Answer:
\(25.5h = 153\)
\(h = 6\)
The height is 6 feet, so A is correct.
Unsure how to do my Algebra homework!
On solving the exponential function 16000 = P(0.9455)^t, the original value of the car is obtained as $18,930.
What is an exponential function?
The formula for an exponential function is f(x) = a^x, where x is a variable and a is a constant that serves as the function's base and must be bigger than 0.
The value of car in amount is A(t) = $16,000.
The rate of depreciation is x = 5.45% per year.
Rewriting the rate in exponential form - (1 - 0.0545) = 0.9455
The car is t = 3 years old.
Let P be the model that depicts the original cost of the car.
Then the exponential function will be -
16000 = P(0.9455)^t
Substituting the value of t in the equation -
16000 = P(0.9455)³
16000 = 0.8452P
P = 16000/0.8452486
P = 18,929.34 ≈ 18,930
Therefore, the original value of car was $18,930.
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When Ali was 8 years old she was 127 cm tall. By the time she was 12 she had grown
to 147.3 cm tall. Using the line of best fit predict her height at age 15. (Round the
answer to the nearest tenths)
Answer: 162.5
Step-by-step explanation:
Answer:
The answer is 235.7
Step-by-step explanation:
Have a great day =)
Which of the following is equivalent to (5y + 3x) + 9x?
15xy + 9y
9x(5y + 3x)
5y + 12x
5y + 27x
Answer:
5y + 12x
Step-by-step explanation:
Let's simplify step-by-step.
5y+3x+9x
Combine Like Terms:
=5y+3x+9x
=(3x+9x)+(5y)
=12x+5y
Answer:
5y + 12x
Step-by-step explanation
Simplify step-by-step.
5y+3x+9x
Combine like terms:
=5y+3x+9x
=(3x+9x)+(5y)
=12x+5y
Suppose X,Y and Z are three different random variables. Let X obey a Bernoulli Distribution. The probability distribution function is. c is a constant here.
Let Y obey the Standard Normal (Gaussian) Distribution, which can be written as Y N(0,1). X and Y are independent. Meanwhile, let Z = XY.
Calculate the covariance of Y and Z (Cov(Y, Z)) and determine whether values of c would affect the correlation.
The value of c does not affect the covariance of Y and Z.
How did we arrive at this assertion?The covariance of Y and Z can be calculated as Cov(Y, Z) = E[YZ] - E[Y]E[Z]. Since X is Bernoulli with parameter p and E[X] = p, we have E[Z] = pE[Y]. Hence,
Cov(Y, Z) = E[YZ] - E[Y]E[Z]
= E[YXY] - pE[Y]^2
= pE[Y^2 X] - pE[Y]^2
= p(E[Y^2]E[X] + Var[Y]p) - pE[Y]^2
= p(1 * p + 1 * p^2) - p^2
= p - p^2
It can be seen that the value of c does not affect the covariance of Y and Z.
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Simplify: [3(2a)3/2]2
Answer:
the correct answer would be the first one, 72a^3
Answer:
the first one
Step-by-step explanation:
Please help me with this
An example of a function that models a linear relationship between two quantities, x and y is y = mx + b
How to explain the functionWe need to use the equation of a straight line, which is commonly expressed in slope-intercept form as:
y = mx + b
In this function, x represents the independent variable, m is the slope of the line, and b is the y-intercept. To use this function, we simply plug in the values of x, m, and b that correspond to the specific relationship we are modeling.
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Solve equation by factoring.
Hi ;-)
\(x^2+6x-10=30 \ \ /-30\\\\x^2+6x-40=0\\\\a=1, \ b=6, \ c=-40\\\\\Delta=b^2-4ac=6^2-4\cdot1\cdot(-40)=36+160=196\\\\\sqrt{\Delta}=\sqrt{196}=14\\\\x_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-6-14}{2}=\boxed{-10}\\\\x_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-6+14}{2}=\boxed4\)
State the domain and range and determine if the relation is a function
Answer:
DOMAIN = {3, 4, 5, 6, 7}, RANGE = {2, 1, 9, 12}, the relation is a function.
Step-by-step explanation:
The domain of the relation is the set of points in A which have a tail connected to it. That is {3, 4, 5, 6, 7}.
The range of the relation is the set of points in B which have a tip connected to it. That is {2, 1, 9, 12}.
Since each element of the domain of the relation is associated with exactly one element of the range, the relation is a function.
Calculate the bearing of Y from X
Answer:
074°
Step-by-step explanation:
the bearing of Y from X is the measure of the angle from the north line (N) at X in a clockwise direction to Y , that is ∠ NXY
∠ NXY = 180° - 106° = 74°
the 3- figure bearing of Y from X is 074°
helphelphelphelp
i need help quick
whoever answers this first..
i will give them 100 points
Answer:
Decreased by 19%.
-------------------------------
Decrease by of x 10% can be shown as a product of x and:
100% - 10% = 90% = 0.9Same applies to the second decrease, then we get a final number:
x*0.9*0.9 = 0.81 xIt represent a one off decrease of:
1 - 0.81 = 0.19 = 19%Hence the answer is 19%.
Answer:
19%
Step-by-step explanation:
let's start from 100 and remove 10%100 - 100/10 = 90
let's take 10% off again90 - 90/10 = 91
find the difference between 100 and 81100 - 81 = 19%
for a better understanding look at the figure
Evaluate f (x) = 3x – 5 when x = -1, x = 0, and x = 3.
When x = -1, f (x) = –2 , when r = 0, f (x) = -5), and when x = 3, f (x) = 4).
f(x) = 3x − 5 when x=−1, x=0, x=3
Answer:
-8, -2, 4
Step-by-step explanation:
1. Insert -1, 0, and 3 into x
2. Solve
Replace x with -1: f(-1) = 3(-1) − 5
Multiply 3(-1): f(-1) = -3 − 5
Subtract by 5: f(-1) = -8
The answer is -8
Now do this for the rest of the problems:
f(0) = 3(0) − 5 when x=−1, x=0, and x=3
-2 is the 2nd answer
f(3) = 3(3) − 5 when x=−1, x=0, and x=3
4 is the 3rd answer
This is my first answer, so I hope I explained it well!
Harun is designing a room addition for a home and wants a rectangular window with area that is more than 12 square feet but not more than 24 square feet. Harun knows he wants the window to be 4 feet wide.
12 because ther is 12 and y0u mknus 12 so you get 12
Which of the following statements with respect to political risk is true?
Oa. Political risk premiums are added to the required rate of return to adjust for political risks.
b. Companies cannot take any steps to reduce the potential from loss from expropriation since a foreign
government is involved.
Oc. The risk of expropriation of U.S. assets abroad is high even in traditionally friendly and stable countries.
Od. A company can reduce political risk by structuring operations so that the subsidiary has value only as a part of the
integrated corporate system.
The cost of dress in a shop is 320.00 for more than more than the cast: If a customer of a pair of pays 305.00 for the turo items. How much does each cost.
The price of each of these be
A dress market at Rs.120 is 96A pair of shoes market at Rs.750 is 600A bag market at Rs.250 is 200.What is discount?The discount is determined by dividing the purchase price by the item's par value. Discount is a type of cost price reduction or deduction for a product. It is primarily employed in consumer interactions when discounts on various goods are offered to customers. A percentage represents the discount rate. (Discount List Price) 100 is the formula used to determine the rate of discount. The discount is the amount that is subtracted from the selling price in the formula. [(List price - Selling price)/List price] 100 is an additional formula for computing discount percentages.The simplest definition of a price is the sum of money exchanged by a buyer and seller for a good or service.A. Price \(}=\left(\frac{100 \%-20 \%}{100 \%}\right) * 120=\frac{80}{100} * 120=96 \\\)
B. Price =\(\left(\frac{100 \%-20 \%}{100 \%}\right) * 750=\frac{80}{100} * 750=600 \\\)
C. Price \(=\left(\frac{100 \%-20 \%}{100 \%}\right) * 250=\frac{80}{100} * 250=200\)
The complete question is.
A shop gives 20% discount. What would the price of each of these be?
A dress market at Rs.120
A pair of shoes market at Rs.750
A bag market at Rs.250
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Determine the probability of occurence of the following single eventsA "4" appears in a single toss of a die
SOLUTION
The probability of an event occuring is found using the formula
\(\frac{possible\text{ outcome}}{\text{total possible outcome }}\)There is only "one" 4, in a die, out of a total of "six" numbers labelled 1 to 6.
So, possible outcome = 1
Total possible outcome = 6, since the die was tossed once.
Probability becomes
\(\frac{1}{6}\)Hence the answer is
\(\frac{1}{6}\)The difference of two numbers is 2 their sum is 22 what are the numbers
12+10=22
12-10=22
is the two numbers whose sum is 22 and difference is 2.
PLZ PLZ PLZ HELP ME GET THIS RIGHT ILL GIVE 40 POINTS AND BRAINLY IF THERE BOTH RIGHT, I REALLY NEED HELP I SUCK AT GEOMETRY!!!
100 POINTS
PLEASE SOLVE WITH STEPS.
THANK YOU!!!
Answer:
y = -3π/2 x + π
Step-by-step explanation:
sin(xy) = ½
The slope of the tangent line is dy/dx. Take the derivative of both sides with respect to x. You'll need to use chain rule and product rule.
cos(xy) (x dy/dx + y) = 0
x dy/dx + y = 0
x dy/dx = -y
dy/dx = -y/x
At x = ⅓ and y = π/2:
dy/dx = -(π/2) / ⅓
dy/dx = -3π/2
Using point-slope form of a line:
y − π/2 = -3π/2 (x − ⅓)
Simplifying to slope-intercept form:
y − π/2 = -3π/2 x + π/2
y = -3π/2 x + π
-2a-6a-9=-9-6a-2a
help please g
Answer:
the solution to the equation -2a - 6a - 9 = -9 - 6a - 2a is all real numbers, or (-∞, +∞).
Step-by-step explanation:
To solve this equation for "a", you need to simplify and rearrange the terms so that all the "a" terms are on one side of the equation and all the constant terms are on the other side. Here are the steps:
Start by combining the "a" terms on the left side of the equation: -2a - 6a = -8a. The equation now becomes: -8a - 9 = -9 - 6a - 2a.
Combine the constant terms on the right side of the equation: -9 - 2a - 6a = -9 - 8a. The equation now becomes: -8a - 9 = -9 - 8a.
Notice that the "a" terms cancel out on both sides of the equation. This means that the equation is true for any value of "a". Therefore, the solution is all real numbers, or in interval notation: (-∞, +∞).
In summary, the solution to the equation -2a - 6a - 9 = -9 - 6a - 2a is all real numbers, or (-∞, +∞).
use elimination to solve each system below:
system 1 system 2
4x+3y=4 3x+2y=7
-2x-3y=-8 2x-y=7
enter the value of x and y in the solution for each in the following table
value of x value of y
system 1
system 2
Answer:
SYSTEM 1
\(4x + 3y = 4 - - - eqn(i) \\ - 2x - 3y = - 8 - - - eqn(ii) \\ eqn(i) + eqn(ii) \\ = > 4x - 2x = 4 - 8 \\ 2x = - 4 \\ x = \frac{ - 4}{2} \\ x = - 2 \\ in \: eqn(i) \: \: 4x + 3y = 4 \\ but \: x = - 2 \\ = > 4( - 2) + 3y = 4 \\ = > - 8 + 3y = 4 \\ 3y = 12 \\ y = \frac{12}{3} \\ y = 4\)
SYSTEM 2
\(3x + 2y = 7 - - - eqn(i) \\ 2x - y = 7 - - - eqn(ii) \\ multiply \: eqn(ii) \: by \: 2 \\ = > 4x - 2y = 14 - - - eqn(iii) \\ eqn(i) + eqn(iii) \\ = > 7x = 21 \\ x = \frac{21}{7} \\ x = 3 \\ in \: eqn(ii) \: 2x - y = 7 \\ but \: x = 3 \\ hence \: \: 2(3) - y = 7 \\ y = 6 - 7 \\ y = - 1\)
Determine without graphing wether the given quadratic function has a maximum value or a minimum value and find the value 6x^2-12x
You have the following quadratic function:
\(6x^2-12x\)the previous function is a parabolla with a positive leading coefficient equal to 6 (leadding coefficient is the coefficient of the quadratic term). It means that the parabola opens up and then the parabolla has a minimum point.
The x-coordinate of the minimum point is just the x-coordinate of the vertex, which is given by:
\(x=-\frac{b}{2a}\)a and b are coefficients of the quadratic function. In this case a=6 and b=-12.
Replace the previous parameters into the expression for x and simplify:
\(x=-\frac{-12}{2(6)}=\frac{12}{12}=1\)Now, the y-coordinate of the vertex (minimum point in this case) is:
\(y=6(1)^2-12(1)=6-12=-6\)Then, the minimum of the function is at the point (1 , -6)
What is m
angle 1?
35°
40°
55°
70°
9514 1404 393
Answer:
(b) 40°
Step-by-step explanation:
Angle x and the one marked 70° are alternate interior angles, so are congruent. The sum of the two base angles of the isosceles triangle is ...
x° +x° = 70° +70° = 140°
So, the remaining angle 1 in the triangle is ...
180° -140° = 40°
∠1 = 40°
the two arithmetic sequences, 1,5,9,13... and 1,6,11,16.. have infinitely many terms in common. what is the sum of the first three common terms
Arithmetic sequence is modeled by the next formula:
\(a_n=a_1+(n-1)\cdot d\)where an is the nth term, a1 is the first term, and d is the common difference.
In the case of the first sequence:
\(a_n=1+(n-1)\cdot4\)In the case of the second sequence:
\(a_n=1+(n-1)\cdot5\)The 6th term of the first sequence is:
\(a_6=1+(6-1)\cdot4=21\)The 5th term of the second sequence is:
\(a_5=1+(5-1)\cdot5=21\)The 11th term of the first sequence is:
\(a_{11}=1+(11-1)\cdot4=41\)The 9th term of the second sequence is:
\(a_9=1+(9-1)\cdot5=41\)Therefore, the first three common terms are: 1, 21, and 41. And the sum of them is 63
Problem 1.1.A basket of fruit is arranged out of apples, bananas, and oranges.What is the smallest number of fruit that should be put in the basket to guaranteethat there are either at least 8 apples or at least 6 bananas or at least 9 oranges
Answer:
21
Step-by-step explanation:
The question is based in pigeonhole principle that says If n or more pigeons are distributed among k >0 pigeonholes,then at least one pigeonhole contains at least \(\frac{n}{k}\) pigeons.
8 + 6 + 9−3 + 1 = 21
Please answer this correctly without making mistakes I want ace expert and genius people to answer this correctly without making mistakes
Answer:
-73
Step-by-step explanation:
if f is 73
and they made f negative, they just made 73 negative too.
i don't know if there is more in that expression
all i can see is
-f=___
There are 35 boxes with 48 base balls in each box how many baseballs are there altogether
Answer:
35x48=1680
Step-by-step explanation:
1680
Y=7x+8 find the slope of this line
Answer:
this problem is actually already solved the slope is 7 or 7/1 and the y -intercept is 8.
hope this helped!
A supermarket sells orange juice in three sizes. The 32 fl oz container costs $1.99,the 64 fl oz container costs $3.69, and the 96 fl oz container costs $5.85. Which size orange juice has the lowest price per fluid ounce? Explain!
Answer:
64 fl oz
Step-by-step explanation:
To find the best price you take the cost and divide it by the number of fluid ounces ($1.99/32). For the 32 oz it costs .062, for the 64 oz it costs .057, and for the 96 oz it costs .060 (these are all approximate number btw). Therefore, since 64 oz has the lowest number it has the lowest price per fluid oz.
The mean monthly mortgage paid by all home owners in a city is $1320 with a standard deviation of $105. Using Chebyshev's theorem, find the interval, [L,U] , that contains monthly mortgage payments of at least 75% of all homeowners. Round your answers to two decimal places.
Using Chebyshev's Theorem, it is found that the interval that contains monthly mortgage payments of at least 75% of all homeowners is [1110, 1530].
Chebyshev TheoremThe Chebyshev Theorem can also be applied to non-normal distribution. It states that:
At least 75% of the measures are within 2 standard deviations of the mean. At least 89% of the measures are within 3 standard deviations of the mean.In this problem:
The mean is of $1320.The standard deviation is of $105.By the Chebyshev's Theorem, at least 75% of the measures are within 2 standard deviations of the mean, hence:
\(1320 - 2(105) = 1110\)\(1320 + 2(105) = 1530\)The interval that contains monthly mortgage payments of at least 75% of all homeowners is [1110, 1530].
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if sin(θ)=7/25, when π/2<θ<π, use the given information about θ to find the exact value of sin(θ/2)
we know that π/2 < θ < π, which is another way of saying that θ is in the II Quadrant, so half that angle will most likely be located on the I Quadrant, where cosine as well as sine are both positive.
Now, let's keep in mind that θ itself is in the II Quadrant, where the cosine is negative whilst the sine is positive.
\(\textit{Half-Angle Identities} \\\\ sin\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1-cos(\theta)}{2}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(\theta )=\cfrac{\stackrel{opposite}{7}}{\underset{hypotenuse}{25}}\qquad \textit{let's now find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases}\)
\(\pm\sqrt{25^2-7^2}=a\implies \pm\sqrt{576}=a\implies \pm 24=a\implies \stackrel{II~Quadrant}{-24=a} \\\\[-0.35em] ~\dotfill\\\\ cos(\theta )=\cfrac{\stackrel{adjacent}{-24}}{\underset{hypotenuse}{25}} \\\\\\ sin\left(\cfrac{\theta}{2}\right)\implies \pm \sqrt{\cfrac{1-\left( -\frac{24}{25} \right)}{2}}\implies \pm \sqrt{\cfrac{1 +\frac{24}{25} }{2}}\)
\(\pm\sqrt{\cfrac{~~\frac{49}{25} ~~}{2}}\implies \pm\sqrt{\cfrac{49}{50}}\implies \stackrel{I~Quadrant}{+\sqrt{\cfrac{49}{50}}}\implies \cfrac{\sqrt{49}}{\sqrt{50}}\implies \cfrac{7}{5\sqrt{2}} \\\\\\ \stackrel{\textit{rationalizing the denominator}}{\cfrac{7}{5\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies \cfrac{7\sqrt{2}}{5\sqrt{2^2}}}\implies \cfrac{7\sqrt{2}}{10}\)