A sample of gas had a volume of 20.0 liters at 00C and 1520 torr. What would be the volume of this gas sample at 00C and 760 torr?

Answer:

The answer is a

Answer:

ΔEN CO   = 1.0

Explanation:

To calculate the electronegativity difference, we have to substract the element which has the highest EN to the other, that has a low value.

For this case EN from O - EN from C

Electronegativity is a property of the periodic table that increases diagonally, where Fr and Rb are the elements of less EN while F is the most electronegative element, with a value of 4. This is because F is an element with a high ionization energy and a negative electronic affinity.

ΔEN CO  = 3.5 - 2.5 = 1.0

Electronegativity (EN) describes the ability of an atom to compete for

electrons with other atoms to which it is attached.

Answer:

The action is acceleration and the reaction is friction

We would expect to measure a pressure of approximately 75.25 kPa for the gas in the container at the higher temperature of 267 oC.

To determine the expected pressure of the gas in the container at the higher temperature, we can use the combined gas law, which relates the initial and final conditions of temperature and pressure in a fixed volume system. The combined gas law equation is given as:

(P1 * V1) / T1 = (P2 * V2) / T2

Where:

P1 = Initial pressure

V1 = Initial volume (which is fixed in this case)

T1 = Initial temperature

P2 = Final pressure (to be determined)

V2 = Final volume (which is fixed in this case)

T2 = Final temperature

In this scenario, the initial conditions are given as 3 oC (which is equivalent to 276 K) and 38.5 kPa. The final temperature is 267 oC (which is equivalent to 540 K). Since the volume is fixed, we can substitute the given values into the equation:

(38.5 kPa * V1) / 276 K = (P2 * V1) / 540 K

Simplifying the equation, we can cancel out V1:

38.5 / 276 = P2 / 540

Solving for P2:

P2 = (38.5 / 276) * 540 ≈ 75.25 kPa

Therefore, we would expect to measure a pressure of approximately 75.25 kPa for the gas in the container at the higher temperature of 267 oC.

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Answer: Formula:

pH=−log[H

+

]

when pH=4

[H

+

]=10

−pH

=10

−4

when pH=2

[H

+

]=10

−pH

=10

−2

Answer:K2X

Explanation: Valency can be defined as the combining power of an element. It is the valency that dictates the value an element will have when writing a chemical formula for its compound.

MgX is a compound of magnesium and an element X. The valency of magnesium in most of its compound is +2. Now for the 2 to have been absent in the chemical formula, this shows that the element X itself have a valency if -2 for the valencies of both to have canceled out.

Now considering the element potassium, it is an alkaline metal belonging to group 1 of the periodic table. Hence, it is expected that it has a valency of +1

Forming a compound with element X means there would be an exchange of valencies between the two. We have established that x has a valency of -2. The formula of the compound thus formed by exchanging the valencies of both element would be K2X

The chemical formula for the compound formed between Lithium and element X is Li₂X.

Valency can be described as the combining power of a chemical element. It is the valency that describes the value an element will have in the chemical formula for that compound.

MgX compound is a compound of magnesium and an element X. The valency of magnesium is +2.  The chemical formula shows that the element X itself has a valency of -2 which gave a neutral compound.

Now given element is Lithium, it is an alkali metal of group 1 of the periodic table. It has a valency of +1 as it has one electron in its valence shell.

Forming a compound with element X, there will be an exchange of valencies between the two. As element X has a valency of -2. The formula of the formed compound by exchanging the valencies of Lithium and element X would be Li₂X

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There are 2.64 × 1022 molecules of sucrose present in this serving of fruit dessert containing 15.0 g of sugar.

To determine the number of molecules of sugar present in the serving, we need to calculate the number of moles of sugar and then convert it to the number of molecules.

Given:

Mass of sugar (sucrose) = 15.0 g

Molar mass of sucrose (C12H22O11) = 342 g/mol

First, calculate the number of moles of sugar using the formula:

Number of moles = Mass of substance / Molar mass

Number of moles of sugar = 15.0 g / 342 g/mol ≈ 0.0439 mol

Next, we use Avogadro's number, which states that there are approximately 6.022 × 10^23 molecules in one mole of a substance. Therefore, to find the number of molecules of sugar:

Number of molecules = Number of moles × Avogadro's number

Number of molecules of sugar = 0.0439 mol × 6.022 × 10^23 molecules/mol ≈ 2.64 × 10^22 molecules

Therefore, there are approximately 2.64 × 10^22 molecules of sugar present in this serving.

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Answer:

cool

Explanation:

Answer:

Language

Explanation:

this is very obvious not to be mean

Answer:

The correct answer is - ascending order of atomic numbers in period and similar characters in groups.

Explanation:

The modern periodic table is arranged in periods and groups. In periods the arrangement of the elements are on the basis of the increasing order of atomic numbers.

In groups of the periodic table, elements are arranged on the basis of the similar characters of the elements and number of electrons in outer shell of the elements. The elements in the Modern Periodic Table are arranged in 7 Periods and 18 Groups.

Thus, the correct answer is - ascending order of atomic numbers in period and similar characters in groups.

Answer:

Assuming that the addition of 5.00 mL of 0.011 M HCl to 50.00 mL of pure water does not significantly affect the volume of the solution:

Calculate the number of moles of HCl added:

moles HCl = concentration x volume = 0.011 mol/L x 0.00500 L = 5.50 x 10^-5 mol

Calculate the total volume of the solution:

total volume = 50.00 mL + 5.00 mL = 55.00 mL = 0.055 L

Calculate the concentration of H+ ions in the solution:

[H+] = moles HCl / total volume = 5.50 x 10^-5 mol / 0.055 L = 1.00 x 10^-3 M

Calculate the pH of the solution:

pH = -log[H+] = -log(1.00 x 10^-3) = 3.00

Therefore, the pH of the solution is 3.00.

Explanation:

Answer:

\(\huge\boxed{\sf v = 0.004\ m\³}\)

Explanation:

Mass = m = 4 kg

Density of water = 1000 kg/m³ (Standard)

Volume = v = ?

Density = m/v

1000 = 4 / v

1000 × v = 4

v = 4/1000

v = 0.004 m³

\(\rule[225]{225}{2}\)

The value of ΔG at 25 °C for the given reaction is: ΔG = -370.4 kJ/mol + 0 = -370.4 kJ/mol So, the correct answer is -370.4 kJ/mol

To determine the value of ΔG (Gibbs free energy) at 25 °C for the given reaction:

25 (s, rhombic) + 3/2 \(O_2\)(g) → \(2SO_3\)(g)

We can use the equation:

ΔG = ΔG° + RT ln(Q)

where:

ΔG is the standard Gibbs free energy change

ΔG° is the standard Gibbs free energy change under standard conditions

R is the gas constant (8.314 J/(mol·K) or 0.008314 kJ/(mol·K))

T is the temperature in Kelvin (25 °C = 298 K)

Q is the reaction quotient, which is the ratio of the concentrations of the products to the concentrations of the reactants at a given point during the reaction.

Given that ΔG° is -370.4 kJ/mol, we can plug the values into the equation:

ΔG = -370.4 kJ/mol + (0.008314 kJ/(mol·K) * 298 K) * ln(Q)

Now, we need to determine the value of Q. Since all reactants and products are in their standard states, Q = 1, as their concentrations are taken to be 1.

ΔG = -370.4 kJ/mol + (0.008314 kJ/(mol·K) * 298 K) * ln(1)

Since ln(1) = 0, the term (0.008314 kJ/(mol·K) * 298 K) * ln(1) becomes 0.

Therefore, the value of ΔG at 25 °C for the given reaction is:

ΔG = -370.4 kJ/mol + 0 = -370.4 kJ/mol

So, the correct answer is -370.4 kJ/mol.

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Answer: The amount of heat absorbed for the reaction of 25 mL of 1.0 M H₂SO4 and 50 mL of 1.0 M NaOH, resulting in a temperature increase from 25°C to 33.9°C, is 10.14 kJ.

Explanation:

Answer:

i would say the first one!

The correct answer is: K3 = 1/K1 x 1/K2

The equilibrium expression for reaction 3 may be written using the equilibrium expressions for reactions 1 and 2 and the expression for K3.

First, we need to reverse the equation for reaction 1:

CH4(g) + H2O(g) ⇆ CO(g) + 3H2(g)

Next, we need to multiply the equation for reaction 2 by 3:

3CO2(g) + 3H2(g) ⇆ 3CO(g) + 3H2O(g)

Now we can add the two equations to obtain the equation for reaction 3:

CH4(g) + 2H2O(g) ⇆ CO2(g) + 4H2(g)

Just substituting the equilibrium equations for reactions 1 and 2 into the equation for reaction 3 will yield the equilibrium expression for reaction 3:

K3 = ([CO][H2]^4)/([CH4][H2O]^2[CO2])

Therefore, the correct answer is:

K3 = 1/K1 x 1/K2

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Answer:

Explanation:

I am almost sure that the products are identical.

Answer:

Increases

Explanation:

The gravitational potential energy of an object increases as you bring it higher with respect to the ground.

Gravitational potential energy depends on the mass, height and gravity between two bodies;

   Gravitational potential energy  = mgh

m is the mass

g is the height

h is the height

Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

Answer: 5,266

Explanation:

5,266

Answer:

Physical and chemical methods can be used to monitor the rate of a chemical reaction. Physical methods measure changes in properties like temperature, pressure, or volume. Chemical methods track reactant consumption or product formation using techniques like titration or spectrophotometry. The choice of method depends on the reaction being studied, and scientists use these methods to gain insight into reaction kinetics and optimize conditions for better efficiency and selectivity.

In this question, we have a reaction involving Iron (III) oxide and hydrogen gas, resulting in solid iron metal and liquid water, the properly balanced equation that will perfectly contain every element in this reaction will be:

Fe2O3 + 3 H2 -> 2 Fe + 3 H2O

The concept combined gas equation is used here to determine the final temperature of the gas. These laws relate one thermodynamic variable to another holding everything else constant.

The combination of Boyle's law, Charles's law and Gay - Lussac's law give rise to the combined gas law. The state of a gas is determined by the macroscopic and microscopic parameters like pressure, volume, temperature, etc.

The combined gas equation is:

P₁V₁ /T₁ = P₂V₂ /T₂

T₂ = P₂V₂T₁ / P₁V₁

T₁ = 45 + 273 = 318 K

T₂ = 49.5 × 6.50 × 318 / 89.5 × 3.5 = 326.62 K

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Answer:

Explanation:

ABC Powder: sprays a very fine chemical powder. This acts to blanket the fire and suffocate it. Class A, B, C fires

Carbon dioxide: extinguishes CO2. By doing so, it removes oxygen from the fire, effectively suffocating it of oxygen. Class B fires

Foam: spray a type of foam that expands when it hits the air and blankets the fire. This prevents the vapors from rising off the liquid to feed the fire, thus starving it of fuel. Class A and B

Water: releases microscopic water molecules that fight the fire on a variety of levels. the level of oxygen in the air is decreased, which helps to suffocate the fire. Class: most all

also, your fire classes:

Class A: freely burning, combustible solid materials such as wood or paper

Class B: flammable liquid or gas

Class C: energized electrical fire (energized electrical source serves as the ignitor of a class A or B fire – if electrical source is removed, it is no longer a class C fire)

Class D: metallic fire (titanium, zirconium, magnesium, sodium)

Class K: cooking fires – animal or vegetable oils or fats

The ammonia formation has been 1.125 mol/L.

Keq is defined as the ratio of the mathematical product of the equilibrium concentrations of the species on the right that is multiplied by the concentrations of the chemical products divided by the mathematical product of the equilibrium concentrations of the species on the left.

This is the reaction that makes ammonia from hydrogen and nitrogen. Only one product is produced in this reaction. This reaction is therefore known as a binding reaction. A small Keq Keq < 1 implies a large concentration of reactants at equilibrium. In this case, the reaction drives the formation of reactants. If Keq ≈ 1 it means that there is a significant amount of reactants and products in equilibrium.

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Keq is equal to the number 4.5

Answer:

The correct answer is - the number of moles of solute per liter of solution.

Explanation:

The molar concentration is also known as molarity which is the amount of concentration of a solute is in a chemical solution is the number of moles of solute per unit volume of solution. It is represented as M and can be calculated by:

M = n/v

Where n is the number of moles of the solute and,

v is the volume of solution (in liters normally)

It is worldwide used measurment for the concentration.

Hello, this is Bing. I can help you with your question. Based on the information I found on the web, **H2** can be broken down into its two atoms of hydrogen (H) by supplying enough energy to overcome the bond that holds them together⁴. This process is called **dissociation** and requires an energy equal to or greater than the **dissociation energy** of H2, which is about 436 kJ/mol⁴.

One way to break down H2 is by using **electricity** to split water (H2O) into hydrogen (H2) and oxygen (O2) through a process called **electrolysis**¹. In this process, water is decomposed into its elements by passing an electric current through it. The electric current is provided by a battery or another source of electricity and the water needs to have an **electrolyte**, such as salt or acid, added to it to make it conductive¹. Two electrodes, usually made of metal or other conductive material, are inserted into the water and connected to the battery. The electrode connected to the positive terminal of the battery is called the **anode** and the one connected to the negative terminal is called the **cathode**¹. When the electric current flows through the water, hydrogen gas bubbles form at the cathode and oxygen gas bubbles form at the anode¹. The overall chemical reaction for electrolysis of water is:

2 H2O → 2 H2 + O2

Another way to break down H2 is by using **heat** to cause a reaction between hydrogen and oxygen that produces water and releases a large amount of energy. This reaction is called **combustion** or **oxidation** and can be ignited by a spark or a flame³. The reaction is very fast and explosive and can be dangerous if not controlled. The overall chemical reaction for combustion of hydrogen is:

2 H2 + O2 → 2 H2O

I hope this helps you understand how H2 can be broken down and what methods are used to do so.

Answer: 55.5 oC is 0.014 atm (3rd decimal point)

Explanation:

The Clausius-Clapeyron equation is given as:

ln(P2/P1) = -(ΔH_vap/R) * (1/T2 - 1/T1)

where:

P1 = vapor pressure at temperature T1

P2 = vapor pressure at temperature T2

ΔH_vap = enthalpy of vaporization

R = gas constant = 8.314 J/(mol*K)

Converting the enthalpy of vaporization to J/mol:

ΔH_vap = 35.2 kJ/mol = 35,200 J/mol

Converting temperatures to Kelvin:

T1 = 64.7 + 273.15 = 337.85 K

T2 = 55.5 + 273.15 = 328.65 K

Substituting the values into the equation and solving for P2:

ln(P2/1 atm) = -(35,200 J/mol / 8.314 J/(mol*K)) * (1/328.65 K - 1/337.85 K)

ln(P2/1 atm) = -4.231

P2/1 atm = e^(-4.231)

P2 = 0.014 atm

Therefore, the vapor pressure for methanol at 55.5 oC is 0.014 atm, to the third decimal point.