a skater extends her arms horizontally, holding a 2 kg mass in each hand. she is rotating about a vertical axis with an angular velocity of 1 rev/s. if she pulls her hands in towards the center of her body, approximately what will the final angular velocity be if her own moment of inertia remains approximately constant at 5 kg m2, and the distance of the masses from the axis changes from 1 m to 0.2 m?

A good relationship must possess the attributes of communication and trust. Without trust, there can be no intimacy, and without communication, there can be no understanding.

This is a true expression of the truth. In order to build a solid and lasting connection between two individuals, communication and trust are essential elements of a good relationship.

Absolutely! Relationships that lack open and honest communication, as well as trust, are likely to be unstable and can lead to misunderstandings, conflicts, and even a breakdown of the relationship over time. Building a strong foundation of trust and communication can help ensure that a relationship can withstand challenges and grow stronger over time.

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Answer:

Even in space, objects have mass. And if they have mass, they have inertia. That is, an object in space resists changes in its state of motion. A force must be applied to set a stationary object in motion.

Answer:

get help with your work

try understand your work

ask your teacher for assistance or class

or maybe cheat but understand the work first if you wanna

Answer:

\(\boxed {\boxed {\sf 15 \ m/s \ or \ 15 \ m*s^{-1}}}\)

Explanation:

We are asked to find the final velocity. We are given the acceleration, time, and initial velocity, so we can use the following kinematics formula.

\(v_f= v_i+ at\)

In this formula, \(v_f\) is the final velocity, \(v_i\) is the initial velocity, \(a\) is the acceleration, and \(t\) is the time.

The bicycle has an initial velocity of 5.0 m *s⁻¹ or m/s, acceleration of 2 m/s², and a time of 5 seconds.

\(\bullet \ v_i = 5.0 \ m/s \\\bullet \ a= 2\ m/s^2\\\bullet \ t= 5 \ s\)

Substitute the values into the formula.

\(v_f=5.0 \ m/s + ( 2\ m/s^2 * 5 \ s)\)

Solve inside the parentheses.

\(v_f= 5.0 \ m/s + (10 \ m/s)\)

Add.

\(v_f= 15 \ m/s\)

The units can also be written as:

\(v_f= 15 \ m*s^{-1}\)

The bicycle's final velocity is 15 meters per second.

The dimensions of the rectangular waveguide are 2b × b = 2.93 × 0.93 m², where a = 2b. The working frequency of the waveguide is 1.77 GHz, and the cutoff frequencies for the first 5 modes are 80.6 MHz, 40.3 MHz, 88.4 MHz, 20.2 MHz, and 44.4 MHz respectively.

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When a net force is applied tangentially to the edge of a solid, uniform sphere that is at rest on a horizontal surface, the sphere will begin to rotate. This is because the force causes a torque, or rotational force, to be applied to the sphere. The torque causes the sphere to begin rotating around its central axis.The amount of torque that is applied to the sphere depends on the magnitude of the force and the distance between the force and the central axis of the sphere. The greater the distance between the force and the central axis, the greater the torque that is applied.

As the sphere begins to rotate, its kinetic energy increases. This energy is stored in the rotational motion of the sphere and is proportional to the square of its rotational speed. The sphere will continue to rotate until the force is no longer applied. At this point, the sphere will continue to rotate at a constant speed due to its inertia.

In order to stop the sphere from rotating, a torque must be applied in the opposite direction to the original torque. This can be done by applying a force at a distance from the central axis that is opposite in direction to the original force. Overall, when a net force is applied tangentially to the edge of a solid, uniform sphere on a horizontal surface, the sphere will begin to rotate around its central axis. The amount of rotation depends on the magnitude of the force and the distance between the force and the central axis. The sphere will continue to rotate until the force is no longer applied and will only stop rotating when a torque is applied in the opposite direction.

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Answer:

2700

Explanation:

1m/s=3.6km/hr

which class question is this

Answer:

2.00

Explanation:

Move the sinθ to the right.

Communications: Laura develops programs that flag suspicious network activity.

Communication involves the transfer of information from one person (sender) to another (recipient), especially through the use of semiotics, symbols, signs and network devices.

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The stress function of the form Φ = C(x²- y²) provides the solution for torsion of the bar.

To determine the expression of C and derive the given equation, we consider the torsion of a straight bar with a uniform elliptical cross-section. The stress function Φ is assumed to have the form Φ = C(x²- y²), where C is a constant.

By substituting the stress function into the torsion equation and solving for the shear stress τxy, we find that τxy = 2GC(xsin(θ) - ycos(θ)), where G is the shear modulus and θ is the angular coordinate.

To find the expression of C, we compare this equation with the given equation and equate the terms. This leads us to C = Ty/(2G), where Ty is the applied torque.

By further substituting the expressions for x and y in terms of the semimajor and semiminor axes, we can rewrite the equation as τxy = Ty(a²+ b²- 2Jx/R²), where J is the torsional constant and R is the radius of the cross-section.

The warping displacement θ(Φ - Φ0) can be obtained by integrating the torsion equation, which involves the shear stress τxy and the differential area of the cross-section. This displacement can be expressed as θ(Φ - Φ0) = -G∫(τxy dA).

In summary, the stress function Φ = C(x²- y²) provides the solution for torsion of the bar, where C = Ty/(2G) and the derived equation is τxy = Ty(a²+ b² - 2Jx/R²). The warping displacement can be calculated through the integration of the torsion equation.

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Answer:

The sea level will be 5m higher in 1667 y (years)

Explanation:

From the question, the rate at which the ocean's level is currently rising is about 3mm per year.

First, we will convert mm (millimeter) to m (meter)

1 mm = 0.001 m

Then,

3 mm = 3 × 0.001 m

= 0.003m

That is, the rate at which the ocean's level is currently rising is about 0.003m per year.

Now, to determine how long it will take for the ocean's level be 5 m higher than now at the given rate,

If the ocean rises 0.003 m in 1 year, then

the ocean will rise 5 m in x years

x = (5 m × 1 year) / 0.003 m

x = 5 / 0.003

x = 1666.67 years

x ≅ 1667 years

Hence, the sea level will be 5m higher in 1667 y (years)

Impulse is important because it is the force that changes an object's momentum.

Momentum is a physical concept that describes the movement of an object due to the product of its mass and velocity. Momentum is a vector quantity, meaning it has both a magnitude and a direction. In classical mechanics, momentum is conserved, meaning that the total momentum of a system remains constant over time.

In the examples given, impulse is what allows the elevator to be hoisted up, the nylon ropes to hold a climber's weight, the runner to move around the track, and the plane to take off from the runway. Without impulse, none of these activities would be possible.

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Answer: Aplitude

Explanation: Loudness depends on the amplitude,or height, of sound waves. The greater the amplitude, the louder the sound perceived. Amplitude is measured in decibels.

Answer:

Amplitude

Explanation:

The loudness of a sound is determined by the amplitude of the wave. In terms of the pattern of a transverse wave, amplitude refers to how "high" and "low" the waves go from the center line.

PF

Answer:

23 cm from the mirror

Explanation:

Answer:

left

Explanation:

When a force is applied in the opposite direction of motion, it opposes the motion of the object, causing its speed to decrease.

A force is an influence in physics that can change the motion of an object. A force can cause a mass object to change its velocity, or accelerate.

Intuitively, force can be described as a push or a pull. A force is basically a vector quantity as it has both magnitude and direction.

The term "force" has a specific meaning in science. At this level, it is perfectly acceptable to refer to a force as a push or a pull.

Another object applies a force to another. The concept of a force is not restricted to living or non-living things.

To slow a moving object, apply force in the opposite direction to the direction of motion.

Thus, the force should be applied from left to slow down the object.

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Answer:

Put water at room temperature into a vacuum chamber and begin removing the air. Eventually, the boiling temperature will fall below the water temperature and boiling will begin without heating. Or if you want to be easy but messy, add dry ice to a bowl of water and watch how the water starts to boil.

The correct answer is C. The ΔG°, also known as the standard free-energy change, is defined as the free-energy change that occurs when the reactants and products are in their standard states at a specified temperature and pressure, usually at 25°C and 1 atm pressure. The standard state of a substance is the pure form of the substance at the specified temperature and pressure.

The concentrations of the reactants and products are not usually specified in the definition of ΔG°. Instead, it is assumed that the concentrations of the reactants and products are at their standard state concentrations, which are usually 1M or 1 mol/L for aqueous solutions. For example, the standard free-energy change of the reaction A + B → C + D at 25°C and 1 atm pressure is defined as the free-energy change that occurs when A, B, C, and D are each at a concentration of 1M.

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a) The gravitational force on the earth is 81 times that on the moon

b) The slope of the graph is the universal gravitational constant

c) The force is  5 * 10^19 N

d) The acceleration due to gravity is the same.

We know that the term gravity has to do with the force that acts on any object that we can be able to find on the surface of the earth. We know that the larger the mass of the object, the greater the magnitude of the gravitational force on the object.

We can see that in the question the distance between the earth and the moon was halved hence the force would now be one quarter of its initial value hence;

New force = 1/4 * 2 * 10^20

= 5 * 10^19 N

The acceleration  due to gravity does not change hence it is the same both at the surface and near the surface.

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Answer:

The 1 you are on. (2nd one)

Explanation:

The first one its volume=mass/density so wrong.

For the 3rd, you wouldn't be able to get volume in grams.

For the last, chemicals? Also l/w*h?

The distance between the two buses is 48km.

Let us assume that the velocity of the first bus is 36 km/h and that of the second bus is 108 km/h.

To find the distance between them, we will consider that both buses move in opposite directions.

Distance travelled by bus 1 in 20 minutes = 36 km/h × 20 min ÷ 60 min/h = 12 km

Distance travelled by bus 2 in 20 minutes = 108 km/h × 20 min ÷ 60 min/h = 36 km

Total distance between them = distance travelled by bus 1 + distance travelled by bus 2= 12 km + 36 km= 48 km

Therefore, the distance between them in 20 minutes is 48 km.

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Answer:

Explanation:'Distance' is the total length travelled by an object. The standard unit is the 'metre'.

A distance-time graph shows how far an object has travelled in a given time.

Distance is plotted on the Y-axis (left) and Time is plotted on the X-axis (bottom)

Answer:

a)  E_{z} = 0, b) E_{z} = 0, c)    z = 1.73 [1 + \(\sqrt{1 - \frac{4R^2}{3} }\)], d)   \(E_{max}\)Emax = 9.7  10¹⁰ N / C

Explanation:

For this exercise we use the expression

          E = k ∫ dq / r²

By applying this expression to our problem of a ring of radius R, with a perpendicular axis in the z direction, we can calculate the electric field for a small charge element

          dE = k dq / r²

In the attachment we can see a diagram of the electric field, it is observed that the fields perpendicular to the z axis cancel and the field remains in the direction of the axis

           d\(E_{z}\)= dE cos φ

we substitute

         E_{z} = k∫  \(\frac{dq}{r^2}\)  cos φ

let's write the expressions

          r² = R² + z²

          cos φ = z / r

we substitute in the integral, where we see that the load differential does not depend on the distance and the value of the total load is + Q

          E_{z} = k  \(\frac{1}{ (R^2 +z^2) } \ \frac{z}{ (R^2 + z^2)^{1/2} }\) ∫  dq

          E_{z} = k Q  \(\frac{z}{ (R2+z^2)^{3/2} }\)  

This is the expression for the electric field in the axis perpendicular to the ring, we analyze this expression to answer the questions

a) the magnitude of the field at z = 0

         E_{z} = 0

b) the magnitude of the field for z = inf

        when z »R the expression remains

          E_{z} = k \(\frac{z}{z^{3} }\) Q

          E_{z} = k Q \(\frac{1}{z^2}\)

therefore when the value of z = int the field goes to E_{z} = 0

c) In value of z for which the field is maximum.

    We have an extreme point when the first derivative is equal to zero

     \(\frac{dE_z}{dz } = k Q [ (R^2 +z^2)^{3/2} - z \ 3 \frac{z}{ (R^2 +z^2)^{1/2} } = 0\)

we solve

    (R² + z²)^{ 3/2} = 3 z² /(R² +z²) ^{1/2}

    (R² + z²)² = 3z²

    r² + z² = √3    z

    z² –1.732 z + R² = 0

we solve the quadratic equation

       z = [1.732 ± \(\sqrt{3 - 4R^2}\)]/ 2 = [1.73 ± 1.73 \(\sqrt{ 1 - \frac{4 R^2}{3} }\)   ] / 2

       z = 0.865 [1 ± \(\sqrt{1 - \frac{4R^2}{3} }\)]

Therefore there are two points where the field has an extreme point one, one is a maximum and the other a minimum, as we have already determined a minimum at z = 0 the maximum point must be

  z = 0.865 [1 + \(\sqrt{1 - \frac{4R^2}{3} }\)]

d) the value of Emax

         z₁ = 0.865 [1+\(\sqrt{1 - \frac{4 \ 0.04^2}{3} }\)) = 1.73 [1 + √0.99786]

          z₁ = 1.729 m

         z₂ = 0.865 [1 - √0.99786 ]

         z₂ = 0.0011 m≈ 0

for which the field has a maximum value substituting in equation 1

            \(E_{max} = 9 10^9 \ 9 \ \frac{1.729}{(0.04^2 + 1.729^{3/2})}\)

            \(E_{max}\) = 81 10⁹   \(\frac{1.729}{1.4408}\)

            \(E_{max}\)Emax = 9.7  10¹⁰ N / C

The wire gauge best suited to support roses, carnations, and chrysanthemums depends on the size and weight of the stems.

Generally, a wire gauge between 18-22 is suitable for these types of flowers. However, if the stems are thicker and heavier, a larger wire gauge may be needed. It's important to choose the right wire gauge to ensure the stems are adequately supported and don't break under their own weight.
The best wire gauge to support roses, carnations, and chrysanthemums is typically between 18 to 22 gauge. To choose the appropriate wire gauge for supporting these flowers, follow these steps:

1. Consider the weight and stem thickness of the flowers: Roses, carnations, and chrysanthemums have medium-weight stems, so a wire gauge that offers a balance of flexibility and strength is ideal.
2. Compare wire gauges: 18-gauge wire is thicker and provides more support, while 22-gauge wire is thinner and more flexible. Choose a wire gauge based on the specific needs of your flowers and their arrangement.
3. Test the wire with your flowers: Before committing to a wire gauge, test it with your flowers to ensure it provides adequate support without damaging the stems.
In conclusion, the best wire gauge for supporting roses, carnations, and chrysanthemums is typically between 18 to 22 gauge, depending on the specific needs of the flowers and their arrangement.

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Answer:

34.51

Explanation:

k=1/2mv² is the kenetic energy equation to fill is in

k=[1/2(0.235)×50]²

Two kids of different masses take part in a tug of war with no friction. The distance of their center of mass can be calculated, and if child B pulls on the rope towards child A, the distance he will move before colliding with child A can also be calculated.

A. To find the center of mass (CM) of the system, we need to take into account both the masses and their distances from each other. The formula for the position of the CM is:

CM = (m1x1 + m2x2) / (m1 + m2)

where m1 and m2 are the masses, x1 and x2 are their distances from a chosen reference point.

In this case, let's take child A as the reference point, so x1 = 0 (since child A is at the origin), and x2 = 11 m. Then we have:

CM = (m1x1 + m2x2) / (m1 + m2)

= (26 kg * 0 + 49 kg * 11 m) / (26 kg + 49 kg)

= 7.6 m

Therefore, the center of mass of the system is located 7.6 m from child A.

B. As child B pulls on the rope, he will move towards child A, and their separation distance will decrease. At the same time, the center of mass of the system will move towards child B. Since there is no external force acting on the system, the position of the center of mass will not change.

Let's assume that child B moves a distance of x towards child A before they collide. Then the distance between child A and the CM of the system will be (11 - x), and the distance between child B and the CM will be x. Using the formula for the position of the CM, we can set up an equation:

CM = (m1x1 + m2x2) / (m1 + m2)

= ((26 kg) * 0 + (49 kg) * (11 - x)) / (26 kg + 49 kg)

= (539 - 49x) / 75

Since the CM does not move, this must be equal to the initial position of the CM, which we found to be 7.6 m from child A:

(539 - 49x) / 75 = 7.6

Solving for x, we get:

x = 6.4 m

Therefore, child B will have moved a distance of 6.4 m towards child A before they collide.

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The density of sugar, which is in 1.58 g/cm³, is equivalent to 0.05708 in/in³.

Density is a measure of the mass of matter contained by a unit volume.

Density is a function of mass and density, hence, it is measured in units of grams (g) and cubic centimeters (cm³).

However, cubic centimeters can be converted to pounds per cubic inch as follows:

1 gram / cubic centimetre = 0.0361 pound / cubic inch

According to this question, the density of sugar is 1.58 g/cm³. This value is equivalent to;

= 1.58 × 0.0361 = 0.05708

Therefore, the density of sugar, which is in 1.58 g/cm³, is equivalent to 0.05708 in/in³.

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School population.

The biggest school in the world is in lucknow, india. it has more than 40,000 students and 2500 teachers! would it be easier to make new friends in a school with 40,000 kids than a school with fewer than 100 kids? School population.

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Answer:

Greater than

Explanation:

Distance is the length of the path traveled.  Displacement is the difference between the final position and initial position.

Speed = distance / time

Velocity = displacement / time

Since you return to your starting point, your displacement is 0 m, so your average velocity is 0 m/s.  Therefore, your average speed is greater than your average velocity.

Speed ls a function of distance and time, while velocity is a function of displacement and time. Since the rider returned to his starting point, then the magnitude of the average speed is greater than the magnitude of the average velocity

The total distance traveled will be sum of the 'to' and 'fro' distance.

The total displacement will be 0 (Final position - Initial position) ; since the rider returned to his starting position.

This means the average velocity will be 0 while the average speed will have a value greater than 0.

Therefore, the average speed will be greater.

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The answer for Eating food from a uranium glass plate is safer is Choice C which is food is irradiated / not contaminated.

It is safer to eat food from a uranium glass plate because the uranium added to the glass will always be in the oxidized form used to color it. The uranium added to the glass will also be not soluble thus it will not be radioactive.

Thus, the reason for eating food safely from the uranium glass plate is it will not be contaminated

The other two options(alpha cannot penetrate skin or body and contains a low percentage of uranium) will be wrong because the plate will be completely non-radioactive.

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