A/ Soft sample tested by Vickers hardness test with loads (2.5, 5) kg, and the diameter of square based pyramid diamond is (0.362) mm, find the Vickers tests of the sample? (5 points)

1. The amount of manufacturing overhead cost that would have been applied to the Koopers job is $9,840.

2. Using departmental predetermined overhead rates, the total manufacturing cost of the Koopers job is $47,040.

3. The bid price would have been $70,560.

The plantwide predetermined overhead rate for the current year is $2.40 per direct labour dollar ($4,032,000 ÷ $1,680,000).

The amount of manufacturing overhead cost that would have been applied to the Koopers job is $10,200 ($30,000 × 0.34).  

The predetermined overhead rate for each department is:

Department A = $0.60 per direct labour dollar ($672,000 ÷ 1,120,000)

Department B = $0.96 per direct labour dollar ($1,344,000 ÷ $1,400,000)

Department C = $0.72 per direct labour dollar ($1,008,000 ÷ $1,400,000)

The amount of manufacturing overhead cost that would have been applied to the Koopers job is $9,840 ($48,000 × 0.205 + $84,000 × 0.172 + $54,000 × 0.144).

Using a plantwide predetermined overhead rate, the total manufacturing cost of the Koopers job is $48,500 ($18,000 + $20,000 + $10,200).

Thus, the bid price is $72,750 (150% × $48,500). Using departmental predetermined overhead rates, the total manufacturing cost of the Koopers job is $47,040 ($18,000 × 0.205 + $20,000 × 0.172 + $10,000 × 0.144 + $18,000 + $20,000 + $10,000).

Thus, the bid price would have been $70,560 (150% × $47,040).

Hence, the solution to the problem is as follows: The company's plantwide predetermined overhead rate for the current year is $2.40 per direct labour dollar. The amount of manufacturing overhead cost that would have been applied to the Koopers job is $10,200.

Suppose that instead of using a plantwide predetermined overhead rate, the company had used departmental predetermined overhead rates based on direct labour cost. The predetermined overhead rate for each department for the current year is:

Department A = $0.60 per direct labour dollar

Department B = $0.96 per direct labour dollar

Department C = $0.72 per direct labour dollar

The amount of manufacturing overhead cost that would have been applied to the Koopers job is $9,840.Using a plantwide predetermined overhead rate, the total manufacturing cost of the Koopers job is $48,500.

Thus, the bid price is $72,750.Using departmental predetermined overhead rates, the total manufacturing cost of the Koopers job is $47,040. Thus, the bid price would have been $70,560.

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Answer:

\(\frac{12}{5}\)

Step-by-step explanation:

4/5x=3/10(x+4)  / · 10

8x=3(x+4)

8x=3x+12

8x-3x=12

5x=12  /:5

x=12/5

Answer: D

Step-by-step explanation:

A line segment is defined as a part of a straight line connecting two points called  the endpoints, option D.

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Answer: $22575

Step-by-step explanation:

$18075 is the value that he earns on the item itself so then you add on his basic wage and that gives you his final total of $22575

Needless to say he makes some pretty good money haha

Answer:

Step-by-step explanation:

Correct option is A)

Answer:

3/4

Step-by-step explanation:

Answer:

3/4

Step-by-step explanation:

1/4 + 1/2

find the LCM of the two fractions

4

2,4

4 is the LCM now cross multiply 1/4 + 1/2

1 1

-- + -- if the LCM is 4 multiply the 1 above four

4 2. by 2 and multiply the 1 above 2 by 1 and multiply the 2 by 2.

this might seem confusing but I'm sorry for confusion

There are many ways to find f and g, so the composition of those is  (f o g)(x) = 4/(x² + 9).

A function whose values are obtained from two given functions by first applying one to an independent variable and then using the result to apply the second, and whose domain is made up of those independent variable values for which the first function's result falls within the second function's domain.

Find f and g, so that                        

(f o g)(x)  =  4/x²+9                

Well, there is more than one possibility.                                                  

For instance, It can be:  f(x)  = 4/x  and  g(x) = x² + 9

and then you have                          

(f o g)(x)  =  f[ g(x) ]                    

(f o g)(x)  = 4/g(x)                      

(f o g)(x)  =  4/x²+9                                                      

Another possibility:   f(x)  =  4/x+9    and g(x) = x²

and for those, you get

(f o g)(x)  =  f[ g(x) ]              

(f o g)(x)  =   4/g(x)+9      

(f o g)(x)  =  4/x²+9                                                              

Since f and g can be found in a variety of ways, as you can see above, the composition of those is  (f o g)(x) = 4/(x² + 9).

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The quadrilaterals that describe DEFG include parallelogram, rhombus, and square

It should be noted that a quadrilateral simply means a close shape and a polygon that has four sides.

In this case, the quadrilaterals that describe DEFG include parallelogram, rhombus, and square. In a parallelogram, it should be noted that the sides are parallel to each other.

Therefore, the quadrilaterals that describe DEFG include parallelogram, rhombus, and square.

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(11x - 2) + (6x + 7) = 90

17x + 5 = 90

17x = 85

x = 5

11(5) - 2 = 55 - 2 = 53

6(5) + 7 = 30 + 7 = 37

53º and 37º

Hope this helps! :)

The measures of two acute angles are 53 degrees and 37 degrees.

A triangle is a three-sided polygon that consists of three edges and three vertices.

The given triangle is a right angle triangle.

The sum of two acute angles is equal to a right angle

(11x - 2) + (6x + 7) = 90

Add the variable terms and constants

17x + 5 = 90

Subtract 5 on both sides

17x = 85

Divide both sides by 17

x = 5

So 11(5) - 2 = 55 - 2 = 53

and 6(5) + 7 = 30 + 7 = 37

Hence, the measures of two acute angles are 53 degrees and 37 degrees.

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Answer:

Step-by-step explanation:

10 people don’t play volleyball 120-10=110 110 play one or both games 90+72 =162 which is > 110 by 52

There are 52 people who play volleyball as well as football.

Let A, B be two different sets the,

n (A ∪ B) = n (A) + n (B) − n (A ∩ B) .

"A Venn diagram is a diagram that uses overlapping shapes to illustrate the logical relationships between two or more sets."

For given situation:

Let set A: People playing volleyball

set B: People playing football

⇒ n(A) = 90

⇒ n(B) = 72

Given group is of 120 people.

10 people play neither of games.

This means, only 110 people play football or volleyball or both.

⇒ n(A ∪ B) = 110

Using the Inclusion Exclusion Principle,

n (A ∪ B) = n (A) + n (B) − n (A ∩ B)

⇒ 110 = 90 + 72 - n (A ∩ B)

⇒ n(A ∩ B) = 52

Therefore, 52 people play volleyball as well as football.

Venn-diagram for given information is as shown below.

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On average, a customer spends approximately 1.16 minutes waiting time on hold before they can start speaking to a representative.

To find the average waiting time for a customer on hold before they can start speaking to a representative, we need to consider both the arrival rate of calls and the average service time of the staff members.

Given:

9 staff members taking calls.

On average, one call arrives every 5 minutes (standard deviation of 5 minutes).

Each staff member spends on average 18 minutes with each customer (with a standard deviation of 27 minutes).

To calculate the average waiting time, we need to use queuing theory, specifically the M/M/c queuing model. In this model:

"M" stands for Markovian or memoryless arrival and service times.

"c" represents the number of servers.

In our case, we have an M/M/9 queuing model since we have 9 staff members.

The average waiting time for a customer on hold is given by the following formula:

Waiting time = (1 / (c * (μ - λ))) * (ρ / (1 - ρ))

Where:

c = number of servers (staff members) = 9

μ = average service rate (1 / average service time)

λ = average arrival rate (1 / average interarrival time)

ρ = λ / (c * μ)

First, let's calculate the average arrival rate (λ):

λ = 1 / (average interarrival time) = 1 / 5 minutes = 0.2 calls per minute

Next, calculate the average service rate (μ):

μ = 1 / (average service time) = 1 / 18 minutes = 0.0556 customers per minute

Now, calculate ρ:

ρ = λ / (c * μ) = 0.2 / (9 * 0.0556) ≈ 0.407

Finally, calculate the waiting time:

Waiting time = (1 / (c * (μ - λ))) * (ρ / (1 - ρ))

= (1 / (9 * (0.0556 - 0.2))) * (0.407 / (1 - 0.407))

≈ 1.16 minutes

Therefore, on average, a customer spends approximately 1.16 minutes waiting on hold before they can start speaking to a representative.

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Answer:

\(0.75 {ms}^{ - 2} \)

Step-by-step explanation:

\(acceleration = \frac{velocity}{time} \\ = \frac{15ms ^{ - 1} }{20s} \\ = \frac{3}{4} ms ^{ - 2} \\ = 0.75 {ms}^{ - 2} \)

\(\Large\rm{\underbrace{\green{ \: Acceleration \: = \: \ \frac{v}{t} \: }}}\)

\( \bf \large \implies \: Acceleration \: = \: \frac{15}{20} \\ \)

\(\bf \large \implies \: Acceleration \: = \: \cancel\frac{15 \: \small \: m /s }{20 \: s} \: = \: \frac{3}{4} \: m /s ^{ - 1} \\ \)

\(\bf \large \implies \: Acceleration \: = \: \cancel\frac{3}{4} \:m /s ^{ - 1} \: = \: 0.75 \: \: m /s ^{ - 1} \\ \)

\( \bf \large \implies \: \: Acceleration \: = \: 0.75 \: \: m /s ^{ - 1} \\ \)

Mergelyan's theorem is a generalization of Stone-Weierstrass theorem for polynomials, which states that any continuous function on a compact subset K of the complex plane can be uniformly approximated to arbitrary accuracy by polynomials.

More specifically, Mergelyan's theorem states that:

Let K be a compact subset of the complex plane, and let E be a closed subset of K. Suppose that f is a continuous function on E. Then for any ε > 0, there exists a polynomial p(z) such that |f(z) - p(z)| < ε for all z in E.

In other words, Mergelyan's theorem guarantees that any continuous function on a closed subset of a compact set can be uniformly approximated by polynomials on that subset.

The proof of Mergelyan's theorem relies on a construction involving complex analysis and geometric ideas. It involves using the Runge approximation theorem, which states that any function that is holomorphic on an open set containing a compact set K can be approximated uniformly on K by rational functions whose poles lie outside of K. The idea is to use this result to approximate the given continuous function f by a sequence of rational functions with poles outside of E, and then to use partial fraction decomposition to write each of these rational functions as a sum of polynomials. By taking a uniform limit of these polynomial approximations, one obtains a polynomial that approximates f to within any desired tolerance on E.

Overall, Mergelyan's theorem provides a powerful tool for approximating complex-valued functions by polynomials, which has many applications in complex analysis, numerical analysis, and engineering.

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The missing Value, x, that when multiplied by 5/3^4 gives the result of 5^4 is 13125.

The missing value that, when multiplied by 5/3^4, gives the result of 5^4, we can set up the equation:

(5/3^4) * x = 5^4

To solve for x, we can simplify both sides of the equation. First, let's simplify the right side:

5^4 = 5 * 5 * 5 * 5 = 625

Now, let's simplify the left side:

5/3^4 = 5/(3 * 3 * 3 * 3) = 5/81

Now we have:

(5/81) * x = 625

To solve for x, we can multiply both sides of the equation by the reciprocal of 5/81, which is 81/5:

(81/5) * (5/81) * x = (81/5) * 625

On the left side, the fraction (81/5) * (5/81) simplifies to 1, leaving us with:

1 * x = (81/5) * 625

Simplifying the right side:

(81/5) * 625 = 13125

Therefore, the missing value, x, that when multiplied by 5/3^4 gives the result of 5^4 is 13125.

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Answer:

360°F

Step-by-step explanation:

When you multiply the numerals in the brackets . The first set of brackets is 90 then the second is 4.0 then multiply them and you will get 360.0°F

Answer:

the answer is 90×4= 360°F

dear I think the figure under the root is 144

14²- √144

(14 ×14) -12

the square root of 144 is 12

196 -12

184

Answer: "dookie dookie dookie"

*picture of the most trash game

A manufacturer of compact fluorescent light bulbs advertises have a standard deviation of 1,000 hours so the values are:

A normal distribution with,

μ = 9000

σ = 1000

a) The standardized score is the value x decreased by the mean and then divided by the standard deviation.

x = 105000 - 9000 / 1000 ≈ 1.50

Determine the corresponding probability using the normal probability table in appendix,

P(X>10500) = P(Z>1.50) = 1 - P(Z<1.50)

= 1 - 0.9332 = 0.0668.

b) n = 15

The sampling distribution of the mean weight is approximately normal, because the population distribution is approximately normal.

The sampling distribution of the sample mean has mean μ and standard deviation σ/√n

μ = 1000/√15 = 258.19

c) The sampling distribution of the sample mean has mean μ and standard deviation σ/√n

The z-value is the sample mean decreased by the population mean, divided by the standard deviation:

z = x-u/σ/√n = 10500-9000/1000√15 = 5.81

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Answer:

With enough centrifugal force and outward thrust the rocket can exceed the pull of the vacuum no matter how strong it is.

Step-by-step explanation:

The Euclidean norm of the residuals is 0.2916

To find the Euclidean norm of the residuals, we first need to calculate the residuals for each equation in the system. The residual of an equation is the difference between the left-hand side (LHS) and the right-hand side (RHS) of the equation.

Given the system of equations:

x1 - x2 = 2 (Equation 1)

-2x1 + 5x2 = -1 (Equation 2)

Let's calculate the residuals:

Residual 1 = LHS of Equation 1 - RHS of Equation 1

= (x1 - x2) - 2

Residual 2 = LHS of Equation 2 - RHS of Equation 2

= (-2x1 + 5x2) - (-1)

Now, substitute the numerical values x1 = 2.96 and x2 = 1.04 into the residuals:

Residual 1 = (2.96 - 1.04) - 2

= 1.92 - 2

= -0.08

Residual 2 = (-2 * 2.96 + 5 * 1.04) - (-1)

= (-5.92 + 5.20) - (-1)

= -0.72 + 1

= 0.28

The Euclidean norm of the residuals is calculated by taking the square root of the sum of the squares of the residuals:

Euclidean norm = sqrt((Residual 1)^2 + (Residual 2)^2)

= sqrt((-0.08)^2 + (0.28)^2)

= sqrt(0.0064 + 0.0784)

= sqrt(0.0848)

≈ 0.2916

Therefore, the Euclidean norm of the residuals, rounded to four decimal places, is approximately 0.2916.

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Answer:

If is in that form (the blue part ) ,then the answer is that one

a.) The type of distribution that is represented by the histogram is a left skewed histogram.

b.) The type of sampling this will represent is a simple random sampling.

A left skewed histogram can be defined as the type of distribution where by the tails is displayed towards the left of the histogram. This is represented in the histogram given in the diagram above.

A simple random sampling is defined as the type of sampling whereby every member of a population is given an equal chance to be selected. Since the information represented is the sample of an entire league, making another bigger league from it gives them all equal chance to be selected.

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Answer:

Cube surface area:

A= 9126 m^2

Answer:

Step-by-step explanation:

B

Answer:

B

Step-by-step explanation:

128/2=64 mph

(the rate)

2 hr= 120 min

so.. 120-24= 96

and with the wind speed is r-c and without it is r+c because your going against the wind.

The required markup from the cost of $270 is 20% of the sale price.

The selling price of an item is ​$360. It is marked down by ​%10, but this sale price is still marked up from the cost of ​$270.

What is the percentage?

The percentage is the ratio of the composition of matter to the overall composition of matter multiplied by 100.

here,
Selling price after 10% marked down,
= [1 - 0.10] × 360
= 324
Now,
Percentage marked up of cost price of $270
= 324 - 270 / 270 × 100
= 20%

Thus, as of the given condition markup cost of $270 is 20% of the sale price.

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The p-value of the given hypothesis is; 0.9999

The formula for the z-score of proportions is;

z = (p^ - p)/√(p(1 - p)/n)

where;

p^ is sample proportion

p is population proportion

n is sample size

We are given;

p^ = 15% = 0.15

p = 20% = 0.2

n = 5000

Thus;

z = (0.15 - 0.2)/√(0.2(1 - 0.2)/5000)

z = -8.8388

From p-value from z-score calculator, we have;

P(Z < -8.8388) = 1 - 0.0001 = 0.9999

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Answer:

The question might be centered on computation on the hourly rate earned by the three friends:

Nina $12.69

Ty $8.25

Kim  $8.60

Step-by-step explanation:

Hourly rate earned=total earnings/hours worked

Nina:

Nina earned $177.60 for 14 hours,hence hourly rate is $ 12.69   ($177.60/14)

Ty:

Ty earned $148.50 for 18 hours period of work,thus earned $8.25  ($148.50/18)

Kim earned $137.60 for 16 hours duration of work,invariably Kim earned  $8.60 ($137.60/16)

From the above analysis it is clear that Nina earned the highest hourly rate of $12.69 per hour

Answer:

Step-by-step explanation:

The question might be centered on computation on the hourly rate earned by the three friends:

Nina $12.69

Ty $8.25

Kim  $8.60

Hourly rate earned=total earnings / hours of work

Nina:

Nina earned $177.60 for 14 hours,

\(=\frac{177.60}{14}\)

=  $ 12.69 per hour

Ty:

Ty earned $148.50 for 18 hours period of work,

\(=\frac{148.50}{18}\)

=  $8.25 per hour 

Kim

Kim earned $137.60 for 16 hours period of work,

\(\frac{137.60}{16}\)

 $8.60 per hour

From the  analysis it is obvious that Nina earned the highest hourly rate of $12.69 per hour

Answer:

is the act of explaining, reframing, or otherwise showing your own understanding of something.

Step-by-step explanation:

Answer:

4096

Step-by-step explanation:

Explanation:

The rule we use is (a^b)^c = a^(b*c). It says to multiply the exponents when we raise one exponential expression to another exponent. The base stays the same.

So, (2^4)^3 = 2^(4*3) = 2^12

You could take the slightly longer path to say the following

(2^4)^3 = (2^4)*(2^4)*(2^4) = 2^(4+4+4) = 2^12