Answers
Answer:
92.16J
Explanation:
E = ½ke²
E = ½(800)(0.48)²
E = 400 x 0.48²
E = 92.16
Related Questions
In a closed container, the pressure is inversely proportional to the volume when the temperature is held constant. Find the pressure of a gas compressed to 0.386 CU feet if the pressure is 12.86 PSI at 2.52cu ft
Answers
Explanation:
p = k / v
pv = k
12.86 * 2.52 = k =32.4
p * 0.386 = 32.4
p = 83.95 = 84.0 psi using 3 Sig Digits
12.
A hiker walks for 5km on a bearing of 053" true (North 53° East). She then turns and
walks for another 3km on a bearing of 107° true (East 17° South).
(a)
Find the distance that the hiker travels North/South and the distance that she travels
East/West on the first part of her hike.
Answers
The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.
This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.
Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.
The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.
Angles will always be expressed in degrees in the solution.
The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.
The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.
Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.
The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.
The angle between the two is (180 - 53 - 17) = 110 degrees.
The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.
Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.
Distance Travelled East/WestThe hiker walked East for the second part of the hike.
To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.
The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.
Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.
To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.
The angle between the second vector and the Eastern direction is 17 degrees.
Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.
The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.
Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
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what is effort arm
don't say the answer of gogle
Answers
Answer:
effort arm mean the use of any work by using your hand force motion or by hand power
If a space probe moves 20 m in 4 s, how fast is it moving?
Answers
Answer:
Speed =distance/time.
=20/4
=5m/s.
Formula: s = d/t
s = speed
d = distance
t = time
Solve using the values we are given.
s = 20/4
s = 5m/s
best of Luck!
8. Assuming no friction and a truly horizontal track, what is the largest acceleration the glider can
experience when being pulled by masses on the hanger? In this thought experiment, you are not
limited to just the masses we have available in lab, You must explain your answer.
Answers
Newton's second law allows concentrating that the response for maximum acceleration of the system is equal to the acceleration of gravity (a = g)
Newton's second law states that the net force is proportional to the product of the mass and the acceleration of the body
F = m a
The bold letters indicate vectors, F is the force, m and the mass and acceleration of the body, respectively.
The reference system is a coordinate system with respect to which measurements are made, in this case let's set a system where the x-axis is horizontal and the positive part is in the direction of movement, the y-axis is vertical.
In the attached we can see a diagram of the indicated system, as it indicates that there is no friction force, we write the equations for each part
truck
T = Ma
Hanging masses
T- m g = m a
for the rope to stay taut, the acceleration must be the same. We solve the system
M a - m g = m a
a = \(\frac{m}{m+ M}\) g
This is the acceleration of the truck. Let's analyze the different cases to shrink the maximum acceleration:
The hanging mass is much greater than the mass of the truck (m> M), we neglect the more of the trucka = g
The hanging mass is less than the mass of the truck (m <M)a = \(\frac{1}{1 + \frac{M}{m} }\) g
a = ( \(1 + \frac{M}{m}\) )⁻¹ g
The \(\frac{M}{m}\) value is much greater than the integer, we despise it the integer
a = \(\frac{m}{M}\) g
Since the truck mass is greater than the hanging mass, this acceleration is less than the acceleration of gravity.
a <g
In conclusion, using Newton's second law we can concentrate that the response for maximum acceleration of the system is equal to the acceleration of gravity (a = g)
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An ant climbs vertically on a fence. Its motion is shown on the following graph of vertical position � yy vs. time � tt. Graph of y (in meters) vs. t (in seconds) that starts at 6 m at 0sec, decreases linearly to 2m at 4 sec, stays constant at 2m from 4 sec to 7 sec, increases linearly to 5 m from 7 sec to 9 sec, then stays constant until 10 sec. Graph of y (in meters) vs. t (in seconds) that starts at 6 m at 0sec, decreases linearly to 2m at 4 sec, stays constant at 2m from 4 sec to 7 sec, increases linearly to 5 m from 7 sec to 9 sec, then stays constant until 10 sec. What is the instantaneous speed of the ant at time � = 8 s t=8 st, equals, 8, start text, space, s, end text?
Answers
The instantaneous speed of the ant at t=8s is equal to the slope of the segment between t=7s and t=9s, which is 1.5m/s.
To find the instantaneous speed of the ant at time t=8s, we need to calculate the derivative of the displacement function with respect to time. Since the displacement of the ant is given by a piecewise function, we need to differentiate each segment of the function separately and then piece them together. From 0s to 4s, the displacement of the ant decreases linearly from 6m to 2m. The slope of this segment is -1m/s. From 4s to 7s, the displacement of the ant is constant at 2m. The slope of this segment is zero. From 7s to 9s, the displacement of the ant increases linearly from 2m to 5m. The slope of this segment is 1.5m/s. Finally, from 9s to 10s, the displacement of the ant is constant at 5m. The slope of this segment is zero.
Therefore, the instantaneous speed of the ant at t=8s is equal to the slope of the segment between t=7s and t=9s, which is 1.5m/s. This means that the ant is moving upwards at a constant speed of 1.5m/s at time t=8s. It's important to note that the instantaneous speed of the ant tells us how fast it's moving at a specific moment in time. It's not the same as the average speed over a given time interval, which would be calculated by dividing the total displacement by the total time elapsed.
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An aluminum-alloy rod has a length of 10.000 cm at 20.000C and a length of 10.015 cm at the boiling point of water. (a) What is the length of the rod at the freezing point of water
Answers
The Length of the rod at the freezing point of water is 9.9625 cm
What is length?Length can be defined as the measurement of the distance between two points. The S.I unit of length is meter (m)
To calculate the length of the rod at the freezing point of water, we use the formula below
Formula:
(L₃-L₁)/L₁(t₃-t₁) = (L₂-L₁)/L₁(t₂-t₁)................ Equation 1Where:
L₁ = length of the aluminum alloy rod at 20 °CL₂ = Length of the aluminum alloy rod at boiling point.L₃ = Length of the aluminum alloy rod at freezing point.t₁ = Initial temperature of the aluminum alloy rodt₂ = Temperature of the aluminum alloy rod at the boiling point of water.t₃ = Temperature of the aluminum alloy rod at the freezing point of water.From the question,
Given:
L₁ = 10 cmL₂ = 10.015 cmt₁ = 20 °Ct₂ = 100 °C (boiling point of water)t₃ = 0 °C ( Freezing point of water)L₃ = ?Substitute these values into equation 1
(L₃-10)/[10(0-20)] = (10.015-10)/[10(100-20)]Solve for L₃
(L₃-10)/(-200) = 0.015/80L₃-10 = (-200)(0.015/80)L₃-10 = -0.0375L₃ = 10-0.0375L₃ = 9.9625 cm.Hence, The Length of the rod at the freezing point of water is 9.9625 cm.
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answer the question in the picture
Answers
The option that represents what the magnetic field look like above the North pole is an arrow that decreases as we go up and points up (E)
How to explain the informationThe magnetic field lines of a magnet point away from the north pole and towards the south pole. The field lines are strongest at the poles and weaken as you move away from the poles.
So, the arrow that represents the magnetic field above the north pole will be pointing up, but it will become smaller and smaller as you go up.
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The four particles as connected by rods of negligible mass as fig below. if the origin is the canter of rectangle and the system rotates in the XY plane about the Z axis with an rad angular speed of 12. calculate S a) The moment of inertia of the system about Z axis and b) The rotational kinetic energy of the system 3.00 kg 2.00 kg y(m) 2.00 kg 6.00 m 4.00 kg ---x(m)
Answers
The moment of inertia of the system about the Z-axis is 245 kg m², and the rotational kinetic energy of the system is 21168 J.
The moment of inertia of a system about its axis of rotation is the sum of the products of the masses of its constituents and the square of their respective distances from the axis of rotation.
The radius of the rectangular plate is 6 m, and the distance of each particle from the center is half of the sides of the rectangle, which are 4 m and 3 m.
Therefore, using the parallel axis theorem, we get the moment of inertia of the system about the Z-axis as shown below.
\(Iz = ICM + MR^{2}\)
(1)We can obtain the moment of inertia of the rectangle about its center as: \(ICM = (1/12) ML^{2}\)
(2) where M is the mass of the rectangle, and L is the length of the rectangle.
Substituting values, we get: ICM = \((1/12) $\times$ 3.00 $\times$ (4^{2} + 6^{2} )\)
ICM = \(5 kg m^{2}\)
Using the parallel axis theorem, the moment of inertia of the four particles about the center of the rectangle is:
\(IP = 4 $\times$ [(1/12) $\times$ 2.00 $\times$ (4^{2} + 3^{2})] + 2.00 $\times$ (3^{2}) + 4.00 $\times$ (4^{2})IP = 97 kg m^{2}\)
The moment of inertia of the system about Z-axis is: \(Iz = ICM + MR^{2} Iz = 5 kg m^{2} + 3.00 kg $\times$ (6^{2} ) + 4 $\times$ [(4^{2}+ 3^{2} )/4] Iz = 245 kg m^{2}\)
The kinetic energy of a rotating body is given as:\(K.E. = (1/2) I\omega^{2}\) where I is the moment of inertia of the system, and ω is the angular velocity of the system.
The rotational kinetic energy of the system is:\(K.E. = (1/2) I\omega^{2} K.E. = (1/2) $\times$ 245 $\times$ (12)^{2} K.E. = 21168 J\)
2)\(I\omega^{2} K.E. = (1/2) $\times$ 245 $\times$ (12)^{2} K.E. = 21168 J\)
Therefore, the moment of inertia of the system about the Z-axis is 245 kg m², and the rotational kinetic energy of the system is 21168 J.
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What is the mass of a person that has 4336500 joules of potential energy standing at the top of Mt. Everest at 8850 meters?
Answers
The mass of the person standing at the top of Mt. Everest with 4336500 joules of potential energy is approximately 49.1 kilograms.
To find the mass of the person standing at the top of Mt. Everest, we can use the formula for potential energy:
Potential Energy (PE) = mass (m) x acceleration due to gravity (g) x height (h)
We know that the potential energy (PE) is 4336500 joules, the height (h) is 8850 meters, and the acceleration due to gravity (g) is 9.8 m/s^2. So, we can rearrange the formula to solve for the mass (m):
m = PE / (g x h)
Substituting the given values, we get:
m = 4336500 J / (9.8 m/s^2 x 8850 m)
m ≈ 49.1 kg
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Lightning flashes and you hear a thunderclap 4 seconds later. The velocity of sound is 340 m/s. How far away did the lightning strike?
Answers
Answer:
1,360 m
Explanation:
340 meters per second, and it was 4 seconds later.
340 * 4 is how to find teh distance where the lightning struck.
340 * 4 = 1,360 meters
friction between two flat surfaces can be divided into two categories. what are the two most common kinds of friction?
Answers
Answer:
kinetic and static
Explanation:
hope it helps! ^w^
A cloth hat and large rock are dropped at at the same time on the moon
Answers
Answer:
What’s the question??
Explanation:
Earth’s gravitational field is 7.51 N/kg at the altitude of the space shuttle. What is the size of the force of attraction between a student of mass 53 kg and Earth? Answer in units of N.
Answers
Explanation:
395.53 N
The force of attraction between a student of mass 53 kg and Earth is calculated using the equation F = G*m1*m2/r^2, where G is the gravitational constant (7.51 N/kg), m1 is the mass of the student (53 kg), m2 is the mass of Earth, and r is the distance between them (the altitude of the space shuttle). Plugging in these values, we get F = 7.51*53*5.97e24/((6.37e6 + 6.37e6)^2) = 395.53 N.
Discerning between common characteristics is one advantage of a dichotomous key.true or false
Answers
Answer:
A two-choice sorting device used in taxonomy to identify taxa, genus species, or common names of plant or animal specimens. ... A key is used to identify a plant or animal. true. Discerning between common characteristics is one advantage of a dichotomous key
Explanation: true
Answer:
The answer is true.
How would the scientists predict the motion of each of the markers relative to the edges of the valley down which the glacier flows? What pattern would they predict in the markers over time?
Answers
Answer:
Glaciologists use Glen–Nye Flow Law, to predict the movements of glaciers.
Explanation:
In some parts of the world, glaciers are an important natural resource. This is so because the nature and behaviour of glaciers are an impact the hydrologic, geologic, and ecological systems of their immediate location.
Due to the above, Glaciologists monitor and try to predict the movement and morphology of glaciers.
One of the techniques used by Glaciologists in the monitoring and prediction of glaciers in the use of markers.
The movement of markers is measured relative to the edges of the valley down which the glacier flows. The movement of the markers are then predicted using the Glen–Nye Flow Law.
The Glen–Nye Flow Law is expressed mathematically as follows:
∑= \(kr^{n}\)
∑= shear strain (flow) rate
r = stress
n = a constant between 2–4 (typically 3 for most glaciers) that increases with lower temperature
k = a constant dependent on temperature
Cheers!
What is heredity and how does it influence physical fitness?
Answers
Brainliest if correct
Answers
Answer:
B 1,3, and 4
Explanation:
please answer this question
Answers
Answer:
Pic not clear.........
What two states of matter are pictured in the image below?
Answers
Answer:
volume liquid
Explanation:
What blew up billions of years ago in space
Answers
Answer:
i'am a french personn i use a traductor
Explanation:
Des astronomes ont débusqué une explosion cosmique vieille de 10,5 milliards d'années. Une énorme explosion cosmique vieille de 10,5 milliards d'années: des astronomes annoncent mardi avoir découvert la supernova, une étoile en fin de vie, la plus lointaine jamais détectée
People travel from all over the world to see more than 30 glaciers at Glacier National Park in Alaska.
Which factor causes glacial movement downhill?
A. gravity
B. oceans
C. snow
D. wind
Answers
Explanation
During the day when temperatures are higher, the snow melts and water enters the cracks in the rock. When the temperature drops below 0°C the water in the crack freezes and expands by about 9 per cent. This makes the crack larger.
Glaciers move by sliding over bedrock or underlying gravel and rock debris. With the increased pressure in the glacier because of the weight, the individual ice grains slide past one another and the ice moves slowly downhill.
An atom that loses an electron is called a/an
A. Valence electron
B. bond
C. anion
D. cation
Answers
A student drops a pen from a classroom window on the third floor of the mathematics building. If the pen is dropped from33 ft above ground level, at what velocity does the pen hit the ground? Use - 32 ft/s2 for the acceleration caused by gravity.Ignore air resistance. Round any intermediate calculations to no less than six decimal places, and round your final answer totwo decimal places.
Answers
Answer:
45.96 m/s
Explanation:
To find the velocity when the pen hits the ground, we will use the following equation
\(v^2_f=v^2_i+2ay\)Where vf is the velocity when the pen hits the ground, vi is the initial velocity, a is the acceleration and y is the height of the building.
So, replacing vi = 0 m/s, a = -32 ft/s², and y = -33 ft, we get
\(\begin{gathered} v^2_f=0^2+2(-32)(-33) \\ v^2_f=2112 \\ vf=\sqrt[]{2112} \\ v_f=45.96\text{ m/s} \end{gathered}\)Then, the pen hit the ground at 45.96 m/s
what is angular motion
Answers
Answer:
The motion of a body about a fixed point or fixed axis.
Explanation:
Brainly
POSSIBLE POINTS: 10
A circuit has a source voltage of 100 volts, a switch, and a light bulb with a resistance of 1000 Ohms. What is the amount of
current flowing through the circuit?
Answers
Answer:
V=IR
I=V/R
I=100/1000
I=0.1A
light from proxima centauri takes 4.3 years to reach the earth. How far away is the Proxima Centauri?
Answers
Answer:
4.246 light years
Explanation:
4.246 light years
The closest star, Proxima Centauri, is 4.24 light-years away. A light-year is 9.44 trillion km, or 5.88 trillion miles. That is an incredibly large distance. Walking to Proxima Centauri would take 950 million years.
HOPE IT HELPS.
PLEASE MARK ME AS BRAINLIEST.
Answer:
4.25 light years
Explanation:
a light year is the distance light travels in one year it is equal to 9.461 x 1012 km. alpha centauri A & B are roughly 4.35 light years away from us. proxima centauri is slightly closer at 4.25 light years.
What is the acceleration of a 4,000 kg car pushed with a
force of 12,000 N?
Answers
Answer:
3 m/s
Explanation:
A= F/m
12,000/ 4000 = 3
Answer:
3 m/s^2
Explanation:
The equation you have to use is F=ma because the problem is a Newton's 2nd law problem.
Our known values are:
F ( Force ) = 12,000 N
m ( mass ) = 4,000 kg
a ( acceleration ) = ?
Now we plug in the known values into the equation and solve
F=ma
12,000=4,000a
We have to divide 4,000 by both sides to isolate the a value
12,000/4,000=4,000/4,000a
The 4,000s on the right of the equation cancel.
And 12,000 divided by 4,000 equals 3
The acceleration (a) is 3 meters per second squared (m/s^2)
Next, check to make sure 3 does work by plugging it back into the equation.
12,000=4,000*3
12,000=12,000 ✔
As you can see, the acceleration will be 3 m/s^2
What is the maximum wavelength of light needed to eject electrons from a metal whose work function is 4.48 eV? What is the frequency of the light?
Answers
Given,
The work function of the metal, W=4.48 eV
The work function is given by the formula,
\(W=h\upsilon_0\)Where ν₀ is the threshold frequency of the metal.
But the frequency is related to wavelength as,
\(\upsilon=\frac{c}{\lambda}\)Where c is the speed of light and λ is the wavelength.
Thus the work function will be,
\(W=\frac{hc}{\lambda_0}\)Where λ₀ is the maximum wavelength needed to eject the electron from the given metal.
On substituting the known values in the above equation,
\(\begin{gathered} 4.48\times1.6\times10^{-19}\text{ J}=\frac{6.63\times10^{-34}\text{ Js}\times3\times10^8\text{ m/s}}{\lambda_0} \\ \Rightarrow\lambda_0=\frac{6.63\times10^{-34}\text{ Js}\times3\times10^8\text{ m/s}}{_{}4.48\times1.6\times10^{-19}\text{ J}} \\ =277.48\times10^{-9}\text{ m} \end{gathered}\)Thus the maximum wavelength of the light required is 277.48 nm.
The frequency of the light is,
\(\begin{gathered} \upsilon_0=\frac{c}{\lambda_0} \\ =\frac{3\times10^8}{277.48\times10^{-9}} \\ =1.08\times10^{15}\text{ Hz} \end{gathered}\)Thus the frequency of the required light is 1.08×10¹⁵ Hz.
Harold is using what he knows about cause-and-effect relationships to write a paper explaining cloud shape. How could he describe cause and effect in his paper?
Answers
Harold could use cause-and-effect relationships to describe the formation of different cloud shapes in his paper by explaining how certain environmental factors cause specific cloud formations to occur by explaining the changes in temperature, humidity, and air pressure.
Explain the formation of clouds?Clouds form when warm, moist air rises and cools, causing the water vapor to condense into tiny water droplets or ice crystals. These droplets or crystals then cluster together to form visible clouds in the atmosphere.
To explain the cause-and-effect relationships, Harold could use phrases like "as a result of," "because of," "due to," and "resulting in." For example, he could write, "When warm, moist air rises and cools, it causes water droplets to condense into cumulus clouds," or "High-altitude cirrus clouds are formed due to the presence of ice crystals in the atmosphere."
By using cause-and-effect relationships in his paper, Harold can help readers understand how and why different types of clouds form, and how they are influenced by various environmental factors.
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