Answer:
Explanation:
The needle is showing north south direction . when current starts flowing in the wire which is held vertical to the ground , it deflects towards east .
a )
Therefore a magnetic field towards east has been created . It is possible only if current flows towards the surface in the vertical wire .
b )
magnetic field created at the magnetic needle B = 10⁻⁷ x 2I / d where I is current and d is distance .
B = 10⁻⁷ x 2 x 26.3 / .27
= 194.81 x 10⁻⁷ T
angle of deflection of solenoid = 22.9°
Tan 22.9 = B /H
.422 = 194.81 x 10⁻⁷ / H
H = 461.63 x 10⁻⁷ T
= .46 x 10⁻⁴ T .
A) The current in the wire flows towards the Earth's surface
B) The magnitude of the horizontal component of the Earth's magnetic field is : 0.46 x 10⁻⁴ T
A) The compass needle held horizontally points in a North-south direction of the earth and also deflects eastwards when current is allowed to flow through it. The deflection of the needle indicates the presence/generation of a magnetic field on the earth surface. which is facilitated by the flow of the current in the wire towards the Earth's surface
B) Determine The magnitude of the horizontal component of the Earth's magnetic field
B ( magnetic field ) = 10⁻⁷ * 2I / d ---- ( 1 )
where : l = 26.3 A, d = 0.27 m
Back to equation ( 1 )
B = 10⁻⁷ * 2 * 26.3 / 0.27
= 194.81 * 10⁻⁷ T
Final step : Calculate the magnitude of horizontal component ( H )
Tan ∅ = B / H ---- ( 2 )
where : ∅ ( angle of deflection ) = 22.9°
∴ H = B / Tan ( 22.9° )
= ( 194.81 * 10⁻⁷ ) / 0.422
= 0.46 x 10⁻⁴ T
Hence we can conclude that The current in the wire flows towards the Earth's surface and The magnitude of the horizontal component of the Earth's magnetic field is : 0.46 x 10⁻⁴ T
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It takes 25.7 N to push a crate
at a constant speed across flat
ground where uk
= 0.238.
What is the normal force acting
on the crate?
(Unit = N)
Answer:
108 N
Explanation:
Divide the force by uk to get the normal force
(25.7)/(0.238) = 107.98 N = 108 N
Answer:
107
Explanation:
Find the vector whose magnitude is 5 and which is in the direction of the vector 4i -3j +k
The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
To solve this problemThe given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:
The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:
Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26
Normalize the vector by dividing each component by the magnitude:
Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k
Multiply the normalized vector by the desired magnitude:
To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:
Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)
Simplifying the expression gives:
Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k
So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
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1. The kinetic energy of a car is 8 106 J as it travels along a horizontal road. How much work is required to stop the car in 10 s? (A) zero joules (B) 8 105 J (C) 8 107 J (D)8 104 J (E) 8 106 J
The power to stop the car with kinetic energy of a car is \(8*10^{6} J\) as it travels along a horizontal road is \(8*10^{5} watt\), option B
What is Kinetic energy ?Kinetic energy can be seen as one that is been recorded when an object is able to move from a place , in a broad term we can say this is the energy that can be attributed to that of someone leaving a place and go to another place hence we can see it as the one in the motion.
The definition of energy as the "power to accomplish work" refers to the capacity to apply a force that moves an object. Even if the word is vague, it is clear what energy actually means: it is the force that causes objects to move. The two types can be attributed to the one we know which are kinetic and potential energy.
\(Power \frac{Energy}{time}\)
\(Energy = 8*10^{6} J\)
\(time = 10 s\)
\(Power = \frac{8*10^{6} J}{10}\)
\(power = 8*10^{5} watt\)
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proper question;
The kinetic energy of a car is 8 × 106 J as it travels along a horizontal road. How much power is required to stop the car in 10 s? (A) zero joules (B) 8 105 J (C) 8 107 J (D)8 104 J (E) 8 106 J
A block of mass m1 = 18.5 kg slides along a horizontal surface (with friction, μk = 0.22) a distance d = 2.3 m before striking a second block of mass m2 = 7.25 kg. The first block has an initial velocity of v = 8.25 m/s.
Assuming that block one stops after it collides with block two, what is block two's velocity after impact in m/s?
How far does block two travel, d2 in meters, before coming to rest after the collision?
Answer:
19.5 m/s
87.8 m
Explanation:
The acceleration of block one is:
∑F = ma
-m₁gμ = m₁a
a = -gμ
a = -(9.8 m/s²) (0.22)
a = -2.16 m/s²
The velocity of block one just before the collision is:
v² = v₀² + 2aΔx
v² = (8.25 m/s)² + 2 (-2.16 m/s²) (2.3 m)
v = 7.63 m/s
Momentum is conserved, so the velocity of block two just after the collision is:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
m₁u₁ = m₂v₂
(18.5 kg) (7.63 m/s) = (7.25 kg) v
v = 19.5 m/s
The acceleration of block two is also -2.16 m/s², so the distance is:
v² = v₀² + 2aΔx
(0 m/s)² = (19.5 m/s)² + 2 (-2.16 m/s²) Δx
Δx = 87.8 m
The velocity of block 2 and the distance traveled by it prior to being at rest post-collision are 19.5 m/s and 87.8 m. Check the calculations below:
FrictionGiven that,
\(m_{1}\) = 18.5 kg
d = 2.3m
To find,
Acceleration of block 1:
∑\(F = ma\)
⇒ -m₁gμ = m₁a
⇒ a = -gμ
⇒ a \(= -(9.8 m/s^2) (0.22)\)
∵ a \(= -2.16 m/s^2\)
Now,
To determine the velocity of block one prior to the collision:
We know,
The initial velocity of block 1 = 8.25 m/s
⇒ \(v^2 = v_{o}^2 + 2\)aΔx
⇒ \(v^2 = (8.25 m/s)^2 + 2 (-2.16 m/s^2) (2.3 m)\)
∵ \(v = 7.63 m/s\)
We also know,
\(m_{2}\) = 7.25 kg
Now,
The velocity of block 2 post collision:
⇒ \(m_{1} u_{1} + m_{1} u_{1} = m_{1} v_{1} + m_{2} v_{2}\)post-collision
Through this,
⇒ \((18.5 kg) (7.63 m/s) = (7.25 kg) v\)
∵\(v = 19.5 m/s\)
The distance can be found through:
⇒ \(v^2 = v_{o} ^{2} + 2\)\(a\)Δ\(x\)
⇒ \((0 m/s)^2 = (19.5 m/s)^2 + 2 (-2.16 m/s^2)\)Δ\(x\)
∵ Δ\(x = 87.8 m\)
Thus, 19.5 m/s and 87.8 m are the correct answers.
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Explain the difference between a high tide and a low tide.
Answer: Tidal range
Explanation:
Tides are considering the rise and fall of sea levels and there are two types of it which are called high tide and low tide. The difference between high tide and low tide is called the tidal range.
The tidal range is not constant and it is considering height difference. It can change and it is depending on the locations of the Sun or the Moon.
High tide is the highest level of the place where the water rises because when the water rises to its highest level, then the water is reaching its high tide.When it comes to low tide, then it is the opposite of high tide. Water is reaching its lowest level.
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The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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A satellite is orbiting the earth at 15000.km above the center of the earth, What speed is it going?
On the moon, what would be the force of gravity acting on an object that has a mass of 7kg?
Answer:
Force of gravity, F = 70 N
Explanation:
It is required to find the force of gravity acting on an object that has a mass of 7 kg. Force of gravity always acts in downward direction.
The force of gravity is equal to the weight of an object. It is given by :
\(F=mg\)
g = acceleration due to gravity, for Earth, g = 10 m/s²
So,
\(F=7\times 10\\\\F=70\ N\)
So, 70 N of force of acting on an object.
what are the strengths and weaknesses of the four methods of waste management?
Answer & Explanation: Waste management are all activities and actions required to manage waste from its inception to its final disposal. There are several methods of managing waste with its strengths and weaknesses. The strengths include;
* It creates employment
* It keeps the environment clean
* The practice is highly lucrative
* It saves the earth and conserves energy
The weaknesses of the methods of waste management includes;
* The sites are often dangerous
* The process is mostly
* There is a need for global buy-in
* The resultant product had a short life
Seven little spheres of mercury, each with a diameter of 2 mm. When they coalesce to form a single sphere, how big will it be (i.e. what is its diameter)? How does its surface area compare with the total surface area of the previous Seven little spheres?
Answer:
The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.
Explanation:
Volume of a Sphere
The volume of a sphere of radius r is given by:
\(\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3\)
The volume of each little sphere is:
\(\displaystyle V_l=\frac{4}{3}\cdot \pi\cdot 2^3\)
\(V_l=33.51\ mm^3\)
When the seven little spheres coalesce, they form a single bigger sphere of volume:
\(V_b=7*V_l=234.57\ mm^3\)
Knowing the volume, we can find the radius rb by solving the formula for r:
\(\displaystyle V_b=\frac{4}{3}\cdot \pi\cdot r_b^3\)
Multiplying by 3:
\(3V_b=4\cdot \pi\cdot r_b^3\)
Dividing by 4π:
\(\displaystyle \frac{3V_b}{4\cdot \pi}= r_b^3\)
Taking the cubic root:
\(\displaystyle r_b=\sqrt[3]{\frac{3V_b}{4\cdot \pi}}\)
Substituting:
\(\displaystyle r_b=\sqrt[3]{\frac{3*234.57}{4\cdot \pi}}\)
\(r_b=3.83\ mm\)
The surface area of the seven little spheres is:
\(A_l=7*(4\pi r^2)=7*(4\pi 2^2)=351.86\ mm^2\)
The surface area of the bigger sphere is:
\(A_b=4\pi r_b^2=4\pi (3.83)^2=184.33\ mm^2\)
The ratio between them is:
\(\displaystyle \frac{351.86\ mm^2}{184.33\ mm^2}=1.91\)
The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.
Most of the heat transfer that is taking place on the earth is by ...
By conduction and convection, Most of the heat transfer that is taking place on the earth.
Conduction uses direct molecule contact to transport heat. Thermal energy will be transferred from an area with more kinetic energy to one with less kinetic energy. Slower-moving particles will collide with faster-moving ones. The kinetic energy of the slower-moving particles will consequently grow. The most frequent method of heat transfer, conduction, involves direct physical contact.
Thermal energy is transferred when a fluid, such as air or a liquid, is heated and subsequently moves away from the source. Convection is the name for this form of heat transmission. A hot surface causes the fluid above it to expand, lose density, and rise.
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if the initial velocity of body is 2 metre per second and final velocity is four metre per second calculate average velocity
Answer:
3 m/s
Explanation:
Average velocity = Initial velocity + Final velocity / 2
Solving :
⇒ Average velocity = 2 + 4 / 2
⇒ Average velocity = 6/2
⇒ Average velocity = 3 m/s
if the initial velocity of body is 2 metre per second and final velocity is four metre per second calculate average velocity
Solution:AV = 2 + 4 / 2AV = 6/2AV = 6 ÷ 2AV = 3m/sSo the average velocity is 3ms.
Which particles are considered nucleons? O A. Electrons and neutrons O B. Neutrons and protons OC. Protons and electrons D. Only electrons
The particles that are considered nucleons are neutrons and protons. Option B.
What are nucleons?Nucleons are particles found in the nucleus of an atom, specifically protons and neutrons.
Protons have a positive charge, while neutrons have no charge, and together they make up the majority of the mass of an atom.
Electrons, on the other hand, are much smaller than protons and neutrons, and they orbit around the nucleus in shells. Since they are not found in the nucleus, electrons are not considered nucleons.
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Un pato que nada en un estanque efectúa cuatro oscilaciones en 5 s. Calcula el período de las ondas causadas por las oscilaciones del pato.
Answer:
Explanation:
que paso cuz
What is the energy stored in food?
Hey there!
The energy that is stored in food is called CHEMICAL ENERGY
So, when humans/people eat foods their bodies transfigure the energy that is stored which is known as the calories.
Whereas the chains (bonds) in the middle of the atoms in the food humans eat that break up the check mal reactions that has been taken into place and newer compounds will be created. Each food that you eat stores unlikeable amounts of energy
Answer: Chemical energy
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What form of energy is released into the atmosphere by the earth's surface
Answer:
Thermal Energy (Heat)
Answer:
Heat
Explanation:
the form that is raised from the atmosphere from earths surface is heat
Which statement is true about the theory of plate tectonics and the theory of continental drift?
A) The theory of plate tectonics proves the theory of continental drift completely wrong.
B) The theory of plate tectonics tells exactly where the continents were before Pangaea divided.
C) The theory of plate tectonics gives the method by which continents can move as part of plates.
D) The theory of plate tectonics does not explain how continental movements could occur.
The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .
What is theory of plate tectonics and the theory of continental drift ?According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.
The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.
According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.
Therefore, option C is correct.
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(a) A person moves a distance of 3 km towards east, then 2 km towards north and then 3.5 km towards east.
Find :
(i) the distance covered by the person,
(ii) the displacement of this motion.
(b) Name the type of motion in which a body has uniform speed but not uniform velocity ?
Answer:
Explanation:
Answer:
The distance covered by the person is 8.5 metre and the displacement is 6.8 metre.
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b. printed circuit board A length th of copper track on a has a cross-sectional area of 5x108 m². The Current in the track is 3.5 mA. Your are with some useful information about of copper contains 6. 0x1026 atoms. show that the electron is about 10²⁹ m². copper. has a mass of 8.9x10³kg. skg of copper 29 for copper density number densi provided r. 1m²
Answer:
The change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².
The given parameters;
Current flowing in the wire, I = 4.00 mA
Initial diameter of the wire, d₁ = 4 mm = 0.004 m
Final diameter of the wire, d₂ = 1 mm = 0.001 m
Length of wire, L = 2.00 m
Density of electron in the copper, n = 8.5 x 10²⁸ /m³
The initial area of the copper wire;
The final area of the copper wire;
The initial drift velocity of the electrons is calculated as;
The final drift velocity of the electrons is calculated as;
The change in the mean drift velocity is calculated as;
The time of motion of electrons for the initial wire diameter is calculated as;
The time of motion of electrons for the final wire diameter is calculated as;
The average acceleration of the electrons is calculated as;
Thus, the change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².
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Explanation:
The changing mean drift velocity of the electrons plays out at 3.506 x 10⁻⁷ m/s along with an average acceleration nearing 4.38 x 10⁻¹⁵ m/s².
How to solveAs the electrons traverse one end of the wire to another, their mean drift velocity undergoes a shift of 3.506 x 10⁻⁷ m/s with an average acceleration of 4.38 x 10⁻¹⁵ m/s² in accordance with the following parameters:
- The current flowing through the wire is at 4.00 mA.
- The original diameter of the wire, d₁, measures at 4 mm or 0.004 m.
- Conversely, the final diameter, d₂, displays a measurement of 1 mm or 0.001 m.
- The length of the entire wire is consistent, measuring at 2 meters.
- Notably, the density of electrons present within copper reaches an estimated value of 8.5 x 10²⁸ /m³.
Calculations regarding both initial and final area coverage provided by copper must be explored along with numerical data involving the two varying drift velocities for accurate results.
Thus, we arrive at the change rate of the mean drift velocity between points in the wire as well as the plenitude of electron acceleration achieved after contemplation into the corresponding motion periods.
The conclusion reflects that our measurements find the changing mean drift velocity of the electrons plays out at 3.506 x 10⁻⁷ m/s along with an average acceleration nearing 4.38 x 10⁻¹⁵ m/s².
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A bicycle wheel has a diameter of 63.0 cm and a mass of 1.75 kg. Assume that the wheel is a hoop with all of the mass concentrated on the outside radius. The bicycle is placed on a stationary stand and a resistive force of 121 N is applied tangent to the rim of the tire. (a) What force must be applied by a chain passing over a 8.96-cm-diameter sprocket in order to give the wheel an acceleration of 4.40 rad/s2
Answer:
F2 = 834 N
Explanation:
We are given the following for the bicycle;
Diameter; d1 = 63 cm = 0.63 m
Mass; m = 1.75 kg
Resistive force; F1 = 121 N
For the sprocket, we are given;
Diameter; d2 = 8.96 cm = 0.0896 m
Radius; r2 = 0.0896/2 = 0.0448 m
Radial acceleration; α = 4.4 rad/s²
Now moment of inertia of the wheel which is assumed to be a hoop is given by; I = m(r1)²
Where r1 = (d1)/2 = 0.63/2
r1 = 0.315 m
Thus, I = 1.75 × 0.315²
I = 0.1736 Kg.m²
The torque is given by the relation;
I•α = F1•r1 - F2•r2
Where F2 is the force that must be applied by the chain to give the wheel an acceleration of 4.40 rad/s².
Thus;
0.1736 × 4.4 = (121 × 0.315) - (0.0448F2)
>> 0.76384 = 38.115 - (0.0448F2)
>> 0.0448F2 = 38.115 - 0.76384
>> F2 = (38.115 - 0.76384)/0.0448
>> F2 = 833.73 N
Approximately; F2 = 834 N
The force applied by a chain passing over a 8.96-cm-diameter sprocket in order to give the wheel an acceleration of 4.40 rad/s2 is F2 = 834 N
What is force?
Force is an external agent applied on any object to displace it from its position. Force is a vector quantity, so with magnitude it also requires direction. Direction is necessary to examine the effect of the force and to find the equilibrium of the force.
We are given the following for the bicycle;
Diameter; d1 = 63 cm = 0.63 m
Mass; m = 1.75 kg
Resistive force; F1 = 121 N
For the sprocket, we are given;
Diameter; d2 = 8.96 cm = 0.0896 m
Radius; r2 = 0.0896/2 = 0.0448 m
Radial acceleration; α = 4.4 rad/s²
Now the moment of inertia of the wheel which is assumed to be a hoop is given by;
\(I=mr_1^2\)
Where
r1 = 0.315 m
I = 1.75 × 0.315²
I = 0.1736 Kg.m²
The torque is given by the relation;
\(I\alpha=F_1\times r_1-F_2\times r_2\)
Where \(F_2\) is the force that must be applied by the chain to give the wheel an acceleration of 4.40 rad/s².
0.1736 × 4.4 = (121 × 0.315) - (0.0448\(F_2\))
0.76384 = 38.115 - (0.0448\(F_2\))
\(F_2= \dfrac{38.115-0.7638}{0.0448}\)
\(F_2=833.73\ N\)
Approximately; F2 = 834 N
Thus the force applied by a chain passing over a 8.96-cm-diameter sprocket in order to give the wheel an acceleration of 4.40 rad/s2 is F2 = 834 N
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A cricket bowler bowls a cricket ball with a perfectly straight arm, accelerating their arm until they achieve an angular velocity of 2400°/s just prior to releasing the cricket ball. Taking the shoulder joint as the axis of rotation, discuss how the more proximal regions of the arm e.g., the elbow area, will differ from the more distal points of the arm e.g., the hand/ball, in terms of angular displacement, angular velocity, and angular acceleration, as well as in terms of linear displacement, velocity, and acceleration?
The force applied on the hand/ball is lesser than the force applied on the arm, causing a lesser angular acceleration, velocity and displacement of the hand/ball.
Conservation of angular momentumThe angular acceleration of the ball is determined from the principle of conservation of angular momentum.
τ = Fr
Fr = Iα
α = Fr/I
F = Iα/r
where;
F is the force applied to the ballr is perpendicular distanceI is moment of inertia of the ballα is angular acceleration of the ballFrom the formula above, the greater the distance from axis of rotation, the lesser the applied force.
The arm is closer to the axis rotation than the hand/ball.
The force applied on the hand/ball is lesser than the force applied on the arm.
When the applied force is small, the angular acceleration will be small.When the angular acceleration is small, the angular velocity will be small.When the angular velocity is small, the angular displacement will be small.Similar effect will happen to linear displacement, velocity, and acceleration.
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what is displacement
Answer:
Displacement is the absolute value of the difference between the initial position and the final position.
10. A pump lifted 50.0 kilograms of water at a constant velocity a vertical distance of 10.0 meters in 75.0 seconds. Theaverage power consumption of the pump is(a) 6.67 W(b) 16.7 W(c) 32.7W(d) 65.4 W
Given,
Mass of the water, m=50.0 kg
Height to which water was lifted, Δh=10.0 m
Time taken to pump the water, t=75.0 s
The work done to lift the water is given by the change in the potential energy of the water
i.e.
\(W=mg\Delta h\)Where g is the acceleration due to gravity.
On substituting known values in the above equation,
\(W=50.0\times9.8\times10.0=4900.0\text{ J}\)Power is given by
\(P=\frac{W}{t}\)Substituting the known values,
\(P=\frac{4900.0}{75.0}=65.3\text{ W}\approx65.4\text{ W}\)Therefore the power consumption of the pump is 65.4 W
What is the length of the path traveled between two points?
The length of the path traveled between two points is called distance.
About distanceDistance physically can refer to several different things, namely:
Distance traveled: the length of a specified path between two points; for example the distance traveled when using a vehicle on the highway. Straight line (Euclid) distance: the length of the shortest path between two points, which can be traveled if there are no obstacles between the two points (generally expressed formally as the Euclidean distance). Geodesic distance: the length of the shortest path between two points, which can be traveled without leaving a surface; for example the length of the great circle along the curvature of the Earth's surface. The length of a given path of an object moving back to its starting point, such as a ball being thrown straight up, or the Earth completing one orbit.Learn more about distance at
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A balloon has a charge of -1.0 x 10-6 C and is held 0.97 m away from a steel tube. If the force between them is -5.5 N, what is the charge of the tube?
We can use Coulomb's Law to solve this problem:
F = k * (q1 * q2) / r^2
where:
F = -5.5 N
k = Coulomb's constant (9.0 x 10^9 N·m^2/C^2)
q1 = charge of the balloon (-1.0 x 10^-6 C)
q2 = charge of the steel tube= ?
r = distance between the balloon and the steel tube (0.97 m)
Plugging in the given values and solving for q2:
-5.5 N = (9.0 x 10^9 N·m^2/C^2) * (-1.0 x 10^-6 C) * q2 / (0.97 m)^2
Solving for q2, we get:
q2 = (-5.5 N) * (0.97 m)^2 / [(9.0 x 10^9 N·m^2/C^2) * (-1.0 x 10^-6 C)]
q2 ≈ -6.4 x 10^-6 C
Therefore, the charge of the steel tube is approximately -6.4 x 10^-6 C.
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Why did Thomson observe two glowing dots when he put neon gas into a
cathode-ray tube?
Answer:
Electrons accelerated to high velocities travel in straight lines through an empty cathode ray tube and strike the glass wall of the tube, causing excited atoms to fluoresce or glow.
What is the powder taking the shape of?
The magnetic field
The poles
A snowman
A star
The powder takes the shape of a magnetic field.
What is the particle shape of powder?Powder morphology is connected to the shape and size of powder particles and is strongly dependent on the manufacturing methods. For example, mechanical alloying/mechanical milling leads to unevenly shaped powder particles, while gas dissipation leads to spherically shaped particles.
Atomized metal powder particles come in two basic particle shapes: those that are almost superbly round called spherical, and those that have lopsided, rounded shapes, called spheroidal.
So we can conclude that Powders are a group of particles of different sizes.
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Valerie's 170 W electric rollers are plugged into a 200 V line in her bedroom. What current do the electric rollers draw?
Given data
*The given power of the electric rollers is P = 170 W
*The given voltage is V = 200 V
The formula for the electric current of the electric rollers draw is given as
\(I=\frac{P}{V}\)Substitute the known values in the above expression as
\(\begin{gathered} I=\frac{170}{200} \\ =\text{0}.85\text{ A} \end{gathered}\)Hence, the electric rollers draw the electric current is I = 0.85 A
If friction is present when an object is dropped and hits the ground, how does its kinetic energy just before striking the ground compare to its gravitational potential energy at the top of the drop? OKinetic energy is greater. Kinetic energy is less. The energies are the same. The energies are unrelated.
Kinetic energy is less just before striking the ground compare to its gravitational potential energy at the top of the drop.
What is kinetic energy?
Kinetic energy, which can be seen in the moving of an object or subatomic particle, is the energy of motion. Kinetic energy is present in every particle and moving entity. Examples of kinetic energy in action include a person walking, a baseball soaring through the air, a piece of food dropping from a table, and a charged particle in an electric field.
A falling object loses potential energy while gaining kinetic energy. The difference between the rise in kinetic energy and the decrease in potential energy is exact. Thus, potential energy is transformed into kinetic energy when an item falls freely. The kinetic energy of the object is transformed into heat and sound energy when it strikes the earth.
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Use the following information to answer questions 2-4. Two people are playing a game of
tug-of-war with the rope attached to a mass of 25 kg at the center. The person pulling to
the left pulls with a force of 20 N. The person pulling to the right pulls with a force of 10 N.
2. Which direction will the 25 kg mass move?
a. Left
b. Right
C. It will not move
How do you know?
What will the velocity of the mass be after 1 second?
What will the velocity of the mass be after 2 seconds?
The direction in which the 25 kg mass will move is to the Left. The correct option is A.
This is because the force pulling to the left is greater than that to the right.
The velocity of the mass after 1 second will be 0.4 m/s
The velocity of the mass after 2 seconds will be 0.8 m/s
What is the net force on the mass of 25 kg?The net force o the mass of 25 kg is given below:
Net force = 20 N - 10 N
Net force = 10 N
The velocity of the mass is given by the formula below:
Velocity = net force * time / mass
velocity after 1 second = 10 * 1 / 25
velocity after 1 second = 0.4 m/s
velocity after 2 seconds = 10 * 2 / 25
velocity after 2 seconds = 0.8 m/s
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