a sample of gas at a pressure of 5.1 atm and a temperature of 45 degrees celsius is heated. it’s pressure goes to 7.8 atm what is it’s new temperature in celsius

answer:

in heat transfer, as the fluid flows along the tube, the wall layers are heated or cooled. temp. variation occurs in the wall layers.

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hopefully, this helps

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Based on the given isotopic composition, the relative contribution of C3 plants is higher compared to C4 plants in the soil organic matter of Kenya.

To determine the relative contribution of C3 and C4 plants to the soil organic matter in Kenya based on their stable carbon isotopic composition, we can use the concept of isotopic discrimination.

C3 and C4 plants have different photosynthetic pathways, and they exhibit distinct carbon isotope signatures. C3 plants typically have a more negative δ13C value (around -30 permil to -22 permil), while C4 plants have a less negative δ13C value (around -16 permil to -9 permil).

In this case, the soil organic matter in Kenya has a δ13C value of -18 permil, while the air δ13C value is -7 permil. The difference between these values (-18 permil - (-7 permil)) gives us the isotopic discrimination between the atmosphere and the soil organic matter.

δ13C discrimination = δ13C organic matter - δ13C atmosphere

δ13C discrimination = -18 permil - (-7 permil)

δ13C discrimination = -11 permil

Since the δ13C discrimination is negative, it suggests that C3 plants have a dominant contribution to the soil organic matter. C4 plants, with their less negative δ13C values, are less likely to contribute significantly to the organic matter in this case.

Therefore, based on the given isotopic composition, the relative contribution of C3 plants is higher compared to C4 plants in the soil organic matter of Kenya.

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Answer:

b

Explanationbecause i took the test and got a 100

Answer:

pH is the number given to a substance of how powerful it is before 7 or beyond 7.

the solution is an acid.

Explanation:

Pls mark BRAINLIEST

Answer:

August 15, 1971

The nine sheikhdoms still had not agreed on terms of union by 1971, however, prompting Bahrain to declare itself fully independent on August 15, 197

1.A solution has a pH of 5, calculate the pOH, [H+], and [OH-]. Classify the solution as an acid, base, or neutral solution.

it's an acid

Explanation:

I hope that this helps

Answer:

36 atoms

Explanation:

The equation for the reaction is given below:

C6H12O6 + 6O2 —> 6CO2 + 6H2O

From the reaction above, the reactants include:

C6H12O6 and 6O2.

Thus, the total atom present in the reactants can be obtained as follow:

Element >>>>>>>> Atom present

Carbon (C) >>>>>> 6

Hydrogen (H) >>>> 12

Oxygen (O) >>>>>> 18

TOTAL >>>>>>>>>> 36

From the above illustration, 36 atoms are represented in the reactants.

The correct option for the given question is B) 2-decyne. HgSO₄ acid-catalyzed hydration of 2-decyne gives a single ketone in the reaction. Alkynes can undergo hydration in the presence of acid catalysts to produce ketones or aldehydes as the product. The reaction between alkynes and water is an addition reaction. The reaction of hydration proceeds in two steps:

The pi bond of the triple bond attacks the proton of the acid to form a carbocation intermediate. Step 2: The intermediate carbocation reacts with water to form the ketone or aldehyde.

The reaction mechanism of the HgSO₄ acid-catalyzed hydration of 2-decyne is given below:

Figure: Reaction mechanism of the HgSO₄ acid-catalyzed hydration of 2-decyne

The reaction mechanism shows that the protonation of the triple bond of 2-decyne forms a carbocation intermediate. The intermediate then reacts with water to produce the single ketone product.

Thus, the correct option for the given question is B) 2-decyne.

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The correct answer is option C, 3-decyne, which gives a single ketone in the HgSO4 acid-catalyzed hydration reaction.

Here's the balanced chemical equation for the hydration reaction:

\(CH_3(CH_2)_6C\equiv CCH_2(CH_2)_2CH_3 + H_2O + HgSO_4 \rightarrow CH_3(CH_2)_6C(O)CH_2(CH_2)_2CH_3 + HgSO_4\)

The reaction mechanism involves the following steps:

Step 1: Protonation of the triple bond

Step 2: Addition of H2O molecule to form a vinyl alcohol intermediate

Step 3: Tautomerization of vinyl alcohol to form a ketone intermediate

Step 4: Deprotonation of the ketone intermediate to yield the final product, a single ketone.

In the HgSO4-acid-catalyzed hydration of each of the alkynes, 2-decyne, 4-decyne, and 5-decyne gives two ketones each. This is because of the presence of two terminal alkyne groups that react with water to form two carbonyl groups.

However, 3-decyne has only one terminal alkyne group that can react with water to form a single carbonyl group. Therefore, 3-decyne gives a single ketone in the HgSO4 acid-catalyzed hydration reaction.

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Significantly, pH 7 is the neutral pH, which is also the pH of pure water.Pure water has a pH of 6.14 at 100°C, which is considered "neutral" at this high temp on the pH scale.

The pH scale determines how acidic or basic water is.The range is 0 to 14, and 7 representing neutrality.Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7.

The pH value of pure water is 7 at room temp (25 °C).The purity of water is 6.14 at a temperature of 100 degrees Celsius, which is lower than 7, but remains neutral just on pH scale.

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The type of polymerization that occurs to form polyethylene (paperclip model) is called addition polymerization. This process involves the repeated addition of monomers, in this case, ethylene molecules, to form long chains of polyethylene.

The paperclip model is a visual representation of the repeating units in the polymer chain, with each paperclip representing a monomer unit. Initiation: A catalyst is used to initiate the reaction by creating a reactive site on the ethylene monomer.
Propagation: The reactive site on the first ethylene monomer reacts with the double bond of another ethylene monomer, forming a single bond between them and creating a new reactive site on the second monomer. This process continues as more ethylene monomers join the chain.
Termination: The polymer chain eventually terminates when two reactive sites meet or when the reactive site reacts with another molecule, such as a chain transfer agent.

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Explanation:

Balance the following equation: C3H8 + O2 ----> CO2 + H2O. (There will be no need for state symbols.) First of all, to balance these equations, list the number of each atom, for both sides of the equation. In this example, it would be: The first step would be to balance out the carbons on the products side by multiplying CO2 by 3.  The balanced chemical equation for C3H8 +O2 = CO2 + H2O is C3H8 +5O2 = 3CO2 +4H2O. This is the chemical reaction in which C3H8 or propane burns in air or oxygen to produce carbon dioxide and water.

Answer:

The Ice is Less Dense than the Water

Explanation:

I just answered this one myself, and the explanation is also just that Ice isn't dense enough to sink.

His distance and displacement are the same, which was 400 m

Given

Distance = 400 m

time = 2 min

Required

Distance and displacement

Solution

Distance is a scalar quantity that indicates the length of the trajectory that is traveled by an object within a certain interval. Distance has no direction, only has magnitude  

Can be simplified distance = totals traveled  

Displacement is a vector quantity that shows changes in the position of objects in a certain interval of time. Displacement has magnitude and direction  

Can be simplified displacement = distanced traveled from starting point to ending point  

From the definition above shows that the displacement and the distance that he traveled have the same value (magnitude), which is equal to 400 m

The value of the two will be different if he starts and finishes at the same point, then the displacement value is zero while the distance he has traveled is still 0

The pH of the buffered solution is 4.87.

The pH of a buffered solution can be calculated using the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

where pKa is the negative logarithm of the acid dissociation constant (Ka) for the weak acid, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the weak acid.

In this case, benzoic acid (HA) is the weak acid, and potassium benzoate (A-) is its conjugate base.

The pKa for benzoic acid is given as 6.28 x 10^-5.

The concentration of benzoic acid ([HA]) is 0.55 M, and the concentration of potassium benzoate ([A-]) is 0.60 M.

So, plugging these values into the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

pH = 6.28 x 10^-5 + log(0.60/0.55)

pH = 4.87

Therefore, the pH of the buffered solution is 4.87.

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Answer: B: a solvent

Explanation: I hope this helps!

Answer:

426 mg = 4.26 x 10² mg

Explanation:

1 cup = 237.6 mL x 1 L/1000 mL = 0.2376 L

We divide the liters of milk the student drinks into the volume in liters of a cup to calculate the number of cups the student drinks per day:

number of cups per day = 0.318 L/0.2376 L = 1.34 cup

Now, we multiply the number of cups by the amount of calcium that a cup of milk has:

amount of calcium = 1.34 cup x 318 mg = 426 mg = 4.26 x 10² mg

Therefore, the student gets 426 mg (or 4.26 x 10² mg) of calcium in one day.

Answer:

Mercury is released into the environment from many sources. Mercury becomes airborne when rocks erode, volcanoes erupt and soil decomposes. It then circulates in the atmosphere and is redistributed throughout the environment.

I think this is right.

Answer:

1.T

2.I

Explanation:

hope it help

#carry on learning

The object and description that matches is Object 2 and T.

Object 1 has no matching description.

A Fish aquarium filter is a filter whose function is to clean the water of debris, removes the toxic buildup of ammonia and nitrates, and aerates the water so that fish can in a conducive environment and breathe properly

An engine oil filter is a filter whose function is to filter and remove contaminants that may be present in the engine oil, transmission oil, lubricating oil, or hydraulic oil in order for proper functioning of the engine.

Therefore, the object and description that matches is Object 2 and T.

Object 1 has no matching description.

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Considering the two acids and bases involved, the reverse reaction is favored.

The term reversible reaction refers to a reaction that can go either forward or backwards depending on the conditions of the reaction.

We must recall that acetic acid is a weak acid hence the equilibrium position would always lie towards the left hand side of the equation. Hence considering the two acids and bases involved, the reverse reaction is favored.

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Answer:

Answer

battery

Explanation:

Explanation

Answer:

2,1,2

Explanation:

4Na=2(Na2So4)

4HCl= 2(H2O)

Right side 8 O so 1(O2)

The average atomic mass of the Mc in the sample, given the that the hypothetical mass spectrum of Mc, is 289.1 amu

First, we shall determine the atomic mass of each isotope as shown from the spectrum. Details below:

For 1st isotope

Atomic mass of 1st isotope = (Number of atom /total atom) × atomic mass

Atomic mass of 1st isotope = (3 / 10) × 288.2

Atomic mass of 1st isotope = 86.46 amu

For 2nd isotope

Atomic mass of 2nd isotope = (Number of atom /total atom) × atomic mass

Atomic mass of 2nd isotope = (5 / 10) × 289.2

Atomic mass of 2nd isotope = 144.6 amu

For 3rd isotope

Atomic mass of 3rd isotope = (Number of atom /total atom) × atomic mass

Atomic mass of 3rd isotope = (2 / 10) × 290.2

Atomic mass of 3rd isotope = 58.04 amu

Finally, we shall determine the average atomic mass of Mc. Details below:

Average atomic mass of Mc = sum atomic masses of isotopes

Average atomic mass of Mc = 86.46 + 144.6 + 58.04

Average atomic mass of Mc = 289.1 amu

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The condensed ground-state electron configuration of the transition metal ion \(Mn^{2+}\) is [Ar] \(3d^{5}\)

The electronic configuration of an element is the symbolic notation of the manner in which the electrons of its atoms are distributed in the periodic table over different atomic orbitals. While writing electron configurations, standardized rules are followed in which the energy level and the type of orbital are generally written first, followed by the number of electrons present in the orbital which is written in superscript.

In case of Manganese atomic number of the atom is 25. When we follow Aufbau principle the electronic configuration is \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{5}\) if we have to write it in a compact form we can write as [Ar]\(3d^{5}4s^{2}\). In case of \(Mn^{2+}\) we have to remove electron from the higher most orbital that is 4s so now the electronic configuration will be become [Ar]\(3d^{5}\).

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Answer:

20

Explanation:

owls are 10 of anything 10x 2 =20

It seems as though the value of the owl is up to you though

Hopes this helps

Answer:

N2O3= Dinitride Trioxide

CO= Carbon Oxide

SO3= Sulfide Trioxide

Explanation:

Di= 2

Tri= 3

Br is most reactive element than S, Ar, Te

Reactivity means is the impulse for which a chemical substances undergoes a chemical reaction either by itself or with other material with an  overall release of energy called as reactivity and here S, Ar, Br Te  the bromine is the most reactive element because bromine is the intermediate in reactivity between chlorine and iodine and also the one of the most reactive element and here given option is sulphur, argon and tellurium are the unreactive element that's why the bromine is halogen element and among this bromine is most reactive

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Answer:

Student B because it can be done in natural settings​

Explanation:

The molar concentration of a 12% sodium chloride solution is approximately 2.05 M.

To determine the molar concentration of a 12% sodium chloride solution, we need to convert the given percentage concentration into molarity.

First, we need to understand that the percentage concentration refers to the mass of the solute (sodium chloride) relative to the total mass of the solution.

In this case, a 12% sodium chloride solution means that there are 12 grams of sodium chloride in 100 grams of the solution.

To convert this into molar concentration, we need to consider the molar mass of sodium chloride, which is 58.5 g/mol.

We can start by calculating the number of moles of sodium chloride in 12 grams:

Moles of sodium chloride = mass of sodium chloride / molar mass of sodium chloride

Moles of sodium chloride = 12 g / 58.5 g/mol = 0.205 moles

Next, we calculate the volume of the solution in liters using the density of the solution. Since the density is not provided, we assume a density of 1 g/mL for simplicity:

Volume of solution = mass of solution / density

Volume of solution = 100 g / 1 g/mL = 100 mL = 0.1 L

Finally, we calculate the molar concentration (Molarity) by dividing the number of moles by the volume in liters:

Molar concentration = moles of solute / volume of solution

Molar concentration = 0.205 moles / 0.1 L = 2.05 M

Therefore, the molar concentration of a 12% sodium chloride solution is approximately 2.05 M.


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Assuming complete combustion, the stated statement indicates that 24 g of methane were consumed.

In the chemical process of burning, an item swiftly combines with oxygen to produce heat. The initial substance and the supply of oxygen are referred to as fuel and oxidizer, respectively. Despite typically being a liquid, fuel for airplane propulsion can also occasionally be a solid, liquid, or gas.

Briefing:

CH4 + 2O₂——————-> CO₂ + 2H₂O

1 mole of methane, or 16 g, will yield =2 x 18 = 36 g of water.

Thus, = 16/36 x 54 = 24 g of methane will be converted into 54 g of water.

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Extensive property is dependent on mass. Intensive property is property that depends only on the type of matter rather than the amount. Hense, Volume is an example of Extensive property and Density is an example of Intensive property.

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The number of mole present in 87 grams of potassium bromide, KBr is 0.731 mole

We'll begin our calculation by obtaining the molar mass of potassium bromide, KBr. Details below:

Molar mass of potassium bromide, KBr = K + Br

Molar mass of potassium bromide, KBr = 39 + 80

Molar mass of potassium bromide, KBr = 119 g/ mol

Finally, we shall determine the number of mole present. Details below:

Mole = mass / molar mass

Mole of potassium bromide, KBr = 87/ 119

Mole of potassium bromide, KBr = 0.731 mole

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Complete question:

How many moles are in 87g of potassium bromide?

The notation for the enthalpy of the solution is ∆Hsol. The correct answer is option ∆Hsol.

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