A sample is prepared by completely dissolving 10.0 grams of nacl in 1.0 liter of h2o. which classification best describes this sample?
(1) homogeneous compound
(2) homogeneous mixture
(3) heterogeneous compound
(4) heterogeneous mixture

The total volume of gas produced by the complete decomposition of 1.44 kg k g of ammonium nitrate is 33.5 L.

The decomposition reaction of ammonium nitrate is given by:

NH4NO3(s) → N2(g) + 2H2O(g)

From the balanced chemical equation, we can see that 1 mole of ammonium nitrate produces 1 mole of nitrogen gas and 2 moles of water vapor. The molar mass of NH4NO3 is 80.04 g/mol, so 1.44 kg of NH4NO3 is equal to 18 moles.

To find the volume of gas produced, we can use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin:

T = 127°C + 273.15 = 400.15 K

Next, we need to convert the pressure from mmHg to atm:

747 mmHg / 760 mmHg/atm = 0.981 atm

Now we can plug in the values and solve for V:

V = nRT/P = (1 mole N2)(0.08206 L·atm/mol·K)(400.15 K)/0.981 atm

= 33.5 L

Therefore, the total volume of gas produced by the complete decomposition of 1.44 kg of ammonium nitrate at 127°C and 747 mmHg is 33.5 L.

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The total volume of gas produced by the complete decomposition of 1.44 kg of ammonium nitrate at 127°C and 747 mmHg is 960.4 L.

Explanation: To solve this problem, we need to use the ideal gas law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. We can first find the number of moles of gas produced by calculating the amount of ammonium nitrate in moles (1.44 kg divided by the molar mass of NH4NO3), then multiplying by the stoichiometric ratio of gas produced per mole of ammonium nitrate (2 moles of gas per mole of NH4NO3).

Next, we can use the given temperature and pressure to convert the number of moles of gas into volume using the ideal gas law. It's important to note that the given temperature is in Celsius, so we need to convert it to Kelvin by adding 273.15. After plugging in the values and solving for V, we get a total volume of 960.4 L.

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Answer:

WYZX

Explanation:

The distance b/w the x-axis and peaks of the wave denote the amplitude

The waves in order with largest amplitude are given in order as W,Y,Z,X where W has largest amplitude.

Amplitude, in physics, the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.

The amplitude of a pendulum is thus one-half the distance that the bob traverses in moving from one side to the other. Waves are generated by vibrating sources, their amplitude being proportional to the amplitude of the source.

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Answer:

Answer is iven below.

Explanation:

Part c:

.The sampling wasn't done at steady state that the balances need so any accumulation terms zero.

.The volumes of ethyl alcohol and water aren't additive in a very mixture this may cause improve measurements

.Using average density of fermentation alcohol and water in conversions doesn't account for the actual fact that the majority if not all streams don't have an excellent 50:50composition quantitative relation of fermentation alcohol and water

.Effects of temperature ,pressure, and density were treated as negligible.

.The calibration curve used could be an inaccurate reading of the manometer.

(A) Finding the amount of CuSO4.5H2O dissolved in the specified volume of solution is necessary to determine the concentration of the solution.

Given:

Bluestone (CuSO4.5H2O) mass is 12.48 g.

200 mL is the solution's volume.

Moles per litre, or concentration, is a common unit of measurement. The volume must be changed to litres:

200 mL of solution is equivalent to 200/1000, or 0.2 L.

We divide the number of moles of solute by the litres of solution to obtain the concentration (C):

Molar mass of CuSO4.5H2O is equal to the mass of CuSO4.5H2O.

The formula below can be used to determine the molar mass of CuSO4.5H2O:

Cu's atomic mass is 63.55 g/mol.

S has an atomic mass of 32.07 g/mol.

O has an atomic mass of 16.00 g/mol.

H has an atomic mass of 1.01 g/mol.

CuSO4.5H2O's molar mass is equal to 249.70 g/mol (63.55 + 32.07 + (4 * 16.00) + (5 * (2 * 1.01)) g/mol.

CuSO4.5H2O moles are equal to 12.48 g and 249.70 g/mol.

We can now determine the concentration:

C = Molecular weight of CuSO4.5H2O / litres of solution

Moles of CuSO4.5H2O = 12.48 g / 249.70 g/mol

(B) The concentration of the 100 mL sample, if the student takes 100 mL of the solution, would be determined using the same formula as in part (A), but using the new volume of the sample (0.1 L) rather than 0.2 L.

(C) CuSO4 would be the only residue left after heating the 100 mL sample vigorously to completely evaporate the water. We must use stoichiometry and the molar mass of CuSO4 (minus the water molecules) to get the mass of the residue.

The following formula can be used to determine the molar mass of CuSO4: Molar mass of CuSO4 = 63.55 + 32.07 + (4 * 16.00) = 159.61 g/mol

Stoichiometry enables us to determine that 1 mole of CuSO4.5H2O yields 1 mole of CuSO4. As a result, the moles of CuSO4 and CuSO4.5H2O would be equal.

To determine the residue's mass:

CuSO4 residue mass equals moles of CuSO4.5H2O times the molar mass of CuSO4.

Please let me know the options for parts (B) and (C) so I can assist you.

Answer:

Explanation:

Explanation:

it's a decimal form not scientific notation

50÷20= 2.5

please mark me BRAINLIEST

Answer:since,there is a single bond between the two carbon atoms and both share their one atom therefore for completing its shell it need to combine with three atoms of carbon or other element . therefore it cannot be linked to more than 3 covalent bonds since its shell will be completed to become stable .

Explanation:

To draw the Lewis structure for sulfate (SO₄²⁻) with minimized formal charges and determine the total likely resonance structures, follow these steps:

1. Identify the central atom: Sulfur (S) is the central atom in the sulfate ion.
2. Count the total number of valence electrons: Sulfur has 6, each oxygen has 6, and there are 2 extra electrons due to the 2- charge. So, the total number of valence electrons is 6 + 4(6) + 2 = 32.
3. Connect the central atom to the surrounding atoms with single bonds: Connect the sulfur atom to each of the four oxygen atoms using single bonds. This uses up 8 valence electrons (2 for each bond).
4. Distribute the remaining valence electrons to complete the octets of the surrounding atoms: 32 - 8 = 24 valence electrons are left. Distribute them to the four oxygen atoms to complete their octets (6 electrons for each oxygen atom).
5. Check for the need for multiple bonds to satisfy the octet rule for the central atom: Sulfur has 8 electrons around it (1 from each single bond), so the octet rule is satisfied.

Now, the Lewis structure is complete with minimized formal charges. However, there are multiple resonance structures for SO₄²⁻. Since sulfur can form double bonds with any of the four oxygen atoms, there are a total of 4 likely resonance structures for SO₄²⁻, with one double bond in each resonance structure and the remaining oxygen atoms having single bonds.

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Answer:

Each molecule of liquid water is involved in approximately four hydrogen bonds with strengths significantly lower than covalent bonds but significantly greater than natural thermal energy. ... Even a very small reinforcement of hydrogen bonds can have a major impact on normal metabolism.

Explanation:

On completing and balancing the half-reaction of chromium (iii) forming from dichromate the number of electrons are either produced or consumed  are option (b): Three electrons are produced.

To determine the number of electrons produced or consumed in the half-reaction of chromium(III) forming from dichromate, let's first write the balanced half-reaction. The dichromate ion (Cr2O7^2-) is reduced to chromium(III) ion (Cr^3+) in this reaction. We can represent the reduction half-reaction as follows:

Cr2O7^2- ⟶ Cr^3+

To balance the half-reaction, we need to equalize the number of chromium atoms and oxygen atoms on both sides. Since there are two chromium atoms on the left side and only one on the right side, we add a coefficient of 2 in front of the chromium ion:

2Cr2O7^2- ⟶ 2Cr^3+

Now, let's examine the changes in oxidation state for chromium in this reaction. In dichromate (Cr2O7^2-), chromium has an oxidation state of +6, while in chromium(III) (Cr^3+), it has an oxidation state of +3. Therefore, the oxidation state of chromium decreases by 3 in this reduction half-reaction.

Reduction involves a gain of electrons. Since the oxidation state of chromium decreases by 3, it means that three electrons are gained by each chromium ion. Therefore, the correct answer is option (b): Three electrons are produced.

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Answer:

c. Six electrons are consumed

Explanation:

The first step is to ensure that the chromium atoms are balanced by adjusting the coefficients if needed. Do so by giving the Cr3+ ion a coefficient of 2.

Cr2O2−7 ⟶ 2Cr3+ (aq)

Next, balance the oxygen atoms by adding H2O molecules. The half-reaction has seven O atoms on the left and none on the right, so add 7H2O (l) to the right side.

Cr2O2−7 ⟶ 2Cr3+ (aq) + 7H2O (l)

Next, balance the hydrogen atoms by adding H+ ions. The half-reaction has 14 H atoms on the right side and none on the left, so add 14H+(aq) to the left side.

Cr2O2−7 + 14H+ (aq) ⟶ 2Cr3+ (aq) + 7H2O (l)

At this point, the charge can be balanced by adding electrons (e−). To do so, find the total charge on each side of the reaction. The left side has a total charge of (−2) + 14 × (+1) = 12+. The right side has a total charge of 2 × (+3) = 6+. Adding 6e− to the left side brings the charge down to 6+ to match the right side.

Cr2O2−7 + 14H+ (aq) +6e− ⟶ 2Cr3+ (aq) + 7H2O (l)

This gives us the answer to the question, which is that six electrons are consumed, since they are on the left side of the equation. Note that it does not make a difference whether the reaction is assumed to be in an acidic or a basic solution. The extra step taken for a basic solution is to add the same number of OH− ions to both sides of the reaction, which does not affect the number of electrons needed to balance the charges.

The standard entropy change for the reaction is ΔS° = -344.4 J/(K·mol).

The entropy change can be calculated using the formula ΔS° = ΣnS°(products) - ΣmS°(reactants), where n and m are the stoichiometric coefficients of the products and reactants, respectively.

From the table, the standard molar entropy of P4(g), O2(g), and P4O10(s) are 41.5 J/(K·mol), 205 J/(K·mol), and 110 J/(K·mol), respectively. Plugging in the values and taking into account the stoichiometric coefficients, we get ΔS° = (5 × 110 J/(K·mol)) + (1 × 41.5 J/(K·mol)) - (1 × 5 × 205 J/(K·mol)) = -344.4 J/(K·mol).

The negative value indicates a decrease in entropy as the reactants form the product, which is expected for a reaction that results in the formation of a solid compound.

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A molecule or subunit that functions alone or combines with other similar molecules to form a polymer. All of the biomolecules that make up our cells are made up of strings of monomers. For example, proteins are made up of strings of amino acids and nucleic acids are strings of nucleotides.

Answer:

the porson above me is right

The most abundant isotope here is 259Q.

We know that isotopes refers to those atoms of elements that have the same atomic number but different mass numbers. The reason for the difference in the mass number is because they do not have the same number of neutrons. Recall that the mass number is the sum of the number of protons and neutrons in the nucleus of an atom.

The existence of isotopy is the reason why the relative atomic masses of elements are not whole numbers.

Note that the isotopes are not abundant to the same extent. The isotopes that are are more abundant tend to affect the value of the relative atomic mass. The relative atomic mass is nearest in value to the mass of the most abundant individual isotope.

As such, the most abundant isotope here is 259Q.

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Answer:

B. 75.0 kPa

Explanation:

P1V1/T1=P2V2/T2

(x * 100 L)/(300 K)=(100 kPa * 50.0 L)/(200 K)

x=75.0 kPa

Answer:

24rq3r54

Explanation:

3t5q6tq6tq

Answer:

The same genes or slightly different versions of the same gene can be found on each chromosome in a pair. They form a line and split off bits of themselves, which they barter with one another. In sexual reproduction, crossing over is the first method that genes are shuffled to develop genetic variation.

Answer:

Ionization

Explanation:

Ionization is the physical process of converting an atom or molecule into an ion by adding or removing charged particles such as electrons or other ions.

The average daily output of sulfur dioxide (SO2) is approximately 12,118.56 kg.

The average daily output of sulfur dioxide (SO2) assuming that 5% of the sulfur content of the coal ends up in the ash (i.e. 5% of S is unreacted) and the rest is released in the stack gas can be calculated as follows: Given, Quantity of coal burned each day at the Iowa State University Power Plant = 250,000 kg Average sulfur content of the coal = 2.55%5% of the sulfur content ends up in the ash, and the rest is released in the stack gas. Hence, the percentage of sulfur that goes into the stack gas is 100% - 5% = 95%. Therefore, the daily amount of sulfur burned in coal = 250,000 kg x 2.55% = 6,375 kg, Amount of sulfur that goes into the ash = 5% x 6,375 kg = 318.75 kg, Amount of sulfur that goes into the stack gas = 95% x 6,375 kg = 6,056.25 kgThe molecular mass of SO2 = 64 g/mol. Hence, the molar mass of S = 32 g/mol.

The daily amount of sulfur dioxide produced from sulfur burned in the coal is equal to the amount of sulfur burned in the coal multiplied by the molar mass of sulfur dioxide i.e., 6,056.25 kg / 32 g/mol = 189,265 mol. The number of moles of sulfur dioxide can be converted to mass by multiplying it with the molar mass of sulfur dioxide i.e., 189,265 mol x 64 g/mol = 12,118,560 g = 12,118.56 kgTherefore, the average daily output of sulfur dioxide (SO2) is approximately 12,118.56 kg. When coal is burned, it emits various gases such as sulfur dioxide, nitrogen oxides, and carbon dioxide. Sulfur dioxide (SO2) is a gas that causes acid rain, which is detrimental to human health, plants, and animals, as well as buildings and monuments.

The average daily output of sulfur dioxide (SO2) is calculated to be approximately 12,118.56 kg. It is due to the 250,000 kg of coal that is burned every day at the Iowa State University Power Plant, which is a mixture of Kentucky, Illinois, and Colorado coal, with an average sulfur content of 2.55%. In addition, it is assumed that 5% of the sulfur content of the coal ends up in the ash, and the rest is released into the stack gas. As a result, 95% of sulfur in coal, i.e. 6,056.25 kg, is released into the stack gas, and 5% of sulfur in coal, i.e. 318.75 kg, ends up in the ash. Therefore, the average daily output of sulfur dioxide (SO2) is approximately 12,118.56 kg.

The burning of coal leads to the emission of various gases, including sulfur dioxide (SO2), which has detrimental effects on the environment, human health, and animals. The average daily output of sulfur dioxide (SO2) is determined based on the quantity of coal burned every day at the Iowa State University Power Plant, which is a mixture of Kentucky, Illinois, and Colorado coal with an average sulfur content of 2.55%, and the assumption that 5% of the sulfur content of the coal ends up in the ash, and the rest is released into the stack gas. The amount of sulfur dioxide produced as a result of burning coal can be reduced by employing methods such as coal washing and flue-gas desulfurization, which capture sulfur dioxide before it is released into the atmosphere.

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Answer:

Net force: 110 N

Resulting Force: 24.7289837 pounds-force

Explanation:

First you would add 30+60+20N which would be 110N

110N would equal to the 24.72898937 pounds of force.

The reaction with an energy term is H₂ (g) + F₂ (g) → 2HF (g) ΔH = - 542 kJ/mol.

Based on the change in enthalpy of chemical reactions there are two types of reactions namely exothermic and endothermic.

The exothermic reaction

The endothermic reaction

In the reaction, the energy is evolved for each mole H₂ that reacts. The reaction is an exothermic reaction and the enthalpy change is negative.

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Answer:

A

Explanation:

The bubbles formed from the plants are always oxygen. The photosynthetic reaction taking place in the plants release oxygen molecules.

Photosynthesis is the biochemical process of synthesizing chemical energy by green plants with the aid of light energy. They store this chemical energy in the form of glucose.

In photosynthetic reaction, water and carbon dioxide are combined to produce glucose and oxygen gas. The bubbles formed in the reaction is oxygen gas.

This process is an event in the carbon cycle to balance the amount of carbon dioxide in the atmosphere and in living matter. Photosynthesis provide the sufficient oxygen for respiration for animals. Hence, option A is correct.

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225

To calculate total pressure, simply sum the partial pressures of each gas.

Considering the definition of molar ratio, the mole ratio of acetic acid to water in 100 g of vinegar is 0.015 : 0.985.

A molar ratio is the ratio of the molar amounts of two compounds involved in a chemical reaction.

That is, in a chemical reaction, the molar ratio refers to the relationship between the number of moles of one substance and the number of moles of another. A chemical reaction can have one or more mole ratios, depending on how many chemicals are involved.

In this case you know that the percentage composition of acetic acid and water in vinegar is 5% acetic acid and 95% water. This means that in 100 g of vinegar, there are 5 g of acetic acid and 95 g of water.

On the other hand, the molar mass is the amount of mass that a substance contains in one mole. In  this case, you know:

Then, considering the mass of each compound in vinager and the definition of molar mass, the moles of each compound can be calculated as:

So, the total moles can be calculated as:

total moles = moles of vinegar + moles of water

total moles = 0.08 moles + 5.28 moles

total moles = 5.36 moles

Finally, the mole ratio of acetic acid to water in 100 g of vinegar can be calculated as:

Mole ratio of vinegar to water = 0.08÷5.36 : 5.28÷5.36

Solving:

Mole ratio of vinegar to water = 0.015 : 0.985

In summary, the mole ratio of acetic acid to water in 100 g of vinegar is 0.015 : 0.985.

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It is true that electromagnetic waves can travel in empty space or space that has no particles.

The correct option is True.

Waves of the electromagnetic field make up electromagnetic radiation; they travel through space while carrying momentum and radiant energy. It consists of X-rays, gamma rays, microwaves, infrared, light, and radio waves.

Electromagnetic waves include radio waves, television waves, and microwaves. The only thing separating them is the wavelength. The wavelength is the distance between each wave's peak and the next.

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In the correct significant figures, the solutions to the given problems are;

The term significant figures refers to the number of important single digits in the coefficient of an expression in scientific notation.

61.2 m + 9.35 m + 8.6 m = 79.15 m

9.44 m – 2.11 m = 7.33  m

1.36 m + 10.17 m = 11.53 m

34.61 m – 17.3 m = 17.31 m

Thus, in the correct significant figures, the solutions to the given problems are;

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The substances would take up more space as gas than as a solid.

We know that a solid has a definite shape and a definite volume. We know what the space that a solid is going to occupy is because the space that it can occupy is fixed. This is quite important to be at the back of our minds as we discuss.

A gas does not take up a definite space. We know that a gas does take up the volume of the object thus we can be bold to say that the gas is going to take up more space than the solid in all the cases.

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So if the pressure is reduced by 0.8 atm and the temperature is reduced to 20.3°c, the new volume will be 38.8 L.

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space

From the ideal gas equation,

At constant temperature and pressure, the volume of a gas is directly proportional to the number of moles of gas. At constant temperature and volume, the pressure of a gas is directly proportional to the number of moles of gas. Or you could think about the problem a bit and use PV = nRT.

\(\frac{P_{1} V_{1}}{T_{1} } = \frac{P_{2} V_{2}}{T_{2} }\)

(1.8 × 22 ÷ (26.4 + 273.15)) = ((1 × \(V_{2}\) ÷ (20.3 + 273.15))

\(V_{2}\) = final volume of gas = 38.8 L

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