A shoe store orders shoes from the manufacturer and sells them at a mall. Storing shoes at the store costs $6 per shoe pair for a year. When reordering shoes from the manufacturer, there is a fixed cost of $14 per order as well as $7 per shoe pair. The retail store sells 1750 shoe pairs each year. Find a function that models the total inventory costs as a function of x x the number of shoe pairs in each order from the manufacturer

Answer:

674

Step-by-step explanation:

Answer:

woah woah woah woah calm down there buddy its 674 :)

Answer:

6.5 years

Step-by-step explanation:

Simple interest formula:  \(A=P(1+rt)\)

where:

Given:

\(\implies 8962.5=7500(1+0.03t)\)

\(\implies t=\dfrac{100}{3}\left(\dfrac{8962.5}{7500}-1\right)\)

\(\implies t=6.5\)

Therefore, she borrowed the money for 6.5 years

The effective annual rate for a 8.65% interest compounded monthly is 9.14%.

To calculate the effective annual rate, we need to take into account the compounding frequency. In this case, the interest is compounded monthly.

We can use the formula for compound interest to calculate the effective annual rate:

Effective Annual Rate = (1 + (interest rate / compounding frequency))^compounding frequency - 1

Plugging in the given values:

Effective Annual Rate = (1 + (8.65% / 12))^12 - 1

                     = (1 + 0.0072083)^12 - 1

                     = 1.0072083^12 - 1

                     ≈ 0.0914 or 9.14%

Therefore, the effective annual rate for a 8.65% interest compounded monthly is approximately 9.14%.

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Answer:

0.6

Step-by-step explanation:To find this answer, you must thinkk of the slash inbetween the numerator and the denominator. So divide the 3 bye the 5. Use a calculator if needed. 3/5=0.6 Hope this helped plz mark brainliest.

The radius of the circle is 1.3636...ft (approx).

Given, the central angle a = 120° and the arc length s = 9 ft.

The formula to find the radius of a circle is given as:  R = (180 × s)/(π × a)

Where, R = radius of the circle

a = central angle in degrees

s = arc length

π = 3.14

Substitute the given values in the formula, R = (180 × 9)/(3.14 × 120)R = 1.3636...ft (approx)

Therefore, the radius of the circle is 1.3636...ft (approx).

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Answer:

x = 3

Step-by-step explanation:

3(2 - 4x) = -30

=>6 - 12x = -30

=> 12x = 36

=> x = 3

Answer:c

Step-by-step explanation:

i did the test

Answer:

$10.83

Step-by-step explanation:

d. Expected life in years of the depreciable asset. The acceptable way to express the useful life of a depreciable asset is in terms of the expected life in years.

The useful life refers to the period of time over which the asset is expected to contribute to the revenue-generating activities of a business.

While options a, b, and c may be relevant factors for certain specific assets (such as units produced, hours of productivity, or miles driven), they do not encompass the overall concept of useful life. Useful life is a broader measure that takes into account the anticipated duration of productive use, regardless of specific output or activity metrics.

Expressing the useful life in years provides a common standard for comparison and allows for consistency in depreciation calculations and financial reporting. It is a practical and widely accepted approach to estimating the lifespan of a depreciable asset.

It is worth noting that the estimated useful life in years may vary depending on the nature of the asset and industry practices. It is typically determined based on factors such as technological advancements, physical wear and tear, economic obsolescence, and the intended purpose of the asset.

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To find an equation in standard form with solutions x = -3 and x = 8, we can use the fact that the solutions of a quadratic equation are the values where the equation equals zero.

If x = -3 is a solution, then (x + 3) = 0 is a factor of the quadratic equation.
If x = 8 is a solution, then (x - 8) = 0 is a factor of the quadratic equation.

To find the equation, we can multiply these factors together:

(x + 3)(x - 8) = 0

Expanding this product, we get:

x^2 - 8x + 3x - 24 = 0

Combining like terms:

x^2 - 5x - 24 = 0

Therefore, the equation of the form x^2 + bx + c = 0 with solutions x = -3 and x = 8 is:

x^2 - 5x - 24 = 0

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Let n be any odd integer. Then n = 2k + 1 for some integer k.

So

n ³ = (2k + 1)³

… = (2k)³ + 3 (2k)² + 3 (2k) + 1

… = 8k ³ + 12k ² + 6k + 1

… = 2 (4k ³ + 6k ² + 3k) + 1

is also odd, since 4k ³ + 6k ² + 3k is just another integer.

\(\text{Slope,~} \tan \theta  =\dfrac{15}{18}=\dfrac 56\)

The complete table is

Sulfur atoms         6     9     12   27

Oxygen atoms     12    18    24   54    

A ratio in mathematics is a comparison of two or more numbers that shows how big one is in comparison to the other.

A ratio can be compared by the division of two numbers. For example, the ratio of a and b can be represented as a: b and read as a is to b. Here a: b can be written as a/b

Here we have  

The ratio of oxygen atoms to sulfur atoms in sulfur dioxide is always the same. The table shows the number of atoms in different quantities of sulfur dioxide.  

The given table is

Sulfur atoms         6     9     12   ___

Oxygen atoms     12    __   ___   54      

Let x, y, and z be the missing values in the table

Given that ratio of oxygen atoms to sulfur atoms in sulfur dioxide is always the same.  

=> 12/6 = x/9 = y/12 = 54/z    

Now the x, y, and z values can be calculated as follows

Take 12/6 = x/9  

=> 2 = x/9    

=> x = 18  

Take 12/6 = y/12  

=> 2 = y/12

=> y = 24

Take 12/6 = 54/z  

=> 2 = 54/z

=> z = 54/2

=> z = 27    

Therefore,

The complete table is

Sulfur atoms         6     9     12   27

Oxygen atoms     12    18    24   54      

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The complete Question is given in the picture

There are 40 such bit strings.

To count the number of bit strings of length seven that either begin with two 0s or end with three 1s, we need to use the principle of inclusion-exclusion.

Let A be the set of bit strings that begin with two 0s, and let B be the set of bit strings that end with three 1s.

Then, we want to find the size of the set A ∪ B, which consists of bit strings that satisfy either condition.

The size of A can be calculated as follows:

since the first two digits must be 0, the remaining five digits can be any combination of 0s and 1s,

so there are \(2^5 = 32\) possible strings that begin with two 0s.

Similarly, the size of B can be calculated as follows:

since the last three digits must be 1, the first four digits can be any combination of 0s and 1s,

so there are\(2^4 = 16\) possible strings that end with three 1s.

However, we have counted the strings that both begin with two 0s and end with three 1s twice.

To correct for this, we need to subtract the number of strings that belong to both A and B from the total count.

The strings that belong to both A and B must begin with two 0s and end with three 1s, so they have the form 00111xxx,

where the x's can be any combination of 0s and 1s.

There are \(2^3 = 8\) such strings.

Therefore, the total number of bit strings of length seven that either begin with two 0s or end with three 1s is:

|A ∪ B| = |A| + |B| - |A ∩ B| = 32 + 16 - 8 = 40.

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To evaluate the expression, we need to use the binomial distribution formula: P(X = k) = (n choose k) * p^k * (1-p)^(n-k) where:

- n is the sample size (10 individuals in this case)
- k is the number of individuals who have consumed alcohol (5 in this case)
- p is the probability of an individual consuming alcohol, which is 0.6 according to the problem

If you provide the value of p, I can help you calculate the probability.

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Answer:

2 ( Option A )

Step-by-step explanation:

The given integral to us is ,

\(\longrightarrow \displaystyle \int_0^1 5x \sqrt{x}\ dx \)

Here 5 is a constant so it can come out . So that,

\(\longrightarrow \displaystyle I = 5 \int_0^1 x \sqrt{x}\ dx \)

Now we can write √x as ,

\(\longrightarrow I = \displaystyle 5 \int_0^1 x . x^{\frac{1}{2}} \ dx \)

Simplify ,

\(\longrightarrow I = 5 \displaystyle \int_0^1 x^{\frac{3}{2}}\ dx \)

By Power rule , the integral of x^3/2 wrt x is , 2/5x^5/2 . Therefore ,

\(\longrightarrow I = 5 \bigg( \dfrac{2}{5} x^{\frac{5}{2}} \bigg] ^1_0 \bigg) \)

On simplifying we will get ,

\(\longrightarrow \underline{\underline{ I = 2 }}\)

Answer:

A)2

Step-by-step explanation:

we would like to integrate the following definite Integral:

\( \displaystyle \int_{0} ^{1} 5x \sqrt{x} dx\)

use constant integration rule which yields:

\( \displaystyle 5\int_{0} ^{1} x \sqrt{x} dx\)

notice that we can rewrite √x using Law of exponent therefore we obtain:

\( \displaystyle 5\int_{0} ^{1} x \cdot {x}^{1/2} dx\)

once again use law of exponent which yields:

\( \displaystyle 5\int_{0} ^{1} {x}^{ \frac{3}{2} } dx\)

use exponent integration rule which yields;

\( \displaystyle 5 \left( \frac{{x}^{ \frac{3}{2} + 1 } }{ \frac{3}{2} + 1} \right) \bigg| _{0} ^{1} \)

simplify which yields:

\( \displaystyle 2 {x}^{2} \sqrt{x} \bigg| _{0} ^{1} \)

recall fundamental theorem:

\( \displaystyle 2 ( {1}^{2}) (\sqrt{1} ) - 2( {0}^{2} )( \sqrt{0)} \)

simplify:

\( \displaystyle 2 \)

hence

our answer is A

Answer:

Mixed Number Form: x = 1 45/299

Decimal Form: x = 1.15050167…

Step-by-step explanation:

Answer:

  b)  -3

Step-by-step explanation:

You want the value of 'a' when the quadratic y = –3x² – 15x – 11 is written in the form y = a(x – h)² + k.

The leading coefficient in either form is the coefficient of x². It is the same in both forms: -3.

Answer:

3.1% of Ramon's earning are spent on electricity.

Step-by-step explanation:

Ramon's monthly salary

= $1,710

Electricity rent

=$53.60

*work show below*

\(\frac{53.60}{1,710} *100\)

0.0313450292397661*100=3.134502923976608

3.134502923976608 rounded to the nearest tenth is 3.1%...

Thus my-our answer checks out! have a great day bestie!

The possible 3rd degree binomial with a constant term of 888 is x^3 + 2x^2 + 3x + 888, for the given one degree of freedom.

To find a 3rd degree binomial with a constant term of 888, we can start by writing the general form of a 3rd degree binomial: ax^3 + bx^2 + cx + d.

Since we want the constant term to be 888, we can set d = 888.

Now, we need to choose values for a, b, and c. We have one degree of freedom, so we can choose any values for a, b, and c as long as they satisfy the condition of being a 3rd degree binomial.

For example, let's choose a = 1, b = 2, and c = 3.

Therefore, a possible 3rd degree binomial with a constant term of 888 is x^3 + 2x^2 + 3x + 888.

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12

Step-by-step explanation:

n + (2/3)n = 2n - 4

(5/3)n = 2n - 4

(5/3)n - 2n = -4

(-1/3)n = -4

n = 12

Answer: Im going to guess 25

Step-by-step explanation: bryan is 36 half of 36 is 18 and becky is 7 years older than 18 which half so you would do 18+7=25 there is your answer.

I THINK DONT QUOTE ME ON THAT ANSWER

Answer:

As the sucrose concentration is higher in the solution, the water in the balloon, where the sucrose is less concentrated, will tend to leave and try to dilute the outer solution until both sucrose concentrations are equal. But as the water leaves the balloon, the concentration inside will increase, so it will flow outside until both concentrations are equal and not until the outer concentration is similar to the initial concentration in the balloon.

Step-by-step explanation:

Hope this helps:)

Answer:

12 m

Step-by-step explanation:

Here's a picture to show the problem.

                                        boat

                    --------------------------------------------

~~~~~~~~~~~\                                              /~~~~~~~~~~~~~~~~~~~~~~~~

                       \-----------Alexandra ---------/          surface of the water

                                          |\                              

                                          |     \

                                          |          \

                                          |               \

                                  d      |                   \      13 m

                                          |                        \

                                          |                            \

                                          |                                \

                                          | ---  rt <                         \

                          hook      -----|------------------------------    fish

                                                           5 m

There is a right angle at the hook. We have a right triangle with leg d, the distance we need to find, leg 5 m, and hypotenuse 13 m.

a² + b² = c²

5² + b² = 13²

25 + b² = 169

b² = 144

b = √144

b = 12

Answer: 12 m

Answer:

$28.50

Step-by-step explanation:

21 chicken wings= $39.90

1 chicken wing= 39.90÷21= $1.90

15 chicken wings= 15×1.90= $28.50

The area of the given figure is 20cm².

What is a kite?

A quadrilateral called a kite has two pairs of sides that are each the same length and are next to one another.

What is area of a kite?

A kite's diagonals are perpendicular. The area of a kite is calculated as half of the diagonal product, which is the same as the area of a rhombus. The formula: can be used to express the area of a kite.

Area of Kite =1/2×D1×D2

D1 is the kite's long diagonal.

D2 is the kite's short diagonal.

when we draw the figure in coordinate system we find that it is shape of a kite,

so area of kite = 1/2*4*4+1/2*4*6

                         = 20 cm²

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Answer:

1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289

Step-by-step explanation:

The pattern will lead to the answer being all the perfect squares from 1 to 300.