a skydiver dives from an airplane. air resistance is measured each second following the skydiver’s jump.
a. the skydriver has the slowest speed 2 seconds
b.the skydriver has the slowest speed 4 seconds
c.the skydriver has the slowest speed 1 seconds
d.the skydriver has the slowest speed 3 seconds

Answer: UV rays, either from the sun or from artificial sources like tanning beds, can cause sunburn. Exposure to UV rays can cause premature aging of the skin and signs of sun damage such as wrinkles, leathery skin, liver spots, actinic keratosis, and solar elastosis. UV rays can also cause eye problems.

Explanation: Uv means ultraviolet

Seismic waves are sent from the AP center in an earthquake. Waves move through various materials in a variety of orientations. The seismic waves would go forth at the same pace in all directions, which would be true for everyone who felt the ground trembling. Here option A is the correct answer.

When an earthquake occurs, it generates seismic waves that travel through the Earth's layers and cause the ground to shake. These waves propagate in different directions and interact with the media they encounter, including rock, soil, and water. As a result, the shaking experienced by people who feel the earthquake may vary depending on their location and the type of surface they are standing on.

Out of the given options, only option A can be considered true for all people who feel earth-shaking. This is because seismic waves travel outward from the epicenter in all directions at the same speed, regardless of the type of surface they encounter. However, the other options are not necessarily true for all observers.

Option B, which suggests that the amplitude of the shaking will be the same for all observers, is not accurate because the intensity of the shaking can vary depending on factors such as the distance from the epicenter, the direction of propagation, and the type of soil or rock that the seismic waves encounter.

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Complete question:

An earthquake sends seismic waves outward from the epicenter. the waves travel through different media in different directions. what will be true for all people who feel the earth shaking?(1 point)

A - the seismic waves will travel outward at the same speed in all directions.

B - the amplitude of the shaking will be the same for all observers.

C - the earth will rise and fall with the same frequency.

D - the seismic waves will be equally far apart for all observers.

Answer:

D. Different types of telescopes are needed to collect data from different ranges of radiation.

Explanation:

Different types of telescopes are used in space science because each type is designed to detect a specific range of radiation in the electromagnetic spectrum. For example, gamma-ray detectors are used to detect high-energy gamma rays, while radio telescopes are used to detect long-wavelength radio waves. By using different types of telescopes, scientists can collect data from different ranges of radiation and gain a more complete understanding of the universe.

In order for the toy car to travel over all three hills, one of the changes that could be made to the model is to order the hills from tallest to shortest.

This is because when the car is released from the top of the first hill, it has potential energy due to its height.

As it travels down the hill, the potential energy is converted to kinetic energy, which is the energy of motion.

In order to make it up the next hill, the car needs to have enough potential energy to overcome the force of gravity pulling it back down.

By ordering the hills from tallest to shortest, the car will build up potential energy as it goes up each hill, allowing it to make it over the subsequent hills.

Adding a loop after the tallest hill may not necessarily maximize the kinetic energy of the car. While the loop may provide a brief increase in kinetic energy due to the car's acceleration,

it also introduces friction and air resistance that can slow the car down. In addition, the loop may not provide enough potential energy for the car to make it up the subsequent hills.

Ordering the hills from shortest to tallest may not provide enough potential energy for the car to make it over all three hills.

While the car may build up speed going down the shorter hills, it may not have enough potential energy to make it up the taller hills, resulting in it stalling out at point x again.

Therefore, ordering the hills from tallest to shortest is the best change to make to the model to ensure the car can travel over all three hills.

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Answer:

The energy changes

Explanation:

When an non-conservative force (for example friction, air resistance, applied force) does work on an object, the total mechanical energy (Ek+Ep) of that object changes. If positive work is done, then the object will gain energy. If negative work is done, then the object will lose energy.

A magnetic field's energy density, u, is given by: u = (1/2)μB^2 where is the permeability of empty space and B is the magnetic field's strength. A volume V's energy content is determined by.

U = uV = (1/2)μB^2V Given that V = 1.66 m3 and U = 7.50 x 10-3 J, we may solve for B as follows: B2 is equal to (2U)/(V) = (27.50 10-3 J)/(4 10 7 Tm/A 2 1.66 m3). B^2 = 3.584×10^3 T^2 B = √(3.584×10^3 T^2) = 59.86 T Hence, the magnetic field is around 59.86 T strong. Renew your effort The formula for a magnetic field energy density, u, is: u = (1/2)B2, where B is the magnetic field's intensity and is the permeability of empty space. The energy content of a volume V is given. A uniform magnetic field B stores energy of 7.50×10–3J in a box that is 1.66 m3 in volume.

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Answer:

The gravitational force between Saturn and it's moon is 1.62 m/s ^2

Explanation:

google it

Answer:

Explanation:

C bro

Answer:

Frictional Force = 1.8 N

Explanation:

From Newton's Second Law, we know that the acceleration is produced in an object, whenever an unbalanced force is applied to it. So, for the production of acceleration application of an unbalanced force is necessary. Since, the block is moving with uniform speed in this case. Therefore, there is no acceleration involved in the motion of block. So, the all the forces acting on the block must cancel the effect of each other. So, that there is no unbalanced force to produce any acceleration. Therefore, the frictional force must be equal to the applied force in order to cancel its effect and balance it.

Frictional Force = Applied Force

Frictional Force = 1.8 N

Answer:

 fem = -A β

Explanation:

Faraday's law gives the induced electromotive source (emf)

           fem = \(- \ \frac{d \phi_B }{dt}\)

the magnetic flux is

           \(\phi_B\) = B. A = B A cos θ

the bold are vectros.  In this case the normal to the ring is parallel to the magnetic field so the angle is zero  cos 0 = 1, also the area of the ring is constant

             fem = -A  \(\frac{dB}{dt}\)

we carry out the derivative of the function B = α + β t

            fem = -A β

so we see that there is an electromotive force in the ring.

Answer:

a)   τ₁ = 660 N m,  b)  τ’= 686 N m,  c)    F = 623.6 N

Explanation:

a) For this exercise let's use the concepts of torque and rotational balance.

For this we set a reference system at the base and assuming that the counterclockwise rotations are positive

where the force F = 600 N, the distance to the axis is x = 1.1 m, the mass of the system m = 70g and the weight is placed at the point of the center of  gravity x_{cm} = -1.0 m

The torque at the front is

          τ₁ = F x

          τ₁ = 600 1.1

          τ₁ = 660 N m

b) let's write the rotational equilibrium condition

           ∑ τ = 0

           τ'- W x_{cm} = 0

           τ ’= mg x_{cm}

            τ’= 70 9.8 1.0

            τ’= 686 N m

c) the greatest force Matt can apply

           τ’= F x

           F = τ’/ x

           F = 686 / 1.1

           F = 623.6 N

Answer:

Find the given attachments

The average speed and average velocity of a man walking 10m to east for 20s and 12m to west for 20s is 0.55 m/s and 0.05 m/s respectively.

The formula for average speed is total distance travelled upon time

average speed= total distance / total time

Average speed = 22m / 40 s

Average speed = 0.55 m/s

Thus, the average speed of a man walking 10m to east for 20s and 12m to west for 20s is 0.55m/s

The formula to calculate average velocity is

Average velocity = ΔD/Δt (total time)

Average velocity = 12-10/40s

Average velocity = 0.05 m/s

Thus, the average velocity of a man walking 10m to east for 20s and 12m to west for 20s is 0.05m/s

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1 minute = 60 seconds

30 minutes x 60 = 1800 seconds

24 m/s x 1800 seconds = 43,200 meters

1000 meters = 1 km

43,200 meters / 1000 = 43.2 km

The car traveled 43.2 km

The letter(s) typically used to represent energy density is "U" or "u". Energy density is a measure of the amount of energy stored in a given volume or mass of a substance. It is commonly used in the fields of physics and engineering to describe the amount of energy that can be stored in various materials or systems.

The symbol "U" or "u" is often used to represent energy density in equations and formulas, with the units of energy per unit volume or mass. For example, the energy density of a battery can be expressed in units of joules per cubic meter or watt-hours per kilogram, depending on the specific application.

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To learn the equilibrium and temperature.

What is equilibrium?

When Newton's first law is true, the equilibrium state of an object is present. When all external forces (including moments) operating on an object in a reference coordinate system are equal, the object is said to be in equilibrium. The net effect of all external forces and moments acting on this object is zero as a result.

What is temperatue?

Temperature is a unit of measurement that can be expressed on a variety of scales, including Fahrenheit and Celsius. Temperature shows the direction of the spontaneous movement of heat energy, i.e., from a hotter body (one with a higher temperature) to a colder body (one with a lower temperature).

Their temperatures must be equal if two bodies are in thermal equilibrium.

As for coldness or warmth, we generally observe that metals feel colder while non metallic objects don't (i.e. comparatively they feel warmer than metals). This is due to the fact that metals are good conductor of heat. So when we touch a metallic body, heat flows from our body and is transferred to other points of the metal object. Since our body loses heat, we feel cold. In non metals, this conduction of heat from point of contact to other locations does not happen.

Therefore, the amount of heat loss from our body is much smaller. So we don't feel that cold.

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As a roller coaster car crosses the top of a 60-m-diameter loop-the-loop, its apparent weight is the same as its true weight. The car's speed at the top will be 24.25 m/s

Any object moving in a circle (or along a circular path) experiences a centripetal force. That is, there is some physical force pushing or pulling the object towards the center of the circle. This is the centripetal force requirement.

diameter = 60 m

weight + normal = m\(v^{2}\)/r

m = mass

v = velocity

r= radius

since , apparent weight is the same as its true weight

2W = m\(v^{2}\)/r

2 * m * g = m\(v^{2}\)/r

v = \(\sqrt{2gr}\)

v = \(\sqrt{2 * 9.8 * 30}\) = 24.25 m/s

The car's speed at the top will be 24.25 m/s

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Answer:

40.1 m/s or 144.36 km/h

Explanation:

The equation is (v=∆ f/f) x (c/2)

V is velocity

delta f is returned frequency minus intial frequency divided by the initial frequency

c is the speed of light in m/s divided by 2

v= (400,000,109 Hz - 400,000,002 Hz)/400,000,002Hz x (299,792,458 m/s)/2

40cm³ is  volume of a metal block measures 10cm×2cm×2cm and 5 blocks have the same total volume.

volume=l×b×h

volume=10cm×2cm×2cm= 40cm³

volume=l×b×h

volume= 2cm×2cm×2cm=8cm³

blocks have the same total volume= 40cm³/8cm³= 5

The space occupied inside an object's borders in three dimensions is referred to as its volume. It is sometimes referred to as the object's capacity. Finding an object's volume can help us calculate the quantity needed to fill it, such as the volume of water needed to fill a bottle, aquarium, or water tank.

A sphere is the most basic and typical form of a three-dimensional shape. We see spheres on a regular basis in the form of balls, globes, ornamental lights, oranges, etc.

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The most energetic X-ray photon it can produce is 6.839 * \(10^{5}\) eV

An X-ray is an electromagnetic spectrum having wavelengths in the range of 10 pm to 10 nm.

where pm = picometer

            nm = nanometer

An X-ray tube is a vacuum tube that converts electrical input into X-rays.

It is given that an X-ray tube has an applied voltage of 685 kV.

V = 685 * \(10^{3}\) V

Photons are particles having energy or movement but it does not have mass or electrical charge.

E is the energy of the photon.

E = q * V

where q is the charge of the photon.

charge of a photon is 1.6 * \(10^{-19}\)

q = 1.6 *  \(10^{-19}\) C

E = q * V

  = 1.6 *  \(10^{-19}\) * 658 * \(10^{3}\)

  = 1096 * \(10^{-16}\)

E = 1.096 *  \(10^{-13}\) J

E = 1.096 * \(10^{-13}\) * 6.24 * \(10^{18}\)

E = 6.839 * \(10^{5}\) eV

Hence, the most energetic X-ray photon it can produce is 6.839 * \(10^{5}\) eV

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Answer:

587 N

Explanation:

So there is 198 N, 202 N, 187 N on the left

And 155 N, 252 N, 168 N on the right

So what I am thinking is adding them to get one answer for the left also one from the right.

Left : 202 + 198= 400 + 187= 587 N

Right : 155 + 252= 407 + 168= 575 N

Maybe the most force is greater

587 N > 575 N

Two cars X and Y start from two points separated by 75 m. Y which is ahead of X. starts from rest with acceleration of 10 m/s2 and X starts with uniform velocity of 40 m/s . The time gap between the two meetings would be approximately 1.44 seconds.

Let's assume that the two cars meet for the first time after time t₁, and then they meet for the second time after time t₂.

We can start by finding the time it takes for car Y to catch up to car X for the first time. We can use the following kinematic equation:

d = ut + (1/2)at²

where d is the distance between the two cars, u is the initial velocity of car X, a is the acceleration of car Y, and t is the time it takes for car Y to catch up to car X.

Plugging in the values, we get:

75 = 40t₁ + (1/2)(10)t₁²

Simplifying the equation, we get:

5t₁² + 8t₁ - 15 = 0

Solving for t1 using the quadratic formula, we get:

-t₁ = 1.5 seconds or -1 seconds

Since time cannot be negative, we discard the negative solution and conclude that the two cars meet for the first time after 1.5 seconds.

Now, let's find the time it takes for the two cars to meet for the second time. We can use the fact that the two cars have covered the same distance between their first and second meetings.

The distance covered by car Y during the time t₁ is:

d₁ = (1/2)(10)(1.5)² = 11.25 m

The distance remaining between the two cars is:

75 - 2d₂ = 52.5 m

To find the time it takes for car Y to cover this distance, we can use the same kinematic equation as before:

52.5 = 0t₂ + (1/2)(10)t₂²

Simplifying the equation, we get:

t₂ = (21)

Therefore, the time gap between the two meetings is:

t₂ - t₁ = √(21) - 1.5 seconds

So, the time gap between the two meetings is approximately 1.44 seconds.

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Answer:

Value of the resistors​ R = 2 ohm

Explanation:

Given:

Resistor R1 = 4 ohm

Resistor R2 = 4 ohm

Find:

Value of the resistors​ R

Computation:

We know that Resistor R1 and Resistor R2 connected in parallel series.

So,

Using common resistance in parallel series

⇒ 1/R = 1/R1 + 1/R2

⇒ 1/R = 1/4 + 1/4

⇒ 1/R = (1 + 1) / 4

⇒ 1/R = 2/4

⇒ R = 4/2

⇒ R = 2

Value of the resistors​ R = 2 ohm

Answer:

2.75x10⁻¹⁰m

Explanation:

By scientific notation, we have to express 0.000000000275 m in powers.

This can be done by counting the number of zeros after the decimal and the number after 0 which is 2.

from 2 to the decimal point, we have 10 characters

so we express it scientifically as,

= 2.75x10⁻¹⁰m

for easy understanding. i have added an attachment to help you out on how to do this.

(a) The work necessary to bring a 101 kg object to a height of 992 km above the surface of the Earth is 986 MJ. (b) The extra work needed to launch the object into circular orbit at a height of 992 km above the surface of the Earth is 458 MJ.

To bring an object to a height of 992 km above the surface of the Earth, we need to do work against the force of gravity. The work done is given by the formula;

W = mgh

where W is work done, m is mass of the object, g is acceleration due to gravity, and h is the height above the surface of the Earth.

Using the given values, we have;

m = 101 kg

g = 9.81 m/s²

h = 992 km = 992,000 m

W = (101 kg)(9.81 m/s²)(992,000 m) = 9.86 × 10¹¹ J

Converting J to MJ, we get;

W = 986 MJ

Therefore, the work necessary to bring a 101 kg object to a height of 992 km above the surface of the Earth is 986 MJ.

To launch the object into circular orbit at this height, we need to do additional work to overcome the gravitational potential energy and give it the necessary kinetic energy to maintain circular orbit. The extra work done is given by the formula;

W = (1/2)mv² - GMm/r

where W is work done, m is mass of the object, v is velocity of the object in circular orbit, G is gravitational constant, M is the mass of the Earth, and r is the distance between the object and the center of the Earth.

We can find the velocity of the object using the formula:

v = √(GM/r)

where √ is the square root symbol. Substituting the given values, we have;

v = √[(6.67 × 10⁻¹¹ N·m²/kg²)(5.97 × 10²⁴ kg)/(6,371 km + 992 km)] = 7,657 m/s

Substituting the values into the formula for work, we have;

W = (1/2)(101 kg)(7,657 m/s)² - (6.67 × 10⁻¹¹ N·m²/kg²)(5.97 × 10²⁴ kg)(101 kg)/(6,371 km + 992 km)

W = 4.58 × 10¹¹ J

Converting J to the required units, we get;

W = 458 MJ

Therefore, the extra work needed to launch the object into circular orbit at a height of 992 km above the surface of the Earth is 458 MJ.

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--The given question is incomplete, the complete question is

"(a) Calculate the work (in MJ) necessary to bring a 101 kg object to a height of 992 km above the surface of the Earth.__ MJ (b) Calculate the extra work (in MJ) needed to launch the object into circular orbit at this height of 992 km above the surface of the Earth .__MJ."--

48 m/s in terms of km/h is 720.8 km/h. In terms of m/min is 2880 m/min, in terms of km/s is 0.048 km/s and in terms of km/min is 2.88 km/min.

To solve this question, we need to understand some terms. The unit of velocity is measured in m/s. It can be expressed in different units of velocity.

1 km (kilometer) = 1000 meter

1 h (hour) = 3600 seconds

1 minutes = 60 seconds

To convert m/s into km/h,

48 m/s * 3600/1000 =  172.8 km/h

To convert m/s into m/min,

48 m/s * 60 = 2880 m/min

To convert m/s into km/s,

48 m/s ÷ 1000 = 0.048 km/s

To convert m/s into km/minutes,

48 m/s * 60 / 1000 = 2.88 km/min

Therefore, the 48 m/s expressed is 172.8 km/h, 2880 m/min, 0.048 km/s and 2.88 km/min.

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48 m/s is equivalent to  172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

To express 48 m/s in different units of velocity:

km/h (kilometers per hour):

To convert m/s to km/h, we can use the conversion factor of 3.6 since 1 m/s is equal to 3.6 km/h.

48 m/s * (3.6 km/h / 1 m/s) = 172.8 km/h

Therefore, 48 m/s is equivalent to 172.8 km/h.

m/min (meters per minute):

To convert m/s to m/min, we can use the conversion factor of 60 since there are 60 seconds in a minute.

48 m/s * (60 m/min / 1 s) = 2880 m/min

Therefore, 48 m/s is equivalent to 2880 m/min.

km/s (kilometers per second):

Since 1 kilometer is equal to 1000 meters, to convert m/s to km/s, we divide the value by 1000.

48 m/s / 1000 = 0.048 km/s

Therefore, 48 m/s is equivalent to 0.048 km/s.

km/minute (kilometers per minute):

To convert m/s to km/minute, we first need to convert m/s to km/s (as calculated in the previous step) and then multiply by 60 to convert seconds to minutes.

0.048 km/s * 60 = 2.88 km/minute

So, 48 m/s is equivalent to 2.88 km/minute.

Hence, 48 m/s is equivalent to approximately 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

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The speed of the 20-kg ball after collision is 11.7 m/s, and it is traveling in the westward direction. We can also say that the direction of the velocity is opposite to the direction of the initial velocity of the first ball.

Mass of the first ball (\(m_{1}\)) = 6 kg

Velocity of the first ball before collision (\(v_{1}\)i) = 30 m/s, traveling westward

Mass of the second ball (\(m_{2}\)) = 20 kg

Velocity of the second ball before collision (\(v_{2}\)i) = 0 m/s, at rest

Velocity of the first ball after collision (\(v_{1}\)f ) = 9.0 m/s, traveling eastward

Velocity of the second ball after collision ( \(v_{2}\)f)

Equation:Conservation of momentum:

\(m_{1}\)\(v_{1}\)i+ \(m_{2}\)\(v_{2}\)i=\(m_{1}\) \(v_{1}\)f + \(m_{2}\) \(v_{2}\)f

We can use the conservation of momentum equation to solve for the final velocity of the second ball (v2f). First, we need to find the initial velocity of the first ball in the eastward direction, which can be found using the velocity formula:

\(v_{1}\)i,east = -\(v_{1}\)i,west = -30 m/s

Now, we can substitute the given values into the conservation of momentum equation and solve for \(v_{2}\)f:

\(m_{1}\)\(v_{1}\)i+ \(m_{2}\)\(v_{2}\)i= \(m_{1}\)\(v_{1}\)f + \(m_{2}\) \(v_{2}\)f

(6 kg)(-30 m/s) + (20 kg)(0 m/s) = (6 kg)(9.0 m/s) + (20 kg)( \(v_{2}\)f )

-180 kgm/s = 54 kgm/s + 20 kg \(v_{2}\)f

-234 kgm/s = 20 kg \(v_{2}\)f

\(v_{2}\)f = (-234 kgm/s) / (20 kg)

\(v_{2}\)f = -11.7 m/s

Therefore, the speed of the 20-kg ball after collision is 11.7 m/s, and it is traveling in the westward direction. We can also say that the direction of the velocity is opposite to the direction of the initial velocity of the first ball.

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