The probability of drawing a king and face card is \(\frac{4}{13}\)
What is probability?
Probability is the ability to happen. The subject of this area of mathematics is the occurrence of random events. From 0 to 1 is used to express the value. To forecast how likely occurrences are to occur, probability has been introduced in mathematics.
Here In total number of deck of card is 52.
In 52 cards there is 4 jacks, 4 queen , 4king. Then there is 12 face cards.
Here if we select one king card then probability,
=> P1(choosing one king)= \(\frac{4}{52}\) = \(\frac{1}{13}\)
Here if we select one face card then probability
=> P2( choosing face card)= \(\frac{12}{52}= \frac{3}{13}\)
Then probability of choosing a face card and a king ,
=> P = \(\frac{1}{13}+\frac{3}{13} = \frac{4}{13}\)
Hence the probability is \(\frac{4}{13}\) .
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3:Let f be a quadratic function such that
f(x) = ax² +bx+c = a (x-h)² + k
If k < 0, for what values of a will f(x) have no real zeros?
O a=0
O a<0
O azo
4.
O a>0
O aso
none of the answer choices
Answer:
O a=0
Step-by-step explanation:
WILL GIVE BRAINLIEST 15 POINTS
Congruent yes or no
Congruent? _______
If so, what property? ________
Congruent yes or no
Congruent? _______
If so, what property? ________
#1
No
See in first one the angle included is in between the two similar sides( corresponding to other triangle)
In second one the angle marked is not between the corresponding similar sides .
So not congruent
#2
Yes
Three angles of both are equal
AAA (angle-angle-angle)La temperatura ambiente a las 6 am era de 59 grados Farenheit. Fue aumentando de forma lineal hasta la 1 pm en que el termómetro marcó 81 grados.
a) Escriba una ecuación lineal que muestre la temperatura en función de la hora en ese intervalo.
b) Calcule con esa ecuación la temperatura a las 11:15 am. Aproxime a la décima de grado Farenheit si fuera necesario.
The linear function that represent this problem is 7y = 22x + 127, and the temperature at 11:15am is 53.19 degrees
What is the linear equationa.
We can take two points from this to find the slope and y - intercept to determine the linear function.
A(6, 59)
B(13, 81)
The slope of a linear equation has a formula of ;
m = y₂ - y₁ / x₂ - x₁
m = 81 - 59 / 13 - 6
m = 22/7
Using the slope to find the y - intercept, we need just one point;
y = mx + c
59 = 22/7(13) + c
59 = 286/7 + c
c = 59 - 286/7
c = 127/7
The equation can be written as;
y = 22/7x + 127/7
rewriting this;
7y = 22x + 127
b. The temperature at 11.15am
Substituting this into the equation;
7y = 22(11.15) + 127
7y = 372.3
y = 53.19 degrees Fahrenheit
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Translation:
The room temperature at 6 am was 59 degrees Fahrenheit. It was increasing linearly until 1 pm when the thermometer marked 81 degrees. a) Write a linear equation that shows the temperature as a function of time in that interval. b) Calculate with this equation the temperature at 11:15 am. Round to the nearest tenth of a degree Fahrenheit if necessary.
What is the reciprocal of the divisor 5 1/5 divided by 1/10
The reciprocal of the divisor 5 1/5 divided by 1/10 is 10.
The reciprocal of the divisor: Reciprocal and division of fractions are two different methods. When the numerator and denominator of a fraction are interchanged, then it is said to be its reciprocal. Suppose a fraction is a/b, then its reciprocal will be b/a. A fraction is a numerical quantity that is not a whole number.
The reciprocal of the divisor 5 1/5 divided by 1/10
To the reciprocal of the divisor.
Equation: 5 1/5 divided by 1/10
1st: Flip the 1/10 to become 10/1
2nd: Change division to multiplication
New equation: 5.1/5.10/1
⇒ 50/5
⇒ 10.
The reciprocal of the divisor 5 1/5 divided by 1/10 is 10.
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Find the interquartile range (IQR) of the data in the dot plot below VV
(PLS HELP ME PLSSS)
The interquartile range of the data that is represented on the dot plot is: 2 chocolate chips.
What is the Interquartile Range?Interquartile range (IQR) = upper quartile - lower quartile.
Upper quartile (Q3) = center of the second half of the data = 5
Lower quartile (Q1) = center of the first half of the data = 3
Interquartile range (IQR) = 5 - 3
Interquartile range (IQR) = 2 chocolate chips.
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need help asap. pls somebody help.
Answer:
D
Step-by-step explanation:
why the panic ? you only need to compare the tiles with the actual terms in the equations and add them up.
x²
-x²
-x -x
x x x x (clearly that means 4x)
-1 -1 -1
1 1
so, we see it is D.
The equation y=1/5x+3.5 can be used to find the amount of accumulated snow y in inches x hours after 5 P.M. on a certain day. Graph this equation.
The coordinates of the y-intercept are (0, 3.5) and the coordinates of the x-intercepts are (-17.5, 0). Using these coordinates, the graph of the equation is shown below.
Graphing linear equationsFrom the question, we are to graph the given linear equation.
To graph the equation,
We will determine the coordinates of the x-intercepts and y-intercepts.
When x = 0
y = 1/5x + 3.5
y = 1/5(0) + 3.5
y = 3.5
(0, 3.5)
When y = 0
y = 1/5x + 3.5
0 = 1/5x + 3.5
Multiply through by 5
0 = x + 17.5
x = -17.5
(-17.5, 0)
Using the coordinates of the x-axis and y-axis, the graph of the equation is shown below.
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73⁰
32⁰
What is the value of y?
Y
Answer:
75 Degrees
Step-by-step explanation:
A triangle is equal to 180 degrees
32+73+Y=180
subtract 32 and 73 from 180
32+73 is 105
180 - 105 is 75
we are left with Y=75
Find the equation of the line in standard form that passes through the following points. Eliminate anyfractions and simplify your answer.(4, -8) and (9, 11)
We want to find the equation of the line that passes through the points:
(4 , -8) and (9 , 11)
First, we're going to find the slope between these points using the fact that:
If we have two points that lie on a line:
\((x_1,y_1)\text{ and }(x_2,y_2)\)The slope between them can be found using the formula:
\(m=\frac{y_2-y_1}{x_2-x_1}\)If we replace our values:
\(\begin{gathered} (x_1,y_1)=(4,-8) \\ (x_2,y_2)=(9,11) \\ x_1=4 \\ x_2=9 \\ y_1=-8 \\ y_2=11 \end{gathered}\)The slope will be:
\(m=\frac{11-(-8)}{9-4}=\frac{11+8}{5}=\frac{19}{5}\)Now, we could apply the point-slope equation. This equation tells us that we can find the equation of the line if we got a point (x1,y1) on the line, and the slope m:
\(y=y_1+m(x-x_1)\)Replacing our values:
\(\begin{gathered} y=-8+\frac{19}{5}(x-4) \\ y=-8+\frac{19}{5}x-\frac{76}{5} \\ y=\frac{19}{5}x-\frac{116}{5} \end{gathered}\)This, is the general form. We want to express the last equation as a standard form like this:
\(Ax+By=C\)If we re-write:
\(\begin{gathered} y=\frac{19x-116}{5} \\ \\ 5y=19x-116 \\ 19x-5y=116 \end{gathered}\)Therefore, the standard for the equation of the line that passes through (4 , -8) and (9, 11) is:
19x-5y=116
when studying radioactive material, a nuclear engineer found that over 365 days ,1,000,000 radioactive atoms decayed to 972,924 radioactive atoms ,so 27,076 atoms decayed during 365 days , find the mean number of radioactive atoms that decayed in a day?
Answer:
The mean number of radioactive atoms that decay per day is 81.485.
Solve for x
1+2/x-9=x+3/x^2-12x+27
Answer:
x ≓ 3.242593855
Step-by-step explanation:
2/3+1/4 in simplest form
Hey there!
2/3 + 1/4
= 2 × 4/3 × 4 + 1 × 3/4 × 3
= 8/12 + 3/12
= 8 + 3 / 12 + 0
= 8 + 3 / 12
= 11/12
Therefore, your answer is: 11/12
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
You flip a fair coin until you see three tails in a row. What is the average number of headsthat you’ll see until gettingTTT?
Answer:
14
Step-by-step explanation:
From the given information:
suppose, Y is the number of times a coin is being flipped.
If the coin is flipped for the first time and we get H, then we have:
TTT = \(\dfrac{1}{2}(Y+1)\)
Afterward, if we get H, then we waste two times plus the probability of this event \(\dfrac{1}{4}\).
Therefore, we have : \(\dfrac{1}{4}(Y+2)\)
Afterward, if we get H, then we waste three times plus the probability of this event \(\dfrac{1}{8}\).
Therefore, we have : \(\dfrac{1}{8}(Y+3)\)
If we got T at the third time, then;
T = \(\dfrac{1}{8}(3)\)
Thus, average number of headsthat you’ll see until gettingTTT can be expressed as:
\(= \dfrac{1}{2}(Y+1)+ \dfrac{1}{4}(Y+2)+ \dfrac{1}{8}(Y+3)+ \dfrac{1}{8}(3)\)
= 14
Mari swims every 4 days and runs every 6 days. In how many days will she both swim and run on the same day?
Answer:
12
Step-by-step explanation:
We find the LCM which is simply 12.
Which sequence of transformations was applied to the parent tangent function to create the function m(x) = 2tan(3x+4)
The function m(x) = 2tan(3x+4) is obtained by applying a sequence of transformations to the parent tangent function.
To determine the sequence of transformations, let's break down the given function:
1. Inside the tangent function, we have the expression (3x+4). This represents a horizontal compression and translation.
2. The coefficient 3 in front of x causes the function to compress horizontally by a factor of 1/3. This means that the period of the function is shortened to one-third of the parent tangent function's period.
3. The constant term 4 inside the parentheses shifts the function horizontally to the left by 4 units. So, the graph of the function is shifted to the left by 4 units.
4. Outside the tangent function, we have the coefficient 2. This represents a vertical stretch.
5. The coefficient 2 multiplies the output of the tangent function by 2, resulting in a vertical stretch. This means that the graph of the function is stretched vertically by a factor of 2.
In summary, the sequence of transformations applied to the parent tangent function to create the function m(x) = 2tan(3x+4) is a horizontal compression by a factor of 1/3, a horizontal shift to the left by 4 units, and a vertical stretch by a factor of 2.
Example:
Let's consider a point on the parent tangent function, such as (0,0), which lies on the x-axis.
After applying the transformations, the corresponding point on the function m(x) = 2tan(3x+4) would be:
(0,0) -> (0,0) (since there is no vertical shift in this case)
This example helps illustrate the effect of the transformations on the graph of the function.
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Help Enter a recursive rule and an explicit rule for each geometric sequence.
The recursive rule is f(n) = f(n - 1) * 2; f(1) = 9 and the explicit rule is f(n) = 9(2)^n-1
How to determine the ruleThe recursive rule
From the question, we have the following parameters that can be used in our computation:
The table
The table definitions imply that we simply multiply 2 to the previous term to get the current term
This means that
f(n) = f(n - 1) * 2
Where
f(1) = 9
The explicit rule
The table definitions imply that we simply multiply 2 to the previous term to get the current term
a = 9
r = 2
So we have
f(n) = a * r^n-1
This gives
f(n) = 9(2)^n-1
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Write the sentence as an equation.
the quotient of w and 319 is equal to 342
Answer:
w÷319= 342
Step-by-step explanation:
w divided by 319 is equal to 342
An inner city revitalization zone is a rectangle that is twice as long as it is wide. The width of the region is growing at a rate of 34 m per year at a time when the region is 450 m wide. How fast is the area changing at that point in time?
Answer:
The area is changing at the point of \(\mathbf{61200 m^2/year}\)
Step-by-step explanation:
From the given information:
Let's recall from our previous knowledge that the formula for finding the area of a rectangle = L × w
where;
L = length and w = width of the rectangle
Suppose the Length L is twice the width w
Then L = 2w --- (1)
From The area of a rectangle
A = L × w
A = 2w × w
A = 2w²
Taking the above differentiating with respect to time
\(\dfrac{dA}{dt }= 4w \times \dfrac{dw}{dt} --- (2)\)
At the time t
\(\dfrac{dw}{dt}= 34 m \ per \ year ; w = 450 \ m\)
Replacing the values back into equation 2, we get:
\(\dfrac{dA}{dt }= 4 \times 450 \times 34\)
\(\mathbf{\dfrac{dA}{dt }= 61200 m^2/year}\)
Convert the decimal 0.65 to a fraction in its lowest terms.
Answer:
The correct fraction is 13/20.
Step-by-step explanation:
\(.65 = \frac{65}{100} = \frac{13}{20} \)
00:00
Brandy made 7 batches of cookies. Each batch contained 12 cookies.
She put the same number of cookies in each of 5 bags. How many cookies were NOT put in bags?
16 cookies
12 cookies
4 cookies
2 cookies
Answer:
4 cookies
Step-by-step explanation:
The remainder of (7x12)/5 is your answer.
Consider the initial value problem:
y' + 5/3y =1 - 1/5t, y(0)= yo
What equation expresses the requirement that the solution touches the t-axis?
a. y(t)= 0
b. y'(t)= 0
c. y''(t)= 0
Answer:
a. y(t) = 0
Step-by-step explanation:
There are two axis on the graph. One is x-axis which is horizontal line on the graph and the other is y-axis which is vertical side of the graph. The point where x-axis and y-axis meet is origin which has value 0. The equation to write the points of the graph is represented by y(x) = 0. In the given equation there is t variable used in the values.
Solve this correctly for brainliest !!!!!! 3(7) + 2 • |7 - 8| - 12
Answer:
3(7) + 2* |7 - 8| - 12 = 11
Step-by-step explanation:
3(7) + 2* |7 - 8| - 12
21 + 2* |-1| - 12
21 + 2* 1 - 12
21 + 2 - 12
23 - 12 = 11
Hope this helps! :)
Arrange the steps in order to simplify the expression
Answer:
Step-by-step explanation:
For step explanation:
1. write the problem
2. distinguishing the neg sign
3. distributing 3
4. moving like terms next to each other through commutative property
5. Combining like terms
6. getting rid of parentheses
-2squreroot3+sequreoot75
Answer:
3*(root3)
Step-by-step explanation:
square root of 75 = sq. root of ( 5 × 5 × 3 )= 5root3
now 5root3 - 2root3 = (5-2)root3 = 3root3
Solve for y
129 = y + 43
Answer:
86=y
Step-by-step explanation:
129=y+43
-43 -43
86=y
or
y=86
Circle A has been transformed to Circle B.
What is the scale factor of Circle A to Circle B?
Scale Factor
=
Image Radius
Pre- Image Radius
Answer: 21
Step-by-step explanation: im not guessing im a certified expert at calculus and have a masters degree in mathmatics so yeah
Answer:
21
Step-by-step explanation:
I did the test
Hope this helps :)
Triangle UVW is drawn with vertices at U(−1, 1), V(0, −4), W(−4, −1). Determine the coordinates of the vertices for the image, triangle U′V′W′, if the preimage is rotated 90° clockwise.
U′(1, −1), V′(0, 4), W′(4, 1)
U′(−1, −1), V′(−4, 0), W′(1, 4)
U′(1, 1), V′(−4, 0), W′(−1, 4)
U′(−1, 1), V′(0, −4), W′(−4, −1)
The coordinates of the vertices for the image of the triangle U′V′W′ is
U′(1, 1), V′(−4, 0), W′(−1, 4)
How to find the coordinates after transformationTo rotate a point 90 ° clockwise about the origin, we can apply the transformation (x, y) → (y, -x)
So applying this transformation to each vertex of triangle UVW we get
U(−1, 1) → U' = (1, 1)
V(0, −4) → V' = ( -4, 0)
W(−4, −1) → W' = (-1, 4)
Therefore the coordinates of the vertices for the image triangle U'V'W' are U′(1, 1), V′(−4, 0), W′(−1, 4)
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In a certain lottery, five different numbers between 1 and 35 inclusive are drawn. These are the winning numbers. To win the lottery, a person must select the correct 5 numbers in the same order in which they were drawn. What is the probability of winning
Answer:
\(Pr =\frac{1}{38955840}\)
Step-by-step explanation:
Given
\(n = 35\) ---- 1 to 35
\(r = 5\) -- selection
Required
The probability of winning
The probability of getting the first number correctly is:
\(P(1) = \frac{1}{35}\)
At this point, the remaining numbers are 34
So, the second selection has the following probability
\(P(2) = \frac{1}{34}\)
Following the above sequence, we have:
\(P(3) = \frac{1}{33}\)
\(P(4) = \frac{1}{32}\)
\(P(5) = \frac{1}{31}\)
So, the required probability is:
\(Pr =P(1) * P(2) * P(3) * P(4) * P(5)\)
\(Pr =\frac{1}{35} *\frac{1}{34}*\frac{1}{33}*\frac{1}{32}*\frac{1}{31}\)
\(Pr =\frac{1}{35*34*33*32*31}\)
\(Pr =\frac{1}{38955840}\)
Need Help!!!! A pre-image has coordinates J(3, -6) and K(-1, -2). The image has coordinates J'(6, 3) and K'(2, -1). Describe the clockwise rotational path of the line segment.
After considering the given data we conclude that the clockwise rotational path of the line segment is a rotation of -59.04 degrees about the point (-6, -1).
We have to evaluate the center and angle of rotation to explain the clockwise rotation of the line segment.
So in the first step, we can evaluate the midpoint of the line segment JK and the midpoint of the line segment J'K'. we can calculate the vector connecting the midpoint of JK to the midpoint of J'K'. This vector is (4-1, 1-(-4) = (3,5)
The center of rotation is the point that is equidistant from the midpoints of JK and J'K'. We can evaluate this point by finding the perpendicular bisector of the line segment connecting the midpoints.
The slope of this line is the negative reciprocal of the slope of the vector we just found, which is -3/5. We can apply the midpoint formula and the point-slope formula to evaluate the equation of the perpendicular bisector:
Midpoint of JK: (1, -4)
Midpoint of J'K': (4, 1)
The slope of the vector: 3/5
(x₁ + x₂)/2, (y₁ + y₂) /2
Point-slope formula: y - y₁ = m(x - x₁)
Perpendicular bisector: y - (-4) = (- 3/5)(x - 1)
Applying simplification , we get: y = (- 3/5)x - 1.2
To evaluate the center of rotation, we need to find the intersection point of the perpendicular bisector and the line passing through the midpoints of JK and J'K'. This line has slope ( 3 - (4)) /(4 - 1) = 7/3 and passes through the point (4, 1). Applying the point-slope formula, we can evaluate its equation:
y - 1 = (7/3)( x - 4)
Apply simplification , we get: y = (7/3)x - 17/3
To evaluate the intersection point, we can solve the system of equations:
y =(- 3/5)x - 1.2 = (7/3)x - 17/3
Evaluating for x and y, we get x = -6 and y = -1.
Therefore, the center of rotation is (-6, -1).
√( 4 - 1)² + ( 1 - ( - 4))²) = 5√(2)
Distance between image points and center of rotation
√( ( 6 - (-6))² + ( 3 - (-1))² = 13
The ratio of these distances gives us the scale factor of the transformation, which is 13/√2).
The angle of rotation is negative as the image moves clockwise direction. We can apply the inverse tangent function to find the angle of the vector connecting the midpoint of JK to the midpoint of J'K':
Angle of vector: arctan(5/3) = 59.04 degrees
Therefore, the clockwise rotational path of the line segment is a rotation of -59.04 degrees about the point (-6, -1).
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6. During the winter months, there is a decrease of between 10 and 30 percent in business at a certain restaurant. Which of the following could not be the percent that winter business is of the normal business?
D (94)
Hoped I help :]