A set of data is represented in the stem plot below.

Stem plot with stems of 3, 4, 5, 6, 7, 8, 9, 10. Leaf for stem of 3 is 5. Leaves for stem of 4 are 2 and 3. Leaves for stem of 5 are 1, 5, and 7. Leaves for stem of 6 are 2, 6, 8, and 9. Leaves for stem of 7 are 4, 5, 6, 7, 8, and 9. Leaves for stem of 8 are 2, 4, 6, and 8. Leaves for stem of 9 are 3 and 4. Leaf for stem of 10 is 1.

Key: 3 | 5 = 35

Part A: Find the mean of the data. Show each step of work. Round answer to the nearest whole number. (2 points)

Part B: Find the median of the data. Show each step of work. (2 point)

Part C: Find the mode of the data. Show each step of work. (2 point)

Part D: Compare your values for mean, median, and mode from parts A, B, and C. Explain which value would best represent the data, and why? (4 points)

Answer:

b = 1/3

Step-by-step explanation:

The general structure of equations in slope-intercept form is:

y = mx + b

In this form, "m" represents the slope and "b" represents the y-intercept.

The given equation is already in slope-intercept form. In other words, you have already been given "m" and "b". Therefore, the value which corresponds with the y-intercept is (1/3).

f(x) = mx + b

f(x) = -(2/9)x + 1/3

Answer:

i think it is 1/100

Step-by-step explanation:

4/20^2 add all the marbles number together than put the amount of orange marbles on top of it so it is 4/20 than square it

64,80,100,125.... the increments are 16, 20, 25 so, in this case the increment is 1/4 of the original quantity

16 is 1/4 of 64, 20 is 1/4 of 80, 25 is 1/4 of 100

so the grow rate is 1/4 = 0.25

in percent, it is 25%

64,112,196,343.... the increments are 48, 84, 147 so, in this case, the increment is 3/4 of the original quantity

48 is 3/4 of 64, 84 is 3/4 of 112 and 147 is 3/4 of 196

so the grow rate is 3/4 = 0.75

in percent, it is 75%

64,128,256,512.... the increments are 64, 128, 256 so, in this case, the increment is equal to the original quantity

so the grow rate is 1

in percent, it is 100%

125,100,80,64....​ the decrements are 25, 20, 16 so, in this case the decrement is 1/5 of the original quantity

25 is 1/5 of 125, 20 is 1/5 of 100 and 16 is 1/5 of 80

the quantities decrease, so the grow rate is negative: -1/5 = -0.2

in percent, it is -20%

Answer:

Solution,

b=8

Now,

9-b

=9-8

=1

Hope this helps...

Good luck on your assignment...

Answer:

x \(\geq -10\\\)

Step-by-step explanation:

x\(x\geq -10\)

The vectors related to given points are AB <6, 4> and BC <4, 6>, respectively.

In this problem we must determine the equations of two vectors represented by a figure, each vector is between two consecutive points set on Cartesian plane. The definition of a vector is introduced below:

AB <x, y> = B(x, y) - A(x, y)

Where:

Now we proceed to determine each vector:

AB <x, y> = (6, 4) - (0, 0)

AB <x, y> = (6, 4)

AB <6, 4>

BC <x, y> = (10, 10) - (6, 4)

BC <x, y> = (4, 6)

BC <4, 6>

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Since the distance between the centers is 10 and the radius of both circles is 7, the two circles are externally tangent.Therefore, Chante is right.

To prove that two circles are externally tangent, we need to show that their radii are equal and the distance between their centers is equal to the sum of their radii.

We can find the equation of the first circle to be (x+2)^2+(y−4)^2=49, which has a radius of 7.

For the second circle, we can rewrite the equation as x^2+y^2−6x+16y−37=0, which has a radius of sqrt(37).

Since the radius of both circles is 7, they are equal.

To find the distance between their centers, we can use the Pythagorean theorem. The distance between the centers is the square root of (6^2 + 16^2) = sqrt(100) = 10.

Since the distance between the centers is 10 and the radius of both circles is 7, the two circles are externally tangent.

Therefore, Chante is right.

the correct question is: Chante claims that two circles given by (x+2)^2+(y−4)2=49 and x^2+y^2−6x+16y+37=0 are externally tangent. She is right. Show that she is right.

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Answer:

make me brainliest plsssssssss

Step-by-step explanation:

A

Answer:

A.

Step-by-step explanation:

Given that point P partitions a directed line segment from A to B into the ratio 3:4, we are to determine how close P is to either A or B.

To do this, we take an example.

Let the length of line segment AB be 14 Units.

Since P divides AB in the ratio 3:4

Therefore, from the above, we can conclude that P will be closer to A as its distance from A is shorter than its distance from B.

The correct option is A.

Answer:

Point P partitions the directed line segment from A to B into the ratio 3:4. Will P be closer to A or B? Why?

A number line goes from point A to point B. A line is drawn from point A to point B.

Right Answer  A.)   P will be closer to A because it will be Three-sevenths the distance from A to B.  

Wrong Answer  B.)   P will be closer to A because it will be Four-sevenths the distance from A to B.

Wrong Answer C.)    P will be closer to B because it will be Three-sevenths the distance from B to A.

Wrong Answer D.)   P will be closer to B because it will be Four-sevenths the distance from B to A.

Step-by-step explanation:

The radius of the pool is 9.01 m.

Given,

In the question:

A circular pool is surrounded by a brick walkway 3 m wide.

The area of the walk- way is 198 m^2.

To find the Radius of the pool.

Now, According to the question:

"Area of the circle bounded by the outside edge of the walkway" minus "area of the pool" = "area of the walkway".

Let R = Radius of the pool

Area of the circle bounded by the outside edge of the walkway is:

\(\pi\)(R +3)^2

Area of the pool is:

\(\pi R^2\)

Now, Our equation is:;

\(\pi\)(R +3)^2 - \(\pi R^2\) = 198

\(\pi\)((R+3)^2 - \(R^2\)) = 198

Open the inner bracket :

\(\pi\)(\(R^2+6R+9-R^2\)) = 198

\(\pi\)(6R +9) = 198

6R+9 = 198/\(\pi\)

6R = 198/\(\pi\) - 9

R = (198/\(\pi\) - 9)/6

R = (198/(3.14) - 9)/6

R = (63.057 - 9)/6

R = 54.057/6

R = 9.01 meters

Hence, The radius of the pool is 9.01 m.

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The simplified expression for (f ∘ g)(x) is 2 + x (option d).

To find and simplify (f ∘ g)(x), we need to substitute the expression for g(x) into f(x) and simplify.

Given:

f(x) = log₃(9x)

g(x) = \(3^x\)

Substituting g(x) into f(x):

(f ∘ g)(x) = f(g(x)) = log₃\((9 * 3^x)\)

Now, we simplify the expression:

log₃\((9 * 3^x)\) = log₃(9) + log₃\((3^x)\)

Since logₓ(a * b) = logₓ(a) + logₓ(b), we have:

log₃(9) + log₃\((3^x)\) = log₃\((3^2)\) + x

Using the property logₓ\((x^a)\) = a * logₓ(x), we get:

log₃\((3^2)\) + x = 2 * log₃(3) + x

Since logₓ\((x^a)\) = a, where x is the base, we have:

2 * log₃(3) + x = 2 + x

Therefore, (f ∘ g)(x) simplifies to:

(f ∘ g)(x) = 2 + x

So, the correct answer is (d) 2 + x.

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Complete Question:

Given f(x)=log₃(9x) and g(x)=\(3^x\). Find and simplify (f ∘ g)(x)

(a) 2x

(b) x

(c) \(27^x\)

(d) 2+x

(e) None of these.

Answer:

  D.  (4, -2, 2)

Step-by-step explanation:

The domain is the horizontal extent of the graph, the values of x for which the relation is defined.

We can read the x-values of the points from the graph:

  (-4, -2, 2)

Answer:

leading co-efficent is 4

Answer:

There is a total 50 questions.

Step-by-step explanation:

Let x = total questions in the exam

Since 82% of the test was scored correctly, that means 18% of the student's exam was scored incorrectly.

With this information we can write:

\(18\%x=9\) (Given that the student made 9 mistakes)

\(x=9\div18\%\) (divide 18% on both sides)

\(x=50\)

∴ There was a total of 50 questions in the examination.

The lines: x a d y a z a d and x b c y b z b c are coplanar.The equation of the plane is given by: (a(x - x₁) + d(a - y₁))(b(y - y₁) + c(b - y₁)) = 0 where (x₁, y₁) are the coordinates of the chosen points.

To determine if the lines x a d y a z a d and x b c y b z b c are coplanar, we need to check if they lie on the same plane. Two lines are coplanar if they either intersect or are parallel and lie on the same plane.

In this case, we can observe that the two lines have a common direction vector (a, d) and (b, c), respectively. This implies that they are parallel.

To find the equation of the plane in which they lie, we can use any two points from each line. Let's choose the point (x, a, y) from the first line and the point (x, b, y) from the second line.

We can then use these points along with the direction vectors (a, d) and (b, c) to write the equation of the plane using the point-normal form.

The equation of the plane is given by:

(a(x - x₁) + d(a - y₁))(b(y - y₁) + c(b - y₁)) = 0

where (x₁, y₁) are the coordinates of the chosen points.

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Answer:

\(L = 0.83\ in\)

Step-by-step explanation:

Given

Width = 1.2 in when Length = 1 in

Required

Determine the length when width = 1 in

First, we need to determine the ratio:

\(Ratio = \frac{Width}{Length}\)

\(Ratio = \frac{1.2}{1}\)

\(Ratio = 1.2\) --- (1)

Let the required Length be represented with L

So:

\(Ratio = \frac{Width}{Length}\)

\(Ratio = \frac{1}{L}\) --- (2)

Equate (1) and (2)

\(\frac{1}{L} = 1.2\)

Multiply through by L

\(L * \frac{1}{L} = 1.2 * L\)

\(1 = 1.2 * L\)

Divide through by 1.2

\(L = \frac{1}{1.2}\)

\(L = 0.83\ in\) (Approximated)

To prove the existence of a subspace U of V such that the projection operator P can be represented as PU, we can use the properties of the projection operator and the fundamental theorem of linear algebra.

Given that P^2 = P and every vector in null P is orthogonal to every vector in range P, we know that V can be decomposed into the direct sum of range P and null P. This means that for every vector v in V, there exist unique vectors u in range P and w in null P such that v = u + w. By defining U as range P, we have V = U ⊕ null P. Since every vector in null P is orthogonal to every vector in range P, the sum of U and null P is direct.

Now, consider the action of P on an arbitrary vector v in V. Since v = u + w, where u is in U and w is in null P, applying P to v yields P(v) = P(u + w) = u. Thus, P can be represented as PU, where U is the subspace defined as range P. Therefore, we have proven that there exists a subspace U of V such that P can be represented as PU.

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QUESTION:

What is the slope of y=7x-2

ANSWER:

\(\green{{m = 7}}\)

EXPLANATION:

The slope-intercept form is \(\blue{{y = mx + b}}\) where \(\blue{{m}}\) is the slope and \(\blue{{b}}\) is the y-intercept

\(\green{{y = mx + b}}\)

Using the slope-intercept form, the slope is \(\blue{{7}}\)

\(\green{\boxed{m = 7}}\)

hope it's helps

Answer:

16m

8m

50.24m

200.96m^2

Step-by-step explanation:

13. 8*2=16

14. 8m

15. 2pi r = 2* pi* 8= 50.24

16. pi r^2 = pi * 8^2= 200.96m^2

The solutions are m = 4 and m = 5. Thus, the values of m that make y = x^m a solution of the given differential equation are m = 4 and m = 5.

To find all values of m for which the function y = x^m is a solution of the given differential equation x^2y'' - 8xy' + 20y = 0, we can substitute y = x^m into the differential equation and determine the values of m that satisfy the equation.

In the first paragraph, we summarize the task: we need to find the values of m that make the function y = x^m a solution to the differential equation x^2y'' - 8xy' + 20y = 0. In the second paragraph, we explain how to proceed with the solution.

Substituting y = x^m into the differential equation, we have x^2(m(m-1)x^(m-2)) - 8x(mx^(m-1)) + 20x^m = 0. Simplifying this equation, we get m(m-1)x^m - 8mx^m + 20x^m = 0. We can factor out x^m from this equation, yielding x^m(m(m-1) - 8m + 20) = 0.

For the function y = x^m to be a solution, the expression in parentheses must equal zero, since x^m is nonzero for x ≠ 0. Thus, we need to solve the quadratic equation m(m-1) - 8m + 20 = 0. Simplifying further, we get m^2 - 9m + 20 = 0.

Factoring this quadratic equation, we have (m-4)(m-5) = 0. Therefore, the solutions are m = 4 and m = 5. Thus, the values of m that make y = x^m a solution of the given differential equation are m = 4 and m = 5.

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Answer:

x + 2/5 = 4

subtract 2/5 from both sides

That is

x + 2/5 - 2/5 = 4 - 2/5

x = 4 - 2/5

x = 18/5 or 3 3/5 as a mixed number

Hope this helps

There are 1260 different strings that can be made from 5 of the 7 letters in the word "meeting."

To determine the number of unique subsets of 5 letters from the word "meeting," we can use the combination formula:

\(n_Cr = n! / r!(n-r)!\)

Where n is the total number of items (in this case, the number of letters in the word "meeting") and r is the number of items being selected (in this case, 5 letters).

So, for "meeting," n = 7 and r = 5.

Plugging these values into the formula gives:

\(7C5 = 7! / 5!(7-5)! = 21\)

Therefore, there are 21 unique subsets of 5 letters that can be formed from the letters in the word "meeting."

To determine the number of different strings that can be made from 5 of those 7 letters, we can use the permutation formula:

\(n_Pr = n! / (n-r)!\)

Where n is the total number of items (in this case, the number of letters in the word "meeting") and r is the number of items being selected (in this case, 5 letters).

So, for "meeting," n = 7 and r = 5.

Plugging these values into the formula gives:

7P5 = 7! / (7-5)!

= 7! / 2!

= 2520 / 2

= 1260

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Scott owns the deer because he was the first to take possession of the carcass. Joe is not entitled to the deer because he did not physically take possession of it before Scott did.

1. Joe goes deer hunting on public land.

2. While in his deer stand, Joe sees a large buck.

3. Joe shoots the buck but the deer continues to run 300 yards before dying.

4. Before Joe can take possession of the carcass, Scott finds the dead animal and takes possession of the deer.

5. Scott owns the deer because he was the first to take possession of the carcass.

6. Joe is not entitled to the deer because he did not physically take possession of it before Scott did.

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By using standard error, The nurse sampled approximately 100 patients to analyze their exercise time.

To determine the sample size, we can use the formula for the standard error of the mean:

Rearranging this formula to solve for the sample size, we get:

Plugging in the values given in the problem, we get:

However, because the population size is large (i.e. infinite), we can use the rule of thumb that a sample size of at least 30 is sufficient for a normal distribution. Therefore, the nurse should sample at least 30 patients, but she likely sampled around 100 patients to obtain a standard error of 3 minutes with a normal distribution of exercise time.

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Answer:

b)a collage using paper, wood, and paint

Step-by-step explanation: