A rubber ball is attached to a 1.44m string and spin in a horizontal circle. The tension in the string is 2.91 N. It takes 0.644s for the ball yo complete one revolution. What is the mass in kg of the ball?

A Rubber Ball Is Attached To A 1.44m String And Spin In A Horizontal Circle. The Tension In The String

Answers

Answer 1

We are given that a mass is attached to a string and is spun is in a horizontal circle, this means that the free body diagram of the problem is the following:

We will add the forces in the vertical direction:

\(T_y-mg=0\)

The forces add up to zero since there is no acceleration in the vertical direction. Therefore, we can add "mg" to both sides:

\(T_y=mg\)

Now, The vertical component of the tension can be put in terms of the total tension using the following right triangle:

Therefore, we use the trigonometric function sine:

\(\cos x=\frac{T_y}{T}\)

Multiplying both sides by "T"

\(T\cos x=T_y\)

Substituting in the sum of vertical forces:

\(T\cos x=mg\)

Now, Since the horizontal component of the tension is equivalent to the centripetal force, we have that:

\(T_x=ma_r\)

Where:

\(\begin{gathered} r=\text{ radius of the circle} \\ a_r=\text{ radial acceleration} \end{gathered}\)

We can use the trigonometric function cosine to determine the horizontal component of the tension:

\(\sin x=\frac{T_x}{T}\)

Multiplying both sides by "T":

\(T\sin x=T_x\)

Substituting we get:

\(T\sin x=ma_r\)

Now, we divide both equations:

\(\frac{T\sin x}{T\cos x}=\frac{ma_r}{mg}\)

Simplifying we get;

\(\tan x=\frac{a_r}{g}\)

Now, we multiply both sides by "g":

\(g\tan x=a_r\)

Now, in any circular motion, the period "P" is given by:

\(P=\frac{2\pi}{\omega}\)

Where:

\(\begin{gathered} r=\text{ radius} \\ v=\text{ tangential velocity} \end{gathered}\)

Also, the acceleration is given by:

\(a_r=\frac{4\pi^2r}{P^2}\)

Substituting the expression for the acceleration we determined before we get:

\(g\tan x=\frac{4\pi^2r}{P^2}\)

Substituting the expression for the period:

\(g\tan x=\frac{4\pi^2r}{(\frac{2\pi}{\omega})^2}\)

Solving the square:

\(g\tan x=\frac{4\pi^2r}{\frac{4\pi^2}{\omega^2}}\)

Solving the fraction:

\(g\tan x=\frac{4\pi^2r\omega^2}{4\pi^2}\)

Simplifying:

\(g\tan x=r\omega^2\)

Now, we can put the radius in terms of the length of the spring using the following triangle:

using the function sine we get:

\(L\sin x=r\)

Substituting in the previous equation we get:

\(g\tan x=L\sin x\omega^2\)

Now, we decompose the tangent:

\(\frac{g\sin x}{\cos x}=L\sin x\omega^2\)

Simplifying:

\(\frac{g}{\cos x}=L\omega^2\)

Now, we invert both sides:

\(\frac{\cos x}{g}=\frac{1}{L\omega^2}\)

Multiplying both sides by "g" we get:

\(\cos x=\frac{g}{L\omega^2}\)

The angular velocity is the angle divided by time, since it takes 0.644 s to complete one revolution this means that :

\(\omega=\frac{2\pi}{0.644}\)

substituting the values:

\(\cos x=\frac{9.8}{1.44(\frac{2\pi}{0.644})^2}\)

Solving the operations:

\(\cos x=0.071\)

Now, going back to the sum of forces in the vertical direction:

\(T\cos x=mg\)

Dividing both sides by "g":

\(\frac{T\cos x}{g}=m\)

Substituting the values:

\(\frac{(2.91)(0.071)}{9.8}=m\)

Solving the operations:

\(0.021=m\)

Therefore, the mass of the ball is 0.021 kg.

A Rubber Ball Is Attached To A 1.44m String And Spin In A Horizontal Circle. The Tension In The String
A Rubber Ball Is Attached To A 1.44m String And Spin In A Horizontal Circle. The Tension In The String
A Rubber Ball Is Attached To A 1.44m String And Spin In A Horizontal Circle. The Tension In The String

Related Questions

A crate with a mass of 35.0 kg is pushed with a horizontal force of 150 N. The crate moves at a constant speed across a level, rough surface a distance of 5.85 m

A crate with a mass of 35.0 kg is pushed with a horizontal force of 150 N. The crate moves at a constant

Answers

(a) The work done by the 150 N force is 877.5 Joules.

(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.

To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.

(a) The applied force's work may be estimated using the following formula:

Work = Force * Distance * cos(theta)

where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.

As a result, the applied force's work is:

Work = 150 N * 5.85 m * cos(0) = 877.5 J

So, the work done by the 150 N force is 877.5 Joules.

(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.

The frictional work may be estimated using the following formula:

Work = Force of Friction * Distance * cos(theta)

The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.

Thus, the work done by friction is:

Work = 150 N * 5.85 m * cos(180) = -877.5 J

Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.

The coefficient of kinetic friction may be calculated using the following equation:

Friction Force = Kinetic Friction Coefficient * Normal Force

The normal force equals the crate's weight, which may be computed as:

Normal Force = mass * gravity

where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.

Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N

Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:

Force of Friction = coefficient of kinetic friction * Normal Force

150 N = coefficient of kinetic friction * 343 N

coefficient of kinetic friction = 150 N / 343 N ≈ 0.437

As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.

In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.

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A 9-volt battery is used to power 2 lightbulbs on separate branches of a parallel circuit. The first lightbulb has a resistance of 3 ohms and the second has a resistance of 2 ohms.

What is the power output of the battery?

Please show work if possible!

Answers

Power= current x potential difference

To find total resistors in ohms, in parallel circuit, do 1/given ohms for all resistors first; then, add them together:

1/3 ohms + 1/2 ohms = 5/6 ohms

V= IR

xR

VR = I

I=VR

= 9 x 5/6

= 7.5 amps

P = I x V

= 7.5 x 9

= 67.5

Hope this helps!

According to the principal of superposition,

Answers

Answer:

the resultant wave is the algebraic sum of all the waves reaching that particular point at a given time.

Explanation:

imagine two or three waves reaching a particular particle x at the same time. The particle will vibrate those waves and give out or transmit a resultant wave which is the algebraic sum of the incoming two waves. If both the waves have the same amplitude and phase, the resultant wave will be amplified. However if the waves have the same amplitude and equal but opposite phase then the resultant wave will be a straight line

How far can a person run in 15 minutes if they can run 2 miles per hour?

Answers

Answer:

if a person can run 2 miles per hour which means 60 mins

60x=15×2

60×=30

×=30/60

×=0.5miles

so a person can run 0.5 miles in 15 minutes

which means 804.67 meters in 15 minutes

Determine how would the frequency of the pendulum change if it was taken to the moon by finding the ratio of its frequency on the moon fM to its frequency on the earth fE. Suppose that gE is the free-fall acceleration on the earth and gM is the free-fall acceleration on the moon.
Express your answer in terms of some or all of the variables l, m, gE, gM.
fM/fE = ?

Answers

For the  pendulum taken to the moon, The frequency change that would occur is mathematically given as

\(\frac{Fmoon}{Fearth}=0.408\)

What frequency change would occur to the pendulum if it was taken to the moon?

Generally, the equation for the Time period  is mathematically given as

\(T=2\pi\sqrt{L/g}\)

Therefore

\(\frac{Fmoon}{Fearth}=\frac{\sqrt{g/6L}}{\sqrt{g/6L}}\\\\\frac{Fmoon}{Fearth}=\sqrt{1/6}\)

\(\frac{Fmoon}{Fearth}=0.408\)

In conclusion, The frequency change

\(\frac{Fmoon}{Fearth}=0.408\)

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Answer:

.408

Explanation:

03: Hook's law suggests that F is directly proportional to -x, how much true you have found this statement in your experiment? Explain any differences.​

Answers

Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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According to The Flash, The heroes top speed is Mach 3.3, or 2,500 miles per hour. How
long would it take for him to run around the planet? (circumference of the earth is
roughly 25,000 miles) *

Answers

Answer:

nearly 2 days or less hes fast but not that fast

Explanation:

but maybe he can run it in five minutes

Explain why a ping pong ball and bouncy ball of the same size have different weights

Answers

Answer:

the material

Explanation:

weight is defined as the amount of force on the object because of gravity. ping pong balls and bouncy balls are made out of different materials that are different weights. most bouncy balls are also not hollow, unlike ping pong balls. these factors affect the weight of these objects.

The cores of the terrestrial worlds are made mostly of metal because ______.

A. metals sunk to the centers a long time ago when the interiors were molten throughout
B. the terrestrial worlds as a whole are made mostly of metal
C. the core contained lots of radioactive elements that decayed into metals
D. over billions of years, convection gradually brought dense metals downward to the core

Answers

It is C because I got it right on the assignment

A particle with mass 3×10−2 kg
k
g
and charge +3 μC
μ
C
enters a region of space where there is a magnetic field of 1 T
T
that is perpendicular to the velocity of the particle. When the particle encounters the magnetic field, it experiences an acceleration of 12 m/s2
m
/
s
2
. What is the speed of the particle when it enters the magnetic-field region?

Answers

The speed of the particle when it enters the magnetic-field region is 120,000 m/s.

Speed of the particle

Magnetic force on the particle is given as;

F = qvB

where;

q is magnitude of the chargev is speed of the particleB is magnetic field strength

From Newton's second law, force on an object is given as;

F = ma

where;

m is mass of the particlea is acceleration

ma = qvB

v = ma/qB

v = (3 x 10⁻² x 12)/(3 x 10⁻⁶ x 1)

v = 120,000 m/s

Thus, the speed of the particle when it enters the magnetic-field region is 120,000 m/s.

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how many legs a cow has​

Answers

the cow has 4 legs :)

A form of energy NOT associated with the particles of objects is
thermal energy
mechanical energy
nuclear energy
chemical energy

Answers

Answer:

mechanical energy

Explanation:

because except mechanical energy all posseses particles

A cheetah can maintain its maximum speed of 100 km/hr for 30.0 seconds. What minimum distance must a gazelle running 80.0 km/hr be ahead of the cheetah to escape?

Answers

Explanation:

Suppose the cheetah is initially positioned at x=0 (m) from the reference, and the gazelle is intially at poisiton x=d (m).

Then, at the worst case, that is when cheetah is running at the maximum case, the position of the gazelle relative to the reference must be larger than that of cheetah.

In equation form,

\(0\text{ km}+\frac{100\text{ km}}{1 \text{ hr}}\cdot30\text{ s }\cdot\frac{1\text{ hr}}{3600\text{ s}}\le d \text{ km}+\frac{80\text{ km}}{1 \text{ hr}}\cdot30\text{ s }\cdot\frac{1\text{ hr}}{3600\text{ s}}\)

\((100-80)\cdot \frac{30}{3600}\le d\)

\(d\ge \frac16\text{ km}=166.66 \text{m}\)

The minimum distance that a gazelle running 80.0 km/hr be ahead of the cheetah to escape is 6.5807km

If a cheetah can maintain its maximum speed of 100 km/hr for 30.0 seconds, the distance covered by the cheetah is expressed as:

Distance  = Speed * time

Given the following:

Speed = 100km/hrTime = 30secs = 0.00833333hr

Distance covered = 100 * 0.00833333

Distance covered = 0.0833 km

If gazelle is running at a speed of 80.0km/hr, the distance of gazelle will be expressed as:

Distance of gazelle = 80 * 0.08333Distance covered by gazelle = 6.6664km

Taking the difference in distance = 6.6664km - 0.0833 km =6.5807km

Hence the minimum distance that a gazelle running 80.0 km/hr be ahead of the cheetah to escape is 6.5807km

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Based on the diagram, how is the greenhouse gas effect maintained?

Human activities absorb sunlight to create stable warm temperatures of Earth.
Sunlight absorbed at the surface results in greenhouse gases warming the atmosphere.
Greenhouse gases produced from human activities heat surface temperatures of Earth.
Sunlight is reflected by the surface of Earth, and heat is trapped in the atmosphere by greenhouse gases.

Based on the diagram, how is the greenhouse gas effect maintained? Human activities absorb sunlight to

Answers

The correct statement is " Sunlight absorbed at the surface results in greenhouse gases warming the atmosphere." The correct option is B.

The greenhouse effect is a natural phenomenon that keeps the Earth's temperature within a range that is suitable for humans and other forms of life. The greenhouse effect is maintained by certain gases in the atmosphere, known as greenhouse gases, which trap the sun's energy and warm the Earth's surface.

Option A, which states that human activities absorb sunlight to create stable warm temperatures on Earth, is not correct. Human activities do not directly absorb sunlight. However, they do release greenhouse gases, which contribute to the greenhouse effect and increase the temperature of the Earth's surface.

Option C, which states that greenhouse gases produced from human activities heat the surface temperatures of Earth, is partially correct. Human activities, such as burning fossil fuels, do release greenhouse gases that contribute to the greenhouse effect. However, this option suggests that the greenhouse gases themselves heat the surface of the Earth, which is not accurate. The greenhouse gases trap heat in the atmosphere, which warms the Earth's surface.

Option D, which states that sunlight is reflected by the surface of the Earth, and heat is trapped in the atmosphere by greenhouse gases, is not entirely accurate. The Earth's surface absorbs the sun's energy, and some of this energy is reflected back into space. The rest is absorbed by the Earth's surface and then re-emitted as heat. The greenhouse gases in the atmosphere trap this heat and prevent it from escaping into space, which causes the Earth's temperature to rise.

Therefore, The correct answer is option B.

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At which location would a bowling ball have the greatest weight? on Earth, at the top of a tall mountain on the surface of the moon on Earth, several kilometers below the surface on Earth at sea level

Answers

Several Kilometres below the earth at Sea level

.

A cyclist rides 3 km west and then turns around and rides 2 km east. What is her displacement?

Answers

Answer:

1km west

Explanation:

Because if the cyclist is going back 2km then its 3-2=1km

a 1 kg blob of putty moving at 10 m/s runs into another 1 kg stationary blob, and they stick together. the momentum of the blobs after the collision is

Answers

The momentum of the blobs after the collision of a 1 kg blob of putty moving at 10 m/s with another 1 kg stationary blob will be 5 m/s.

The term "completely inelastic collision" is used to describe every time two masses cling together after colliding. Any inelastic collision will result in the internal energy of the objects being transformed into kinetic energy. Because of this, even though the system's energy is conserved (no outside forces are at action), its internal energy is changing in an unknowable and unpredictable fashion. This implies that the concept of energy conservation in inelastic collisions is absolutely meaningless to us. However, the conserved quantity that we can monitor is momentum.

Initial momentum is expressed as p = m1v1 + m2v2,

where, I denotes vector quantities.

v2 = 0  (because the second blob is at rest).

As a result, p=m1v1, |p|=m1|v1|=1*10= 10 kg*m/s,

The total amount of momentum is conserved in a closed system. The end momentum is 10 kg*m/s and is therefore also directed in the same direction as the beginning momentum.

The combined mass is now M=m1+m2= 1+1 = 2 kg due to the fact that two blobs are now clumped together. As a result, p = mv= 10 =2v; from this, v= 10/2 = 5 m/s, headed in the same direction as the first blob's starting velocity.

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F=ma
1. Your car has a mass of 2000 kg. If your car produces a force of 7000 N, how fast will it accelerate?
Formula
Substitution
(plug and chug)
Answer
(number and unit)
Submit Assig

Answers

Answer:

\(\huge\boxed{\sf a = 3.5\ m/s\²}\)

Explanation:

Given data:

Mass = m = 2000 kf

Force = F = 7000 N

Required:

Acceleration = a = ?

Formula:

F = ma (derived from Newton's Second Law of Motion)

Solution:

Taking formula.

F = ma

Solve it for a.

a = F / m

a = 7000 / 2000

a = 3.5 m/s²

\(\rule[225]{225}{2}\)

Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?

Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 areopen, i leads e by 30.

Answers

Based on the information, it should be noted that the resistance R is 0.5 Ω.

How to calculate the resistance

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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Question 4 of 10
Which of the following describes the reactants of a chemical reaction?
OA. The chemicals on the right side of a chemical equation
B. The substances that are formed
OC. The substances that are made
O D. The chemicals on the left side of a chemical equation

Answers

The substances that are altered and the chemicals on the right side of a chemical equation are the results of a chemical reaction. B and D are the appropriate choices.

Reactants are the substance(s) in a chemical equation to the left of the arrow. A component that is present at the outset of a chemical reaction is known as a reactant. Products are the substance(s) to the right of the arrow. A substance that remains after a chemical reaction is complete is known as a product. The creation of products from the reaction of two reactants is known as a chemical reaction. The compounds that result from a reaction are called products. The substances that are original materials are the reactants.

On the left side of the reaction are the reactants, and on the right are the products. B and D are the proper choices as a result.

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Two
objects attract each other gravitationally
a force of 50 10 10 N when they are
apart.
If the mass of one object is
2.00 kg, what is the mass of the other
Object?
with
0.20m

Answers

 M2 = 0.665 kg

The mass of other object is 0.665 kg

Solution:

To solve this, we must apply Newton's law of universal gravitation, which states that the force of gravity between two massive bodies 1, 2, is proportional to their masses M1 and M2 and inversely proportional to the square of the distance d between them:

        F = (GM1M2) / D²

 Here G = 6.67 × 10⁻¹¹ Nm²/kg²

           F = 50×10⁻¹⁰N

           M1 = 2.00kg

            D = .20 m

by substituting values ,

               50×10⁻¹⁰N =(( 6.67 × 10⁻¹¹ Nm²/kg²)(2.00kg)M2) / (.20 m)²

                50×10⁻¹⁰ = 1.334 × 10⁻¹⁰ M2 /( .20)²

                (50×10⁻¹⁰) (.20)² = 1.334 × 10⁻¹⁰ M2

                 2 ×10⁻¹⁰ = 1.334 × 10⁻¹⁰ M2

                 M2 = 1.334 × 10⁻¹⁰ / 2 ×10⁻¹⁰

                 M2 = 0.665 kg

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A-0.06 C charge that moves downward is in a uniform electric field with a strength of 200 N/C. What is the
magnitude and direction of the force on the charge?
O 12 Nup
O 12 N down
O 3333 Nup
O 3333 N down

Answers

Answer:

its B

Explanation:

i just took the test

The correct option is B. The magnitude of the force on the charge is 12N and the direction is downward.

The electric field is a region of space where electric force can be felt. The formula for calculating the magnitude of a force in an electric field is expressed as:

\(\overline F=qE\) where:

q is the charge measured in CoulombsE is the electric field intensity measured in N/C

Given the following parameters:

q = -0.06C

E = 200N/C

Substitute the given parameters into the formula as shown:

\(\overline F = -0.06 * 200\\\overline F = -12N\\\)

Since the modulus of the force is in the negative sense, hence the direction will be downward.

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A-0.06 C charge that moves downward is in a uniform electric field with a strength of 200 N/C. What is

Hellllllpppppp what happens

Hellllllpppppp what happens

Answers

Answer:

u can write ur answer and submit it

its a test

Two atoms of the same element only differ because one of the atoms has more electrons, making it an ion. Which statement is true? They have the same A-number and the same Z-number. They have the same A-number but different Z-number. They have a different A-number but the same Z-number. They have different A-numbers and different Z-numbers.

Answers

The correct answer is Option B. The statement "they have the same A-number but different Z-number" is true .

Atoms of the same element only differ because one of the atoms has more electrons, making it an ion.

This difference does not affect the mass of the atom, which is determined by the sum of its protons and neutrons, represented by the atomic mass or A-number.

The number of protons in an atom is called the atomic number or Z-number.

The Z-number of an element is unique to it. All the atoms of a given element have the same number of protons.

Thus, for example, all carbon atoms have six protons, making the Z-number of carbon 6.

However, different isotopes of an element can have different numbers of neutrons.

This means that they have a different atomic mass or A-number.

Therefore, they have the same A-number but different Z-number.

Therefore the correct Option is B.

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What is the relationship between unbalanced and motion?

Answers

The relationship between unbalanced forces and motion is that unbalanced forces cause motion.

When there is an unbalanced force acting on an object, it will accelerate in the direction of the net force.

The magnitude and direction of the motion are directly influenced by the magnitude and direction of the unbalanced force.

In the absence of any opposing forces, an unbalanced force will result in continuous acceleration, causing the object to move faster and faster.

This relationship is described by Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

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a car accelerate uniformly from rest to a speed of 20m/s in 8seconds.the mass of the car is 1200kg. calculate the acceleration of the car

Answers

Answer:3000

Explanation:

given:u=0v=20m/st= 8sec

thereforea=v-u/t=20-0/8=20/8=5/2 m/som=1200 kg

thereforef=ma=1200*5/2=600*5=3000N

On a brisk walk, a person burns about 331 Cal/h. If the brisk walk were done at 3.0 mi/h, how far would a person have to walk
to burn off 1 lb of body fat? (A pound of body fat stores an amount of chemical energy equivalent to 3,500 Cal.)
mi?​

Answers

Answer:

32mi

Explanation:

If 1lb contains 3,500 Cal

It means the number of hours required to burn 3500cal would be;

3500/331 = 10.57hours

But a brisk walk is 3.0 mi/h,

It means a distance of 3.0 × 10.57 mi would be covered = 31.71 miles

32miles{ approximated to the nearest whole}

Note Distance = speed × time

Which correctly describes latent heat?

A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid

Answers

Option C. The heat absorbed or lost by a substance while it's changing state  correctly describes latent heat

Latent heat is the heat absorbed or lost by a substance while it is changing state.

The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.

For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.

Latent heat is not associated with a temperature change; rather, it's associated with a change of state.

For instance, the temperature of water remains at 100°C while boiling.

When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.

When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.

Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.

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Jacob Grena raises a spoon 0.210 m above a table . If the spoon and its contents have a mass of 30.0 g, what is the gravitational potential energy associated with the spoon at that height relative to the table's surface?

Answers

Explanation:

The spoon is raised so it gains Gravitational potential energy. Formula to find Gravitational potential energy;

Gravitational potential energy = mass × Gravitational field strength × height of the body from the surface (table in this scenario)

In symbols; E = m×g×h

Substitute values:

m = 30g = 0.03kg (don't forget to convert grams to kg)

g = 10N/kg

h = 0.210 m

So it's;

0.03kg × 10N/kg × 0.210m = 0.063 Joules

SI Unit of energy is joules

A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J

Answers

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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