Answer:
honestly I really don't know but I think that it would have to do the same for me and the kids that are not going well for you guys too much further that you are as well and as you can imagine how much I miss your beautiful and very sweet dreams you have been a wonderful day for you all the time I am going through this equation for the ss of my own is to have the same problem with my brother is not a big brains for the ss of his own and I don't want us that since we don't
An object completes 2500 cycles in 25 s.
a. What is the period of its rotation?
b. What is the frequency of its rotation?
Answer:
a) 0.01s
b) 100Hz
Explanation:
Period is defined as the time taken by a wave to complete 1 oscillation.
Since the object completes 2500 cycles in 25secs, we can write
2500cycles = 25secs
1 cycle = x
Cross multiply
2500x = 25
x = 25/2500
x = 0.01secs
Hence the period of its rotation is 0.01secs
b) is the reciprocal of the period
Frequency = 1/Period
Frequency = 1/0.01
Frequency = 100Hertz
Hence the frequency of rotation is 100Hz
An electric iron is connected to the mains power supply of 220 V. When the electric iron is
adjusted at 'minimum heating' it consumes a power of 360 W but at 'maximum heating' it takes a
power of 840 W. Calculate the current and resistance in each case.
Answer:
Given: V = 220V, Pmin = 360W, Pmax = 840W
For minimum heating case:
We know that
Pmin = VI
360 = 220 X I
I = 1.63 amp
R = V/I
R = 220/1.63
R = 134.96ohms
For maximum heating case:
We know that
Pmax = VI
840 = 220 X I
I = 3.81 amp
R = V/I
R = 220/3.81
R = 57.74 ohms
Why does a traveller's bag have wheels
Answer:
To make carrying the loads easier
Answer:
It's convenient and easy to rove a traveller's bag when it has wheels. You could easily drag the bag without hesitation instead of lifting it or pushing it heavily.
Help me please
There’s 2 questions.
Answer:
50 Joules of work on the system Total distance is 1m W= F ×D 50 Joules = F × 1m F= 50 Newtons W= 1234 J D= 451234= F × 45 meters F= 27.42 Newtons I do exams and quizzes if ur interestedHey, I'm a Turk. What language do you speak? I'm very curious.
Answer:
What languages do i sqeak?
English, Korean and Filipino
Uhh why are you asking it?
A solenoid of radius r = 1.25 cm and length ℓ = 30.0 cm has 300 turns and carries 12.0 A. (a) Calculate the flux through the surface of a disk-shaped area of radius R = 5.00 cm that is positioned perpendicular to and centered on the axis of the solenoid as shown in Figure P30.48a. (b) Figure P30.48b shows an enlarged end view of the same solenoid. Calculate the flux through the tan area, which is an annulus with an inner radius of a = 0.400 cm and an outer radius of b = 0.800 cm.
The flux is 0.0118 Wb. The flux through the annular region is 2.26×\(10^{-6\)
(a) The magnetic field at the center of the solenoid is given by the formula B = μ₀nI, where μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current. Thus, the magnetic field at the center of the solenoid is:
B = μ₀nI = (4π×\(10^{-7\) T·m/A)(300/0.3 m)(12.0 A) = 1.51 T
The flux through the disk-shaped area can be calculated as Φ = BA, where A is the area of the disk. The area of the disk is A = π\(R^2\) = π(0.050 \(m)^2\)= 0.00785 \(m^2\). Thus, the flux is:
Φ = BA = (1.51 T)(0.00785 \(m^2\)) = 0.0118 Wb
(b) The flux through the annular region can be calculated as the difference in flux between two concentric circles, one with radius b and the other with radius a. The magnetic field at a point on the axis of the solenoid a distance z from the center is given by the formula B = μ₀nIz/(2R), where R is the radius of the solenoid. Thus, the magnetic field at the inner and outer radii of the annular region are:
B_a = μ₀nIa/(2R) = \((4π×10^{-7} T·m/A)(300/0.3 m)(12.0 A)(0.004 m)/(2×0.0125 m) = 2.40×10^{-3 }T\)
B_b = μ₀nIb/(2R) = \((4π×10^{-7} T·m/A)(300/0.3 m)(12.0 A)(0.008 m)/(2×0.0125 m) = 4.79×10^{-3} T\)
The flux through the annular region is then:
Φ = π(\(b^2 - a^2\))B = π(0.0008 m^2 - 0.00016 \(m^2\))(4.79×\(10^{-3\)T - 2.40×\(10^{-3\) T) = 2.26×\(10^{-6\)Wb.
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What is the partial pressure and percentage of sea-level oxygen at the top of lab?
The partial pressure and percentage of sea-level oxygen at the top of a lab can be calculated using the concept of Dalton's Law of Partial Pressures. First, let's understand what partial pressure means. In a mixture of gases, each gas exerts a pressure that is proportional to its concentration.
The partial pressure of a gas is the pressure it would exert if it occupied the entire volume alone. To calculate the partial pressure of oxygen at the top of a lab, we need to know the percentage of oxygen in the air at sea level. The percentage of oxygen at sea level is approximately 21%. Now, to calculate the partial pressure at the top of the lab, we need to know the total atmospheric pressure at that height.
Partial Pressure of Oxygen = Percentage of Oxygen * Total Atmospheric Pressur The partial pressure of oxygen at the top of the lab would be 0.21 * P. Please note that the exact value of the total atmospheric pressure at the top of the lab is needed to provide a specific answer. Additionally, this is a simplified explanation of the concept, and there may be other factors to consider in a more detailed analysis.
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What is the overall charge of the wall?
Answer:
The overall charge on the wall is zero.
Explanation:
Because the atoms making the wall are neutral i.e. number of positive charges are equal to number of negative charges.
what physical quantity of the system is represented by the slope of the force-versusacceleration graph? how well does it match the experimental setup?
The slope of the force-versus-acceleration graph represents the mass of the system according to Newton's second law of motion. In an ideal experimental setup, the measured slope should match the actual mass of the object being tested.
The physical quantity represented by the slope of the force-versus-acceleration graph is mass. According to Newton's second law of motion, force is equal to mass multiplied by acceleration (F = ma). Therefore, the slope of the graph gives us the mass of the object being measured. In terms of the experimental setup, the slope of the force-versus-acceleration graph should match the mass of the object being tested. If the experiment is conducted accurately and the force and acceleration measurements are precise, the slope of the graph should correspond to the actual mass of the object. However, it's important to note that experimental uncertainties, measurement errors, and external factors can introduce discrepancies between the expected slope and the actual measured slope. Careful calibration and control of experimental conditions are necessary to ensure accurate results.
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QUESTION 17
Which statement best describes the difference between strong nuclear forces and weak nuclear forces? (2 points)
O Weak nuclear forces are involved when certain types of atoms break down. Strong nuclear forces are responsible for
holding atoms' nucleus together.
O Weak nuclear forces hold bonds between atoms together. Strong nuclear forces hold together the nucleus of an
atom,
O Strong nuclear bonds prevent atoms from falling apart. Weak nuclear bonds prevent compounds from falling apart.
O Strong nuclear forces are involved in breaking electrons from their shells. Weak nuclear forces hold protons in the
nucleus.
Answer: Weak nuclear forces are involved when certain types of atoms break down. Strong nuclear forces are responsible for holding atoms' nucleus together.
You throw an orange out a widow at a height of 12 meters upwards at an angle of 32 to the horizontal with an initial velocity of 3.5m/s.How long will the orange be in flight before it hits the ground? Round the answer to the nearest tenth.__ Seconds
Answer:
3 meters
Explanation:
add up dum boi
A sample of an unknown substance has a mass of 0.465 kg. if 3,000.0 j of heat is required to heat the substance from 50.0°c to 100.0°c, what is the specific heat of the substance?
The specific heat of the substance will be 0.129 J/g°C.
What is specific heat capacity?The amount of heat required to increase a substance's temperature by one degree Celsius is known as specific heat capacity.
Similarly, heat capacity is the relationship between the amount of energy delivered to a substance and the increase in temperature that results.
The given data in the problem is;
Q is the amount of energy necessary to raise the temperature = 3,000.0 j
M is the mass= 0.465 kg.
Δt is the time it takes to raise the temperature.=50°c
s stands for specific heat capacity=?
Mathematically specific heat capacity is given by;
\(\rm Q= MC \triangle t \\\\ C = \frac{Q}{M\triangle t} \\\\ C = \frac{3000}{0.465 \triangle 50} \\\\ C =129.0 J/Kg^0C \\\\ C= 0.129 J/g^0C\)
Hence the specific heat of the substance will be 0.129 J/g°C.
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a system gains 782 kj of heat, resulting in a change in internal energy of the system equal to 176 kj. how much work is done?
The amount of work done in this situation is 606 kJ when a system gains 782 kj of heat, resulting in a change in internal energy of the system equal to 176 kj
When a system gains 782 kJ of heat and undergoes a change in internal energy of 176 kJ, the work done can be calculated as follows: W = Q - ΔU
Equation for work done, Where W = Work done, Q = Heat energy ΔU = Change in internal energy of the system
Therefore, Substitute the given values in the above equation. W = 782 kJ - 176 kJW = 606 kJ
Therefore, the amount of work done is 606 kJ.
In 100 words, when a system gains heat, its internal energy changes, which causes a change in the amount of work done. The equation for the work done is W = Q - ΔU. Where W is the work done, Q is the heat energy, and ΔU is the change in internal energy of the system.
In the given problem, a system gains 782 kJ of heat, resulting in a change in internal energy of 176 kJ. Using the formula, W = Q - ΔU, we can calculate the work done to be 606 kJ. Therefore, the amount of work done in this situation is 606 kJ.
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20 POINTS
A 1400 kg car moving north at 24.0 m/s collides with a 2200 kg car moving east at 18.0 m/s. The
two cars stick together after the collision. What is the speed and direction of the two cars after
the collision?
Help!! Plz anyone knows the answer.
Answer:
"correlated positively* one doesn't know any move than that
a weight w is now placed on the block and 7.1 n is needed to push them both at constant velocity. what is the weight w of the block? answer in units of n.
The weight of the block so that a force of 7.1 n can push both the block and the weight together with a constant velocity is (7.1μ - w) N.
To find out the weight w of the block when a weight w is placed on the block and 7.1 N is required to push them both at a constant velocity, the following solution should be used:
We know that, In the given problem statement, the force required to push both blocks is equal to 7.1 N.
So, Net Force = 7.1 N
Let the weight of the block is W N.
Net Force = (W + w) μ
Where μ is the coefficient of friction.
Therefore,
7.1 = (W+w)μ
W = (7.1μ - w) N
Weight of the block = (7.1μ - w) N
Weight of the block = (7.1μ - w) N (Approx)
Therefore, the weight w of the block when a weight w is placed on the block and (7.1μ - w) N is required to push them both at constant velocity is 0.7244 N.
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BRAINEST IF CORRECT, please hurry, URGENT
Using the letters for the seven colours and starting with R (Red), what is the correct order for the colours in a rainbow? Your answer should be in the form RXXXXXX Which of these seven colours has the shortest wavelength?
Answer:
Red
Orange
Yellow
Green
Blue
Indigo
Violet
shortest wavelength: violet (380 nanometers)
¯\(°_o)/¯
Answer:
Red Orange Yellow Green Blue Indigo Violet
violet has the shortest wavelength
happy to help :)
A cyclist and a motorcyclist ride on a straight road. The speed of a cyclist is 21.6 km/h , of a motorcyclist
68.4 km / h
After what time interval will the distance between them be 550 m , if at the beginning the distance between
them was 1375 m ?
About 50 000 years ago, in an area located outside Flagstaff, Arizona, a giant
4.5 x 107-kg meteor fell and struck the earth, leaving a 180-m-deep hole now
known as Barringer crater. If the meteor was traveling at 20 000 m/s upon
impact, with what average force did the meteor hit the earth?
Answer:
F_A =5.625*10^1^6N
Explanation:
From the question we are told that
50,000 years ago,
A giant 4.5 107-kg meteor
180-m-deep hole
20,000 m/s
Generally for this problem the energy change is given as
\triangle E=\frac{1}{2} mv^2 +mgd△E=
2
1
mv
2
+mgd
Having the potential and kinetic energy in place
Mathematically solving for Average forceF_AF
A
\triangle E=F_a*d△E=F
a
∗d
F_A =\frac{1/2* 4.5*10^7(20,000)^2-kg+4.5*10^7*9.81*160}{160}F
A
=
160
1/2∗4.5∗10
7
(20,000)
2
−kg+4.5∗10
7
∗9.81∗160
Therefore Average force F_AF
A
is given by
F_A =5.625*10^1^6N
Weight and mass are directly proportional to each other. True False
Weight and mass are not directly proportional to each other. Weight and mass are two different physical quantities. The given statement is false
Mass refers to the amount of matter an object contains, while weight is the force exerted on an object due to gravity. The relationship between weight and mass is given by the equation F = mg, where F represents weight, m represents mass, and g represents the acceleration due to gravity.
This equation shows that weight is proportional to mass but also depends on the acceleration due to gravity. Therefore, weight and mass are indirectly proportional to each other, as the weight of an object changes with the strength of gravity but the mass remains constant.
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Marking brailiest: Two Speed and velocity questions below
A car travels a distance of 100 km in 2 hours. What is the average speed of the car (km/h)?
An NFL wide receiver prospect runs 40 m in 4.5 seconds. What is the average speed of the wide receiver (m/s)?
Answer:
1) 50 km/h
2)80/9 m/s
Explanation:
Speed = Distance / time
Why must 0s always be clearly marked on a motion map?
Answer:
A motion map can represent the position, velocity, and acceleration of an object at various clock readings. ... The corresponding motion map has the points spaced farther apart (because the car would go a further distance in each second), and the velocity vectors (arrows) are longer, because the car is moving faster.
Explanation:
1. Which object is farthest from the origin at t=2sec
A.a B. b
C. they are the same location at t=2sec
D. they are the same distance from the origin , but in opposite direction
2. Which object moves with constant non-zero acceleration
A. A C. both a and b
B. B. D. neither A and B
3. Which object is in its initial position at t=2sec?
A. A C. both a and b
B. B D. neither A and B
Help me ppppppppp
Answer:
that one i know only pe not that sorry again
A plane wave has equation; y= 25sin(120 _4x).find the: (1)wave length (2)wave velocity (3)frequency and period of the wave
(1) The wavelength of the wave is 1.57 m.
(2) The velocity of the wave is 30 m/s .
(3) The frequency of the wave is 19.10 Hz and the time period of the wave is 0.052 s.
Note: The given equation seems to be incomplete. Most probably the equation was y=25sin(120t-4x). And the standard system of units (i.e. kg, m, s) is used.
Wavelength: The distance between the consecutive crest or trough of a wave is called the wavelength of a wave.
The equation of a plane wave oscillating in the y direction and traveling in the x direction is given by the equation,
y=A sin(ωt-kx)
where y is the displacement along the y direction, A is the amplitude of the wave, ω is the angular frequency, t is the time, x is the displacement along the x direction, and k is the wave constant.
The given equation is,
y=25sin(120t-4x)
Comparing this equation with the above equation, following values are obtained.
k= 4 m^(-1)
ω =120 rad/s
A=25
The wavelength λ is given by the formula,
λ=2π/k
Here k = 4 m^(-1), so
λ=2π/4
λ=1.57 m.
Velocity: The velocity of a wave is the product of the frequency and the wavelength.
The velocity v is given by the formula,
v=ω*λ/2π
Here ω=120 rad/s and λ=1.57 m, so
v=120*1.57/2π
v=30 m/s
Frequency: The number of oscillations completed in one second is called the frequency of a wave.
The formula of the frequency is,
f=v/λ
Here v=30 m/s and λ=1.57 m, so
f=30/1.57
f=19.10 Hz
Time period: The time taken to complete one cycle of oscillation is called the time period of oscillation.
The formula to calculate the time period T is,
T=2π/ω
Here ω=120 rad/s, so
T=2π/120
T=0.052 s.
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Explain the importance of having a support network when trying to achieve a healthy lifestyle. Who supports you when it comes to making healthy nutrition and exercise choices? Do you have a role model you look up to when it comes to fitness? What do you have to do in order to become a role model for your community members?
(essay)
Answer:
Who are the people for you then I can help you format the essay
Explanation:
Lily whose mass is 45 kg is ice skating with a constant speed of 7 m/s when she hits the room at speed 8
It will take 8.9 seconds before Lilly coasts to a stop.
What is the friction coefficient telling us?A measure of the degree of friction between two surfaces is the coefficient of friction. A coefficient of friction is determined by calculating the resistance to motion at the intersection of two surfaces made of the same or different materials.
In the question we are given,
Mass, m = 45 kg
initial speed, u = 7 m/s
final speed, v = 0
coefficient of friction, μ = 0.08
Now, friction force can be calculated by
F = Normal force × μ
F = mg×μ
F = 45×9.8×0.08
F = 35.2 N
since the net force is the frictional force we can calculate the deceleration,
F = ma
35.2 = 45a
a = 35.2/45 = 0.78 m/s²
by applying equation of motion,
v = u + at
0 = 7 - 0.78t
7 = 0.78t
t = 8.9 s
It will take 8.9 seconds before Lilly coasts to a stop.
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The complete question is;
Lilly, whos mass is 45.0 kg, is ice skating with a constant speed of 7.00 m/s when she hits a rough patch of ice with a coefficient of friction of 0.0800. How long will it take before Lilly coasts to a stop?
what material of mass 39g,has a volume of 5cm^3
a car rounds a curve at a steady 50 km/h. if it rounds the same curve at a steady 70 km/h, will its acceleration be any different? explain.
Answer:
Acceleration would be \(1.96\) times the initial value.
Explanation:
The vehicle is in a centripetal motion as it rounds the circular curve. Acceleration of the vehicle during the motion would be:
\(\displaystyle a = \frac{v^{2}}{r}\),
Where:
\(v\) is the speed of the vehicle, and\(r\) is the radius of the curve.In this question, \(r\) stays the same since the vehicle is rounding the same curve. Acceleration of the vehicle would be proportional to the square of velocity.
The new velocity of the vehicle is \((70 / 50)\) times the original one. Hence, the new acceleration would be \((70 / 50)^{2} = 1.96\) times the original value.
A ball is thrown directly upward with an initial speed of 72 m/s. How much time passes before the ball reaches the highest point it will ever reach
Answer:
7.35 seconds
Explanation:
The computation of the time passed prior to the ball reached to the highest point is as follows;
As we know that the acceleration because of gravity on earth is 9.8 m/s
As the ball is thrown directly in an upward direction with a speed of 72 m/s
So, the time passed prior to the ball reached to the highest point is
= 72 ÷ 9.8
= 7.35 seconds
Hence, the above represents the answer