A spherical conductor with a 0.193 m radius is initially uncharged. How many electrons should be removed from the sphere in order for it to have an electrical potential of 7.10 kV at the surface?

Answer:

43200 J

Explanation:

(1/2(mass)) (speed)^2

The acceleration of Thomas is 0.233 m/s^2.

Acceleration is the rate of change of velocity. Thomas the Train chugs along at a velocity of 2 m/s.

Thomas needs to go faster so more coal is shoveled into his engine and he accelerates for 10 seconds until he is going 4.33 m/s.

We are to find the acceleration of Thomas.

The formula for acceleration is given as :

acceleration = (final velocity - initial velocity) / time

In the given problem, the initial velocity of Thomas, u = 2 m/s.

The final velocity of Thomas, v = 4.33 m/s The time for which Thomas accelerates, t = 10 s.

Therefore, the acceleration of Thomas will be given as:

a = (v - u) / ta = (4.33 - 2) / 10s => 2.33 / 10s => 0.233 m/s^2

Thus, the acceleration of Thomas is 0.233 m/s^2.

To summarize, the acceleration of Thomas is 0.233 m/s^2.

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2.5 watt

Explanation:

we know

power = work done /time

work done gainst gravity is = mgh

as mg = weight = force = 5 N

and height = 2 m

so work done = mgh = 5*2 = 10N

therefore ,

Power = 10/4 = 2.5 watt

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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Answer: 10s

Explanation:

The time required for the object to  accelerate is 10 seconds.

Given the following data:

To find the time required for the object to  accelerate, we would use the first equation of motion:

Mathematically, the second equation of motion is given by the formula;

\(V = U + at\)

Where:

Substituting the parameters into the formula, we have;

\(28.0 = 8.0 + 2t\\\\2t = 28.0 - 8.0\\\\2t = 20.0\\\\t = \frac{20.0}{2}\)

Time, t = 10 seconds.

Therefore, the time required for the object to  accelerate is 10 seconds.

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The tax rate you will pay is displayed in tax brackets for each category of taxable income.

Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.

Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.

As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.

Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.

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Answer: 12 ounce steak on venus

Explanation: venus = closer to the sun. The sun = more potential gravity, which would make it heavier than a quarter pound hamburger on jupiter.

The time it takes the marble to travel from P to M, obtained using the kinematic equation of motion is about 0.8 seconds

The kinematic equations of motion are four equations that describe the motion of an object undergoing constant acceleration.

The horizontal distance from P to N = 60 cm = 0.6 m

The vertical distance from N to M = 50 cm = 0.5 m

Let v represent the horizontal velocity of the mable, we get;

The duration it takes the mable to travel from P to N, t₁ = 0.6/v

The duration it takes the marble to reach the base of the table can be found using the kinematic equation of motion as follows;

h = u·t + (1/2)·g·t²

u = 0 (The initial vertical velocity is zero)

h = 0.5 meters

Therefore;

0.5 = (1/2) × 9.8 × t²

t² = 0.5/((1/2) × 9.8)

t = √(0.5/((1/2) × 9.8)) ≈ 0.32

The horizontal distance traveled during the time of flight of 0.4 meters indicates;

v = 0.4/0.32 ≈ 1.25

Therefore, t₁ = 0.6/v = 0.6/(0.4/0.32) ≈ 0.48

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The maximum angle at which an object will not slip on an incline can be calculated using the coefficient of friction (μ).

When an object is on an inclined plane, there are two main forces acting on it: the gravitational force pulling it downward (mg) and the normal force (N) exerted by the inclined plane perpendicular to its surface. Additionally, there is a frictional force (F) acting parallel to the surface of the incline.

To prevent slipping, the frictional force must be equal to or greater than the force component pulling the object down the incline. This force component is given by the equation F = mg sin(θ), where θ is the angle of inclination.

The maximum frictional force that can be exerted between two surfaces is given by the equation F = μN, where μ is the coefficient of friction.

For an object not to slip, the maximum frictional force (F) must be equal to or greater than the force component pulling the object down the incline (mg sin(θ)). Therefore, we have:

F ≥ mg sin(θ)

Substituting F = μN, we get:

μN ≥ mg sin(θ)

Since N = mg cos(θ) (the normal force is equal to the component of the gravitational force perpendicular to the incline):

μmg cos(θ) ≥ mg sin(θ)

μ cos(θ) ≥ sin(θ)

Now, divide both sides of the equation by cos(θ):

μ ≥ tan(θ)

Taking the inverse tangent (arctan) of both sides, we get:

θ ≤ arctan(μ)

Therefore, the maximum angle at which an object will not slip on an incline is given by θ = arctan(μ).

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Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

If a rose with the genotype Yy is pale yellow in color, then there is not complete dominance for neither allele and it is a case of incomplete dominance. Nonetheless, since allele Y is for pale yellow and the hybrid has this phenotype, then it is partially dominant (pale yellow, Y, option 3).

Incomplete dominance is a genetic phenomenon in which one of the two alleles present for a given gene locus is expressed more strongly when compared to the other allele, which is called partially dominant and partially recessive alleles, respectively.

Conversely, complete dominance is due to the presence of an allele that completely masks the expression of the recessive allele in heterozygous hybrid individuals.

Therefore, with this data, we can see that incomplete dominance is associated with the expression of both alleles in the heterozygous hybrid individuals.

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Answer:

B

Explanation:

quantization of energy is only seen in atoms

Answer:

prototype - a first model of something

obsolete - out of date

Unintended Consequence - outcomes of actions that weren't predicted and intended

Feedback - reactions to something from someone like a customer

Explanation:

180 million km = 10 min

? = 1 min

180 million x 10 = 1,800,000,000 km

180 million km = 600s

? = l s

108,000,000,000km

The magnetic field that forms when a wire carries an electric current is a circular field that is strongest at the ends of the wire and weakest in the middle.

A current-carrying wire's magnetic field looks like a series of concentric circles that extend outward from the wire in both directions.

The magnitude of the magnetic field is greatest at the center of the wire and decreases as you move away from it.

The direction of the magnetic field is determined by the direction of the current flow: if the current is flowing clockwise around the wire, then the magnetic field will be pointing outward from the wire.

The magnetic field also has a north and south pole, so the direction of the field also depends on which direction around the wire the current is flowing.

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Answer:

the glove could be heavy so slowing down his power

Explanation:

JUST GUESSED

A parallel circuit can be modelled by connecting the components parallel.

A parallel circuit is a form of electrical circuit in which the components are linked in parallel to one another, each having a separate channel for current flow and being directly connected to the power source. The circuit must first be schematically represented, with the power supply and each component linked in parallel. Next, the total resistance the total current in the circuit by using Ohm's Law must be calculated.

Additionally, it is necessary to confirm that the total current entering the circuit equals the total current leaving the circuit. In a parallel circuit, the total current passing through all of the components equals the current entering the circuit. The voltage drop between each component must then be once more computed using Ohm's Law.

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Answer:

0.58 L

Explanation:

For this problem we need to simply use the ideal gas equation to create a proportional comparison for the initial information to the final information.

(P_1 * V_1) / T_1 = (P_2 * V_2) / T_2

Using this, we can solve for V_2 to find the new volume of the gas once pressure and temperature changes.

(P_1 * V_1) * T_2 / T_1 = (P_2 * V_2)

(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2

Consider our givens:

P_1 = 110atm

T_1 = 303K

V_1 = 2L

P_2 = 440atm

T_2 = 353K

Now we simply plug in these values to the equation to find the new volume, V_2.

(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2

(110atm * 2L) * 353K / (303K * 440atm) = V_2

77660 atm*L*K / 133320 K*atm = V_2

0.583 L = V_2

Hence, the new volume is 0.583 L.

Cheers.

Answer:

reducing the voltage of electric current in the coil

Explanation:

The water pressure at the bottom of the 54-m-high water tower is

pressure of water at a certain depth is calculated using the formula

Pressure, P = height * density * acceleration due to gravity

density of water is given by = 1000 kg/m³

acceleration due to gravity is given by = 9.82 m/s²

the given height, at the bottom of the 54-m-high water tower  = 54 m

Pressure = 1000 kg/m³ *  9.82 m/s² * 54 m

Pressure = 530280 N/m²

Pressure = 0.53 M N/m²

Pressure = 0.53 M Pa

The pressure at the bottom of the 54-m-high water tower is 0.53 MPa

The unit of pressure used here is Pa which is equal to N/m² other unit include pound - force foot

1 N/m² = 0.73756 pound-force foot

530280 N/m² = 530280 * 0.73756 = 391113.32 pound-force foot

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Answer:

ОА.

The net force acting on the car from all directions is zero.

Explanation:

Constant speed along a straight line

It means constant magnitude of velocity without chainging direction

It means constant velocity. Which means acclecration is zero

By Newton's second law:

\(F=ma\)

Net force is also zero

Answer:

The tension in the rope if it is parallel to the slope is 24.31 N.

Explanation:

Given;

mass of the sled, m = 9 kg

angle of inclination of the slope, θ = 16⁰

The tension in the rope if it is parallel to the slope is calculated from the parallel component of the tension;

\(T_|_| = mgSin \theta\\\\T_|_| = 9 \times 9.8 \times sin(16^0)\\\\T_|_| = 24.31 \ N\)

Therefore, the tension in the rope if it is parallel to the slope is 24.31 N.

Answer: reduced by 1/4

Explanation:

The force will be reduced by 1/4. Try plugging in 2r, then squaring it. You will get 4r^2, which is essentially dividing the force by 4

The law of conservation of momentum states that in an isolated system, the total momentum of two or more bodies acting on each other remains constant unless an external force acts on them. Therefore, it cannot create or destroy momentum.

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The expression for the work done is given as

*Here Q is the charge

*Here V is the potential difference

The work done in the electric circuit is the product of charge (Q) flows and the potential difference (V) in the circuit.

The basic standard unit for the work done is in Joules.

Answer:

Explanation:

To solve this problem, we can use the following equations for the addition of two sinusoidal waves:

y1 = A1 sin(ωt + φ1)

y2 = A2 sin(ωt + φ2)

where A1 and A2 are the amplitudes of the waves, ω is the angular frequency, t is time, and φ1 and φ2 are the initial phase angles.

(a) To find the resultant amplitude of the two waves, we can use the following equation:

Ar = √(A1^2 + A2^2 + 2A1A2cos(φ2 - φ1))

where Ar is the resultant amplitude.

Substituting the given values, we get:

Ar = √((3.0 × 10^(-6))^2 + (4.0 × 10^(-6))^2 + 2(3.0 × 10^(-6))(4.0 × 10^(-6))cos(150° - 60°))

Ar ≈ 5.03 × 10^(-6) m

Therefore, the resultant amplitude is approximately 5.03 × 10^(-6) m.

(b) To find the resultant's initial phase angle, we can use the following equation:

tan(φr) = (A1sin(φ1) + A2sin(φ2))/(A1cos(φ1) + A2cos(φ2))

where φr is the initial phase angle of the resultant wave.

Substituting the given values, we get:

tan(φr) = (3.0 × 10^(-6)sin(60°) + 4.0 × 10^(-6)sin(150°))/(3.0 × 10^(-6)cos(60°) + 4.0 × 10^(-6)cos(150°))

φr ≈ 142.85°

Therefore, the resultant's initial phase angle is approximately 142.85°.

(c) The circle of reference and the time graph for the sine waves can be drawn as follows:

Sine Waves

The blue and red arrows represent the maximum displacement of the waves. The black arrow represents the displacement of the resultant wave. The time graph shows the displacement of each wave and the resultant wave over time.

We have that the total distance covered by the runner is

\(d_t=20.723miles\)

The total distance covered by the runner is a sum of all miles covered by the runner

Therefore

With

\(d_t\)=Total distance

\(d_t=d_1+d_2+d_3\\\\d_t=9.5+8.89+2.333\)

\(d_t=20.723miles\)

in conclusion

The total distance covered by the runner is

\(d_t=20.723miles\)

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