a spinning top completes 6.00×10^3 rotations before it starts to topple over. the average angular speed of the rotations is 8.00×10^2 rpm. calculate how long the top spins before it begins to topple.

Answer: Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant

Explanation:

Answer: Boyle's law states that when the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature.

Explanation:

Answer: Provided temperature remains constant, the volume and pressure of a gas are inversely related.

Explanation: Robert Boyle discovered that as long as the temperature of a gas remains constant, the relationship between the volume and the pressure of the gas is inverse. Basically, as the volume of a gas increases, its pressure decreases. As the pressure of the gas increases, its volume decreases.

Answer:

As the stone is falling totally under the influence of gravity and toward the earth surface the acceleration is due to gravity and positive. Hence acceleration due to gravity,g is 4m/s²

Answer:

6.37*10^6 m

Explanation:

We know that,

g = GM/R²

values given to us

acceleration due to gravity = g = 9.8 m/s²

Mass of the earth is= 6.4*10^24

G = 6.67*\(10^{-11}\)

implementing

9.8 = 6.67*10^-11 * 6*10^24/R^2

9.8 = 40.02 * 10^13/ R^2

R^2 = 4002/98 * 10^12

R^2 = 40.83* 10^12

R= 6.37*10^6 m   (approximately)

Answer:

increasing the masses of the objects and decreasing the distance between the objects

Answer:the objects have the same acceleration

Explanation:

Answer:

Height of the first projectile = 49.98 m

Height of the second projectile = 72.52 m

Explanation:

From the given information;

Two projectiles are thrown from the same point with the velocity of49m/s

First is  projected making an angle  θ with the horizontal

and the second at an angle of 90 - θ.

Thus; for the first height to the horizontal; we have;

\(H_1 = \dfrac{v^2 sin^2 \theta}{2g}\)  ----- (1)

the second height in the vertical direction is :

\(H_2 = \dfrac{v^2 cos^2 \theta}{2g}\)    -----(2)

However; the second is found to rise 22.5 m higher than the first; so , we have :

\(\dfrac{v^2 cos^2 \theta}{2g}= 22.5 + \dfrac{v^2 sin^2 \theta}{2g}\)

Let's recall that :

Cos²θ = 1 - Sin²θ

Replacing it into above equation; we have:

\(\dfrac{v^2}{2g} - \dfrac{v^2 sin^2 \theta}{2g}= 22.5 + \dfrac{v^2 sin^2 \theta}{2g}\)

\(\dfrac{v^2}{2g} - 22.5 = \dfrac{v^2 sin^2 \theta}{g}\)

\(\dfrac{1}{2 } \dfrac{v^2}{g} - 22.5 = \dfrac{v^2 sin^2 \theta}{g}\)

\(\dfrac{1}{2 } - \dfrac {9.8 \times 22.5}{(49)^2} = sin^2 \theta\)

\(\dfrac{1}{2 } - \dfrac {220.5}{2401} = sin^2 \theta\)

\(sin^2 \theta= 0.408\)

From (1);

\(H_1 = \dfrac{v^2 sin^2 \theta}{2g}\)

\(H_1 = \dfrac{49^2 \times 0.408}{2*9.8}\)

\(H_1 = \dfrac{979.608}{19.6}\)

\(\mathbf{H_1 =49.98 \ m }\)

Height of the first projectile = 49.98 m

Similarly;

From(2)

\(H_2 = \dfrac{v^2 cos^2 \theta}{2g}\)    

\(H_2 = \dfrac{v^2 (1-sin^2 \theta)}{2g}\)

\(H_2 = \dfrac{49^2 (1-0.408 )}{2 \times 9.8}\)

\(H_2 = \dfrac{2401 (0.592 )}{19.6}\)

\(H_2 = \dfrac{1421.392}{19.6}\)

\(\mathbf{H_2 = 72.52 \ m}\)

Height of the second projectile = 72.52 m

Answer:

Newton first law

Explanation:

Newton's first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force. The hockey puck moved because you hit it. ( tell me if I helped I hope you do good)

Answer:

all of the above

Explanation:

they are in every cell

Answer:

all but Nucelus

Explanation:

nucieus is not it

The number of significant figures in 00.6022009 is 7 .

The number of significant figures is 7.

Explanation:

Significant figures

Given :

The number 00.6022009

To find:

The number of significant figures in the number.

Solution

00.6022009

All zero’s preceding the first integers are not significant.

Zeros in between the integers are significant

So, the number of significant figures is 7.

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Answer:

1.47 eV

Explanation:

We have,
Stopping potential = E
KE1(max) = 0.62 eV
Ф1 = 2.90 eV

We know KE(max) = E - Φ

0.62 = E - 2.9
So, E = 2.9 + 0.62 = 3.52 eV

Now, all we have to do is evaluate for the metal with Φ = 2.05 eV
KE(max)2 = 3.52 - 2.05 = 1.47 eV

Answer:

When the  water is frozen it turns to ice and the density decreases.

Explanation:

Have A Wonderful Day !!

Answer:

a = 0.175 m/s^2

Explanation:

From newtons eauations of motion we know

v=u+at

here v= final velocity, u= initial velocity, a = acceleration, t= time

u = o( initialy object must be at rest)

therefore, 3.5 = 0+ a(20)

⇒ a = 3.5/20 =0.175 m/s^2

I cant see the numbers but to find them heres an example 17 n would be at the top next to 15 and 20 if there on there and them you find the other number 105 w I think would be on the left then draw a straight line till they touch and wherever it is will be you answer and if you need further help search it up on here or google

Explanation:

ok so start on the latitude which is the lines that go left to right. it would be the first number in the parentheses.(latitude,longitude) so if the number is 17°North you would look on the right side of the map and find 17°N. It might show y 15°N so you have to try and find where you think 17°N would be. place you finger where you think 17°N is. then find 105°West which is longitude and is the lines that go up and down. and drag you fingers together in a straight line until they both meet and that is where the awnser is.

hope u understand

Answer:

Acceleration.

Explanation:

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

\(Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}\)

\(a = \frac{v - u}{t}\)

Where,

a is acceleration measured in \(ms^{-2}\)

v and u is final and initial velocity respectively, measured in \(ms^{-1}\)

t is time measured in seconds.

The S.I unit for measuring acceleration is meters per seconds square (m/s²).

Hence, 10 m/s^2 is an example of acceleration.

The initial angular momentum of the propeller before the torque was applied will be 32 kg m²/s.

Torque is the force's twisting action about the axis of rotation. Torque is the term used to describe the instant of force. It is the rotational equivalent of force. Torque is a force that acts in a turn or twist.

The amount of torque is equal to force multiplied by the perpendicular distance between the point of application of force and the axis of rotation.

The given data in the problem is;

The rotational inertia is,I  = 2.0 kg m²

The clockwise torque is, T = 4.0Nm

The time period is,t= 4.0s,

The angular speed is,ω= 24 * (rad)/s

The initial angular momentum of the propeller is,I₀

The angular acceleration is found by the relation;

\(\rm \tau = I \times \alpha \\\\ \alpha =\frac{\tau}{i} \\\\ \alpha =\frac{4.0}{2.0} \\\\ \alpha= 2.0 \ rad/sec^2\)

The initial angular velocity is found as;

\(\rm \omega_f = \omega_0 + \alpha t \\\\ \omega_0 = \omega_f -\alpha t \\\\ \omega_0 =24 -[(-2.0)\times 4.0)] \\\\ \omega_0 = 16 \ rad/sec\)

The initial angular momentum of the propeller is found as;

\(\rm L_0 = I \omega_0 \\\\ L_0 = 20 \times (1.6) \\\\ I_0 = -32 \ kgm^2/s\)

Hence,the initial angular momentum will be 32 kg m²/s.

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Answer: 14 kg•m2/s

Explanation:

Trust me it’s from khan

Answer:

An electrical charge is created when electrons are transferred to or removed from an object. Because electrons have a negative charge, when they are added to an object, it becomes negatively charged. When electrons are removed from an object, it becomes positively charged.

Answer:

Displacement = 1725m

Explanation:

\(t = \frac{u-v}{a}\)

\(t = \frac{65-50}{0.5} = 30s\)

\(s = ut+\frac{1}{2}at^{2} \\s = 50*30 + \frac{1}{2} *0.5*30^{2} = 1725m\)

The color of the star at 5900K is close to the color of the sun, that is yellow. So the color of the star at 5900K will be yellow.

The color of light emitted by a hypothetical opaque, non-reflective body at a specific temperature expressed in kelvins is known as color temperature. Regardless of the temperature of other light sources, the color of their light is classified using the color temperature scale.

One aspect of visible light is color temperature. Lower color temperatures (2700–3000 K) are referred to as "warm colors," while color temperatures over 5000 K are referred to as "cool colors" (bluish) (yellowish).

The Sun closely resembles a radiator with a black body. The total radiative power per square unit determines the effective temperature, which is approximately 5780 K. Over the atmosphere, sunlight has a color temperature of approximately 5900 K.

Therefore, the star with a temperature around 5900K will have a color similar to that of the sun which is yellow.

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There are 7.23 x 10^22 neon atoms present in a 2.68 L sample of neon gas at STP. (7.23e22)

At STP (standard temperature and pressure), one mole of any ideal gas occupies a volume of 22.4 liters. Neon is an ideal gas, and its atomic mass is 20.18 g/mol.

First, we need to calculate the number of moles of neon in a 2.68 L sample at STP:

n = V/ V_m

where n is the number of moles, V is the volume of the gas sample, and V_m is the molar volume of the gas at STP.

n = 2.68 L / 22.4 L/mol

n = 0.120 mol

Next, we can use Avogadro's number to calculate the number of neon atoms present in the sample:

N = n * N_A

where N is the number of neon atoms, n is the number of moles, and N_A is Avogadro's number (6.022 x 10^23 atoms/mol).

N = 0.120 mol * 6.022 x 10^23 atoms/mol

N = 7.23 x 10^22 atoms (7.23e22)

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To solve this problem, we can use the equation. Therefore, there are 6.73e22 ne atoms present in a 2.68e0 L sample of ne at STP.

n = (PV)/(RT)
Where n is the number of atoms, P is the pressure (which is 1 atm at STP), V is the volume (which is given as 2.68e0 L), R is the gas constant (0.08206 L·atm/K·mol), and T is the temperature (which is 273 K at STP).
Plugging in the values, we get:
n = (1 atm)(2.68e0 L) / (0.08206 L·atm/K·mol)(273 K)
n = 0.1119 mol
To convert from moles to atoms, we can use Avogadro's number, which is 6.02 x 10^{23} atoms/mol. So:
n atoms = (0.1119 mol)(6.02 x 10^{23} atoms/mol)
n atoms = 6.73e22 atoms
Therefore, there are 6.73e22 ne atoms present in a 2.68e0 L sample of ne at STP.

To determine how many Ne atoms are present in a 2.68e0 L sample of Ne at STP, follow these steps:
1. At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 L.
2. Find the moles of Ne in the given sample: moles of Ne = (2.68e0 L) / (22.4 L/mol) = 0.1196 moles
3. Convert moles of Ne to atoms using Avogadro's number (6.02 x 10^{23}): Ne atoms = (0.1196 moles) x (6.02e23 atoms/mol) = 7.20e22 Ne atoms
Therefore, there are 7.20e22 Ne atoms present in a 2.68e0 L sample of Ne at STP.

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Solar nebula flattening is a natural consequence of collisions between particles in a spinning cloud. therefore, option B is correct.

When a solar nebula collapses under its own gravity, it begins to spin due to the conservation of angular momentum. As the cloud spins, particles within it collide and interact. These collisions cause the cloud to flatten into a disk shape rather than remaining spherical.

Angular momentum plays a crucial role in this process. The initial slight asymmetry or irregularity in the nebula's shape leads to variations in the speeds and directions of the particles' motions. As particles collide and transfer momentum, their motion tends to align along the rotational axis of the cloud, promoting the formation of a flattened disk structure.

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Answer:

718.02N is the answer to the question

Answer:

you hit a golf ball to the moon

Explanation:

Answer:

You hit the ball and it flies

Explanation:

You hit the ball and it flies

Answer:

friction

air drag

every thing that opposes the motion affects kinetic energy

Explanation:

kinetic energy is a energy which is increase with increase in motion and potential energy is energy stored while the object is at rest

potential energy ∝ 1/(kinetic energy)

as kinetic energy increases potential energy decreases

The rocks of the Appalachian Blue Ridge are dominated by metamorphic rocks, specifically the type known as gneiss. Gneiss is a type of metamorphic rock that is formed when preexisting rocks, such as granite, shale, or volcanic rock, are subjected to high temperatures and pressures over a long period of time.

The resulting gneiss has a banded texture, with alternating light and dark layers that reflect the different minerals that were present in the original rock. Gneiss is a common rock type in the Appalachian Mountains, which was formed by the collision of tectonic plates over 300 million years ago. The Blue Ridge region, in particular, is characterized by a series of ridges and valleys that are sculpted from the resistant gneiss formations.

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The stretch in a spring can be calculated using the formula:

where delta_x is the stretch, F_spring is the force applied on the spring and k is the spring constant.

The force applied on the spring is equal to the weight of the mass, which is 7.3 kg, multiplied by the acceleration due to gravity (9.8 m/s^2):

So the stretch in the spring can be calculated as follows:

The Stretch of a spring is analogous to the vibration of a pendulum. This is because there is an alternating movement of the spring past the balance point. Stretch on the spring also has a tension restoring force according to Hooke's law: Fs = -K.X Where K is the spring constant, and X is the stretch length.

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This expression represents the varying slope of the terminal ray as it rotates counterclockwise from its initial position.

To answer this question, we first need to understand what is meant by the initial and terminal rays of an angle. An angle is formed by two rays that share a common endpoint, called the vertex. The initial ray is the one that forms the starting position of the angle, while the terminal ray is the one that rotates counterclockwise from the initial ray to form the angle.

In this case, the initial ray points in the 12-o'clock direction, which means it is vertical and pointing upwards. As the terminal ray rotates counterclockwise, it will move in a circular motion around the vertex, forming an angle of varying measure.

Now, if θ = 0.3, we can use the formula for the slope of a line to find the slope of the terminal ray. Since the initial ray is vertical, it has an undefined slope. However, as the terminal ray rotates counterclockwise, it will start to slope downwards. The slope of the terminal ray at any given angle can be found using the tangent function:

slope = tan(θ)

So, if θ = 0.3, we have:

slope = tan(0.3) ≈ 0.309

This means that the terminal ray has a slope of approximately 0.309 at an angle of 0.3 radians.

Next, we are asked to write an expression in terms of 4 that represents the varying slope of the terminal ray. Since the slope of the terminal ray is given by the tangent function, we can write:

slope = tan(θ) = tan(4x/4)

where x represents the angle measure in radians, and 4 is included to ensure that the angle measure stays within the range of the tangent function. This expression represents the varying slope of the terminal ray as it rotates counterclockwise from its initial position.

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Explanation:

They don’t like to stretch.

Due to the difference in net force delivered to the item in each situation, 250 N cannot push an object while the frictional force is 188 N, whereas 251 N may push the identical thing with rapid acceleration.

When friction is present, an object may continue to travel at a steady speed despite the application of an external force. The friction force simply balances the applied force in this scenario. There is no acceleration since there is no net force.

No, acceleration has no impact on the kinetic friction coefficient. The type of surfaces that make contact with one other and not the speed at which they are travelling determine the coefficient of kinetic friction, which is constant.

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Electrons are emitted from the cathode with a range of velocities. This phenomenon can be explained by considering the energy distribution of electrons within the cathode material.

Electrons in a metal are in various energy states, which are influenced by factors such as temperature and the presence of an electric field.

When a potential difference is applied across a cathode and an anode, the electric field created between them can cause some electrons in the cathode to gain enough energy to overcome the work function, which is the minimum energy needed for an electron to be emitted from the surface of the metal. The energy of these emitted electrons varies due to their initial energy states and the amount of energy gained from the electric field.

Thermal energy can also play a role in electron emission. At higher temperatures, a greater number of electrons in the cathode have sufficient thermal energy to overcome the work function. These thermally emitted electrons will also exhibit a range of velocities depending on their initial energy states and the amount of thermal energy gained.

In summary, electrons are emitted from the cathode with a range of velocities due to the different energy states within the cathode material and the various energy sources, such as the electric field and thermal energy, that can contribute to overcoming the work function.

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