A solution is prepared by dissolving 0.26 mol of hydrazoic acid and 0.26 mol of sodium azide in water sufficient to yield 1.00 L of solution. The addition of 0.05 mol of HCl to this buffer solution causes the pH to drop slightly. The pH does not decrease drastically because the HCl reacts with the ________ present in the buffer solution. The Ka of hydrazoic acid is 2.5 x 10^-5.

The acceleration of the car is -2.3m/s².

Acceleration is the rate at which the direction and speed of motion change over time. It is said to have been accelerated when something changes its direction and moves faster or slower. Motion on a circle accelerates even when the speed is constant because the direction is constantly changing.

Velocity is the rate at which displacement changes. The rate at which speed changes is known as acceleration. Because it consists of both magnitude and direction, velocity is a vector quantity. Since acceleration is merely the rate at which velocity changes, it too is a vector quantity.

v = u +at

0 = 35 + a×15

15a = -35

a = -35/15

a = -2.3m/s².

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Answer:

B. -2.3 m/s²

Explanation:

To answer this question, we have to use the following formula:
\(\boxed{a = \frac{v - u}{t}}\),

where:

• a ⇒ acceleration

• v ⇒ final velocity

• u ⇒ initial velocity

• t ⇒ time taken for the change in velocity to occur

From the question, we know that initially, the car was travelling at 35 km/h. Therefore, u = 35 km/h. The question also tells us that the car comes to a full stop, meaning its final velocity is 0 m/s. Therefore, v = 0 km/h. It takes the car 15 seconds to stop, so t = 15 s.

Using the information above and substituting it into the formula, we can calculate the acceleration of the car:

\(a = \frac{0 - 35}{15}\)

  = -2.3 m/s²

Therefore, the acceleration of the car is -2.3 m/s², and the correct answer is B.

Explanation:

Adding logs of same base is equivalent to multiplying the arguments. You get:

\( log_{3}(35x) = 4\)

Use the definition of the log to turn this into an exponential function:

\( {3}^{4} = 35x\)

\(81 = 35x\)

\(x = \frac{81}{35} \)

The concentration (molarity) of the final NaCl solution is 175 M.

To find the concentration (molarity) of the final NaCl solution, we can use the equation:

M1V1 = M2V2

Where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

In this case, we have an initial NaCl solution with a concentration of 2.5 M and a volume of 350 mL (0.350 L). We are diluting this solution to a total volume of 5.0 mL (0.005 L).

Plugging these values into the equation, we have:

(2.5 M) * (0.350 L) = M2 * (0.005 L)

Simplifying the equation:

0.875 = 0.005 * M2

Dividing both sides by 0.005:

M2 = 0.875 / 0.005

M2 = 175M

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Taking into account the reaction stoichiometry, 1 mole of H₂ can be produced by reacting 2 moles of HCI.

In first place, the balanced reaction is:

Mg + 2 HCl  → MgCl₂ + H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

By reaction stoichiometry 2 moles of HCl form 1 mole of H₂.

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The vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane the vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane is 164.83 torr.

The term vapor pressure is defined as the tendency of a material to change into the vapour state, and it increases with temperature.

For calculating mole fraction of C₂H₄Br₂ as follows

X C₂H₄Br₂ = moles of C₂H₄Br₂ / moles of C₂H₄Br₂ + moles of C₃H₆Br₂

= 0.3 / 0.3 + 1.80

= 0.14

For calculating mole fraction of C₃H₆Br₂ as follows:

XC₃H₆Br₂ =  moles of C₃H₆Br₂ / moles of C₂H₄Br₂ + moles of C₃H₆Br₂

= 1.80 / 2.1

= 0.85

For calculating total vapor pressure as follows:

P total = [ ( 0.14 × 127) + (0.85 × 173) ]

= 17.78 + 147.05

= 164.83 torr

Thus, The vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane the vapor pressure at 85.0°C of a solution prepared by dissolving 0.300 mol of liquid dibromoethane is 164.83 torr.

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Answer:

Vanadium (V), Niobium (Niobium), Tantalum (Ta), Dubnium (Db), Cerium (Ce), and Thorium (Th)

Explanation:

Groups go vertical (up and down) on the periodic table.

Periods go horizontal (left to right) on the period table.

Answer: weathering

Explanation: It is slowly by wind or by water

Answer:

Hi!

So, a homogeneous mixture is when the parts that make up the mixture are all mixed in perfectly evenly, so they're only appearing as one uniform substance.

In a heterogeneous mixture, the pieces are not evenly mixed. A pizza has separate parts, like the crust and toppings, so it's a heterogeneous mixture.    

The volume of the radiator solution formed with the 197 mL of antifreeze is 788 mL.

A percentage is given as the respective ratio of the quantity present with respect to others.

The solution of 25% v/v can be depicting the presence of a 25% volume of antifreeze in the radiator solution.

The volume of the radiator solution has 197 mL of antifreeze. The total volume of the solution suppose is x.

25% of x = 197 mL

25/100 * x = 197

x = 788 mL

The volume of the radiator solution formed with 25% v/v antifreeze is 788 mL.

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The compound that may be classified as a binary compound is NH4Cl.

A binary compound is a type of chemical compound that is composed of two different elements. These elements can be either a metal and a nonmetal or two nonmetals. Binary compounds are named using a system of nomenclature that involves using prefixes and suffixes to indicate the number and type of atoms in the compound.

For example, the compound formed by sodium (Na) and chlorine (Cl) is a binary compound called sodium chloride (NaCl), while the compound formed by carbon (C) and oxygen (O) is a binary compound called carbon dioxide (CO2).

NH4Cl is composed of two elements, nitrogen (N) and hydrogen (H), and is classified as a binary compound.

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hope it helps:)

\(a. \: Ca + Cl _{2} → CaCl _{2} \\

\\ b. \: Cl _{2}+H _{2} O+ NaOH → \\ NaCl+ H _{2}O \\ \\

c. \: \: \: H _{2} SO _{4} +CaCO _{3} → \\ CaSO _{4} +H _{2}O+CO _{2} \\ \\

d. \: \: Fe+Cu(NO _{3}) _{2} → \\ Fe(NO _{3} ) _{2}+Cu\)

brainliest pls ｡◕‿◕｡

Answer:

Extrusive and intrusive igneous rocks are the two primary subcategories. Lava, which is magma that has surfaced from beneath the Earth, is what gives rise to extrusive rocks, and they can also be formed by oozing fissures. Meanwhile, Magma cools and solidifies inside the planet's crust, forming intrusive rocks, however because they are inside the earths crust and have solidified there, they are usally the type to penetrate exsisting rocks, inlike extrusive rocks, which form on their own.

Explanation:

I hope this helps, I made this up as I went, with the information i do know. :)

it is b shared to form a covalent bond

Explanation:

A covalent bond is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding.

Answer:

Average atomic mass = 19.9 amu

Explanation:

Isotopes can be defined as two or more forms of a chemical element that are made up of equal numbers of protons and electrons but different numbers of neutrons.

Generally, the isotopes of a chemical element have the same chemical properties because of their atomic number but different physical properties due to their atomic weight (mass number).

Given the following data;

Relative abundance of Z-19 = 55%

Relative abundance of Z-21 = 45%

Atomic mass of Z-19 = 19 amu

Atomic mass of Z-21 = 21 amu

To find the average atomic mass;

Average atomic mass = 19 * (55/100) + 21 * (45/100)

Average atomic mass = 19*0.55 + 21*0.45

Average atomic mass = 10.45 + 9.45

Average atomic mass = 19.9 amu

Therefore, the average atomic mass for element Z is 19.9 amu.

472.7ml of a .5500 M solution of NaI are needed to produce 34.81mg of I\(_2\) in the reaction COCl\(_2\)+2NaI  → 2NaCl+CO+I\(_2\).

A measurement of three-dimensional space is volume. Several imperial or US customary units, as well as SI-derived units (such the cubic meter and liter), are frequently used to quantify it quantitatively. Volume and length (cubed) have a symbiotic relationship.

COCl\(_2\)+2NaI  → 2NaCl+CO+I\(_2\)

number of moles of I\(_2\) =34.81/254=0.13moles

2 moles of NaI gives 1 moles of I\(_2\)

0.13moles are obtained by 2×0.13=0.26moles of NaI

0.550moles of I\(_2\) is present in 1000ml

0.26moles of I\(_2\) is present in (1000/0.55)×0.26=472.7ml

Therefore, 472.7ml of a .5500 M solution of NaI are needed to produce 34.81mg of I\(_2\).

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Answer:  NOT accurate, but precise.  

[translation:  You screwed up, but did it in style].

Explanation:

The average mass measurement is 41.95g.  Compared to the actual value of 28.0 grams, the measurement is NOT accurate.  

The standard deviation for the data is 0.112.  Dependiong on your definition of precision, this looks relatively good.  I would go for precise.  

Considering the definition of pH, the pH is 6.35 and the solution is acidic.

pH is the Hydrogen Potential and it is a measure of acidity or alkalinity. pH indicates the amount of hydrogen ions present in a solution or substance.

Mathematically, pH is calculated as the negative base 10 logarithm of the activity of hydrogen ions:

pH= - log [H⁺]

The numerical scale that measures the pH of substances includes the numbers from 0 to 14. The pH value 7 corresponds to neutral substances. Acidic substances are those with a pH lower than 7, while basic substances have a pH higher than 7.

In this case, being [H⁺]=4.5×10⁻⁷ M, you can replace this value in the definition of pH:

pH= -log (4.5×10⁻⁷ M)

Solving:

pH= 6.35

Finally, the pH is lower than 7, the solution is acidic.

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Answer:

500g

Explanation:

Answer:Suppose that during the Icy Hot lab that 65 KJ of energy were transfered to 450 g of water at 20 degrees C. What would have been the final temerpatur

Explanation:

The density would be 0.5929 g/cm3.

The density of an object is the ratio of the mass of the object to its volume.

This can be expressed mathematically as: Density = mass/volume

In this case, the dimension of the object is 20.8 cm x 5.3 cm x 4.4 cm. Thus, the volume of the object would be:

20.8 x 5.3 x 4.4 = 485.056 cm3

The mass of the object is given as 287.57 g.

Thus, density of the object = 287.57/485.056 =

In other words, the density of the object would be 0.5929 g/cm3

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Answer:

Explanation:

Propionic acid  has chemical formula of  C₃H₆O₂ , and smells somewhat unpleasant (like body odour).

Answer:

• Molecular mass of Iron (III) tetraoxide

\( \dashrightarrow \: { \tt{(56 \times 3) + (16 \times 4)}} \\ = { \tt{168 + 64}} \\ = { \tt{232\:g}}\)

[ molar masses: Fe → 56, O → 16 ]

\( \dashrightarrow \:{ \rm{232 \: g \: = 1 \: mole}} \\ \\ \dashrightarrow \: { \rm{55.85 \: g = ( \frac{55.85}{232}) \: moles }} \\ \\ \dashrightarrow \: { \boxed{ \tt{ = 0.24 \: moles}}}\)

In an acetic acid solution:

1. To make a buffer with pH = 5.00, have a ratio of

\(\frac{[A-]}{[HA]} = 10^{-5.50}\) = 0.316.

The volume of sodium hydroxide needed:

V(NaOH) = (0.316 M - 0.200 M) / 4.50 M = 0.0316 L = 31.6 mL

Therefore, 31.6 mL of 4.50 M sodium hydroxide must be added to 250.0 mL of 0.200 M acetic acid solution to make a buffer with pH = 5.00.

2. The pH of the buffer is calculated as follows:

pH = pKa + log(\(\frac{[A-]}{[HA]}\))

= 4.76 + log(0.2/0.1)

= 4.86

Therefore, the pH of the buffer is 4.86.

3. The mass of salt that must be dissolved in 0.25 dm³ of 1 mol dm³ propanoic acid to give a buffer of pH 4.87:

\(\frac{[A-]}{[HA]} = 10^{-4.87}\) = 0.0114

Therefore, the mass of acetate that must be dissolved:

Mass of acetate = (0.0114 mol dm³)(0.25 dm³) = 0.00285 g

Therefore, 0.00285 g of sodium propanoate must be dissolved in 0.25 dm³ of 1 mol dm³ propanoic acid to give a buffer of pH 4.87.

4. The pH of the buffer is calculated as follows:

pH = pKa + log(\(\frac{[A-]}{[HA]}\))

= 4.74 + log(0.1/0.1)

= 4.74

Therefore, the pH of the buffer is 4.74.

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1. The IUPAC name of N is nitrogen.

2. Nitrogen dioxide

3.The IUPAC name of O is oxygen

4.The IUPAC name of OH is hydroxyl.

The IUPAC name of ·0 is a radical. It is commonly found in organic chemistry and plays an important role in many reactions.

IUPAC names for the given compounds are:1.1. N: Nitrogen

The IUPAC name of N is nitrogen.

It is a non-metal and belongs to group 15 in the periodic table. It has an electronic configuration of 1s2 2s2 2p3.1.2. NO2: Nitrogen dioxide

Explanation: NO2 is a chemical compound that is formed by the combination of nitrogen and oxygen. It is a reddish-brown gas that has a pungent odor.

The IUPAC name of NO2 is nitrogen dioxide.1.3. O: Oxygen

Explanation: The IUPAC name of O is oxygen.

It is a non-metal and belongs to group 16 in the periodic table. It has an electronic configuration of 1s2 2s2 2p4.

X: UnknownExplanation: No IUPAC name can be given to an unknown compound as the structure and composition are not known.

Y: Hydroxyl Explanation: The IUPAC name of OH is hydroxyl.

It is a functional group that is composed of an oxygen atom and a hydrogen atom (-OH). It is commonly found in alcohols and phenols. ·0: RadicalExplanation: A radical is a molecule or an ion that contains an unpaired electron.

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Note: The complete question is given below

Provide the IUPAC names for the following compounds:

\(CH_3CH_2CH(CH_3)CH_2CH_2CH_2CH_3\)

C6H5CH(CH3)2

H2NCH2CH2CH2CH2CH2NH2

CH3CH2CH2CH2CH2OH

CH3CH2CH2CHOHCH3

Answer:

A

Explanation:

Pressure and Temperature have to be divided by each each other because they are directly related.

Answer:

the answer is in the picture

Explanation:

Answer:

Accuracy is the degree of closeness to true value.

Precision is the degree to which an instrument or process will repeat the same value.

Hope it helps....

Answer:

Accuracy and precision are alike only in the fact that they both refer to the quality of measurement, but they are very different indicators of measurement. Accuracy is the degree of closeness to true value. Precision is the degree to which an instrument or process will repeat the same value