Wavelength of the waves in meters is 4m.
What is wavelentgh?Wavelength is the distances between identically any points (adjacent cresta) in the adjacent cycles of a wave form signals propagates in spaces or along side a wire. In wireless system's, this lengths is usually specifies in meters (m), centimetres (cm) or millimetres (mm).
To solve this equation first we have to use the wave formulation -
V= fλ
As we know
v= velocity
f= frequency
λ=wavelength
We know the frequency and the velocity of the both elements which have good unit's. All we have to do is rearranged the equations and solve for λ.
λ= v/f
Let's calculate both the value to get our main answer-
λ= 7m/s / 28s^-1
λ= 4m
Thus, the wavelength is 4m.
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i need help on this 8th grade knowledge please
a 7.0-g bullet is fired into a 1.5-kg ballistic pendulum. the bullet emerges from the block with a speed of 200 m/s, and the block rises to a maximum height of 12 cm. find the initial speed of the bullet. (please do not include units in your answer)
The initial speed of the bullet is 200 m/s.
What is Conservation of momentum?Conservation of momentum is a law of physics which states that the total momentum of a system remains constant over time. This means that when two or more objects interact, the total momentum of the system remains the same before and after the interaction. The law of conservation of momentum is applicable to both isolated systems and systems that interact with external forces. It is an important concept in a variety of applications ranging from collisions of particles to the motion of galaxies. Conservation of momentum also plays an important role in the field of quantum mechanics.
The initial speed of the bullet can be calculated using the conservation of momentum equation:
m₁v₁ + m₂v₂ = m₁v′₁ + m₂v′₂
where m₁ is the mass of the bullet, v₁ is the initial speed of the bullet, m₂ is the mass of the pendulum, v₂ is the initial speed of the pendulum, v′₁ is the final speed of the bullet, and v′₂ is the final speed of the pendulum.
In this problem, m₁ = 7.0 g, v₁ = ?, m₂ = 1.5 kg, v₂ = 0 m/s, v′₁ = 200 m/s, and v′₁ = 0 m/s.
Substituting this into the equation, we get:
7.0 g x v₁ + (1.5 kg)(0 m/s) = 7.0 g(200 m/s) + (1.5 kg)(0 m/s)
Solving for v₁, we get:
v₁ = 200 m/s
Therefore, the initial speed of the bullet is 200 m/s.
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Convert 0.592 hm to cm. *
Answer:
5920 cm
Explanation:
1 hm = 100m
1 m = 100cm
1 hm = 100×100cm = 10000 cm
0.592 hm = 0.592×10000cm = 5920 cm
Good luck !
light of wavelength 460 nm falls on two slits spaced 0.3 mm apart if the spacing between the first and third dark fringes is to be 4,0 mm what is the distance from the slits to the screen
The distance is 0.0013.4 mm
For dark fringe is 4,0
light of wavelength 460 nm
slits spaced 0.3 mm.
\($y=\frac{D}{d}(2 n-1) \frac{\lambda}{2}$$\)
For First dark fringe put n=1
For third dark fringe put n=3
\($\begin{aligned}& y_1=\frac{D \lambda}{d 2} \\& y_3-y_1=\frac{5 D \lambda}{2 d}-\frac{D \lambda}{2 d}=\frac{5 D \lambda}{2 d} \\& \Delta y=\frac{2 D D \lambda}{2 d} \\& L_1 \mathrm{~mm}=\frac{2 \times D \times 460 \mathrm{~nm}}{0.3 \mathrm{~mm}} \\& D=\frac{4 \times 0.3}{2 \times 460} \mathrm{~mm}=0.001304 \mathrm{~mm}\end{aligned}$$\)
Therefore, the distance from the slits to the screen is 0.001304 mm.
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Int this setup of YDSE distance from the slits to the screen is 1.739 m
As we all know from the young's double slit experiment the position of n(th) dark fringe width is given by
\(y=(n+\frac{1}{2} )\)λ\(\frac{D}{d}\)
here, y= position of minima on the screen
n= no. of minima
D= slit- screen separation
d= slit width
λ= wavelength of light used
Given,
λ= 460nm= 460×10⁻⁹ m
Δy= 4×10⁻³ m
d= 0.3mm= 0.3×10⁻³ m
According to question, y₃-y₁= Δy= 4×10⁻³ m
For first dark fringe n=0
For third dark fringe n=2
On putting all the values and solving we get
D= 1.739m
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in a radio telescope, the role that the mirror plays in visible-light telescopes is played by: a special kind of lens
Answer:
✔ ∅ e. a large metal dish (antenna)Explanation:
in a radio telescope, the role that the mirror plays in visible-light telescopes is played by:
✘ O a. a spectrometer
✘ O b. an interferometer
✘ O c. a special kind of lens
✘ O d. computer software
✔ ∅ e. a large metal dish (antenna)Have a Nice Best Day : )
What is the frequency of a raido wave with a wavelength of 1.0 mm?
Answer:
3×10^6
Explanation:
frequency is the speed of light ( c) which is a constant number divided the wavelength
f = 3×10^6 / 1.0
6. A wave has a frequency of 600 Hz and is traveling at 300 m/s. What is its
wavelength?
Answer:
0.5m
Explanation:
v=f×lamda
v is 300m/s, f is 600Hz, lamda is ?
lamda=v/f
lamda=300/600
lamda =3/6=1/2m
What does properties mean
Answer:
a thing or things belonging to someone; possessions collectively.
Explanation:
PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP
I NEED TO GIVE THIS IN TODAY!!!
Answer:
a) greater
smaller
Explanation:
An astronaut 100m from the spaceship observes a 200kg meteoroid that drifts toward the shop at 10m/sec. If the astronaut can gain a hold on the meteoroid and the astronaut’s rocket gun is capable of delivering a force of 100N, can the meteoroid be stopped before it hits the spaceships?
No
Refer to the attachment for calculations
Atomic Hydrogen emits a spectral line with a wavelength of ______ in the radio portion of the electromagnetic spectrum, which allows radio astronomers to detect and map regions of H atoms
Atomic Hydrogen emits a spectral line with a wavelength of 21 centimeters (or 21 cm) in the radio portion of the electromagnetic spectrum. This particular spectral line is known as the "Hydrogen Line" or the "21-cm Line." Radio astronomers utilize this wavelength to detect and map regions of H atoms in space. By observing the 21-cm line emissions, astronomers can study the distribution, velocity, and dynamics of atomic hydrogen in galaxies, interstellar mediums, and other astronomical objects. The 21-cm line has been instrumental in advancing our understanding of the structure and evolution of the universe.
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A wave has a speed of 20 m/s and a wavelength of 5 meters. if the same wave was created in the same medium, with half the original frequency, how would the wavelength change?
Answer:
The wavelength of the wave would increase to 10 meters.
Explanation:
We can use the formula:
velocity = frequency × wavelength
to relate the velocity, frequency, and wavelength of a wave.
Given that the wave has a speed of 20 m/s and a wavelength of 5 meters, we can solve for its frequency as follows:
frequency = velocity ÷ wavelength = 20 m/s ÷ 5 meters = 4 Hz
Now, if the same wave is created in the same medium, but with half the original frequency, its new frequency will be:
new frequency = 4 Hz ÷ 2 = 2 Hz
To find the new wavelength of the wave, we can rearrange the formula above to solve for wavelength:
wavelength = velocity ÷ frequency
Using the new frequency of 2 Hz, we get:
new wavelength = 20 m/s ÷ 2 Hz = 10 meters
Therefore, if the same wave was created in the same medium, with half the original frequency, the wavelength of the wave would increase to 10 meters.
When you stand on the merry-go-round in question 12, you hold a string from which
is suspended a rubber stopper of mass 45 g. You are 2.9 m from the centre of the
merry-go-round. You take 4.1 s to complete one revolution. What angle does the string make with the vertical?
The angle the string makes with the vertical is : 34.6°
Given data :
mass of rubber stopper ( m ) = 45 g
Radius ( r ) = 2.9 m
Time to complete one revolution ( T ) = 4.1 secs
Calculate the angle the string makes with the verticalapplying the formula below
Tan ∅ = \(\frac{mw^2r}{mg}\) --- ( 1 )
cancel out m from equation ( 1 )
Tan ∅ = \(\frac{w^2r}{g}\) ----- ( 2 )
where ; w = \(\frac{2\pi }{T}\)
Therefore equation ( 2 ) becomes
Tan ∅ = \(\frac{4\pi ^2r}{T^2g}\) --- ( 3 )
where ; r = 2.9 m, T = 4.1 secs , g = 9.8
Insert values into equation ( 3 )
Tan ∅ = 0.69
∅ = Tan ( 0.69 )
= 34.6°
Hence we can conclude that The angle the string makes with the vertical is : 34.6°.
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A cell phone battery uses chemistry to create a charge separation between the terminals (anode and cathode). Such a battery is listed as having a capacity of Q = 5.5E-08 C. If there are 1.0 million electrons moving through the phone every second how long will the battery last in seconds?
8.8E16 seconds will pass on the battery.
The maximum charge that a cell phone battery can hold is indicated by its capacity.The question specifies the battery's capacity as Q = 5.5E-08 C.
The current times the time equals the amount of charge that is transferred per second. As a result, the current I is determined by dividing the charge Q by the time t.
\(I = \frac{Q}{t}\)
Rearranging the equation yields:
\(t = \frac{Q}{I}\)
The current I is equal to the number of electrons moving through the phone per second, which is 1.0 million, divided by the charge of an electron (1.6E-19 C)
\(I =\frac{ (1.0E6 electrons/sec)}{(1.6E-19 C/electron) }I = 6.25E24 electrons/sec\)
Therefore, the time t is equal to the capacity of the battery Q divided by the current I:
\(t =\frac{ Q}{I} t =\frac{(5.5E-08 C)}{(6.25E24 electrons/sec) }t = 8.8E16 seconds\)
Therefore,The battery will last 8.8E16 seconds.
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what is ultraviolet light from the sun is absorbed primarily in eath's?
Ultraviolet light from the sun is absorbed primarily in Earth's ozone layer.
Ultraviolet (UV) light from the sun is absorbed primarily in Earth's atmosphere by a gas called ozone (O3). Ozone is present in the Earth's stratosphere, which is located about 10-50 kilometers above the surface. UV light with wavelengths between 200 and 290 nanometers (nm) is absorbed by ozone, which breaks it down into oxygen (O2) molecules and atomic oxygen (O). This process converts UV energy into heat, which warms the stratosphere. This absorption of UV radiation by ozone is important because it helps to protect life on Earth from the harmful effects of UV radiation, which can cause skin cancer, cataracts, and other health problems. The thickness of the ozone layer varies with location and time of year and can be affected by human-made chemicals, such as chlorofluorocarbons (CFCs), which have been phased out of use due to their destructive effect on ozone.
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Your total calorie _____ is an estimation of how many calories you burn when you exert yourself. A.Moderate B.Conditions C.Expenditure D.Anaerobic ( Subject P.E )
Answer:
C. Expenditure
Explanation:
I took the quiz
Item 20 which isotope, when bombarded with bismuth-209, would yield two neutrons and an isotope with atomic number 121 and mass number 299? multiple choice pb-211 po-209 sr-92 rn-38
The isotope that, when bombarded with bismuth-209, would yield two neutrons and an isotope with atomic number 121 and mass number 299 is Pb-211.
When a nucleus absorbs a neutron, it can undergo a nuclear reaction and transform into a different isotope. In this case, bismuth-209 (Bi-209) is bombarded, and it absorbs a neutron, becoming Bi-210. Bi-210 then undergoes beta decay, resulting in the formation of lead-210 (Pb-210). Pb-210 further undergoes beta decay, resulting in the formation of Pb-211, which has an atomic number of 121 and a mass number of 299. During this process, two neutrons are released.
Therefore, Pb-211 is the isotope that satisfies the given conditions of yielding two neutrons and an isotope with atomic number 121 and mass number 299 when bombarded with Bi-209.
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Which two phrases describe a situation that will cause a stationary object to
start moving?
A. A net force equal to 0
B. A net force greater than 0
C. Unbalanced forces
D. Balanced forces
(two phrases)
Answer:
A net force greater than 0 is the answer
Explanation:
trust
Answer:
b c
Explanation:
How to Calculate weight
Answer:
Weight is a measure of the force of gravity pulling down on an object. It depends on the object's mass and the acceleration due to gravity, which is 9.8 m/s2 on Earth. The formula for calculating weight is F = m × 9.8 m/s2, where F is the object's weight in Newtons (N) and m is the object's mass in kilograms.
Explanation:
Ultrasound is used in medicine both for diagnostic imaging (Fig. P17.9) and for therapy. For diagnosis, short pulses of ultrasound are passed through the patient's body. An echo reflected from a structure of interest is recorded, and the distance to the structure can be determined from the time delay for the echo's return. To reveal detail, the wavelength of the reflected ultrasound must be small compared to the size of the object reflecting the wave. The speed of ultrasound in human tissue is about 1500 m/s (nearly the same as the speed of sound in water). (a) What is the wavelength of ultrasound with a frequency of 2.40 MHz?
The wavelength of ultrasound with a frequency of 2.40 MHz is approximately 0.625 mm.
Ultrasound is widely used in medicine for both diagnostic imaging and therapeutic purposes. In diagnostic imaging, short pulses of ultrasound are directed into the patient's body. When these pulses encounter a structure of interest, they bounce back as echoes. By recording and analyzing these echoes, medical professionals can determine the distance to the reflecting structure.
However, to reveal fine detail, it is crucial for the wavelength of the ultrasound wave to be small compared to the size of the object reflecting the wave.
The speed of ultrasound in human tissue is approximately 1500 m/s, which is similar to the speed of sound in water. To calculate the wavelength, we can use the formula: wavelength = speed of sound / frequency.
In this case, the frequency is given as 2.40 MHz, which is equivalent to 2.40 million cycles per second. By substituting the values into the formula, we get:
wavelength = 1500 m/s / 2.40 MHz
= 1500 m/s / (2.40 x 10⁶ Hz)
≈ 0.625 mm
Therefore, the wavelength of ultrasound with a frequency of 2.40 MHz is approximately 0.625 mm.
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A baker pushes a cart full of rolls with a force of 20.0 N for a distance of 4.0 m. How much work does the baker do on the cart?
Answer:
80
Explanation:
You calculate work by W(j)=Force(n) x distance moved (m)
So 20.0 N x 4.0 m = 80.
:)
The work done when a baker pushes a cart full of rolls with a force of 20.0 N for a distance of 4.0 m is 80 Nm.
What is Work done?
The work done by a force can be defined as the product of the displacement of that object and the component of the applied force of the object which is in the same direction as that of displacement. When we push a block with some force 'f' and the body moves with some acceleration, work is done.
W = f × d
where, W = work done,
f = applied force,
d = displacement of the object
W = 20N × 4.0m
W = 80Nm
Therefore, the work done by the baker on that cart is 80 Newton meters.
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Attempt 2 Identify which statements about denaturation are true and which are false. True statements False statements A denatured protein has a different tertiary structure than its native state. Soaking fish in lime juice (pH 2.3) denatures the proteins. Digestive enzymes hydrolyze proteins Cooking an egg hydrolyzes its albumin. Egg white meringue, made by beating egg whites, contains denatured proteins A denatured protein has a different primary structure than its native state Denaturation and digestion refer to the same process
Denaturation refers to the process of alteration of the native structure of proteins. Some of the statements about denaturation are true, and some of them are false.
True statements:
A denatured protein has a different tertiary structure than its native state. Soaking fish in the lime juice (pH 2.3) denatures the proteins. Digestive enzymes hydrolyze proteins. Egg white meringue, made by beating egg whites, contains denatured proteins
False statements:
A denatured protein has a different primary structure than its native stateDenaturation and digestion refer to the same process. Cooking an egg hydrolyzes its albumin. This statement is false because cooking an egg does not hydrolyze its albumin but denatures it. This process can be referred to as coagulation.
Denaturation and digestion are not the same process. Denaturation refers to the alteration of the native structure of proteins, while digestion refers to the breakdown of food into smaller and simpler molecules in the body through mechanical and chemical processes.
Hence, the statements that are true are:
A denatured protein has a different tertiary structure than its native state.
Soaking fish in the lime juice (pH 2.3) denatures the proteins.
Digestive enzymes hydrolyze proteins. Egg white meringue, made by beating egg whites, contains denatured proteins.
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what seems to control the assembly and disassembly of intermediate filaments?
The assembly and disassembly of IFs are regulated by a variety of factors, including phosphorylation, subunit availability, pH, and ionic strength.
Intermediate filaments (IFs) are components of the cytoskeleton that control a variety of biological processes. IFs are typically less dynamic than microtubules and actin filaments, and they appear to be more stable. The assembly and disassembly of intermediate filaments are regulated by phosphorylation-dephosphorylation mechanisms.
The assembly and disassembly of intermediate filaments are controlled by a variety of factors. One of the primary determinants of IF dynamics is phosphorylation. Phosphorylation of specific residues on the IF proteins affects both the ability of the protein to form filaments and its stability once it has formed a filament.
In some cases, the presence of free subunits can promote filament formation, while in others, the formation of complexes between subunits can inhibit filament assembly. Changes in pH or ionic strength can also affect the assembly and disassembly of IFs.Intermediate filaments (IFs) are cytoskeletal structures that are typically more stable than microtubules or actin filaments.
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A 3.5-kg plastic tank that has a volume of 0.2 m3 is filled with liquid water. assuming the density of water is 1000 kg/m3, determine the weight of the combined system.
The weight of the combined system = 1,996.3 N
How is the weight of the combined system calculated?
Given,
Mass of the Plastic tank = 3.5 kg
Volume of the liquid water in the tank = 0.2 m³
Density of water = 1000 kg/m³
Now,
We know
Density = Mass ÷ Volume
Thus,
Mass = Density × Volume
therefore,
Mass of the water in the tank = 1000 × 0.2
= 200 kg
Thus,
The mass of the combined system = 3.5 kg + 200 kg = 203.5 Kg
Also,
Weight in N = Mass × Acceleration due to gravity (g)
and,
g = 9.81 m/s²
Therefore,
The weight of the combined system = 203.5 kg × 9.81 m/s²
= 1,996.3 N
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Why does a magnet get demagnetized when hammered?
Answer:
Answer is on the pic
Explanation:
I hope it's helpful!
A boy pushes a cart with a constant velocity of 0.5m/s by applying a force of 60 N. What is the total frictional force acting on the cart?
Answer:
The total frictional force equals 60 N
Explanation:
We know that F - f = ma where F is the applied force, f is the frictional force, m the mass of the object and a its acceleration.
Now, since the cart moves with constant velocity, its acceleration is zero. So, a = 0.
So F - f = ma
F - f = m(0) = 0
F - f = 0
So, F = f
From the above, we see that the frictional force equals the applied force which is equal to 60 N.
So, f the total frictional force equals 60 N
Which name is given to the force that stretches the spring with a metal that weights it down
Answer:
gravity
Explanation:
ok what i understand from your query is that a spring balance with a metal piece attached to it is weighing it down, a spring balance is measured in newtons (f=ma), the acceleration part is gravity (-9.81 m/s^2). The metal piece is attached to the string.
hope this answers your question and please take my answer with a grain of salt and refer to some webpages or videos
A crane lifts a steel grider in 45s.it required the crane to do 8750000 j of work .how much power did the crane use
Answer:
\(194.44kw\)
Explanation:
\(power = \frac{workdone}{time \: taken} \)
\( p = \frac{8750000}{45} \)
\(p = 194444.44watt\)
\(p = 194.44kw\)
the basic requirement for a fusion reaction is (are)
The basic requirement for a fusion reaction is a combination of high temperature and pressure, along with a sufficient amount of fuel.
In fusion, the aim is to merge light atomic nuclei, typically isotopes of hydrogen, to form a heavier nucleus and release a tremendous amount of energy. Achieving the necessary conditions involves confining the fuel, such as deuterium and tritium, using powerful magnetic fields or intense laser beams.
These confinement methods ensure that the fuel is heated to millions of degrees, creating a plasma state where atomic collisions occur at high velocities. The high temperature and pressure cause the atomic nuclei to overcome their mutual electrostatic repulsion and merge, releasing energy in the form of light and heat.
Properly sustaining and controlling these conditions are key to realizing controlled fusion reactions, which hold immense potential as a clean and virtually limitless energy source.
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______ tides, tides that are weaker than normal, happen when the Moon is at first or last quarter phase and the sun and moon interfere with each other.
A high
B low
C neap
D spring
Answer:
C. Neap Tides
Explanation:
Answer:
c neap tides
Explanation: