A scooter travels 30 feet in 2 seconds at a constant speed.
What is the speed of the scooter in feet per second?

Answer:29x+10y<60

Step-by-step explanation:

She has $60 to spend.

And no tax. it should be 29x+10y>(less than or equal to) $60.

True. Hexadecimal numbers are written using the base 16 number system, where digits range from 0 to 9 and A to F. They are commonly used in computer systems for concise representation and easy conversion to binary.

In the hexadecimal number system, there are 16 symbols used to represent values, namely 0-9 and A-F. Each digit in a hexadecimal number represents a multiple of a power of 16.

The symbols 0-9 represent the values 0-9, respectively. The symbols A-F represent the values 10-15, respectively, where A represents 10, B represents 11, C represents 12, D represents 13, E represents 14, and F represents 15.

For example, the hexadecimal number "3F" represents the value (3 * 16^1) + (15 * 16^0) = 48 + 15 = 63 in decimal.

Similarly, the hexadecimal number "AB8" represents the value (10 * 16^2) + (11 * 16^1) + (8 * 16^0) = 2560 + 176 + 8 = 2744 in decimal.

Hexadecimal numbers are commonly used in computer systems, as they provide a convenient way to represent large binary numbers concisely. Each hexadecimal digit corresponds to a four-bit binary number, allowing for easy conversion between binary and hexadecimal representations.

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Answer:

x²+7x+12

Step-by-step explanation:

x*x=x²

x*4=4x

3*x=3x

4x+3x=7x

3*4=12

=x²+7x+12=0

Answer: ^2 + 7 + 12

Step-by-step explanation:

(x + 4)(x + 4)

( + 4)+3( + 4)

( + 4)+3( + 4)

^2 + 4 + 3( + 4)

^2 + 4 + 3 + 12

^2 +7 +12

The Values of (a+b)ab are undefined.

Given that, a = 3an and db = -2We need to find the values of (a+b)

Now, we have a = 3an... equation (1)Also, we have db = -2... equation (2)From equation (1), we get: n = 1/3... equation (3)Putting equation (3) in equation (1), we get: a = a/3a = 3... equation (4)Now, putting equation (4) in equation (1), we get: a = 3an... 3 = 3(1/3)n = 1

From equation (2), we have: db = -2=> d = -2/b... equation (5)Multiplying equation (1) and equation (2), we get: a*db = 3an * -2=> ab = -6n... equation (6)Putting values of n and a in equation (6), we get: ab = -6*1=> ab = -6... equation (7)Now, we need to find the value of (a+b).For this, we add equations (1) and (5),

we get a + d = 3an - 2/b=> a + (-2/b) = 3a(1) - 2/b=> a - 3a + 2/b = -2/b=> -2a + 2/b = -2/b=> -2a = 0=> a = 0From equation (1), we have a = 3an=> 0 = 3(1/3)n=> n = 0

Therefore, from equation (5), we have:d = -2/b=> 0 = -2/b=> b = ∞Now, we know that (a+b)ab = (0+∞)(0*∞) = undefined

Therefore, the values of (a+b)ab are undefined.

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The vectors v and w are orthogonal because their dot product is 0 .

The angle between v and w is  :

\(cos\theta=0\\\\= > \theta=90\)

We have the information from the question:

v = -i - j,

w = -i + j

We have to find the dot product and state the vectors are parallel, orthogonal, or neither. vij, wij.

Now, According to the question:

The dot product are:

(v)(w) =  (-i - j)( -i + j)

Taking each  set of integer of the vector into consideration:

(v)(w) = ( -1 × - 1) ( -1 × 1)

(v)(w) = 1 - 1

(v)(w) = 0

So, The dot product is 0

This is implies that :

\(cos\theta=0\\\\= > \theta=90\)°

Hence, we can conclude that :

The vectors v and w are orthogonal because their dot product is 0 .

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The given question is incomplete, complete question is:

for the following vectors, (a) find the dot product vw; (b) find the angle between v and w; (c) state whether the vectors are parallel, orthogonal, or neither. vij, wij

v=-i-j, w=-i+j

Answer: yes

Step-by-step explanation:

Answer:

The volume of the solid is:

\(408~\text{in}^{3}\)

Step-by-step explanation:

Step 1: Analyzing the cross-sectional area

Upon looking at the cross-sectional area, we can see that we can separate it into three different rectangles (as shown in the diagram).

The area of rectangles are given by:

\(\text{Area}=\text{Length}\times \text{Width}\)

The length of the top rectangle is 7, and the width is 2, so substitute these values:

\(\text{Area}=7\times2\\\text{Area}=14\)

The length of the middle rectangle is 8, and the width is 5, so substitute these values and calculate:

\(\text{Area}=8\times5\\\text{Area}=40\)

The bottom rectangle is the same as the top rectangle, so it will have the same area as it:

\(\text{Area}=14\)

The area of the entire cross-sectional area will be the sum of all these areas:

\(\text{Total Area}=14+40+14\\\text{Total Area}=68~\text{in}^{2}\)

Step 2: Calculating the volume

The volume of any solid is given by:

\(\text{Volume}=\text{Cross-sectional area}\times \text{Length}\)

We have obtained the cross-sectional area, and the length is \(6\).

Substitute these values into the formula:

\(\text{Volume}=\text{Cross-sectional area}\times \text{Length}\\\text{Volume}=68\times 6\\\\\text{Calculate:}\\\text{Volume}=408~\text{in}^{3}\)

Answer:

A = 7 x 9.3

A = 65.1 yd²

Step-by-step explanation:

(I am assuming that either 7 or 9.3 refers to the height. It is unclear.)

A = bh

Volume of a convention centre in the shape of a rectangular pyramid of height 261m and base measuring 468m by 395m is 16,082,820 m³.

Therefore the answer is 16,082,820 m³.

A rectangular pyramid is a solid with a rectangular base and four triangular faces. Its volume is one-third volume of the cuboid it is inscribed in.

The formula to calculate the volume of a right rectangular pyramid of height h and base dimension l × b is

V = l × b × h/ 3

Therefore the volume of convention centre can be calculated by

V = 468 × 395 × 261/ 3 m³

V = 16,082,820 m³

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Answer:

D = \(5\sqrt{5}\)

Step-by-step explanation:

\(d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\d= \sqrt{(-7-(-2))^2+(-7-3)^2} \\d= \sqrt{(-5)^2+(-10)^2} \\d= \sqrt{25+100} \\d= \sqrt{125} \\d= 5\sqrt{5}\)

Answer:

(-4, -0.5)

Step-by-step explanation:

(ignore this words)

The inequality that represents the given statement is "negative one fifth is greater than or equal to negative two sevenths y " is   and the solution is y ≥ 7/10.

The statement for the inequality is given as : "negative one fifth is greater than or equal to the product of negative two sevenths and a number" .

Let the number be "y" .

Negative one fifth means = -1/5

Negative two sevenths means = -2/7 .

So, according to the question,

The inequality can be represented as

-1/5 ≥ (-2/7)×y

To solve the inequality multiplying both sides by -1

1/5 ≤ 2/7×y

So , y ≥ (1/5) × (7/2)

y ≥ 7/10 .

Therefore, the correct option is (c)

-- The given question is incomplete , the complete question is

"Write and solve the inequality that represents "negative one fifth is greater than or equal to the product of negative two sevenths and a number".

(a) negative two sevenths is less than or equal to negative one fifth y where y is less than or equal to two thirty fifths

(b) negative two sevenths is greater than or equal to negative one fifth y where y is less than or equal to negative seven tenths

(c) negative one fifth is greater than or equal to negative two sevenths y where y is greater than or equal to seven tenths

(d) negative one fifth is less than negative two sevenths y where y is less than or equal to negative two thirty fifths." --

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Answer: 4 1/8

Step-by-step explanation:

1 6/8 + 2 3/8 = 33/8 = 4 1/8

Answer:

4 1/8

Step-by-step explanation:

first turn the fractions into improper fractions...

so 1 6/8 = 14/8

and 2 3/8 = 19/8

then add together.. 14/8+19/8=33/8

change into a mixed number = 4 1/8

or

do 1+2=3

and 6/8+3/8=9/8=1 1/8

and add the two values together... 3+ 1 1/8 = 4 1/8

Answer:

b. To find the probability a customer who ordered pancakes came to thediner late, we need to look at the intersection of the "pancakes" row and the "late" column. This gives us a probability of 0.1, or 10%

c. To determine whether breakfast choice and meal time are independent, we need to see if the probability of one event changes based on the occurrence of the other event. In this case, it seems that breakfast choice and meal time are not independent, as the probability of being late seems to differ based on what breakfast item the customer chose. For example, the probability of being late is higher for customers who ordered pancakes compared to those who ordered cereal. Therefore, the choice of breakfast item appears to be related to the probability of being late, and so breakfast choice and meal time are not independent.

Step-by-step explanation:

Answer:

(-3, -1) (-2, 3)

(-2, 3) (-2, 3)

Step-by-step explanation:

Answer:

I think this is your answer _. 4 ×( _ 2°3)

Answer:

\(9x^{5}+30x^{4}-2x^{3}-108x^{2}-135x-50\)

Step-by-step explanation:

see below, if you have any questions leave a comment  

Let's solve the following equation to see where Maya made a mistake:

2 (3x + 6) = 3 (x - 10)

Step 1: Solving parenthesis

6x + 12 = 3x - 30

Step 2: Like terms

6x - 3x = -30 - 12

Step 3: Complete the subtractions at both sides

3x = -42

Step 4: Dividing by 3 at both sides

3x/3 = -42/3

x = -14

Maya didn't multiply correctly 3 * - 10

Yes, Javionery, option B is the correct one.

The measure of angle x is given as follows:

x = 48º.

The three trigonometric ratios are the sine, the cosine and the tangent of an angle, and they are obtained according to the formulas presented as follows:

For angle x, we have that:

Hence we apply the sine ratio to obtain the measure of x as follows:

sin(x) = 7/9.4

x = arcsin(7/9.4)

x = 48º.

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d. Dummy coding. Categorical variables need to be converted into numerical variables to be used in regression analysis. Dummy coding involves creating binary variables for each category of the categorical variable.

For example, if the categorical variable is "color" with categories "red," "green," and "blue," dummy coding would involve creating three binary variables: "red" (0 or 1), "green" (0 or 1), and "blue" (0 or 1). These binary variables can then be used in the regression analysis. In conclusion, to use categorical variables in regression analysis, dummy coding is necessary.


In order to use categorical variables in a regression analysis, they must be converted into numerical values. This process is called dummy coding (also known as one-hot encoding). Dummy coding involves creating new binary variables (0 or 1) for each category of the categorical variable. This allows the regression model to incorporate the categorical data while maintaining its numerical nature.

To use categorical variables in a regression analysis, you must apply dummy coding to convert them into numerical values.

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The upper limit of the confidence interval is 0.243 at 99% confidence and the interval for the proportion of adults that prefer honey is 0.157 and 0.243.

Sample size = 815

sample proportion = 0.2(20%)

Confidence = 99%

To calculate the 99% confidence interval for the proportion of adults that choose honey on their peanut butter sandwiches, we can utilize the following formula:

CI = p ± z x (sqrt(p(1-p)/n))

The z-score corresponds to a 99% confidence level = 2.576.

CI = 0.2 ± 2.576* (sqrt(0.2(1-0.2)/815))

CI = 0.2 ± 0.043

CI upper limit = 0.2 + 0.043

CI upper limit = 0.243

CI lower limit = 0.2 - 0.043

CI lower limit =0.157

Therefore, we can conclude that the 99% confidence interval for the proportion of adults that prefer honey is 0.157 and 0.243. The upper limit of the interval is 0.243.

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Answer:

\( \red{\bold {7x - 9y - 39 = 0}} \)

Step-by-step explanation:

Line passes through the points

\( (3, \: - 2) =(x_1, \: y_1) \:\&\: (-6,\: - 9)= (x_2, \: y_2)\)

Equation of line in two point form is given as:

\( \frac{y-y_1}{y_1-y_2} = \frac{x-x_1}{x_1-x_2} \\\\

\frac{y-(-2)}{-2-(-9)} = \frac{x-3}{3-(-6)} \\\\

\frac{y+2}{-2+9} = \frac{x-3}{3+6} \\\\

\frac{y+2}{7} = \frac{x-3}{9} \\\\

9(y+2) = 7 (x - 3)\\\\

9y + 18 = 7x - 21\\\\

7x - 9y - 21 - 18 = 0\\\\

\huge \purple {\boxed {7x - 9y - 39 = 0}} \)

Answer:

D

Step-by-step explanation:

In Quadrant 2, cosine will be negative so we can eliminate options B and C. If tan theta = -4/3 we know the opposite side to theta is 4 and the adjacent side to theta is 3. Using Pythagorean Theorem, the hypotenuse is 5 which means cos theta = adjacent / hypotenuse = -3/5.

Answer:

x>9/5

Step-by-step explanation:

2/3x-1/5(+1/5)>1(+1/5)

[add 1/5 on both sides]

2/3x (÷3/2)>6/5 (÷3/2)

[flip 2/3 to 3/2 so that they cancel out]

x>9/5

The equation of the line passing through the points (0, 2) and (3, 0) is

The equation of the line passing through the points (0, -4) and (5, -1) is

The slope between the points (4,5) and (‐3, 6) is -1/7.

The equation of a line in slope intercept form is written as

y = mx + c

where

m = slope and c is the y- intercept

From the graph points (0, 2) and (3, 0) is used

To find the equation of the line passing through the points (0, 2) and (3, 0), we can use the point-slope form of the equation of a line, which is:

y - y1 = m(x - x1)

m = (y2 - y1) / (x2 - x1)

m = (0 - 2) / (3 - 0)

m = -2/3

substitute in the point-slope form of the equation of a line. using point (0, 2):

y - y1 = m(x - x1)

y - 2 = (-2/3)(x - 0)

y - 2 = (-2/3)x

y = (-2/3)x + 2

For the second line points (0, -4) and (5, -1) is used

m = (-1 + 4) / (5 - 0)

m = 3/5

Using point (0, 4)

y - y1 = m(x - x1)

y - 4 = (3/5)(x - 0)

y - 4 = 3/5 x

y = 3/5 x + 4

The slope between two points (x1, y1) and (x2, y2) can be calculated using the formula:

slope = (y2 - y1) / (x2 - x1)

slope = (6 - 5) / (-3 - 4)

slope = 1 / (-7)

slope = -1/7

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There are 50,000 odd five-digit counting numbers that can be formed by choosing digits from the set with repetition allowed.

To determine the number of odd five-digit counting numbers that can be formed by choosing digits from a set (with repetition allowed), we need to consider the restrictions and possibilities for each digit position.

1. The leftmost digit:

2. The remaining four digits:

To find the total number of odd five-digit counting numbers, we multiply the possibilities for each digit position:

Total number = (5 options for the leftmost digit) \(\times\) (10 options for each of the remaining four digits)

Total number = \(5 \times 10^4 = 50,000\)

Therefore, there are 50,000 odd five-digit counting numbers that can be formed by choosing digits from the set when repetition is allowed.

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The number of groups of five courses the student can select for the next semester is 126.

In order to answer this question, we must first determine how many courses the student has already taken. If the student has already taken 11 courses, then the total number of courses she needs to take is 9.

We can use the formula for combinations, nCr, to calculate the number of groups of five courses that she can select for the next semester. The formula is nCr=n!/(r!(n-r)!). In this case, n is the total number of courses (9) and r is the number of courses in each group (5).

Therefore, the number of groups of five courses the student can select for the next semester is 9C5, or 9!/[5!(9-5)!], which equals 126. This means the student can select 126 different groups of five courses for the next semester.

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The correct option Input-Output Tables for Function Rules is

f(x)= 2x +3.

Input (x):       3   6  9   12

Output(f(x)):  9  15 21  27

Give:

Observe the table:

Each pair of numbers in the table is related by the same function rule. That rule is: multiply each input number (x-value) by 2 then add 3 to find each output number (y-value) or f(x). You can use a rule like this to find other values for this function, too.

Now look at how to use a function rule to complete a table.

Input (x) Output (f(x))      Rule : f(x)=2x + 3

3               9                          2x3+3= 9

6                   15                          2x6+3=15

9               21                          2x9+3=21

12              27                          2x12+3=27

So here we can see by using f(x)=2x + 3, we can find the output.

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It is gvien that y varies inversely as x.

The relation between x and y in mathematical expressin is given as.

The value of y is 11 when x is 8 , we have to determine the value of y when x is 10.

Apply the mathematical expression and substitute the value of x and y ,

Now , substitute the value of k in the mathematical expression and value of x which is 10, to find the value of y.

Thus the value of y is 8.8 when x is 10.