Answer:
C
Explanation:
Static electricity force is greater than gravity force on the sock, so it sticks and does not fall.
If a planet has an orbital eccentricity equal to 0.70, then its orbit is
Closer to a perfect circle then a straight line
Almost rectangular
A very elongated ellipse
Almost parabolic
If a planet has an orbital eccentricity equal to 0.70, then its orbit is
a very elongated ellipse.What is eccentricity?Eccentricity is a measure of how squashed an ellipse is compared to a perfect circle.
The value of eccentricity ranges from 0 to 1, where 0 represents a perfect circle and 1 represents a parabolic orbit (which is not a closed orbit).
An eccentricity of 0.70 indicates that the planet's orbit is significantly elongated and not close to a perfect circle.
Therefore, the correct answer is - A very elongated ellipse.
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why 0 factorial equal to 1
Answer:
you can see the factorial as many different ways, i will only show you two
first wayyou can see \(n!=\frac{(n+1)!}{n+1}\)
so 0! would mean that
\(0!=\frac{(0+1)!}{0+1}=\frac{1!}{1} =1/1=1\)
second waythe other way you can see factorial is as the number of ways to order n things
let's say we have
a b and c and we want to arrange them in all possible ways so those are
abc
acb
bac
bca
cab
cba
and no more
for just a and b
we have
ab
ba
and no more
for just a
we have only
a
for no objects we have
that way, the one that it's upward, it's a bit philosophical but i hope you understand it
A solid sphere and a solid cylinder , both uniform and having the same mass and radius, are released from rest at the same height on a ramp. If they roll down the ramp without slipping, which one will have the lower forward velocity at the bottom of the ramp?
a. The solid sphere
b. The solid cylinder
c. Both will have the same forward velocity
Answer:
I (cylinder) = 1/2 M R^2
I (sphere) = 2/5 M R^2
The equation of motion shows
I * alpha = M g R sin theta = const
An increase in the moment of inertia will result in a smaller acceleration
The cylinder will have the smallest forward velocity because it will arrive at the bottom after the sphere
1. d=600m 50° N of W
2. d=400m 75° S of E
Answer:
this means the answer 1000 upon 75 + 50
Which of the following is an example of a force that acts at a distance? *
a bear walking through the woods
a jet ski skimming across the water
a leaf falling off of a tree to the ground
a tennis ball hit by a tennis player's racket
I’m curious to the differences between a rhetorical essay and a persuasive essay? Can anyone help out with a quick thorough answer?
Answer:
In a rhetorical essay you only analyze and cite 1 source in a persuasive essay you cite and analyze many different sources
Explanation:
A horse is working steadily, providing 750 WW of output power. How much food energy does the horse need to work for 1 hour, to the nearest MJMJ
Answer:
2.7MJ
Explanation:
Power is expressed according to the formula
Power = work done/Time
The energy required is also known as the work done
Given
Power = 750Watts
Time = 1hr = 3600secs
Substitute the given values into the formula
750 = work done/3600
Work done = 750×3600
Work done = 2,700,000Joules
Convert to megajoules
Since
1MJ = 10^6Joules
x = 2.7×10^6Joules
Cross multiply
10^6x = 2.7×10^6
x = 2.7×10^6/10^6
x = 2.7
Hence the amount of energy absorber by the food in MJ is 2.7MJ
Which observation is evidence that electromagnetic radiation (EMR) has particle-like
properties? (1 point)
O EMR refracts as it moves into a different medium.
O
A diffraction pattern is observed when EMR passes through a narrow slit.
O Some EMR is blocked when it passes through a polarized lens.
O EMR with energy above a certain value can eject electrons out of a metal.
The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.
Electromagnetic radiations as particlesThe observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.
This observation that electromagnetic radiation behaves like particles is known as the photoelectric effect.
It provides evidence that electromagnetic radiation exhibits particle-like properties. When EMR with sufficient energy (above a certain threshold) interacts with a metal surface, it can cause the ejection of electrons from the metal.
This behavior indicates that EMR behaves as discrete packets of energy called photons, which transfer their energy to the electrons and cause their release. The photoelectric effect supports the particle nature of EMR and is a fundamental concept in the field of quantum mechanics.
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Explain, in terms of moments of forces, how the valve works.
The moment of forces in a valve equals force multiplied by the perpendicular distance to the pivot.
What is a Force?This can be defined as an action which changes the motion of an object. A valve is fixed to a pivot and opens and closes thereby controlling flow of fluid.
The moment of forces in a valve is the force multiplied by the perpendicular distance to the pivot.
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A penny sinks to the bottom of a wishing well
What type of frictional force is that?
The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.
What do feathers, fur, overcoats, and whale blubber all have in common?
A. They are all good conductors of heat.
B. They all generate heat.
C. They are all electrical conductors.
D. They are all heat insulators.
Answer:
D. They are all heat insulators.
Explanation:
Those things mentioned above are examples of heat insulators. As a heat insulator, it helps to prevent the heat from leaving the body thereby keeping the body warm and risk free.Feathers in birds and overcoat in humans helps to keep the bodies of the wearer safe and warm during the cold season.
please help in this question!! I will mark brainlest
Answer:
im not too sure about that all i know is history
A 500 g air-track glider collides with a spring at one end of the track. The figures show the glider's velocity and the force exerted on the glider by the spring. (Figure 1), (Figure 2) How long is the glider in contact with the spring? Express your answer to two significant figures and include the appropriate units.
We can find the time for which the glider is in contact with the spring by using the impulse-momentum theorem:
Impulse = Change in momentum
The impulse of the force exerted by the spring is given by the area under the force-time graph, which is a triangle:
Impulse = (1/2) * (1 N) * (0.02 s) = 0.01 Ns
The initial momentum of the glider is:
p1 = m * v1 = (0.5 kg) * (0.3 m/s) = 0.15 kg m/s
The final momentum of the glider is zero, since it comes to rest:
p2 = 0 kg m/s
Therefore, the change in momentum is:
Δp = p2 - p1 = -0.15 kg m/s
Setting the impulse equal to the change in momentum and solving for the time gives:
Impulse = Change in momentum
0.01 Ns = Δp = p2 - p1
0.01 Ns = 0 - 0.15 kg m/s
0.01 Ns = -0.15 kg m/s
t = Δp / Impulse = (-0.15 kg m/s) / (0.01 Ns) ≈ -15 s
The negative value for time doesn't make sense physically, so we need to check our work. Looking at the force-time graph, we see that the force is actually zero for most of the time, and only becomes non-zero when the glider is in contact with the spring. Therefore, we need to find the time for which the force is non-zero.
The force is non-zero for a duration of 0.01 s, so this is the contact time:
t = 0.01 s
Therefore, the glider is in contact with the spring for 0.01 seconds.
here's the answer. I'm not too sure about it, but good luck
The time for which the glider is in contact with the spring is approximately 0.17 s.
Momentum is a physical quantity that describes the motion of an object. It is defined as the product of an object's mass and velocity. Mathematically, momentum can be expressed as:
p = mv
where p is momentum, m is the mass of the object, and v is the velocity of the object.
Impulse is the change in momentum of an object that results from the application of a force over a certain period of time. Impulse is equal to the product of force and the time interval over which the force acts. Mathematically, impulse can be expressed as:
J = FΔt
where J is the impulse, F is the force applied to the object, and Δt is the time interval over which the force acts.
The relationship between impulse and momentum is given by the impulse-momentum theorem, which states that the impulse applied to an object is equal to the change in momentum of the object. Mathematically, the impulse-momentum theorem can be expressed as:
J = Δp
where J is the impulse, and Δp is the change in momentum of the object. This theorem is useful in analyzing collisions and other situations where forces act on objects for a finite period of time.
Here in the Question,
To find the time for which the glider is in contact with the spring, we need to use the impulse-momentum theorem, which relates the impulse (change in momentum) of an object to the force applied to it and the time over which the force is applied:
impulse = force x time = change in momentum
The momentum of the glider before it collides with the spring is:
p1 = m1v1 = (0.500 kg)(0.750 m/s) = 0.375 kg·m/s
The momentum of the glider after it rebounds from the spring is:
p2 = m2v2
We can find v2 from the velocity-time graph in Figure 1. At the moment of maximum compression, the velocity of the glider is zero, so we need to find the time at which this occurs. From the graph, we can see that this occurs at about t = 0.02 s. Therefore, the velocity of the glider after rebounding from the spring is:
v2 = -0.750 m/s
(Note that the negative sign indicates that the glider is moving in the opposite direction after rebounding.)
The change in momentum of the glider is:
Δp = p2 - p1 = m2v2 - m1v1 = (0.500 kg)(-0.750 m/s) - (0.500 kg)(0.750 m/s) = -0.750 kg·m/s
The impulse applied to the glider by the spring is equal in magnitude to the change in momentum:
impulse = Δp = -0.750 kg·m/s
We can find the time for which the force is applied by rearranging the impulse-momentum theorem:
time = impulse/force
We can find the force from the force-time graph in Figure 2. The force at the maximum compression is approximately 4.5 N. Therefore, the time for which the glider is in contact with the spring is:
time = impulse / force = (-0.750 kg·m/s) / (4.5 N) ≈ 0.167 s ≈0.17 s
Therefore, Rounding to two significant figures and including the appropriate units, the time for which the glider is in contact with the spring is approximately 0.17 s.
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Two charges and are separated by 10cm on the x- axis. Q2 is at the origin and Q1 is 12cm to the right.
a. What is the net Electric Force (magnitude and direction) on Q2 due to Q1?
b. Calculate the magnitude and direction of the net electric field -2.0 cm to the left of Q2.
Answer:
Explanation:
Q₂ is at the origin and Q₁ is at 12 cm on x -axis
Force between Q₁ and Q₂
= K x Q₁ x Q₂ / .12 where k is a constant equal to 9x 10⁹
Force F = 9 x 10⁹ x Q₁ x Q₂ / .12²
= 625 x 10⁹ x Q₁Q₂ N
This is the force each one exerts on other . So electric force on Q₂ due to Q₁ is 625 x 10⁹ x Q₁Q₂ N . Its direction is towards left as both will repel each other.
b)
Electric field due to charge Q₂ at - 2 cm
= 9 x 10⁹ x Q₂ / .02²
= 22500 x 10⁹ x Q₂ N/C , towards left .
Electric field due to charge Q₁ at - 2 cm
= 9 x 10⁹ x Q₁ / .14²
= 459.18 x 10⁹ x Q₁ N/C , towards left
As both the fields are to the same direction
Net field = 75 x 10⁹ x Q₂ + 459.18 x 10⁹ x Q₁
10⁹ ( 22500 x Q₂ + 459.18 x Q₁ ) N/C .
Direction will be towards left.
One of the possible criteria of Schizophrenia is hallucinations.
Select one:
O True
O False
Calculate the speed of a spider that walked 36 cm in 4 seconds.
Select ALL the
correct answers.
Which two examples describe ways that corporations can give large donations to presidential candidates?
A corporation leader makes
direct payment to the candidate.
A corporation creates another company to accept candidate contributions
A corporation collects moneys from its employees to contribute to
A corporation contributes to a Super PAC that
a PAC
accepts contributions
for a candidate,
Reset
Next
Answer: Hope this helps ;) don't forget to rate this answer !
Explanation:
There are two correct answers:
A) A corporation leader makes direct payment to the candidate.
D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.
Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.
Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.
I hope this helps! Let me know if you have any other questions.
Name and describe at least SIX engineering challenges that the Mars copter, Ingenuity, had to overcome in order to be built/to travel to Mars/to function on Mars. BE SPECIFIC with your answers...........................
Answer:
Explanation:
1. Ingenuity is a flight test.
Ingenuity is what is known as a technology demonstration – a project that seeks to test a new capability for the first time, with limited scope. Previous groundbreaking technology demonstrations include the Mars Pathfinder rover Sojourner and the tiny Mars Cube One (MarCO) CubeSats that flew by Mars in 2018.
Ingenuity features four specially made carbon-fiber blades, arranged into two rotors that spin in opposite directions at around 2,400 rpm – many times faster than a passenger helicopter on Earth. It also has innovative solar cells, batteries, and other components. Ingenuity doesn't carry science instruments and is a separate experiment from the Mars 2020 Perseverance rover.
2. Ingenuity will be the first aircraft to attempt controlled flight on another planet.
Which simple machines are used in the tool or device
Answer:
Explanation:
What are simple machines?
Simple machines reduce effort or extend the ability to perform tasks beyond their abilities.
Why do we use simple machines?
Simple machines are used widely as they help humans and save time.
Simple Machine Examples:
MachineScrewWheel and axle - wheeled carry-on luggageLever - see sawPulley - flag polesInclined planeWedge - knifeb. Density and relative density.
Explanation:
density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.
The relative density of a substance is defined as the ratio of the density of that substance to the density of water at 4oC. It is also defined as the ratio of the mass of substance to the mass of equal volume of water at 4oC. i.e., R.D. = Mass of the substance / mass of an equal volume of water at 4oC
1. Swordfish are capable of stunning output power for short bursts. A 650 kg swordfish has a cross-sectional area of 0.92 m2 and a drag coefficient of 0.0091- very low due to some evolutionary adaptations. Such a fish can sustain a speed of 30 m/s for a few seconds. Assume seawater has a density of 1026 kg/m3. a) How much power does the fish need to put out for motion at this high speed
Answer:
\(P_{sp}=178.4W/kg\)
Explanation:
From the question we are told that:
Mass of fish \(m_f=650kg\)
Cross-sectional area \(A=0.92 m^2\)
Drag coefficient of \(\mu= 0.0091\)
Seawater density \(\rho= 1026 kg/m^3.\)
Speed of Fish \(v=30 m/s\)
Generally the equation for Drag force F_d is mathematically given by
\(F_d = \mu * \rho *A v^2 /2\)
\(F_d = 0.0091* 0.92* 1026* 30^2/2 \\F_d= 3865. 35 N\)
Generally the equation for high speed Power \(P_{sp}\) is mathematically given by
\(P_{sp}=3865*35*\frac{v}{m_f}\)
\(P_{sp}=F_d*35*\frac{30}{650}\)
\(P_{sp}=178.4W/kg\)
write the realtionship between the density of a liquid and its upthrust? clarify
Answer:
B = ρ g V_liquid
the thrust is proportional to the density of the liquid
Explanation:
The density of a liquid is defined as the relationship between the mass and the volume of the liquid
ρ = m / V
The upward push of the liquid is given by the principle of Archimedes Archimedes establishes that the push is equal to the weight of the dislodged liquid
B = W_liquid
B = m _liquid g
we substitute mass for density
B = ρ g V_liquid
therefore we see that the thrust is proportional to the density of the liquid
Ann and Bob are pushing opposite sides
of a door with I = 10.5 kg-m2. Ann
pushes 34.8 N at 0.732 m from the axis,
while Bob pushes 59.6 N at 0.300 m,
both perpendicular to the door. What is
the angular acceleration?
The angular acceleration of the door is approximately 0.723 rad/s^2.
How to solve this problemFirst we can use the equation for torque:
torque = force * lever arm
where
torque is the net torque acting on the doorforce is the force applied by each person, and lever arm is the distance from the axis of rotation to the point where the force is appliedThe net torque causes angular acceleration of the door, which is related to torque by the equation:
torque = moment of inertia * angular acceleration
Where moment of inertia is a measure of how difficult it is to change the rotational motion of the door.
In this case, we can calculate the net torque on the door as the sum of the torques due to Ann and Bob:
torque_net = torque_Ann + torque_Bob
where
torque_Ann = force_Ann * lever_arm_Anntorque_Bob = force_Bob * lever_arm_BobSubstituting the given values, we have:
torque_Ann = 34.8 N * 0.732 m = 25.46 N·m
torque_Bob = 59.6 N * 0.300 m = 17.88 N·m
torque_net = 25.46 N·m - 17.88 N·m = 7.58 N·m
Next, we can calculate the moment of inertia of the door, using the given value:
moment of inertia = I = 10.5 kg-m^2
Finally, we can use the equation for angular acceleration to solve for the unknown:
torque_net = moment of inertia * angular acceleration
Solving for angular acceleration, we get:
angular acceleration = torque_net / moment of inertia
Substituting the previously calculated values, we have:
angular acceleration = 7.58 N·m / 10.5 kg-m^2
≈ 0.723 rad/s^2
Therefore, the angular acceleration of the door is approximately 0.723 rad/s^2.
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The boiling point of nitrogen is -196°C. What is that on the absolute temperature scale?
Answer:
The boiling point of nitrogen on the absolute temperature scale is 77.15 K
Explanation:
Temperature in Kelvin(Absolute temperature) = Temperature in Celcius + 273.15.
Principle 7: An object will continue to remain at rest or move at a constant speed and in a straight line
unless it is subjected to unbalanced forces.
1. List the supporting phenomena:
The supporting phenomena for Principle 7, also known as Newton's first law of motion or the law of inertia, include:
Inertia of an object: An object's tendency to resist changes in its motion. If an object is at rest, it will remain at rest unless acted upon by an unbalanced force. Similarly, if an object is moving at a constant speed in a straight line, it will continue to do so unless acted upon by an unbalanced force.
Conservation of momentum: If the net external force acting on a system is zero, the total momentum of the system remains constant. This implies that objects in motion will continue moving at a constant velocity in the absence of external forces.
Smooth and frictionless surfaces: When an object is placed on a smooth and frictionless surface, it can continue to move at a constant speed and in a straight line due to the absence of external forces such as friction or resistance.
Space travel: In outer space, where there is no significant gravitational or atmospheric resistance, objects can continue moving at a constant speed and in a straight line once set in motion, due to the absence of significant external forces.
Free-falling objects: In the absence of air resistance, objects falling freely near the surface of the Earth experience negligible external forces. As a result, they continue to accelerate downward at a constant rate (due to gravity) without any change in their direction until they encounter other forces like air resistance or contact with the ground.
These phenomena provide evidence and support for the principle that an object will remain at rest or move at a constant speed and in a straight line unless acted upon by unbalanced forces.
Why don’t we feel the gravitational pull of objects around us?
An airbys A380 airliner lands at 30 m/s. Partially loaded, its mass is 480000 kg. The engines apply reverse thrust for 12s to slow the plane to 25 m/s.How much thrust did the engines apply?
To determine the thrust applied by the engines, we can use Newton's second law of motion, which states that force (thrust) is equal to mass times acceleration. In this case, we need to calculate the force required to decelerate the plane from 30 m/s to 25 m/s in 12 seconds.
First, we calculate the change in velocity (∆v):
\(\displaystyle\sf \Delta v=25\,m/s-30\,m/s=-5\,m/s\)
Next, we calculate the acceleration (∆a) using the formula:
\(\displaystyle\sf \Delta a=\frac{\Delta v}{\Delta t}\)
where ∆t is the change in time, which is 12 seconds in this case.
\(\displaystyle\sf \Delta a=\frac{-5\,m/s}{12\,s}\)
Now, we can determine the force (thrust) applied by the engines using Newton's second law:
\(\displaystyle\sf F=m\cdot a\)
where m is the mass of the airplane, which is 480000 kg.
\(\displaystyle\sf F=480000\,kg\cdot \left(\frac{-5\,m/s}{12\,s}\right)\)
Calculating the result:
\(\displaystyle\sf F=-200000\,N\)
Therefore, the engines applied a thrust of -200000 Newtons (N) to decelerate the plane. The negative sign indicates that the thrust is in the opposite direction of the motion.
how atoms are in one mole of patassuim
Answer:
There are 6.022 × 10²³ atoms of potassium in every mole of potassium.
This glass of lemonade is sitting in the hot summer sun. As time passes, in which direction will heat transfer take place?
The heat transfer takes place from the Ice to lemonade (ice → lemonade).
What is heat transfer?The term “heat transfer” refers to the movement of heat. The flow of heat across a system's boundary is due to a temperature differential between the system and its surroundings.
When a temperature difference exists between states of matter, heat transfer happens solely in the direction of decreasing temperature, that is, from a hot object to a cold item.
The temperature of ice is increasing while the lemonade is decreasing. Heat transfer happens solely in the direction of decreasing temperature,
Hence, the heat transfer takes place from the Ice to lemonade (ice → lemonade.
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Answer: C
Explanation:
An amusement park ride called the Rotor debuted in 1955 in Germany. Passengers stand in the cylindrical drum of the Rotor as it rotates around its axis. Once the Rotor reaches its operating speed, the floor drops but the riders remain pinned against the wall of the cylinder. Suppose the cylinder makes 26.0 rev/min and has a radius of 3.70 m. 1) What is the coefficient of static friction between the wall of the cylinder and the backs of the riders
Answer:
μs = 0.36
Explanation:
While the drum is rotating, the riders, in order to keep in a circular movement, are accelerated towards the center of the drum.This acceleration is produced by the centripetal force.Now, this force is not a different type of force, is the net force acting on the riders in this direction.Since the riders have their backs against the wall, and the normal force between the riders and the wall is perpendicular to the wall and aiming out of it, it is easily seen that this normal force is the same centripetal force.In the vertical direction, we have two forces acting on the riders: the force of gravity (which we call weight) downward, and the friction force, that will oppose to the relative movement between the riders and the wall, going upward.When this force be equal to the weight, it will have the maximum possible value, which can be written as follows:\(F_{frmax} = \mu_{s}* F_{n} = m * g (1)\)
where μs= coefficient of static friction (our unknown)As we have already said Fn = Fc.The value of the centripetal force, is related with the angular velocity ω and the radius of the drum r, as follows:\(F_{n} = m* \omega^{2} * r (2)\)
Replacing (2) in (1), simplifying and rearranging terms, we can solve for μs, as follows:\(\mu_{s} = \frac{g}{\omega^{2} r} (3)\)
Prior to replace ω for its value, is convenient to convert it from rev/min to rad/sec, as follows:\(\omega = 26.0 \frac{rev}{min} * \frac{1min}{60 sec} *\frac{2*\pi rad }{1 rev} = 2.72 rad/sec (4)\)
Replacing g, ω and r in (3):\(\mu_{s} = \frac{g}{\omega^{2} r} = \frac{9.8m/s2}{(2.72rad/sec)^{2} *3.7 m} = 0.36 (5)\)