 cm = 0.25 m,Width = 25.0 cm = 0.25 m,Height = 5.00 m

The cross-sectional area of the column can be calculated as:

area = length * width = 0.25 m * 0.25 m = 0.0625 m^2

The weight supported by the column is given as 6.80 * 10^6 N.

Now we can substitute these values into the formula for stress:

stress = force / area = (6.80 * 10^6 N) / (0.0625 m^2) = 1.088 * 10^11 Pa

Therefore, the stress on the rectangular cast-iron column is 1.088 * 10^11 Pascals.

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Answer: D. about 40 m

Explanation:

Answer:

the answer is B

Explanation:

because i had this question in 8th grade

Projectile motion is a combination of constant motion in the horizontal direction, and accelerated motion in the vertical direction. Therefore, the correct answer option is: D. constant, accelerated.

Projectile motion can be defined as a form of motion which is experienced by a physical object (body) that is projected near the surface of planet Earth, while moving along a parabolic (u-shaped curve) path, and under the influence of a gravitational force only.

Based on scientific research and records by scientists such as Galileo, we can infer and logically deduce that the initial horizontal velocity of a physical object undergoing a projectile motion is always equal to its final horizontal velocity.

Additionally, Galileo stated that projectile motion combines constant or uniform motion in the horizontal direction and accelerated motion in the vertical direction.

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The heavy person will reach the ground first. This is because both individuals have the same parachute size, meaning they experience the same amount of air resistance. However, the heavy person has a greater weight (gravitational force) acting on them, which causes them to accelerate at a faster rate than the lighter person. As a result, the heavy person will reach the ground before the lighter person.

Explanation:

Therefore, the heavier person will reach the ground before the lighter person, despite having the same-size parachute.

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