Answer:
6,000 kg
Explanation:
On the Moon’s surface, lunar astronauts placed a corner reflector, off which a laser beam is periodically reflected. The distance to the Moon is calculated from the round-trip time. What percent correction is needed to account for the delay in time due to the slowing of light in Earth’s atmosphere? Assume the distance to the Moon is precisely 3.84×108 m , and Earth’s atmosphere (which varies in density with altitude) is equivalent to a layer 30.0 km thick with a constant index of refraction n = 1.000293.
Answer:
\(T_d=2.8*10^-^6\%\)
Explanation:
From the question we are told that
Distance b/w Earth and the moon \(d_e=3.84×10^8 m\)
Thickness of Earth's atmosphere\(d_t=30km\)
Constant index of refraction \(n = 1.000293.\)
Generally the equation for percentage of time delay \(T_d\) is mathematically given as
\(T_d=\frac{d(n-1)}{rm}*100\%\)
\(T_d=\frac{(35*10^3)(1.000293-1)()100)}{3.674*10^8} *\%\)
\(T_d=2.8*10^-^6 \%\)
Therefore the general percentage correction needed because of tym deley is given as
\(T_d=2.8*10^-^6\%\)
you have water in two buckets of equal height.Your friend asked you which bucket contains the moat water.Now how did you find out .write short answer
To determine which bucket contains more water, I would pour the water from one bucket into the other until they are both at the same level. Then, I would compare the amount of water left in each bucket. The bucket with more water remaining is the one that originally had more water.
what is 60mph (miles per hour) in meters per second? ( A mile is 5280ft)
please someone help me
Answer:
60mph=26.8224meters per second
Explanation:
why food cook faster with salt water than cook with pure water
Answer:
oil heats faster
Explanation:
v=√gr tan 31.0 grados
The banking angle is the angle that the surface makes with the horizontal, or the angle of inclination.
v = √rg tanθ
tanθ=v²/rg
The relation gives the angle of banking of the cyclist going round the curve. Here v is the speed of the cyclist, r is the radius of the curve, and g is the acceleration due to gravity.
The banking angle is the angle that the surface makes with the horizontal, or the angle of inclination. The normal force acting on the car while travelling through such a curving road has a horizontal component. The centripetal force needed to prevent skidding is provided by this component.
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Which of the following is a mood disorder?
phobic disorder
bipolar disorder
schizophrenia
conversion disorder
Answer:
bipolar disorder
Explanation:
bipolar disorder, is previously known as manic depression, is a mental disorder characterized by periods of depression and periods of abnormally elevated mood that last from days to weeks.
What is Concave lenses ?
Explanation:
A concave lens is also known as a diverging lens because it is shaped round inwards at the centre and bulges outwards through the edges, making the light diverge. They are used to treat myopia as they make faraway objects look smaller than they are.
Calculate the kinetic energy of a 100.0-kg meteor approaching the Earth at a speed of 10.0 km/s. Remember that 1 km = 1000 m.
5.00 × 109 J
10 × 107 J
50.0 × 108 J
1.00 × 108 J
How to solve this problem?
Answer:
5.6 m/s
Explanation:
m = 0.25 kg, h = 2 m
initail energy = mgh = 0.25 * 9.81 * 2 = 4.91 J
80% of 4.91 J converted to final kinetic energy mv^2/2
so 0.8 * 4.91 = 0.25*v^2/2
v^2 = 2*0.8*4.91/0.25 = 31.4
v = 5.6 m/s
Vector A = 3x + 5y and vector B = -3x + 6y. Find Vector C such that 2A + 7B + 4C = 0.
Vector C = 15/4x - 13y
What is a vector?A vector is an object that has both a magnitude and a direction. Geometrically, we can picture a vector as a directed line segment, whose length is the magnitude of the vector and with an arrow indicating the direction. The direction of the vector is from its tail to its head.
Examples of vectorsTwo examples of vectors are those that represent force and velocity. Both force and velocity are in a particular direction. The magnitude of the vector would indicate the strength of the force or the speed associated with the velocity.
From the question;
Vector A = 3x + 5y
Vector B = -3x + 6y
2A + 7B + 4C = 0
Substituting the vectors A and B
2(3x + 5y) + 7(-3x + 6y) + 4C = 0
6x +10y - 21x + 42y +4C = 0
Taking like terms
-15x +52y + 4C = 0
4C = 15x - 52y
Dividing both sides by 4
Vector C = 15/4x - 13y
In conclusion, our Vector C is derived by substituting in the equation given.
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In which regions can the gravitational field strength due to the two planets be zero? Explain.
A. None
B. A, B and C
C. A and C
D. B
Answer:
I believe its a and c but my notes are all kinds of messed up so im sorry if its wrong
Explanation:
None of the regions can the gravitational field strength due to the two planets be zero.
What is gravitational field?
A gravitational field is a model used in physics to explain the effects that a large thing has on the area surrounding it, exerting a force on smaller, less massive bodies. Consequently, a gravitational field, which is measured in newtons per kilogram, is employed to describe gravitational processes.
Field due to given masses can not be zero in the given region they do not cancel each other.
None of the regions can the gravitational field strength due to the two planets be zero.
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NEED HELP WITH PHYSICS< WILL NAME BRAINLIEST
Answer:
c
Explanation:
A rigid body is rotating with constant angular speed 3 radians per second about a fixed axis through the points A. (4, 1, 1), B. (2, -1; 0), distances being measured in centimeters. The rotation is in the left-handed sense relative to the direction AB
1, Determine the unit vector pointing in the direction BA.
2, What is the angular velocity () of the of the body?
3, Write the position vector of point P: P .
Find the instantaneous velocity of particle P [hint v = w×r)
4, What is meant by left-handed rotation (left-handed coordinate system)?
5, Write the position vectors of points A and B The rotation axis AB has direction BA. Write the direction BA in terms of the components given above.
1.Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)
2.The angular velocity (ω) of the body is given as 3 radians per second.
3.Without the position of point P given, it is not possible to write the position vector of P.
4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule.
5.Position vector of point A: (4, 1, 1)
Position vector of point B: (2, -1, 0)
The direction vector BA = (-2, -2, -1)
1.To determine the unit vector pointing in the direction BA, we subtract the coordinates of point B from the coordinates of point A and normalize the resulting vector.
The direction vector BA is given by:
BA = (4 - 2, 1 - (-1), 1 - 0) = (2, 2, 1)
To obtain the unit vector in the direction of BA, we divide the direction vector by its magnitude:
|BA| = √(2^2 + 2^2 + 1^2) = √(4 + 4 + 1) = √9 = 3
Unit vector in the direction BA: BA/|BA| = (2/3, 2/3, 1/3)
2.The angular velocity (ω) of the body is given as 3 radians per second.
3.Without the position of point P given, it is not possible to write the position vector of P. Please provide the position of point P to proceed with the calculation.
4.Left-handed rotation refers to the direction of rotation where the rotation follows the left-hand rule. In a left-handed coordinate system, if you curl the fingers of your left hand in the direction of rotation, your thumb will point in the direction of the rotation axis. It is the opposite direction to a right-handed rotation.
5.The position vectors of points A and B are:
Position vector of point A: (4, 1, 1)
Position vector of point B: (2, -1, 0)
The direction vector BA can be obtained by subtracting the coordinates of point A from the coordinates of point B:
BA = (2 - 4, -1 - 1, 0 - 1) = (-2, -2, -1)
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5. A tennis player hits a ball when it is at a height of 1.1 meters above the court, giving it a velocity of 12 m/s at an angle of 22° above the horizontal towards the net. The net is 1.81 meters high and stands 2.6 meters from the player.
a) Show that the ball will just pass over the net.
b) Find when and where the ball hits the ground.
According to the information, the ball will just pass over the net (question A); and the ball hits the ground approximately at 7.04 meters from the player and after a time of flight of approximately 1.31 seconds (question B).
How to determine if the ball will clear the net?To determine if the ball will clear the net, we compare the vertical displacement of the ball with the net height. The ball's initial height is 1.1 meters, and it reaches its highest point during flight. By calculating the trajectory, we can confirm that the ball's vertical displacement at its highest point will be higher than the net height of 1.81 meters, ensuring it clears the net.
How to find when and where the ball hits the ground?To find when and where the ball hits the ground, we need to calculate the time of flight and horizontal displacement. Using the given initial velocity and angle, we can determine the time it takes for the ball to reach the ground. By calculating the horizontal displacement based on the initial horizontal velocity and total time of flight, we find that the ball hits the ground approximately 7.04 meters from the player. The time of flight is approximately 1.31 seconds. The specific values may vary depending on the given initial conditions.
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Two identical objects A and B of mass M move on a one-dimensional, horizontal air track. Object B initially moves to the left with speed vo. Object A initially moves to the right with speed 3vo, so that it collides with object B. Friction is negligible. Express your answers to the following in terms of M and vo.
(a) Determine the total momentum of the system of two objects.
(b) A student predicts that collision will be totally inelastic (the objects stick together on collision). Assuming this is true, determine the following for the two objects immediately after the collision. i. the speed ii. the direction of motion.
I 'm having trouble in how to approach the problem, specifically when to use inelastic or elastic.
a) Total momentum before collision is: \(\mathrm{\rho = M \times 3v_0 - M \times v_0 = 2M \times v_0}\)
b) Immediately after the collision, two objects move together with a speed of v₀. The direction of motion is to the right, as A was moving to right before collision.
What is momentum?Momentum may be defined as the product of mass and velocity of any object.
(a) Before the collision, total momentum of the system is :
\(\mathrm{\rho = m_A \times v_A + m_B \times v_B}\)
\(\mathrm{m_A = m_B = M, v_A = 3v_0, \ and \ vB = -v_0}\) (since B is moving to the left).
Therefore, total momentum before the collision is:
\(\mathrm{\rho= M \times 3v_0 - M \times v_0 = 2M \times v_0}\)
(b) Immediately after the collision, the two objects move with the same velocity v. Total momentum of the system is: p' = (mA + mB) × v = 2M × v
As total momentum is conserved: p' = p
\(\mathrm{2M \times v = 2M \times v_0}\)
\(\mathrm{v = v_0}\)
Therefore, immediately after the collision, two objects move together with a speed of v₀. The direction of motion is to the right, since A was moving to the right before collision.
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How do I find the mass in kg
To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.
The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.
When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.For more questions on mass
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27) The recoil of a shotgun can be significant. Suppose a 3.3-kg shotgun is held tightly by an arm and shoulder with a combined mass of 15.0 kg. When the gun fires a projectile with a mass of 0.038 kg and a speed of 385 m/s, what is the recoil velocity of the shotgun and arm shoulder combination?
Since the initial linear momentum of the system is 0, the linear momentum of the gun-arm system must be equal in magnitude and opposite in direction to the linear momentum of the bullet.
Find the linear momentum of the bullet:
\(\begin{gathered} p_{\text{bullet}}=m_{\text{bullet}}v_{\text{bullet}} \\ =(0.038kg)(385\frac{m}{s}) \\ =14.63\operatorname{kg}\cdot\frac{m}{s} \end{gathered}\)If the gun-arm system recoils with a speed v, the total linear momentum of the gun-arm system is:
\((3.3\operatorname{kg}+15.0\operatorname{kg})v\)Since the linear momentum of the gun-arm system must have the same magnitude as the linear momentum of the bullet, then:
\((3.3\operatorname{kg}+15.0\operatorname{kg})v=14.63\operatorname{kg}\cdot\frac{m}{s}\)Isolate v and find its value:
\(\begin{gathered} v=\frac{14.63\operatorname{kg}\cdot\frac{m}{s}}{3.3\operatorname{kg}+15.0\operatorname{kg}} \\ =0.79945\ldots\frac{m}{s} \\ \approx0.8\frac{m}{s} \end{gathered}\)Therefore, the recoil speed of the shotgun and arm-shoulder combination is 0.8 meters per second.
6.
least 2 m. If the same car is moving with the speed 80K/h,what is the minimum stopping distance?
A car moving with a speed of 40 km/h can be stopped by applying the brakes after at-
The minimum stopping distance of the car is determined as 8 m.
What is the minimum stopping distance?The minimum stopping distance of the car is calculated as follows;
d = (u²)/(2a)
where;
d is the minimum stopping distanceu is the initial velocitya is the acceleration of the carwhen the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s
2 = (11.11²)/(2a)
a = (11.11²)/(2 x 2)
a = 30.86 m/s²
when the speed becomes 80 km/h, the minimum stopping distance is calculated as;
u = 80 km/h = 22.22 m/s
d = (22.22² )/ (2 x 30.86)
d = 8 m
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did you know that before pencil erasers were added
Answer:
Yes, The original erasers were bread. Until the 1770's humanity's preferred way of erasing graphite marks relied on bread that had been de-crusted, moistened and balled up. The first pencil only came out in 1795.
Explanation:
Answer:
Until the 1770s, humanity's preferred way of erasing errant graphite marks relied on bread that had been de-crusted, moistened and balled up. While these erasers were cheap and plentiful, they had a distinct disadvantage: They were, you know, made of bread.
Discuss two ways to determine your muscular strength explain the advantages
Answer:
Two ways to determine ones muscular strength is to either lift the heaviest weight possible or by doing one repetition. The advantages these two methods is that it is easy to determine and does not require calculations or estimating.
Explanation:
Answer:
Two ways to determine ones muscular strength is to either lift the heaviest weight possible or by doing one repetition. The advantages these two methods is that it is easy to determine and does not require calculations or estimating.
Explanation:
You know you can provide 600 W
of power to move large objects. You need to move a 60-kg
safe up to a storage loft, 18 m
above the floor.
Part A
With what average speed can you pull the safe straight up?
A. The average speed you can use to pull the safe is 1.02 m/s
B. The time needed to pull the safe up is 17.65 s
A. How do i determine the velocity?First, we shall obtain the force. This is shown below:
Mass of safe (m) = 60 KgAcceleration due to gravity (g) = 9.8 m/s² Force (F) =?F = mg
F = 60 × 9.8
F = 588 N
Finally, we shall obtain the average speed. Details below:
Power = 600 WForce = 588 NAverage speed =?Power = force × average speed
600 = 588 × average speed
Divide both sides by 588
Average speed = 600 / 588
Average speed = 1.02 m/s
B. How do i determine the time?The time needed to pull the safe up can be obtained as follow:
Average speed = 1.02 m/sTotal distance = 18 mTime = ?Time = Total distance / average speed
Time = 18 / 1.02
Time = 17.65 s
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Complete question:
You know you can provide 600 W
of power to move large objects. You need to move a 60-kg
safe up to a storage loft, 18 m
above the floor.
Part A
With what average speed can you pull the safe straight up?
Part B
What is the time needed to pull the safe up?
What came first the color orange or the fruit?
Answer:
The fruit, orange, came first. The color was named after the fruit.
From the word "Orange" we know that it was used for the first time to refer to the fruit in the 13th century and it was not until 1542 when it began to be used to name the color.
(This was almost 300 years later)
¿What are oranges?It is known that oranges are the fruit of the sweet orange tree, which is a tree that belongs to the Citrus genus of the Rutaceae family.
¡Hope this helped!
Three vectors with magnitudes 120N, 100N and 80N are given in the diagram below. Write them using the unit vectors i, j and k. . 100N 80N 53° 40° Y 37° 120N X Trigonometric values you may use Cos37⁰ = 0.8 = sin53° sin37° 0.6 = cos53° cos40° = 0.766, sin40° = 0.643
The vectors can be expressed using unit vectors as follows:
Vector A = 96N i + 96N j + 0N k
Vector B = 76.6N i + 64.3N j + 0N k
Vector C = 64N i + 48N j + 0N k.
In the given diagram, let's consider the vectors as follows:
Vector A with magnitude 120N, Vector B with magnitude 100N, and Vector C with magnitude 80N.
To express these vectors using unit vectors i, j, and k, we need to determine their respective components in the x, y, and z directions.
For Vector A (120N), we have the following information:
Magnitude = 120N
Direction: X-axis (cosine component) with an angle of 37° and Y-axis (sine component) with an angle of 53°.
Using the trigonometric values provided:
cos37° = 0.8 and sin53° = 0.8
Therefore, the components of Vector A are:
Ax = 120N * 0.8 = 96N (in the X-direction)
Ay = 120N * 0.8 = 96N (in the Y-direction)
Az = 0N (no component in the Z-direction)
Thus, Vector A can be written as 96N i + 96N j + 0N k.
Similarly, using the trigonometric values for Vector B and Vector C, we can calculate their components:
For Vector B (100N):
Bx = 100N * cos40° = 100N * 0.766 = 76.6N
By = 100N * sin40° = 100N * 0.643 = 64.3N
Bz = 0N
Vector B can be expressed as 76.6N i + 64.3N j + 0N k.
For Vector C (80N):
Cx = 80N * cos37° = 80N * 0.8 = 64N
Cy = 80N * sin37° = 80N * 0.6 = 48N
Cz = 0N
Vector C can be written as 64N i + 48N j + 0N k.
In summary, the vectors can be expressed using unit vectors as follows:
Vector A = 96N i + 96N j + 0N k
Vector B = 76.6N i + 64.3N j + 0N k
Vector C = 64N i + 48N j + 0N k.
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If you react 33.0 grams of Ca how many moles of CaSO4 is produced?Ca + H2SO4 → CaSO4 + H2
0.825 moles of CaSO₄ is produced
Explanation:The given equation of reaction is:
\(Ca+H_2SO_4\rightarrow CaSO_4+H_2\)Mass of Ca = 33.0 g
Molar mass of Ca = 40 g/mol
Number of moles of Ca = Mass/Molar Mass
Number of moles of Ca = 33/40
Number of moles of Ca = 0.825 moles
From the equation:
1 mole of ca produced 1 mole of CaSO₄
0.825 moles of Ca will produce 0.825 moles of CaSO₄
Therefore, 0.825 moles of CaSO₄ is produced
What wavelength of light (in nm) is associated with a frequency of 5.72 E14 Hz
Answer: 520 nm; 5.77 × 1014 Hz; 3.82 × 10−19 J
find the rms speed of a sample of oxygen at 30° C and having a molar mass of 16 g/mol.
At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.
The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:
vrms = √(3kT/m)
Where:
vrms is the rms speed
k is the Boltzmann constant (1.38 x 10^-23 J/K)
T is the temperature in Kelvin
m is the molar mass of the gas in kilograms
To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:
m = 16 g/mol = 0.016 kg/mol
Substituting the values into the formula, we have:
vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))
Calculating this expression yields the rms speed of the oxygen sample:
vrms ≈ 482.34 m/s
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bi Name two processes by which a hot drinks cool
Problem I Marcella (see warmup problem, above) gets her car moving steadily at 4m/s but suddenly someone stops ahead to assist her and parks their car 14 meters from the front of her car. Marcella grabs the car bumper and pulls very hard, with 200 N of force. The work she does transfers energy out, it reduces the K of the car, as it gradually approaches the other car. a) What is the initial kinetic energy before she tries to stop the car? b) What is the final kinetic energy, when her car hits the other car? What is the speed? c) Suppose the other person also slowed her car, pushing it from the front. How much force would be needed to stop her car 1 meter from the other car? [1 m allows the person not to be crushed!]
Answer:
Explanation:
a) KE = (1/2) * m * (\(v^{2}\)) = F * d = 14m * 200N = 2800 m/N or 2.8 * \(10^{3}\) m/N
b) 0J and 0m/s (if Marcella stopped after going 14 meters)
c) Known from part (a) that KE = 2800 J = F1 * d1,
2800J = F1 * (14m - 1m) => F1 = 2800J/13m = 215.384 N
HELP QUICK which image shows the correct way of lining up vectors to add them together?
Answer:
C is correct.
When vectors are to be added the correct order is head to ail.
This is opposed to subtraction where the vectors are connected tail to tail.
(D) shows 2 vectors how would be subtracted and the result would the sum of the lengths of the vectors (since they are shown as being colinear).
1)Draw a celestial sphere and label the horizon, the cardinal points, the celestial and anti meridians, the zenith and the nadir.
A celestial sphere is a tool that allows us to study in detail the characteristics of the planet and its reference points.
What is a celestial sphere?The celestial sphere is an astronomical tool that allows individuals to study the planet Earth and other planets. This tool is an ideal sphere that is used as a model of the Earth. Additionally, it represents the locations of celestial objects, meridians, parallels, geographical locations, among others.
What are meridians and parallels?The meridians and parallels are imaginary lines that are located on the earth to be located geographically on the surface. These also distribute the terrestrial locations in four quadrants (cardinal points).
NorthwestNortheastSouthwestSoutheastWhat is the Zenith and Nadir?The zenith is a term that refers to the highest point in the sky relative to the observer and it is just above the observer's head (90°).
The nadir is a term that refers to the intersection between the observer's vertical and the celestial sphere. That is to say: if you imagine a line that passes through the center of the Earth and through our location on its surface, the nadir is on that line, below our feet.
Below is an image in which the zenith, nadir, cardinal points, meridians and parallels are referenced.
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