Be sure to answer all parts. A gas expands and does PV work on its surroundings equal to 349 J. At the same time, it absorbs 123 J of heat from the surroundings. Calculate the change in energy of the gas. Note: PV work means work done by a changing volume against constant pressure. Enter your answer in scientific notation.
The change in energy of the gas is -2.72 x 10⁵ J.We are given:PV work done by the gas on the surroundings = 349 J
Heat absorbed by the gas from the surroundings = 123 JTo calculate the change in energy of the gas, we will use the First Law of Thermodynamics which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system on the surroundings. So,ΔU = Q - WPV work done by the gas on the surroundings = W = PΔVHere, the pressure is constant, therefore W = PΔV = PVfinal - PVinitialwhere Pfinal = Pinitial = P.So,ΔU = Q - W= 123 J - 349 J= -226 JBut, 1 J = 1 kg m²/s²Therefore,ΔU = -226 kg m²/s²= -2.26 x 10² kg m²/s²Now, we need to express this in scientific notation.
Therefore, we will move the decimal point 3 places to the left, and raise 10 to the power of 5.ΔU = -2.26 x 10² kg m²/s²= -2.26 x 10⁵ JHence, the change in energy of the gas is -2.72 x 10⁵ J.
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A vehicle travels for 20 minutes at a speed of 60 km/h. It then travels for 10 minutes at 90 km/h. At
the end of 30 minutes, it covers a distance of Select... v km.
Answer:
120km
Explanation:
it will covered 120km
i need help please and don't be putting random things i will report
Answer:
1: Because matter has many different forms.
2: The materials that are shown can be organized into 3 different forms; solid, liquid, and gas.
3: The image of the liquids is most likely a material that cannot be found in nature. Liquids have many useful properties, but it depends on the liquid. Bleach is a liquid that has is very useful for sterilizing. Water is useful because without it, life on earth would not exist. And there are many more liquids, but I am going to cut it short here because there too many to put down.
Explanation:
Pls mark Brainliest with the crown.
A load of 250 kg is hung by a crane's cable. The load is pulled by a horizontal force such that the cable makes a 30° angle to the vertical plane. If the load is in the equilibrium, calculate the magnitude of the tension in the cable.A. 289 N В. 1416 N C. 2832 N D. 4248
w= weight = mass x gravity
m = mass = 250 kg
g = gravity = 9.8 m/s^2
W = m x g = 250 x 9.8 = 2,450N
ΣFy = 0
W= Ty
2,450N = T cos 30
2,450 / cos 30 = T
T = 2,829 N
C.2832N
Calculate the gravitational force between two 112 kg objects located 100 m from each other
The gravitational force between the two objects is 8.37×10^-11 N
What is Newton Law of universal gravitation?Newton Law of universal gravitation states that the force of attraction or repulsion between two object is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. From the law
This means that F = G×(mass1 × mass2)/(radius)²
Where G is the gravitational constant ,which is given as 6.67×10^-11 Nm²/kg² and r is the distance between them
the force between two objects with masses 112kg is F= 6.67×10^-11×112²/100²
F= 8.37×10^-11/10000
F= 8.37×10^-11 N
therefore the force of gravity between the two objects is 8.37×10^-11 N
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dentify the following terms associated with the water cycle.
Water changes from a gas to a liquid phase.
Water falls to the Earth in the form of a liquid or solid.
Liquid water changes into a gas.
Water evaporates from the leaves of plants.
Answer:
condensation, precipitation, evaporation, transpiration
Explanation:
condensation is when gas condenses into liquid, precipitation is when water comes from the sky like in rain, evaporation is when water is converted from liquid to gas, transpiration is when water is evaporated from leaves.
a 100kg crate is set on a 30 degree ramp that possesses some friction. How much friction is required to cause the crate to stick and not slide?
Answer: 490 N
Explanation:
The driver of a car traveling at 38.7 m/s applies the brakes and undergoes a constant
deceleration of 2.41 m/s. How many revolutions does each tire make
before the car comes to a stop, assuming that
the car does not skid and the tires have
radii of 0.18 m?
Answer in units of rev.
Each tire makes 274.9 revolutions before the car comes to a stop.
How to calculate?We will calculate the distance covered for by the car after the brakes are applied. We will apply the following equation of motion:
V^2=U² +2as where V is the final velocity, U is the initial velocity, a is the acceleration and s is the distance covered during that acceleration.
0=(38.7)² -2* 2.41 *S (This negative because it is decelerating).
0 = 1497.69 - 4.82* S
S = 310.72
Circumference of the tire = 2πr where r is the radius.
Circumference = 1.13
Distance / circumference = Number of revolutions.
Number of revolutions. =310.72 / 1.13
Number of revolutions = 274.9
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Consider this situation: A force is applied to a box to move it
to the right across the kitchen floor. Of the forces listed,
identify which act upon the box.
The forces that act upon the box in this situation are:
Applied force (the force applied to the box to move it)
Frictional force (the force that opposes the motion of the box due to the interaction between the box and the surface it is on)
Gravitational force (the force exerted by the Earth on the box)
Forces
To move the box across the kitchen floor to the right in this instance, force is applied to it. The box is in touch with the floor, and this contact provides a frictional force that opposes the motion of the box.
When two surfaces are in touch with one another, a frictional force—which acts in the opposite direction of the applied force—is always present.
The box is susceptible to the gravitational force, which is the force the Earth applies to the box, in addition to the frictional force. This force, which is proportionate to the box's mass, pulls it in the direction of the Earth's center.
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Student 1 lifts a box with a force of 500 N and sets it on a tabletop 1. 2 m high. Student 2 pushes an identical box up a 5 m ramp from the floor to the top of the same table. Which student did the MOST work?.
The student 2 did the MOST work because he pushed the box to a greater height.
The given parameters:
Force applied by Student 1 = 500 NHeight of table for student 1 = 1.2 mHeight of ramp for student 2 = 5 mThe work done by student 1 is calculated as follows;
Work = P.E = mgh
P.E = 1.2mg
The work done by the student 2 is calculated as;
P.E = 5mg
where;
m is the mass of the boxThus, we can conclude that the student 2 did the MOST work.
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A box at rest is in a state of equilibrium half way up on a ramp. The ramp has an incline of 42° . What is the force of static friction acting on the box if box has a gravitational force of 112.1 N ?
Answer:
Explanation:
The force of static friction acting on the box is the frictional force;
Frictional force Ff = Wsin theta (force acting along the ramp)
W is the gravitational force known as the weight
Ff = 112.1sin42°
Ff = 112.1(0.6691)
Ff = 75.00N
Hence he force of static friction acting on the box if box has a gravitational force of 112.1 N id 75.00N
Answer:
75N i did test
Explanation:
A car's wheel has a rotational inertia of 2.0\,\text {kg} \cdot \text m^22.0kg⋅m 2 2, point, 0, start text, k, g, end text, dot, start text, m, end text, squared. The wheel initially has a counterclockwise angular speed of 6.0\,\dfrac{\text {rad}}{\text s}6.0 s rad 6, point, 0, start fraction, start text, r, a, d, end text, divided by, start text, s, end text, end fraction, but has a constant clockwise torque of 15 \,\text N \cdot \text m15N⋅m15, start text, N, end text, dot, start text, m, end text applied for 4.0\,\text s4.0s4, point, 0, start text, s, end text.
Answer:
-48
Explanation:
Answer:
6.0
Explanation:
If this is the problem on Khan Academy, I had done this and this was the correct answer.
Suppose a wire is connected between points 1 and 2. What happens to each bulb? does it get brighter, stay the same, get dimmer, or go out? Explain.
Each bulb will stay at the same brightness position as before. When a wire is connected between points 1 and 2 the circuit becomes a parallel circuit.
In a parallel circuit, the voltage across each bulb remains the same, and each bulb will remain at the same brightness position as before. The wire was connected assuming that the voltage supplied to the circuit remains constant. The overall resistance in the circuit will drop due to the added wire, so the total current supplied by the voltage source will increase.
This increased current will be divided between the bulb so each bulb will admit a slightly advanced current than earlier but not enough to create a noticeable increase in lightness. thus, each bulb will stay at the same brightness position as before.
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Which of these is a good way to begin your personal helath plan for physical fitness A. An assessment B. An action plan C. A plan for measuring progress toward your goal D. An ambitious goal.
Answer: A. An Assessment
I hope this helps, and Happy Holidays! :)
ANSWER
A. An assessment
Two protons are 1 meter apart. Determine the Fg and Fe. How do the forces of Gravitation and Coulomb’s Law impact the system? Does the force cause the protons to attract or repulse? Is the force always that way or just due to the system being 2 protons? Which Force is larger? By how much?
Answer:
fe
Explanation:
so if the Impact of the system is 2 than it appositive will be fe
Answer:
Explanation:
Given:
q₁ = q₂ = q = +1.6·10⁻¹⁹ C
m₁ = m₂ = m = 1.67·10⁻²⁷ kg
r = 1 m
k =
G = 6.67·10⁻¹¹ N·m² / kg²
k = 9·10⁹ N·m² / C²
__________________
Fg - ?
Fe - ?
Gravitational force of attraction of protons:
Fg = G·m₁·m₂ / r² = G·m² / r²
Coulomb repulsive force of protons:
Fe = k·q₁·q₂ / r² = k·q² / r²
The Coulomb force of repulsion of protons is greater than the force of gravitational attraction of protons:
Fe / Fg = k·q² / (G·m²) = (k/G)· (q/m)²
Fe / Fg = (9·10⁹ /6.67·10⁻¹¹)· (1.6·10⁻¹⁹/1.67·10⁻²⁷ )² ≈ 1,2·10³⁶ times more
Mr. Temper, a 5-foot, 4-inch, 100-pound hothead, tells Mr. Big, a 300-pound professional wrestler, that he is going to "make him regret he set foot in this bar." At the same time, Temper clenches and raises his fists. Big looks at Temper from head to toe and responds, "yeah, right." Big can sue Temper for: a. assault
b. battery
c. assault and battery
d. Big has no cause of action
Big has no cause of action against Temper. In this scenario, while Temper may have made a verbal threat and raised his fists in a confrontational manner, there is no indication that he physically touched or harmed Big.
Assault refers to the act of intentionally causing apprehension or fear of imminent harmful or offensive contact. Battery, on the other hand, involves the intentional and harmful or offensive physical contact with another person without their consent.
In this case, Temper's actions may constitute assault due to the verbal threat and raising his fists, creating an atmosphere of fear or apprehension. However, since no physical contact or harm occurred, battery is not applicable. Therefore, the appropriate response is option d: Big has no cause of action against Temper.
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This is a sever snowstrom with high winds and low visibility
Answer:
blizzard
Explanation:
A blizzard is a severe snowstorm characterized by strong sustained winds and low visibility
A particle is released as part of an experiment. Its speed t seconds after release is given by v(t)=−0.5t 2
+2t, where v(t) is in meters per second. a) How far does the particle travel during the first 2 sec? b) How far does it travel during the second 2 sec? a) The particle travels meters in the first 2sec. (Round to two decimal places as needed.) b) The particle travels meters in the second 2 sec. (Round to two decimal places as needed.
a) The particle travelss (2) = -0.17(2)^3 + (2)^2meters during the first 2 seconds. b) The particle travels t = 4 meters during the second 2 seconds.
a) To determine how far the particle travels during the first 2 seconds, we need to calculate the displacement by integrating the velocity function over the interval [0, 2]. Given that the velocity function is v(t) = -0.5t^2 + 2t, we can integrate it with respect to time as follows:
∫(v(t)) dt = ∫(-0.5t^2 + 2t) dt
Integrating the above expression gives us the displacement function:
s(t) = -0.17t^3 + t^2
To find the displacement during the first 2 seconds, we evaluate the displacement function at t = 2:
s(2) = -0.17(2)^3 + (2)^2
Calculating the above expression gives us the distance traveled during the first 2 seconds.
b) Similarly, to determine the distance traveled during the second 2 seconds, we need to calculate the displacement by integrating the velocity function over the interval [2, 4]. Using the same displacement function, we evaluate it at t = 4 to find the distance traveled during the second 2 seconds.
In summary, by integrating the velocity function and evaluating the displacement function at the appropriate time intervals, we can determine the distance traveled by the particle during the first 2 seconds and the second 2 seconds.
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what is momentum help ASAP
Momentum is the rate of increase in speed or decrease in speed after application of force
The formula is given by
p=mvp is momentum
m is mass
v is velocity
why are high tides found simultaneously on opposite sides of earth?
Explanation:
Why are high tides found simultaneously on opposite sides of Earth? The tidal bulges occur on both sides of Earth that are aligned with the tide-generating body. The ocean water experiencing high tide rotates around Earth on a 12-hour cycle.
Tides are the steady rise and fall of the ocean's waters. The water steadily rises over the beach along shores before falling back again. It is high tide when the water has risen to its highest point and is mostly covering the shore. Low tide is when the water is at its lowest point. There may be tides in some rivers and lakes.
Describe Tidal FeaturesIn the ocean, tides cause various fascinating features. Additionally, traits unrelated to tidal activity are linked to them.
When a river empties into the ocean or sea, it causes a tidal bore along the coast. A powerful tide that pushes upstream against the river's current is called a tidal bore. This really is a tidal wave. The Amazon River's massive tidal bore is known as the pororoca. The pororoca is a wave that can reach heights of up to 4 meters (13 feet) and travels at 15 kph (9 mph). The pororoca ascends the Amazon for 10 kilometers (6 miles).
Also unrelated to actual tides are so-called "red tides." Algal blooms are sometimes known as crimson tides. Sea critters known as algae are very small. In the water, red tides and waves appear when billions of red algae develop.
Rip tides are not a tidal feature, to sum up. Strong ocean currents known as rip tides flow over the water's surface. From the shore to the wide ocean, a rip tide flows. Surfers can benefit from rip tides since they can use them to avoid having to paddle out to sea. Swimmers can be swept out to sea during rip tides, which makes them extremely dangerous.
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8. Simple machines make a job easier to perform by
a. decreasing the amount of work
b. decreasing the amount of friction
c. decreasing the amount of force and/or changing the direction of force
d. only lower the amount of force
Answer:
C
Explanation:
The distance from earth to the center of our galaxy is about 22,000 ly (1 ly = 1 light year = 9.47 × 10 15 m) , as measured by an earth-based observer. A spaceship is to make this journey at a speed of 0.9990c. According to a clock on board the spaceship, how long will it take to make the trip? Express your answer in years. (1 yr is equal to 3.16 × 10 7 s .)
According to the clock on board the spaceship traveling at a speed of 0.9990c, it will take approximately 22,082 years to make the trip from Earth to the center of our galaxy.
The distance from Earth to the center of our galaxy is given as 22,000 light-years, which is equivalent to 22,000 × 9.47 × 10¹⁵ m.
To calculate the time it takes for the spaceship to make this journey, we need to account for time dilation due to relativistic effects. According to special relativity, the time experienced on the spaceship will be dilated relative to the time measured by an Earth-based observer.
Distance = 22,000 light-years × 9.47 × 10¹⁵ m/ly
Time dilation factor (γ) = 1 / √(1 - (0.9990c)²/c²)
Time taken = (Distance × γ) / c
Time taken in seconds = Time taken × 3.16 × 10⁷ s/yr
Substituting the values:
Distance = 22,000 × 9.47 × 10¹⁵ m = 2.082 × 10¹¹ m
γ = 1 / √(1 - (0.9990c)²/c²) ≈ 22.366
Time taken = (2.082 × 10¹¹ m × 22.366) / 3 × 10⁸ m/s ≈ 1.482 × 10¹³ s
Time taken in years = (1.482 × 10¹³ s) / (3.16 × 10⁷ s/yr) ≈ 4.682 × 10⁵ years
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A 0.675 kg mass is attached to a
spring of spring constant 72.4 N/m,
pulled, and released. What is the
period of the resulting oscillation?
(Unit = s)
Answer:
T= 0.6 secExplanation:
This problem bothers on the simple harmonic motion of a loaded spring
Given data
mass attached, m= 0-.675 kg
spring constant, k= 72.4 N/m
the period of oscillation can be solved for using the formula bellow
\(T= 2\pi \sqrt{\frac{m}{k} }\)
Substituting the given data into the expression above we have
\(T= 2*3.142\sqrt{\frac{0.675}{72.4} }\\T= 6.284*\sqrt{0.0093 }\\T= 0.6\)
T= 0.6 sec
Answer:
0.607
Explanation:
Trust me
asportscar, electro-fiasco i, can accelerate uniformly to 100 km/h in 3.5 s. its maximum braking rate can not exceed 0.7g. what is the minimum time required to go 1.0 km, assuming it begins and ends at rest?
The minimum time required to travel 1.0 km is 8.75 seconds.
What is travel?Travel is the movement of people from one place to another, usually over a certain distance and for a certain period of time. It can be done for many reasons, including pleasure, business, or to visit family or friends.
This can be calculated by taking the total distance traveled (1.0 km) and dividing it by the average speed (100 km/h). The average speed is 100 km/h because the car accelerates uniformly from 0 km/h to 100 km/h in 3.5 seconds.
Therefore, the total time required is 10 seconds (1 km / 100 km/h). However, this does not take into account the deceleration time of the car, which must also be taken into account.
The maximum braking rate of the car is 0.7 g, which is equivalent to 7 m/s2. Since the car must come to a complete stop at the end of the 1.0 km journey, the time required for deceleration must be calculated. This can be done using the equation:
Time for deceleration = (Final Velocity - Initial Velocity) / Acceleration
Since the initial velocity is 0 m/s and the final velocity is 0 m/s, the equation simplifies to:
Time for deceleration = 0 / 7 m/s2 = 0 seconds
Therefore, the total time required to travel 1.0 km is 10 seconds (for acceleration) + 0 seconds (for deceleration) = 10 seconds. Subtracting this from the total time required gives us the minimum time required to travel 1.0 km, which is 8.75 seconds.
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A space shuttle travels around the Earth at a constant speed of 28000 kilometers per hour. If it takes 90 minutes to complete one orbit, how far is its journey around Earth?
I need the answer ASAP!
Can you describe 2 amazing things in science that you have learned about? It can be anything science related, volcanoes, computers, medicine think of something and write.
Answer:
I learned about human body, and cause of global warming.
Explanation:
These topics were so great to learn because I didn't know about Endocrine system, but now I know the job and the importance of the Endocrine system. Also, I learned about global warming and I never knew what the cause of it was and it was great to learn new things!
what volume will a sample of copper 98.2 g occupy? the density of copper is 8.96 g/mL
Answer:
Density=mass/volume.
8.96=98.2/volume.
volume=98.2/8.96=10.95982143 ~ 11cm^3.
The volume of a sample of copper of 98.2 g would be 10.95 ml if the density of copper is 8.96 g/mL.
What is density?It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
Due to their superior electrical and thermal conductivities, remarkable resistance to corrosion, and simplicity of production, copper alloys are frequently employed. In general, copper alloys are not magnetic. Electrical wire, cable, contacts, and other components.
As given in the problem the density of copper is 8.96 g/mL, and we have to find the volume occupied by the sample of copper.
mass = density×volume
98.2 g = 8.96 g/mL×volume
volume =98.2/8.96
=10.95 ml
Thus, the volume of a 98.2 g sample of copper would be 10.95 ml.
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Calculate the total energy transferred when 200 g of ice cubes at 0°C are changed to steam at 100°C.
Specific heat capacity of water = 4200 J/kg °C
Specific latent heat of fusion = 340 kJ/kg
Specific latent heat of vaporisation = 2260 kJ/kg
Answer:
\(604000\ \text{J}\)
Explanation:
m = Mass of ice = 200 g
\(\Delta T\) = Temperature change of water = \((100-0)^{\circ}\text{C}\)
c = Specific heat capacity of water = 4200 J/kg °C
\(L_f\) = Specific latent heat of fusion = 340 kJ/kg
\(L_v\) = Specific latent heat of vaporisation = 2260 kJ/kg
Heat required to convert ice to water = \(mL_f\)
Heat required to raise the temperature of water to boiling point = \(mc\Delta T\)
Heat required to convert water to steam = \(mL_v\)
Total heat required
\(q=mL_f+mc\Delta T+mL_v\\\Rightarrow q=m(L_f+c\Delta T+L_v)\\\Rightarrow q=0.2(340\times 10^3+4200(100-0)+2260\times 10^3)\\\Rightarrow q=604000\ \text{J}\)
Heat required to convert the given amount of ice to steam at the required temperature is \(604000\ \text{J}\).
A proton and an electron are placed in an electric field. Which undergoes the lesser acceleration?.
An Electron will undergoes the lesser acceleration
What is Proton and Electron ?An electron is a negatively charged particle of equivalent magnitude to a proton, which is positively charged. Therefore, they will feel the same amount of electric force when exposed to an electric field. As a result, the relationship between acceleration and mass will be inverse. An electron will accelerate more quickly than a proton because an electron has a lower mass.
Due to their opposite polarity, an electron and a proton are attracted to one another by an electrical force of equal strength when they are placed in an electric field. However, because of their opposing charges, the force will act in the opposite direction.
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Drag each label to the correct location on the table.
Sort the processes based on the type of energy transfer they involve.
The correct processes based on the type of energy transfer they involve can be linked as ;
condensation - thermal energy removedfreezing -thermal energy removeddeposition - thermal energy removedsublimation - thermal energy addedevaporation - thermal energy addedmelting - thermal energy addedWhat is energy transfer ?Conduction, radiation, and convection are the three different ways that thermal energy is transferred. Only fluids experience the cyclical process of convection.
The total amount of energy in the universe has never changed and will never change because it cannot be created or destroyed.
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