A smooth 3-in. -diameter hole is punched into the side of a large chamber where oxygen

is stored at 500°R and 150 psia. Assume frictionless flow.

(a) Compute the initial mass flow rate from the chamber if the surrounding pressure is

15. 0 psia.

(b) What is the flow rate if the pressure of the surroundings is lowered to zero?

(c) What is the flow rate if the chamber pressure is raised to 300 psia?

Answers:

(a) 26. 5 lbm/sec; (b) no change; (c) 53. 0 lbm/sec

Answers

Answer 1

The initial mass flow rate from the chamber can be computed using the equation for isentropic flow:

\(m = A * (P / \sqrt(T)) * \sqrt(k / R) * [(2 / (k + 1)) ^ ((k + 1) / (2 * (k - 1))]\)

Where m is the mass flow rate, A is the area of the hole, P is the pressure of the chamber, T is the temperature of the chamber, k is the specific heat ratio, and R is the gas constant.

Plugging in the given values:

\(m = (\pi * (3 / 12) ^ 2) * (150 / \sqrt(500)) * \sqrt(1.4 / 0.068) * [(2 / (1.4 + 1)) ^ ((1.4 + 1) / (2 * (1.4 - 1)))]\)

m = 26.5 lbm/sec

(b) If the pressure of the surroundings is lowered to zero, there is no change in the flow rate because the flow is choked, meaning that the flow rate is limited by the sonic velocity at the throat of the nozzle.

(c) If the chamber pressure is raised to 300 psia, the flow rate can be computed using the same equation as before:

\(m = (\pi * (3 / 12) ^ 2) * (300 / \sqrt(500)) * \sqrt(1.4 / 0.068) * [(2 / (1.4 + 1)) ^ ((1.4 + 1) / (2 * (1.4 - 1)))]\)

m = 53.0 lbm/sec

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Related Questions

upon first connection to a pse, what level of resistance does a pd indicate that it has?

Answers

When a Power Sourcing Equipment (PSE) is connected to a Powered Device (PD) for the first time, the PD indicates the level of resistance it has by presenting a certain value of resistance to the PSE. This value is called the initial or startup resistance.
The initial resistance of a PD depends on the type of PD and the standard it complies with. Generally, there are two types of PDs: the Class 0 PDs and the Class 1-4 PDs.
Class 0 PDs are devices that do not have the capability to communicate with the PSE and do not require any power from the PSE for operation. They present a very high initial resistance (typically more than 100kΩ) to the PSE, indicating that they are non-compliant devices.
On the other hand, Class 1-4 PDs are devices that have the ability to communicate with the PSE and negotiate for power delivery. They present a lower initial resistance to the PSE (typically between 1kΩ to 25kΩ), indicating that they are compliant devices.
The specific value of initial resistance for a PD depends on the power class it belongs to. The IEEE 802.3af standard defines four power classes for PDs based on the maximum power they can consume: Class 0 (less than 4 watts), Class 1 (4 watts), Class 2 (7 watts), and Class 3 (15.4 watts). The higher the power class, the lower the initial resistance of the PD.
In summary, the initial resistance of a PD upon first connection to a PSE depends on the type of PD and the power class it belongs to. Class 0 PDs present a high initial resistance (typically more than 100kΩ), while Class 1-4 PDs present a lower initial resistance (typically between 1kΩ to 25kΩ), with the specific value depending on the power class.

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State Four Reasons for using plant and Equipment Sing

Answers

There will be several advantages to equipment standardization. Digital solutions accelerate standardization by giving an overview of the field equipment.

What benefit does using equipment provide?

By using the most effective and efficient procedures, they aid in accelerating the rate of output. Reduce construction costs overall, especially for big contracts. A machine or piece of equipment can effortlessly perform tasks that are too difficult or delicate for human muscles to complete.

What purposes do tools and equipment serve?

In general, they are used to assemble or disassemble objects (such as hammers and nail guns) (e.g., jackhammers and saws). Hand tools and power tools are two common categories for tools. All non-powered instruments are considered hand tools, such as such as pliers and hammers.

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Customer Responsibilities in SLAs. You have been chosen to work on a committee that is drafting an SLA to be used during negotiations with service desk customers. For the first meeting, each attendee has been asked to prepare a list of suggested customer responsibilities. Prepare for the meeting by listing your recommendations. Think through any service encounters you have been involved in (such as calling a software publisher or hardware vendor) when preparing your list and determine what you feel was reasonable for vendors to ask you to do.

Answers

Service level agreements, or SLAs, are notoriously challenging to track, analyze, and meet. In many service desks, they can also be challenging to configure and alter.

What does SLA in customer service stand for?

A service level agreement, A service-level agreement (SLA), which outlines the products or services to be supplied, the single point of contact for end-user issues, and the metrics by which the process' efficacy is reviewed and approved, establishes expectations between the service provider and the client.

The importance of SLA in customer service

An SLA specifies the kind of service you can anticipate and enables you to hold your service provider accountable. You can lessen some of the effects of the needs that were agreed upon are not covered by requiring your provider to make up the losses. SLAs are preferred by service providers as they significantly increase client retention.

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3. 1 4 1 5 9
this is pi

Answers

Answer:

FOLLOWED BY...  2 6 5 3 5 8 9

UwU

Circumference over diameter 7 9 then 3 2 3

Suppose Host A and Host B are separated by 15,000 kilometers. A direct link with rate, R = 5Mbps connects the two hosts. Suppose a propagation speed of 2.5x108 meters/sec. What is the bandwidth delay if using ∙ pppppppp

Answers

To calculate the bandwidth delay product, we need to multiply the bandwidth (R) by the round-trip time (RTT). The RTT is the time it takes for a packet to travel from the source (Host A) to the destination (Host B) and back. So, the bandwidth delay product in this scenario is 0.6 megabits (Mb).

First, we need to calculate the RTT. The RTT is the time it takes for a signal to propagate from Host A to Host B and back. Since the distance between the hosts is 15,000 kilometers, and the propagation speed is 2.5x10^8 meters/second, we can calculate the RTT as follows:

RTT = (2 * distance) / speed

RTT = (2 * 15,000,000 meters) / (2.5x10^8 meters/second)

RTT = 0.12 seconds

Now, we can calculate the bandwidth delay product:

Bandwidth Delay Product = Bandwidth (R) * RTT

Bandwidth Delay Product = 5 Mbps * 0.12 seconds

Bandwidth Delay Product = 0.6 megabits

Thus, the answer is 0.6 megabits (Mb).

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when defining an ada abstract data type, where are the specification, representation and implementation customary placed, respectively?

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When defining an Ada abstract data type, the specification, representation, and implementation are typically placed in different sections of the program, as follows:

Specification: The specification of the abstract data type defines its interface and behavior without revealing the implementation details. It includes the type definition, subprograms, and package specifications. The specification is usually placed in a separate package or package specification file (.ads) and serves as the public interface for the abstract data type.

Representation: The representation of the abstract data type defines the internal structure and layout of the data. It includes the private type declaration and any private variables or components needed for the implementation. The representation is typically placed in the private part of the package or a separate private package (.adb) that accompanies the specification.

Implementation: The implementation of the abstract data type consists of the actual code that implements the behavior and operations defined in the specification. It includes the subprogram bodies and any necessary helper functions or procedures. The implementation is usually placed in the body of the package (.adb) or in separate implementation-specific files.

By separating the specification, representation, and implementation, Ada promotes encapsulation and information hiding. The specification defines the public interface, while the representation and implementation remain hidden and can be modified without affecting the code that uses the abstract data type. This allows for modularity, abstraction, and easier maintenance of the program.

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Water flows through a horizontal bend and discharges into the atmosphere, as shown in Fig. P5.2.4. When the pressure gage reads 10 psi, the resultant x-direction anchoring force, FAx, in the horizontal plane required to hold the bend in place is shown on the figure. Determine the flowrate through the bend and the y-direction anchoring force, FAy, required to hold the bend in place. The flow is not frictionless.

Answers

To calculate the flowrate through the bend, use Bernoulli's equation. Connect the velocities and cross-sectional areas at sites 1 and 2 using the continuity equation.

Definition of the equation of continuity Explain it and provide a Bernoulli Theorem expression?

ρA1V1=ρA2V2. The Principle of Continuity is the name given to this equation. Let's say we need to determine the efflux speed for the following configuration. Bernoulli's equation, applied at points 1 and 2, reads as follows: p + 1 2 v 1 2 + g h = p 0 + 1 2 v 2 2.

\(P1 + 0.5rhoV1^2 + rhogh1 = P2 + 0.5rhoV2^2 + rhogh2\)

\(P1 + 0.5rhoV1^2 = P2 + 0.5rhoV2^2\)

The mass flow rate is constant along a streamline, hence when we solve for V2 using the continuity equation, we obtain:

\(V2 = sqrt(2*(P1-P2)/rho + V1^2)\)

\(Q = A1V1 = A2V2\)

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What variables can you control directly to change the weight of your rocket?

Answers

Answer:

Density and Volume

Your Welcome

At a certain location, wind is blowing steadily at 7 m/s. Determine the mechanical energy of air per unit mass and the power generation potential of a wind turbine with 80-m-diameter blades at that location. Also determine the actual electric power generation assuming an overall efficiency of 30 percent. Take the air density to be 1.25 kg/m3.

Answers

Answer:

Explanation:

From the information given;

The velocity of the wind blow V = 7 m/s

The diameter of the blades  (d) = 80 m

Percentage of the overall efficiency \(\eta_{overall} = 30\%\)

The density of air \(\rho = 1.25 kg/km^3\)

Then, we can use the concept of the kinetic energy of the wind blowing to estimate the mechanic energy of air per unit mass by using the formula:

\(e_{mechanic} = \dfrac{mV^2}{2}\)

here;

m = \(\rho AV\)

= \(1.25 \times \dfrac{\pi}{4}(80)^2 \times 7\)

= 43982.29 kg/s

\(W = e_{mechanic} = \dfrac{mV^2}{2}\)

\(= \dfrac{43982.29 \times 7^2}{2}\)

\(= 1077566.105 \ W\)

\(\mathbf{ =1077.566 \ kW}\)

The actual electric power is:

\(W_{electric} = \eta_{overall} \times W\)

\(W_{electric} = 0.3 \times 1077.566\)

\(\mathbf{W_{electric} =323.26 \ kW}\)

You have a 12-inch PVC water main that is 850 feet long flowing at 5.6 cfs. Point A is at an elevation of 750 ft. Point B is at an elevation of 765 ft. If the pressure in a water main at Point A is 85 psi, what is the pressure at point B, in psi? (5 points)

Answers

Known :

D = 12 in = 1 ft

L = 850 ft

Q = 5.6 cfs

hA = 750 ft

hB = 765 ft

PA = 85 psi = 12240 lb/ft²

Solution :

A = πD² / 4 = π(1²) / 4

A = 0.785 ft²

Velocity of water :

U = Q / A = 5.6 / 0.785

U = 7.134 ft/s

Friction loss due to pipe length :

Re = UD / v = (7.134)(1) / (0.511 × 10^(-5))

Re = 1.4 × 10⁶

(From Moody Chart, We Get f = 0.015)

hf = f(L / d)(U² / 2g) = 0.015(850 / 1)((7.134²) / 2(32.2))

hf = 10 ft

PA + γhA = PB + γhB + γhf

PB = PA + γ(hA - hB - hf)

PB = 12240 + (62.4)(750 - 765 - 10)

PB = 10680 lb/ft²

PB = 74.167 psi

Which of the following is not a characteristic of an external combustion engine?
A. External pistons are used.
B. Fuel is sent directly to the engine.
C. Boiler burns fuel to produce steam.
D. Steam is sent to the engine to produce power.

Answers

Answer is B. Fuel is sent directly to the engine :)

Why is the reasoning important when you make a scientific argument?

Answers

Answers and credibility of how you got there without reasoning

Design a circuit that can convert a 50Hz triangular wave with 1V peak into a TTL-compatible pulse wave with fundamental frequency of 50Hz. Draw the input-output waveforms vs. time.

Answers

The given triangular waveform with 50 Hz frequency and 1 V peak is to be converted into a TTL-compatible pulse waveform with fundamental frequency 50 Hz. TTL-compatible pulse waveform has high and low voltage levels of 5 V and 0 V respectively.

The basic idea of conversion is to compare the input triangular waveform with a reference voltage level of 2.5 V (halfway between 5 V and 0 V) and create a pulse waveform such that output is high (5 V) when the input waveform is above 2.5 V and low (0 V) when the input waveform is below 2.5 V.

Here, we can use a simple NAND gate.The logic gate will produce a high output (5 V) only when both its inputs are low (0 V). Therefore, we can connect the comparator output to one input of the NAND gate and a 5 V source to the other input of the NAND gate. This will give a high output when the input waveform is below 2.5 V and low output when the input waveform is above 2.5 V. Thus, we will get a TTL-compatible pulse waveform.The circuit diagram is as shown below:And the input-output waveforms are shown below:

Therefore, we have successfully designed a circuit that can convert a 50 Hz triangular wave with 1V peak into a TTL-compatible pulse wave with a fundamental frequency of 50Hz.

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Cell phones require powerful batteries in orde to work effectively. Which activity is best described as an engineering endeavor related to cell phone batteries

Answers

Where are the options?

A hydrogenation catalyst is prepared by soaking alumina particles (100-150 mesh size) in aqueous NiNO3 solution. After drying and reduction, the particles contain about 7 wt% NiO. This catalyst is then made into large cylindrical pellets for rate studies. The gross measurements for one pellet are: Mass, g 3.15 Diameter, mm 25 Thickness, mm 6 Volume, cm3 3.22 The alumina particles contain micropores, and the pelleting process introduces macropores surrounding the particles. If the macropore volume of the pellet is 0.645 cm3 and the micropore volume is 0.40 cm3 /g of particles, determine: i] The density of the pellet ii] The macropore volume in cm3 /g iii] The macropore void fraction in the pellet iv] The micropore void fraction in the pellet v] The solid fraction vi] The density of the particles

Answers

i] The density of the pellet is 0.977 g/cm^{3}. ii] The macropore volume in cm^{3}/g is 0.205 cm^{3}/g. iii] The macropore void fraction in the pellet is 25.1%.iv] The micropore void fraction in the pellet is 49.0%. v] The solid fraction of the pellet is 25.9%. vi] The density of the particles is 1.222 g/cm^{3}.

i] To determine the density of the pellet, we can use the formula:

Density = Mass / Volume

Given that the mass of the pellet is 3.15 g and the volume is 3.22cm^{3}, we can calculate the density as follows:

Density = 3.15 g / 3.22 cm^{3}≈ 0.977 \(g/cm^{3\)

ii] The macropore volume in cm3/g can be calculated by dividing the macropore volume of the pellet (0.645 cm3) by the mass of the pellet (3.15 g):

Macropore volume = 0.645 cm^{3} / 3.15 g ≈ 0.205 \(cm^{3} /g\)

iii] The macropore void fraction in the pellet can be calculated using the formula:

Macropore void fraction = Macropore volume / Total volume of the pellet

Total volume of the pellet = Volume - Macropore volume = 3.22 cm^{3}- 0.645 cm^{3} = 2.575 cm^{3}

Macropore void fraction = 0.645 cm^{3} / 2.575 \(cm^{3}\)≈ 0.251 or 25.1%

iv] The micropore void fraction in the pellet can be calculated using the given micropore volume of the particles (0.40 cm^{3} /g) and the mass of the pellet (3.15 g):

Micropore volume in the pellet = Micropore volume/g x Mass

Micropore volume in the pellet = 0.40 \(cm^{3} /g\) x 3.15 g = 1.26 cm3

Micropore void fraction = Micropore volume in the pellet / Total volume of the pellet

Micropore void fraction = 1.26 \(cm^{3}\) / 2.575 \(cm^{3}\) ≈ 0.490 or 49.0%

v] The solid fraction of the pellet can be calculated by subtracting the sum of macropore and micropore void fractions from 1:

Solid fraction = 1 - (Macropore void fraction + Micropore void fraction)

Solid fraction = 1 - (0.251 + 0.490) ≈ 0.259 or 25.9%

vi] The density of the particles can be determined using the mass of the pellet (3.15 g) and the total volume of the particles:

Total volume of the particles = Volume - Macropore volume = 3.22 \(cm^{3}\)- 0.645 \(cm^{3}\) = 2.575\(cm^{3}\)

Density of the particles = Mass / Total volume of the particles

Density of the particles = 3.15 g / 2.575\(cm^{3}\) ≈ 1.222 \(g/cm^{3}\)

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When driving a commercial motor vehicle safely, it is recommended that you leave at
least one second between your vehicle and the vehicle you are following for each
feet of your vehicle's length.

Answers

Answer:

If you are driving below 40 mph, you should leave at least one second for every 10 feet of vehicle length.

“Snow Cover Area change Analysis for Kabul Basin”

Summarize how GIS & Remote Sensing is incorporated in this study.

Answers

GIS

The full for GIS is : Geographic Information System.

The GIS is a system of mapping that is used to create, analyze, manage and map all the types of data.

It is a method capturing, checking as well as displaying all the data that is related to the position of the surface of earth.

Remote Sensing

Remote sensing is defined as a process where the various physical characteristics of an area are constantly monitored and detected by a process of measuring the reflection of the emitted radiations at ta distance.

The snow covered areas of the Kabul basin can be monitored and analyzed by using the process of GIS and remote sensing.

They provide a continuous source of information and data about snow covered peaks, the amount of snow to the authorities.

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What strategy may help a visual learner process data?

Answers

A strategy that may help a visual learner process data is a pie chart or histogram.

water is to be pumped from the large tank shown with an exit velocity of 6 m/s. it was determined that the original pump (pump 1) that supplies 1 kw of power to the water did not produce the desired velocity. it is proposed that an additional pump (pump 2) be installed as indicated to increase the flowrate to the desired value. how much power (in kw) must pump 2 add to the water? the head loss for this flow is hl

Answers

Pump 2 must add approximately X kW of power to the water.

To determine the power required by Pump 2, we need to consider the change in kinetic energy of the water as it exits the tank. The kinetic energy can be calculated using the formula:

Kinetic Energy = (1/2) * mass * velocity^2

Since the water has an exit velocity of 6 m/s, we can calculate the initial kinetic energy. We are given that Pump 1 supplies 1 kW of power, so we can use this information to find the flow rate (Q) in kg/s using the equation:

Power (P) = Q * Head Loss (hl) * g

We know the velocity (V) is equal to the flow rate (Q) divided by the cross-sectional area (A) of the tank. Therefore:

Q = A * V

By substituting this equation into the power equation, we can solve for the flow rate Q:

1 kW = (A * V) * hl * g

Once we have the flow rate, we can determine the mass of water (m) using the equation:

mass = Q * density

With the mass and the exit velocity, we can calculate the initial kinetic energy. To achieve the desired velocity, the kinetic energy must increase. The additional power required by Pump 2 can be calculated by finding the difference between the final and initial kinetic energies.

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In an MDI device, which two pins does the device use to transmit?
Answers: a. 1 and 2 b. 3 and 4 c. 4 and 6 d. 3 and 6

Answers

The answer is d. 3 and 6. An MDI (Metered Dose Inhaler) device is used to deliver medication to the lungs in the treatment of respiratory diseases such as asthma and COPD.

It consists of a canister containing the medication and a metering valve that dispenses a precise amount of medication with each actuation. The device is actuated by depressing the canister, which releases the medication through a mouthpiece. The valve is opened by depressing a stem, which is connected to the canister by a gasket. The gasket contains two small holes, one of which is connected to pin 3 and the other to pin 6 of the valve stem. When the stem is depressed, the holes are aligned and the medication is released through the mouthpiece.

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A switch that can open or close an electric circuit can be used to?

Answers

Answer:

When a switch is in the "off" position the circuit is open. Electric charges cannot flow when a switch is in the off position.

Explanation:

A switch that can open or close an electric circuit can be used to stop the flow of current.

What is a switch?

A switch can be defined as an electrical component (device) that is typically designed and developed for interrupting the flow of current or electrons in an electric circuit.

This ultimately implies that, a switch that can open or close an electric circuit can be used to stop the flow of current.

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Que 18. In a centrifugal pump work done by impeller is 350 kW and manometric efficiency is 58 %. Find power delivered by the pump. ​

Answers

To find the power delivered by the pump, we can use the concept of pump efficiency. The power delivered by the pump is given by the equation:

Power Delivered = Power Input / Efficiency Given: Work done by the impeller (Power Input) = 350 kW Manometric Efficiency = 58% = 0.58 Now, let's calculate the power delivered by the pump: Power Delivered = Power Input / Efficiency Power Delivered = 350 kW / 0.58 Power Delivered ≈ 603.448 kW Therefore, the power delivered by the pump is approximately 603.448 kW. The power delivered by the pump is 603.45 kW. This is calculated by dividing the work done by the impeller (350 kW) by the manometric efficiency (58%) and multiplying by 100The manometric efficiency of a centrifugal pump represents the ratio of the energy imparted to the fluid (work done by the impeller) to the actual energy added to the fluid (power delivered by the pump). It is expressed as a percentage.

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A liquid of specific heat 3000J/kgk rise from 15°c to 65°c in 1 min when an electric heater is used. If the heater generate 63000J, calculate the mass of the water​

Answers

Answer:

  0.42 kg

Explanation:

Heat is proportional to mass by way of the conversion factor that is the inverse of the specific heat.

  \(\dfrac{63000\text{ J}}{\dfrac{3000\text{ J}}{\text{kg$\cdot$K}}\cdot(65-15)\text{ K}}=0.42\text{ kg}\)

The mass of the liquid is about 0.42 kg.

How often might ergonomic training be offered in the workplace

Answers

Answer:

'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​

'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​v'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'स माचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?​

Explanation:

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A cylindrical metal specimen having an original diameter of 11.04 mm and gauge length of 54.1 mm is pulled in tension until fracture occurs. The diameter at the point of fracture is 7.44 mm, and the fractured gauge length is 71.0 mm. Calculate the ductility in terms of (a) percent reduction in area (percent RA), and (b) percent elongation (percent EL).

Answers

The ductility of the cylindrical metal specimen in terms of percent reduction in area is approximately 54.45 % and in terms of percent elongation is approximately 31.24 %.

How to solve for the ductility

Percent RA = [(A0 - A f) / A0] * 100

Let's calculate it:

A₀ = \(\pi *(11.04 mm / 2)^2\) ≈ 95.61 mm²

A f = \(\pi *(7.44 mm / 2)^2\)≈ 43.54 mm²

Percent RA = [\((95.61 mm^2 - 43.54 mm^2) / 95.61 mm^2\)] * 100

≈ 54.45 %

(b) Percent Elongation (Percent EL):

The percent elongation can be calculated using the formula:

Percent Elongation = [(Lf - L0) / L0] * 100

Let's calculate it:

Percent Elongation = [(71.0 mm - 54.1 mm) / 54.1 mm] * 100

≈ 31.24 %

Therefore, the ductility of the cylindrical metal specimen in terms of percent reduction in area is approximately 54.45 % and in terms of percent elongation is approximately 31.24 %.

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How many additional years does it take to earn a Masters after getting a Bachelors degree?

Answers

Answer: Most master’s degree programs will take an average of two years from start to finish – about half of the time it takes to earn your bachelor’s degree. While bachelor’s degree programs involve many introductory and general education courses, a master’s degree curriculum is all about the subject area you selected to study.

Explanation: Hope this was helpful

Can anyone tell me all the corrects answers to these? I’m sorry if this is the wrong subject I’m not sure what to put it under but I really need help!

Can anyone tell me all the corrects answers to these? Im sorry if this is the wrong subject Im not sure

Answers

Answer:

Crankshaft position sensor - F     I can't quite make out the letter but it's the thing at the bottom almost touching the notched wheel.

Coil Module - B  

Knock Sensor - D

Coil Pack -E

Fuse Block - A

Powertrain Control Module - C

An electric motor runs at 600 r/min when driving a load requiring a torque of 200 N m. Ifthe motor input is 15 kW, calculate the efficiency of the motor and the heat lost by the motor perminute, assuming its temperature to remain constant

Answers

The efficiency of the motor is 80%.

The heat lost by the motor per minute is 7.5 kW.

Here are the calculations:

The output power of the motor is given by:

P_o = τ * ω

where τ is the torque and ω is the angular velocity.

P_o = 200 N m * (2π * 600 r/min) / 60 s/min = 6000 W

The efficiency of the motor is given by:

η = P_o / P_i

where P_i is the input power.

η = 6000 W / 15 kW = 0.8

The heat lost by the motor per minute is given by:

Q = P_i - P_o

Q = 15 kW - 6000 W = 7.5 kW

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Consider the following data for 2008 in a small suburban community:

1. number of accidents: 360 fatal 10 injury 36 pdo 314
2. number of fatalities 15
3. area population: 50,000
4. registered vehicles 35,000
5. annual vmt: 12,000,000
6. average speed 30 mi/hr

compute all relevant exposure and population based accident and fatality rates for this data. compare these to national norms for the current year. (hint: use the internet to location current national norms)

Answers

Answer:

Motorcyclist Fatality and Injury Rates per Vehicle Miles Traveled, 1998-2008. 10. 9. Fatalities in School Transportation Related Crashes,. 1998-2008.

Explanation:

estimate the diffusion coefficient of fibrinogen, assuming that it is a a) a prolate ellipsoid b) a cylindrical rod c) a sphere. which shape, if any is an accurate model of the shape of fibrinogen (measured diffusion coefficient

Answers

Estimate the diffusion coefficient of fibrinogen, assuming different shapes: a) prolate ellipsoid, b) cylindrical rod, c) sphere. Determine the accurate model for fibrinogen's shape based on measured diffusion coefficient.

How can we estimate the diffusion coefficient of fibrinogen and determine its accurate shape model?

Fibrinogen, a protein involved in blood clotting, can exhibit different shapes in solution. To estimate its diffusion coefficient, we consider three potential shapes: a) a prolate ellipsoid (elongated), b) a cylindrical rod, and c) a sphere. The diffusion coefficient describes the rate at which a molecule moves through a medium.

To estimate the diffusion coefficient, we can apply mathematical models such as the Stokes-Einstein equation, which relates the diffusion coefficient to the size and shape of a molecule. However, the accuracy of the estimated diffusion coefficient depends on the assumption about the molecule's shape.

For a prolate ellipsoid, the diffusion coefficient would be influenced by its elongation and aspect ratio. Similarly, a cylindrical rod's diffusion coefficient would depend on its length and radius. On the other hand, if fibrinogen behaves as a sphere, its diffusion coefficient would solely rely on its molecular size.

To determine the accurate model for fibrinogen's shape, we need to compare the estimated diffusion coefficients with experimentally measured values. By measuring the diffusion of fibrinogen under controlled conditions, such as in a suitable medium, we can obtain the actual diffusion coefficient. Comparing it to the estimations for each shape model will indicate which one accurately represents fibrinogen's shape.

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