A sports car can go from a state of rest to 36 meters per second in 3 seconds.
What is the car's average acceleration?

10 m/s
120 m/s²
120 StartFragment m/s²
12 m/s²
12 StartFragment m/s²
120 m/s

Answer:

magnitude is 1382.59 N/C

Explanation:

Given the data in the question;

The time taken is;

t = x / v

we substitute;

t = ( 2 × 10⁻²) / ( 5.69  × 10⁶ )

t = 3.5149 × 10⁻⁹ s

next, the acceleration is;

a = 2y/t² = [2( 0.150 × 10⁻²)] / [ ( 3.5149 × 10⁻⁹ )² ]

a =  2.42826 × 10¹⁴ m/s²

now, the electric field is;

E = ma / q

we know that;

mass of electron m = 9.11 × 10⁻³¹ kg,

charge of electron q = 1.60 × 10⁻¹⁹ coulomb

we substitute

E = ( 9.11 × 10⁻³¹ )(2.42826 × 10¹⁴) / 1.60 × 10⁻¹⁹

E = 2.21214 × 10⁻¹⁶  / 1.60 × 10⁻¹⁹

E = 1.3826 × 10²¹

E = 1382.59 N/C

Therefore, magnitude is 1382.59 N/C  

Answer:

Explanation:

Angle:

β = - 23°

( From the symmetry condition)

The force required to extend a rod increases as the cross sectional area

increases.

The rod that experiences the largest force is rod B

Reason:

The elongation of a rod by the application of a force is given by the

following formula;

\(\Delta L = \dfrac{F \cdot L}{A \cdot E}\)

From the above equation, we have that the elongation is inversely

proportional to the cross sectional area, such that the extension of a rod by

a given force reduces as the cross sectional area of the rod increases.

Therefore, the force required to extend the length of a rod by a specific

amount increases as the cross sectional area of the rod increases,

indicating that the rod with the largest cross sectional area require the

most force and therefore, experiences the largest force.

The rod that experiences the largest force is the rod with the largest cross

sectional area, which is rod B

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Given:

The speed of sound in water is,

The signal returns after

To find:

The depth of the ocean

Explanation:

The distance traveled by sound in this sound is,

The depth of the ocean is,

Hence, the depth is 2868.75 m.

As the time of motion increases, the velocity of the object increases downwards.

The given parameters;

The final velocity of the object at different time is calculated as follows;

when the time = 1 second;

v = v₀ - gt

v = 9.8  - 9.8(1)

v = 0

when the time = 2 second;

v = v₀ - gt

v = 9.8 - 9.8(2)

v = -9.8 m/s

when the time = 3 second;

v = v₀ - gt

v = 9.8 - 9.8(3)

v = -19.6 m/s

Thus, we can conclude that as the time of motion increases, the velocity of the object increases downwards.

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Answer:

67.28 N

Explanation:

Given that,

The mass of an box, m = 15.2 kg

The coefficients of static and kinetic frictions for plastic on wood are 0.55 and 0.36, respectively.

The force of static friction,

\(F_s=\mu_smg\\\\F_s=0.55\times 15.2\times 9.8\\\\F_s=81.92\ N\)

The force of kinetic friction,

\(F_k=\mu_kmg\\\\F_k=0.36\times 15.2\times 9.8\\\\F_k=53.62\ N\)

Net force acting on the object is :

F = 120.9 -53.62

= 67.28 N

Hence, this is the required solution.

Answer:

which can cause an object with mass to change its volocity

Answer: That depends on what other components are in the same circuit

along with the 15-ohm resistor.

If there's nothing else, and the battery is connected across the 15-ohm

resistor, then when you measure the voltage across the 15-ohm resistor,

your voltmeter is also connected straight across the battery, and you read

10 volts.

Explanation:

Answer:

what are the choices

Explanation:

Answer:

Landforms are a result of a combination of constructive and destructive forces. Collection and analysis of data indicates that constructive forces include crustal deformation, faulting, volcanic eruption and deposition of sediment, while destructive forces include weathering and erosion.

Explanation:

The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:

Hello There!!

Explanation:

Work done= force × distance moved

Work done=5000N×15m

Work done=75,000J

hope this helps,have a great day!!

~Pinky~

The value added by the baker is $3. The bread's contribution to GDP is the final sale price of the bread, which is $6

In this scenario, each person involved in the production and sale of the bread adds value to the final product. The concept of value added refers to the increase in the market value of a product at each stage of production.

The farmer grows the wheat and sells it for $1. The value added by the farmer is $1.

The miller processes the wheat into flour, increasing its value. The miller sells the flour to the baker for $3, so the value added by the miller is $3 - $1 = $2.

The baker uses the flour to make bread, further adding value to the product. The baker sells the bread to the engineer for $6, so the value added by the baker is $6 - $3 = $3.

The engineer consumes the bread, but since no further economic value is added, there is no additional value added by the engineer.

The bread's contribution to GDP (Gross Domestic Product) is the final sale price of the bread, which is $6. GDP measures the total value of all goods and services produced within a country's borders, and the sale of the bread represents the final output of the production chain.

Overall, the value added at each stage contributes to the final price of the bread, and the final sale price of the bread represents its contribution to GDP.

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Answer:

control

Explanation:

you always need a control in experiment

The new distance of the 3.78 nC particle when the electrostatic force is doubled is 0.049 m.

The magnitude of the electrostatic force experienced by the 3.78 n C particle when it is 0.069 m from the 2.15 nC particle is calculated as follows;

F = kq₁q₂ / r²

where;

F = ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 0.069² )

F = 1.536  x 10⁻⁵ N

When this electrostatic force is doubled, the new distance of 3.78 nC particle from the 2.15 nC is calculated as;

r² = kq₁q₂ / 2F

r = √ ( kq₁q₂ / 2F )

r = √ [ ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 2 x 1.536  x 10⁻⁵ ) ]

r = 0.049 m

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The magnitude of the angular acceleration of the roller is approximately 108.8 rad/s².

To find the magnitude of the angular acceleration of the roller, we can use the rotational analog of Newton's second law: τ = Iα, where τ is the torque, I is the moment of inertia, and α is the angular acceleration.

First, let's calculate the moment of inertia of the roller. The moment of inertia of a solid cylinder rotating about its central axis is given by the formula: I = (1/2)mr², where m is the mass and r is the radius.

Given:

Mass of the roller (m) = 2.4 kg

Radius of the roller (r) = 3.8 cm = 0.038 m

Moment of inertia (I) = (1/2) * 2.4 kg * (0.038 m)² = 0.0021744 kg·m²

Next, we need to calculate the torque (τ) applied to the roller. Torque is given by the formula: τ = rFsin(θ), where r is the distance from the axis of rotation to the point of application of the force, F is the magnitude of the force, and θ is the angle between the force and the line connecting the axis of rotation and the point of application.

Given:

Force applied (F) = 16 N

Angle (θ) = 35°

Distance from the axis of rotation to the point of application (r) is equal to the radius of the roller, so r = 0.038 m.

Torque (τ) = (0.038 m) * (16 N) * sin(35°) = 0.2366 N·m

Now, we can use the equation τ = Iα and solve for the angular acceleration (α):

0.2366 N·m = (0.0021744 kg·m²) * α

α = 0.2366 N·m / 0.0021744 kg·m² ≈ 108.8 rad/s²

Therefore, the magnitude of the angular acceleration of the roller is approximately 108.8 rad/s².

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Answer:

a)  P = 4.03 10⁵ Pa, b)  P = 4.03 10⁵ Pa

Explanation:

a) The pressure as a function of the depth of a fluid is

          P =\(P_{atm}\) + ρ g y

where Patm is the atmospheric pressure, the sea density of about 1025 kg / m³

let's calculate

         P = 1.01825 10⁵ + 1025 9.8 30

         P = 4.03 10⁵ Pa

b) When the hood is submerged, the water exerts a perpendicular force on the entire surface, in the equilibrium position, the air is compressed by this force until the pressure it exerts is equal to the external pressure (open at the lower), therefore the air pressure is

        P = 4.03 105 Pa

"\(3.958\times 10^5 \ Pa\)" would be the pressure outside the bell .as well as the air pressure inside it. A further explanation is below.

According to the question,

Depth,

Pressure,

             \(= 1.018\times 10^{5} \ Pa\)

Now,

→ The water pressure outside the bell will be:

= \(P_o +p\times g\times d\)

By putting the values, we get

= \(1.018\times 10^5+1000\times 9.8\times 30\)

= \(3.958\times 10^5 \ Pa\)

And inside the air pressure will be same as the water pressure.

Thus the response above is right.

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The kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.

The total energy of the system is conserved. The initial energy of the system is the electrostatic potential energy, which is given by:

U = k × (Q₁ × Q₂) / r

where:

U = potential energy in joules

k = Coulomb's constant (8.988 x 10⁹ N m²/C²)

Q₁ and Q₂ = charges in coulombs

r = distance between the charges in meters

In this case:

U = 8.988 x 10⁹ N m²/C² × (12 C × 5 Q) / (1.0 m) = 5.375 x 10⁻⁷ J

The final energy of the system is the kinetic energy of particle B. The kinetic energy is given by:

KE = 1/2 × m × v²

where:

KE = kinetic energy in joules

m = mass in kilograms

v = velocity in meters per second

Solve for the velocity of particle B using the conservation of energy equation:

KE = U

Substituting the expressions for KE and U gives:

1/2 × m × v² = 5.375 x 10⁻⁷ J

Solving for v gives:

v = √(2 × 5.375 x 10⁻⁷ J / m)

= 1.53 m/s

The kinetic energy of particle B is then:

KE = 1/2 × m × v²

= 1/2 × m × (1.53 m/s)²

= 4.32 J

Therefore, the kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.

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Answer:

2.29 s

Explanation:

This problem is a description of an elastic collision (the two objects collide and effectively become one object).  The equation for an elastic collision is

\(m_1v_1+m_2v_2=m_3v_3\), where:

\(m_1v_1\) = the mass of the child (55.0 kg) times the velocity of the child (2.5\(\frac{m}{s}\))

\(m_2v_2\) =  the mass of the sled (12.0 kg) times the velocity of the sled (0.0\(\frac{m}{s}\))

\(m_3v_3\) = the combined mass of the child and the sled (67.0 kg) times the combined velocity of the child and the sled (\(v_3\))

First, rearrange the problem to solve for \(v_3\):

\(\frac{m_1v_1+m_2v_2}{m_3}=v_3\)

So,

\(\frac{(55.0\ kg)(2.5\ \frac{m}{s})+(12.0\ kg)(0.0\ \frac{m}{s})}{67.0\ kg}=v_3\\\frac{137.5\frac{kg*m}{s}}{67.0\ kg}=v_3\\2.05\frac{m}{s}=v_3\)

The force of friction for this problem is given as 60 N.  To stop the child and the sled, the force of friction must be equal and opposite to the force of the child and sled.  According to Newton's first law, force equals mass times acceleration (F=ma).  So, an equation to solve this portion of the problem can be given as -60 N=ma, where m=67.0 kg.  So,

\(-60\ N=(67.0\ kg)a\\\frac{-60\ \frac{kg*m}{s^2}}{67.0\ kg}=a\\-0.90\frac{m}{s^2}\)

Acceleration can then be used in kinematic equation #1 (\(v_f=v_i+at\)) to solve for time.  Rearrange the equation and let

\(v_f=0.0\frac{m}{s}\\v_i=2.05\frac{m}{s}\\a=-0.90\frac{m}{s^2}\)

So,

\(\frac{v_f-v_i}{a}=t\\\frac{0.0\frac{m}{s}-2.05\frac{m}{s}}{-0.90\frac{m}{s^2}}=t\\\frac{-2.05\frac{m}{s}}{-0.90\frac{m}{s^2}}=t\\2.29\ s=t\)

Answer:

1.625 Pounds Explanation:

The equivalent temperature in Celsius scale is (86°F − 32) × 5/9 = 30°C

Take the °F temperature and subtract 32

Multiply this number by 5.

Divide this number by 9 to obtain your answer in °C.

The formula to convert °F to °C is:

T(°C) = (T(°F) - 32) × 5/9

converting 86 degrees Fahrenheit into degrees Celsius:

T(°C) = (86°F - 32) × 5/9

T(°C) = 30 °C

(86°F − 32) × 5/9 = 30°C

When doing the temperature conversion, one quick way to make certain you did the conversion right is to remember Fahrenheit temperatures are higher than the corresponding Celsius scale until you get down to -40°, which is where the Celsius and Fahrenheit scales meet. Below this temperature, degrees Fahrenheit are lower than degrees Celsius.

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Answer:

They have the same acceleration.

Explanation:

50km/h to 60km/h = 10km/h

0km/h to 10 km/h = 10km/h

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Answer:

they have a same acceleration

Explanation:

50km/h to 60 km/h=10km/h

0km/h to 60 km/h=10km/h

Answer:The correct statement about electric charges is:

"An object with a negative charge and an object with a positive charge will attract each other."

Explanation:

*an object with a negative charge and an object with a positive charge will attract each other" this statement is true.

Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C.

Hence option B is correct.

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A car is moving at 16 m/s at a time t = 0. With an acceleration of 0.50t, in m/s², for t, in seconds, it slows down. At t = 8 seconds, it stops. Option D is correct.

The change of displacement with respect to time is defined as the velocity.  velocity is a vector quantity.

Given data;

t = 0 ,u=16 m/s

acceleration = −0.50t m/s²

v=0,t=?

The acceleration is found as;

\(\rm a= \frac{dv}{dt} \\\\\ dv=adt \\\\ dv=-0.50 \ t dt\)

Intregating both sides we get;

\(\rm [v]_0^{16}=-0.50\frac{t^2}{2} \\\\ 16=0.25 t^2\\\\\ t^2=\frac{16}{0.25} \\\\\ t= 8 \ sec\)

Hence, the car stops at t=8sec. Option D is correct.

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Answer:

B. 686N

Explanation:

well do not write this because of I made a big mistake in my calculations

The tension on Box A if the acceleration of the system is provided clockwise is 686N.

The tension is the force of pulling in the linear objects.

Given is the system of two masses hung over a pulley with a string. Mass of block A, M(A) =35kg, M(B) = 20kg and the acceleration clockwise a =-2.67 m/s²

The tension in the string of each block = T =m(g-a)

Substitute the values, we get

T = 35 x (9.81-(-2.67)) +20(9.81 +2.67)

T =436.8 N + 249.6

T = 686.4 N

Thus, the tension in the the block A will be approximately 686N.

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The methods to determine the specific charge of an electron are The J. J. Thomson Method and The Millikan Oil Drop Method.

The J. J. Thomson Method

In this method, an electric field is created between two parallel metal plates. Electrons are accelerated by this field from the negative plate to the positive plate. After that, they strike a fluorescent screen. When the electrons are shot through the electric field perpendicular to the magnetic field, they experience the Lorentz force, which is given by the formula: $F= evB$ $F= evB$

When a magnetic field is applied at right angles to an electron beam, it bends the path of the beam into a circular path. The radius of the path of an electron beam in a magnetic field is determined by the relationship:r = mv/eB. As a result, the specific charge of an electron may be calculated from the expression: $e/m = 2V / B^2r^2$

The Millikan Oil Drop Method

This is another technique for determining the specific charge of an electron. The oil drop experiment was first done by Robert A. Millikan in 1909. He did this experiment by suspending charged droplets of oil in a uniform electric field between two parallel plates.

The fall of the oil droplets in the absence of an electric field was also noted. The fall velocity of the oil droplet was determined by measuring the time taken by the oil droplet to pass through a fixed distance between the plates in the absence of an electric field. By measuring the electric field strength, the voltage applied to the plates, and the fall velocity of the oil droplet, the specific charge of the electron was determined.

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The methods to determine the specific charge of an electron are :

In the J. J. Thomson Method, an  electric field is created between two parallel metal plates. Electrons are accelerated by this field from the negative plate to the positive plate. After that, they strike a fluorescent screen.

When the electrons are shot through the electric field perpendicular to the magnetic field, they experience the Lorentz force.

The Millikan Oil Drop Method is an experiment by which is created by suspending charged droplets of oil in a uniform electric field between two parallel plates.

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projectile's vertical speed v yv y v, start , y,  drops prior to reaching its maximum height since its acceleration is in the opposite direction. Since the object's height is rising, the initial direction of the velocity is upward

.

At the projectile's highest point, vertical velocity zeroes out. After reaching the highest point, the vertical speed increases due of the same-direction acceleration. As the object's height lowers, the vertical velocity has a downward direction.

In projectile The beginning vertical velocity determines the maximum height. Increasing the launch angle raises the maximum height because steeper launch angles have a larger vertical velocity component.

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Answer:

4.167m/sec

Explanation:

1km=1000m

1.5km=1500m

1min=60sec

6min=360sec

In 360sec they travel 1500m

In 1 sec they travel=1500m/360

1sec=4.167m

Explanation:

It is given that,

The position of a particle is given by :

\(r(t)=(3t^2i+5j-6tk)\ m\)

(a) Velocity of a particle is given by :

\(v=\dfrac{dr(t)}{dt}\)

Putting values,

\(v=\dfrac{d}{dt}(3t^2+5-6t)\\\\v=(6ti-6k)\ m/s\)

The acceleration of the particle is given by :

\(a=\dfrac{dv}{dt}\\\\a=\dfrac{d}{dt}(6t-6)\\\\a=6i\ m/s^2\)

(b) At t = 0,

Velocity, v = 6k m/s

Acceleration, a = 6i m/s²