a shopper pushes a cart 40.0m south down one aisle and then turns 90.0 degrees and moves 15.0m. He then makes another 90.0 degree turn and moves 20.0m. Find the shoppers total displacement. (there could be more than one correct answer)

The speed of the 5.30-kg object when it has fallen 2.50 m is 3.03 m/s.

In the scenario, the two objects (m1 = 5.30 kg and m2 = 3.50 kg) are connected by a light string passing over a light, frictionless pulley. When the 5.30-kg object is released from rest at a point

h = 4.00 m

above the table, we have to find the tension, acceleration, and speed of the 5.30-kg object. The following are the answers to parts a, b, and c of the given question.a. What is the tension in the string?The tension in the string is equal to the weight of the objects. Therefore, we can calculate the tension in the string as:

$$T = (m_1 + m_2)g$$

Substitute the values to get:Tension

T = (5.30 kg + 3.50 kg) × 9.8 m/s² = 82.6 NAns

The tension in the string is 82.6 N.b. What is the acceleration of the 5.30-kg object?We can calculate the acceleration using the formula:

$$a = \frac{m_1 - m_2}{m_1 + m_2}g$$

Substitute the values to get:Acceleration

a = (5.30 kg - 3.50 kg) / (5.30 kg + 3.50 kg) × 9.8 m/s² = 1.84 m/s²Ans:

The acceleration of the 5.30-kg object is 1.84 m/s².c.

What is the speed of the 5.30-kg object when it has fallen 2.50 m?We can use the formula to calculate the final velocity of an object with constant acceleration. The formula is

v² = u² + 2aswhere:v = final velocityu = initial velocity = 0as = acceleration × distance = 1.84 m/s² × 2.50 m = 4.6 m/s²Substitute the values to get:

v² = 0² + 2 × 1.84 m/s² × 2.50 mv² = 9.2 m²/s²v = √9.2 m²/s² = 3.03 m/sAns:

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The diagram that shows the greatest magnitude net torque with a zero net force is the diagram in second option.

option B is the correct answer.

The net torque is the sum of the individual torques. The torque itself is obtained from the product of applied force and the perpendicular distance of the force.

In rotational equilibrium, there is no net torque on the object. There may be individual torques, but they add up to zero and cancel each other out.

Mathematically, the formula for torque is given as;

τ = Fr

where;

The torque applied to an object increases with increase in the perpendicular distance.

To obtain a zero net force, sum of all the opposite forces applied to an object must be equal to zero.

The forces must be equal in magnitude but opposite in direction, and the diagram that meets this specification is the last graph.

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The two fields were physical quantities are used in motion calculations are length and mass with time.

The physical quantity in a field is referred as every point in a particular space time.

 If we consider an object, the physical property of the object is considered as physical quantity and to measure that object is known as units. The Physical quantity can be classified as elemental physical quantity and derived physical quantity. Length, mass, time, etc.. are elemental physical quantity, momentum, density, acceleration, etc... are derived physical quantity. Only for charge and temperature the physical quantity will be less than zero.

Length, mass and time  are the physical quantities used in motion calculations.

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The primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.

A primary difference between an electromagnetic wave and a mechanical wave is the medium through which they propagate.

Electromagnetic waves can propagate through a vacuum or empty space without requiring a material medium. They are generated by the oscillation and interaction of electric and magnetic fields.

Examples of electromagnetic waves include radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. These waves can travel through space, air, or other materials, as they do not rely on physical particles to transmit energy.

On the other hand, mechanical waves require a physical medium to propagate. They are disturbances that travel through a material medium, transferring energy from one location to another. Mechanical waves rely on the interaction and displacement of particles within the medium to transmit energy.

Examples of mechanical waves include sound waves, water waves, seismic waves, and waves on a string. These waves cannot travel through a vacuum as they depend on the physical presence and interaction of particles within the medium.

In summary, the primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.

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Answer:

Increase

Explanation:

As the surface area of an object increases, the pressure reduces and vice versa.

Pressure is the force applied per unit area on a body;

   Pressure = \(\frac{Force}{Surface area}\)

Pressure is inversely related to surface area.

 A small surface area will ensure pressure to be maximized.

The time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

An echo is a repetition or reflection of a sound or signal. It can be caused by sound waves bouncing off a surface, signal interference, or the repetition of a message in communication.

The speed of sound in air at room temperature is approximately 343 meters per second. When a person claps, the sound waves propagate outward in all directions and reach the school building, where they bounce off and return to the person as an echo. The time it takes for the sound to travel the distance to the building and back to the person is the time interval between the clap and the echo.

To calculate the time interval, we can use the following formula:

time = distance / speed

where distance is the total distance traveled by the sound (twice the distance from the person to the school building), and speed is the speed of sound in air.

distance = 2 x 300m = 600m

speed = 343 m/s

time = 600m / 343 m/s = 1.75 seconds (rounded to two decimal places)

Therefore, the time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

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ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:

Impulse = Change in momentum

The momentum of an object is given by the product of its mass and velocity:

Momentum = mass × velocity

In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.

Therefore, the change in momentum is given by:

Change in momentum = (mass × final velocity) - (mass × initial velocity)

Change in momentum = mass × (final velocity - initial velocity)

Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))

Change in momentum = 0.14 kg × (49 m/s + 32 m/s)

Change in momentum = 0.14 kg × 81 m/s

Change in momentum = 11.34 kg·m/s

So, the impulse imparted on the baseball is 11.34 kg·m/s.

Answer:

(a) To solve for the initial speed of the rock at launch, we can use the kinematic equation:

v = v0 + at

Where:

v = final velocity (15m/s)

v0 = initial velocity (what we're solving for)

a = acceleration due to gravity (-9.8m/s^2)

t = time (2.0s)

Plugging in the values, we get:

15m/s = v0 - 9.8m/s^2 (2.0s)

v0 = 34.6m/s

Therefore, the initial speed of the rock at launch was approximately 34.6m/s.

(b) To solve for the speed of the rock 5.0s after launch, we can use the same kinematic equation:

v = v0 + at

But this time, we need to add the additional time and distance that the rock traveled after the initial 2.0s. To do this, we'll use the equation:

d = v0t + 1/2at^2

Where:

d = distance traveled

v0 = initial velocity (34.6m/s)

a = acceleration due to gravity (-9.8m/s^2)

t = time (5.0s - 2.0s = 3.0s)

Plugging in the values, we get:

d = (34.6m/s)(3.0s) + 1/2(-9.8m/s^2)(3.0s)^2

d = 103.8m - 44.1m

d = 59.7m

So, the rock traveled 59.7m in the additional 3.0s after the initial 2.0s. Now we can find its speed using the kinematic equation:

v = v0 + at

Where:

v0 = final velocity from before (15m/s)

a = acceleration due to gravity (-9.8m/s^2)

t = time (3.0s)

Plugging in the values, we get:

v = 15m/s - 9.8m/s^2 (3.0s)

v = -12.6m/s

Note that the velocity is negative because the rock is now moving downward. Therefore, the speed of the rock 5.0s after launch is approximately 12.6m/s.

The correct answer is D. An average city

Explanation:

A neutron star differs from others due to its massive density, this means a lot of matter is compressed in a small area. Indeed, neutron stars have a mass of around 1.4 to 2.8 times the mass of the sun. But these are considerably small as they only measure around 20 kilometers, which is the size of an average city. Additionally, neutron stars are this dense because they are the result of a regular star exploding, which leads to a super-dense core, or neutron star. In this context, the mass of a neutron star is compressed to the size of an average city.

Answer: B

Explanation:

Answer:

F = 2.65 10⁻¹¹ N

Explanation:

The radiation pressure for a fully reflective surface is

          P = 2S / c

where S is the pointiing vector which is the energy per unit area,

          S = I = \(\frac{\ P_{prom} }{A}\)

the area of ​​a circle is

           A = π r² = π d²/4

           S = \(\frac{3.98 \ 10^{-3} }{ \frac{\pi \ 0.003^2 }{4} }\)

           S = 0.563 10⁻³ W / m2

let's calculate the pressure

           P = 2 0.563 10⁻³/3 108

           P = 0.3753 10⁻⁵  N / m²

this pressure exerts an upward force, the definition of pressures

           P = F / A

           F = P A

let's calculate

           F = 0.3753 10-5 π / 4 0.003²

           F = 2.65 10⁻¹¹ N

Work of art from the Amarna Period that is abstract or descriptive in nature.

That momentarily altered during the Amarna Period. The neck, arms, and hands were among the longer characteristics on the body. The traditional Egyptian painting form was briefly replaced by this strange new art form, which resulted in portraits of people that were virtually caricatures.

Religious iconoclasts are associated with the Amarna Period. Because he only worshiped the Aten, the pharaoh Amenhotep IV changed his name to Akhenaten. At Tell el-Amarna in Middle Egypt, he constructed a brand-new capital and cemetery.

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Answer:

Emotional and Social Development

During the preschool years, your little one is learning to read emotional cues and is getting better at relating to other people, according to the New York University Child Study Center 1⭐

⭐This is a verified and trusted source

New York University Child Study Center: The Preschool Years: (Ages Four and Five) Expectations and Challenges

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. He can empathize with others and make friends with other children his own age. By his fifth birthday, your preschooler often seeks friends of the same gender and shows a preference for playing with other children, rather than adults. Your preschooler also engages in pretend play and can probably tell the difference between reality and fantasy, according to the American Academy of Pediatrics.

Physical Development

There's a big difference between a 2-year-old and a 5-year-old. During the preschool years, your child develops in many physical ways. She goes from toddling around unsteadily to being able to jump, stand on one foot, walk up and down stairs and walk backward, according to the New York University Child Study Center 1⭐

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New York University Child Study Center: The Preschool Years: (Ages Four and Five) Expectations and Challenges

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. By the time she's 5, your little one should also be able to ride a tricycle, build a block tower, paint on paper, skip, throw a ball, dress and undress and begin drawing recognizable objects, adds the University of Illinois Extension.

''The ability to use an applied force in order to make an object move'' is the  scientific definition of energy that relates it to work.

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The earth conducts seismic waves-- when an earthquake occurs, stations farther and farther away from the quake see the S and P waves propagated through deeper and deeper layers. By measuring the arrival time of the waves, the velocity of the waves can be found as a function of depth. There is clear evidence for several layers in the earth which both refract the waves and below which the velocities are different. This is a bit like holding a book under your desk while a friend (gently) taps the other end of the desk. If you listen closely to the sound (i.e. with your ear on the top of the desk) the sound changes noticeably if a large book is pressed up against the bottom of the desktop. You might also try to figure out how to tell if a golf ball is wound, liquid filled, or solid-- without looking at it. (You can tell if you hit one!)

Scientists can tell by observing the seismic waves that are recorded all over the surface of the earth from distant earthquakes. The seismic waves are reflected (bounced off) layers of different densities, and they are refracted (bent) when they enter layers of different densities. Some of them don't go through liquid at all (the S waves). Scientists have been monitoring earthquakes and studying the phases of seismic waves that arrive at different stations for - hmm, well I don't exactly know - but certainly at least the last 75 years, with more and more sophisticated equipment. Seismologists look at the little wiggles that are made by pens on paper, connected to seismometers, every time a wave from an earthquake anywhere in the world passes under their station. It is by studying many of these seismic records, for many years, and pooling all our knowledge, that we have been able to come up with a working model of what the inside of the earth is made of, where the boundaries between layers of different density and composition lie, and why we have earthquakes where we do.

to Something you can do to model how seismologists "listen" to earthquakes is densitieshave a friend tap on a big table while you put your ear on the table at the other end. We put sensitive instruments in the ground that act like ears so we can detect seismic waves from distant earthquakes.

The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.

It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.

Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.

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In the case, Mel stretches a spring exercise device by 0.73 meters with a force of 177 N. We can use Hooke's law, which states that the force applied to a spring is directly proportional to the displacement of the spring from its equilibrium position, to calculate the stiffness constant.

Hooke's law is given by the equation:

F = kx, where F is the force applied to the spring, k is the stiffness constant, and x is the displacement of the spring from its equilibrium position.

Plugging in the given values:

Force (F) = 177 N Displacement (x) = 0.73 m

We can rearrange the equation to solve for the stiffness constant (k):

k = F / x

Plugging in the values:

k = 177 N / 0.73 m

k ≈ 242.47 N/m (rounded to two decimal places)

Therefore, the stiffness constant of the spring exercise device is approximately 242.47 N/m.

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Answer:

D

Explanation:

(a) The work done by the donkey on the cart is 59,721.9 J.

(b) The work done by the force of gravity on the cart is -48,434.87 J.

(c) The work done on the cart by friction during this time is 11,315.12 J.

(a) The work done by the donkey on the cart is calculated as follows;

Wd = Fd cosθ

where;

Wd = 375 N x 163 m x cos(12.3)

Wd = 59,721.9 J

(b) The work done by the force of gravity on the cart is calculated as;

Wg =  Fg x d x cosθ

Where;

θ = 90⁰ + 4.03⁰ = 94.03⁰

Wg = (431 kg x 9.81 m/s²) x 163 m x cos (94.03)

Wg = -48,434.87 J

(c) The work done on the cart by friction during this time is calculated as;

Wf = Ff x d x cosθ

where;

Ff = μmg cosθ

Ff = 0.0165 x 431 kg x 9.81 x cos (4.03)

Ff = 69.59 N

Wf = 69.59 x 163 x cos (4.03)

Wf = 11,315.12 J

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Answer:

A. the motion of an object along a curved path

Answer:

Explanation:

angular acceleration ω = 8 rad /s²

tangential acceleration a = angular acceleration x radius of circle of rotation

For a point on the end of the rod , radius of circle = L .

tangential acceleration = 8 L .

For  a point a distance L/2 from the end of the rod, radius of circle = L /2 .

tangential acceleration = 8 L/2 = 4 L  .

It is so because angular acceleration will be same for this point , only radius changes .

required ratio = 8L / 4L

= 2.

Answer:

Birds and fish both have a backbone structure, which makes them structurally and functionally similar.

Explanation:

We will have the following:

First, we find the distance it traveled upward:

Now, we find the distance it traveled to the ground:

Now, the total distance is:

So, the ball traveled a total of 12 meters.

Answer:

a charge Q is transferred from an initially uncharged

Explanation:

Hope this helps!

a) It is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge.

a) Zero error refers to the deviation or discrepancy in the measurement instrument, where the indication or reading on the instrument is not zero when the quantity being measured is zero. In other words, it is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

Zero error can occur due to various reasons such as manufacturing defects, wear and tear, misalignment, or improper calibration of the instrument. It can be positive or negative, depending on whether the instrument reads higher or lower than the actual value.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge. These instruments are commonly used to measure the dimensions of objects with high precision.

In a vernier caliper, for instance, zero error can occur when the jaws do not close perfectly when there is no object being measured. If the caliper shows a reading other than zero when the jaws are closed, it indicates the presence of zero error.

To obtain accurate measurements, the zero error needs to be accounted for and compensated. This can be done by adjusting the position of the zero on the scale or by subtracting the zero error value from the measured readings.

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Answer:Correct option is B)

In horizontal direction, two forces are acting on the block : 100 N force and friction force (f)

f=μN=μmg=0.5×10×10=50N

So, net force acting on the block in horizontal direction = 100 N-50 N = 50 N

acceleration of the block = Net force / mass of block = 50 N/10 kg = 5 ms

−2

Solve any question of Laws of Motion with:-

Explanation:

Answer:

i believe it would be C

Explanation:

Answer:

The graph of the velocity of an object in free fall would look like a straight line sloping downward. As the object falls, its velocity increases at a constant rate, so the graph of its velocity versus time will be a straight line with a negative slope. This is because acceleration due to gravity is a constant -9.8 meters per second squared, so the velocity of a free-falling object will increase by 9.8 meters per second every second.

Therefore, the graph that shows the change in velocity of an object in free fall is a straight line with a negative slope. Here is an example of such a graph:

Free Fall Velocity Graph

Answer:

\(1.694*10^3KW/hr\)

Explanation:

Formula:

\(KW/hr=E_{(change)}\)

\(P=\frac{E}{t}\)

\((KW)(s)=1000J\)

\((3600)(KW)(s)=3600*1000J\)

\(KW=3.6*10^6\)

\(\frac{6.1*10^9}{3.6*10^6}=\frac{x}{1KW}\)

\(1.694*10^3KW/hr\)

Hope it helps

Answer:

290 N of horizontal force

Explanation:

To calculate the Net force of an object you find the sum of each force.

225 N + 165 N = 290 N

Since the reference direction is horizontal, that's how i got 290 N of horizontal force.

I hope you found this helpful...

The net force on the canoe is equal to 390N when both forces act in the same direction.

The net force can be defined as the vector sum of all the forces acting on a particle. The net force is a single force indicating same the effect of the original forces on the motion of the particle. The net force is equal to the same acceleration as all actual forces together.

The net force will become the resultant force. The net force has the same effect on the rotational motion as all actual forces together.

If the two acting forces on the canoe are acting in the same direction then the net force il be equal to the sum of these two forces.

Given, the one horizontal force on the canoe, F₁ = 225N

The other horizontal force on the canoe, F₂ = 165 N

The net force on the canoe, F = F₁ + F₂ = 225 + 165 = 390 N

Therefore,  the net horizontal force on the canoe is equal to 390 N.

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