A soccer ball initially at rest rolls down a hill with an acceleration of 3.0 m /s2 .it accelerates for 5 seconds before melissa is able to catch it how far did it roll ?

It is important to note that the debate between scientific realism and antirealism is ongoing and complex, with various nuances and perspectives within each position. Different philosophers of science and scientists may hold different views on the nature of scientific terms and their relationship to reality.

According to a scientific realist perspective, scientific terms for unobservable phenomena such as "atom" and "black hole" are seen as referring to entities that truly exist in reality. Scientific realists believe that scientific theories and concepts accurately capture aspects of the world, including unobservable entities and phenomena. They argue that scientific theories provide the best explanation of the natural world and aim to describe the underlying structure and mechanisms of reality.

On the other hand, scientific antirealists hold a different view. They argue that scientific terms that refer to unobservable phenomena do not necessarily correspond to something that exists independently in reality. Antirealists often emphasize the instrumentalist view of science, which suggests that scientific theories are simply tools or frameworks that help us organize and predict observable phenomena, without making claims about the ultimate nature of reality.

Antirealists may argue that scientific theories are subject to revision and change over time as new evidence emerges, suggesting that the terms used to describe unobservable phenomena are not fixed and may not have a one-to-one correspondence with actual entities in reality. They may also highlight the role of social and cultural factors in shaping scientific knowledge, suggesting that scientific terms are influenced by human conventions and interpretations.

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An iron nail is drawn to the magnet's north pole and adheres to it. The iron nail becomes a conduit for the magnetic field lines. As a result, the side that becomes attached to the North Pole serves as the South Pole.

Is an iron nail more drawn to a magnet's north or south pole?

A magnet's strength is greatest close to its poles. Therefore, the magnet's two poles will attract the greatest amount of nails.

An iron nail is more attracted to which pole of a magnet?

Iron nails are magnetically inducted to acquire the opposite polarity when they are brought close to one end of a magnet. Since opposing poles are drawn to one another,

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The amount of wavelength of light thick is the thumbnail x/y.

Given:

Wavelength of light= x

Thickness of thumbnail= y

The amount of wavelength thick the thumbnail is x/y

What is wavelength?

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Answer: From What i Seeing it is Option B

Both sides of the equation have the same units (kg * m/s), confirming the dimensional homogeneity of the equation.

To check the dimensional homogeneity of the equation \(mv = ∫ fcos(angle) dt\), we need to examine the units of each term.

The unit of mass (m) is typically expressed in kilograms (kg). The unit of velocity (v) is typically expressed in meters per second (m/s). Therefore, the product of mass and velocity (mv) has units of kg * m/s.

The integral (∫) is a mathematical operator and does not have any units associated with it.

The force (f) is typically expressed in newtons (N). The cosine of an angle (cos(angle)) is dimensionless.

The unit of time (t) is typically expressed in seconds (s).

When we multiply the force (f) and the cosine of the angle (cos(angle)) by the differential of time (dt), the units become N * dimensionless * s.

Therefore, both sides of the equation have the same units (kg * m/s), confirming the dimensional homogeneity of the equation.

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Answer:

180m to the east

Explanation:

Displacement is the distance traveled in a specific direction. It is a vector quantity with both magnitude and direction. Therefore, the start and finish position is very paramount.

  point A runs 150m east,

   70m west

  100m east

                                       150m

                --------------------------------------------------------→

                                                                   70m

                                                         ←---------------------

                                                                   100m

                                                         -----------------------------------→

The displacement of the athlete  = 150 - 80 + 100  = 180m to the east

The velocity of the pumpkin 3.0 seconds after it was dropped is 29.4m/s.

The formula for the first equation of motion is expressed as;

v = u + gt

Where v is final velocity, u is initial velocity, g is acceleration due to gravity ( g = 9.8m/s² ) and t is time elapsed.

Given the data in the question;

Since the pumpkin was initially at rest before it was dropped.

To determine the velocity of the pumpkin after 3 seconds, plug the given values into the above equation of motion.

v = u + gt

v = 0 + ( 9.8m/s² × 3.0s )

v = 9.8m/s² × 3.0s

v = 29.4 m/s

Therefore, the final velocity is 29.4 meter per seconds.

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The voltage required to accelerate an electron to a specific velocity depends on the mass of the electron, the charge on the electron, and the desired velocity.

To calculate the voltage through which an electron must be accelerated to achieve a specific velocity, we can use the formula for the kinetic energy of the electron. The kinetic energy of the electron is given by the equation KE= 0.5mv^2, where m is the mass of the electron and v is the velocity. Since the electron starts at rest, the initial kinetic energy is zero. Therefore, the kinetic energy of the electron is equal to the work done on it by the electric field. The work done by the electric field is given by the equation W=qV, where q is the charge on the electron and V is the voltage. Equating these two equations, we get 0.5mv^2=qV. Solving for V, we get V= (0.5mv^2)/q. Therefore, the voltage required to accelerate an electron to a specific velocity depends on the mass of the electron, the charge on the electron, and the desired velocity.
To answer your question, we need to determine the voltage required to accelerate an electron to a specific velocity (V). To do this, we will use the following equation:

KE = 0.5 * m * v^2,

where KE is the kinetic energy, m is the electron's mass (9.109 × 10^-31 kg), and v is the velocity.

Additionally, we know that KE = eV, where e is the elementary charge (1.602 × 10^-19 C) and V is the voltage.

Rearranging the equation, we get:

V = (0.5 * m * v^2) / e

By plugging in the mass and elementary charge values, as well as the desired velocity, you can calculate the required voltage (V).

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The statements that are true are

Angular momentum is the product of the rotational inertia and angular speed of a rotating object.

Let

From the law of conservation of angular momentum, we have that

initial angular momentum equals final angular momentum

So, I₁ + I₂ = I₃ + I₄

Ixω₀ + 0 = Ixω + Iyω

Ixω₀ = Ixω + Iyω

From the above, we see that

Since I₄ > I₂ = 0,

The angular momentum of disk Y immediately after the collision is greater than the angular momentum of disk Y immediately before the collision.

Also, since I₁ + I₂ = I₃ + I₄,

The angular momentum of the disk X-disk Y system immediately after the collision is equal to the angular momentum of the system immediately before the collision.

So, the statements that are true are

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Using the Pitzer correlation, the molar volume of acetylene vapor at 277.6 K and 19.7 bar is approximately 31.24 cm^3/mol.

To find the molar volume of acetylene vapor at a given temperature and pressure using the Pitzer correlation for the second virial coefficient, we can use the following equation:

B(T) = B0 + B1(T - Tc) + B2(T - Tc)^(3/2)

where B(T) is the second virial coefficient at temperature T, B0, B1, and B2 are constants, Tc is the critical temperature, and T is the temperature.

First, we need to calculate the constants B0, B1, and B2 using the given data:

B0 = 0.083 - (0.189 / Tc)^(1/2) - (0.001 / Tc)

B1 = 0.139 + (0.673 / Tc)^(1/2) - (0.950 / Tc)

B2 = 0.000012

Substituting the values into the equation, we can calculate the second virial coefficient B(T).

Next, we can use the ideal gas law to relate the molar volume V to the pressure P and temperature T:

PV = RT

Solving for V, we get:

V = RT / P

Substituting the values of R, T, and P, we can calculate the molar volume V in cm^3/mol.

Using the given data:

T = 277.6 K

P = 19.7 bar

Tc = 308.3 K

R = 8.314 J/mol·K

Acentric factor (ω) = 0.187

Calculating B(T) and V:

B(T) ≈ 0.001531 m^3/mol

V ≈ (8.314 J/mol·K * 277.6 K) / (19.7 bar * 10^5 Pa/bar) ≈ 31.24 cm^3/mol

Therefore, the molar volume of acetylene vapor at 277.6 K and 19.7 bar is approximately 31.24 cm^3/mol.

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Inertia is directly related to the mass of an object.

Inertia is the tendency of an object to resist a change in its motion. The more mass an object has, the more inertia it has, and the harder it is to change its motion. This is why it is harder to push a heavy object than a light one.

The relationship between inertia and mass can be seen in Newton's Second Law of Motion, which states that the acceleration of an object is equal to the force applied to it divided by its mass. This means that the more mass an object has, the less it will accelerate when a force is applied to it. In conclusion, inertia is directly related to the mass of an object. The more mass an object has, the more inertia it has, and the harder it is to change its motion.

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1/Rt = 1/R1 + 1/ R2 ......n.....

1/Rt= 1/5ohm + 1/10ohm + 1/15ohm +1/20ohm

1/Rt= 12ohm + 6ohm + 4ohm +3ohm

60.

1/Rt = 25 ohm

60

Rt= 60

25

Rt= 2.4 ohm.

note: Rt is equivalent resistance.

Answer:A) 19.8 seconds

B) 467.5 metres

Explanation: 100km/hr = 27.78m/s

So, it covers 27.78 metres in one second

Take the time it would cover 550m as x

Therefore 27.78m = 1second

550m = x

Cross multiplying

27.78x = 550m

Divide both sides by the coefficient of x

x = 550÷27.78

x = 19.8seconds

B) distance = speed × time

Speed = 85km/hr = 23.61m/s

Time = 19.8seconds

Therefore,

Distance = 23.61 × 19.8

Distance = 467.5m

Answer:

-7.5

Explanation:

edge 2021

Answer:

The acceleration due to gravity of the planet is approximately 15.083 m/s²

Explanation:

The given information are;

The mass of the golf ball = 45.93 gram

The time it takes the golf ball to hit the ground 0.44 seconds

The height, s, from which the golf ball is dropped = 146 cm = 1.46 m  

The equation of motion for the golf ball can be expressed as follows;

s = u·t + 1/2·a·t²

Where;

s = 1.46 m

u = The initial velocity of the golf ball = 0 m/s

a = The acceleration due to gravity of the planet

t = The time it takes the golf ball to hit the ground = 0.44 seconds

By substituting, we have;

1.46 = 0 × 0.44 + 1/2 × a × 0.44²

a = 1.46/(1/2 × 0.44²) ≈ 15.083 m/s²

The acceleration due to gravity of the planet = a ≈ 15.083 m/s².

Answer: Liquid

“A substance will take on the shape of an open container if it is a Liquid. Explanation: The major state of matter are solid, liquid and gas. Liquid usually have a definite volume.”

Answer:

solid

Explanation:

Solids are fixed and solid.

Answer:

C, it will move.

Explanation:

Answer:

The object will move forward

Explanation:

When more than one force acts upon an object, the vector sum of these forces is the resultant force. When the resultant force on an object is zero, it will remain at rest if it is at rest, or continue to move in a straight line at a constant velocity if it is in motion.

Radioactivity is a part of our earth - it has existed all along. Naturally occurring radioactive materials are present in its crust, the floors and walls of our homes, schools, or offices and in the food we eat and drink. There are radioactive gases in the air we breathe. Our own bodies - muscles, bones, and tissue - contain naturally occurring radioactive elements.

Answer:

B

Explanation:

The pattern that the double slit experiment produces is a diffraction pattern (made as a result of single and double slit interference).

Answer:

B. It is the result of diffraction.

Explanation: a p e x

The approximate length of the rope and mass of the student cannot be determined without additional information, such as the height and the acceleration due to gravity.

To determine the approximate length of the rope and mass of the student, more information is needed. The maximum gravitational potential energy (GPE) of the student-earth system can be calculated using the formula GPE = mgh, where m is the mass of the student, g is the acceleration due to gravity (approximately 9.81 m/s²), and h is the height.

However, with only the maximum GPE value of 2000 J provided, we cannot determine the individual values of m and h. If the height or mass were given, the other variable could be calculated, allowing for the approximate length of the rope and mass of the student to be determined.

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Answer:

μ = dynamic viscosity = unknown

ρ = 1000 kg/m^3

k = 0.8 W/m.K

Cp = 4000 J/kg.K

Explanation:

To find the required heat flux, we can use the equation:

Q = m * Cp * (T_out - T_in)

where Q is the heat flux, m is the mass flow rate, Cp is the specific heat capacity, and T_out and T_in are the temperatures at the exit and entrance of the tube, respectively.

Given:

m = 2 x 10^-3 kg/s.m

Cp = 4000 J/kg.K

T_out = 75°C = 75 + 273 = 348 K

T_in = 25°C = 25 + 273 = 298 K

Substituting these values into the equation, we get:

Q = (2 x 10^-3) * 4000 * (348 - 298) = 2.4 W

Therefore, the required heat flux is 2.4 W.

To determine the surface temperature at the tube exit and at a distance of 0.5 m from the entrance, we need to calculate the convective heat transfer coefficient (h) using the following equation:

h = Nu * k / D

where Nu is the Nusselt number and D is the tube diameter.

The Nusselt number can be determined using the following correlation for fully developed flow in a circular tube:

Nu = 0.023 * Re^0.8 * Pr^0.3

where Re is the Reynolds number and Pr is the Prandtl number.

Re = (D * m) / (P * A)

A = π * (D^2 / 4)

Substituting the given values into the equations, we can calculate Re:

D = 12.7 mm = 12.7 x 10^-3 m

P = 1000 kg/m^3

A = π * (12.7 x 10^-3 / 2)^2

Re = (12.7 x 10^-3 * 2 x 10^-3) / (1000 * π * (12.7 x 10^-3 / 2)^2)

Simplifying, we get:

Re ≈ 0.635

Next, we calculate Pr:

Pr = ν / α

ν = μ / ρ

α = k / (ρ * Cp)

Given:

μ = dynamic viscosity = unknown

ρ = 1000 kg/m^3

k = 0.8 W/m.K

Cp = 4000 J/kg.K

We are not given the value of μ, so we cannot calculate Pr accurately.

Therefore, we are unable to determine the convective heat transfer coefficient (h) and, consequently, the surface temperature at the tube exit and at a distance of 0.5 m from the entrance.

Answer:

Average speed = 26.67 km/h

Explanation:

It is given that,

The first half of the journey by a body is traveled with a speed of 40 km/h and the next half is covered with a speed of 20 km/h

We need to find the average speed of the whole journey.​ When two speeds are given, the average speed is given by :

\(v=\dfrac{2v_1v_2}{v_1+v_2}\\\\v=\dfrac{2\times 40\times 20}{40+20}\\\\v=26.67\ km/h\)

So, the average speed of the body of the whole journey is 26.67 km/h.

The power of the eye would be 0 diopters.

The power of the eye can be calculated using the formula P = 1/f, where P is the power in diopters and f is the focal length in meters.

For objects at the greatest distance possible with normal vision, the focal length is infinity. Therefore, the power of the eye would be 0 diopters. However, assuming a typical lens-to-retina distance of 2.00 cm, the power can be calculated as follows: P = 1/0.02 m = 50 diopters or 50 cm^(-1). Therefore, the correct answer is option a.
To calculate the power of the eye, we use the lens maker's formula, which relates the focal length (f) of a lens to its power (P): P = 1/f. For normal vision, the farthest distance an object can be viewed is considered to be at infinity, which results in the focal length being equal to the lens-to-retina distance, f = 2.00 cm. Using the lens maker's formula, we have P = 1/(2.00 cm) = 0.50 cm^(-1).

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The transfer function is Vc(s)/Vs(s) = (R + 1/(sC)) / (sL + R + 1/(sC)), the pole-zero map includes poles at -R/L and zeros at -1/(sC), the response to Vs(t) = u(t)V can be calculated using inverse Laplace transform techniques and the response to Vs(t) = o(t)V can also be determined using inverse Laplace transform techniques.

To find Vc(s)/Vs(s), we need to consider the given electrical system with components R, L, and C. By applying Kirchhoff's laws and solving for the output voltage Vc(s) and input voltage Vs(s) in the Laplace domain, we can derive the transfer function as (R + 1/(sC)) / (sL + R + 1/(sC)).

The pole-zero map provides insights into the stability and behavior of the system. In this case, the transfer function has poles at -R/L, indicating a time constant associated with the system's dynamics. The transfer function also has zeros at -1/(sC), which affect the frequency response characteristics.

To find the response to Vs(t) = u(t)V, where u(t) represents the unit step function, we can apply inverse Laplace transform techniques to the transfer function Vc(s)/Vs(s). This will yield the time-domain response of the system to a step input.

Similarly, to find the response to Vs(t) = o(t)V, where o(t) represents the unit impulse function, we can use inverse Laplace transform techniques on the transfer function Vc(s)/Vs(s). This will give us the time-domain response of the system to an impulse input.

By calculating the inverse Laplace transforms of the transfer functions in cases 3) and 4), we can obtain the time-domain responses of the electrical system to the respective inputs.

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Answer: They CG of a vehicle highly influences manuovereability and performance / dynamic control over vehicle.

Explanation: it was from quora

you are so much welcome

Answer:

E = h ν        energy of electromagnetic particle  

(b)   has the greater frequency

Answer:

the great plague

Explanation:

The force on the negatively charged object is approximately -1.44 N. The force between two charged objects can be calculated using Coulomb's law.

Coulomb's law states that the force (F) between two charges (q1 and q2) is proportional to the product of the charges and inversely proportional to the square of the distance between them.

Mathematically, Coulomb's law is represented as:

F = k * (|q1| * |q2|) / r^2,

where F is the force, k is the electrostatic constant (9 × 10^9 N m^2/C^2), |q1| and |q2| are the magnitudes of the charges, and r is the distance between the charges.

In this case, the pith ball possesses a charge of +10 μC (10 × 10^-6 C), and the metal plate possesses a charge of -64 μC (-64 × 10^-6 C). The distance between them is 0.02 m.

Plugging in the values into Coulomb's law:

F = (9 × 10^9 N m^2/C^2) * ((10 × 10^-6 C) * (-64 × 10^-6 C)) / (0.02 m)^2.

Simplifying the calculation:

F = (9 × 10^9 N m^2/C^2) * (-640 × 10^-12 C^2) / (0.0004 m^2).

F = -2.56 × 10^-3 N.

Therefore, the force on the negatively charged object is approximately -1.44 N (since the negative sign indicates the direction of the force).

The force on the negatively charged object is approximately -1.44 N. This is calculated using Coulomb's law, which considers the magnitude of the charges and the distance between them. The negative sign indicates an attractive force between the two charges.

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Answer:

try this

Explanation:

The energy of a falling object when it hits the ground is equaled to the energy it starts with because the potential energy is converted into kinetic energy entirely with the height at 0. This means the energy would be 200 J.

RESULT